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  • Automatic adition of `using` in CodeRush.

    - by drasto
    I just installed CodeRush Pro (evaluation trial) for Visual Studio and I can say I like it much so far. Comparing to Resharper there is only one type of feature I'm really missing. It is the way CodeRush deals with using. When I type some class name that is not declared in some package listed in using, CodeRush underlines it red as an error(what it is) but if I hover over it with cursor it does not offer me to add using, it merely says it is "Undeclared element". I have to use VS default using addition (move caret to the identifier, hover cursor over that really small box that appears under first letter, click the button that appears and choose for example using System form a drop down menu). Is there a way how to configure CodeRush to offer mi add using when I hover a cursor over highlighted "issue"(that says Undeclared element)? The second part of this is that Resharper has somethink called Type name completion. It some improved intellisense. Lets say you have no using declaration in your file. Then you type something like ICompar and press CTRL+SPACE. Of cause there will be no suggestions. But with Resharper you can press CTRL+ALT+SPACE and you get suggestions of all classes starting with ICompar even if they are not in using. When you choose one of them the correct using is automatically added for you. Is there a way to make CodeRush behave this way ?

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  • Followed the official android documentations but still could not use SQLite in app

    - by user366539
    My DBHelper class public class DBHelper extends SQLiteOpenHelper { public DBHelper(Context context) { super(context,"SIMPLE_DB",null,1); } @Override public void onCreate(SQLiteDatabase db) { db.execSQL("CREATE TABLE SIMPLE_TABLE ( " + "ID INTEGER PRIMARY KEY " + "DESC TEXT);"); } @Override public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { } } Activity class public class SimpleDatabase extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); DBHelper dbHelper = new DBHelper(this); SQLiteDatabase db = dbHelper.getReadableDatabase(); db.execSQL("INSERT INTO SIMPLE_TABLE VALUES (NULL, 'test');"); Cursor cursor = db.rawQuery("SELECT * FROM SIMPLE_TABLE", null); TextView text = (TextView)findViewById(R.id.textbox); text.setText(cursor.getString(0)); } } I figure it crashed (application has stopped unexpectedly!) at SQLiteDatabase db = ... because if I commented the code out from there to the end then it worked fine. But I have no idea whatsoever why it does that. Any help would be appreciated.

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  • DynamicContent.html: Write a JavaScript in an HTML document that can change the content of an HTML e

    - by A sw A
    ShowHide.html: Write a JavaScript in an HTML document that displays an image and allows the user to toggle the image between appearing and not appearing in the document. Place your image in a (division) tag that has a style attribute. “style.visibility” can take two values: “visible” and “hidden”. The document has a button called “Toggle Image”, which calls the toggle function upon the event “onclick”. DynamicColors.html: Write a JavaScript in an HTML document that changes the background and foreground colors of the body of a document according to the user input. The document has two input texts: background color and foreground color. The colors change when the event “onchange” occurs as you type in the text input and the event handler is called. Your event handler takes two parameters: “where”, and “newColor”. To change the document color and background color you need to change the elements document.body.style.color and document.body.style.backgroundColor. Available colors are: black, silver, gray, white, maroon, red, purple, fuchsia, green, lime, olive, yellow, navy, blue, teal, and aqua. DynamicContent.html: Write a JavaScript in an HTML document that can change the content of an HTML element (a help box). The content of an element is accessed through its “value” property. The content of a help box can change depending on the placement of the mouse cursor. When the cursor is placed over a particular input field (“onmouseover” event), the help box can display advice on how the field is to be filled. When the cursor is moved away from the input field (“onmouseout” event), the help box content changes to simply indicate that assistance is available. Your messages are stored in an array of strings.

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  • The SVG text node disappear after change its text content

    - by sureone
    svg: <text xml:space="preserve" y="228" x="349.98" text-anchor="middle" stroke-width="0" stroke-linejoin="null" stroke-linecap="null" stroke-dasharray="null" stroke="#000000" fill="#000000" style="cursor: move; pointer-events: inherit;" font-size="24" font-family="serif" id="cur_b">cur_b</text> <text xml:space="preserve" y="222" x="103.98" text-anchor="middle" stroke-width="0" stroke-linejoin="null" stroke-linecap="null" stroke-dasharray="null" stroke="#000000" fill="#000000" style="cursor: move; pointer-events: inherit;" font-size="24" font-family="serif" id="cur_a">cur_a</text> <text xml:space="preserve" y="229" x="590.0211" text-anchor="middle" stroke-width="0" stroke-linejoin="null" stroke-linecap="null" stroke-dasharray="null" stroke="#000000" fill="#000000" style="cursor: move; pointer-events: inherit;" font-size="24" font-family="serif" id="cur_c">cur_c</text> NSString* theJS = @ "var theNode0 = document.getElementById('cur_a'); theNode0.textContent='200A'; theNode0.setAttribute('fill','#FF0000'); var theNode1 = document.getElementById('cur_c'); theNode1.textContent='200A'; theNode1.setAttribute('fill','#00FF00');" [self.webView stringByEvaluatingJavaScriptFromString:theJS]; The SVG text node value is changed but disappeared after about one second.

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  • Does PHP have job control like bash does?

    - by Andrew
    Hello, does PHP support something like ampersand in bash (forking)? Let's say I wanted to use cURL on 2 web pages concurrently, so script doesn't have to wait before first cURL command finnishes, how could one achieve that in PHP? Something like this in bash: curl www.google.com & curl www.yahoo.com & wait

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  • python gio waiting for async operations to be done

    - by pygabriel
    I have to mount a WebDav location and wait for the operation to be finished before to proceed (it's a script). So I'm using the library in this way: location = gio.File("dav://server.bb") location.mount_enclosing_volume(*args,**kw) # The setup is not much relevant location.get_path() # Returns None because it's not yet mounted since the call is async How to wait until the device is mounted?

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  • Simple java syncrhonization question

    - by Misha Koshelev
    Dear All: Was wondering, which is correct: Option One class A { public void methodOne() { synchronized(this) { modifyvalue notifyAll() } } public void methodTwo() { while (valuenotmodified) { synchronized(this) { wait() } } } Option Two class A { public void methodOne() { modifyvalue synchronized(this) { notifyAll() } } public void methodTwo() { while (valuenotmodified) { synchronized(this) { wait() } } } and why? Thank you Misha

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  • Using IoC and Dependency Injection, how do I wrap an existing implementation with a new layer of imp

    - by Dividnedium
    I'm trying to figure out how this would be done in practice, so as not to violate the Open Closed principle. Say I have a class called HttpFileDownloader that has one function that takes a url and downloads a file returning the html as a string. This class implements an IFileDownloader interface which just has the one function. So all over my code I have references to the IFileDownloader interface and I have my IoC container returning an instance of HttpFileDownloader whenever an IFileDownloader is Resolved. Then after some use, it becomes clear that occasionally the server is too busy at the time and an exception is thrown. I decide that to get around this, I'm going to auto-retry 3 times if I get an exception, and wait 5 seconds in between each retry. So I create HttpFileDownloaderRetrier which has one function that uses HttpFileDownloader in a for loop with max 3 loops, and a 5 second wait between each loop. So that I can test the "retry" and "wait" abilities of the HttpFileDownloadRetrier I have the HttpFileDownloader dependency injected by having the HttpFileDownloaderRetrier constructor take an IFileDownloader. So now I want all Resolving of IFileDownloader to return the HttpFileDownloaderRetrier. But if I do that, then HttpFileDownloadRetrier's IFileDownloader dependency will get an instance of itself and not of HttpFileDownloader. So I can see that I could create a new interface for HttpFileDownloader called IFileDownloaderNoRetry, and change HttpFileDownloader to implement that. But that means I'm changing HttpFileDownloader, which violates Open Closed. Or I could implement a new interface for HttpFileDownloaderRetrier called IFileDownloaderRetrier, and then change all my other code to refer to that instead of IFileDownloader. But again, I'm now violating Open Closed in all my other code. So what am I missing here? How do I wrap an existing implementation (downloading) with a new layer of implementation (retrying and waiting) without changing existing code? Here's some code if it helps: public interface IFileDownloader { string Download(string url); } public class HttpFileDownloader : IFileDownloader { public string Download(string url) { //Cut for brevity - downloads file here returns as string return html; } } public class HttpFileDownloaderRetrier : IFileDownloader { IFileDownloader fileDownloader; public HttpFileDownloaderRetrier(IFileDownloader fileDownloader) { this.fileDownloader = fileDownloader; } public string Download(string url) { Exception lastException = null; //try 3 shots of pulling a bad URL. And wait 5 seconds after each failed attempt. for (int i = 0; i < 3; i++) { try { fileDownloader.Download(url); } catch (Exception ex) { lastException = ex; } Utilities.WaitForXSeconds(5); } throw lastException; } }

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  • Simple java synchronization question

    - by Misha Koshelev
    I was wondering, which is correct: Option One class A { public void methodOne() { synchronized(this) { modifyvalue notifyAll() } } public void methodTwo() { while (valuenotmodified) { synchronized(this) { wait() } } } Option Two class A { public void methodOne() { modifyvalue synchronized(this) { notifyAll() } } public void methodTwo() { while (valuenotmodified) { synchronized(this) { wait() } } } and why?

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  • Ruby sleep or delay less than a second?

    - by Joseph Silvashy
    So I'm making a script with ruby that must render frames at 24 frames per second, but I need to wait 1/24th of a second between sending the commands... how can I do that? sleep seems to only wait in increments of 1 second or more. update Well ya you can do sleep 0.1 if you want, but is this the best way to delay in a ruby script?

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  • Does add() on LinkedBlockingQueue notify waiting threads?

    - by obvio171
    I have a consumer thread taking elements from a LinkedBlockingQueue, and I make it sleep manually when it's empty. I use peek() to see if the queue empty because I have to do stuff because sending the thread to sleep, and I do that with queue.wait(). So, when I'm in another thread and add()an element to the queue, does that automatically notify the thread that was wait()ing on the queue?

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  • The simplest concurrency pattern

    - by Ilya Kogan
    Please, would you help me in reminding me of one of the simplest parallel programming techniques. How do I do the following in C#: Initial state: semaphore counter = 0 Thread 1: // Block until semaphore is signalled semaphore.Wait(); // wait until semaphore counter is 1 Thread 2: // Allow thread 1 to run: semaphore.Signal(); // increments from 0 to 1 It's not a mutex because there is no critical section, or rather you can say there is an infinite critical section. So what is it?

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  • Microbenchmark showing process-switching faster than thread-switching; what's wrong?

    - by Yang
    I have two simple microbenchmarks trying to measure thread- and process-switching overheads, but the process-switching overhead. The code is living here, and r1667 is pasted below: https://assorted.svn.sourceforge.net/svnroot/assorted/sandbox/trunk/src/c/process_switch_bench.c // on zs, ~2.1-2.4us/switch #include <stdlib.h> #include <fcntl.h> #include <stdint.h> #include <stdio.h> #include <semaphore.h> #include <unistd.h> #include <sys/wait.h> #include <sys/types.h> #include <sys/time.h> #include <pthread.h> uint32_t COUNTER; pthread_mutex_t LOCK; pthread_mutex_t START; sem_t *s0, *s1, *s2; void * threads ( void * unused ) { // Wait till we may fire away sem_wait(s2); for (;;) { pthread_mutex_lock(&LOCK); pthread_mutex_unlock(&LOCK); COUNTER++; sem_post(s0); sem_wait(s1); } return 0; } int64_t timeInMS () { struct timeval t; gettimeofday(&t, NULL); return ( (int64_t)t.tv_sec * 1000 + (int64_t)t.tv_usec / 1000 ); } int main ( int argc, char ** argv ) { int64_t start; pthread_t t1; pthread_mutex_init(&LOCK, NULL); COUNTER = 0; s0 = sem_open("/s0", O_CREAT, 0022, 0); if (s0 == 0) { perror("sem_open"); exit(1); } s1 = sem_open("/s1", O_CREAT, 0022, 0); if (s1 == 0) { perror("sem_open"); exit(1); } s2 = sem_open("/s2", O_CREAT, 0022, 0); if (s2 == 0) { perror("sem_open"); exit(1); } int x, y, z; sem_getvalue(s0, &x); sem_getvalue(s1, &y); sem_getvalue(s2, &z); printf("%d %d %d\n", x, y, z); pid_t pid = fork(); if (pid) { pthread_create(&t1, NULL, threads, NULL); pthread_detach(t1); // Get start time and fire away start = timeInMS(); sem_post(s2); sem_post(s2); // Wait for about a second sleep(1); // Stop thread pthread_mutex_lock(&LOCK); // Find out how much time has really passed. sleep won't guarantee me that // I sleep exactly one second, I might sleep longer since even after being // woken up, it can take some time before I gain back CPU time. Further // some more time might have passed before I obtained the lock! int64_t time = timeInMS() - start; // Correct the number of thread switches accordingly COUNTER = (uint32_t)(((uint64_t)COUNTER * 2 * 1000) / time); printf("Number of process switches in about one second was %u\n", COUNTER); printf("roughly %f microseconds per switch\n", 1000000.0 / COUNTER); // clean up kill(pid, 9); wait(0); sem_close(s0); sem_close(s1); sem_unlink("/s0"); sem_unlink("/s1"); sem_unlink("/s2"); } else { if (1) { sem_t *t = s0; s0 = s1; s1 = t; } threads(0); // never return } return 0; } https://assorted.svn.sourceforge.net/svnroot/assorted/sandbox/trunk/src/c/thread_switch_bench.c // From <http://stackoverflow.com/questions/304752/how-to-estimate-the-thread-context-switching-overhead> // on zs, ~4-5us/switch; tried making COUNTER updated only by one thread, but no difference #include <stdlib.h> #include <stdint.h> #include <stdio.h> #include <pthread.h> #include <unistd.h> #include <sys/time.h> uint32_t COUNTER; pthread_mutex_t LOCK; pthread_mutex_t START; pthread_cond_t CONDITION; void * threads ( void * unused ) { // Wait till we may fire away pthread_mutex_lock(&START); pthread_mutex_unlock(&START); int first=1; pthread_mutex_lock(&LOCK); // If I'm not the first thread, the other thread is already waiting on // the condition, thus Ihave to wake it up first, otherwise we'll deadlock if (COUNTER > 0) { pthread_cond_signal(&CONDITION); first=0; } for (;;) { if (first) COUNTER++; pthread_cond_wait(&CONDITION, &LOCK); // Always wake up the other thread before processing. The other // thread will not be able to do anything as long as I don't go // back to sleep first. pthread_cond_signal(&CONDITION); } pthread_mutex_unlock(&LOCK); return 0; } int64_t timeInMS () { struct timeval t; gettimeofday(&t, NULL); return ( (int64_t)t.tv_sec * 1000 + (int64_t)t.tv_usec / 1000 ); } int main ( int argc, char ** argv ) { int64_t start; pthread_t t1; pthread_t t2; pthread_mutex_init(&LOCK, NULL); pthread_mutex_init(&START, NULL); pthread_cond_init(&CONDITION, NULL); pthread_mutex_lock(&START); COUNTER = 0; pthread_create(&t1, NULL, threads, NULL); pthread_create(&t2, NULL, threads, NULL); pthread_detach(t1); pthread_detach(t2); // Get start time and fire away start = timeInMS(); pthread_mutex_unlock(&START); // Wait for about a second sleep(1); // Stop both threads pthread_mutex_lock(&LOCK); // Find out how much time has really passed. sleep won't guarantee me that // I sleep exactly one second, I might sleep longer since even after being // woken up, it can take some time before I gain back CPU time. Further // some more time might have passed before I obtained the lock! int64_t time = timeInMS() - start; // Correct the number of thread switches accordingly COUNTER = (uint32_t)(((uint64_t)COUNTER * 2 * 1000) / time); printf("Number of thread switches in about one second was %u\n", COUNTER); printf("roughly %f microseconds per switch\n", 1000000.0 / COUNTER); return 0; }

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  • Delay KeyUp Action if User is Typing (C#)

    - by Kirk
    I have a function that is being called when the user is typing in a search box. I want to wait for the user to finish typing before I actually execute the function. I know how to easily accomplish this in JavaScript with timeouts, but how would I go about doing the same thing in C#? Also, how long should I wait before I assume the user is done typing? 100ms?

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  • REBOL: How to do another task while waiting an alarm to trigger ?

    - by Rebol Tutorial
    So I have created an alarm function: alarm: func[seconds message [string! unset!]][ wav: load %attention.wav sound-port: open sound:// wait seconds do [ insert sound-port wav wait sound-port close sound-port if (value? 'message) [ print message ] ] ] which works like this: alarm 30 "Will trigger in 30 seconds" Now how can I for example show a timer which increments while waiting for the alarm since Rebol doesn't support thread ?

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  • Java Synchronized function

    - by leon
    Hi I have a question. In the following code, if a thread were blocked at wait statement, and another thread attempts to execute foo(), would the hello wolrd message be printed? and Why? Many Thanks synchronized foo(){ system.out.println("hello world"); ..... wait(); ..... }

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  • Looking for a simple alternative to Thread.Sleep

    - by George
    HI, During the development of my app, I was using Thread.Sleep to give our external devices some time to adjust to settings before making queries, as they are quite old and slow. I now want to replace these with something a bit more stylish and correct. Does anyone have a simple way to "wait" for a device rather than sleep, bearing in mind the device does not let us know when it is ready, so a wait is about as good as we can do !?? Regards, George.

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  • Android hosts file usage

    - by dominos
    I have the following problem: I make a custom hosts file to test some features of my application and then push it to my android emulator. The thing is that these settings do not take effect immediately. I have to wait about 10 minutes before they become active. So my question is: how to make the new hosts file active instantly? I have many different settings to test and I can't wait 10 minutes every time.

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  • Background processing in Rails

    - by Shreyas Satish
    A certain function in my controller takes a lot of time to process (heavy db work) . So when my user clicks on "submit" on the form he has to wait for the process to complete which is quite long. Is there any way that on "submitting", the user is redirected to the next view without any delay while the processing continues in the back-end without making the user wait ? Thanks & Cheers !

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  • C++ boost thread reusing threads

    - by aaa
    hi. I am trying to accomplish something like this: thread t; // create/initialize thread t.launch(); // launch thread. t.wait(); // wait t.launch(); // relaunch the same thread How to go about implementing something like this using boost threads? in essence, I need persistent relaunch-able thread. Thanks

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  • show message in new windows

    - by lolalola
    Hi, now program show Messagebox and wait user decision. How make, that program don't wait? Show Messagebox, ant keep going. (I do not need a user action. I just need to show text) Or maybe a better option than to report the information to a new window? I hope to understand my problem.

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