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  • inserting large number of dates

    - by Radhe
    How can I insert all dates in an year(or more) in a table using sql My dates table has following structure dates(date1 date); Suppose I want to insert dates between "2009-01-01" to "2010-12-31" inclusive. Is there any sql query for the above?

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  • Trying to catch integrity error with sqlaclhemey

    - by Lostsoul
    I'm having problems with trying to catch a error. I'm using pyramid/sqlalchemy and made a sign up form with email as the primary key. The problem is when a duplicate email is entered it raises a IntegrityError, so I'm trying to catch that error and provide a message but no matter what I do I can't catch it(the error keeps appearing). try: new_user = Users(email, firstname, lastname, password) DBSession.add(new_user) return HTTPFound(location = request.route_url('new')) except IntegrityError: message1 = "Yikes! Your email already exists in our system. Did you forget your password?" I get the same message when I tried except exc.SQLAlchemyError (although I want to catch specific errors and not a blanket catch all). Is there something wrong with my python syntax? or is there something I need to do special in sqlalchemy to catch it?

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  • How to construct this query? (Ordering by COUNT() and joining with users table)

    - by Andrew
    users table: id-user-other columns scores table: id-user_id-score-other columns They're are more than one rows for each user, but there's only two scores you can have. (0 or 1, == win or loss). So I want to output all the users ordered by the number of wins, and all the users ordered by the numbers of losses. I know how to do this by looping through each user, but I was wondering how to do it with one query. Any help is appreciated!

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  • question with its query

    - by user329820
    Hi this is my homework and the question is this: List the average balance of customers by city and short zip code (the first five digits of thezip code). Only include customers residing in Washington State (‘WA’). also the Customer table has 5 columns(Name,Family,CustZip,CustCity,CustAVGBal) I wrote the query like below is this correct? SELECT CustCity,LEFT(CustZip,5) AS NewCustZip,CustAVGBal FROM Customer WHERE CustCity = 'WA' THANKS!!

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  • SQL Databases and table design/organization

    - by John McMullen
    (NOOB disclaimer) I'm working on a system (a type of map), that is accessed mostly via 3 fields: ID (auto incremented), X coordinate, and Y coordinate. As it is right now, i have all data on the map, stored in 1 table. Whenever the map display is loaded it simply queries the database for contents in x and y, and the DB gives the data (other fields in the same entry). If an item on the map is doing something, it has a flag saying its doing something, and then has an ID of the action in another table holding that type of 'actions'. Essentially, for all map data, its stored in 1 table. All actions of a certain type are stored in their own table. I'm a noob, and i'm wondering what the most effective/efficient structure for such a design? (a map that has items, and each item has stats/actions). I'm using PHP atm, using standard SQL queries to get my data. Should i split up the tables so that there are only x number of entries on a table? (coord range limits)? Should it just keep growing and growing? There's a lot of queries to the table... so just tryin to see what is best :/

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  • Killing the mysqld process

    - by Josh K
    I have a table with ~800k rows. I ran an update users set hash = SHA1(CONCAT({about eight fields})) where 1; Now I have a hung Sequel Pro process and I'm not sure about the mysqld process. This is two questions: What harm can possibly come from killing these programs? I'm working on a separate database, so no damage should come to other databases on the system, right? Assume you had to update a table like this. What would be a quicker / more reliable method of updating without writing a separate script. I just checked with phpMyAdmin and it appears as though the query is complete. I still have Sequel Pro using 100% of both my cores though...

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  • Normalise this Table?

    - by Abs
    Hello all, I am creating a social bookmarking app. I am having a re-thought of the DB design in the middle of development. Should I normalise the bookmarks table and remove the tag columns that I have into a separate table. I have 10 tags per bookmark and therefore 10 columns per record (per bookmark). It seems to me that breaking the table into two would just mean I would have to do a join but the way I currently have it, its a straight select - but the table doesn't feel right...? Thanks all

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  • Codeigniter: A nice straight forward tutorial on how to build a reset password/forgotten password?

    - by Psychonetics
    I've built a full sign up system with user account activation, login, validation, captcha etc. To complete this I now need to implement a forgot password/reset password feature.. I have created one function that generates a random password 8 characters, another method that takes that random password word and applies sha1 and hashing. Also one that takes that hashed password and stores it in a table in the database. I will keep these methods to one side as they might come in handy later on but for now I would like to know if anyone can point me to a nice tutorial for creating a password reset feature for my website. Thanks in advance

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  • Best way to construct this query?

    - by Andrew
    I have two tables set up similar to this (simplified for the quest): actions- id - user_id - action - time users - id - name I want to output the latest action for each user. I have no idea how to go about it. I'm not great with SQL, but from what I've looked up, it should look something like the following. not sure though. SELECT `users`.`name`, * FROM users, actions JOIN < not sure what to put here > ORDER BY `actions`.`time` DESC < only one per user_id > Any help would be appreciated.

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  • How to join nearly identical several queries into one?

    - by Devyn
    Hi, Assume I have an order_dummy table where order_dummy_id, order_id, user_id, book_id, author_id are stored. You may complain the logic of my table but I somehow need to do it that way. I want to execute following queries. SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 1 ORDER BY `order_dummy_id` DESC LIMIT 1 SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 2 ORDER BY `order_dummy_id` DESC LIMIT 1 SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 3 ORDER BY `order_dummy_id` DESC LIMIT 1 Please keep in mind that several numbers of same book is included in one order. Therefore, I list order_dummy_id by descending and limit 1 so only LATEST ORDER of A BOOK is shown. But my goal is to show other books in that way in one table. I used group by like this ... SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 GROUP BY book_id but it only shows order_dummy_id with ascending result. I have no idea anymore. Looking forward your kindness help!

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  • Compile error on action for iPhone app: "error:expected ')' before ';' token"

    - by Jamis Charles
    I'm working through the tutorials in the "Beginning iPhone Development" book. I'm on chapter 4 and I'm getting the following compile error on the "if (segment == kShowSegmentIndex)" line: error:expected ')' before ';' token Here's my code: - (IBAction)toggleShowHide:(id)sender{ UISegmentedControl *segmentedControl = (UISegmentedControl *)sender; NSInteger segment = segmentedControl.selectedSegmentIndex; if (segment == kShowSegmentIndex) [switchView setHidden:NO]; else [switchView setHidden:YES]; } I've compared it with the code in the book several times and have retyped it. Sounds like this error is caused by improper brace placement. Any thoughts?

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  • How phpmyadmin, php and everything else works?

    - by Tom
    Ok, I guess I got crazy, but really. How phpmyadmin works? Does it have his own phpmyadmin or what? And how php works? Why writing echo 'hello'; it returns hello in the browser? I am really interested on how these things really works, maybe you know any books or smth to figure it out? Thank you.

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  • Display Events on PHP Calendar

    - by jl
    Hi, I would like to ask if I have a table of events on my database, e.g. description | startdt | enddt event1 | 2010-04-01 10:00:00 | 2010-04-01 13:00:00 event2 | 2010-04-09 14:00:00 | 2010-04-09 18:00:00 event3 | 2010-04-30 11:00:00 | 2010-05-02 16:00:00 I have already created a php calendar, how can I display these above events onto my calendar, so that it will look something like the google calendar? e.g. on the for 2010-04-01, it will display "event1" on the month calendar. Thank you.

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  • PHP Show all data in column

    - by user342391
    I am trying to show all of the data in the 'status' column of my table but am having troubles. What am I doing wrong: <?php $query1 = "SELECT id, status FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id LIMIT $start, $limit "; $result = mysql_query($query1); while ($row = mysql_fetch_array($result)) { echo $row['status'] ; } ?>

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  • database change after pressing 'X' button

    - by Anup Prakash
    What i know:- We can use Ajax to change database from javascript. So whenever we press the 'X' button on title bar it calls "onbeforeunload" event. And by this event we can change the database. But in my case, i want to change the status of user only when user click on 'X' button. Not in case of changing the page. As because changing the page is unloading the page. and closing the page is also unloading the page(As much i know). Is there any way to differentiate between closing the page and moving from one page to other page? I want to use it for changing the status of user(i.e. login/logout), whenever he presses cross button. I don't want to set status "logout" when user changes the page. I want to set status "logout" when user 'X' the button. Plese help me.

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  • PHP drop down which each are dependable

    - by user147685
    Hi all, I have this problems. using html and php. May I know how to do this. I have 2 drop down, eg A and B. Drop down B is depend to the drop down A. Example, A have these options which will be called from dbase(no prob with this, tq) (Jack, Carol), and B wil have options depend on A: if select Jack(T1, T2, T3), if select carol(T1,T2,T3,T4,T5). Here are the sample interface. Can someone help me with this? thank you.

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  • Problem updating values in combobox in vb.net

    - by user225269
    I have this code, but I have a problem. When I update but do not really made any changes to the value and press the update button, the data becomes null. And it will seem that I deleted the value. I've taught of a solution, that is to add both combobox1.selectedtext and combobox1.selecteditem to the function. But it doesn't work. combobox1.selecteditem is working when you try to alter the values when you update. But will save a null value when you don't alter the values using the combobox combobox1.selectedtext will save the data into the database even without altering. But will not save the data if you try to alter it. -And I incorporated both of them, but still only one is performing, and I think it is the one that I added first: Dim shikai As New Updater Try shikai.id = TextBox1.Text shikai.fname = TextBox2.Text shikai.mi = TextBox3.Text shikai.lname = TextBox4.Text shikai.ad = TextBox5.Text shikai.contact = TextBox9.Text shikai.year = ComboBox1.SelectedText shikai.section = ComboBox2.SelectedText shikai.gender = ComboBox3.SelectedText shikai.religion = ComboBox4.SelectedText shikai.year = ComboBox1.SelectedItem shikai.section = ComboBox2.SelectedItem shikai.gender = ComboBox3.SelectedItem shikai.religion = ComboBox4.SelectedItem shikai.bday = TextBox6.Text shikai.updates() MsgBox("Successfully updated!") Please help, what would be a simple workaround to solve this problem?

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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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