Search Results

Search found 5228 results on 210 pages for 'bash alias'.

Page 56/210 | < Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >

  • sudo nohup nice <-- in what order?

    - by Jonah Braun
    So I have a script that I want to run as root, without hangup and nicely. What order should I put the commands in? sudo nohup nice foo.bash & or nohup nice sudo foo.bash & etc. I suspect it doesn't matter but would like some insight from those who really know.

    Read the article

  • How to remove ˆM chars?

    - by LucaB
    I have a file generated from windows that I have to paste into a script under linux. My script works fine, except for the fact that at the end of every line I got a ^M char. How can I remove it with bash? Currently my script is: #/bin/bash IFS=$'\n' for CUSTOMER in `cat exp.csv` do echo $CUSTOMER done

    Read the article

  • Script executes successfully in commandline but not as a cronjob

    - by JasonOng
    I've a bash script that runs a ruby script that fetches my twitter feeds. ## /home/username/twittercron #!/bin/bash cd /home/username/twitter ruby twitter.rb friends It runs successfully in command line. /home/username/twittercron But when I try to run it as a cronjob, it ran but wasn't able to fetch the feeds. ## crontab -e */15 * * * * * /home/username/twittercron The script has been chmod +x. Not sure why it's as such. Any ideas?

    Read the article

  • Next generation of command shells?

    - by ignatius
    I am curious about if there is any project about a replacement for the current unix-shells (like bash, ash, rsh ...), at least adding some new ideas or paradigm in this area. I was searching but i found very few information, this project http://en.wikipedia.org/wiki/Friendly_interactive_shell seems interesting, but not so diferent from the nowadays solutions. What do you think? Do you imagine a linux-distribution on 2020 that still having bash? How can be an evolution of this programs? Br

    Read the article

  • List of common ways those could shut down server unexpectedly ?

    - by SpawnCxy
    After running a bash fork bomb which made my webserver down, I think I should be more careful even not under root.I thought it would be totally fine while I'm not under root.So I ignored the warning and ran the bash fork bomb which is :() { :|:& }; : .(Please don't run it if u don't understand this code cuz it will make you system down).And I think I need a list of common ways those could cause a sever shutting down unexpectly even not under root. Any suggestion would be appreciated. Regards `

    Read the article

  • Is it possible to get the exit code from a subshell?

    - by Geo
    Let's imagine I have a bash script, where I call this: bash -c "some_command" do something with code of some_command here Is it possible to obtain the code of some_command? I'm not executing some_command directly in the shell running the script because I don't want to alter it's environment.

    Read the article

  • Makefile and rm -f file.{ext1,ext2,ext3} issue

    - by ak91
    Hello, Could you explain me, why Makefile rule: clean: rm -f foo.{bar1,bar2,bar3} does not result in removing files: foo.bar1 foo.bar2 and foo.bar3? I believe I saw pattern like that many times in various Makefiles, but I'm currently writing my own Makefile and can't make that rule work correctly (no files are removed). I'm using: gnu make 3.81 gnu bash 4.1.5 Bash evals that pattern as I suspect: $ echo test.{a,b,c} test.a test.b test.c Thanks!

    Read the article

  • Creating a string variable name from the value of another string

    - by NeonGlow
    In my bash script I have two variables 'CONFIG_OPTION' and 'CONFIG_VALUE' which contain string VENDOR_NAME and Default_Vendor respectively. I need to create a variable with name '$CONFIG_OPTION' ie VENDOR_NAME and assign the value in CONFIG_VALUE to newly created variable. How I can do this? I tried $CONFIG_OPTION=$CONFIG_VALUE But I am getting an error on this line as './Build.bash: line 137: VENDOR_NAME="Default_Vendor": command not found' Thanks.

    Read the article

  • Global Import Aliasing in .NET

    - by Josh Stodola
    Using import aliasing in a single class, we can reference class library namespaces by assigning our own custom alias like this: Imports Db = Company.Lib.Data.Objects And then we are able to reference the classes inside of Company.Lib.Data.Objects by using the Db alias that we assigned. Is it possible to do this at the global level so that the alias is applied to the entire solution instead of the given file? Currently, we are working with web applications, so I was hoping we could add something to web.config, but I am also interested in whether or not this is possible with windows forms, console apps, and/or class libraries.

    Read the article

  • Global Import/using Aliasing in .NET

    - by Josh Stodola
    Using import aliasing in a single class, we can reference class library namespaces by assigning our own custom alias like this: ' VB Imports Db = Company.Lib.Data.Objects // C# using Db = Company.Lib.Data.Objects; And then we are able to reference the classes inside of Company.Lib.Data.Objects by using the Db alias that we assigned. Is it possible to do this at the global level so that the alias is applied to the entire solution instead of the given file? Currently, we are working with web applications, so I was hoping we could add something to web.config, but I am also interested in whether or not this is possible with windows forms, console apps, and/or class libraries.

    Read the article

  • How to define an alias in fish shell?

    - by armandino
    I would like to define some aliases in fish. Apparently it should be possible to define them in ~/.config/fish/functions but they don't get auto loaded when I restart the shell. Any ideas? p.s. if anyone is using or has used fish in the past I'd be interested to hear your comments as to whether it offers anything that bash does not.

    Read the article

  • Unix list absolute file name

    - by Matthew Adams
    Given an arbitrary single argument representing a file (or directory, device, etc), how do I get the absolute path of the argument? I've seen many answers to this question involving find/ls/stat/readlink and $PWD, but none that suits my need. It looks like the closest answer is ksh's "whence" command, but I need it to work in sh/bash. Assume a file, foo.txt, is located in my home directory, /Users/matthew/foo.txt. I need the following behavior, despite what my current working directory is (I'm calling the command "abs"): (PWD is ~) $ abs foo.txt /Users/matthew/foo.txt $ abs ~/foo.txt /Users/matthew/foo.txt $ abs ./foo.txt /Users/matthew/foo.txt $ abs /Users/matthew/foo.txt /Users/matthew/foo.txt What would "abs" really be? TIA, Matthew

    Read the article

  • How can I kill and wait for background processes to finish in a shell script when I Ctrl+C it?

    - by slipheed
    I'm trying to set up a shell script so that it runs background processes, and when I ctrl+C the shell script, it kills the children, then exits. The best that I've managed to come up with is this. It appears that kill 0 -INT also kills the script before the wait happens, so the shell script dies before the children complete. Any ideas on how I can make this shell script wait for the children to die after sending INT? #!/bin/bash trap 'killall' INT killall() { echo **** Shutting down... **** kill 0 -INT wait # Why doesn't this wait?? echo DONE } process1 & process2 & process3 & cat # wait forever

    Read the article

  • OSX Lion - sh: mysql command not found

    - by mkk
    I have pretty simple issue I believe. I have successfully installed mysql etc. I do not have any problems with running "mysql" command from terminal [ bash ]. Suddenly, when my application tried to run mysql command I got error: sh: mysql: command not found.. In terminal, when I type sh and then mysql I can log in to mysql without any problems. I have added mysql to PATH in .bash_profile and I suspect this is why sh cannot see it. I have cp .bash_profile to .profile but it did not do the trick, any ideas how can I fix this issue?

    Read the article

  • Linux Mint something wrong with my .bashrc

    - by user2309862
    The path of my .basrc file is /home/vamsi/.bashrc It is weird that my file has nothing but the path I set. I think I am using a file at the wrong location or that I have lost my .bashrc file as none of the environment variables set here seem to work. #ANDROID_DEV ANDROID_HOME=/opt/android-sdk-linux export ANDROID_HOME PATH= $PATH:$ANDROID_SDK_HOME/tools export PATH PATH=$PATH:$ANDROID_HOME/platform-tools export PATH PATH=$PATH:$ANDROID_HOME/build-tools export PATH #MAVEN-PATH M2_HOME=/opt/apache-maven-3.1.0 export M2_HOME M2=$PATH:$M2_HOME/bin export M2 I was prompted to install maven2 in order to use mvn, but the android command cannot be found. Could you please help me find a solution to this issue. EDIT: Meanwhile,I tried this: export PATH=${PATH}:/opt/android-sdk-linux/platform-tools export PATH=${PATH}:/opt/android-sdk-linux/tools Now,the output of $PATH echoes: bash: /usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/opt/android-sdk-linux/platform-tools:/opt/android-sdk-linux/build-tools: No such file or directory

    Read the article

  • combining sed with xargs to obtain a source and output file name

    - by Lytithwyn
    I have a situation where I have some input files like this: M2U0001.MPG M2U0180.MPG And I want to run a command (in a bash shell) on each similarly named file in the directory. I'd like the current file name to be given to this command as an input and a modified version of the filename to be given as an output file. Here's an example: ffmpeg -i M2U0001.MPG M2U0001_fixed.MPG I had the idea of using xargs and sed, but this is as far as I got: ls -1 *.MPG | xargs -I{} ffmpeg -i {} `echo {} | sed -r 's/[0-9]{2,}/&_fixed/'` But this results in the original filename being output in both positions. Am I totally going about this the wrong way? I found that if I echo the filename directly to the embedded chunk like this it works: echo M2U0001.MPG | sed -r 's/[0-9]{2,}/&_fixed/'

    Read the article

  • Open Google Chrome Specific Profile From Command Line Mac

    - by gradedcatfood
    I have been trying to open Google Chrome from command line but with no luck! I have tried How do I start Chrome using a specified "user profile"? My goal is to open Google Chrome with a specific profile such as "profile 1", "profile 2", or "Default" from the command line, using bash to be specific, on my Mac. UPDATE: 6/3/14 Got this to work BUT only works when opening chrome for the first time open -a Google\ Chrome --args --"profile-directory"="Profile 1" So How do you get --args to be accepted AFTER google chrome as already been launched??

    Read the article

  • Msys cd .. command takes me to home directory instead of parent

    - by Adrian
    I'm using Msys on Windows 7 with what I believe to be a Bash shell. I want to navigate the following directory structure: Drive (M:) +--- Coding +--- CPP +--- projects +--- other_folder_1 +--- other_folder_2 My fstab file contains the following line: M:/Coding/CPP/projects/ /home/Adrian/ ... which makes the projects folder my starting directory when opening the shell. Unfortunately when I try to cd .. out of projects, I end up in /home instead of CPP. I imagine this might be related to what I did in the fstab file. Is there any way for me to retain the projects folder as my starting directory while being able to cd into its parent directories?

    Read the article

  • Bootstrap a debian build environment and build source packages with no root privileges

    - by Erwan Queffélec
    On debian squeeze, I am trying to do the following : fetch sources package from the wheezy source repository bootstrap a squeeze chroot for several architectures build the packages for several architectures (i386, amd64 + all and any) I want both the fetching, bootstrapping and build operation to be scriptable, repeatable, and run as a normal user. For the environment setup, I want to make as little use of the root account as possible (install the necessary dependencies, and maybe some visudo stuff). If possible I would like to avoid using a VM (pbuilder with user mode linux) So far I have tried several things with pbuilder (require root), debootstrap (require root) with little success. Here is an example script of what I want to do (does not work): #/bin/bash set -e set -x this=`readlink -f $0` this_dir=`dirname $this` archs='i386 amd64 any all' pushd $this_dir/src # I actually want the following line to work with a repo that # is not in /etc/apt/sources.list but that is another question apt-get source cyrus-imapd-2.4 popd for arch in $archs do build_dir=$this_dir/build/$arch/ pbuilder --create --configfile $build_dir/pbuilderrc --buildresult $build_dir/ pbuilder --build --configfile $build_dir/pbuilderrc --buildresult \ $build_dir/ $this_dir/src/*.dsc # of course I want to use the .dput.cf in /home/myuser/ # and not in /root/ dput $build_dir/$arch/*.changes done

    Read the article

  • How to execute with /bin/false shell

    - by Amar
    I am trying to setup per-user fastcgi scripts that will run each on a different port and with a different user. Here is example of my script: #!/bin/bash BIND=127.0.0.1:9001 USER=user PHP_FCGI_CHILDREN=2 PHP_FCGI_MAX_REQUESTS=10000 etc... However, if I add user with /bin/false (which I want, since this is about to be something like shared hosting and I don't want users to have shell access), the script is run under 1001, 1002 'user' which, as my Google searches showed, might be a security hole. My question is: Is it possible to allow user(s) to execute shell scripts but disable them so they cannot log in via SSH?

    Read the article

  • Running scripts from another directory

    - by Desmond Hume
    Quite often, the script I want to execute is not located in my current working directory and I don't really want to leave it. Is it a good practice to run scripts (BASH, Perl etc.) from another directory? Will they usually find all the stuff they need to run properly? If so, what is the best way to run a "distant" script? Is it . /path/to/script or sh /path/to/script and how to use sudo in such cases? This, for example, doesn't work: sudo . /path/to/script

    Read the article

  • Ctrl+Z and fg to append commands

    - by avilella
    I would like to know what is the behaviour of Ctrl+Z and fg in bash when wanting to append commands to be executed after a running command has finished. For example, in the sequence for commands below, I would expect the console to display "1", then "2", then "3", then "4", but I only get the last command, echo 4, after sleep 30 finishes: avilella@magneto:~$ sleep 30 && echo 1 ^Z [1]+ Stopped sleep 30 avilella@magneto:~$ fg && sleep 5 && echo 2 sleep 30 ^Z [1]+ Stopped sleep 30 avilella@magneto:~$ fg && sleep 5 && echo 3 sleep 30 ^Z [1]+ Stopped sleep 30 avilella@magneto:~$ fg && sleep 5 && echo 4 sleep 30 4 Any ideas?

    Read the article

  • run or send a command to a tmux pane in a running tmux session

    - by cjroebuck
    I want to write a shell script which will attach to a named tmux session, select a window (or pane) in that session and run a command in that selected window (or pane). How do I do this from a bash script? I know tmux new-window -n:mywindow 'exec something' allows you to send commands to a freshly created window. But I need something like tmux select-window -t:0 'my command' I suppose I could use send-keys but seems like their should be something that takes a command or list of commands that get run.

    Read the article

< Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >