Search Results

Search found 10550 results on 422 pages for 'syntax rules'.

Page 56/422 | < Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >

  • Effects of the `extern` keyword on C functions

    - by Elazar Leibovich
    In C I did not notice any effect of the extern keyword used before function declaration. At first I thougth that when defining extern int f(); in a single file forces you to implement it outside of the files scope, however I found out that both extern int f(); int f() {return 0;} And extern int f() {return 0;} Compiles just fine, with no warnings from gcc. I used gcc -Wall -ansi, he wouldn't even accept // comments. Are there any effects for using extern before function definitions? Or is it just an optional keyword with no side effects for functions. In the latter case I don't understand why did the standard designers chose to litter the grammar with superfluous keywords. EDIT: to clarify, I know there's usage for extern in variables, but I'm only asking about extern in functions.

    Read the article

  • How to change out-of-focus text selection color in Xcode?

    - by Jackson
    Okay, I'll bite. I've got really pleasant code/window colors set up in Xcode. Ordinarily, my selection color is very visible. When I am doing a project search and iterating through the results, however, the results list stays in focus and the found text remains out of focus, using a different background color. This color is extremely hard to detect, especially when the text is embedded in a larger code block and the view is shifting around as it scrolls to the results. Here's an example: Left side is in focus (just normal selection), right side is out of focus (during project find) Often it takes a few seconds to find where the heck the selected text is. Unless I'm just missing it, Xcode seems to offer no way to change this particular selection color. Interestingly, it also doesn't seem to follow the selection color from the Appearance panel. Does anyone know a way to change this color or force it to be more visible, short of changing my entire color scheme around?

    Read the article

  • Problem with a SQL statement

    - by benwad
    I'm trying to enter values into a database table using a form and a PHP function. The PHP seems to be fine as the SQL statement it creates looks okay, but the database always throws up an error. This is the SQL statement that my code has generated (with arbitrary values): INSERT INTO Iteminfo ('itemName', 'itemSeller', 'itemCategory', 'itemDescription', 'itemPrice', 'itemPostage', 'itemBegin', 'itemEnd', 'buynow', 'itemPicture') values ('gorillaz album', 'ben', 'music', 'new one ', '5.00', '1.00', '2010-03-15 14:59:51', '2010-03-16 14:59:51', '0', 'http://www.thefader.com/wp-content/uploads/2010/01/gorillaz-plastic-beach.jpg') This throws up an error both when I use the PHP function to evaluate the query and also when I use phpMyAdmin to enter the query manually. However, I can't see anything wrong with it. Can anyone shed some light on this? All of the fields are VARCHAR values, except for itemPrice and itemPostage (which are stored as DECIMAL(4,2)) and the itemBegin and itemEnd, which are stored as DATETIMEs.

    Read the article

  • Which syntax is better for return value?

    - by Omar Kooheji
    I've been doing a massive code review and one pattern I notice all over the place is this: public bool MethodName() { bool returnValue = false; if (expression) { // do something returnValue = MethodCall(); } else { // do something else returnValue = Expression; } return returnValue; } This is not how I would have done this I would have just returned the value when I knew what it was. which of these two patterns is more correct? I stress that the logic always seems to be structured such that the return value is assigned in one plave only and no code is executed after it's assigned.

    Read the article

  • jQuery: jquery form plugin syntax?

    - by k00k
    I'm using jquery with the jquery form plugin. I read through a bunch of posts, the docs, etc., and I'm still having trouble with what I believe to be simple. I have a form with some simple text inputs and a couple textareas, and I have this link that I want to trigger submission of that form to a specific method (/email): <a id="email-data">Send Email</a> and this jquery in doc ready: $('#email-data').click(function() { var options = { url: '/email/', success: alert('Email sent.') }; $('#report-giftcard-sales-form').ajaxSubmit(options); }); So I would expect it to submit to my /email method, but no such luck. Currently I just have the /email method logging a debug message, so it's as simple as can be. Any help is greatly appreciated.

    Read the article

  • Php what does <<< mean ?

    - by Doodle
    In the following code from http://us2.php.net/manual/en/language.oop5.properties.php what does the <<< symbol mean? <?php class SimpleClass { // invalid property declarations: public $var1 = 'hello ' . 'world'; public $var2 = <<<EOD hello world EOD; public $var3 = 1+2; public $var4 = self::myStaticMethod(); public $var5 = $myVar; // valid property declarations: public $var6 = myConstant; public $var7 = array(true, false); // This is allowed only in PHP 5.3.0 and later. public $var8 = <<<'EOD' hello world EOD; } ?>

    Read the article

  • codemirror fails when adding </textarea> tag inside it

    - by Jorre
    I'm using codemirror http://marijn.haverbeke.nl/codemirror/ to let users create their own web templates inside a web application. Codemirror works great, except for the time that users have put a tag inside their source code. When I load that up inside code mirror, it breaks everything in the source code that follows after because it thinks my codemirror text area is closed. I'm using the following way to launch codemirror: CodeMirror.fromTextArea('code') It works great on my existing textarea "code" except when users add inside their templates (in the codemirror textarea). Any help is much appreciated!

    Read the article

  • Understanding syntax in c#

    - by user279521
    I am hoping someone can help me understand what is going on in the code line below: Table t = (Table)Page.FindControl("Panel1").FindControl("tbl"); I understand Page.FindControl("Panel1").FindControl("tbl"); Why is there a (Table) before the Page.FindControl?

    Read the article

  • Can any body help to split php source code

    - by joe-on-wp
    hi, can any body help me on separating this example of data that i need to parse and seperate text just like PHPDoc. It is PHP source code. The example string : function one_to_tree() { //bla bla bla return FALSE; } function two_to_tree() { //bla bla bla return FALSE; } function three_to_tree() { if ($sample){ //bla bla bla } return FALSE; } can anybody help me how to seperate above string based on "function" word and create and array. Thank you

    Read the article

  • problems with chili source code highlighter (mysql)

    - by jason
    I am using Chili source code highlighter it works fine with php source using php as the class. But when i change it to mysql it doesnt highlight any SQL code i also tried sql as the classname, i double checked the recipes' and there is a mysql recipes in there. ... What could i be doing wrong? <pre><code id="code" class="php"></code></pre>

    Read the article

  • ruby send vs __send__

    - by jaydel
    I understand the concept of some_instance.send but I'm trying to figure out why you can call this both ways? The Ruby Koans imply that there is some reason beyond providing lots of different ways to do the same thing and I'm wrestling with figuring this out. Here are the two examples of usage more concretely class Foo def bar? true end end foo = Foo.new foo.send(:bar?) foo.send(:bar?) Anyone have any idea about this? thanks in advance!

    Read the article

  • Retrieving data from enumerated JSON sub arrays in Javascript without getJSON

    - by Archie Ec
    I'm new to JSON and ajax, but i'm trying to access data in an array where the items are enumerated in a sub array within another sub array. So, I can access without issues data.items[0].details.specs.name data.items[0].details.specs.id etc But I run into problems with I try to access something like data.items[0].details.specs[1].name data.items[0].details.specs[1].id data.items[0].details.specs[2].name data.items[0].details.specs[2].id etc Can anyone point me in the right direction on how to access this second aspect? Thanks.

    Read the article

  • Passing a comparator syntax help in Java

    - by Crystal
    I've tried this a couple ways, the first is have a class that implements comparator at the bottom of the following code. When I try to pass the comparat in sortListByLastName, I get a constructor not found error and I am not sure why import java.util.*; public class OrganizeThis implements WhoDoneIt { /** Add a person to the organizer @param p A person object */ public void add(Person p) { staff.put(p.getEmail(), p); //System.out.println("Person " + p + "added"); } /** * Remove a Person from the organizer. * * @param email The email of the person to be removed. */ public void remove(String email) { staff.remove(email); } /** * Remove all contacts from the organizer. * */ public void empty() { staff.clear(); } /** * Find the person stored in the organizer with the email address. * Note, each person will have a unique email address. * * @param email The person email address you are looking for. * */ public Person findByEmail(String email) { Person aPerson = staff.get(email); return aPerson; } /** * Find all persons stored in the organizer with the same last name. * Note, there can be multiple persons with the same last name. * * @param lastName The last name of the persons your are looking for. * */ public Person[] find(String lastName) { ArrayList<Person> names = new ArrayList<Person>(); for (Person s : staff.values()) { if (s.getLastName() == lastName) { names.add(s); } } // Convert ArrayList back to Array Person nameArray[] = new Person[names.size()]; names.toArray(nameArray); return nameArray; } /** * Return all the contact from the orgnizer in * an array sorted by last name. * * @return An array of Person objects. * */ public Person[] getSortedListByLastName() { PersonLastNameComparator comp = new PersonLastNameComparator(); Map<String, Person> sorted = new TreeMap<String, Person>(comp); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; } private Map<String, Person> staff = new HashMap<String, Person>(); public static void main(String[] args) { OrganizeThis testObj = new OrganizeThis(); Person person1 = new Person("J", "W", "111-222-3333", "[email protected]"); Person person2 = new Person("K", "W", "345-678-9999", "[email protected]"); Person person3 = new Person("Phoebe", "Wang", "322-111-3333", "[email protected]"); Person person4 = new Person("Nermal", "Johnson", "322-342-5555", "[email protected]"); Person person5 = new Person("Apple", "Banana", "123-456-1111", "[email protected]"); testObj.add(person1); testObj.add(person2); testObj.add(person3); testObj.add(person4); testObj.add(person5); System.out.println(testObj.findByEmail("[email protected]")); System.out.println("------------" + '\n'); Person a[] = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("------------" + '\n'); a = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("SORTED" + '\n'); a = testObj.getSortedListByLastName(); for (Person b : a) { System.out.println(b); } System.out.println(testObj.getAuthor()); } } class PersonLastNameComparator implements Comparator<Person> { public int compare(Person a, Person b) { return a.getLastName().compareTo(b.getLastName()); } } And then when I tried doing it by creating an anonymous inner class, I also get a constructor TreeMap cannot find symbol error. Any thoughts? inner class method: public Person[] getSortedListByLastName() { //PersonLastNameComparator comp = new PersonLastNameComparator(); Map<String, Person> sorted = new TreeMap<String, Person>(new Comparator<Person>() { public int compare(Person a, Person b) { return a.getLastName().compareTo(b.getLastName()); } }); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; }

    Read the article

  • "Socket operation on non-socket" error due to strange syntax

    - by Robert S. Barnes
    I ran across the error Socket operation on non-socket in some of my networking code when calling connect and spent a lot of time trying to figure out what was causing it. I finally figured out that the following line of code was causing the problem: if ((sockfd = socket( ai->ai_family, ai->ai_socktype, ai->ai_protocol) < 0)) { See the problem? Here's what the line should look like: if ((sockfd = socket( ai->ai_family, ai->ai_socktype, ai->ai_protocol)) < 0) { What I don't understand is why the first, incorrect line doesn't produce a warning. To put it another way, shouldn't the general form: if ( foo = bar() < baz ) do_something(); look odd to the compiler, especially running with g++ -Wall -Wextra? If not, shouldn't it at least show up as "bad style" to cppcheck, which I'm also running as part of my compile?

    Read the article

  • What does the '&' operator do in C++?

    - by rascher
    n00b question. I am a C guy and I'm trying to understand some C++ code. I have the following function declaration: int foo(const string &myname) { cout << "called foo for: " << myname << endl; return 0; } How does the function signature differ from the equivalent C: int foo(const char *myname) Is there a difference between using string *myname vs string &myname? What is the difference between & in C++ and * in C to indicate pointers? Similarly: const string &GetMethodName() { ... } What is the & doing here? Is there some website that explains how & is used differently in C vs C++?

    Read the article

  • postgres counting one record twice if it meets certain criteria

    - by Dashiell0415
    I thought that the query below would naturally do what I explain, but apparently not... My table looks like this: id | name | g | partner | g2 1 | John | M | Sam | M 2 | Devon | M | Mike | M 3 | Kurt | M | Susan | F 4 | Stacy | F | Bob | M 5 | Rosa | F | Rita | F I'm trying to get the id where either the g or g2 value equals 'M'... But, a record where both the g and g2 values are 'M' should return two lines, not 1. So, in the above sample data, I'm trying to return: $q = pg_query("SELECT id FROM mytable WHERE ( g = 'M' OR g2 = 'M' )"); 1 1 2 2 3 4 But, it always returns: 1 2 3 4

    Read the article

  • Ruby: change each value in a hash with something like #collect for arrays?

    - by Adam Nonymous
    Hi! I'd like to replace each value in a hash with value.some_method. For example in a simple hash {"a" = "b", "c" = "d"} every value should be .upcase-d so it looks like {"a" = "B", "c" = "D"}. I tried #collect and #map but always just get arrays back. Is there an 'elegant' way to do this? Thanks in advance, Adam Nonymous UPDATE: Damn, I forgot: The hash is in an instance variable which should not be changed. I need a new hash with the changed values, but would prefer not to define that variable explicitly and then loop over the hash filling it. Something like new_hash = hash.magic {...} ;)

    Read the article

  • Why does one of these statements compile in Scala but not the other?

    - by Jeff
    (Note: I'm using Scala 2.7.7 here, not 2.8). I'm doing something pretty simple -- creating a map based on the values in a simple, 2-column CSV file -- and I've completed it easily enough, but I'm perplexed at why my first attempt didn't compile. Here's the code: // Returns Iterator[String] private def getLines = Source.fromFile(csvFilePath).getLines // This doesn't compile: def mapping: Map[String,String] = { Map(getLines map { line: String => val pairArr = line.split(",") pairArr(0) -> pairArr(1).trim() }.toList:_*) } // This DOES compile def mapping: Map[String,String] = { def strPair(line: String): (String,String) = { val pairArr = line.split(",") pairArr(0) -> pairArr(1).trim() } Map(getLines.map( strPair(_) ).toList:_*) } The compiler error is CsvReader.scala:16: error: value toList is not a member of (St ring) = (java.lang.String, java.lang.String) [scalac] possible cause: maybe a semicolon is missing before `value toList'? [scalac] }.toList:_*) [scalac] ^ [scalac] one error found So what gives? They seem like they should be equivalent to me, apart from the explicit function definition (vs. anonymous in the nonworking example) and () vs. {}. If I replace the curly braces with parentheses in the nonworking example, the error is "';' expected, but 'val' found." But if I remove the local variable definition and split the string twice AND use parens instead of curly braces, it compiles. Can someone explain this difference to me, preferably with a link to Scala docs explaining the difference between parens and curly braces when used to surround method arguments?

    Read the article

< Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >