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  • addSubview and autosizing

    - by neoneye
    How does one add views to a window, so that the views are resized to fit within the window frame? The problem I'm making a sheet window containing 2 views, where only one of them is visible at a time, so it's important that the views have the same size as the window. My problem is that either view0 fits correctly and view1 doesn't or the other way around. I can't figure out how to give them the same size as the window. Possible solution I could just make sure that both views have precisely the same size within Interface Builder, then it would work. However I'm looking for a way to do this programmatically. Screenshot of view0 Below you can see the autoresizing problem in the top and the right side, where the view is somehow clipped. Screenshot of view1 This view is resized correctly. Here is my code Can the views be resized before adding them to the window. Or is it better to do as I do now where the views are added one by one while changing the window frame. How do you do it? NSView* view0 = /* a view made with IB */; NSView* view1 = /* another view made with IB */; NSWindow* window = [self window]; NSRect window_frame = [window frame]; NSView* cv = [[[NSView alloc] initWithFrame:window_frame] autorelease]; [window setContentView:cv]; [cv setAutoresizesSubviews:YES]; // add subview so it fits within the contentview frame { NSView* v = view0; [v setHidden:YES]; [v setAutoresizesSubviews:NO]; [cv addSubview:v]; [v setFrameOrigin:NSZeroPoint]; [window setFrame:[v frame] display:NO]; [v setAutoresizesSubviews:YES]; } // add subview so it fits within the contentview frame { NSView* v = view1; [v setHidden:YES]; [v setAutoresizesSubviews:NO]; [cv addSubview:v]; [v setFrameOrigin:NSZeroPoint]; [window setFrame:[v frame] display:NO]; [v setAutoresizesSubviews:YES]; } // restore original window frame [window setFrame:window_frame display:YES]; [view0 setHidden:NO]; [view1 setHidden:YES];

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  • mysql enum performance: is enum slower than INT

    - by JP19
    Hi, Is it better to have a field status enum('active', 'hidden', 'deleted') OR status tinyint(3) with a lookup table. Assume that status can take only one value at a time. In particular, I am interested in knowing, are operations on enum significantly slower than or as fast as operations on int ? There is a related question on SO Mysql: enum confusion but i) It does not discuss performance at all ii) There is very little explanation on WHY one approach is better than the other. regards, JP

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  • systray gadget to start stop tomcat

    - by opensas
    I'd like to know if anybody knows of any systray applet to control tomcat service con windows xp... apache installs its own, and there's one for mysql in the mysql gui tools... so the only one I'm missing is tomcat... thanks a lot

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  • Why does Windows 7 always automatically change the input or keyboard language?

    - by B-Ball
    I am wondering why Windows 7 always automatically changes my input or keyboard language. I've a notebook with an integrated QWERTY keyboard English (United States). Traveling, I use that one but, additionally, I've my own as well as a much better keyboard at home which is a QWERTZ keyboard German (Germany). Thus, being at home, I'd like to use my QWERTZ keyboard. Unfortunately, Windows 7 does not play along at this one. Every time, I start up my notebook, it is usually set to English (United States) but that's not the problem. In case, I'd use my notebook QWERTY keyboard English (United States), that's fine. However, if I start up my notebook and I'd like to use my QWERTZ keyboard German (Germany), I usually press ALT + Left Shift in order to switch from English (United States) to German (Germany) and Windows 7 switches the input language but only for the program that is currently open. If my input language is set to German (Germany) and I, e.g., open NotePad, Windows 7 automatically switches my input language to English (United States). This is very annoying since I've to change the input or keyboard language to German (Germany) every time I open up a new program. Why doesn't Windows 7 stay with one input language if I changed it manually by pressing ALT + Left Shift? Why doesn't the manual change of the input or keyboard language apply for the whole Windows 7? Why does it only affect the currently opened program? Since I've two keyboards with two different layouts, I seriously need to have both of the keyboards languages installed. I tried both of the below settings in order to find a solution for my problem. Currently, I am using the first option, two input languages. First option: two input languages: Second option: two keyboard languages:

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  • Cassandra API equivalent of "SELECT ... FROM ... WHERE id IN ('...', '...', '...');"

    - by knorv
    Assume the following data set: id age city phone == === ==== ===== alfred 30 london 3281283 jeff 43 sydney 2342734 joe 29 tokyo 1283881 kelly 54 new york 2394929 molly 20 london 1823881 rob 39 sydney 4928381 To get the following result set .. id age phone == === ===== alfred 30 3281283 joe 29 1283881 molly 20 1823881 .. using SQL one would issue .. SELECT id, age, phone FROM dataset WHERE id IN ('alfred', 'joe', 'molly'); What is the corresponding Cassandra API call that would yield the same result set in one command?

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  • Checking jQuery AJAX Request Status

    - by mTuran
    Hi, i do 2 different ajax request via jQuery and i have to check the other one is active or not. How can i do that ? one of example from my ajax requests: active_project_categories_ajax = $.ajax( { url: "/ajax/get_skill_list", dataType: 'json', ...... }); i need something like that: active_project_categories_ajax.status()

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  • Emacs comment-region in C mode

    - by Kinopiko
    In GNU Emacs, is there a good way to change the comment-region command in C mode from /* This is a comment which extends */ /* over more than one line in C. */ to /* This is a comment which extends over more than one line in C. */ ? I have tried (setq comment-multi-line t) but this does not help. There is a section on multi-line comments in the Emacs manual, but it does not mention anything.

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  • Mysql ndb cluster - node restart.

    - by Arafat
    Hi guys! I just setup a mysql cluster on a fairly decent baby (IBM x3650 M3) with 24GB memory, xeon 6core, SAS 6Gbps HDD. Running Debian Lenny 5. 64bits. Ndb version is 7.1.9a. Our database size on MyISAM is around 3.2 GB. Ndb_size estimation is 58GB for ndbengine. A little info about my database is as follows. 150 common tables for global purpose. 130 tables for each clients. So it goes like this, 130 x 115(clients) = 14950 tables. Is it normal or usual to have 14000 tables on one database? The reasons why we did this was, Easy maintenance and per client based customization. Now, the problem is, ndb cluster can only support, 20320 tables. But it can support 5,000,000,000 rows in one table if I'm not wrong. My real head ache is my cluster data node takes less than two minutes to startup with out any data. But as soon as convert my tables into ndb, that too only 2000 tables, data node takes at least 30 to 40 mins to start up. Is it normal? If I convertt all my tables into ndb, will it take even longer? Or let's say if consolidate my 14000 table's data into one, which is 130 tables, will it help? Or is there anything idiotically wrong which I'm doing? I'll attach my config.ini file soon. here's the simple overview of my config Datamemory = 14G Indexmemory = 3GB Maxnooftable = 14000 Maxnoofattributes = 78000 I'm just testing these values with 2000 tables first. Please advise, how to increase the start up speed. Please point out where I'm going wrong. Thanks in advance guys!

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  • How to configure VirtualBox server for performance at home

    - by BluJai
    I currently have two physical Ubuntu Server 10.10 servers at home: one serves as our firewall/router/DHCP/VPN server and the other performs double-duty as a file server and a VirtualBox host for an Ubuntu Desktop 10.10 machine which I use from remote connections (via NoMachine) for many thin-client purposes which are irrelevant to my question. What I'd like to accomplish is to consolidate the two physical machines into one which is a dedicated VirtualBox host (most likely running Ubuntu Server 10.10). Note that I'd like to stick with VirtualBox (if possible) because I'm most comfortable with it and use it on a daily basis at both home and work. Specifically, I plan to have one VM set up as file server, another as the firewall/router/DHCP/VPN (or possibly split those a bit) and a third, which is the only current VM (already VirtualBox), which is the thin-client host. My question comes down to performance and/or recommendations about the file server VM. The file server hosts about 6 terabytes of data across 4 drives. What I'd like to do is use raw disk access from the VM directly to the existing disks. However, I'm curious what performance advantage/disadvantage that would have as compared to using shared folders from the VM host and basically just have the whole drive served as a shared folder to the VM which would then serve it to the other machines on the network. I don't know if virtual disks would even work in this scenario and I certainly wouldn't want a drive to be filled with just a single file which is 1.5 TB (disk image). To add understanding of context, but not to get additional advice, I want to virtualize these machines because I intend to regularly use the snapshot capabilities of VirtualBox for the system disks (which will be virtual drives) of the VMs and I have some physical space/power needs to address (as I mentioned, this is at home).

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  • FileFinder using SQL

    - by James Morgan
    I was thinking of working on a project while I have some free time and this one looks pretty nice: http://mindprod.com/project/filefinder.html One thing I'm wondering about is that will it really be much faster compared to the regular windows search if I use SQL? I'm planning to use MySQL since it's open source. Also, do I need to be good at databases for this? I have basic knowledge about relational databases and can definitely make some SQL statements. Thanks.

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  • Evaluation of CTEs in SQL Server 2005

    - by Jammer
    I have a question about how MS SQL evaluates functions inside CTEs. A couple of searches didn't turn up any results related to this issue, but I apologize if this is common knowledge and I'm just behind the curve. It wouldn't be the first time :-) This query is a simplified (and obviously less dynamic) version of what I'm actually doing, but it does exhibit the problem I'm experiencing. It looks like this: CREATE TABLE #EmployeePool(EmployeeID int, EmployeeRank int); INSERT INTO #EmployeePool(EmployeeID, EmployeeRank) SELECT 42, 1 UNION ALL SELECT 43, 2; DECLARE @NumEmployees int; SELECT @NumEmployees = COUNT(*) FROM #EmployeePool; WITH RandomizedCustomers AS ( SELECT CAST(c.Criteria AS int) AS CustomerID, dbo.fnUtil_Random(@NumEmployees) AS RandomRank FROM dbo.fnUtil_ParseCriteria(@CustomerIDs, 'int') c) SELECT rc.CustomerID, ep.EmployeeID FROM RandomizedCustomers rc JOIN #EmployeePool ep ON ep.EmployeeRank = rc.RandomRank; DROP TABLE #EmployeePool; The following can be assumed about all executions of the above: The result of dbo.fnUtil_Random() is always an int value greater than zero and less than or equal to the argument passed in. Since it's being called above with @NumEmployees which has the value 2, this function always evaluates to 1 or 2. The result of dbo.fnUtil_ParseCriteria(@CustomerIDs, 'int') produces a one-column, one-row table that contains a sql_variant with a base type of 'int' that has the value 219935. Given the above assumptions, it makes sense (to me, anyway) that the result of the expression above should always produce a two-column table containing one record - CustomerID and an EmployeeID. The CustomerID should always be the int value 219935, and the EmployeeID should be either 42 or 43. However, this is not always the case. Sometimes I get the expected single record. Other times I get two records (one for each EmployeeID), and still others I get no records. However, if I replace the RandomizedCustomers CTE with a true temp table, the problem vanishes completely. Every time I think I have an explanation for this behavior, it turns out to not make sense or be impossible, so I literally cannot explain why this would happen. Since the problem does not happen when I replace the CTE with a temp table, I can only assume it has something to do with the functions inside CTEs are evaluated during joins to that CTE. Do any of you have any theories?

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  • Handler vs AsyncTask

    - by Steve
    I'm confused as to when one would choose AsyncTask over a Handler. Say I have some code I want to run every n seconds which will update the UI. Why would I choose one over the other?

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  • Get Date Strings for draw_calendar() Function

    - by Brandon
    I'm using the David Walsh PHP calendar script and need to format my date arguments like this: draw_calendar(7,2009); I want to get today's Month and Year as well as the next month and the month after that (so current month, plus one, plus one). How can I call the function three times in succession to generate these three calendars only knowing today's Month and Year? -Brandon

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  • pdf2swf using MAC OS Batch command or Apple script

    - by Garth Humphreys
    How do I write a batch process on the Mac for pdf2swf, I want to convert all pdfs in a folder into swf. But pdf2swf doesn't have a option to convert a folder of pdfs to swfs, you have to do it one at a time. I'm not sure how if I should use a Apple script or a Shell script, either one I'm not sure how to get or assign a file name variable. pdf2swf file_name_variable.pdf -o file_name_variable.swf -T 9 -f Thanks

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  • R Install/Update on Mac OS X (Snow Leopard): where does R put files during install/config?

    - by doug
    In sum, there's a stray preference-like file or two (probably just one) that i can't find. Here's the whole story: I recently attempted to update my R install from 2.10 to 2.11. As i have done before, i installed from source. I know that all of the dependencies are correctly installed and made available to R, because my prior install worked fine. When i upgraded to 2.11, i am unable to install packages (no exception thrown, it just doesn't appear to complete the install and is unresponsive so i have to quit + restart R. Given i install from source, there are any number of points in the process that i could have messed up. What i need to do now is "start over" which requires that i clear out my my prior install. I am having trouble doing that. There is still at least one preference file or something like that i can't find and one of these is causing the problem, so i need to find it and terminate it with extreme prejudice before i do a fresh install. Although i set a number of flags during the install, i have never opted out of the default install locations during the config step. There has to be one or more preference files still in my file structure (and that's also accessible to the new install of R) because after i follow all of the steps below, then do a fresh install, when i start R for the first time, some of my preferences have persisted (e.g., quartz settings, GUI background color, editor selection, etc.). Again, the problem is that i just cannot locate those files. Finally, the problem can't be that during my last install from source, i inadvertently caused a preference file to be sent to an off-spec location--because again, a fresh R install (whether from source or from the OS X binaries) is finding those files Here's what i've done prior to attempting a clean install of R: Removed files from these locations: ~/.RData ~/.RHistory /Applications/R64.app /Applications/R.app /Library/Frameworks/R.framework (i also removed all symlinks from these) Cleared all RAM and disk caches, in particular the directory where i know R caches: ~/Library/Caches/R* (in fact i've cleared this entire directory) Checked for all 'hidden' files in the OS X directories where login/startup files are often placed: /etc/ ~/ In addition, i've checked R-help, and i've also read through the relevant portions of 'R Installation and Administration'--no luck. I've also searched searched my file structure using the various bash utilities, which nearly always solves problems of this sort quite easily, but in this case obviously searching by name or even pattern is more problematic.

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  • Rails 3 on dreamhost?

    - by p33t3r
    I'd like to deploy a small Rails 3 app on dreamhost (just testing purposes, nothing serious) and I am wondering if anyone did it already... please chose one of I did it and it's super easy, here's how: ... Though I didn't try it, it should be easy, here's how: ... It's quite complicated, but this should get you started: .... NO WAI!!!1!one!1 Set it up on slicehost or another non-shared hosting or you'll die a painful death trying to force it on DH Thoughts?

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  • MVVM/WPF: Using a ObservableCollection<T> as a list in a domain model, is that good/bad ?

    - by msfanboy
    I have aggregated models like Customer:Order:Product. As my View is bound to the BillingViewModel which has a Property Customers of type ObservableCollection and ONE customer in this collection has a "list" of orders named ObservableCollection and ONE order in this collection has a "list" of products named ObservableCollection Well I need the ObservableCollection`s for databinding but should a domain model really have a ObservableCollection ? normally it has a List or IEnumerable ! Is this bad habit or having side effects?

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  • Physical-to-virtual for personal use

    - by Journeyman Geek
    One of my current projects involves reducing the number of old computers lying around. So far, the office systems have been downsized from 5 to 2. One system which had no data on it was dumped entirely, while three other identical boxes were consolidated into to one (I swap hard drives as needed and they just work(tm)). I want to make further cuts. The physical systems in question all run windows xp sp3, and were old Pentium 4s with 256 MB of RAM. Currently, I have got a VirtualBox running on another system. My intention is to migrate all services to that. We can assume that disk space and RAM on the host is not an issue. I'd rather not go with a client-server physical-to-virtual (P2V) method like what VirtualBox uses now. I have a few specific concerns as well - specifically whether I'd need to reactivate or sysprep for dissimilar hardware first. An offline tool for imaging (Windows or Linux) would not be an issue since the drives could be mounted onto another system I have anyway or I could use a LiveCD. What would be my options for P2V conversion, and what would I need to keep in mind when doing this?

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  • PHP Sort Array based on values in another.....

    - by Fearghal
    Need some help regarding array sorting.... I have two arrays. The main one (where the key is the user id) : $user[31] = 'Tom' $user[43] = 'Jane' and another array with the order they should be displayed (where key is the order and value is the user id) : $order[1] = 43 $order[2] = 31 How can I apply the ordering to the main array using the ordering one? Thanks guys!

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