Search Results

Search found 1661 results on 67 pages for 'peter stuart'.

Page 57/67 | < Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >

  • Anonymous user with proftpd on fedora

    - by stukerr
    Hi there, I am trying to setup an anonymous user account on our server to enable people to downlaod technical manuals for our products etc. and I would like this to be as secure as possible! I was just wondering if anyone knew a series of steps that will allow me to create an anonymous ftp account linked to a directory on the server that enables download only ? Also how could i make a corresponding ftp account with write priviledges to this account to allow people within our company to upload new files ? Sorry i'm a bit new to all this! Many Thanks, Stuart

    Read the article

  • Create manual IPSec policy on Window (like spdadd and add on Linux)

    - by hapalibashi
    Hello On Linux it is possible to create an a manual IPSec (no IKE etc) tunnel thus: spdadd 192.168.0.10/32[5066] 192.168.0.11/32[5064] udp -P in ipsec esp/transport//require; add 192.168.0.10 192.168.0.11 esp 2222 -m transport -E des-ede3-cbc "123456789012123456789012" -A hmac-md5 "1234567890123456"; I need to do the same on Windows. I am aware of netsh but I don't think its equivalent, I need to specific the SPI (thats the 2222 above) and this seems impossible. Any ideas or alternatives?! Thanks, Stuart.

    Read the article

  • BizTalk 2009 - The Scope of the Table Looping Functoid

    - by StuartBrierley
    When mapping in BizTalk you will find there are times when you need to map from flat and dispersed elemements in your source schema to a repeated record with child elements in your destination schema.  Below is an example of how you can make use of the Table Looping Functoid to bring together these flat elements and create your repeated group.  Although this example is purposely simple, I have previsouly encounted this issue on a much more complex scale when mapping the response from a credit scoring agency where all the applicant details were supplied in separate parts of a very flat schema. Consider the source and destination schemas as follows:   Although the Table Looping Functoid states that the first input must be a scoping element linked from a repeating group, you can actually also make use of a constant value.  In this case I know that the source schema always contains two people, so I set this to two. Then you need to set the number of columns in your table, in this case 2 (name and sex) and link all the required fields from the source schema. Following this you can configure the table. You can then add the Table Extractor functoids and complete the map. If you now validate this map you will see that BizTalk will warn you about the scoping link for the Table Looping Functoid, but this can be safely ignored. C:\Code\Developer Folders\Stuart Brierley\Test Mapping\TableLooping.btm: warning btm1071: A first input of the Table-Looping functoid must be a link from a Source Tree Node which acts as the scoping parameter. Testing the map will produce the following output:

    Read the article

  • GWB | 30 in 60 Update &ndash; Enrique is almost there!

    - by Staff of Geeks
    We are very close to having our first blogger to reach 30 posts, Enrique Lima.  Stuart Brierley is over the hump with 16 posts and Dave Campbell and Eric Nelson are definitely in the running.  If you don’t know what I am talking about, we are running a contest for our bloggers.  Anyone who blogs on Geekswithblogs who creates 30 posts from May 15th to July 13th will receive a custom Geekswithblogs.net t-shirt with their URL on the back.  This could be their Geekswithblogs.net address or their custom domain.  It is definitely not too late to get started and with TechEd or WWDC right around the corner, there is definitely a lot to talk about. Current Standings: Enrique Lima (28 posts) - http://geekswithblogs.net/enriquelima StuartBrierley (16 posts) - http://geekswithblogs.net/StuartBrierley Dave Campbell (12 posts) - http://geekswithblogs.net/WynApseTechnicalMusings Eric Nelson (10 posts) - http://geekswithblogs.net/iupdateable Christopher House (10 posts) - http://geekswithblogs.net/13DaysaWeek mbcrump (7 posts) - http://geekswithblogs.net/mbcrump Chris Williams (6 posts) - http://geekswithblogs.net/cwilliams Michael Stephenson (5 posts) - http://geekswithblogs.net/michaelstephenson Steve Michelotti (5 posts) - http://geekswithblogs.net/michelotti Liam McLennan (5 posts) - http://geekswithblogs.net/liammclennan Follow Us On Twitter: @StaffOfGeeks Technorati Tags: Geekswithblogs,30 in 60,Standings

    Read the article

  • What is the evidence that an API has exceeded its orthogonality in the context of types?

    - by hawkeye
    Wikipedia defines software orthogonality as: orthogonality in a programming language means that a relatively small set of primitive constructs can be combined in a relatively small number of ways to build the control and data structures of the language. The term is most-frequently used regarding assembly instruction sets, as orthogonal instruction set. Jason Coffin has defined software orthogonality as Highly cohesive components that are loosely coupled to each other produce an orthogonal system. C.Ross has defined software orthogonality as: the property that means "Changing A does not change B". An example of an orthogonal system would be a radio, where changing the station does not change the volume and vice-versa. Now there is a hypothesis published in the the ACM Queue by Tim Bray - that some have called the Bánffy Bray Type System Criteria - which he summarises as: Static typings attractiveness is a direct function (and dynamic typings an inverse function) of API surface size. Dynamic typings attractiveness is a direct function (and static typings an inverse function) of unit testing workability. Now Stuart Halloway has reformulated Banfy Bray as: the more your APIs exceed orthogonality, the better you will like static typing My question is: What is the evidence that an API has exceeded its orthogonality in the context of types? Clarification Tim Bray introduces the idea of orthogonality and APIs. Where you have one API and it is mainly dealing with Strings (ie a web server serving requests and responses), then a uni-typed language (python, ruby) is 'aligned' to that API - because the the type system of these languages isn't sophisticated, but it doesn't matter since you're dealing with Strings anyway. He then moves on to Android programming, which has a whole bunch of sensor APIs, which are all 'different' to the web server API that he was working on previously. Because you're not just dealing with Strings, but with different types, the API is non-orthogonal. Tim's point is that there is a empirical relationship between your 'liking' of types and the API you're programming against. (ie a subjective point is actually objective depending on your context).

    Read the article

  • Friday Stats

    - by jjg
    As some of you may have noticed, we've recently opened a new repository in the Code Tools project for small utilities which can be used to gather info about the OpenJDK code base and builds. 1 The latest addition is a utility for analyzing the class file versions in a collection of class files. I've posted an example set of results from analyzing the class files in an OpenJDK build on Linux. 2. Most of the files are version 52 files as you would expect, but there is a surprising number of version 51 and 50 files, as well as a handful of v45.3 files as well. Digging deeper, it turns out that Nashorn is still using version 51 class files, and the Serviceability Agent is still using version 50 class files and one 45.3 class file, leaving the remainder of the 45.3 class files coming from RMI. For more info on the different class file versions, see Joe Darcy's class file version decoder rIng. Thanks to Stuart Marks for planting the seed for the class file version tool. See the project page, repo, and mail archive. http://cr.openjdk.java.net/~jjg/cfv-summary/open/

    Read the article

  • Tip: Keeping the ADF Mobile PDF Guide up to date

    - by Chris Muir
    This is a little tip for customers using Oracle's ADF Mobile. If you're like me, it's possible you don't rely on the online HTML version of the Mobile Developer's Guide for ADF, but rather download a PDF version of the file to use locally (look to the "PDF" link to the top right of the guide).  For me the convenience of the PDF is it's faster, I can search the whole document easily, I can split read the document across two pages on my home monitor, if I lose my internet connection the document is still available, and it's easy to read on my iPad (especially on long haul flights to the US across the Pacific where there is no internet connection!). The trigger point for me to download the Oracle PDF documentation has always been on a new point release of JDeveloper.  However in the case of ADF Mobile, as an extension to JDeveloper it is releasing at a much faster and independent schedule to JDeveloper and this includes updates to the documentation. As such the 11.1.2.4.0 ADF Mobile PDF guide you have locally might be out of date and you should take the opportunity to download the latest version.  This is also particularly important for ADF Mobile as not only are many new features being added for each release and included in the new documentation, but the guide is under rapid improvement to clarify much of what has been written to date.  Our documentation teams are super responsive to suggestions on how to improve the guides and this often shows per point release. How do you tell you've the latest guide? Look to the document part number which right now is "E24475-03".  This is a unique ID per release for the document, the first part being the document number, and the part after the dash the revision number.  If the website document number has a higher revision number, time to download a new up to date PDF. One last thing to share, you can follow the ADF Mobile guide document manager Brian Duffield on Twitter to keep abreast of updates. Image courtesy of Stuart Miles / FreeDigitalPhotos.net

    Read the article

  • jqGrid tableToGrid "options" parameter

    - by Jimbo
    Basics Hi all, I have see the tableToGrid method (by Peter Romianowski) defined as tableToGrid(selector, options) on the jqGrid wiki, but cannot find anywhere that has documentation of the options Does anyone know about these or where to find them? More What Im actually trying to do is encase the resulting jqGrid in a form, which will submit the checkbox values that are in a column of the table. My problem is that the tableToGrid method appears to be removing the name property from the checkbox elements and hence they are not being submitted with the form post.

    Read the article

  • sorting two tables (full join)

    - by Ruslan
    i'm joining tables like: select * from tableA a full join tableB b on a.id = b.id But the output should be: row without null fields row with null fields in tableB row with null fields in tableA Like: a.id a.name b.id b.name 5 Peter 5 Jones 2 Steven 2 Pareker 6 Paul null null 4 Ivan null null null null 1 Smith null null 3 Parker

    Read the article

  • Capitalization of Person names in programming

    - by Albert
    Hey all, Is anyone aware of some code/rules on how to capitalize the names of people correctly? John Smith Johan van Rensburg Derrick von Gogh Ruby de La Fuente Peter Maclaurin Garry McDonald (these may not be correct, just some sample names and how the capitalization could be/work) This seems like a losing battle... If anyone has some code or rules on when and how to capitalize names, let me know :) Cheers, Albert

    Read the article

  • Find Shortest element in Array

    - by Ani
    I have a Array string[] names = { "Jim Rand", "Barry Williams", "Nicole Dyne", "Peter Levitt", "Jane Jones", "Cathy Hortings"}; Is there any way to find which is the shortest(Length wise) element in this array and then store rest of elements in a different array. Thanks, Ani

    Read the article

  • How do I run .class files on windows from command line?

    - by AndrejaKo
    Hi! I'm trying to run .class file from command line. It works when I manually move to the directory it's stored in, but when I try something like this: java C:\Peter\Michael\Lazarus\Main it says it can't find the main class. Is there any solution to this other than making a .jar file (I know that .jar is the best solution, but at this moment isn't the one I'm looking for)?

    Read the article

  • Multiple calendars on wordpress highlighting only specific categories

    - by zac
    Does anyone know of how, in wordpress, I could implement many calendars on a site, each only highlighting days that are within a specific category? I am hoping to setup multiple calendars, each tracking all of the events from their own cat. After researching for a while the best I could find was this thread: http://wordpress.org/support/topic/266627?replies=11 But it seems to peter out before there is ever a working solution

    Read the article

  • Wordpress as CMS, Without Using It As Website Platform

    - by swt
    What is the best method, if there is one, of using Wordpress as a CMS for users to input data while not actually building the website on the Wordpress platform? One possible solution I've found is using a PHP class called "WPGet" (http://peter.upfold.org.uk/projects/wpget) which fetches directly from the database.

    Read the article

  • Drawing many images inside UIImageView

    - by dusker
    Hi all, i'm looking for a way to draw multiple images (downloaded from a webservice) inside a single uiimageview. So it'd go like i downloaded image #1, and i'd like to draw it inside rect (0,0,100,100) then #2 at (0,100,100,100) etc. I'd like to then be able to take the entire composition and save it as an image in camera roll. thanks in advance for help greetings peter

    Read the article

  • django deployment apache

    - by Uszy Wieloryba
    I would like to create a python script, which will: Create a django project in the current directory. Fix settings.py, urls.py. Do syncdb Install new apache instance listening on specific port (command line argument), with WSGI configured to serve my project. I can't figure out how to do point 3. EDIT: Peter Rowell: I need the solution for both Linux and Windows I have root access This is a dedicated host Apache only

    Read the article

  • Approximate timings for various operations on a "typical desktop PC" anno 2010

    - by knorv
    In the article "Teach Yourself Programming in Ten Years" Peter Norvig (Director of Research, Google) gives the following approximate timings for various operations on a typical 1GHz PC back in 2001: execute single instruction = 1 nanosec = (1/1,000,000,000) sec fetch word from L1 cache memory = 2 nanosec fetch word from main memory = 10 nanosec fetch word from consecutive disk location = 200 nanosec fetch word from new disk location (seek) = 8,000,000 nanosec = 8 millisec What would the corresponding timings be for your definition of a typical PC desktop anno 2010?

    Read the article

  • save 20 users with one sql query?

    - by fayer
    i save a user like this in doctrine: $user = User(); $user->name = 'peter'; $user->save(); is there a way to save 20 users in one sql query? or do i have to loop the above code 20 times hence creating 20 sql queries? thanks

    Read the article

  • DHCPv6: Provide IPv6 information in your local network

    Even though IPv6 might not be that important within your local network it might be good to get yourself into shape, and be able to provide some details of your infrastructure automatically to your network clients. This is the second article in a series on IPv6 configuration: Configure IPv6 on your Linux system DHCPv6: Provide IPv6 information in your local network Enabling DNS for IPv6 infrastructure Accessing your web server via IPv6 Piece of advice: This is based on my findings on the internet while reading other people's helpful articles and going through a couple of man-pages on my local system. IPv6 addresses for everyone (in your network) Okay, after setting up the configuration of your local system, it might be interesting to enable all your machines in your network to use IPv6. There are two options to solve this kind of requirement... Either you're busy like a bee and you go around to configure each and every system manually, or you're more the lazy and effective type of network administrator and you prefer to work with Dynamic Host Configuration Protocol (DHCP). Obviously, I'm of the second type. Enabling dynamic IPv6 address assignments can be done with a new or an existing instance of a DHCPd. In case of Ubuntu-based installation this might be isc-dhcp-server. The isc-dhcp-server allows address pooling for IP and IPv6 within the same package, you just have to run to independent daemons for each protocol version. First, check whether isc-dhcp-server is already installed and maybe running your machine like so: $ service isc-dhcp-server6 status In case, that the service is unknown, you have to install it like so: $ sudo apt-get install isc-dhcp-server Please bear in mind that there is no designated installation package for IPv6. Okay, next you have to create a separate configuration file for IPv6 address pooling and network parameters called /etc/dhcp/dhcpd6.conf. This file is not automatically provided by the package, compared to IPv4. Again, use your favourite editor and put the following lines: $ sudo nano /etc/dhcp/dhcpd6.conf authoritative;default-lease-time 14400; max-lease-time 86400;log-facility local7;subnet6 2001:db8:bad:a55::/64 {    option dhcp6.name-servers 2001:4860:4860::8888, 2001:4860:4860::8844;    option dhcp6.domain-search "ios.mu";    range6 2001:db8:bad:a55::100 2001:db8:bad:a55::199;    range6 2001:db8:bad:a55::/64 temporary;} Next, save the file and start the daemon as a foreground process to see whether it is going to listen to requests or not, like so: $ sudo /usr/sbin/dhcpd -6 -d -cf /etc/dhcp/dhcpd6.conf eth0 The parameters are explained quickly as -6 we want to run as a DHCPv6 server, -d we are sending log messages to the standard error descriptor (so you should monitor your /var/log/syslog file, too), and we explicitely want to use our newly created configuration file (-cf). You might also use the command switch -t to test the configuration file prior to running the server. In my case, I ended up with a couple of complaints by the server, especially reporting that the necessary lease file wouldn't exist. So, ensure that the lease file for your IPv6 address assignments is present: $ sudo touch /var/lib/dhcp/dhcpd6.leases$ sudo chown dhcpd:dhcpd /var/lib/dhcp/dhcpd6.leases Now, you should be good to go. Stop your foreground process and try to run the DHCPv6 server as a service on your system: $ sudo service isc-dhcp-server6 startisc-dhcp-server6 start/running, process 15883 Check your log file /var/log/syslog for any kind of problems. Refer to the man-pages of isc-dhcp-server and you might check out Chapter 22.6 of Peter Bieringer's IPv6 Howto. The instructions regarding DHCPv6 on the Ubuntu Wiki are not as complete as expected and it might not be as helpful as this article or Peter's HOWTO. But see for yourself. Does the client get an IPv6 address? Running a DHCPv6 server on your local network surely comes in handy but it has to work properly. The following paragraphs describe briefly how to check the IPv6 configuration of your clients, Linux - ifconfig or ip command First, you have enable IPv6 on your Linux by specifying the necessary directives in the /etc/network/interfaces file, like so: $ sudo nano /etc/network/interfaces iface eth1 inet6 dhcp Note: Your network device might be eth0 - please don't just copy my configuration lines. Then, either restart your network subsystem, or enable the device manually using the dhclient command with IPv6 switch, like so: $ sudo dhclient -6 You would either use the ifconfig or (if installed) the ip command to check the configuration of your network device like so: $ sudo ifconfig eth1eth1      Link encap:Ethernet  HWaddr 00:1d:09:5d:8d:98            inet addr:192.168.160.147  Bcast:192.168.160.255  Mask:255.255.255.0          inet6 addr: 2001:db8:bad:a55::193/64 Scope:Global          inet6 addr: fe80::21d:9ff:fe5d:8d98/64 Scope:Link          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1 Looks good, the client has an IPv6 assignment. Now, let's see whether DNS information has been provided, too. $ less /etc/resolv.conf # Dynamic resolv.conf(5) file for glibc resolver(3) generated by resolvconf(8)#     DO NOT EDIT THIS FILE BY HAND -- YOUR CHANGES WILL BE OVERWRITTENnameserver 2001:4860:4860::8888nameserver 2001:4860:4860::8844nameserver 192.168.1.2nameserver 127.0.1.1search ios.mu Nicely done. Windows - netsh Per description on TechNet the netsh is defined as following: "Netsh is a command-line scripting utility that allows you to, either locally or remotely, display or modify the network configuration of a computer that is currently running. Netsh also provides a scripting feature that allows you to run a group of commands in batch mode against a specified computer. Netsh can also save a configuration script in a text file for archival purposes or to help you configure other servers." And even though TechNet states that it applies to Windows Server (only), it is also available on Windows client operating systems, like Vista, Windows 7 and Windows 8. In order to get or even set information related to IPv6 protocol, we have to switch the netsh interface context prior to our queries. Open a command prompt in Windows and run the following statements: C:\Users\joki>netshnetsh>interface ipv6netsh interface ipv6>show interfaces Select the device index from the Idx column to get more details about the IPv6 address and DNS server information (here: I'm going to use my WiFi device with device index 11), like so: netsh interface ipv6>show address 11 Okay, address information has been provided. Now, let's check the details about DNS and resolving host names: netsh interface ipv6> show dnsservers 11 Okay, that looks good already. Our Windows client has a valid IPv6 address lease with lifetime information and details about the configured DNS servers. Talking about DNS server... Your clients should be able to connect to your network servers via IPv6 using hostnames instead of IPv6 addresses. Please read on about how to enable a local named with IPv6.

    Read the article

  • creating objects in list

    - by prince23
    List myList = new List { new Users{ Name="Kumar", Gender="M", Age=75, Parent="All"}, new Users{ Name="Suresh",Gender="M", Age=50, Parent="Kumar"}, new Users{ Name="Bennette", Gender="F",Age=45, Parent="Kumar"}, new Users{ Name="kian", Gender="M",Age=20, Parent="Suresh"}, new Users{ Name="Nathani", Gender="M",Age=15, Parent="Suresh"}, new Users{ Name="Peter", Gender="M",Age=90, Parent="All"}, new Users{ Name="Mica", Age=56, Gender="M",Parent="Peter"}, new Users{ Name="Linderman", Gender="M",Age=51, Parent="Peter"}, new Users{ Name="john", Age=25, Gender="M",Parent="Mica"}, new Users{ Name="tom", Gender="M",Age=21, Parent="Mica"}, new Users{ Name="Ando", Age=64, Gender="M",Parent="All"}, new Users{ Name="Maya", Age=24, Gender="M",Parent="Ando"}, new Users{ Name="Niki Sanders", Gender="F",Age=2, Parent="Maya"}, new Users{ Name="Angela Patrelli", Gender="F",Age=3, Parent="Maya"}, }; now i need to format the data like here i need to check the parent based on the parent i will be creating objects under the parent objects now { Name="Kumar", Gender="M", Age=75, Parent="All" } this is the top level as a property Parent ="all" now under parent object kumar here we again create a new object to store these information under object(kumar who is the parent) new Users{ Name="Suresh",Gender="M", Age=50, Parent="Kumar"}, new Users{ Name="Bennette", Gender="F",Age=45, Parent="Kumar"}, what i need to do here is i need to check the parent based on the parent create further objects under it ex: i need to achive like this. looking for the syntax how i can do it. public class SampleProjectData { public static ObservableCollection<Product> GetSampleData() { DateTime dtS = DateTime.Now; ObservableCollection<Product> teams = new ObservableCollection<Product>(); teams.Add(new Product() { PDName = "Product1", OverallStartTime = dtS, OverallEndTime = dtS + TimeSpan.FromDays(3), }); Project emp = new Project() { PName = "Project1", OverallStartTime = dtS + TimeSpan.FromDays(1), OverallEndTime = dtS + TimeSpan.FromDays(6) }; emp.Tasks.Add(new Task() { StartTime = dtS, EndTime = dtS + TimeSpan.FromDays(2), TaskName = "John's Task 3" }); emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(3), EndTime = dtS + TimeSpan.FromDays(4), TaskName = "John's Task 2" }); teams[0].Projects.Add(emp); emp = new Project() { PName = "Project2", OverallStartTime = dtS + TimeSpan.FromDays(1.5), OverallEndTime = dtS + TimeSpan.FromDays(5.5) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(1), EndTime = dtS + TimeSpan.FromDays(4), TaskName = "Victor's Task" }); teams[0].Projects.Add(emp); emp = new Project() { PName = "Project3", OverallStartTime = dtS + TimeSpan.FromDays(2), OverallEndTime = dtS + TimeSpan.FromDays(5) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(1), EndTime = dtS + TimeSpan.FromDays(4), TaskName = "Jason's Task 1" }); emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(7), EndTime = dtS + TimeSpan.FromDays(9), TaskName = "Jason's Task 2" }); teams[0].Projects.Add(emp); teams.Add(new Product() { PDName = "Product2", OverallStartTime = dtS, OverallEndTime = dtS + TimeSpan.FromDays(3) }); emp = new Project() { PName = "Project4", OverallStartTime = dtS + TimeSpan.FromDays(0.5), OverallEndTime = dtS + TimeSpan.FromDays(3.5) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(1.5), EndTime = dtS + TimeSpan.FromDays(4), TaskName = "Vicky's Task" }); teams[1].Projects.Add(emp); emp = new Project() { PName = "Project5", OverallStartTime = dtS + TimeSpan.FromDays(2), OverallEndTime = dtS + TimeSpan.FromDays(6) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(2.2), EndTime = dtS + TimeSpan.FromDays(3.8), TaskName = "Oleg's Task 1" }); emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(5), EndTime = dtS + TimeSpan.FromDays(6), TaskName = "Oleg's Task 2" }); emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(8), EndTime = dtS + TimeSpan.FromDays(9.6), TaskName = "Oleg's Task 3" }); teams[1].Projects.Add(emp); emp = new Project() { PName = "Project6", OverallStartTime = dtS + TimeSpan.FromDays(2.5), OverallEndTime = dtS + TimeSpan.FromDays(4.5) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(0.8), EndTime = dtS + TimeSpan.FromDays(2), TaskName = "Kim's Task" }); teams[1].Projects.Add(emp); teams.Add(new Product() { PDName = "Product3", OverallStartTime = dtS, OverallEndTime = dtS + TimeSpan.FromDays(3) }); emp = new Project() { PName = "Project7", OverallStartTime = dtS + TimeSpan.FromDays(5), OverallEndTime = dtS + TimeSpan.FromDays(7.5) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(1.5), EndTime = dtS + TimeSpan.FromDays(4), TaskName = "Balaji's Task 1" }); emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(5), EndTime = dtS + TimeSpan.FromDays(8), TaskName = "Balaji's Task 2" }); teams[2].Projects.Add(emp); emp = new Project() { PName = "Project8", OverallStartTime = dtS + TimeSpan.FromDays(3), OverallEndTime = dtS + TimeSpan.FromDays(6.3) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(1.75), EndTime = dtS + TimeSpan.FromDays(2.25), TaskName = "Li's Task" }); teams[2].Projects.Add(emp); emp = new Project() { PName = "Project9", OverallStartTime = dtS + TimeSpan.FromDays(2), OverallEndTime = dtS + TimeSpan.FromDays(6) }; emp.Tasks.Add(new Task() { StartTime = dtS + TimeSpan.FromDays(2), EndTime = dtS + TimeSpan.FromDays(3), TaskName = "Stacy's Task" }); teams[2].Projects.Add(emp); return teams; } } above is an sample data where i am grouping them with static data in the same way i need **to for teh data which is cmg from DB and i need to store them list** all these three data are comig from different services. and i am storing them in a list now i have three tables data Product , Project, Task. all the data are coming from webservies. i have created three list where i am storing the data in list. List<Project>objpro= new List<Project>(); List<Product>objproduct= new List<Product>(); LIst<Task>objTask= new List<Task>(); **now what i need to do is i need to do the mapping between these tables. if you see above. i have object of Product under Product i have added object of Project and then under project object i have added task object.** now from the above data which is stored in the list i need to do the same mapping between class. and group the data. public class Product : INotifyPropertyChanged { public Product() { this.Projects = new ObservableCollection<Project>(); } public string PDName { get; set; } public ObservableCollection<Project> Projects { get; set; } private DateTime _st; public DateTime OverallStartTime { get { return _st; } set { if (this._st != value) { TimeSpan dur = this._et - this._st; this._st = value; this.OnPropertyChanged("OverallStartTime"); this.OverallEndTime = value + dur; } } } private DateTime _et; public DateTime OverallEndTime { get { return _et; } set { if (this._et != value) { this._et = value; this.OnPropertyChanged("OverallEndTime"); } } } #region INotifyPropertyChanged Members protected void OnPropertyChanged(string name) { if (this.PropertyChanged != null) this.PropertyChanged(this, new PropertyChangedEventArgs(name)); } public event PropertyChangedEventHandler PropertyChanged; #endregion } public class Project : INotifyPropertyChanged { public Project() { this.Tasks = new ObservableCollection<Task>(); } public string PName { get; set; } public ObservableCollection<Task> Tasks { get; set; } DateTime _st; public DateTime OverallStartTime { get { return _st; } set { if (this._st != value) { TimeSpan dur = this._et - this._st; this._st = value; this.OnPropertyChanged("OverallStartTime"); this.OverallEndTime = value + dur; } } } DateTime _et; public DateTime OverallEndTime { get { return _et; } set { if (this._et != value) { this._et = value; this.OnPropertyChanged("OverallEndTime"); } } } #region INotifyPropertyChanged Members protected void OnPropertyChanged(string name) { if (this.PropertyChanged != null) this.PropertyChanged(this, new PropertyChangedEventArgs(name)); } public event PropertyChangedEventHandler PropertyChanged; #endregion } public class Task : INotifyPropertyChanged { public string TaskName { get; set; } DateTime _st; public DateTime StartTime { get { return _st; } set { if (this._st != value) { TimeSpan dur = this._et - this._st; this._st = value; this.OnPropertyChanged("StartTime"); this.EndTime = value + dur; } } } private DateTime _et; public DateTime EndTime { get { return _et; } set { if (this._et != value) { this._et = value; this.OnPropertyChanged("EndTime"); } } } #region INotifyPropertyChanged Members protected void OnPropertyChanged(string name) { if (this.PropertyChanged != null) this.PropertyChanged(this, new PropertyChangedEventArgs(name)); } public event PropertyChangedEventHandler PropertyChanged; #endregion } hope my question is clear

    Read the article

< Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >