Search Results

Search found 74687 results on 2988 pages for 'work from home'.

Page 57/2988 | < Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >

  • COCOS2D-html5 MoveBy doesn't work

    - by ufo
    I'd like to run an action on a sprite using the MoveBy action. After lots of attempts, I can't achieve the goal... I have issues with the MoveBy in 2 different projects, so maybe I'm missing something in the setup... But I can't figure what! The instruction is like this: this.platform1Sprite.runAction(cc.MoveBy.create(1, cc.p(200, 0))); I don't get any error, simply it doesn't work. Thank you in advance.

    Read the article

  • Wine doesn't work (Problem with the mount manager)

    - by audrianore
    I didn't know exactly when the problem occurred. My Wine worked well a couple days ago. Then, I was just about to install some Windows programs hours ago but I got nothing. No installer window showed up, and no error report. It just won't work. And now I just found where the problem is (screenshot below), but I don't know how to fix it. Any idea? Any help would be appreciated. Thanks in advance. Details: Wine 1.4 Ubuntu 12.04 LTS I tried: Autoremove in Terminal Delete the software configuration

    Read the article

  • Ubuntu 12.10 doesn't work after update

    - by ACRTH
    12.10 doesn't work after a partial distribution update. I had some trouble before I began the update, and the Partial Update thingy appeared. It took about 6 hours to update/upgrade, don't know why. After the update, I restarted the laptop and nautilus doesn't appear nor does Unity. I can't switch to Gnome or anything else to try and fix it. The resolution is weird (doesn't fill out the right side of the screen). I'm almost sure it's Compiz who's the sinner (or me.) but I need help to get everything working again. Internet connections is fine. I have tried sudo apt-get install -f and sudo apt-get upgrade and so on.

    Read the article

  • Android Home Screen Widget (icon, label - style)

    - by dmulligan
    I'm trying to create an icon/widget (1 cell x 1 cell) that can be placed on the home screen of android. The widget will look and act exactly like the other standard shortcuts in android. It will have an icon and under that a label, it will be selectable with the trackball (highlight able) it will be highlighted when it is selected/clicked. How do I go about creating this home screen widget? Do I have to create the widget myself using code/xml or is there some standard xml, style, theme, code that I can use to ensure that the widget will have the same style/theme as the other home screen widgets? I currently have the following res/drawable/corners.xml <?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/Corners"> <stroke android:width="4dp" android:color="#CC222222" /> <padding android:left="4dp" android:top="1dp" android:right="4dp" android:bottom="1dp" /> <corners android:radius="4dp" /> </shape> res/layout/widget.xml <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/Widget" android:layout_width="72dip" android:layout_height="72dip" android:orientation="vertical" android:focusable="true" android:gravity="center_horizontal" style="@android:style/Widget" > <ImageView android:id="@+id/WidgetIcon" android:src="@drawable/icon" android:layout_width="fill_parent" android:layout_height="50dip" android:paddingTop="3dip" android:gravity="center" /> <TextView android:id="@+id/WidgetLabel" android:layout_width="wrap_content" android:layout_height="fill_parent" android:text="@string/app_name" android:textSize="15dip" android:background="@drawable/corners" /> </LinearLayout> The resulting widget looks some what close, but its not selectable, it doesn't get highlighted when clicked and the label isn't exactly in the correct location or the correct style. Any ideas, if there is a correct way to do this, or should I just keep working away on the above until I am closer?

    Read the article

  • Weird onclick behavior of images on home screen widget

    - by kknight
    I wrote a home screen widget with one image on it. When the image is clicked, browser will be opened for a url link. Generally, it is working. But a weird thing is that, when I click background, then click the picture, the browser will not be open. Until I click the second time on the picture, the browser opens. The steps to reproduce is below: Click on the home screen widget background. Click on the image on the home screen. The browser is not opened. Click on the image again. The browser is opened. If I didn't click on the background, the image will react to click very well, i.e. browser will be open when the image is clicked the first time. The widget XML file is as below: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="320dip" android:layout_height="200dip" android:background="@drawable/prt_base" > <ImageView android:id="@+id/picture1" android:layout_width="134dip" android:layout_height="102dip" android:layout_marginLeft="62dip" android:layout_marginTop="6dip" android:scaleType="center" android:src="@drawable/picture1" /> </RelativeLayout> The code to set OnClick on the picture1 ImageView is as below: defineIntent = new Intent(Intent.ACTION_VIEW, Uri .parse("http://www.google.com")); pendingIntent = PendingIntent .getActivity(context, 0 /* no requestCode */, defineIntent, 0 /* no flags */); updateViews.setOnClickPendingIntent( picId, pendingIntent); Anyone knows what's wrong? Thanks.

    Read the article

  • Misplaced Layout after "home"-button and/or powersave screen

    - by TiGer
    Hi, I have an app which also includes a service with a Notification. Right now I am experiencing the foillowing problem : I start my app which will work fine after couple of minutes the powersave kicks in and I get a black screen I (or hte user) click the Menu-button to dismiss the black screen and to unlock the screenlock Now my (fullscreen) app will have "moved" like 30-40 pixels downwards, creating an ugly black border or hole. When I move the scrollwheel it will move up and down, and when I press the Menu button (showing my ap''s menu) it will "fix" the view... or I start my app which will work fine I press the Home button exiting the app, my service though will (correctly) keep running when selecting my service from the notification-bar I will get once again : -Now my (fullscreen) app will have "moved" like 30-40 pixels downwards, creating an ugly black border or hole. When I move the scrollwheel it will move up and down, and when I press the Menu button (showing my ap''s menu) it will "fix" the view... Any idea what the problem is ? The app is running on a ADP2 with Android 1.6 Thanks in advance ! Ok, after some testing I noticed that if I don't run the Activity on Fullscreen, but just leave the TtileBar away this won't happen... Still this is no solution to me, I want it to be fullscreen... Noticed siomething else, when I have the View with the black bar, and I press the home button it will "refresh" the View correctly just before actually going to the Home Screen :(

    Read the article

  • Werid onclick behavior of images on home screen widget

    - by kknight
    I wrote a home screen widget with one image on it. When the image is clicked, browser will be opened for a url link. Generally, it is working. But a weird thing is that, when I click background, then click the picture, the browser will not be open. Until I click the second time on the picture, the browser opens. The steps to reproduce is below: Click on the home screen widget background. Click on the image on the home screen. The browser is not opened. Click on the image again. The browser is opened. If I didn't click on the background, the image will react to click very well, i.e. browser will be open when the image is clicked the first time. The widget XML file is as below: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="320dip" android:layout_height="200dip" android:background="@drawable/prt_base" > <ImageView android:id="@+id/picture1" android:layout_width="134dip" android:layout_height="102dip" android:layout_marginLeft="62dip" android:layout_marginTop="6dip" android:scaleType="center" android:src="@drawable/picture1" /> </RelativeLayout> The code to set OnClick on the picture1 ImageView is as below: defineIntent = new Intent(Intent.ACTION_VIEW, Uri .parse("http://www.google.com")); pendingIntent = PendingIntent .getActivity(context, 0 /* no requestCode */, defineIntent, 0 /* no flags */); updateViews.setOnClickPendingIntent( picId, pendingIntent); Anyone knows what's wrong? Thanks.

    Read the article

  • How LINQ to Object statements work

    - by rajbk
    This post goes into detail as to now LINQ statements work when querying a collection of objects. This topic assumes you have an understanding of how generics, delegates, implicitly typed variables, lambda expressions, object/collection initializers, extension methods and the yield statement work. I would also recommend you read my previous two posts: Using Delegates in C# Part 1 Using Delegates in C# Part 2 We will start by writing some methods to filter a collection of data. Assume we have an Employee class like so: 1: public class Employee { 2: public int ID { get; set;} 3: public string FirstName { get; set;} 4: public string LastName {get; set;} 5: public string Country { get; set; } 6: } and a collection of employees like so: 1: var employees = new List<Employee> { 2: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 3: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 4: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 5: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" }, 6: }; Filtering We wish to  find all employees that have an even ID. We could start off by writing a method that takes in a list of employees and returns a filtered list of employees with an even ID. 1: static List<Employee> GetEmployeesWithEvenID(List<Employee> employees) { 2: var filteredEmployees = new List<Employee>(); 3: foreach (Employee emp in employees) { 4: if (emp.ID % 2 == 0) { 5: filteredEmployees.Add(emp); 6: } 7: } 8: return filteredEmployees; 9: } The method can be rewritten to return an IEnumerable<Employee> using the yield return keyword. 1: static IEnumerable<Employee> GetEmployeesWithEvenID(IEnumerable<Employee> employees) { 2: foreach (Employee emp in employees) { 3: if (emp.ID % 2 == 0) { 4: yield return emp; 5: } 6: } 7: } We put these together in a console application. 1: using System; 2: using System.Collections.Generic; 3: //No System.Linq 4:  5: public class Program 6: { 7: [STAThread] 8: static void Main(string[] args) 9: { 10: var employees = new List<Employee> { 11: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 12: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 13: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 14: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" }, 15: }; 16: var filteredEmployees = GetEmployeesWithEvenID(employees); 17:  18: foreach (Employee emp in filteredEmployees) { 19: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 20: emp.ID, emp.FirstName, emp.LastName, emp.Country); 21: } 22:  23: Console.ReadLine(); 24: } 25: 26: static IEnumerable<Employee> GetEmployeesWithEvenID(IEnumerable<Employee> employees) { 27: foreach (Employee emp in employees) { 28: if (emp.ID % 2 == 0) { 29: yield return emp; 30: } 31: } 32: } 33: } 34:  35: public class Employee { 36: public int ID { get; set;} 37: public string FirstName { get; set;} 38: public string LastName {get; set;} 39: public string Country { get; set; } 40: } Output: ID 2 First_Name Jim Last_Name Ashlock Country UK ID 4 First_Name Jill Last_Name Anderson Country AUS Our filtering method is too specific. Let us change it so that it is capable of doing different types of filtering and lets give our method the name Where ;-) We will add another parameter to our Where method. This additional parameter will be a delegate with the following declaration. public delegate bool Filter(Employee emp); The idea is that the delegate parameter in our Where method will point to a method that contains the logic to do our filtering thereby freeing our Where method from any dependency. The method is shown below: 1: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 2: foreach (Employee emp in employees) { 3: if (filter(emp)) { 4: yield return emp; 5: } 6: } 7: } Making the change to our app, we create a new instance of the Filter delegate on line 14 with a target set to the method EmployeeHasEvenId. Running the code will produce the same output. 1: public delegate bool Filter(Employee emp); 2:  3: public class Program 4: { 5: [STAThread] 6: static void Main(string[] args) 7: { 8: var employees = new List<Employee> { 9: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 10: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 11: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 12: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 13: }; 14: var filterDelegate = new Filter(EmployeeHasEvenId); 15: var filteredEmployees = Where(employees, filterDelegate); 16:  17: foreach (Employee emp in filteredEmployees) { 18: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 19: emp.ID, emp.FirstName, emp.LastName, emp.Country); 20: } 21: Console.ReadLine(); 22: } 23: 24: static bool EmployeeHasEvenId(Employee emp) { 25: return emp.ID % 2 == 0; 26: } 27: 28: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 29: foreach (Employee emp in employees) { 30: if (filter(emp)) { 31: yield return emp; 32: } 33: } 34: } 35: } 36:  37: public class Employee { 38: public int ID { get; set;} 39: public string FirstName { get; set;} 40: public string LastName {get; set;} 41: public string Country { get; set; } 42: } Lets use lambda expressions to inline the contents of the EmployeeHasEvenId method in place of the method. The next code snippet shows this change (see line 15).  For brevity, the Employee class declaration has been skipped. 1: public delegate bool Filter(Employee emp); 2:  3: public class Program 4: { 5: [STAThread] 6: static void Main(string[] args) 7: { 8: var employees = new List<Employee> { 9: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 10: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 11: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 12: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 13: }; 14: var filterDelegate = new Filter(EmployeeHasEvenId); 15: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 16:  17: foreach (Employee emp in filteredEmployees) { 18: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 19: emp.ID, emp.FirstName, emp.LastName, emp.Country); 20: } 21: Console.ReadLine(); 22: } 23: 24: static bool EmployeeHasEvenId(Employee emp) { 25: return emp.ID % 2 == 0; 26: } 27: 28: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 29: foreach (Employee emp in employees) { 30: if (filter(emp)) { 31: yield return emp; 32: } 33: } 34: } 35: } 36:  The output displays the same two employees.  Our Where method is too restricted since it works with a collection of Employees only. Lets change it so that it works with any IEnumerable<T>. In addition, you may recall from my previous post,  that .NET 3.5 comes with a lot of predefined delegates including public delegate TResult Func<T, TResult>(T arg); We will get rid of our Filter delegate and use the one above instead. We apply these two changes to our code. 1: public class Program 2: { 3: [STAThread] 4: static void Main(string[] args) 5: { 6: var employees = new List<Employee> { 7: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 8: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 9: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 10: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 11: }; 12:  13: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 14:  15: foreach (Employee emp in filteredEmployees) { 16: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 17: emp.ID, emp.FirstName, emp.LastName, emp.Country); 18: } 19: Console.ReadLine(); 20: } 21: 22: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 23: foreach (var x in source) { 24: if (filter(x)) { 25: yield return x; 26: } 27: } 28: } 29: } We have successfully implemented a way to filter any IEnumerable<T> based on a  filter criteria. Projection Now lets enumerate on the items in the IEnumerable<Employee> we got from the Where method and copy them into a new IEnumerable<EmployeeFormatted>. The EmployeeFormatted class will only have a FullName and ID property. 1: public class EmployeeFormatted { 2: public int ID { get; set; } 3: public string FullName {get; set;} 4: } We could “project” our existing IEnumerable<Employee> into a new collection of IEnumerable<EmployeeFormatted> with the help of a new method. We will call this method Select ;-) 1: static IEnumerable<EmployeeFormatted> Select(IEnumerable<Employee> employees) { 2: foreach (var emp in employees) { 3: yield return new EmployeeFormatted { 4: ID = emp.ID, 5: FullName = emp.LastName + ", " + emp.FirstName 6: }; 7: } 8: } The changes are applied to our app. 1: public class Program 2: { 3: [STAThread] 4: static void Main(string[] args) 5: { 6: var employees = new List<Employee> { 7: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 8: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 9: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 10: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 11: }; 12:  13: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 14: var formattedEmployees = Select(filteredEmployees); 15:  16: foreach (EmployeeFormatted emp in formattedEmployees) { 17: Console.WriteLine("ID {0} Full_Name {1}", 18: emp.ID, emp.FullName); 19: } 20: Console.ReadLine(); 21: } 22:  23: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 24: foreach (var x in source) { 25: if (filter(x)) { 26: yield return x; 27: } 28: } 29: } 30: 31: static IEnumerable<EmployeeFormatted> Select(IEnumerable<Employee> employees) { 32: foreach (var emp in employees) { 33: yield return new EmployeeFormatted { 34: ID = emp.ID, 35: FullName = emp.LastName + ", " + emp.FirstName 36: }; 37: } 38: } 39: } 40:  41: public class Employee { 42: public int ID { get; set;} 43: public string FirstName { get; set;} 44: public string LastName {get; set;} 45: public string Country { get; set; } 46: } 47:  48: public class EmployeeFormatted { 49: public int ID { get; set; } 50: public string FullName {get; set;} 51: } Output: ID 2 Full_Name Ashlock, Jim ID 4 Full_Name Anderson, Jill We have successfully selected employees who have an even ID and then shaped our data with the help of the Select method so that the final result is an IEnumerable<EmployeeFormatted>.  Lets make our Select method more generic so that the user is given the freedom to shape what the output would look like. We can do this, like before, with lambda expressions. Our Select method is changed to accept a delegate as shown below. TSource will be the type of data that comes in and TResult will be the type the user chooses (shape of data) as returned from the selector delegate. 1:  2: static IEnumerable<TResult> Select<TSource, TResult>(IEnumerable<TSource> source, Func<TSource, TResult> selector) { 3: foreach (var x in source) { 4: yield return selector(x); 5: } 6: } We see the new changes to our app. On line 15, we use lambda expression to specify the shape of the data. In this case the shape will be of type EmployeeFormatted. 1:  2: public class Program 3: { 4: [STAThread] 5: static void Main(string[] args) 6: { 7: var employees = new List<Employee> { 8: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 9: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 10: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 11: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 12: }; 13:  14: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 15: var formattedEmployees = Select(filteredEmployees, (emp) => 16: new EmployeeFormatted { 17: ID = emp.ID, 18: FullName = emp.LastName + ", " + emp.FirstName 19: }); 20:  21: foreach (EmployeeFormatted emp in formattedEmployees) { 22: Console.WriteLine("ID {0} Full_Name {1}", 23: emp.ID, emp.FullName); 24: } 25: Console.ReadLine(); 26: } 27: 28: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 29: foreach (var x in source) { 30: if (filter(x)) { 31: yield return x; 32: } 33: } 34: } 35: 36: static IEnumerable<TResult> Select<TSource, TResult>(IEnumerable<TSource> source, Func<TSource, TResult> selector) { 37: foreach (var x in source) { 38: yield return selector(x); 39: } 40: } 41: } The code outputs the same result as before. On line 14 we filter our data and on line 15 we project our data. What if we wanted to be more expressive and concise? We could combine both line 14 and 15 into one line as shown below. Assuming you had to perform several operations like this on our collection, you would end up with some very unreadable code! 1: var formattedEmployees = Select(Where(employees, emp => emp.ID % 2 == 0), (emp) => 2: new EmployeeFormatted { 3: ID = emp.ID, 4: FullName = emp.LastName + ", " + emp.FirstName 5: }); A cleaner way to write this would be to give the appearance that the Select and Where methods were part of the IEnumerable<T>. This is exactly what extension methods give us. Extension methods have to be defined in a static class. Let us make the Select and Where extension methods on IEnumerable<T> 1: public static class MyExtensionMethods { 2: static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 3: foreach (var x in source) { 4: if (filter(x)) { 5: yield return x; 6: } 7: } 8: } 9: 10: static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 11: foreach (var x in source) { 12: yield return selector(x); 13: } 14: } 15: } The creation of the extension method makes the syntax much cleaner as shown below. We can write as many extension methods as we want and keep on chaining them using this technique. 1: var formattedEmployees = employees 2: .Where(emp => emp.ID % 2 == 0) 3: .Select (emp => new EmployeeFormatted { ID = emp.ID, FullName = emp.LastName + ", " + emp.FirstName }); Making these changes and running our code produces the same result. 1: using System; 2: using System.Collections.Generic; 3:  4: public class Program 5: { 6: [STAThread] 7: static void Main(string[] args) 8: { 9: var employees = new List<Employee> { 10: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 11: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 12: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 13: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 14: }; 15:  16: var formattedEmployees = employees 17: .Where(emp => emp.ID % 2 == 0) 18: .Select (emp => 19: new EmployeeFormatted { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: } 23: ); 24:  25: foreach (EmployeeFormatted emp in formattedEmployees) { 26: Console.WriteLine("ID {0} Full_Name {1}", 27: emp.ID, emp.FullName); 28: } 29: Console.ReadLine(); 30: } 31: } 32:  33: public static class MyExtensionMethods { 34: static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 35: foreach (var x in source) { 36: if (filter(x)) { 37: yield return x; 38: } 39: } 40: } 41: 42: static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 43: foreach (var x in source) { 44: yield return selector(x); 45: } 46: } 47: } 48:  49: public class Employee { 50: public int ID { get; set;} 51: public string FirstName { get; set;} 52: public string LastName {get; set;} 53: public string Country { get; set; } 54: } 55:  56: public class EmployeeFormatted { 57: public int ID { get; set; } 58: public string FullName {get; set;} 59: } Let’s change our code to return a collection of anonymous types and get rid of the EmployeeFormatted type. We see that the code produces the same output. 1: using System; 2: using System.Collections.Generic; 3:  4: public class Program 5: { 6: [STAThread] 7: static void Main(string[] args) 8: { 9: var employees = new List<Employee> { 10: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 11: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 12: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 13: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 14: }; 15:  16: var formattedEmployees = employees 17: .Where(emp => emp.ID % 2 == 0) 18: .Select (emp => 19: new { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: } 23: ); 24:  25: foreach (var emp in formattedEmployees) { 26: Console.WriteLine("ID {0} Full_Name {1}", 27: emp.ID, emp.FullName); 28: } 29: Console.ReadLine(); 30: } 31: } 32:  33: public static class MyExtensionMethods { 34: public static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 35: foreach (var x in source) { 36: if (filter(x)) { 37: yield return x; 38: } 39: } 40: } 41: 42: public static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 43: foreach (var x in source) { 44: yield return selector(x); 45: } 46: } 47: } 48:  49: public class Employee { 50: public int ID { get; set;} 51: public string FirstName { get; set;} 52: public string LastName {get; set;} 53: public string Country { get; set; } 54: } To be more expressive, C# allows us to write our extension method calls as a query expression. Line 16 can be rewritten a query expression like so: 1: var formattedEmployees = from emp in employees 2: where emp.ID % 2 == 0 3: select new { 4: ID = emp.ID, 5: FullName = emp.LastName + ", " + emp.FirstName 6: }; When the compiler encounters an expression like the above, it simply rewrites it as calls to our extension methods.  So far we have been using our extension methods. The System.Linq namespace contains several extension methods for objects that implement the IEnumerable<T>. You can see a listing of these methods in the Enumerable class in the System.Linq namespace. Let’s get rid of our extension methods (which I purposefully wrote to be of the same signature as the ones in the Enumerable class) and use the ones provided in the Enumerable class. Our final code is shown below: 1: using System; 2: using System.Collections.Generic; 3: using System.Linq; //Added 4:  5: public class Program 6: { 7: [STAThread] 8: static void Main(string[] args) 9: { 10: var employees = new List<Employee> { 11: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 12: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 13: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 14: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 15: }; 16:  17: var formattedEmployees = from emp in employees 18: where emp.ID % 2 == 0 19: select new { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: }; 23:  24: foreach (var emp in formattedEmployees) { 25: Console.WriteLine("ID {0} Full_Name {1}", 26: emp.ID, emp.FullName); 27: } 28: Console.ReadLine(); 29: } 30: } 31:  32: public class Employee { 33: public int ID { get; set;} 34: public string FirstName { get; set;} 35: public string LastName {get; set;} 36: public string Country { get; set; } 37: } 38:  39: public class EmployeeFormatted { 40: public int ID { get; set; } 41: public string FullName {get; set;} 42: } This post has shown you a basic overview of LINQ to Objects work by showning you how an expression is converted to a sequence of calls to extension methods when working directly with objects. It gets more interesting when working with LINQ to SQL where an expression tree is constructed – an in memory data representation of the expression. The C# compiler compiles these expressions into code that builds an expression tree at runtime. The provider can then traverse the expression tree and generate the appropriate SQL query. You can read more about expression trees in this MSDN article.

    Read the article

  • Intranet Video-streaming

    - by Jonathan Sampson
    What's a good option for home-video-streaming. For example, somebody may use a laptop webcam to stream their baby's crib allowing them to monitor it from the main home PC. In this case, I wouldn't want to do it across the wire with skype, but instead keep it on my local network. What options exist to make this easy to achieve?

    Read the article

  • Is PLC speed affected by mixing different devices?

    - by CFP
    Hello everyone! At home, I have 4 PLC devices for my home network. Two of them are 85Mb/s powerlan PLC adapters, while the others are 10Mbps powerlan PLC adapters. I have not been able to determine reliably whether the presence of the 10Mb/s ones impact on the speed of the 85Mb/s ones. Is it possible that the bitrate is limited by the slowest devices on the network? Thanks!

    Read the article

  • Does NAT change the source MAC address?

    - by user44073
    I'm trying to secure my home network but don't really need the complexity of a VPN so I'm trying to figure out other options. I'd like to allow my iPhone remote access to my home servers but I can't depend on the IP address because it changes quite often (due to the 3G network, etc). Can I filter incoming connections on my router (pfsense) by MAC address or does NAT change the source as it's passing through the different routers on the internet?

    Read the article

  • Keypress detection wont work after seemingly unrelated code change

    - by LukeZaz
    I'm trying to have the Enter key cause a new 'map' to generate for my game, but for whatever reason after implementing full-screen in it the input check won't work anymore. I tried removing the new code and only pressing one key at a time, but it still won't work. Here's the check code and the method it uses, along with the newMap method: public class Game1 : Microsoft.Xna.Framework.Game { // ... protected override void Update(GameTime gameTime) { // ... // Check if Enter was pressed - if so, generate a new map if (CheckInput(Keys.Enter, 1)) { blocks = newMap(map, blocks, console); } // ... } // Method: Checks if a key is/was pressed public bool CheckInput(Keys key, int checkType) { // Get current keyboard state KeyboardState newState = Keyboard.GetState(); bool retType = false; // Return type if (checkType == 0) { // Check Type: Is key currently down? if (newState.IsKeyDown(key)) { retType = true; } else { retType = false; } } else if (checkType == 1) { // Check Type: Was the key pressed? if (newState.IsKeyDown(key)) { if (!oldState.IsKeyDown(key)) { // Key was just pressed retType = true; } else { // Key was already pressed, return false retType = false; } } } // Save keyboard state oldState = newState; // Return result if (retType == true) { return true; } else { return false; } } // Method: Generate a new map public List<Block> newMap(Map map, List<Block> blockList, Console console) { // Create new map block coordinates List<Vector2> positions = new List<Vector2>(); positions = map.generateMap(console); // Clear list and reallocate memory previously used up by it blockList.Clear(); blockList.TrimExcess(); // Add new blocks to the list using positions created by generateMap() foreach (Vector2 pos in positions) { blockList.Add(new Block() { Position = pos, Texture = dirtTex }); } // Return modified list return blockList; } // ... } and the generateMap code: // Generate a list of Vector2 positions for blocks public List<Vector2> generateMap(Console console, int method = 0) { ScreenTileWidth = gDevice.Viewport.Width / 16; ScreenTileHeight = gDevice.Viewport.Height / 16; maxHeight = gDevice.Viewport.Height; List<Vector2> blockLocations = new List<Vector2>(); if (useScreenSize == true) { Width = ScreenTileWidth; Height = ScreenTileHeight; } else { maxHeight = Height; } int startHeight = -500; // For debugging purposes, the startHeight is set to an // hopefully-unreachable value - if it returns this, something is wrong // Methods of land generation /// <summary> /// Third version land generation /// Generates a base land height as the second version does /// but also generates a 'max change' value which determines how much /// the land can raise or lower by which it now does by a random amount /// during generation /// </summary> if (method == 0) { // Get the land height startHeight = rnd.Next(1, maxHeight); int maxChange = rnd.Next(1, 5); // Amount ground will raise/lower by int curHeight = startHeight; for (int w = 0; w < Width; w++) { // Run a chance to lower/raise ground level int changeBy = rnd.Next(1, maxChange); int doChange = rnd.Next(0, 3); if (doChange == 1 && !(curHeight <= (1 + maxChange))) { curHeight = curHeight - changeBy; } else if (doChange == 2 && !(curHeight >= (29 - maxChange))) { curHeight = curHeight + changeBy; } for (int h = curHeight; h < Height; h++) { // Location variables float x = w * 16; float y = h * 16; blockLocations.Add(new Vector2(x, y)); } } console.newMsg("[INFO] Cur, height change maximum: " + maxChange.ToString()); } /// <summary> /// Second version land generator /// Generates a solid mass of land starting at a random height /// derived from either screen height or provided height value /// </summary> else if (method == 1) { // Get the land height startHeight = rnd.Next(0, 30); for (int w = 0; w < Width; w++) { for (int h = startHeight; h < ScreenTileHeight; h++) { // Location variables float x = w * 16; float y = h * 16; // Add a tile at set location blockLocations.Add(new Vector2(x, y)); } } } /// <summary> /// First version land generator /// Generates land completely randomly either across screen or /// in a box set by Width and Height values /// </summary> else { // For each tile in the map... for (int w = 0; w < Width; w++) { for (int h = 0; h < Height; h++) { // Location variables float x = w * 16; float y = h * 16; // ...decide whether or not to place a tile... if (rnd.Next(0, 2) == 1) { // ...and if so, add a tile at that location. blockLocations.Add(new Vector2(x, y)); } } } } console.newMsg("[INFO] Cur, base height: " + startHeight.ToString()); return blockLocations; } I never touched any of the above code for this when it broke - changing keys won't seem to fix it. Despite this, I have camera movement set inside another Game1 method that uses WASD and works perfectly. All I did was add a few lines of code here: private int BackBufferWidth = 1280; // Added these variables private int BackBufferHeight = 800; public Game1() { graphics = new GraphicsDeviceManager(this); graphics.PreferredBackBufferWidth = BackBufferWidth; // and this graphics.PreferredBackBufferHeight = BackBufferHeight; // this Content.RootDirectory = "Content"; this.graphics.IsFullScreen = true; // and this } When I try adding a console line to be printed in the event the key is pressed, it seems that the If is never even triggered despite the correct key being pressed.

    Read the article

  • How to include the login form on the Home index page in MVC

    - by Bernard Larouche
    Hi guys I really need your help for this. I am relatively new to programming and I need help to something that could be easy for a experienced programmer. I would like to get the login form that we get for free in an MVC application on the left sidebar of my Home index page instead of the usual Account/Login page. I am facing some problems. First I need a product object to be displayed on my Home Index page as well. What I did is that I added a product object to the LogOnModel that they provide in the AccountModels class and I created a UserControl (partial view) copying the content of the LogOn.aspx view. Now my Home index.aspx as well as my partial view inherits the LogOnModel class. I can see the Login form on my Home Index page as well as my product object BUT the login Form is never empty. The last username and password always appear there. I know I must have forgotten something or have done something wrong or the way did it is completely wrong !! Please could you give me some advice Thks <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<CoderForTradersSite.Models.LogOnModel>" %> <h4>Login Form</h4> <p> Please enter your username and password. <%= Html.ActionLink("Register", "Register") %> if you don't have an account. </p> <% using (Html.BeginForm()) { %> <%= Html.ValidationSummary(true, "Login was unsuccessful. Please correct the errors and try again.") %> <div> <fieldset> <legend>Account Information</legend> <div class="editor-label"> <%= Html.LabelFor(m => m.UserName) %> </div> <div class="editor-field"> <%= Html.TextBoxFor(m => m.UserName) %> <%= Html.ValidationMessageFor(m => m.UserName) %> </div> <div class="editor-label"> <%= Html.LabelFor(m => m.Password) %> </div> <div class="editor-field"> <%= Html.PasswordFor(m => m.Password) %> <%= Html.ValidationMessageFor(m => m.Password) %> </div> <div class="editor-label"> <%= Html.CheckBoxFor(m => m.RememberMe) %> <%= Html.LabelFor(m => m.RememberMe) %> </div> <p> <input type="submit" value="Log On" /> </p> </fieldset> </div> <% } %>

    Read the article

  • How does Comparison Sites work?

    - by Vijay
    Need your thinking on how does these Comparision Sites actually work. Sites like Junglee.com policybazaar.com and there are many like these which provides comaprision of products , fares etc. grabbed from different websites. I had read a little about it and what i found is-: These sites uses Feeds of the sites data. These sites uses APIs of the sites which are actually provided by those sites. And for some sites which do not have any of these two posibility then the Comparision sites uses web-crawler to crawl their data. This is what i have found out. If you think there is more things to it please do give your own views. But i want to know these for my learning purpose and a little for curiosity- how does they actually matches the crawled data , feeds, and other so that there is no duplicacy. What is the process or algorithms for it. And where should i go to learn these concepts. References for books , articles or anything else.

    Read the article

  • Want to work at Typemock? We’re Hiring

    - by RoyOsherove
    We are looking for a .NET\C++ developer to join the growing Typemock ranks. You need to: Live in Israel know .NET very well (at least 3 years .NET experience – VB.NET or C#, and willing to learn the other one) Have some C++ experience (recent – sometime in the past couple of years) Be interested in Agile development, unit testing and TDD (you don’t have to be an expert. You’ll become one on the job.) have very good english PASSION for programming Advantage to C++ hardcore devs but you don’t have to be one Advantage to Open source contributors   but you don’t have to be one Advantage to public figures (bloggers, speakers..) but you don’t have to be one   You will be working on one of our products, or several of them along the way. Including Typemock Isolator, Test Lint, TeamMate and future products we are working on! We are counting on all our developers to be part of the design process, to take active part in support and customer meetings, and the first day of every two weeks is dedicated to pet projects – you work on anything you want (even if it’s not to do with Typemock)! send an email with your ENGLISH CV to royo AT typemock.com

    Read the article

  • Getting the alternative to the 200-Line Linux Kernel patch to work

    - by Gödel
    Apparently, there is a comparable alternative to the 200-line kernel patch that involves no kernel upgrade. It is presented here and discussed here. However, I am not sure if webupd8's solution (under the section "Use it in Ubuntu") on Ubuntu actually works or not. In particular, one commenter on ./ is saying he's getting an error message. Could anyone post the "correct" method that actually works? Suggested solution: Based on the comments I've read so far, the following seems to work. (1) In /etc/rc.local, add the following lines to above exit 0: mkdir -p /dev/cgroup/cpu mount -t cgroup cgroup /dev/cgroup/cpu -o cpu mkdir -m 0777 /dev/cgroup/cpu/user echo "/usr/local/sbin/cgroup_clean" > /dev/cgroup/cpu/release_agent (2) Create a file named /usr/local/sbin/cgroup_clean with the following content: #!/bin/sh rmdir /dev/cgroup/cpu/$1 (3) In your ~/.bashrc, add: if [ "$PS1" ] ; then mkdir -m 0700 /dev/cgroup/cpu/user/$$ echo $$ > /dev/cgroup/cpu/user/$$/tasks echo "1" > /dev/cgroup/cpu/user/$$/notify_on_release fi (4) (To make sure the execution bit is on) execute sudo chmod +x /usr/local/sbin/cgroup_clean /etc/rc.local (5) Reboot.

    Read the article

  • Wubi doens't work anymore - shows 'No wubildr' error

    - by Joe
    Basics: HP Mini 311 Ubuntu netbook edition 10.04 (installed via Wubi) Symptoms: I load to Windows Boot Manager as usual. Options are Windows 7 and Ubuntu Netbook, like usual. Selecting Windows 7 does as it should. Loading Ubuntu Netbook, though, does not take me to the usual screen where it lets me select versions of Ubuntu (sorry for bad wording, not sure what the real name is called; it's where you select from about 6 items; I always picked the first due to lack of knowledge without issue). Instead it flashes an error in white on a black screen then restarts very quickly. It took me a few restarts, but here is the error: Try (hd0,0): NTSF5 No wubildr Try (hd0,1): NTSF5: Situation: I have no clue what caused it. The only thing I did last night on Ubuntu was install Skype, but the mic didn't work instantly so I got lazy and switched to Windows 7 and used Skype on there. When I tried to switch back to Ubuntu it began this. (There may be something I forget... it was 5 in the morning). There were no recent updates that I remember. No weird activity. Just... random. Help please?

    Read the article

  • After upgrading to 12.04 the scanner from Brother Printer MFC-290C does not work

    - by Lorenzo
    I upgraded Ubuntu to 12.04 from 11.10. The printer works, but the scanner doesn't now. In 11.10 I had to install a special driver from Brother. The printer's model is Brother MFC-290C. The computer is a Toshiba Satellite. How can I get the scanner working? Update: I have a 64-bit installation on the Toshiba Satellite. Thank you for your instructions, Chad--24216. I followed each step: 1 through 5. I also updated the Brother Linux scanner S-KEY tool. The output of dpkg -l | grep Brother is: ii brscan-skey 0.2.3-0 Brother Linux scanner S-KEY tool ii brscan3 0.2.11-5 Brother Scanner Driver ii mfc290ccupswrapper:i386 1.1.2-2 Brother CUPS Inkjet Printer Definitions ii mfc290clpr:i386 1.1.2-2 Brother lpr Inkjet Printer Definitions ii printer-driver-ptouch 1.3-3ubuntu0.1 printer driver Brother P-touch label printers Still the scanner does not work. Here is the message from Xsane: Failed to open device brother3:bus6;dev1: Invalid argument. Here is the message from Simple Scan: Failed to scan. Unable to connect to scanner. And Scan Utility still doesn't display the scanner line.

    Read the article

  • sudo apt-get update does not work for 12.10

    - by Brian Hawi
    hey i recently installed ubuntu 12.10 but the software center does not work i tried the sudo apt-get update because that worked when i was using ubuntu 11.04.... these are the errors hawi@hawi-HP-G62-Notebook-PC:~$ sudo apt-get update [sudo] password for hawi: Err http:ke.archive.ubuntu.com quantal InRelease Err http:ke.archive.ubuntu.com quantal-updates InRelease Err http:ke.archive.ubuntu.com quantal-backports InRelease Err http:ke.archive.ubuntu.com quantal Release.gpg Unable to connect to ke.archive.ubuntu.com:http: Err http:ke.archive.ubuntu.com quantal-updates Release.gpg Unable to connect to ke.archive.ubuntu.com:http: Err http:ke.archive.ubuntu.com quantal-backports Release.gpg Unable to connect to ke.archive.ubuntu.com:http: Err http:security.ubuntu.com quantal-security InRelease Err http:security.ubuntu.com quantal-security Release.gpg Unable to connect to security.ubuntu.com:http: [IP: 91.189.92.190 80] Err http:extras.ubuntu.com quantal InRelease Err http:extras.ubuntu.com quantal Release.gpg Unable to connect to extras.ubuntu.com:http: Reading package lists... Done W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal/InRelease W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-updates/InRelease W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-backports/InRelease W: Failed to fetch http:security.ubuntu.com/ubuntu/dists/quantal-security/InRelease W: Failed to fetch http:extras.ubuntu.com/ubuntu/dists/quantal/InRelease W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal/Release.gpg Unable to connect to ke.archive.ubuntu.com:http: W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-updates/Release.gpg Unable to connect to ke.archive.ubuntu.com:http: W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-backports/Release.gpg Unable to connect to ke.archive.ubuntu.com:http: W: Failed to fetch http:security.ubuntu.com/ubuntu/dists/quantal-security/Release.gpg Unable to connect to security.ubuntu.com:http: [IP: 91.189.92.190 80] W: Failed to fetch http:extras.ubuntu.com/ubuntu/dists/quantal/Release.gpg Unable to connect to extras.ubuntu.com:http: W: Some index files failed to download. They have been ignored, or old ones used instead. (note i have removed the // after http because the site does not allow me to post more than two links) what could be the issue?

    Read the article

  • How Do Nautilus Album Art Thumbnails work?

    - by Amir Adar
    There's something for which I've been searching an answer for a while now, but to no avail, and it's strange to me, as it seems like a thing that people would talk about: one of those nice little nonsense that enhance the computing experience a little bit. Anyway. I have a fair music collection. I save all the songs as ogg files. All is fine, and I can listen to the files, but there's something weird with the files in Nautilus: some have icons displaying their album art, while others don't, and I just can't understand WHY. I read on this site today that it's a matter of embedding the album art to the file, but that's not true, as I embedded the album art to the files I wanted several times, to no avail. Furthermore, removing an embedded album art from a file didn't have any effect on those that ARE displaying the icons. So my question is: How does it work? Where does Nautilus (or Ubuntu, I don't know) get the picture from? How do I edit it? Thanks in advance! -Amir

    Read the article

  • lucid 10.04 LTS => Precise 12.04.1 : upgrade doesn't work

    - by Rastom
    I googled and looked into all unkown issues on ubuntu forums but I can't figure out why a 10.04 LTS server won't detect the last LTS 12.04.1. I guess since 12.04 is a fresh dist, not much is reported for related issues Here is what I did : apt-get update apt-get upgrade apt-get install update-manager-core it was already installed so no update for this package. I checked : /etc/update-manager/release-upgrades [DEFAULT] # Default prompting behavior, valid options: # # never - Never check for a new release. # normal - Check to see if a new release is available. If more than one new # release is found, the release upgrader will attempt to upgrade to # the release that immediately succeeds the currently-running # release. # lts - Check to see if a new LTS release is available. The upgrader # will attempt to upgrade to the first LTS release available after # the currently-running one. Note that this option should not be # used if the currently-running release is not itself an LTS # release, since in that case the upgrader won't be able to # determine if a newer release is available. Prompt=lts I also checked my sourcelist before running apt-get : /etc/apt/sources.list deb http://archive.ubuntu.com/ubuntu/ lucid main restricted universe multiverse deb http://archive.ubuntu.com/ubuntu/ lucid-security main restricted universe multiverse deb http://archive.ubuntu.com/ubuntu/ lucid-updates main restricted universe multiverse deb http://security.ubuntu.com/ubuntu lucid-security main restricted deb-src http://security.ubuntu.com/ubuntu lucid-security main restricted deb http://security.ubuntu.com/ubuntu lucid-security universe deb-src http://security.ubuntu.com/ubuntu lucid-security universe deb http://security.ubuntu.com/ubuntu lucid-security multiverse deb-src http://security.ubuntu.com/ubuntu lucid-security multiverse # deb http://landscape.canonical.com/packages/hardy ./ # deb-src http://landscape.canonical.com/packages/hardy ./ and then following Ubuntu guide for Precise upgrade the command below should work : root@xxxxxxxxx:/etc/apt# do-release-upgrade -d Checking for a new ubuntu release No new release found So am I missing something ? The server was accessing outside through a proxy but I grant direct access to this server to avoid any Internet access problem or redirection but no clue... Any help would be appreciated

    Read the article

  • apt-get does not work with proxy

    - by tommyk
    For a command sudo apt-get update I get following error W: Failed to fetch http://ch.archive.ubuntu.com/ubuntu/dists/maverick-updates/multiverse/binary-i386/Packages.gz 407 Proxy Authentication Required ( The ISA Server requires authorization to fulfill the request. Access to the Web Proxy filter is denied. ) I am running Ubuntu 10.10 installed on Windows XP using VirtualBox. For internet connections I am using proxy server with an authentication. I tried to use gnome-network-proxy tool to set proxy settings system-wide. After that /etc/environment has been updated by http_proxy variable with the format http://my_proxy:port/, there were no authentication data. I checked this with firefox. Browser asked my for login and password and everything was working fine. It was unfortunately not the case for apt-get. I have also tried to do as described here. Unfortunately it does not work. May it be somehow related to the fact that a proxy is in a Windows domain, any ideas ? EDIT: My proxy name is http-proxy. Is '-' a special character here ?

    Read the article

  • Oracle at Work videó: Banca Transilvania, Exadata és Exalogic, alkalmazások és adattárház

    - by user645740
    Az ORACLE AT WORK videók sorában most a Banca Transilvania romániai bank felso vezetoi osztják meg gyakorlati tapasztalataikat az Exadata Database Machine és az Exalogic megoldások banki muködésérol. Videó link: Video Case Study with Banca Transilvania.    A kolozsvári székhelyu Banca Transilvania a harmadik legnagyobb bank Romániában, 1,5 millió aktív ügyfelet kezel, a bank növekszik. Amikor 1999-ben megjelent a II. generációs Exadata V2-es sorozat, ebbol a Banca Transilvania volt az elso banki vásárló a világon. Eloször az adattárházukat helyezték át Exadatára, hatalmas teljesítmény ugrást tapasztaltak, amit az üzlet ki is tudott használni, több riport, extrém jó válaszidokkel, gyorsabb batch futások. A cél a banki architektúra Exadata és Exalogic rendszerre történo konszolidálása. A videóban az Exadata + Exalogic megoldásuk elonyeirol a Banca Transilvania vezetoi beszélnek: Robert C. Rekkers, CEO;  Leontin Toderici, COO;  Marius Ursuti, IT Director. az alkalmazásaikat Oracle-ön konszolidálják kártya rendszer új core-banking rendszer: FLEXCUBE is az Exadatán fog muködni, ez segíti a bankot a növekedésben, a növekvo ügyfélszám, tranzakciók kezelésében Siebel CRM tesztelik az Exa architektúrán az Oracle E-Business Suite alkalmazásokat is legjobb teljesítmény Oracle adatbázisokra, kisebb válaszidok, adattárház és Oracle OLAP: költségcsökkenés, 30-szor gyorsabb muködés Exalogic: alkalmazásszerverek konszolidációja WebLogic szerveren a bank tesztjei is azt mutatják, hogy az Exalogic elonyei még jobban kidomborodnak az Exadata használatával együtt a gépek beállítását követoen 24 órán belül már kezdhetik a munkát, az elore telepített szoftverekkel, a gyárilag alaposan tesztelt és hangolt gépekkel egyszerubb architektúra, ennek menedzsmentje is kisebb költségu általánosan minden rendszer bevezetési ideje lecsökken az Exa architektúrán lehetové teszi új termékek és szolgáltatások gyorsabb bevezetését költségcsökkentés, teljes költség, Total Cost csökkent kiemelték az Oracle Corporation  felkészült csapatának rugalmasságát az Oracle folyamatos fejlesztése, innovációja, supportja Videó link: Video Case Study with Banca Transilvania.

    Read the article

< Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >