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• Creating a patch file from a diff of 2 folders

  - by karatchov

  I made some changes to an open source project without taking time to create proper patch files. Now, the maintainer of the project released a new version, and among new and edited files, there are a bunch of renamed files. Whats is the best way to apply my changes to the new version ? I'm completely new to diff/patch use, and If I can get it done with git, it would be better.

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• How reference popup object when opener page changes?

  - by achairapart

  This is driving me crazy! Scenario: The main page opens a pop-up window and later calls a function in it: newWin = window.open(someurl,'newWin',options); ...some code later... newWin.remoteFunction(options); and it's ok. Now, popup is still open and Main Page changes to Page 2. In Page 2 newWin doesn't exist anymore and I need to recreate the popup window object reference in order to call again the remote function (newWin.remoteFunction) I tried something like: newWin = open('','newWin', options); if (!newWin || newWin.closed || !newWin.remoteFunction) { newWin = window.open(someurl,'newWin',options); } And it works, I can call newWin.remoteFunction again BUT Safari for some reason gives Focus() to the popup window everytime the open() method is called breaking the navigation (I absolutely need the popup working in the background). Only workaround I can think to solve this is to create an interval in the popup with: if(window.opener && !window.opener.newWin) window.opener.newWin = self; and then set another interval in the opener Page with some try/catch but it is inelegant and very inefficient. so, I wonder, it's really so hard to get the popup object reference between different pages in the opener window?

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• jquery ui dialog - live not working?

  - by ile

  I'm using this dialog: http://docs.jquery.com/UI/Dialog To open dialog I do it this way: $('a.openModal').live("click", function() { var idArr = $(this).attr('id').split("OpenNote"); var id = idArr[1]; alert($(".modalNote#dialog-modal" + id).html()); $(".modalNote#dialog-modal" + id).dialog('open'); return false; }); This dialog is used to display content of note when title is clicked. When I generated html on pageload, then this works fine, but if I add html dynamically then dialog won't open. It is also not hidden when it's appended to div. Is it possible to open it "on-fly"?

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• How to Not alter font in webpage after opening a file (pdf or jpg) in ASP.NET C#? [closed]

  - by Victor

  Possible Duplicate: How to not alter font in webpage after opening a pdf in ASP.NET C#? Previously I posted this question: How to open files from a specific route in ASP-NET c#? in fact, I have already asked this however it was only a minor question so I guess it wasn't that important in the previous post, so I will ask here. Whenever I open a pdf with: Response.Write("<script>window.open('FilePath');</script>"); All of the font in the page is altered, example, the letter's size increases and some of the letter's colors are switched to black instead of the font that I assigned. Is there a way that I can work around that?? http://imageshack.us/a/img838/5145/beforeja.png http://imageshack.us/a/img546/4760/afterw.png Oh and I noticed that this also happens when you open images like jpg

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• Load local Html file doesn't refer the js file in UIWebView

  - by Hero Vs Zero

  I am working with UIWebView project and I want to load an HTML file from a project resource. It is working fine when I run from the URL, but when I view the HTML file locally, JS files are not loaded. Loading the local HTML local file doesn't refer to js files in UIWebView. Here's my code to load the HTML file project local resource and does't refer the js file: NSString *path = [[NSBundle mainBundle] pathForResource:@"textfile" ofType:@"txt"]; NSError *error = nil; NSString *string = [[NSString alloc] initWithContentsOfFile:path encoding:NSUTF8StringEncoding error:&error]; NSString *path1 = [[NSBundle mainBundle] bundlePath]; NSURL *baseURL = [NSURL fileURLWithPath:path1]; NSLog(@"%@ >>> %@",baseURL,path); [webview loadHTMLString:string baseURL:baseURL]; This code doesn't find JS files in UIWebView, even though it loads image files from the project resource successfully.

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• Is there a way to access Skype IM logs?

  - by eternalmatt

  I tried looking in C:\Users[name]\AppData\Roaming\Skype and I found a folder called "chatsync" with some mysterious folders with files ending in .dat. I'm almost certain that these are the chat logs but I don't know a way to properly open these files (notepad shows gibberish mixed with English words). I'm not trying to do sleuthing, just a project for my girlfriend. So more importantly: how can I read Skype's .dat files properly?

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• Can a function defined in a bookmarklet be called from a page-level script?

  - by Soviut

  I have a bookmarklet that needs to open a new window/tab. In order to avoid the popup blocker, I need to call the window.open() method directly in the bookmarklet ie: at the browser-level. However, I want to keep the bookmarklet updatable by loading external Javascript files. To do this, the bookmarklet needs to append script nodes to the DOM. If i were to put window.open() code in one of these externally loaded scripts, the popup blocker would block it since its page-level. What I want to know is if I can create a wrapper function around window.open() in my bookmarklet, then call it from the externally loaded script? What is the scope and what are the permissions on a wrap such as this?

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• Workaround for UnsupportedAudioFileException ?

  - by tschan

  I'm in a very early stage of writing a small music/rhythm game in Java (via Slick framework, which in turns uses OpenAL, but that's probably irrelevant here). The game needs to read (and playback) several sound files in WAV format, but some of the files are throwing [javax.sound.sampled.UnsupportedAudioFileException] exceptions. at javax.sound.sampled.AudioSystem.getAudioInputStream(AudioSystem.java:1102) at org.newdawn.slick.openal.WaveData.create(WaveData.java:123) at org.newdawn.slick.openal.SoundStore.getWAV(SoundStore.java:713) at org.newdawn.slick.openal.SoundStore.getWAV(SoundStore.java:683) at org.newdawn.slick.Sound.<init>(Sound.java:33) The files can be played back just fine in Winamp or Foobar2000, so this means Java just don't recognize some variants of the file format. What are my options at this point? Note: The files in question are user-supplied, so i cannot just convert them beforehand (using something like audacity). Any conversion steps must be done at runtime.

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• Majority Voting in perl?

  - by aliocee

  Hi, i have 5 files containing the same words, i want read each word in all files and decide the winning word by detecting the following characters in a word (*, #, $, &) and generate output file i can only have 2 winners for example: file1 we$ are* ... file2 we$ are* ... file3 we* are$ ... file4 we$ are$ ... file5 we# are& ... output file: we$ - we$ is the winner since it occur in 3 files. are*$ - are* and are$ are the winners since both occur 2 times. here is how i started: #!/usr/local/bin/perl -w sub read_file_line { my $fh = shift; if ($fh and my $line = <$fh>) { chomp($line); return $line; } return; } open(my $f1, "words1.txt") or die "Can't"; open(my $f2, "words2.txt") or die "Can't"; open(my $f3, "words3.txt") or die "Can't"; open(my $f4, "words4.txt") or die "Can't"; open(my $f5, "words5.txt") or die "Can't"; my $r1 = read_file_line($f1); my $r2 = read_file_line($f2); my $r3 = read_file_line($f3); my $r4 = read_file_line($f4); my $r5 = read_file_line($f5); while ($f5) { what can i do here to decide and write the winning word in the output file? $r1 = read_file_line($f1); $r2 = read_file_line($f2); $r3 = read_file_line($f3); $r4 = read_file_line($f4); $r5 = read_file_line($f5); } Thanks.

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• [javascript] Populating jsTree based on XML data uploaded to server folder

  - by PFM

  tl:dr How can I populate jsTree based on a folder location instead of an exact XML url? I'm looking for a little direction on this project. Currently I am trying to copy file structures of hard drives as XML files and recreate them using jsTree on the webserver for a completely independent version of the file structure. I have some python script that outputs XML files that are formed to jsTree and automatically uploads to a folder on the server. The problem is now I am a little lost because I have to manually enter each XML file into jsTree code for it to display so I have multiple entries like this: $("#tree1") .jstree({ "plugins" : [ "themes", "xml_data", "ui", "search", "types" ], "xml_data" : { "ajax" : { "url" : "./XML_DATA/DRIVE1.xml" }, "xsl" : "nest" }, I see in the documentation that instead of populated by the direct file the folders are populated by "server.php" but no where in the php code does it point to any directories or files. After considering the problem I thought of a few solutions and could use some advice on them: Should I be trying to write php code to automatically look through my XML_DATA folder to upload each XML file? Should I just upload all the XML to mySQL and populate my tree based on that? Should the javascript be the code looking through the server's folder for XML files? All the XML is formed the same way but the number of XML files on the server will increase and will have to be refreshed as well as they will be overwritten with changes. Any direction would be appreciated, thanks.

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• How to give an alert in the mobile browser?

  - by MadhuBala

  When we try to open an attachment file from the mail, the desktop browser asks to save / open the file. As like that I need to do in the android mobile browser. How it's possible to ask a question in the mobile browser at the time of open an attachment file (*.ics)? Can anyone help me to develop an application for this ???

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• How do I configure emacs speedbar for C# mode?

  - by Alex B

  I'm using emacs with C# Mode and when I turn on the speedbar, no files show up by default. I can choose "show all files" on the speedbar mode, but then every .cs file shows up with a '[?]' next to the name. How do I properly configure speedbar so it shows up with .cs files by default? How do I get the '[+]' next to each file so I can navigate inside the file?

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• Menu contribution for popupsubmenu ?

  - by Mathan

  In eclipse plugin development i could add files in toolbar, menu and popupmenu by using menu contribution. In my project I want to add a set of files in the popupsubmenu, eg : Like the following Project Explorer - Right Click - New - Annotation, Class, Enum .... I want to add my files abc,def and xyz.. under the new menu item What is the locationuri for popupsubmenu ? Help me on this Thanks in advance Regards Mathan

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• How to create diagrams for papers.

  - by Simon

  I want to create some diagrams for some papers. Diagrams will contain some text, e.g. some console output. I need images for using also in html files. There is TikZ so can create images like this: http://www.texample.net/tikz/examples/boxes-with-text-and-math/ http://www.texample.net/tikz/examples/rule-based-diagram/ http://www.texample.net/tikz/examples/scenario-tree/ but as a result I get some ps/pdf files, not images. What's more I want to generate the pictures from text files as I want to track changes in some VCS, any binary files are not suitable for that.

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• File structure for PHP-based website.

  - by John Berryman

  I'm building a PHP-based web app for the first time and I haven't found anything to pattern it after. At this point I'm mostly curious about how the files should be arranged into directories so that development of the website can be manageable. This includes javascript scripts, images, stylesheets, cgi scripts, html files, pure php files that define common functions, etc. Question: Can someone point me to an explanation about how such a website is typically organized on the server?

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• Programatically importing a file and creating an instance of a class in Python

  - by benofsky

  I have a (python) list of strings which refer to python source files and subsequently classes within those files which I want to import and then create an instance of the classes within the files (everything follows a strict naming convention, making this theoretically possible), in Ruby I would do something like: require "lib/sources/#{source}.rb" s = source.constantize.new How would I do something similar in Python? Thanks, Ben

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• Using svn remove - preserve file on disk instead of having it deleted?

  - by user246114

  Hi, I am creating an eclipse project, which generates a lot of files I don't want to keep under version control. For example, it creates a project folder like: project/ bin/ horse.class cow.class src/ horse.java cow.java so what I do is add the project folder to svn, like: svn add project this puts everything under control, even the bin and .class files. All of those files will have the little 'a' next to them. How can I simply remove the 'add' status from those files? If I try: svn remove bin/horse.class I have to use the --force option and it deletes the file from disk. Is there a way to simply remove it from source but not delete the file from disk? Thanks

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• Most secure way to access my home Linux server while I am on the road? Specialized solution wanted

  - by Ace Paus

  I think many people may be in my situation. I travel on business with a laptop. And I need secure access to files from the office (which in my case is my home). The short version of my question: How can I make SSH/SFTP really secure when only one person needs to connect to the server from one laptop? In this situation, what special steps would make it almost impossible for anyone else to get online access to the server? A lot more details: I use Ubuntu Linux on both my laptop (KDE) and my home/office server. Connectivity is not a problem. I can tether to my phone's connection if needed. I need access to a large number of files (around 300 GB). I don't need all of them at once, but I don't know in advance which files I might need. These files contain confidential client info and personal info such as credit card numbers, so they must be secure. Given this, I don't want store all these files on Dropbox or Amazon AWS, or similar. I couldn't justify that cost anyway (Dropbox don't even publish prices for plans above 100 GB, and security is a concern). However, I am willing to spend some money on a proper solution. A VPN service, for example, might be part of the solution? Or other commercial services? I've heard about PogoPlug, but I don't know if there is a similar service that might address my security concerns? I could copy all my files to my laptop because it has the space. But then I have to sync between my home computer and my laptop and I found in the past that I'm not very good about doing this. And if my laptop is lost or stolen, my data would be on it. The laptop drive is an SSD and encryption solutions for SSD drives are not good. Therefore, it seems best to keep all my data on my Linux file server (which is safe at home). Is that a reasonable conclusion, or is anything connected to the Internet such a risk that I should just copy the data to the laptop (and maybe replace the SSD with an HDD, which reduces battery life and performance)? I view the risks of losing a laptop to be higher. I am not an obvious hacking target online. My home broadband is cable Internet, and it seems very reliable. So I want to know the best (reasonable) way to securely access my data (from my laptop) while on the road. I only need to access it from this one computer, although I may connect from either my phone's 3G/4G or via WiFi or some client's broadband, etc. So I won't know in advance which IP address I'll have. I am leaning toward a solution based on SSH and SFTP (or similar). SSH/SFTP would provided about all the functionality I anticipate needing. I would like to use SFTP and Dolphin to browse and download files. I'll use SSH and the terminal for anything else. My Linux file server is set up with OpenSSH. I think I have SSH relatively secured. I'm using Denyhosts too. But I want to go several steps further. I want to get the chances that anyone can get into my server as close to zero as possible while still allowing me to get access from the road. I'm not a sysadmin or programmer or real "superuser". I have to spend most of my time doing other things. I've heard about "port knocking" but I have never used it and I don't know how to implement it (although I'm willing to learn). I have already read a number of articles with titles such as: Top 20 OpenSSH Server Best Security Practices 20 Linux Server Hardening Security Tips Debian Linux Stop SSH User Hacking / Cracking Attacks with DenyHosts Software more... I have not implemented every single thing I've read about. I probably can't do that. But maybe there is something even better I can do in my situation because I only need access from a single laptop. I'm just one user. My server does not need to be accessible to the general public. Given all these facts, I'm hoping I can get some suggestions here that are within my capability to implement and that leverage these facts to create a great deal better security than general purpose suggestions in the articles above.

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• How to fix this IndexOutOfBoundsException

  - by Rida

  My program runs fine, but there is a little problem. When I add new tracks previously existing file to the ListBox, the program experiences an error. The code seems unwilling to do looping in a new file which was added in a different time. Please help me. Thanks .... public partial class Form1 : Form { //... string[] files, paths; private void button1_Click(object sender, EventArgs e) { if (openFileDialog1.ShowDialog() == DialogResult.OK) { files = openFileDialog1.SafeFileNames; paths = openFileDialog1.FileNames; for (int i = 0; i < files.Length - 1; i++) { listBox1.Items.Add(files[i]); } } } private void listBox1_SelectedIndexChanged(object sender, EventArgs e) { axWindowsMediaPlayer1.URL = paths[listBox1.SelectedIndex]; } }

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• C++, Ifstream opens local file but not file on HTTP Server

  - by fammi

  Hi, I am using ifstream to open a file and then read from it. My program works fine when i give location of the local file on my system. for eg /root/Desktop/abc.xxx works fine But once the location is on the http server the file fails to open. for eg http://192.168.0.10/abc.xxx fails to open. Is there any alternate for ifstream when using a URL address? thanks. part of the code where having problem: bool readTillEof = (endIndex == -1) ? true : false; // Open the file in binary mode and seek to the end to determine file size ifstream file ( fileName.c_str ( ), ios::in|ios::ate|ios::binary ); if ( file.is_open ( ) ) { long size = (long) file.tellg ( ); long numBytesRead; if ( readTillEof ) { numBytesRead = size - startIndex; } else { numBytesRead = endIndex - startIndex + 1; } // Allocate a new buffer ptr to read in the file data BufferSptr buf (new Buffer ( numBytesRead ) ); mpStreamingClientEngine->SetResponseBuffer ( nextRequest, buf ); // Seek to the start index of the byte range // and read the data file.seekg ( startIndex, ios::beg ); file.read ( (char *)buf->GetData(), numBytesRead ); // Pass on the data to the SCE // and signal completion of request mpStreamingClientEngine->HandleDataReceived( nextRequest, numBytesRead); mpStreamingClientEngine->MarkRequestCompleted( nextRequest ); // Close the file file.close ( ); } else { // Report error to the Streaming Client Engine // as unable to open file AHS_ERROR ( ConnectionManager, " Error while opening file \"%s\"\n", fileName.c_str ( ) ); mpStreamingClientEngine->HandleRequestFailed( nextRequest, CONNECTION_FAILED ); } }

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• Django templatetag "order of processing"

  - by Jason Persampieri

  I am trying to write a set of template tags that allow you to easily specify js and css files from within the template files themselves. Something along the lines of {% requires global.css %}, and later in the request, {% get_required_css %}. I have this mostly working, but there are a couple of issues. We'll start with the 'timing' issues. Each template tag is made up of two steps, call/init and render. Every call/init happens before any render procedure is called. In order to guarantee that all of the files are queued before the {% get_required_css %} is rendered, I need to build my list of required files in the call/init procedures themselves. So, I need to collect all of the files into one bundle per request. The context dict is obviously the place for this, but unfortunately, the call/init doesn't have access to the context variable. Is this making sense? Anyone see a way around this (without resorting to a hack-y global request object)? Another possibility to store these in a local dict but they would still need to be tied to the request somehow... possibly some sort of {% start_requires %} tag? But I have no clue how to make that work either.

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• Visual C++ 9 Linker file size limitation.

  - by Raindog

  It appears that the visual C++ 9 linker has a file allocation algorithm that doubles the size of the file every allocation, so you get 512mb, 1024mb, 2048mb, 4096mb. The problem is that it is using a library that cannot handle files larger 2048MB, and as such crashes with an error such as "cannot read file at is the disk full or write protected". Is there a way to bypass this limitation or otherwise replace the linker with something else that works? A bit of background, I have a code generator that generates a large number of files, ~15k cpp files, I've managed to reduce the number of files to something about 6k to get something that at least completes the linking process, I would like to be able to include all 15k without having to create multiple libs.

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• Exception message (Python 2.6)

  - by TurboJupi

  If I want to open binary file (in Python 2.6), that doesn't exists, program exits with an error and prints this: Traceback (most recent call last): File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 4, in <module> pkl_file = open('monitor.dat', 'rb') IOError: [Errno 2] No such file or directory: 'monitor.dat' I can handle this with 'try-except', like: try: pkl_file = open('monitor.dat', 'rb') monitoring_pickle = pickle.load(pkl_file) pkl_file.close() except Exception: print 'No such file or directory' Does anybody know, how could I, in caught Exception, print the following line? File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 11, in <module> pkl_file = open('monitor.dat', 'rb') So, program would not exits, and I would have useful information.

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• Is it possible to make accordion (Expand/Collapse) without <div> [closed]

  - by jitendra

  With below code.. in below code I want whole <h3> click-able but in default condition link text of right side should be shown as "open" and if accordion is open then it should be convert into "close" in default(closed) condition <h3>Title <span>open</span></h3> <p> user contributed content licensed under user contributed content licensed user contributed content licensed under user contributed content licensed user contributed content licensed under user contributed content licensed </p> in open condition <h3>Title <span>close</span></h3> <p> user contributed content licensed under user contributed content licensed user contributed content licensed under user contributed content licensed user contributed content licensed under user contributed content licensed </p> and if JavaScript is disable then all dive should be opened

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• How to launch new Firefox window with multiple tabs using Python

  - by newbie py

  Hi, I want to create a MSWindows Python program that would launch a new Firefox window with multiple tabs each time it is run. For example if I want to search "hello", a new window pops out (even if a Firefox window is already open) and then launches a Google and Bing tabs searching for "hello". If I change the keyword to "world", a new browser pops out again with Google and Bing tabs searching for "world". I've looked at the webbrowser module but couldn't get it to: 1. Launch a new browser when a browser is already open: e.g. webbrowser.open('http://www.google.com',new=1) will instead open a new tab 2. Launch multiple tabs simultaneously in the same window Appreciate the help. Thanks.

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