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  • LWJGL: Camera distance from image plane?

    - by Rogem
    Let me paste some code before I ask the question... public static void createWindow(int[] args) { try { Display.setFullscreen(false); DisplayMode d[] = Display.getAvailableDisplayModes(); for (int i = 0; i < d.length; i++) { if (d[i].getWidth() == args[0] && d[i].getHeight() == args[1] && d[i].getBitsPerPixel() == 32) { displayMode = d[i]; break; } } Display.setDisplayMode(displayMode); Display.create(); } catch (Exception e) { e.printStackTrace(); System.exit(0); } } public static void initGL() { GL11.glEnable(GL11.GL_TEXTURE_2D); GL11.glShadeModel(GL11.GL_SMOOTH); GL11.glClearColor(0.0f, 0.0f, 0.0f, 0.0f); GL11.glClearDepth(1.0); GL11.glEnable(GL11.GL_DEPTH_TEST); GL11.glDepthFunc(GL11.GL_LEQUAL); GL11.glMatrixMode(GL11.GL_PROJECTION); GL11.glLoadIdentity(); GLU.gluPerspective(45.0f, (float) displayMode.getWidth() / (float) displayMode.getHeight(), 0.1f, 100.0f); GL11.glMatrixMode(GL11.GL_MODELVIEW); GL11.glHint(GL11.GL_PERSPECTIVE_CORRECTION_HINT, GL11.GL_NICEST); } So, with the camera and screen setup out of the way, I can now ask the actual question: How do I know what the camera distance is from the image plane? I also would like to know what the angle between the image plane's center normal and a line drawn from the middle of one of the edges to the camera position is. This will be used to consequently draw a vector from the camera's position through the player's click-coordinates to determine the world coordinates they clicked (or could've clicked). Also, when I set the camera coordinates, do I set the coordinates of the camera or do I set the coordinates of the image plane? Thank you for your help. EDIT: So, I managed to solve how to calculate the distance of the camera... Here's the relevant code... private static float getScreenFOV(int dim) { if (dim == 0) { float dist = (float) Math.tan((Math.PI / 2 - Math.toRadians(FOV_Y))/2) * 0.5f; float FOV_X = 2 * (float) Math.atan(getScreenRatio() * 0.5f / dist); return FOV_X; } else if (dim == 1) { return FOV_Y; } return 0; } FOV_Y is the Field of View that one defines in gluPerspective (float fovy in javadoc). This seems to be (and would logically be) for the height of the screen. Now I just need to figure out how to calculate that vector.

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  • SWT Drag and Drop support for Text widget

    - by bryantsai
    I've written an application recently using SWT. In one of its dialog box, I have a few widgets, one of which is Text, which is designed to support DND with other widgets. I've first added DND support for the 2 Tree widgets on the same dialog box (both drag source and drop target). Before I added DND support for that Text widget, I noticed that on Linux platform (gtk), SWT Text widget automatically get drag and drop support. That is, I can already drag from the other Tree widgets and drop on this Text (at any position to inserted there), as well as selecting and dragging any text from this Text to other Tree or Text widget. However, this is only working on Linux platform but not on Windows. The same program, if running on Windows, will not have any DND support for that Text widget (Tree widgets of course have DND support since I specifically write for them). So here's what I want to achieve on Windows as well: drop text at any position in Text widget. before dropping and while hovering, able to see the caret position clearly where the intended position to drop. caret position should move along with the mouse cursor. support multi-line in Text widget SOLUTION: DropTarget target = new DropTarget(sytledText, DND.DROP_MOVE | DND.DROP_COPY); target.setTransfer(new Transfer[] { TextTransfer.getInstance() }); target.addDropListener(new StyleTextDropTargetEffect(sytledText)); Use StyledText instead of Text widget Use StyledTextDropTargetEffect (or extend it) and add it as dr op listener

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  • Inline text box labels with WPF

    - by Douglas
    I'm trying to reproduce the layout of some paper forms in a WPF application. Labels for text boxes are to be "inline" with the content of the text boxes, rather than "outside" like normal Windows forms. So, with an Xxxxxx label: +-----------------------------+ | Xxxxxx: some text written | | in the multiline input. | | | | another paragraph continues | | without indentation. | | | | | +-----------------------------+ The Xxxxxx cannot be editable, if the user selects all the content of the text box, the label must remain unselected, I need to be able to style the text colour/formatting of the label separately, when there is no text in the text box, but it has focus, the caret should flash just after the label, and I need the baselines of the text in the text box and the label to line up. One solution I tried was putting a textblock partially over the input, then using text indent to indent the editable text, though this caused problems with following paragraphs, since they were indented too. I'm not sure how to indent just the first paragraph. It required some fiddling to get the text to line up - a more reliable setup would be ideal. So, any suggestions on how to set this up? Thanks

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  • How to -accurately- measure size in pixels of text being drawn on a canvas by drawTextOnPath()

    - by Nick
    I'm using drawTextOnPath() to display some text on a Canvas and I need to know the dimensions of the text being drawn. I know this is not feasible for paths composed of multiple segments, curves, etc. but my path is a single segment which is perfectly horizontal. I am using Paint.getTextBounds() to get a Rect with the dimensions of the text I want to draw. I use this rect to draw a bounding box around the text when I draw it at an arbitrary location. Here's some simplified code that reflects what I am currently doing: // to keep this example simple, always at origin (0,0) public drawBoundedText(Canvas canvas, String text, Paint paint) { Rect textDims = new Rect(); paint.getTextBounds(text,0, text.length(), textDims); float hOffset = 0; float vOffset = paint.getFontMetrics().descent; // vertically centers text float startX = textDims.left; / 0 float startY = textDims.bottom; float endX = textDims.right; float endY = textDims.bottom; path.moveTo(startX, startY); path.lineTo(endX, endY); path.close(); // draw the text canvas.drawTextOnPath(text, path, 0, vOffset, paint); // draw bounding box canvas.drawRect(textDims, paint); } The results are -close- but not perfect. If I replace the second to last line with: canvas.drawText(text, startX, startY - vOffset, paint); Then it works perfectly. Usually there is a gap of 1-3 pixels on the right and bottom edges. The error seems to vary with font size as well. Any ideas? It's possible I'm doing everything right and the problem is with drawTextOnPath(); the text quality very visibly degrades when drawing along paths, even if the path is horizontal, likely because of the interpolation algorithm or whatever its using behind the scenes. I wouldnt be surprised to find out that the size jitter is also coming from there.

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  • How to draw semi-transparent text on a graphics object?

    - by awe
    I want to draw a text with 32 bit transparency on a graphics object. When I try, I only get black color in the result. If I try to draw a line with the same semitransparent color, it works perfectly. I have this code: lBitmap As New Bitmap(32, 32, PixelFormat.Format32bppArgb) lGraphic As Graphics = Graphics.FromImage(lBitmap) lGraphic.SmoothingMode = SmoothingMode.HighQuality lGraphic.InterpolationMode = InterpolationMode.HighQualityBicubic lGraphic.Clear(Color.Transparent) Dim lTestTransparencyColor As Color = Color.FromArgb(100, 140, 0, 230) lGraphic.DrawLine(New Pen(lTestTransparencyColor), 0, 0, 32, 32) lBrush As New SolidBrush(lTestTransparencyColor) lGraphic.DrawString("A", New Font("Arial", 12), lBrush, 0, 0) Dim lImage As Image = lBitmap lImage.Save("D:\Test.png", Imaging.ImageFormat.Png) The line is drawn with the transparency applied correctly, but the text is black with no transparency. I was thinking it may be that SolidBrush does not support transparency, but I found a predefined brush named Transparent (Brushes.Transparent) that was a SolidBrush when I looked at it in debug. I tried to use Brushes.Transparent as the brush when drawing the text, and it was successfully not showing at all. That means I get full transparency to work, but not partial transparency.

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  • DELETE and EDIT is not working in my python program

    - by user2968025
    This is a simple python program that ADD, DELETE, EDIT and VIEW student records. The problem is, DELETE and EDIT is not working. I dont know why but when I tried removing one '?' in the DELETE dunction, I had the error that says there are only 8 columns and it needs 10. But originally, there are only 9 columns. I don't know where it got the other one to make it 10. Please help.. :( import sys import sqlite3 import tkinter import tkinter as tk from tkinter import * from tkinter.ttk import * def newRecord(): studentnum="" name="" age="" birthday="" address="" email="" course="" year="" section="" con=sqlite3.connect("Students.db") cur=con.cursor() cur.execute("CREATE TABLE IF NOT EXISTS student(studentnum TEXT, name TEXT, age TEXT, birthday TEXT, address TEXT, email TEXT, course TEXT, year TEXT, section TEXT)") def save(): studentnum=en1.get() name=en2.get() age=en3.get() birthday=en4.get() address=en5.get() email=en6.get() course=en7.get() year=en8.get() section=en9.get() student=(studentnum,name,age,birthday,address,email,course,year,section) cur.execute("INSERT INTO student(studentnum,name,age,birthday,address,email,course,year,section) VALUES(?,?,?,?,?,?,?,?,?)",student) con.commit() win=tkinter.Tk();win.title("Students") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Add Record") lbl.pack() lbl1=tkinter.Label(win,width=30,text="Student Number : ") lbl1.pack() en1=tkinter.Entry(win,width=30) en1.pack() lbl2=tkinter.Label(win,width=30,text="Name : ") lbl2.pack() en2=tkinter.Entry(win,width=30) en2.pack() lbl3=tkinter.Label(win,width=30,text="Age : ") lbl3.pack() en3=tkinter.Entry(win,width=30) en3.pack() lbl4=tkinter.Label(win,width=30,text="Birthday : ") lbl4.pack() en4=tkinter.Entry(win,width=30) en4.pack() lbl5=tkinter.Label(win,width=30,text="Address : ") lbl5.pack() en5=tkinter.Entry(win,width=30) en5.pack() lbl6=tkinter.Label(win,width=30,text="Email : ") lbl6.pack() en6=tkinter.Entry(win,width=30) en6.pack() lbl7=tkinter.Label(win,width=30,text="Course : ") lbl7.pack() en7=tkinter.Entry(win,width=30) en7.pack() lbl8=tkinter.Label(win,width=30,text="Year : ") lbl8.pack() en8=tkinter.Entry(win,width=30) en8.pack() lbl9=tkinter.Label(win,width=30,text="Section : ") lbl9.pack() en9=tkinter.Entry(win,width=30) en9.pack() btn1=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Save Student",command=save) btn1.pack() def editRecord(): studentnum1="" def edit(): studentnum1=en10.get() studentnum="" name="" age="" birthday="" address="" email="" course="" year="" section="" con=sqlite3.connect("Students.db") cur=con.cursor() row=cur.fetchone() cur.execute("DELETE FROM student WHERE name = '%s'" % studentnum1) con.commit() def save(): studentnum=en1.get() name=en2.get() age=en3.get() birthday=en4.get() address=en5.get() email=en6.get() course=en7.get() year=en8.get() section=en8.get() student=(studentnum,name,age,email,birthday,address,email,course,year,section) cur.execute("INSERT INTO student(studentnum,name,age,email,birthday,address,email,course,year,section) VALUES(?,?,?,?,?,?,?,?,?)",student) con.commit() win=tkinter.Tk();win.title("Students") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Edit Reocrd :"+'\t'+studentnum1) lbl.pack() lbl1=tkinter.Label(win,width=30,text="Student Number : ") lbl1.pack() en1=tkinter.Entry(win,width=30) en1.pack() lbl2=tkinter.Label(win,width=30,text="Name : ") lbl2.pack() en2=tkinter.Entry(win,width=30) en2.pack() lbl3=tkinter.Label(win,width=30,text="Age : ") lbl3.pack() en3=tkinter.Entry(win,width=30) en3.pack() lbl4=tkinter.Label(win,width=30,text="Birthday : ") lbl4.pack() en4=tkinter.Entry(win,width=30) en4.pack() lbl5=tkinter.Label(win,width=30,text="Address : ") lbl5.pack() en5=tkinter.Entry(win,width=30) en5.pack() lbl6=tkinter.Label(win,width=30,text="Email : ") lbl6.pack() en6=tkinter.Entry(win,width=30) en6.pack() lbl7=tkinter.Label(win,width=30,text="Course : ") lbl7.pack() en7=tkinter.Entry(win,width=30) en7.pack() lbl8=tkinter.Label(win,width=30,text="Year : ") lbl8.pack() en8=tkinter.Entry(win,width=30) en8.pack() lbl9=tkinter.Label(win,width=30,text="Section : ") lbl9.pack() en9=tkinter.Entry(win,width=30) en9.pack() btn1=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Save Record",command=save) btn1.pack() win=tkinter.Tk();win.title("Edit Student") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Edit Record") lbl.pack() lbl10=tkinter.Label(win,width=30,text="Student Number : ") lbl10.pack() en10=tkinter.Entry(win) en10.pack() btn2=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Edit",command=edit) btn2.pack() def deleteRecord(): studentnum1="" win=tkinter.Tk();win.title("Delete Student Record") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Delete Record") lbl.pack() lbl10=tkinter.Label(win,text="Student Number") lbl10.pack() en10=tkinter.Entry(win) en10.pack() def delete(): studentnum1=en10.get() con=sqlite3.connect("Students.db") cur=con.cursor() row=cur.fetchone() cur.execute("DELETE FROM student WHERE name = '%s';" % studentnum1) con.commit() win=tkinter.Tk();win.title("Record Deleted") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Record Deleted :") lbl.pack() lbl=tkinter.Label(win,width=30,text=studentnum1) lbl.pack() btn=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Ok",command=win.destroy) btn.pack() btn2=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Delete",command=delete) btn2.pack() def viewRecord(): con=sqlite3.connect("Students.db") cur=con.cursor() win=tkinter.Tk();win.title("View Student Record"); row=cur.fetchall() lbl1=tkinter.Label(win,background="#000",foreground="#ddd",width=300,text="\n\tStudent Number"+"\t\tName"+"\t\tAge"+"\t\tBirthday"+"\t\tAddress"+"\t\tEmail"+"\t\tCourse"+"\t\tYear"+"\t\nSection") lbl1.pack() for row in cur.execute("SELECT * FROM student"): lbl2=tkinter.Label(win,width=300,text= row[0] + '\t\t' + row[1] + '\t' + row[2] + '\t\t' + row[3] + '\t\t' + row[4] + '\t\t' + row[5] + '\t\t' + row[6] + '\t\t' + row[7] + '\t\t' + row[8] + '\n') lbl2.pack() con.close() but1=tkinter.Button(win,background="#000",foreground="#fff", width=150,text="Close",command=win.destroy) but1.pack() root=tkinter.Tk();root.title("Student Records") menubar=tkinter.Menu(root) manage=tkinter.Menu(menubar,tearoff=0) manage.add_command(label='New Record',command=newRecord) manage.add_command(label='Edit Record',command=editRecord) manage.add_command(label='Delete Record',command=deleteRecord) menubar.add_cascade(label='Manage',menu=manage) view=tkinter.Menu(menubar,tearoff=0) view.add_command(label='View Record',command=viewRecord) menubar.add_cascade(label='View',menu=view) root.config(menu=menubar) lbl=tkinter.Label(root,background="#000",foreground="#ddd",font=("Verdana",15),width=30,text="Student Records") lbl.pack() lbl1=tkinter.Label(root,text="\nSubmitted by :") lbl1.pack() lbl2=tkinter.Label(root,text="Chavez, Vissia Nicole P") lbl2.pack() lbl3=tkinter.Label(root,text="BSIT 4-4") lbl3.pack()

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  • antlr3StringStreamNew string input error [ at offset 0, at <EOF> : cannot match to any predicted input... ]

    - by Embeguru
    I'm using ANTLR 3.4 with simplecTreeParser example and want to give string input from main.c I'v modified input in main as mentioned bellow pANTLR3_UINT8 input_string = (pANTLR3_UINT8)"int a;"; input = antlr3StringStreamNew(input_string, ANTLR3_ENC_8BIT, sizeof(input_string),(pANTLR3_UINT8)"ABCD"); Apparently getting following error -end of input-(1) : error 3 : 23:1: declaration : ( variable | functionHeader ';' - ^( FUNC_DECL functionHeader ) | functionHeader block - ^( FUNC_DEF functionHeader block ) );, at offset 0, at : cannot match to any predicted input... The parser returned 1 errors, tree walking aborted. Any other way to give String input Regards

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  • Which full-text search package should I use for SQLite3?

    - by Benjamin Pollack
    SQLite3 appears to come with three different full-text search engines, called FTS1, FTS2, and FTS3. The documentation available on the website mentions that FTS1 is stable, FTS2 is in development, and that you should use FTS2. Examples I find online use FTS3, which is in CVS, and not documented versus FTS2. None of the full-text search engines come with the amalgamated source, as near as I can tell. So, my question: which of these three engines, if any, should I use for full-text indexing in SQLite? Or should I simply use a third-party tool like Sphinx, or a custom solution in Lucene, instead?

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  • Input system reference trouble

    - by Ockonal
    Hello, I'm using SFML for input system in my application. size_t WindowHandle; WindowHandle = ...; // Here I get the handler sf::Window InputWindow(WindowHandle); const sf::Input *InputHandle = &InputWindow.GetInput(); // [x] Error At the last lines I have to get reference for the input system. Here is declaration of GetInput from documentation: const Input & sf::Window::GetInput () const The problem is: >invalid conversion from ‘const sf::Input*’ to ‘sf::Input*’ What's wrong?

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  • input file cannot be found

    - by Eric Smith
    I am just messing around with reading input files with java until I got stumped at the most basic of steps... finding the input file! The input.txt file is in the same directory as my class file that is calling it yet eclipse still gives me an error that it cant be found: "Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException" My code: package pa; import java.util.Scanner; public class Project { public static void main(String[] args) { java.io.File file = new java.io.File("input.txt"); System.out.println(file.getAbsolutePath()); Scanner input = new Scanner(file); } } input.txt is in the same package, same folder and everything. I'm confused :(

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  • How can I shift html-text in the JButton to the left?

    - by Roman
    I use HTML to put text into a JButton. In this way I can play with colors and text size. What I do not like is the distance from the left border of the button and the text (this separation is too large). Is there a way to decrease this distance? I think it should be some parameter in the style of the HTML code. Sample of the code: JButton btn = new JButton("<html><span style='color:#000000; font-size: 11pt;'>" + label + "</span></html>");

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  • http_post() variables to php script from SMS message but only append data to text file if certain variable (telephone number) equals a known

    - by user1592162
    All, I have an SMS gateway application running on my server that passes incoming SMS messages to a php script. That script writes the data to a text file. Certain aspects of the message can be extracted as variables - for example: Message content: $msgdata Sender: $originator Time: $receivedtime etc... Using the script below I can easily write the message to a text file but it will write the data of every SMS that comes in. I only want to write to a text file if the $originator variable is a certain telephone number (e.g 07123456321) $date = date("d.m.Y H:i:s"); $msgdata = $_REQUEST["msgdata"]; $myFile3 = "test.txt"; $fh = fopen($myFile3, 'a') or die("can't open file"); $stringData3 = "$date - $msgdata\n"; fwrite($fh, $stringData3); fclose($fh); Your assistance is bery much appreciated. Many thanks in advance.

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  • Font-awesome, input type 'submit'

    - by denis.peplin
    It seems no class for input type 'submit' in font-awesome. Is it possible to use some class from font-awesome for button input? I've added icons to all buttons (which actually links with class 'btn' from twitter-bootstrap) in my applications, but can't add icons on 'input type submit'. Or, how to use this code: input#image-button{ background: #ccc url('icon.png') no-repeat top left; padding-left: 16px; height: 16px; } html: <input type="submit" id="image-button">Text</input> (which I took from HTML: How to make a submit button with text + image in it?) with font-awesome?

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  • By passing div id, can i change target of text replacement?

    - by crosenblum
    I am using the code below to replace text inside a div. But I need to loop through a specific div, instead of everything on the page, that is the div's text nodes... I just do not understand how to refer to the div in the code below. (function (parent) { var childs = parent.childNodes; // if there are children to this if (childs && childs.length) { // loop through each text node for (var i = 0, node; node = childs[i]; i++) {

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  • How can I highlight the line of text that is closest to the mouse?

    - by Aaron Digulla
    I have a long text and I'd like to offer the user a reading help: The current line should be highlighted. To make it easier, I'll just use the Y coordinate of the mouse (this way, the mouse pointer isn't going to get in the way). I have a big DIV with the id content which fills the whole width and a small DIV with the class content for the text (see here for an example). I'm using jQuery 1.4. How can I highlight the line of text that is closest to the current mouse position?

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  • Supersede users need to press enter after inputting a string in python 3.0

    - by Cimex
    I've been attempting to create a simple Rock, Paper, Scissors game in python 3.0 -- very standard task for anybody learning programming. But, as I finish up to a point, I think,"wow, that'd be awesome", or,"it'd be cool to do this!" So anyways, I keep building upon the project... I've developed a menu, a single player game vs the computer, and just finished the multiplayer game. But, I've realized, that the multiplayer game isn't very effective. It just dosen't work like the analog version of the game. Currently, it'll ask for player1's input, then player2's input, compare them, and spit out the result and the current score. What I'd rather have happen is that the program asks for both players input at the same time and both players input their choice at the same time. I understand that I can easily do that by just grabbing the index of the first and second answer and compare the 2 inputs -- easy. But what I'd rather have happen is that after both players enter their one character answers at the same time (r for rock, p for paper, or s for scissors), then the program will auto enter the input. Not needing someone to press enter. The input would be dictated by the fact that 2 characters have been entered. I guess my question is: Is there any way to dictate what can be used as an input for 'enter'?

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  • HTML javascript form submitted when image input button

    - by DreamU
    I have a form that contains this single input field, which is nothing more than a button to Print the current web page: <div align="center"> <input type="image" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> After the printing, the page re-submits itself (to itself). Why does it do this and can I stop it? If I just change the type to "input", this code does not re-submit itself after printing: <div align="center"> <input type="input" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> Unfortunately, our style conventions require me to use that button image rather than the standard input button.

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  • Use JQuery to check a checkbox in a parent list-item?

    - by Daniel O'Connor
    Hey Everyone, I'm brand new to Javascript and JQuery, so I've been reading up on it and am trying to check (and set inactive) a checkbox in a parent list-item when one of the children are checked. If this doesn't make any sense, take a look at the list structure. <ul> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 1</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 2 <ul> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 1</li> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 2</li> </ul> </li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 3</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 4</li> </ul> If Child 1 or Child 2 is checked, I want the input in Parent 2 to be checked and set inactive. I've started working on it, but got stuck here: $(function(){ $('.child').click(function() { $(this).parent().parent().parent().toggle(); }); }); As you can see, I didn't make it far. Any help would be appreciated. Thanks!

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  • In SQL Server 2008, when would I use a full text index that covered several tables?

    - by Suddy
    I wanted to do a full text search across several related tables in SQL Server 2008. From browsing this site I've realised the best option is via a view, but initially I thought I was meant to add several tables to the same full text index via Management Studio. I started to do this and realised the index would have no idea how they were related, so my question is: when would I want to have a full text index covering several tables in this way? Apologies for the vagueness, I am just trying to satisfy my curiosity after Google let me down.

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  • identify the input that is multiple of 11 and odd or even java

    - by Bolor Ch
    i am trying to write code to determine the nature of input using if statement only. The nature of input could be following: a multiple of 11 even or odd. For the code below, when I enter my input, it does not display the result as "input:NOT:ODD". Also how can I check multiple conditions with if statement? (else is not considered) import java.util.Scanner; public class test { public static void main( String args[] ) { Scanner input = new Scanner( System.in ); int x; int EO; int Mult; System.out.print ( "Enter value: " ); x = input.nextInt(); EO = x % 2; Mult = x % 11; if (EO > 0 && Mult > 0) { System.out.printf ("%d:NOT:ODD"); } } }

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  • How do I include a newline in a text message sent as email from an ASP.Net application?

    - by Tim Goodman
    I have an ASP.Net Application that sends text messages to mobile phones. It does this by sending an email. For instance, if your phone number is 555-555-5555 and your wireless carrier is Verizon, you can send an email to [email protected] and it will show up as a text message. I want to be able to include a newline in the body of the message. How do I do this? Also please note that my ASP.Net program gets the message from a database (MS SQL Server) so what I really need to know is what characters to include in the message body when I store it in my database. I already tried \n but it just showed up in the text message as \n

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  • HTML5 Search Input: No Background Image in Chrome?

    - by Jason
    I have been pulling my hair out trying to get Chrome to style my search input with a background image. Firefox has no problem, but I fear it's because it treats the input as a regular text input. Is this simply not possible? Try this as a demo: <input type="search" /> ?input[type="search"] { background: transparent url(http://google.com/intl/en_ALL/images/srpr/logo1w.png) no-repeat 0 0; }?????? If it worked correctly, it should put Google's logo (or part of it) as the background image for the "Search" input. But as you will see when you look at this in Chrome, it DOES NOT WORK. Any ideas, or is this just one of HTML5's quirks? :\

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  • How to draw multiple line text to uiimageview iphone?

    - by Hu?nh Phong
    I have UITextView for text, after user press DONE, I convert text to UIImageView and show it. It works with one line of text very good, and Screenshot 1 . But if user types two lines, or more: the result is still one line??? Screenshot 2 I want to display two or more lines in UIimageView Can anybody help me! Thank you very much! Here is my code: -(UIImage *)convertTextToImage : (ObjectText *) objT; { UIGraphicsBeginImageContext(CGSizeMake(([objT.content sizeWithFont:objT.font].width+10), ([objT.content sizeWithFont:objT.font].height+10))); [[objT getcolor] set]; [objT.content drawAtPoint:CGPointMake(5, 5) withFont:objT.font]; UIImage *result = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); return result; }

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  • How to dictate a Non-English text on an English Windows 7?

    - by hellelampe
    I'm using an English Windows 7 with speech recognition working fine if I'm dictating in English. I would like to dictate a letter in German. I don't need further features that let you use your computer without a mouse, I want to dictate my letter. If I just start speaking German the Windows speech recognition software just gives me English gibberish. When I set the Speech Recognition to "German" in the Speech Properties dialog, I get the error message: Speech Recognition could not start because the language configuration is not supported. The recognizer language must match the language of the user interface. Please change the recognizer language in the Speech Recognition control panel under Advanced Options. This error message doesn't help me, because it tells me that I either need to change my system language or the language I want to dictate. But that's not what I want. How can I dictate in German on my PC with the English version of Windows 7?

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