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  • C++ overloading virtual = operator

    - by taz
    Hello, here is the code for my question: class ICommon { public: virtual ICommon& operator=(const ICommon & p)const=0; }; class CSpecial : public ICommon { public: CSpecial& operator=(const CSpecial & cs) { //custom operations return *this; } }; CSpecial obj; Basically: I want the interface ICommon to force it's descendants to implement = operator but don't want to have any typecasts in the implementation. The compiler says "can't instantiate an abstract class. Any help/advice will be appreciated.

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  • Overriding fetch in multiple spine models

    - by Adam Charnock
    I need to override Spine's @fetch() method in all of my Spine models. Currently I have code duplication as follows: TastypieEndpointMixin = fromJSON: (data) -> return unless data return Spine.Model.fromJSON(data.objects) class App.models.Position extends Spine.Model @configure 'Position', 'code', 'name' @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/position/?format=json' validate: -> 'code is required' unless @code @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer class App.models.Player extends Spine.Model @configure 'Player', 'first_name', 'last_name', ... @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/player/?format=json' @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer My question is: How can I create some form of parent class which contains @fetch()? I know this should be a simple problem to solve. I have tried many options (including extending Spine.Model and Spine.Model.Ajax), but nothing works and I cannot seem to get my head around it.

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  • Why isn't the "this." command needed in this constructor? (java)

    - by David
    I'm reading a book about java. It just got to explaining how you create a class called "deck" which contains an array of cards as its instance variable(s). Here is the code snippit: class Deck { Card[] cards; public Deck (int n) { cards = new Card[n]; } } why isn't the this. command used? for example why isn't the code this: class Deck { Card[[] cards; public Deck (int n) { this.cards = new Card[n]; } }

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  • Weak reference and Strong reference

    - by theband
    package uk.co.bigroom.utils { import flash.utils.Dictionary; /** * Class to create a weak reference to an object. A weak reference * is a reference that does not prevent the object from being * garbage collected. If the object has been garbage collected * then the get method will return null. */ public class WeakRef { private var dic:Dictionary; /** * The constructor - creates a weak reference. * * @param obj the object to create a weak reference to */ public function WeakRef( obj:* ) { dic = new Dictionary( true ); dic[obj] = 1; } /** * To get a strong reference to the object. * * @return a strong reference to the object or null if the * object has been garbage collected */ public function get():* { for ( var item:* in dic ) { return item; } return null; } } } In this Class, how they denote one as Weak Reference and one as Strong reference.

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  • spring mvc forward to jsp

    - by jerluc
    I currently have my web.xml configured to catch 404s and send them to my spring controller which will perform a search given the original URL request. The functionality is all there as far as the catch and search go, however the trouble begins to arise when I try to return a view. <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver" p:order="1"> <property name="mediaTypes"> <map> <entry key="json" value="application/json" /> <entry key="jsp" value="text/html" /> </map> </property> <property name="defaultContentType" value="application/json" /> <property name="favorPathExtension" value="true" /> <property name="viewResolvers"> <list> <bean class="org.springframework.web.servlet.view.BeanNameViewResolver" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value="" /> </bean> </list> </property> <property name="defaultViews"> <list> <bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" /> </list> </property> <property name="ignoreAcceptHeader" value="true" /> </bean> This is a snippet from my MVC config file. The problem lies in resolving the view's path to the /WEB-INF/jsp/ directory. Using a logger in my JBoss setup, I can see that when I test this search controller by going to a non-existent page, the following occurs: Server can't find the request Request is sent to 404 error page (in this case my search controller) Search controller performs search Search controller returns view name (for this illustration, we'll assume test.jsp is returned) Based off of server logger, I can see that org.springframework.web.servlet.view.JstlView is initialized once my search controller returns the view name (so I can assume it is being picked up correctly by the InternalResourceViewResolver) Server attempts to return content to browser resulting in a 404! A couple things confuse me about this: I'm not 100% sure why this isn't resolving when test.jsp clearly exists under the /WEB-INF/jsp/ directory. Even if there was some other problem, why would this result in a 404? Shouldn't a 404 error page that results in another 404 theoretically create an infinite loop? Thanks for any help or pointers! Controller class [incomplete]: @Controller public class SiteMapController { //-------------------------------------------------------------------------------------- @Autowired(required=true) private SearchService search; @Autowired(required=true) private CatalogService catalog; //-------------------------------------------------------------------------------------- @RequestMapping(value = "/sitemap", method = RequestMethod.GET) public String sitemap (HttpServletRequest request, HttpServletResponse response) { String forwardPath = ""; try { long startTime = System.nanoTime() / 1000000; String pathQuery = (String) request.getAttribute("javax.servlet.error.request_uri"); Scanner pathScanner = new Scanner(pathQuery).useDelimiter("\\/"); String context = pathScanner.next(); List<ProductLightDTO> results = new ArrayList<ProductLightDTO>(); StringBuilder query = new StringBuilder(); String currentValue; while (pathScanner.hasNext()) { currentValue = pathScanner.next().toLowerCase(); System.out.println(currentValue); if (query.length() > 0) query.append(" AND "); if (currentValue.contains("-")) { query.append("\""); query.append(currentValue.replace("-", " ")); query.append("\""); } else { query.append(currentValue + "*"); } } //results.addAll(this.doSearch(query.toString())); System.out.println("Request: " + pathQuery); System.out.println("Built Query:" + query.toString()); //System.out.println("Result size: " + results.size()); long totalTime = (System.nanoTime() / 1000000) - startTime; System.out.println("Total TTP: " + totalTime + "ms"); if (results == null || results.size() == 0) { forwardPath = "home.jsp"; } else if (results.size() == 1) { forwardPath = "product.jsp"; } else { forwardPath = "category.jsp"; } } catch (Exception ex) { System.err.println(ex); } System.out.println("Returning view: " + forwardPath); return forwardPath; } }

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  • Methodology for a Rails app

    - by Aaron Vegh
    I'm undertaking a rather large conversion from a legacy database-driven Windows app to a Rails app. Because of the large number of forms and database tables involved, I want to make sure I've got the right methodology before getting too far. My chief concern is minimizing the amount of code I have to write. There are many models that interact together, and I want to make sure I'm using them correctly. Here's a simplified set of models: class Patient < ActiveRecord::Base has_many :PatientAddresses has_many :PatientFileStatuses end class PatientAddress < ActiveRecord::Base belongs_to :Patient end class PatientFileStatus < ActiveRecord::Base belongs_to :Patient end The controller determines if there's a Patient selected; everything else is based on that. In the view, I will be needing data from each of these models. But it seems like I have to write an instance variable in my controller for every attribute that I want to use. So I start writing code like this: @patient = Patient.find(session[:patient]) @patient_addresses = @patient.PatientAddresses @patient_file_statuses = @patient.PatientFileStatuses @enrollment_received_when = @patient_file_statuses[0].EnrollmentReceivedWhen @consent_received = @patient_file_statuses[0].ConsentReceived @consent_received_when = @patient_file_statuses[0].ConsentReceivedWhen The first three lines grab the Patient model and its relations. The next three lines are examples of my providing values to the view from one of those relations. The view has a combination of text fields and select fields to show the data above. For example: <%= select("patientfilestatus", "ConsentReceived", {"val1"="val1", "val2"="val2", "Written"="Written"}, :include_blank=true )% <%= calendar_date_select_tag "patient_file_statuses[EnrollmentReceivedWhen]", @enrollment_complete_when, :popup=:force % (BTW, the select tag isn't really working; I think I have to use collection_select?) My questions are: Do I have to manually declare the value of every instance variable in the controller, or can/should I do it within the view? What is the proper technique for displaying a select tag for data that's not the primary model? When I go to save changes to this form, will I have to manually pick out the attributes for each model and save them individually? Or is there a way to name the fields such that ActiveRecord does the right thing? Thanks in advance, Aaron.

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  • Question regarding C++ Templates

    - by Isuru
    I used a simple class for a test program about templates, this is what I did: template <typename T> class test { public: test<T>::test(); T out(); }; template <typename T> test<T>::test() { } T test<T>::out() { } int main() { //test<int> t; } But when I try to compile it says 'T' : undeclared identifier and use of class template requires template argument list , pointing to the same line, where I have implemented the method out() . Can anyone please explain what the problem is?? I'm using visual studio 2008.

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  • Get the newest file from directory structure year/month/date/time

    - by Radek
    I store backups of databases in a directory structure year/month/day/time/backup_name an example would be basics_mini/2012/11/05/012232/RATIONAL.0.db2inst1.NODE0000.20110505004037.001 basics_mini/2012/11/06/012251/RATIONAL.0.db2inst1.NODE0000.20110505003930.001 note that timestamp from the backup file cannot be used. Before the automation testing starts the server time is set to 5.5.2011 So the question is how I can get the latest file if I pass the "base directory" (basics_mini) to some function that I am going to code. My thoughts are that I list the base directory and sort by time to get the year. Then I do the same for month, day and time. I wonder if there is any "easier" solution to that in php.

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  • Java interface design

    - by Nayn
    Hi, I had an interface initially as below. public interface testMe { public Set<String> doSomething(); } public class A implements testMe { public Set<String> doSomething() { return // Set<String> } } I had similar classes implementing testMe. Now I have to add one more class which returns Set<Some Object> public class X implements testMe() { public Set<Some OBject> doSomething() { } } How could i add this mehtod in the interface without breaking existing classes? Thanks Nayn

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  • How to add model entity property in WCF RIA service

    - by Oblomingo
    I'm developing silverlight app with WCF Ria service. I'm using MS SQL database and Entity Framework as ORM framework (Database first method). Model with domain service are in separate project - App1.Data. Silverlight and generated model proxy classes are in App1 project. I want to add property to model entity class EntityClass to get this property on client side. So I did it that way - added this class to project App1.Data: public partial class EntityClass { [DataMember] public List<EntityClass2> PropertyName {get; set;} } After rebuilding EntityClass proxy on client side doesn't have this new property. Where is my mistake?

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  • PHP Doxygen Collaboration Diagrams

    - by Shabbyrobe
    I've started playing around with doxygen to generate documentation from my PHP code. I notice there are two diagrams in the generated output - inheritance and collaboration. I know about the inheritance one, but the collaboration one has piqued my interest since reading the manual: If the COLLABORATION_GRAPH and HAVE_DOT tags are set to YES then doxygen will generate a graph for each documented class showing the direct and indirect implementation dependencies (inheritance, containment, and class references variables) of the class with other documented classes. The impression I get from that description is that composition relationships should be represented by the collaboration diagram as well, but it always seems to just be identical to the inheritance one. Is there something I can do to hint to Doxygen the things I would like to appear in this diagram? Does it just not work with PHP?

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  • Excluding some classes from the cobertura report doesn't work

    - by user357480
    I tried to exclude some classes from cobertura as specified in this site <cobertura-instrument todir="${voldemort.instrumented.dir}" datafile="${cobertura.instrument.file}"> <classpath refid="tools-classpath" /> <ignore regex=".*\.xsd" /> <fileset dir="${voldemort.dist.dir}/classes"> <include name="**/*.class" /> <exclude name="**/client/protocol/pb/*.class"/> <exclude name="**/server/http/*.class"/> </fileset> </cobertura-instrument> but that doesn't work help me out, pleaseeeeeeeeeeee

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  • Hibernate/JPA - annotating bean methods vs fields

    - by Benju
    I have a simple question about usage of Hibernate. I keep seeing people using JPA annotations in one of two ways by annotating the fields of a class and also by annotating the get method on the corresponding beans. My question is as follows: Is there a difference between annotating fields and bean methods with JPA annoations such as @Id. example: @Entity public class User { **@ID** private int id; public int getId(){ return this.id; } public void setId(int id){ this.id=id; } } -----------OR----------- @Entity public class User { private int id; **@ID** public int getId(){ return this.id; } public void setId(int id){ this.id=id; } }

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  • Java hashcode based on identity

    - by hjfreyer
    The default behavior of Object.hashCode() is to return essentially the "address" of the object so that a.hashCode() == b.hashCode() if and only if a == b. How can I get this behavior in a user-defined class if a superclass already defines hashCode()? For instance: class A { public int hashCode() { return 0; } } class B extends A { public int hashCode() { // Now I want to return a unique hashcode for each object. // In pythonic terms, it'd look something like: return Object.hashCode(this); } } Ideas?

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  • Any way to access the type of a Scala Option declaration at runtime using reflection?

    - by Graham Lea
    So, I have a Scala class that looks like this: class TestClass { var value: Option[Int] = None } and I'm tackling a problem where I have a String value and I want to coerce it into that Option[Int] at runtime using reflection. To do so, I need to know that the field is an Option and that the type parameter of the Option is Int. What are my options for figuring out that the type of 'value' is Option[Int] at runtime (i.e. using reflection)? I have seen similar problems solved by annotating the field, e.g. @OptionType(Int.class). I'd prefer a solution that didn't require annotations on the reflection target if possible.

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  • Explanation of output

    - by Anon
    My program class Building { Building() { System.out.print("b "); } Building(String name) { this(); System.out.print("bn " + name); } }; public class House extends Building { House() { System.out.print("h "); // this is line# 1 } House(String name) { this(); // This is line#2 System.out.print("hn " + name); } public static void main(String[] args) { new House("x "); } } We know that compiler will write a call to super() as the first line in the child class's constructor. Therefore should not the output be: b (call from compiler written call to super(), before line#2 b (again from compiler written call to super(),before line#1 ) h hn x But the output is b h hn x Why is that?

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  • Can't get Javac to work on Mac OS X

    - by elguapo-85
    I am trying to compile with javac on Snow Leopard through the command line. I have Xcode installed. I am just using a simple Hello World file, it works in Eclipse but I can't get it to work using javac. javac -version returns javac 1.6.0_17 HelloWorld.java public class HelloWorld { public static void main(String[] args) { String message = "Welcome to Java!"; System.out.println(message); } } I type: javac HelloWorld.java and get the following error. HelloWorld.java:1: class, interface, or enum expected public class HelloWorld ^ 1 error and... javac -cp . HelloWorld.java returns the same. echo $CLASSPATH just returns blank. Thanks for the help.

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  • jQuery selector question

    - by Jakey
    I have a span and an anchor inside a table cell. I have the anchor set up to show a tooltip. I would like the text inside the span to be used for the tooltip. How can I select this text in jQuery? <td class="row-head" colspan="5"><span class="tip-text">Complete Coverage</span><a href="#" class="help"></a></td> JQuery code - the current selector always finds the first instance only for all tips. $(document).ready(function() { $('.help').qtip({ style: { name: 'cream', tip: true }, content: { text: $(this).find('span.tip-text').html() } }); }); Thanks

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  • Importing Classes Within a Module

    - by CodeJoust
    Currently, I have a parser with multiple classes that work together. For Instance: TreeParser creates multiple Product and Reactant modules which in turn create multiple Element classes. The TreeParser is called by a render method within the same module, which is called from the importer. Currently, using the class name in the imported module file works only if the file calling the module contains from module_name import *, so the classes are imported into the main namespace. Finally, if the package has dependencies (such as re and another another module within the same folder), where is the best place to require those modules? Within the __init__.py file or within the module itself? I don't really want to add the module name in front of every call to the class, in case I do call import *, however, is it possible to use a variable name of the current module to call the class, or use a workaround in the __init__.py file? I'm probably used to the ruby require '' method instead of python's module system.

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  • open iphone Mail from Actionsheet..

    - by totato
    hi .. I want to open Mail app from my app when the one button in actionsheet is pressed, I know this way : -(IBAtion)openClick:(id)sender { [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@”mailto:[email protected]”]]; } but can I write this method inside if statement or switch case?(in ControlView class NOT NSObject class , because I use actionsheet for this propose) like this: - (void)actionSheet:(UIActionSheet *)modalView clickedButtonAtIndex:(NSInteger)buttonIndex { switch (buttonIndex) { case 0: { [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@”mailto:[email protected]”]]; break; } I can't test my code because simulator doesn't have the Mail app.. So I need to know is this will work in controlView or must write it in NSObject class ? + seconde question : I want to open Mail app from my app and copy the content in the view to mail body,then the user choice the contact from his contacts list ! Is this way achieve my goal?

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  • RIA Services and multiple/dynamic "Include" strategies

    - by user326526
    As an example, assume the following simple model: public class Order { public List<LineItem> LineItems { get; set; } public List<Fee> Fees { get; set; } } public class LineItem { } public class Fee { } With RIA Services, if I want to retrieve an Order and include all of it's line items in the same network call, I can statically place an [Include] attribute on the above LineItems collection. This works great for a single scenario, but what happens when I need multiple "include strategies"? For instance, one situation might call for including the Fees collection and NOT the LineItems collection. Is there any way with RIA Services to control what's included at runtime without redefining your model and/or creating dtos with the attributes statically placed for each use-case?

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  • How to mock WCF Web Services with Rhino Mocks.

    - by Will
    How do I test a class that utilizes proxy clients generated by a Web Service Reference? I would like to mock the client, but the generated client interface doesn't contain the close method, which is required to properly terminate the proxy. If I don't use the interface, but instead a concrete reference, I get access to the close method but loose the ability to mock the proxy. I'm trying to test a class similar to this: public class ServiceAdapter : IServiceAdapter, IDisposable { // ILoggingServiceClient is generated via a Web Service reference private readonly ILoggingServiceClient _loggingServiceClient; public ServiceAdapter() : this(new LoggingServiceClient()) {} internal ServiceAdapter(ILoggingServiceClient loggingServiceClient) { _loggingServiceClient = loggingServiceClient; } public void LogSomething(string msg) { _loggingServiceClient.LogSomething(msg); } public void Dispose() { // this doesn't compile, because ILoggingServiceClient doesn't contain Close(), // yet Close is required to properly terminate the WCF client _loggingServiceClient.Close(); } }

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  • IntelliJ: Including jars in a jar artifact

    - by skiaddict1
    Developing on the Mac with IntelliJ 9.0.2. I have a program which depends on two library jars. I have figured out how to get IntelliJ to make me a jar of my source (with the Artifact tab), and even to include the two jars in it. However, if I get a listing of the jar file it produces, it looks like this: com/acme/MyClass1.class com/acme/MyClass2.class ... mylib1.jar myLib2.jar And, no surprises, if I double-click the jar file, it gets a NoClassDefFoundError the first time it tries to access a class in one or other library jar. How do I get IntelliJ to include the two library jars such that the classes are visible?

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  • ASP.NET Thread Safety in aspx.cs code behind file

    - by Tim Michalski
    I am thinking of adding a DataContext as a member variable to my aspx.cs code-behind class for executing LinqToSql queries. Is this thread safe? I am not sure if a new instance of this code-behind class is created for each HTTP request, or if the instance is shared amongst all request threads? My fear is that I will get 10 simultaneous concurrent http requests that will be using the same database session. public partial class MyPage : System.Web.UI.Page { private DataContext myDB = new DataContext(); protected void MyAction_Click(object sender, EventArgs e) { myDB.DoWork(); } }

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  • How to force a line break after each image in Safari Reader?

    - by futlib
    I was unable to activate Safari Reader in a local HTML file, so I cannot give you a running example but only describe my problem: The markup of my blog posts is basically this: <div class="post"> <div class="post-header">Hello, World</div> <div class="post-body"> <p>Look at this picture:</p> <p><img src="http://37prime.com/news/wp-content/uploads/2008/03/safari_icon.png"/></p> <p>Isn't that a nice picture?</p> </div> </div> This looks as expected in all browsers, including Safari. In Safari Reader however, the third paragraph "Isn't that a nice picture?" is floating around the image, instead of being on a paragraph of it's own. Has anybody experienced a similar problem?

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