Search Results

Search found 50247 results on 2010 pages for 'base class'.

Page 587/2010 | < Previous Page | 583 584 585 586 587 588 589 590 591 592 593 594  | Next Page >

  • Entity Framework 4 code-only reference column name

    - by Victor
    I created classes: public class Country { public long CountryId {get;set;} public string CountryName {get;set;} } public class Profile { public long ProfileId {get;set;} public string ProfileName {get;set;} public Country Country {get;set;} } and configuration for Profile: public class ProfileConfiguration : EntityConfiguration<Profile> { public IlluminatiCoreProfileConfiguration() { Relation(p => p.Country); } } Then I create context and run context.CreateDatabase(). New database contains table Profiles with column Country_CountryId. How can I write configuration for changing column name to "CountryId"? Thanks.

    Read the article

  • How to mock WCF Web Services with Rhino Mocks.

    - by Will
    How do I test a class that utilizes proxy clients generated by a Web Service Reference? I would like to mock the client, but the generated client interface doesn't contain the close method, which is required to properly terminate the proxy. If I don't use the interface, but instead a concrete reference, I get access to the close method but loose the ability to mock the proxy. I'm trying to test a class similar to this: public class ServiceAdapter : IServiceAdapter, IDisposable { // ILoggingServiceClient is generated via a Web Service reference private readonly ILoggingServiceClient _loggingServiceClient; public ServiceAdapter() : this(new LoggingServiceClient()) {} internal ServiceAdapter(ILoggingServiceClient loggingServiceClient) { _loggingServiceClient = loggingServiceClient; } public void LogSomething(string msg) { _loggingServiceClient.LogSomething(msg); } public void Dispose() { // this doesn't compile, because ILoggingServiceClient doesn't contain Close(), // yet Close is required to properly terminate the WCF client _loggingServiceClient.Close(); } }

    Read the article

  • Can't get images to go under each other

    - by Thomas Pen
    ello I'm new to html and css and tried to display a images that are floating right. Now I want to get the images under each other but is doesn't work. Can someone help me? this my css code for the images: .imagesLeft{ float: left; margin: 5px; } .imagesRight{ float: right; margin: 5px; } this my html code for the images: <div class="imagesRight"> <img src="../images/medewerkers.jpg"> </div> <div class="imagesRight"> <img src="../images/medewerkers1.jpg"> </div> <div class="imagesRight"> <img src="../images/medewerkers2.jpg"> </div> Thanks in advance !

    Read the article

  • Why are static imports of static methods with same names legal?

    - by user1055638
    Lets say we have these packages and classes: package p1; public class A1 { public static void a() {} } package p2; public class A1 { public static void a() {} } package p3; import static p1.A1.a; import static p2.A1.a; public class A1 { public static void test() { } } I am wondering, why the static import of methods is legal (won't result in compile time error) in package p3? We won't be able to use them further in the test() method as such usage will result in the compile time error. Why it is not the same as with a normal import of classes. Lets say we would like to import classes A1 from packages p1 and p2 into p3: package p3; import p1.A1; import p2.A1; such import is illegal and will result in the compile time error.

    Read the article

  • SortList duplicated key, but it shouldn't

    - by Luca
    I have a class which implements IList interface. I requires a "sorted view" of this list, but without modifying it (I cannot sort directly the IList class). These view shall be updated when the original list is modified, keeping items sorted. So, I've introduced a SortList creation method which create a SortList which has a comparer for the specific object contained in the original list. Here is the snippet of code: public class MyList<T> : ICollection, IList<T> { ... public SortedList CreateSortView(string property) { try { Lock(); SortListView sortView; if (mSortListViews.ContainsKey(property) == false) { // Create sorted view sortView = new SortListView(property, Count); mSortListViews.Add(property, sortView); foreach (T item in Items) sortView.Add(item); } else sortView = mSortListViews[property]; sortView.ReferenceCount++; return (sortView); } finally { Unlock(); } } public void DeleteSortView(string property) { try { Lock(); // Unreference sorted view mSortListViews[property].ReferenceCount--; // Remove sorted view if (mSortListViews[property].ReferenceCount == 0) mSortListViews.Remove(property); } finally { Unlock(); } } protected class SortListView : SortedList { /// <summary> /// /// </summary> /// <param name="property"></param> /// <param name="capacity"></param> public SortListView(string property, int capacity) : base(new GenericPropertyComparer(typeof(T).GetProperty(property, BindingFlags.Instance | BindingFlags.Public)), capacity) { } /// <summary> /// Reference count. /// </summary> public int ReferenceCount = 0; /// <summary> /// /// </summary> /// <param name="item"></param> public void Add(T item) { Add(item, item); } /// <summary> /// /// </summary> /// <param name="item"></param> public void Remove(T item) { // Base implementation base.Remove(item); } /// <summary> /// Compare object on a generic property. /// </summary> class GenericPropertyComparer : IComparer { #region Constructors /// <summary> /// Construct a GenericPropertyComparer specifying the property to compare. /// </summary> /// <param name="property"> /// A <see cref="PropertyInfo"/> which specify the property to be compared. /// </param> /// <remarks> /// The <paramref name="property"/> parameter imply that the compared objects have the specified property. The property /// must be readable, and its type must implement the IComparable interface. /// </remarks> public GenericPropertyComparer(PropertyInfo property) { if (property == null) throw new ArgumentException("property doesn't specify a valid property"); if (property.CanRead == false) throw new ArgumentException("property specify a write-only property"); if (property.PropertyType.GetInterface("IComparable") == null) throw new ArgumentException("property type doesn't IComparable"); mSortingProperty = property; } #endregion #region IComparer Implementation public int Compare(object x, object y) { IComparable propX = (IComparable)mSortingProperty.GetValue(x, null); IComparable propY = (IComparable)mSortingProperty.GetValue(y, null); return (propX.CompareTo(propY)); } /// <summary> /// Sorting property. /// </summary> private PropertyInfo mSortingProperty = null; #endregion } } /// <summary> /// Sorted views of this ReactList. /// </summary> private Dictionary<string, SortListView> mSortListViews = new Dictionary<string, SortListView>(); } Practically, class users request to create a SortListView specifying the name of property which determine the sorting, and using the reflection each SortListView defined a IComparer which keep sorted the items. Whenever an item is added or removed from the original list, every created SortListView will be updated with the same operation. This seems good at first chance, but it creates me problems since it give me the following exception when adding items to the SortList: System.ArgumentException: Item has already been added. Key in dictionary: 'PowerShell_ISE [C:\Windows\sysWOW64\WindowsPowerShell\v1.0\PowerShell_ISE.exe]' Key being added: 'PowerShell_ISE [C:\Windows\system32\WindowsPowerShell\v1.0\PowerShell_ISE.exe]' As you can see from the exception message, thrown by SortedListView.Add(object), the string representation of the key (the list item object) is different (note the path of the executable). Why SortList give me that exception? To solve this I tried to implement a GetHashCode implementation for the underlying object, but without success: public override int GetHashCode() { return ( base.GetHashCode() ^ mApplicationName.GetHashCode() ^ mApplicationPath.GetHashCode() ^ mCommandLine.GetHashCode() ^ mWorkingDirectory.GetHashCode() ); }

    Read the article

  • Can't get Javac to work on Mac OS X

    - by elguapo-85
    I am trying to compile with javac on Snow Leopard through the command line. I have Xcode installed. I am just using a simple Hello World file, it works in Eclipse but I can't get it to work using javac. javac -version returns javac 1.6.0_17 HelloWorld.java public class HelloWorld { public static void main(String[] args) { String message = "Welcome to Java!"; System.out.println(message); } } I type: javac HelloWorld.java and get the following error. HelloWorld.java:1: class, interface, or enum expected public class HelloWorld ^ 1 error and... javac -cp . HelloWorld.java returns the same. echo $CLASSPATH just returns blank. Thanks for the help.

    Read the article

  • Methodology for a Rails app

    - by Aaron Vegh
    I'm undertaking a rather large conversion from a legacy database-driven Windows app to a Rails app. Because of the large number of forms and database tables involved, I want to make sure I've got the right methodology before getting too far. My chief concern is minimizing the amount of code I have to write. There are many models that interact together, and I want to make sure I'm using them correctly. Here's a simplified set of models: class Patient < ActiveRecord::Base has_many :PatientAddresses has_many :PatientFileStatuses end class PatientAddress < ActiveRecord::Base belongs_to :Patient end class PatientFileStatus < ActiveRecord::Base belongs_to :Patient end The controller determines if there's a Patient selected; everything else is based on that. In the view, I will be needing data from each of these models. But it seems like I have to write an instance variable in my controller for every attribute that I want to use. So I start writing code like this: @patient = Patient.find(session[:patient]) @patient_addresses = @patient.PatientAddresses @patient_file_statuses = @patient.PatientFileStatuses @enrollment_received_when = @patient_file_statuses[0].EnrollmentReceivedWhen @consent_received = @patient_file_statuses[0].ConsentReceived @consent_received_when = @patient_file_statuses[0].ConsentReceivedWhen The first three lines grab the Patient model and its relations. The next three lines are examples of my providing values to the view from one of those relations. The view has a combination of text fields and select fields to show the data above. For example: <%= select("patientfilestatus", "ConsentReceived", {"val1"="val1", "val2"="val2", "Written"="Written"}, :include_blank=true )% <%= calendar_date_select_tag "patient_file_statuses[EnrollmentReceivedWhen]", @enrollment_complete_when, :popup=:force % (BTW, the select tag isn't really working; I think I have to use collection_select?) My questions are: Do I have to manually declare the value of every instance variable in the controller, or can/should I do it within the view? What is the proper technique for displaying a select tag for data that's not the primary model? When I go to save changes to this form, will I have to manually pick out the attributes for each model and save them individually? Or is there a way to name the fields such that ActiveRecord does the right thing? Thanks in advance, Aaron.

    Read the article

  • How to force a line break after each image in Safari Reader?

    - by futlib
    I was unable to activate Safari Reader in a local HTML file, so I cannot give you a running example but only describe my problem: The markup of my blog posts is basically this: <div class="post"> <div class="post-header">Hello, World</div> <div class="post-body"> <p>Look at this picture:</p> <p><img src="http://37prime.com/news/wp-content/uploads/2008/03/safari_icon.png"/></p> <p>Isn't that a nice picture?</p> </div> </div> This looks as expected in all browsers, including Safari. In Safari Reader however, the third paragraph "Isn't that a nice picture?" is floating around the image, instead of being on a paragraph of it's own. Has anybody experienced a similar problem?

    Read the article

  • Java interface design

    - by Nayn
    Hi, I had an interface initially as below. public interface testMe { public Set<String> doSomething(); } public class A implements testMe { public Set<String> doSomething() { return // Set<String> } } I had similar classes implementing testMe. Now I have to add one more class which returns Set<Some Object> public class X implements testMe() { public Set<Some OBject> doSomething() { } } How could i add this mehtod in the interface without breaking existing classes? Thanks Nayn

    Read the article

  • Working with the Objective-C/Cocoa flat namespace

    - by Stephen Blinkhorn
    I've not found anything that addresses my specific name space question as yet. I am working on some AudioUnit plug-ins featuring Cocoa based GUIs. The plug-ins use a common library of user interface classes (sliders, buttons etc) which are simply added to each Xcode project. When I recompile and distribute updates it is pretty much guaranteed that at least one user interface class will have been updated since the last release. If the user launches an older plug-in before an updated plug-in then the old Cocoa classes are already loaded into the run time and the plug-in attempts to use the older implementations - often resulting in a failure one way or another. I know frameworks are the intended solution but the overhead and backwards compatibility issues are not ideal. I prefix all class names where possible but what options do I have to ensure that each plug-in contains unique class names for the shared user interface classes?

    Read the article

  • Account confirmation email sent as SPAM :( PHP

    - by praveen
    Hi, I'm using PHPMailer to send a confirmation email for newly registered users in my social network. But i found out most of them have ended up in user's spam list. (hotmail and yahoo). How to avoid this? This is my script $mail=new PHPMailer(); $mail->IsSMTP(); $mail->SMTPAuth = mSMTPAuth(); $mail->SMTPSecure = mSMTPSecure(); $mail->Host = mHost(); $mail->Port = mPort(); $mail->Username = mUsername(); $mail->Password = mPassword(); $mail->From = mFrom(); $mail->FromName = "SiteName"; $mail->Subject = "SiteName New Account Activation"; $mail->IsHTML(true); $mail->WordWrap = 50; $mail->Body = "<h2>Welcome to " .$sitename. " " .$username. "! </h2><br><br>"; $mail->Body .= "Please click on the link below to verify your email address:<br><br>"; $mail->Body .= "<a href='".$base. "verify.php?a=" .$gen_key."'>".$base. "verify.php?a=" .$gen_key."</a>"; $mail->Body .= "<br><br>Regards<br>"; $mail->AltBody = "Welcome to " .$sitename. " " .$username. "!\n\nTo verify your email address, please click on the link below:\n\n".$base. "verify.php?a=" .$gen_key; $mail->AddAddress($email); $mail->Send(); $mail->ClearAddresses(); Please help. This is really confusing. Thanks in advance

    Read the article

  • Passing session data to ModelForm inside of ModelAdmin

    - by theactiveactor
    I'm trying to initialize the form attribute for MyModelAdmin class inside an instance method, as follows: class MyModelAdmin(admin.ModelAdmin): def queryset(self, request): MyModelAdmin.form = MyModelForm(request.user) My goal is to customize the editing form of MyModelForm based on the current session. When I try this however, I keep getting an error (shown below). Is this the proper place to pass session data to ModelForm? If so, then what may be causing this error? TypeError at ... Exception Type: TypeError Exception Value: issubclass() arg 1 must be a class Exception Location: /usr/lib/pymodules/python2.6/django/forms/models.py in new, line 185

    Read the article

  • Java hashcode based on identity

    - by hjfreyer
    The default behavior of Object.hashCode() is to return essentially the "address" of the object so that a.hashCode() == b.hashCode() if and only if a == b. How can I get this behavior in a user-defined class if a superclass already defines hashCode()? For instance: class A { public int hashCode() { return 0; } } class B extends A { public int hashCode() { // Now I want to return a unique hashcode for each object. // In pythonic terms, it'd look something like: return Object.hashCode(this); } } Ideas?

    Read the article

  • How to specify a different column for a @Inheritance JPA annotation

    - by Cue
    @Entity @Inheritance(strategy = InheritanceType.JOINED) public class Foo @Entity @Inheritance(strategy = InheritanceType.JOINED) public class BarFoo extends Foo mysql> desc foo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ mysql> desc barfoo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | | foo_id | int | | bar_id | int | +---------------+-------------+ mysql> desc bar; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ Is it possible to specify column barfo.foo_id as the joined column? Are you allowed to specify barfoo.id as BarFoo's @Id since you are overriding the getter/seeter of class Foo? I understand the schematics behind this relationship (or at least I think I do) and I'm ok with them. The reason I want an explicit id field for BarFoo is exactly because I want to avoid using a joined key (foo _id, bar _id) when querying for BarFoo(s) or when used in a "stronger" constraint. (as Ruben put it)

    Read the article

  • Can't instantiate javax.servlet.ServletException

    - by Denis
    Hello, experts! I am trying to create instance of class javax.servlet.ServletException with following code public class MyTroubleViewer { public static void main(String[] args) { javax.servlet.ServletException servletException = new javax.servlet.ServletException("Hello"); System.out.println(servletException.getMessage()); } } But I get exception on creating: Exception in thread "main" java.lang.ClassFormatError: Absent Code attribute in method that is not native or abstract in class file javax/servlet/ServletException ... Maven helps me with dependecies: <dependency> <groupId>javax</groupId> <artifactId>javaee-api</artifactId> <version>6.0</version> <type>jar</type> <scope>compile</scope> </dependency> What am I doing wrong?

    Read the article

  • How to run a jar file in hadoop

    - by Arihant
    I have created a jar file using the java file from this blog using following statements javac -classpath /usr/local/hadoop/hadoop-core-1.0.3.jar -d /home/hduser/dir Dictionary.java /usr/lib/jvm/jdk1.7.0_07/bin/jar cf Dictionary.jar /home/hduser/dir Now i have tried running this jar in hadoop by hit and trial of various commands 1hduser@ubuntu:~$ /usr/local/hadoop/bin/hadoop jar Dictionary.jar Output: Warning: $HADOOP_HOME is deprecated. RunJar jarFile [mainClass] args... 2.hduser@ubuntu:~$ /usr/local/hadoop/bin/hadoop jar Dictionary.jar Dictionary Output: Warning: $HADOOP_HOME is deprecated. Exception in thread "main" java.lang.ClassNotFoundException: Dictionary at java.net.URLClassLoader$1.run(URLClassLoader.java:366) at java.net.URLClassLoader$1.run(URLClassLoader.java:355) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:354) at java.lang.ClassLoader.loadClass(ClassLoader.java:423) at java.lang.ClassLoader.loadClass(ClassLoader.java:356) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:264) at org.apache.hadoop.util.RunJar.main(RunJar.java:149) How can i run the jar in hadoop? I have the right DFS Locations as per needed by my program.

    Read the article

  • How do I make this ASP.NET MVC controller more testable?

    - by Ragesh
    I have a controller that overrides OnActionExecuting and does something like this: protected override void OnActionExecuting(ActionExecutingContext filterContext) { base.OnActionExecuting(filterContext); string tenantDomain = filterContext.RouteData.Values["tenantDomain"] as string; if (!string.IsNullOrWhiteSpace(tenantDomain)) { using (var tx = BeginTransaction()) { this.Tenant = repo.FindOne(t => t.Domain == tenantDomain); } } } Tenant is a protected property with a private setter. The class itself is an abstract base controller that my real controllers derive from. I have code in other controllers that looks a lot like this: if (Tenant == null) { // Do something } else { // Do something else } How do I test this code? What I need to do is to somehow set the Tenant property, but I can't because: It's a protected property, and It has a private setter Changing the visibility of Tenant doesn't "feel" right. What are my alternatives to unit test my derived controllers?

    Read the article

  • In Sinatra, best way to serve iPhone layout vs. normal layout?

    - by Doug
    I'm writing a Sinatra app which needs to render different layouts based on whether the user is using an iPhone or a regular browser. I can detect the browser type using Rack-Mobile-Detect but I'm not sure of the best way to tell Sinatra which layout to use. Also, I have a feeling that how I choose to do this may also break page caching. Is that true? Example code: require 'sinatra/base' require 'haml' require 'rack/mobile-detect' class Orca < Sinatra::Base use Rack::MobileDetect helpers do def choose_layout if request.env['X_MOBILE_DEVICE'] == :iPhone # use iPhone layout else # use normal layout end end end before do # should I use a before filter? choose_layout() end get '/' do haml :home # with proper layout end end #Class Orca

    Read the article

  • Trouble using South with Django and Heroku

    - by Dan
    I had an existing Django project that I've just added South to. I ran syncdb locally. I ran manage.py schemamigration app_name locally I ran manage.py migrate app_name --fake locally I commit and pushed to heroku master I ran syncdb on heroku I ran manage.py schemamigration app_name on heroku I ran manage.py migrate app_name on heroku I then receive this: $ heroku run python notecard/manage.py migrate notecards Running python notecard/manage.py migrate notecards attached to terminal... up, run.1 Running migrations for notecards: - Migrating forwards to 0005_initial. > notecards:0003_initial Traceback (most recent call last): File "notecard/manage.py", line 14, in <module> execute_manager(settings) File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 220, in execute output = self.handle(*args, **options) File "/app/lib/python2.7/site-packages/south/management/commands/migrate.py", line 105, in handle ignore_ghosts = ignore_ghosts, File "/app/lib/python2.7/site-packages/south/migration/__init__.py", line 191, in migrate_app success = migrator.migrate_many(target, workplan, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 221, in migrate_many result = migrator.__class__.migrate_many(migrator, target, migrations, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 292, in migrate_many result = self.migrate(migration, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 125, in migrate result = self.run(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 99, in run return self.run_migration(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 81, in run_migration migration_function() File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 57, in <lambda> return (lambda: direction(orm)) File "/app/notecard/notecards/migrations/0003_initial.py", line 15, in forwards ('user', self.gf('django.db.models.fields.related.ForeignKey')(to=orm['auth.User'])), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 226, in create_table ', '.join([col for col in columns if col]), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 150, in execute cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) django.db.utils.DatabaseError: relation "notecards_semester" already exists I have 3 models. Section, Semester, and Notecards. I've added one field to the Notecards model and I cannot get it added on Heroku. Thank you.

    Read the article

  • Should old/legacy/unused code be deleted from source control repository?

    - by Checkers
    I've encountered this in multiple projects. As the code base evolves, some libraries, applications, and components get abandoned and/or deprecated. Most people prefer to keep them in. The usual argument is that the code does not really take any space, it can be left alone until needed again. So a repository slowly turns into a cesspool of legacy code, where it's hard to find anything. Some people delete old code, since it creates clutter, raises more questions for new people, and you can restore any old snapshot of the code base anyway. However you can't always find the old code if you don't know where to look, as none of the (common) VCS I know offer search over the entire repository including all historical revisions, and the only way to search the old files is to check out the revision where the deleted file exists. What would be a good approach to repository management?

    Read the article

  • How to tell a method has a varargs argument using reflection?

    - by Anthony Kong
    Here is a sample code package org.example; import java.lang.reflect.Method; class TestRef { public void testA(String ... a) { for (String i : a) { System.out.println(i); } } public static void main(String[] args){ Class testRefClass = TestRef.class; for (Method m: testRefClass.getMethods()) { if (m.getName() == "testA") { System.out.println(m); } } } } The output is public void org.example.TestRef.testA(java.lang.String[]) So the signature of the method is reported to take a array of String. Is there any mean in the reflection library I can tell that the method is originally declared to take a varargs?

    Read the article

  • ASP.Net Roles: Page-Level Security Question

    - by jlrolin
    We're currently in the process of re-creating a brand new security model that dwarfs our existing process. Right now, we plan on grabbing a user's roles during the login process and then using a Base Page class to check if the user has the role of the corresponding page the user is navigating to. We can limit the menu's options by the user's roles as well, but we have had problems with users navigating to pages in our system by typing them in or having old bookmarks. Obviously, we need some sort of page level access. A simple function in our Base Page class that checks the role in the Arraylist against the page's assigned role would work, but I was wondering if there was any built-in functionality to support this or a cleaner solution possibly.

    Read the article

  • Accessing typedef from the instance

    - by piotr
    As in stl containers, why can't we access a typedef inside the class from the class instance? Is there a particular insight into this? When value_type was a template parameter it could help making more general code if there wasn't the need to specify the template parameters as in vector::value_type Example: class T { public: typedef int value_type; value_type i; }; T t; T::value_type i; // ok t.value_type i; // won't work

    Read the article

  • Overriding fetch in multiple spine models

    - by Adam Charnock
    I need to override Spine's @fetch() method in all of my Spine models. Currently I have code duplication as follows: TastypieEndpointMixin = fromJSON: (data) -> return unless data return Spine.Model.fromJSON(data.objects) class App.models.Position extends Spine.Model @configure 'Position', 'code', 'name' @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/position/?format=json' validate: -> 'code is required' unless @code @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer class App.models.Player extends Spine.Model @configure 'Player', 'first_name', 'last_name', ... @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/player/?format=json' @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer My question is: How can I create some form of parent class which contains @fetch()? I know this should be a simple problem to solve. I have tried many options (including extending Spine.Model and Spine.Model.Ajax), but nothing works and I cannot seem to get my head around it.

    Read the article

  • How to put tags inside an html attribute?

    - by Mycol
    Using xslt i want to create an attribute: <span class="tooltip"> <xsl:attribute name="onmouseover"> <xsl:text>javascript:function(</xsl:text> <span class="label">Aggiunta</span> <xsl:apply-tempaltes/> <xsl:text>)</xsl:text> </xsl:attribute> The problem is that only the pure text is putted inside the attribute, like <span class="tooltip" onmouseover="javascript:function(Aggiunta ...)"> whithout the span tags or the tags that may come from apply-templates. So how can I put html code into an attribute?

    Read the article

< Previous Page | 583 584 585 586 587 588 589 590 591 592 593 594  | Next Page >