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Search found 50247 results on 2010 pages for 'base class'.

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  • Excluding some classes from the cobertura report doesn't work

    - by user357480
    I tried to exclude some classes from cobertura as specified in this site <cobertura-instrument todir="${voldemort.instrumented.dir}" datafile="${cobertura.instrument.file}"> <classpath refid="tools-classpath" /> <ignore regex=".*\.xsd" /> <fileset dir="${voldemort.dist.dir}/classes"> <include name="**/*.class" /> <exclude name="**/client/protocol/pb/*.class"/> <exclude name="**/server/http/*.class"/> </fileset> </cobertura-instrument> but that doesn't work help me out, pleaseeeeeeeeeeee

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  • How to specify a different column for a @Inheritance JPA annotation

    - by Cue
    @Entity @Inheritance(strategy = InheritanceType.JOINED) public class Foo @Entity @Inheritance(strategy = InheritanceType.JOINED) public class BarFoo extends Foo mysql> desc foo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ mysql> desc barfoo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | | foo_id | int | | bar_id | int | +---------------+-------------+ mysql> desc bar; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ Is it possible to specify column barfo.foo_id as the joined column? Are you allowed to specify barfoo.id as BarFoo's @Id since you are overriding the getter/seeter of class Foo? I understand the schematics behind this relationship (or at least I think I do) and I'm ok with them. The reason I want an explicit id field for BarFoo is exactly because I want to avoid using a joined key (foo _id, bar _id) when querying for BarFoo(s) or when used in a "stronger" constraint. (as Ruben put it)

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  • Should old/legacy/unused code be deleted from source control repository?

    - by Checkers
    I've encountered this in multiple projects. As the code base evolves, some libraries, applications, and components get abandoned and/or deprecated. Most people prefer to keep them in. The usual argument is that the code does not really take any space, it can be left alone until needed again. So a repository slowly turns into a cesspool of legacy code, where it's hard to find anything. Some people delete old code, since it creates clutter, raises more questions for new people, and you can restore any old snapshot of the code base anyway. However you can't always find the old code if you don't know where to look, as none of the (common) VCS I know offer search over the entire repository including all historical revisions, and the only way to search the old files is to check out the revision where the deleted file exists. What would be a good approach to repository management?

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  • Is it good practice to put private API in the .m files and public API in .h files in Cocoa?

    - by Paperflyer
    Many of my classes in my current project have several properties and methods that are only ever called from within the class itself. Also, they might mess with the working of the class depending on the current state of the class. Currently, all these interfaces are defined in the main interface declaration in the .h files. Is it considered good practice to put the “private” methods and properties at the top of the .m files? This won't ever affect anything since I am very likely the only person ever to look at this source code, but of course it would be interesting to know for future projects.

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  • Overriding fetch in multiple spine models

    - by Adam Charnock
    I need to override Spine's @fetch() method in all of my Spine models. Currently I have code duplication as follows: TastypieEndpointMixin = fromJSON: (data) -> return unless data return Spine.Model.fromJSON(data.objects) class App.models.Position extends Spine.Model @configure 'Position', 'code', 'name' @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/position/?format=json' validate: -> 'code is required' unless @code @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer class App.models.Player extends Spine.Model @configure 'Player', 'first_name', 'last_name', ... @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/player/?format=json' @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer My question is: How can I create some form of parent class which contains @fetch()? I know this should be a simple problem to solve. I have tried many options (including extending Spine.Model and Spine.Model.Ajax), but nothing works and I cannot seem to get my head around it.

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  • how to open many files simultaneously for reading in c

    - by monkeyking
    I'm trying to port some of my c++ code into c. I have the following construct class reader{ private: FILE *fp; alot_of_data data;//updated by read_until() method public: reader(const char*filename) read_until(some conditional dependent on the contents of the file, and the arg supplied) } Im then instantiating hundreds of these object and iterate over them using several 'read_until()' for each file until allfiles is at eof. I'm failing to see any clever way to do this in c, the only solution I can come up with is making an array of FILE pointers, and do the same with all the private member data from my class. But this seems very messy, can I implement the functionality of my class as a function pointer, or anything better, I think I'm missing a fundamental design pattern? The files are way to big to have all in memory, so reading everything from every file is not feasible Thanks

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  • How to implement a TypeConverter for a type and property I don't own?

    - by CannibalSmith
    This is annoying: <GeometryDrawing> <GeometryDrawing.Pen> <Pen Brush="Black"/> </GeometryDrawing.Pen> </GeometryDrawing> I want this: <GeometryDrawing Pen="Black"/> So I write a TypeConverter: public class PenConverter : TypeConverter { static readonly BrushConverter brushConverter = new BrushConverter(); public override bool CanConvertFrom(ITypeDescriptorContext context, Type sourceType) { if (sourceType == typeof(string)) return true; return base.CanConvertFrom(context, sourceType); } public override object ConvertFrom(ITypeDescriptorContext context, CultureInfo culture, object value) { var s = value as string; if (a != null) { var brush = brushConverter.ConvertFromInvariantString(s) as Brush; return new Pen(brush, 1); } return base.ConvertFrom(context, culture, value); } } Now, how do I link it up with the Pen type? I can't just add a TypeConverterAttribute to it as I don't own it (nor do I own GeometryDrawing.Pen property).

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  • Java reflection for generics

    - by Vijay Bhore
    I am using Java Reflection to expose methods in custom eclipse tool. I am writing method getReturnType which accepts java.lang.reflect.Method as input and returns object of Class private static Class<?> getReturnType(Method method) { Type type = ((ParameterizedType)method.getGenericReturnType()).getRawType(); return getClass(type); } This code compiles well but at runtime i get the below exception while casting Type to ParameterizedType. java.lang.ClassCastException: java.lang.Class cannot be cast to java.lang.reflect.ParameterizedType Please suggest. Thanks!

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  • jQuery selector question

    - by Jakey
    I have a span and an anchor inside a table cell. I have the anchor set up to show a tooltip. I would like the text inside the span to be used for the tooltip. How can I select this text in jQuery? <td class="row-head" colspan="5"><span class="tip-text">Complete Coverage</span><a href="#" class="help"></a></td> JQuery code - the current selector always finds the first instance only for all tips. $(document).ready(function() { $('.help').qtip({ style: { name: 'cream', tip: true }, content: { text: $(this).find('span.tip-text').html() } }); }); Thanks

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  • Where is BuildConfig.DEBUG?

    - by Ollie C
    My project doesn't seem to be aware of this new constant that's apparently auto-generated in Android Tools r17 builds: "Added a feature that allows you to run some code only in debug mode. Builds now generate a class called BuildConfig containing a DEBUG constant that is automatically set according to your build type. You can check the (BuildConfig.DEBUG) constant in your code to run debug-only functions such as outputting debug logs." I've confirmed that this class is not being auto-generated anywhere in my project by the new tools. I deleted all project outputs (including all gen folders) and rebuilt, and only R.java classes are being generated. Why are the tools not generating the BuildConfig class? It may be relevant that I'm using IntelliJ.

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  • Trouble using South with Django and Heroku

    - by Dan
    I had an existing Django project that I've just added South to. I ran syncdb locally. I ran manage.py schemamigration app_name locally I ran manage.py migrate app_name --fake locally I commit and pushed to heroku master I ran syncdb on heroku I ran manage.py schemamigration app_name on heroku I ran manage.py migrate app_name on heroku I then receive this: $ heroku run python notecard/manage.py migrate notecards Running python notecard/manage.py migrate notecards attached to terminal... up, run.1 Running migrations for notecards: - Migrating forwards to 0005_initial. > notecards:0003_initial Traceback (most recent call last): File "notecard/manage.py", line 14, in <module> execute_manager(settings) File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 220, in execute output = self.handle(*args, **options) File "/app/lib/python2.7/site-packages/south/management/commands/migrate.py", line 105, in handle ignore_ghosts = ignore_ghosts, File "/app/lib/python2.7/site-packages/south/migration/__init__.py", line 191, in migrate_app success = migrator.migrate_many(target, workplan, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 221, in migrate_many result = migrator.__class__.migrate_many(migrator, target, migrations, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 292, in migrate_many result = self.migrate(migration, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 125, in migrate result = self.run(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 99, in run return self.run_migration(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 81, in run_migration migration_function() File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 57, in <lambda> return (lambda: direction(orm)) File "/app/notecard/notecards/migrations/0003_initial.py", line 15, in forwards ('user', self.gf('django.db.models.fields.related.ForeignKey')(to=orm['auth.User'])), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 226, in create_table ', '.join([col for col in columns if col]), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 150, in execute cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) django.db.utils.DatabaseError: relation "notecards_semester" already exists I have 3 models. Section, Semester, and Notecards. I've added one field to the Notecards model and I cannot get it added on Heroku. Thank you.

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  • what is the best way to have a Generic Comparer

    - by oo
    I have a lot of comparer classes where the class being compared is simply checking the name property of the object and doing a string compare. For example: public class ExerciseSorter : IComparer<Exercise> { public int Compare(Exercise x, Exercise y) { return String.Compare(x.Name, y.Name); } } public class CarSorter : IComparer<Car> { public int Compare(Car x, Car y) { return String.Compare(x.Name, y.Name); } } what is the best way to have this code generic so i dont need to write redundant code over and over again.

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  • ASP.NET Thread Safety in aspx.cs code behind file

    - by Tim Michalski
    I am thinking of adding a DataContext as a member variable to my aspx.cs code-behind class for executing LinqToSql queries. Is this thread safe? I am not sure if a new instance of this code-behind class is created for each HTTP request, or if the instance is shared amongst all request threads? My fear is that I will get 10 simultaneous concurrent http requests that will be using the same database session. public partial class MyPage : System.Web.UI.Page { private DataContext myDB = new DataContext(); protected void MyAction_Click(object sender, EventArgs e) { myDB.DoWork(); } }

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  • Is it possible to group validation?

    - by lambdabutz
    I am using a lot of my own validation methods to compare the data from one association to the other. I've noticed that I'm constantly checking that my associations aren't nil before trying to call anything on them, but I am also validating their presence, and so I feel that my nil checks are redundant. Here's an example: class House < ActiveRecord::Base has_one :enterance, :class => Door has_one :exit, :class => Door validates_presence_of :enterance, :exit validate :not_a_fire_hazard def not_a_fire_hazard if enterance && exit && enterance.location != exit.location errors.add_to_base('If there is a fire you will most likely die') return false end end end I feel like I am repeating myself by checking the existence of enterance and exit within my own validation. Is there a more "The Rails Way" to do this?

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  • Importing Classes Within a Module

    - by CodeJoust
    Currently, I have a parser with multiple classes that work together. For Instance: TreeParser creates multiple Product and Reactant modules which in turn create multiple Element classes. The TreeParser is called by a render method within the same module, which is called from the importer. Currently, using the class name in the imported module file works only if the file calling the module contains from module_name import *, so the classes are imported into the main namespace. Finally, if the package has dependencies (such as re and another another module within the same folder), where is the best place to require those modules? Within the __init__.py file or within the module itself? I don't really want to add the module name in front of every call to the class, in case I do call import *, however, is it possible to use a variable name of the current module to call the class, or use a workaround in the __init__.py file? I'm probably used to the ruby require '' method instead of python's module system.

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  • How do I prevent JDialog from showing in gnome-panel(Linux)?

    - by aeter
    I have a class: public class ANote extends JDialog{...} In GNOME(Linux) it shows an entry in the gnome-panel. I want it to show nothing (the same way it does in the taskbar in Windows), because there may be present several instances of the class simultaneously, and this overcrowds the gnome-panel. How do I prevent it from showing an instance in the gnome-panel? EDIT: So far I have tried playing with the modality, which hides it from the gnome-panel, but blocks the main frame of the application behind the ANote instances.

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  • How do you set up your JScript (NOT JScript.NET) development environment?

    - by jJack
    In my environment, if I create a class in JScript syntax: class test{ } and then save it to a file named "test.js" and run it with wscript, I get a Microsoft JScript "Syntax error" at line 1. However, if I simply, say, write a function: function getInput() { var wshell = WScript.CreateObject("WScript.Shell"); wshell.Popup ("Do you want to continue?"); return userInput } getInput() and run it the same way, it works. Hopefully, there is something fundamentally wrong with my class definition. If that is the case, I am excited to find out.

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  • Rails Named Scope and overlapping conditions

    - by Tumtu
    Hi everyone, have a question about rails SQL generation: class Organization < ActiveRecord::Base has_many :people named_scope :active, :conditions => { :active => 'Yes' } end class Person < ActiveRecord::Base belongs_to :organization end Rails SQL for all active people in the first organiztion Organization.first.people.active.all [4;36;1mOrganization Load (0.0ms)[0m [0;1mSELECT TOP 1 * FROM [organizations] [0m [4;35;1mPerson Load (0.0ms)[0m [0mSELECT * FROM [people] WHERE ((([people].[active] = 'Yes') AND ([people].organization_id = 1)) AND ([people].organization_id = 1)) [0m Why Rails generates "[people].organization_id = 1" condition twice ? Does someone know how to make it DRY ? e.g. SELECT * FROM [people] WHERE (([people].[active] = 'Yes') AND ([people].organization_id = 1))

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  • Eclipse+Subversive- Multiple src paths in a single project each from a separate parts of a single re

    - by guinaut
    In a nutshell, I would like to have a single eclipse project with multiple src directories each managed by subversive (or subclipse). If the code base were small, I would use several projects. However, the code base is not small (50+ src paths). Does anyone know how to do this with the Subversion plugins for eclipse? All of the src paths derive from modules that in turn have a common point node in the repository. However, the modules are versioned, so I can’t checkout all of them. It looks as though Subclipse and Subversive do not support multiple src paths. Can anyone confirm this? Solutions?

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  • IntelliJ: Including jars in a jar artifact

    - by skiaddict1
    Developing on the Mac with IntelliJ 9.0.2. I have a program which depends on two library jars. I have figured out how to get IntelliJ to make me a jar of my source (with the Artifact tab), and even to include the two jars in it. However, if I get a listing of the jar file it produces, it looks like this: com/acme/MyClass1.class com/acme/MyClass2.class ... mylib1.jar myLib2.jar And, no surprises, if I double-click the jar file, it gets a NoClassDefFoundError the first time it tries to access a class in one or other library jar. How do I get IntelliJ to include the two library jars such that the classes are visible?

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  • how to use @ in python.. and the @property and the @classmethods

    - by zjm1126
    this is my code: def a(): print 'sss' @a() def b(): print 'aaa' b() and the Traceback is: sss Traceback (most recent call last): File "D:\zjm_code\a.py", line 8, in <module> @a() TypeError: 'NoneType' object is not callable so how to use the '@' thanks updated class a: @property def b(x): print 'sss' aa=a() print aa.b it print : sss None how to use @property thanks updated2 and the classmethods: class a: @classmethods def b(x): print 'sss' aa=a() print aa.b the Traceback is : Traceback (most recent call last): File "D:\zjm_code\a.py", line 5, in <module> class a: File "D:\zjm_code\a.py", line 6, in a @classmethods NameError: name 'classmethods' is not defined

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  • Why are static imports of static methods with same names legal?

    - by user1055638
    Lets say we have these packages and classes: package p1; public class A1 { public static void a() {} } package p2; public class A1 { public static void a() {} } package p3; import static p1.A1.a; import static p2.A1.a; public class A1 { public static void test() { } } I am wondering, why the static import of methods is legal (won't result in compile time error) in package p3? We won't be able to use them further in the test() method as such usage will result in the compile time error. Why it is not the same as with a normal import of classes. Lets say we would like to import classes A1 from packages p1 and p2 into p3: package p3; import p1.A1; import p2.A1; such import is illegal and will result in the compile time error.

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  • Operator Overloading with C# Extension Methods

    - by Blinky
    I'm attempting to use extension methods to add an operater overload to the C# StringBuilder class. Specifically, given StringBuilder sb, I'd like sb += "text" to become equivalent to sb.Append("text"); Here's the syntax for creating an extension method for StringBuilder: public static class sbExtensions { public static StringBuilder blah(this StringBuilder sb) { return sb; } } It successfully adds the "blah" extension method to the StringBuilder. Unfortunately, operator overloading does not seem to work: public static class sbExtensions { public static StringBuilder operator +(this StringBuilder sb, string s) { return sb.Append(s); } } Among other issues, the keyword 'this' is not allowed in this context. Are adding operator overloads via extension methods possible? If so, what's the proper way to go about it?

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  • Is this crufty?

    - by bobobobo
    I'm writing code like: class Game { int getMouseX() { return inputManager.getMouseX() ; } } ; I remember seeing code like this and hating it. One function passes off to another? What is this "pattern" (or, possibly, anti-pattern) called? I don't like it! On the other hand, it saves exposing the InputManager to the user of the class... would that be a better choice? Or should Game simply not contain InputManager? Edit What about using multiple inheritance instead? class Game : public InputManager, public Window { // by virtue of inheriting InputManager and Window, // Game now has "acquired" the capabilities of // InputManager's public functions, without requiring delegate. } ; Have I not found a reasonably good use for multiple inheritance??

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  • How to tell a method has a varargs argument using reflection?

    - by Anthony Kong
    Here is a sample code package org.example; import java.lang.reflect.Method; class TestRef { public void testA(String ... a) { for (String i : a) { System.out.println(i); } } public static void main(String[] args){ Class testRefClass = TestRef.class; for (Method m: testRefClass.getMethods()) { if (m.getName() == "testA") { System.out.println(m); } } } } The output is public void org.example.TestRef.testA(java.lang.String[]) So the signature of the method is reported to take a array of String. Is there any mean in the reflection library I can tell that the method is originally declared to take a varargs?

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