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  • how to show a pop-up message on submit form

    - by user1400
    hello i use of php and jquery in my application i want when users submit success a form in page1 , forward form page1 to page2 and show a pop-up message "success" and when they do not submit success , dont forward and just show pop-up message "error" how i can implement this process? thanks?

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  • General Question about MD5

    - by chicane
    So im just playing around with PHP and the MD5 functionality, sorry if this sounds really silly, but I cant seem to understand, how is it possible to represent an unlimited number of characters of input into a 32 bit character output? Is my logic sound here? Or is there a limit to the input that a MD5 function can take? Thanks...

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  • Color Code .inc in Dreamweaver CS4 Mac

    - by Nic Hubbard
    I have done this in all my previous versions, but I can't get it working in CS4. I have updated the MMDocumentTypes.xml file to add inc to the php section. Restarting Dreamweaver does not help. I even updated the Extensions.txt file, and that still does not work. Has anyone had this issue?

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  • Connecting to remote mysql database with API

    - by Ajay
    I am designing a desktop application in C#, which needs to be connected to my online mysql database. I tried to give access in control panel a "%" which means from any IP, but it is not working. May be the hosting provider (bigrock) not allowing that. Alternatively, I am trying to write some code in online on PHP which will get the "sql" as parameter and returns the output as JSON format using json_encode. Is there any alternate methods which is better approach.

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  • Profiler for Zend Server CE

    - by Tim Lytle
    I'm looking for a PHP profiler that works with Zend Server (CE). From what I can tell, XDebug is a pain to setup with Zend Server. While Zend Debugger is free (as I understand it), the Profiler is only on Zend Studio. Any other options?

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  • zend framework version trouble

    - by sasori
    Hi, am 100% sure I downloaded and extracted version 1.8 of ZF, but then when I go to console and typed "zf show version" it says am using 1.9.6, yes I do have 1.9.6 but it is "Compressed" and untouched, how could this be possible ?, I double checked my system variables, there's no evidence of ZF there. I also checked my php.ini file, it's pointed to the location of the extracted 1.8 ZF.. please help. this is my first attempt in using ZF

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  • What does Apache need to support both mysqli and PDO?

    - by Nathan Long
    I'm considering changing some PHP code to use PDO for database access instead of mysqli (because the PDO syntax makes more sense to me and is database-agnostic). To do that, I'd need both methods to work while I'm making the changeover. My problem is this: so far, either one or the other method will crash Apache. Right now I'm using XAMPP in Windows XP, and PHP Version 5.2.8. Mysqli works fine, and so does this: $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database'; $sql = "SELECT * FROM `employee`"; But this line makes Apache crash: $dbc->query($sql); I don't want to redo my entire Apache or XAMPP installation, but I'd like for PDO to work. So I tried updating libmysql.dll from here, as oddvibes recommended here. That made my simple PDO query work, but then mysqli queries crashed Apache. (I also tried the suggestion after that one, to update php_pdo_mysql.dll and php_pdo.dll, to no effect.) Test Case I created this test script to compare PDO vs mysqli. With the old copy of libmysql.dll, it crashes if $use_pdo is true and doesn't if it's false. With the new copy of libmysql.dll, it's the opposite. if ($use_pdo){ $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database<br />'; $sql = "SELECT * FROM `employee`"; $dbc->query($sql); foreach ($dbc->query($sql) as $row){ echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } else { $dbc = @mysqli_connect($hostname, $username, $password, $dbname) OR die('Could not connect to MySQL: ' . mysqli_connect_error()); $sql = "SELECT * FROM `employee`"; $result = @mysqli_query($dbc, $sql) or die(mysqli_error($dbc)); while ($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } What does Apache need in order to support both methods of database query?

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  • opensourcing a website code

    - by pygabriel
    Hi! I'm writing a little website (webapp) in php+codeigniter, I'd really like to make it open source (to attract collaborators and to have a free VCS hosting). Is that a good practice? This mine security? Which are the best tools to change important data before uploading? (like config files with db names and passwords used for testing etc..)

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  • Fastest Linux IDE with Find&Replace

    - by Nik
    I'm looking for a fast IDE for Linux that has Find&Replace. I'm currently using Geany and I've tried NetBeans, and Aptana doesn't have a PHP plugin for 2.0. I prefer one that has a sense of projects. Does anyone have any suggestions?

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  • how to update two input box in jquery

    - by Mac Taylor
    hey guys i create two input text fields , one for title and another for permanent link i need to update the second filed automatically when user is typing the tilte how can i do such a thing in jquery /php somehow im looking for a way to simulate wordpress creation of permanent link in post section

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  • Web based file manager

    - by ToughPal
    Hi, I have been using extplorer http://extplorer.sourceforge.net/ Are there any good alternatives which run on PHP & like extplorer. I am having issues with several folder permissions. ie files that are stored under apache & the ftpuser? Regards,

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  • What's the best way to implement news system without using wordpress ?

    - by Tristan
    Hello, I'm a little afraid of using Wordpress because of his connotation "all made", plus my website is 100% hand coded, actually, i use the phpBB but it's not what I want cause visitors have to go out of the website to go to the forum to see the news. So how/what can I do to have my own news system management (publish/review/moderate comments).... Are there tools (i mean except WYSIWYG) / PHP class I can use to implement myself ? I hope you understand what i mean. Thank you :)

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  • How does this script work for the ImageShack.us API?

    - by vette982
    I'm looking into using the ImageShack.us API for uploading images from my website. I found this tutorial for using it with the XML return http://elliottback.com/wp/using-the-imageshack-xml-api/, but I'm not sure about what to do with it. Where do I enter my API key for this script? Furthermore, he shows the use of two PHP files - should these be combined into one file? Any help with this would be appreciated (examples would be even better).

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  • javascript error: variable is not defined

    - by Hristo
    to is not defined [Break on this error] setTimeout('updateChat(from, to)', 1); I'm getting this error... I'm using Firebug to test and this comes up in the Console. The error corresponds to line 71 of chat.js and the whole function that wraps this line is: function updateChat(from, to) { $.ajax({ type: "POST", url: "process.php", data: { 'function': 'getFromDB', 'from': from, 'to': to }, dataType: "json", cache: false, success: function(data) { if (data.text != null) { for (var i = 0; i < data.text.length; i++) { $('#chat-box').append($("<p>"+ data.text[i] +"</p>")); } document.getElementById('chat-box').scrollTop = document.getElementById('chat-box').scrollHeight; } instanse = false; state = data.state; setTimeout('updateChat(from, to)', 1); // gives error }, }); } This links to process.php with function call getFromDB and the code for that is: case ('getFromDB'): // get the sender and receiver user IDs from their user names $from = mysql_real_escape_string($_POST['from']); $query = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$from' LIMIT 1"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_assoc($result); $fromID = $row['user_id']; $to = mysql_real_escape_string($_POST['to']); $query = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$to' LIMIT 1"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_assoc($result); $toID = $row['user_id']; $query = "SELECT * FROM `Messages` WHERE `from_id` = '$fromID' AND `to_id` = '$toID' LIMIT 1"; $result = mysql_query($query); while($row = mysql_fetch_assoc($result)) { $text[] = $line = $row['message']; $log['text'] = $text; } break; So I'm confused with the line that is giving the error. setTimeout('updateChat(from,to)',1); aren't the parameters to updateChat the same parameters that came into the function? Or are they being pulled in from somewhere else and I have to define to and from else where? Any ideas how to fix this error? Thanks, Hristo

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  • Timthumb 403 forbidden issue

    - by Nirmal Ram
    I am trying to use timthumb in one of my projects and it doesn't seem to be working and i searched all over and couldn't get the issue sorted. Here is the url of my site http://192[dot]185[dot]98[dot]213/~ancoradc/wp-content/themes/AncoraDC/timthumb.php?w=150&h=150&zc=1&src=http://192[dot]185[dot]98[dot]213/~ancoradc/wp-content/uploads/2013/06/fluke.jpg The file has 755 permission and cache is also 755 but i don't why this isn't working. Can anyone please advice me what could be wrong here ?

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  • Create attribute in existing XML

    - by user560411
    Hello. I have the following php code that inserts data into XML and works correctly. However, I want to add an ID number like below <CD id="xxxx"> My question is how can i add an ID into CD for this to work ? I use form to parse the id. ** the main code ** <?php $CD = array( 'TITLE' => $_POST['title'], 'BAND' => $_POST['band'], 'YEAR' => $_POST['year'], ); $doc = new DOMDocument(); $doc->load( 'insert.xml' ); $doc->formatOutput = true; $r = $doc->getElementsByTagName("CATEGORIES")->item(0); $b = $doc->createElement("CD"); $TITLE = $doc->createElement("TITLE"); $TITLE->appendChild( $doc->createTextNode( $CD["TITLE"] ) ); $b->appendChild( $TITLE ); $BAND = $doc->createElement("BAND"); $BAND->appendChild( $doc->createTextNode( $CD["BAND"] ) ); $b->appendChild( $BAND ); $YEAR = $doc->createElement("YEAR"); $YEAR->appendChild( $doc->createTextNode( $CD["YEAR"] ) ); $b->appendChild( $YEAR ); $r->appendChild( $b ); $doc->save("insert.xml"); ?> the XML file <?xml version="1.0" encoding="utf-8"?> <MY_CD> <CATEGORIES> <CD> <TITLE>NEVER MIND THE BOLLOCKS</TITLE> <BAND>SEX PISTOLS</BAND> <YEAR>1977</YEAR> </CD> <CD> <TITLE>NEVERMIND</TITLE> <BAND>NIRVANA</BAND> <YEAR>1991</YEAR> </CD> </CATEGORIES> </MY_CD>

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