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  • SQL SERVER – Puzzle – Statistics are not Updated but are Created Once

    - by pinaldave
    After having excellent response to my quiz – Why SELECT * throws an error but SELECT COUNT(*) does not?I have decided to ask another puzzling question to all of you. I am running this test on SQL Server 2008 R2. Here is the quick scenario about my setup. Create Table Insert 1000 Records Check the Statistics Now insert 10 times more 10,000 indexes Check the Statistics – it will be NOT updated Note: Auto Update Statistics and Auto Create Statistics for database is TRUE Expected Result – Statistics should be updated – SQL SERVER – When are Statistics Updated – What triggers Statistics to Update Now the question is why the statistics are not updated? The common answer is – we can update the statistics ourselves using UPDATE STATISTICS TableName WITH FULLSCAN, ALL However, the solution I am looking is where statistics should be updated automatically based on algorithm mentioned here. Now the solution is to ____________________. Vinod Kumar is not allowed to take participate over here as he is the one who has helped me to build this puzzle. I will publish the solution on next week. Please leave a comment and if your comment consist valid answer, I will publish with due credit. Here is the script to reproduce the scenario which I mentioned. -- Execution Plans Difference -- Create Sample Database CREATE DATABASE SampleDB GO USE SampleDB GO -- Create Table CREATE TABLE ExecTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO -- Insert One Thousand Records -- INSERT 1 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 1000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Display statistics of the table - none listed sp_helpstats N'ExecTable', 'ALL' GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here -- NOTE: Replace your _WA_Sys with stats from above query DBCC SHOW_STATISTICS('ExecTable', _WA_Sys_00000004_7D78A4E7); GO -------------------------------------------------------------- -- Round 2 -- Insert Ten Thousand Records -- INSERT 2 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 10000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here -- NOTE: Replace your _WA_Sys with stats from above query DBCC SHOW_STATISTICS('ExecTable', _WA_Sys_00000004_7D78A4E7); GO -- You will notice that Statistics are still updated with 1000 rows -- Clean up Database DROP TABLE ExecTable GO USE MASTER GO ALTER DATABASE SampleDB SET SINGLE_USER WITH ROLLBACK IMMEDIATE; GO DROP DATABASE SampleDB GO Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Index, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Statistics, Statistics

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  • Chalk Talk with John: Business Value of Identity and Access Management

    - by John Brunswick
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Conveying the business value of Identity and Access Management to non technologists can potentially be challenging, especially considering the breadth capability supplied by these technologies. In this episode of Chalk Talk with John, Bob at Codeaway Valley asks Jim from Middleware Fields how they are able to manage access to buildings and facilities throughout their community. Bob and his team struggle to keep up with the needs of their community members, while ensuring the community’s safety. Jim shares his creative solution to simplifying the management of access throughout their community in Middleware Fields. Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} About me: Hi, I am John Brunswick, an Oracle Enterprise Architect. As an Oracle Enterprise Architect, I focus on the alignment of technical capabilities in support of business vision and objectives, as well as the overall business value of technology.  Before coming to Oracle, I was a Practice Manager within BEA System's Business Interaction Division consulting organization, orchestrating enterprise systems in support of line of business goals. Follow me on Twitter and visit my site for Oracle Fusion Middleware related tips.

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  • My Doors - Why Standards Matter to Business

    - by Brian Dayton
    "Standards save money." "Standards accelerate projects." "Standards make better solutions."   What do these statements mean to you? You buy technology solutions like Oracle Applications but you're a business person--trying to close the quarter, get performance reviews processed, negotiate a new sourcing contract, etc.   When "standards" come up in presentations and discussions do you: -          Nod your head politely -          Tune out and check your smart phone -          Turn to your IT counterpart and say "Bob's all over this standards thing, right Bob?"   Here's why standards matter. My wife wants new external doors downstairs, ones that would get more light into the rooms. Am I OK with that? "Uhh, sure...it's a little dark in the kitchen."   -          24 hours ago - wife calls to tell me that she's going to the hardware store and may look at doors -          20 hours ago - wife pulls into driveway, informs me that two doors are in the back of her station wagon, ready for me to carry -          19 hours ago - I re-discovered the fact that it's not fun to carry a solid wood door by myself -          5 hours ago - Local handyman, who was at our house anyway, tells me that the doors we bought will likely cost 2-3x the material cost in installation time and labor...the doors are standard but our doorways aren't   We could have done more research. I could be more handy. Sure. But the fact is, my 1951 house wasn't built with me in mind. They built what worked and called it a day.   The same holds true with a lot of business applications. They were designed and architected for one-time use with one use-case in mind. Today's business climate is different. If you're going to use your processes and technology to differentiate your business you should have at least a working knowledge of: -          How standards can benefit your business -          Your IT organization's philosophy around standards -          Your vendor's track-record around standards...and watch for those who pay lip-service to standards but don't follow through   The rallying cry in most IT organizations today is "learn more about the business, drop the acronyms." I'm not advocating that you go out and learn how to code in Java. But I do believe it will help your business and your decision-making process if you meet IT ½...even ¼ of the way there.   Epilogue: The door project has been put on hold and yours truly has to return the doors to the hardware store tomorrow.

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  • Do your filesystems have un-owned files ?

    - by darrenm
    As part of our work for integrated compliance reporting in Solaris we plan to provide a check for determining if the system has "un-owned files", ie those which are owned by a uid that does not exist in our configured nameservice.  Tests such as this already exist in the Solaris CIS Benchmark (9.24 Find Un-owned Files and Directories) and other security benchmarks. The obvious method of doing this would be using find(1) with the -nouser flag.  However that requires we bring into memory the metadata for every single file and directory in every local file system we have mounted.  That is probaby not an acceptable thing to do on a production system that has a large amount of storage and it is potentially going to take a long time. Just as I went to bed last night an idea for a much faster way of listing file systems that have un-owned files came to me. I've now implemented it and I'm happy to report it works very well and peforms many orders of magnatude better than using find(1) ever will.   ZFS (since pool version 15) has per user space accounting and quotas.  We can report very quickly and without actually reading any files at all how much space any given user id is using on a ZFS filesystem.  Using that information we can implement a check to very quickly list which filesystems contain un-owned files. First a few caveats because the output data won't be exactly the same as what you get with find but it answers the same basic question.  This only works for ZFS and it will only tell you which filesystems have files owned by unknown users not the actual files.  If you really want to know what the files are (ie to give them an owner) you still have to run find(1).  However it has the huge advantage that it doesn't use find(1) so it won't be dragging the metadata for every single file and directory on the system into memory. It also has the advantage that it can check filesystems that are not mounted currently (which find(1) can't do). It ran in about 4 seconds on a system with 300 ZFS datasets from 2 pools totalling about 3.2T of allocated space, and that includes the uid lookups and output. #!/bin/sh for fs in $(zfs list -H -o name -t filesystem -r rpool) ; do unknowns="" for uid in $(zfs userspace -Hipn -o name,used $fs | cut -f1); do if [ -z "$(getent passwd $uid)" ]; then unknowns="$unknowns$uid " fi done if [ ! -z "$unknowns" ]; then mountpoint=$(zfs list -H -o mountpoint $fs) mounted=$(zfs list -H -o mounted $fs) echo "ZFS File system $fs mounted ($mounted) on $mountpoint \c" echo "has files owned by unknown user ids: $unknowns"; fi done Sample output: ZFS File system rpool/ROOT/solaris-30/var mounted (no) on /var has files owned by unknown user ids: 6435 33667 101 ZFS File system rpool/ROOT/solaris-32/var mounted (yes) on /var has files owned by unknown user ids: 6435 33667ZFS File system builds/bob mounted (yes) on /builds/bob has files owned by unknown user ids: 101 Note that the above might not actually appear exactly like that in any future Solaris product or feature, it is provided just as an example of what you can do with ZFS user space accounting to answer questions like the above.

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  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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  • Comparing strings with user-created string class

    - by meepz
    Basically, I created my own string class, mystring.h and mystring.c. What I want to do is write a function that compares two "strings" and then returns 1 first word is larger than the second, the opposite if word 2 is larger than word 1, and 0 if the two words are equal. What I have so far is this: int compareto(void * S1, void * S2){ String s1 = (String S1); String s2 = (String S2); int i, cs1 = 0, cs2 = 0; //cs1 is count of s1, cs2 is count of s2 while(s1->c[i] != '\0'){ //basically, while there is a word if(s1->c[i] < s2->c[i]) // if string 1 char is less than string 2 char cs2++; //add to string 2 count else (s1->c[i] > s2->c[i]) //vice versa cs1++; i++; } for my return I basically have if(cs1>cs2){ return 1; } else if(cs2 > cs1){ return 2; } return 0; here is mystring.h typedef struct mystring { char * c; int length; int (*sLength)(void * s); char (*charAt)(void * s, int i); int (*compareTo)(void * s1, void * s2); struct mystring * (*concat)(void * s1, void * s2); struct mystring * (*subString)(void * s, int begin, int end); void (*printS)(void * s); } string_t; typedef string_t * String; This does what I want, but only for unspecified order. What I want to do is search through my linked list for the last name. Ex. I have two entries in my linked list, smith and jones; Jones will be output as greater than smith, but alphabetically it isnt. (I'm using this to remove student entries from a generic link list I created) Any suggestions, all of my google searches involve using the library, so I've had no luck)

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  • sorting two tables (full join)

    - by Ruslan
    i'm joining tables like: select * from tableA a full join tableB b on a.id = b.id But the output should be: row without null fields row with null fields in tableB row with null fields in tableA Like: a.id a.name b.id b.name 5 Peter 5 Jones 2 Steven 2 Pareker 6 Paul null null 4 Ivan null null null null 1 Smith null null 3 Parker

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  • Find Shortest element in Array

    - by Ani
    I have a Array string[] names = { "Jim Rand", "Barry Williams", "Nicole Dyne", "Peter Levitt", "Jane Jones", "Cathy Hortings"}; Is there any way to find which is the shortest(Length wise) element in this array and then store rest of elements in a different array. Thanks, Ani

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  • Summary of the last decade of garbage collection?

    - by Ben Karel
    I've been reading through the Jones & Lin book on garbage collection, which was published in 1996. Obviously, the computing world has changed dramatically since then: multicore, out-of-order chips with large caches, and even larger main memory in desktops. The world has also more-or-less settled on the x86 and ARM microarchitectures for most consumer-facing systems. How has the field of garbage collection changed since the seminal book was published?

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  • f# types' properties in inconsistent order and of slightly differing types

    - by philbrowndotcom
    I'm trying to iterate through an array of objects and recursively print out each objects properties. Here is my object model: type firmIdentifier = { firmId: int ; firmName: string ; } type authorIdentifier = { authorId: int ; authorName: string ; firm: firmIdentifier ; } type denormalizedSuggestedTradeRecommendations = { id: int ; ticker: string ; direction: string ; author: authorIdentifier ; } Here is how I am instantiating my objects: let getMyIdeasIdeas = [| {id=1; ticker="msfqt"; direction="buy"; author={authorId=0; authorName="john Smith"; firm={firmId=12; firmName="Firm1"}};}; {id=2; ticker="goog"; direction="sell"; author={authorId=1; authorName="Bill Jones"; firm={firmId=13; firmName="ABC Financial"}};}; {id=3; ticker="DFHF"; direction="buy"; author={authorId=2; authorName="Ron James"; firm={firmId=2; firmName="DEFFirm"}};}|] And here is my algorithm to iterate, recurse and print: let rec recurseObj (sb : StringBuilder) o= let props : PropertyInfo [] = o.GetType().GetProperties() sb.Append( o.GetType().ToString()) |> ignore for x in props do let getMethod = x.GetGetMethod() let value = getMethod.Invoke(o, Array.empty) ignore <| match value with | :? float | :? int | :? string | :? bool as f -> sb.Append(x.Name + ": " + f.ToString() + "," ) |> ignore | _ -> recurseObj sb value for x in getMyIdeas do recurseObj sb x sb.Append("\r\n") |> ignore If you couldnt tell, I'm trying to create a csv file and am printing out the types for debugging purposes. The problem is, the first element comes through in the order you'd expect, but all subsequent elements come through with a slightly different (and confusing) ordering of the "child" properties like so: RpcMethods+denormalizedSuggestedTradeRecommendationsid: 1,ticker: msfqt,direction: buy,RpcMethods+authorIdentifierauthorId: 0,authorName: john Smith,RpcMethods+firmIdentifierfirmId: 12,firmName: Firm1, RpcMethods+denormalizedSuggestedTradeRecommendationsid: 2,ticker: goog,direction: sell,RpcMethods+authorIdentifierauthorName: Bill Jones,RpcMethods+firmIdentifierfirmName: ABC Financial,firmId: 13,authorId: 1, RpcMethods+denormalizedSuggestedTradeRecommendationsid: 3,ticker: DFHF,direction: buy,RpcMethods+authorIdentifierauthorName: Ron James,RpcMethods+firmIdentifierfirmName: DEFFirm,firmId: 2,authorId: 2, Any idea what is going on here?

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  • How to extract $lastexitcode from c# powershell script execution.

    - by scope-creep
    Hi, I've got a scipt executing in C# using the powershell async execution code on code project here: http://www.codeproject.com/KB/threads/AsyncPowerShell.aspx?display=PrintAll&fid=407636&df=90&mpp=25&noise=3&sort=Position&view=Quick&select=2130851#xx2130851xx I need to return the $lastexitcode and Jean-Paul describes how you can use a custom pshost class to return it. I can't find any method or property in pshost that returns the exit code. This engine I have needs to ensure that script executes correctly. Any help would be appreciated. regards Bob. Its the $lastexitcode and the $? variables I need to bring back. Hi, Finally answered. I found out about the $host variable. It implements a callback into the host, specifically a custom PSHost object, enabling you to return the $lastexitcode. Here is a link to an explanation of $host. http://mshforfun.blogspot.com/2006/08/do-you-know-there-is-host-variable.html It seems to be obscure, badly documented, as usual with powershell docs. Using point 4, calling $host.SetShouldExit(1) returns 1 to the SetShouldExit method of pshost, as described here. http://msdn.microsoft.com/en-us/library/system.management.automation.host.pshost.setshouldexit(VS.85).aspx Its really depends on defining your own exit code defintion. 0 and 1 suffixes I guess. regards Bob.

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  • Concatenate row values T-SQL

    - by Robert
    I am trying to pull together some data for a report and need to concatenate the row values of one of the tables. Here is the basic table structure: Reviews ReviewID ReviewDate Reviewers ReviewerID ReviewID UserID Users UserID FName LName This is a M:M relationship. Each Review can have many Reviewers; each User can be associated with many Reviews. Basically, all I want to see is Reviews.ReviewID, Reviews.ReviewDate, and a concatenated string of the FName's of all the associated Users for that Review (comma delimited). Instead of: ReviewID---ReviewDate---User 1----------12/1/2009----Bob 1----------12/1/2009----Joe 1----------12/1/2009----Frank 2----------12/9/2009----Sue 2----------12/9/2009----Alice Display this: ReviewID---ReviewDate----Users 1----------12/1/2009-----Bob, Joe, Frank 2----------12/9/2009-----Sue, Alice I have found this article describing some ways to do this, but most of these seem to only deal with one table, not multiple; unfortunately, my SQL-fu is not strong enough to adapt these to my circumstances. I am particularly interested in the example on that site which utilizes FOR XML PATH() as that looks the cleanest and most straight forward. SELECT p1.CategoryId, ( SELECT ProductName + ', ' FROM Northwind.dbo.Products p2 WHERE p2.CategoryId = p1.CategoryId ORDER BY ProductName FOR XML PATH('') ) AS Products FROM Northwind.dbo.Products p1 GROUP BY CategoryId; Can anyone give me a hand with this? Any help would be greatly appreciated!

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  • Spring Security HTTP Basic Authentication

    - by Raspayu
    Hi people! I am trying to do a really simple basic authentication with Spring Security. I have configured properly the namespace, and there are no Exceptions in the server. In my "servlet.xml" I have got the next for Spring Security: <security:http> <security:http-basic></security:http-basic> <security:intercept-url method="POST" pattern="/**" access="ROLE_USER" /> </security:http> <security:authentication-manager alias="authenticationManager"> <security:authentication-provider> <security:user-service> <security:user name="cucu" password="tas" authorities="ROLE_USER" /> <security:user name="bob" password="bobspassword" authorities="ROLE_USER" /> </security:user-service> </security:authentication-provider> </security:authentication-manager> It nearly all goes perfect: the methods that are not POST doesn't prompt any login form, and the POST method prompt it. The problem is, that nor "cucu", neither "bob" can login there. Can anyone see what am I doing wrong? Thanks in advance! ;-)

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  • SQL Syntax to count unique users completing a task

    - by Belliez
    I have the following code which shows me what users has completed ticket and this lists each user and the date they close a ticket. i.e. Paul Matt Matt Bob Matt Paul Matt Matt At the moment I manually count each user myself to see their totals for the day. EDIT: Changed output as columns instead of rows: What I have been trying to do is get SQL Server to do this for me i.e. the final result to look like: Paul | 2 Matt | 5 Bob | 1 My code I am currently using is and I would be greatful if someone can help me change this so I can get it outputting something similar to above? DECLARE @StartDate DateTime; DECLARE @EndDate DateTime; -- Date format: YYYY-MM-DD SET @StartDate = '2013-11-06 00:00:00' SET @EndDate = GETDATE() -- Today SELECT (select Username from Membership where UserId = Ticket.CompletedBy) as TicketStatusChangedBy FROM Ticket INNER JOIN TicketStatus ON Ticket.TicketStatusID = TicketStatus.TicketStatusID INNER JOIN Membership ON Ticket.CheckedInBy = Membership.UserId WHERE TicketStatus.TicketStatusName = 'Completed' and Ticket.ClosedDate >= @StartDate --(GETDATE() - 1) and Ticket.ClosedDate <= @EndDate --(GETDATE()-0) ORDER BY Ticket.CompletedBy ASC, Ticket.ClosedDate ASC Thank you for your help and time.

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  • Error with masterpage

    - by Raphyboy
    Hi, i'm creating a brand new masterpage with VS2010 Beta 2 and I get this warning (that causes me errors in the content pages): Validation (XHTML 1.0 Transitional): Content is not supported outside 'script' or 'asp:content' regions. The masterpage's code : <%@ Master Language="C#" AutoEventWireup="true" CodeBehind="Bob.master.cs" Inherits="TShirtFactory.Web.All.Core.lib.masterpage.Bob" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> <asp:ContentPlaceHolder ID="head" runat="server"> </asp:ContentPlaceHolder> </head> <body> <form id="form1" runat="server"> <div> <asp:ContentPlaceHolder ID="ContentPlaceHolder1" runat="server"> </asp:ContentPlaceHolder> </div> </form> </body> </html> As you can see, it's the default masterpage generated code. I get the warning when I hover the tag at top. Does anybody have an idea of what's going on ? Thank you

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  • How do I Handle Ties When Ranking Results in MySQL?

    - by Laxmidi
    Hi, How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem: SET @rank=0; SELECT student_names.students, @rank := @rank +1 AS rank, scores.grades FROM student_names LEFT JOIN scores ON student_names.students = scores.students ORDER BY scores.grades DESC So imagine the the above query produces: Students Rank Grades Al 1 90 Amy 2 90 George 3 78 Bob 4 73 Mary 5 NULL William 6 NULL Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place. The correct ranking should be: Students Rank Grades Al 1 90 Amy 1 90 George 3 78 Bob 4 73 Mary 5 NULL William 5 NULL If anyone has any advice, please let me know. Thank you! -Laxmidi

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  • script to find "deny" ACE in ACLs, and remove it

    - by Tom
    On my 100TB cluster, I need to find dirs and files that have a "deny" ACE within their ACL, then remove that ACE on each instance. I'm using the following: # find . -print0 | xargs -0 ls -led | grep deny -B4 and get this output (partial, for example only) -r--rw---- 1 chris GroupOne 4096 Mar 6 18:12 ./directoryA/fileX.txt OWNER: user:chris GROUP: group:GroupOne 0: user:chris allow file_gen_read,std_write_dac,file_write_attr 1: user:chris deny file_write,append,file_write_ext_attr,execute -- -r--rwxrwx 1 chris GroupOne 14728221 Mar 6 18:12 ./directoryA/subdirA/fileZ.txt OWNER: user:chris GROUP: group:GroupOne 0: user:chris allow file_gen_read,std_write_dac,file_write_attr 1: user:chris deny file_write,append,file_write_ext_attr,execute -- OWNER: user:bob GROUP: group:GroupTwo 0: user:bob allow dir_gen_read,dir_gen_write,dir_gen_execute,std_write_dac,delete_child,object_inherit,container_inherit 1: group:GroupTwo allow std_read_dac,std_write_dac,std_synchronize,dir_read_attr,dir_write_attr,object_inherit,container_inherit 2: group:GroupTwo deny list,add_file,add_subdir,dir_read_ext_attr,dir_write_ext_attr,traverse,delete_child,object_inherit,container_inherit -- As you can see, depending on where the "deny" ACE is, I can see/not-see the path. I could increase the -B value (I've seen up to 8 ACEs on a file) but then I would get more output to distill from... What I need to do next is extract $ACENUMBER and $PATHTOFILE so that I can execute this command: chmod -a# $ACENUMBER $PATHTOFILE Additional issue is that the find command (above) gives a relative path, whereas I need the full path. I guess that would need to be edited somehow. Any guidance on how to accomplish this?

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  • How do you jump to a particular row in a DataGridView by typing (a la Windows Explorer details view)

    - by russcollier
    I have a .NET Winforms app in C# with a DataGridView that's read-only and populated with some number of rows. I'd like to have functionality similar to Windows Explorer's (and many other applications) details view for example. I'd like the DataGridView to behave such that when it has focus if you start typing, the current row selection will jump to the row where the (string) value of cell 0 (i.e. the first column in the row) starts with the characters you typed in. For example, if I have a DataGridView with 1 column and the following rows: Bob Jane Jason John Leroy Sam If the DataGridView has focus and I hit the 'b' key on my keyboard, the selected row is now "Bob". If I quickly type in the keys 'ja', the selected row is Jane. If I quickly type in the letters 'jas', the selected row is Jane. If I hit the 'z' key, nothing is selected (since nothing starts with Z). Likewise if Jane is currently selected and I keep typing the letter 'j', the selection will cycle through to Jason, then John, then back to Jane, each time I hit the 'j' key. I've been doing some Googling (and "stackoverflowing" :-)) for awhile and cannot find any examples of this type of functionality. I have a rough idea in my head to do this via some sort of short lived timer thread, collecting the keystrokes on KeyPress events for the DataGridView, and selecting rows based on those collected keystrokes matching a Cells[0].Value.StartsWith() type of condition. But it seems like there has to be an easier way that I'm just not seeing. Any ideas would be much appreciated. Thanks!

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  • SQL Server, how to join a table in a "rotated" format (returning columns instead of rows)?

    - by Joshua Carmody
    Sorry for the lame title, my descriptive skills are poor today. In a nutshell, I have a query similar to the following: SELECT P.LAST_NAME, P.FIRST_NAME, D.DEMO_GROUP FROM PERSON P JOIN PERSON_DEMOGRAPHIC PD ON PD.PERSON_ID = P.PERSON_ID JOIN DEMOGRAPHIC D ON D.DEMOGRAPHIC_ID = PD.DEMOGRAPHIC_ID This returns output like this: LAST_NAME FIRST_NAME DEMO_GROUP --------------------------------------------- Johnson Bob Male Smith Jane Female Smith Jane Teacher Beeblebrox Zaphod Male Beeblebrox Zaphod Alien Beeblebrox Zaphid Politician I would prefer the output be similar to the following: LAST_NAME FIRST_NAME Male Female Teacher Alien Politician --------------------------------------------------------------------------------------------------------- Johnson Bob 1 0 0 0 0 Smith Jane 0 1 1 0 0 Beeblebrox Zaphod 1 0 0 1 1 The number of rows in the DEMOGRAPHIC table varies, so I can't say with certainty how many columns I need. The query needs to be flexible. Yes, it would be trivial to do this in code. But this query is one piece of a complicated set of stored procedures, views, and reporting services, many of which are outside my sphere of influence. I need to produce this output inside the database to avoid breaking the system. Any ideas? This is MS SQL Server 2005, by the way. Thanks.

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  • How to build a GridView like DataBound Templated Custom ASP.NET Server Control

    - by Deyan
    I am trying to develop a very simple templated custom server control that resembles GridView. Basically, I want the control to be added in the .aspx page like this: <cc:SimpleGrid ID="SimpleGrid1" runat="server"> <TemplatedColumn>ID: <%# Eval("ID") %></ TemplatedColumn> <TemplatedColumn>Name: <%# Eval("Name") %></ TemplatedColumn> <TemplatedColumn>Age: <%# Eval("Age") %></ TemplatedColumn> </cc:SimpleGrid> and when providing the following datasource: DataTable table = new DataTable(); table.Columns.Add("ID", typeof(int)); table.Columns.Add("Name", typeof(string)); table.Columns.Add("Age", typeof(int)); table.Rows.Add(1, "Bob", 35); table.Rows.Add(2, "Sam", 44); table.Rows.Add(3, "Ann", 26); SimpleGrid1.DataSource = table; SimpleGrid1.DataBind(); the result should be a HTML table like this one. ------------------------------- | ID: 1 | Name: Bob | Age: 35 | ------------------------------- | ID: 2 | Name: Sam | Age: 44 | ------------------------------- | ID: 3 | Name: Ann | Age: 26 | ------------------------------- The main problem is that I cannot define the TemplatedColumn. When I tried to do it like this ... private ITemplate _TemplatedColumn; [PersistenceMode(PersistenceMode.InnerProperty)] [TemplateContainer(typeof(TemplatedColumnItem))] [TemplateInstance(TemplateInstance.Multiple)] public ITemplate TemplatedColumn { get { return _TemplatedColumn; } set { _TemplatedColumn = value; } } .. and subsequently instantiate the template in the CreateChildControls I got the following result which is not what I want: ----------- | Age: 35 | ----------- | Age: 44 | ----------- | Age: 26 | ----------- I know that what I want to achieve is pointless and that I can use DataGrid to achieve it, but I am giving this very simple example because if I know how to do this I would be able to develop the control that I need. Thank you.

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  • What algorithms are suitable for this simple machine learning problem?

    - by user213060
    I have a what I think is a simple machine learning question. Here is the basic problem: I am repeatedly given a new object and a list of descriptions about the object. For example: new_object: 'bob' new_object_descriptions: ['tall','old','funny']. I then have to use some kind of machine learning to find previously handled objects that had similar descriptions, for example, past_similar_objects: ['frank','steve','joe']. Next, I have an algorithm that can directly measure whether these objects are indeed similar to bob, for example, correct_objects: ['steve','joe']. The classifier is then given this feedback training of successful matches. Then this loop repeats with a new object. a Here's the pseudo-code: Classifier=new_classifier() while True: new_object,new_object_descriptions = get_new_object_and_descriptions() past_similar_objects = Classifier.classify(new_object,new_object_descriptions) correct_objects = calc_successful_matches(new_object,past_similar_objects) Classifier.train_successful_matches(object,correct_objects) But, there are some stipulations that may limit what classifier can be used: There will be millions of objects put into this classifier so classification and training needs to scale well to millions of object types and still be fast. I believe this disqualifies something like a spam classifier that is optimal for just two types: spam or not spam. (Update: I could probably narrow this to thousands of objects instead of millions, if that is a problem.) Again, I prefer speed when millions of objects are being classified, over accuracy. What are decent, fast machine learning algorithms for this purpose?

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  • Comparable and Comparator contract with regards to null

    - by polygenelubricants
    Comparable contract specifies that e.compareTo(null) must throw NullPointerException. From the API: Note that null is not an instance of any class, and e.compareTo(null) should throw a NullPointerException even though e.equals(null) returns false. On the other hand, Comparator API mentions nothing about what needs to happen when comparing null. Consider the following attempt of a generic method that takes a Comparable, and return a Comparator for it that puts null as the minimum element. static <T extends Comparable<? super T>> Comparator<T> nullComparableComparator() { return new Comparator<T>() { @Override public int compare(T el1, T el2) { return el1 == null ? -1 : el2 == null ? +1 : el1.compareTo(el2); } }; } This allows us to do the following: List<Integer> numbers = new ArrayList<Integer>( Arrays.asList(3, 2, 1, null, null, 0) ); Comparator<Integer> numbersComp = nullComparableComparator(); Collections.sort(numbers, numbersComp); System.out.println(numbers); // "[null, null, 0, 1, 2, 3]" List<String> names = new ArrayList<String>( Arrays.asList("Bob", null, "Alice", "Carol") ); Comparator<String> namesComp = nullComparableComparator(); Collections.sort(names, namesComp); System.out.println(names); // "[null, Alice, Bob, Carol]" So the questions are: Is this an acceptable use of a Comparator, or is it violating an unwritten rule regarding comparing null and throwing NullPointerException? Is it ever a good idea to even have to sort a List containing null elements, or is that a sure sign of a design error?

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  • Spring security with GAE

    - by xybrek
    I'm trying to implement Spring security for my GAE application however I'm getting this error: No bean named 'springSecurityFilterChain' is defined I added this configuration on my application web.xml: <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> And in the servlet-context: <!-- Configure security --> <security:http auto-config="true"> <security:intercept-url pattern="/**" access="ROLE_USER" /> </security:http> <security:authentication-manager alias="authenticationManager"> <security:authentication-provider> <security:user-service> <security:user name="jimi" password="jimi" authorities="ROLE_USER, ROLE_ADMIN" /> <security:user name="bob" password="bob" authorities="ROLE_USER" /> </security:user-service> </security:authentication-provider> </security:authentication-manager> What could be causing the error?

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