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  • How to generate spectrum color palettes

    - by ddimitrov
    Is there an easy way to convert between color models in Java (RGB, HSV and Lab). Assuming RGB color model: How do I calculate black body spectrum color palette? I want to use it for a heatmap chart. How about single-wavelength spectrum? Edit: I found that the ColorSpace class can be used for conversions between RGB/CIE and many other color models.

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  • Jar Store - prevent from copying

    - by Vladimir
    We are going to create Jar Store the way like App Store works, but for Java Developers. Everyone will able to submit and sell custom .jar library which solves some little problem, but solves it very good to save other developer's work time. The only undecided question is how to prevent .jar copying or publishing bought .jar to the Net.

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  • JpaInspector cannot override inspectProperty()

    - by Gulcan
    Hi, I want to use JpaInspector class that is written for Metawidget. However when I insert this class into my Java project in Netbeans 6.8, It gives an error for inspectProperty() method of JpaInspector class, "method does not override or implement a method from supertype". Does it mean that parent class of JpaInspector, that is BaseObjectInspector, does not have such a method? Or what should I do to use JpaInspector in my project? Thanks.

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  • Best practices regarding equals: to overload or not to overload?

    - by polygenelubricants
    Consider the following snippet: import java.util.*; public class EqualsOverload { public static void main(String[] args) { class Thing { final int x; Thing(int x) { this.x = x; } public int hashCode() { return x; } public boolean equals(Thing other) { return this.x == other.x; } } List<Thing> myThings = Arrays.asList(new Thing(42)); System.out.println(myThings.contains(new Thing(42))); // prints "false" } } Note that contains returns false!!! We seems to have lost our things!! The bug, of course, is the fact that we've accidentally overloaded, instead of overridden, Object.equals(Object). If we had written class Thing as follows instead, then contains returns true as expected. class Thing { final int x; Thing(int x) { this.x = x; } public int hashCode() { return x; } @Override public boolean equals(Object o) { return (o instanceof Thing) && (this.x == ((Thing) o).x); } } Effective Java 2nd Edition, Item 36: Consistently use the Override annotation, uses essentially the same argument to recommend that @Override should be used consistently. This advice is good, of course, for if we had tried to declare @Override equals(Thing other) in the first snippet, our friendly little compiler would immediately point out our silly little mistake, since it's an overload, not an override. What the book doesn't specifically cover, however, is whether overloading equals is a good idea to begin with. Essentially, there are 3 situations: Overload only, no override -- ALMOST CERTAINLY WRONG! This is essentially the first snippet above Override only (no overload) -- one way to fix This is essentially the second snippet above Overload and override combo -- another way to fix The 3rd situation is illustrated by the following snippet: class Thing { final int x; Thing(int x) { this.x = x; } public int hashCode() { return x; } public boolean equals(Thing other) { return this.x == other.x; } @Override public boolean equals(Object o) { return (o instanceof Thing) && (this.equals((Thing) o)); } } Here, even though we now have 2 equals method, there is still one equality logic, and it's located in the overload. The @Override simply delegates to the overload. So the questions are: What are the pros and cons of "override only" vs "overload & override combo"? Is there a justification for overloading equals, or is this almost certainly a bad practice?

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  • get Phone numbers from android phone

    - by Luca
    Hi! First of all i'm sorry for my english... I've a problem getting phone numbers from contacts. That's my code import android.app.ListActivity; import android.database.Cursor; import android.os.Bundle; import android.provider.ContactsContract; import android.widget.SimpleAdapter; import android.widget.Toast; import java.util.ArrayList; import java.util.HashMap; public class TestContacts extends ListActivity { private ArrayList<HashMap<String,String>> list = new ArrayList<HashMap<String,String>>(); private SimpleAdapter numbers; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.contacts); numbers = new SimpleAdapter( this, list, R.layout.main_item_two_line_row, new String[] { "line1","line2" }, new int[] { R.id.text1, R.id.text2 } ); setListAdapter( numbers ); Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null); while (cursor.moveToNext()) { String contactId = cursor.getString(cursor.getColumnIndex( ContactsContract.Contacts._ID)); String hasPhone = cursor.getString(cursor.getColumnIndex( ContactsContract.Contacts.HAS_PHONE_NUMBER)); //check if the contact has a phone number if (Boolean.parseBoolean(hasPhone)) { Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null); while (phones.moveToNext()) { // Get the phone number!? String contactName = phones.getString( phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)); String phoneNumber = phones.getString( phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.NUMBER)); Toast.makeText(this, phoneNumber, Toast.LENGTH_LONG).show(); drawContact(contactName, phoneNumber); } phones.close(); } }cursor.close(); } private void drawContact(String name, String number){ HashMap<String,String> item = new HashMap<String,String>(); item.put( "line1",name); item.put( "line2",number); list.add( item ); numbers.notifyDataSetChanged(); } } It'seems that no contact have a phone number (i've added 2 contacts on the emulator and i've tried also on my HTC Desire). The problem is that if (Boolean.parseBoolean(hasPhone)) returns always false.. How can i get correctly phone numbers? I've tried to call drawContact(String name, String number) before the if statement without querying for the phone number, and it worked (it draws two times the name). but on the LinearLayout they are not ordered alphabetically... how can i order alphabetically (similar to the original contacts app)? thank you in advice, Luca

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  • Getting an error on a webservice call from C#

    - by ooo
    i am calling a java webservice from C#. i generate the wdsl proxy through visual studio which works fine and i see the methods. etc. I have one issue where i get this error in one of the requests: org.xml.sax.SAXException: No object was found for class type class com.ml.ets.ease.analytics.soap.Request does anyone have any idea why i might be getting this error.

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  • No Secure Random Number Generators Available in JDK

    - by rwbutler
    Hi, I am currently running JDK 6 on Windows 7 and have installed the Unlimited Strength Policy Files. I wrote a Java app some time ago which used to work but now fails, giving an error message indicating that the SHA1PRNG SecureRandom is not available. I have tried printing a list of cryptographic providers available on the platform and it would appear that there are no secure random number generators available - does anyone have any idea why this might be? Many thanks in advance for your help!

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  • Jmockit in JBoss

    - by Filip
    In a jboss service I need to mock some inner class (not EJB) with JMockit. Just for tests I've created inner class ToBeMocked and another one Mock. While deploying to jboss I get error NoClassDefFoundError in line: Mockit.setUpMock(ToBeMocked.class, new Mock()); with message: java.lang.NoClassDefFoundError: mockit/Mockit jmockit.jar is added to the classpath in jboss_service.xml. Any ideas?

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  • Authentication with wget

    - by Llistes Sugra
    I am currently accepting the parameters login and password in my servlet, but logs are storing this info when using wget (as long as it is GET method, and apache is in the middle) Instead of this I want to enhance my servlet's authentication accepting: wget --http-user=login --http-password=password http://myhost/myServlet How can I read, in my servlet, the server side, the login and the password user is sending, in java code?

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  • Send Mail through Jsp page.

    - by sourabhtaletiya
    hi friends ,i have tried alot to send mail via jsp page but i am not succeded. A error is coming javax.servlet.ServletException: 530 5.7.0 Must issue a STARTTLS command first. x1sm5029316wbx.19 <html> <head> <title>JSP JavaMail Example </title> </head> <body> <%@ page import="java.util.*" %> <%@ page import="javax.mail.*" %> <%@ page import="javax.mail.internet.*" %> <%@ page import="javax.activation.*" %> <% java.security.Security.addProvider(new com.sun.net.ssl.internal.ssl.Provider()); Properties props = System.getProperties(); props.put("mail.smtp.starttls.enable","true"); props.put("mail.smtp.starttls.required","true"); String host = "smtp.gmail.com"; String to = request.getParameter("to"); String from = request.getParameter("from"); String subject = request.getParameter("subject"); String messageText = request.getParameter("body"); boolean sessionDebug = false; props.put("mail.smtp.host", "smtp.gmail.com"); props.put("mail.transport.protocol", "smtp"); props.put("mail.smtp.port", "25"); props.put("mail.smtp.auth", "true"); props.put("mail.debug", "true"); props.put("mail.smtp.socketFactory.port","25"); props.put("mail.smtp.starttls.enable","true"); Session mailSession = Session.getDefaultInstance(props, null); mailSession.setDebug(sessionDebug); Message msg = new MimeMessage(mailSession); props.put("mail.smtp.starttls.enable","true"); msg.setFrom(new InternetAddress(from)); InternetAddress[] address = {new InternetAddress(to)}; msg.setRecipients(Message.RecipientType.TO, address); msg.setSubject(subject); msg.setSentDate(new Date()); msg.setText(messageText); props.put("mail.smtp.starttls.enable","true"); Transport tr = mailSession.getTransport("smtp"); tr.connect(host, "sourabh.web7", "june251989"); msg.saveChanges(); // don't forget this props.put("mail.smtp.starttls.enable","true"); tr.sendMessage(msg, msg.getAllRecipients()); tr.close(); // Transport.send(msg); /* out.println("Mail was sent to " + to); out.println(" from " + from); out.println(" using host " + host + ".");*/ %> </table> </body> </html>

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  • Recommend me a good JNI book

    - by Jose Figueroa
    Hello, I'm creating a software project in Java, is a remote administration tool. The thing is that I need to add some features with C++ and I read some about this process and I realized I need JNI, could you recommend me a good JNI Book or something related with ?

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  • Password Protected Excel File

    - by dhorn
    I have an excel spreadsheet that is password-protected. I need to open this spreadsheet and read the data from it. I've been attempting to use the POI API to no avail. A Java solution would be preferred but any ideas would be helpful. Edit: Yes, I have the password. Edit2: I am unable to open it with POI with the password, I am looking for an alternate solution.

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  • XMLTask 1.16: Does it work with Ant so far?

    - by noelg103
    I'm trying to use XMLTask 1.16, but, unfortunately, I got error, java.lang.UnsupportedClassVersionError: Bad version number in .class file, all the time. But if I switch back to XMLTask 1.15, it work fine. Does anyone know how to make XMLTask 1.16 work with Ant.

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  • Maven won't use public key to deploy

    - by magneticMonster
    I'm using SSH to deploy my Java artifacts to a server. I have the keys set up so that I can interactively SSH to the server without requiring a password, but when I try to run the "mvn deploy" or "mvn release:perform" commands, it hangs (at what I assume is the password prompt). My ~/.m2/settings.xml file contains the username for the server (because it is different than my local username) and references the id of the server that requires the different user.

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  • User Session Management with Spring

    - by Chris
    I am developing a flex java - spring web app and have set up the business logic using hibernate. I want to maintain sessions so that when the user logs in , i can track the logged in user to display information that is related to the username. I want to do this using spring if possible and wondered if anyone could redirect me to a tutorial or even explain the method to which this is achieved , or if it is hard to achieve. Thanks Chris

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  • JVM version manager

    - by luacassus
    Is there Ruby Version Manager (http://rvm.beginrescueend.com) equivalent for the Java world? I'm looking for tool which allow me to easily download and install a new JVMs and switch between them. For example: jvm install <version> jvm list - will list installed JVMs on my system jvm use jdk1.6 - will switch my env to jdk 1.6 version, etc.

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  • How to call custom JDialog built with Netbeans GUI editor?

    - by Raptrex
    Yesterday I asked this question: Is this possible to make as an option dialog? and I learned it could be made with JDialog. I'm using Netbeans GUI editor and made a button that will call my custom JDialog I designed in the GUI editor. The JDialog is called jDialog1. How do I call the jDialog1 with the button? private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) { // TODO add your handling code here: }

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  • Convert arbitrary size of byte[] to BigInteger[] and then safely convert back to exactly the same by

    - by PatlaDJ
    I believe conversion exactly to BigInteger[] would be optimal in my case. Anyone had done or found this written in Java and willing to share? So imagine I have arbitrary size byte[] = {0xff,0x3e,0x12,0x45,0x1d,0x11,0x2a,0x80,0x81,0x45,0x1d,0x11,0x2a,0x80,0x81} How do I convert it to array of BigInteger's and then be able to recover it back the original byte array safely? ty in advance.

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