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  • Regex doesn't work properly

    - by oneofthelions
    I am trying to implement a regular expression to allow only one or two digits after a hyphen '-' and it doesn't work properly. It allows as many digits as user types after '-' Please suggest my ExtJS Ext.apply(Ext.form.VTypes, { hyphenText: "Number and hyphen", hyphenMask: /[\d\-]/, hyphenRe: /^\d+-\d{1,2}$/, hyphen: function(v){ return Ext.form.VTypes.hyphenRe.test(v); } }); //Input Field for Issue no var <portlet:namespace/>issueNoField = new Ext.form.TextField({ fieldLabel: 'Issue No', width: 120, valueField:'IssNo', vtype: 'hyphen' }); This works only to the limit that it allows digits and -. But it also has to allow only 1 to 2 digits after - at most. Is something wrong in my regex? hyphenRe: /^\d+-\d{1,2}$/,

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  • Regular Expression not disappearing

    - by user2439019
    I have 3 phone fields and any one is required. SO i had a custom validation class to make any one of them is required. And i am calling those class as follows [RegularExpression(@"^\(?([0-9]{3})\)?. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [AtLeastOneRequired("PhoneHome", "PhoneMobile", "PhoneOffice", ErrorMessage = "Please provide either of PhoneHome or PhoneMobile or phoneOffice. ")] public string PhoneHome { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneOffice", ResourceType = typeof(ResContactItems))] public string PhoneOffice { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneMobile", ResourceType = typeof(ResContactItems))] public string PhoneMobile { get; set; } The problem is with only "PhoneHome " field , if i enter incorrect format, it will display error message based ont he regular expression given .But the regular expression message is not disappearing wwhen we enter the correct format too.It will disappear only in f the field is empty.Other two fields are showing properly. Is this due to the custom class i am calling.? Please help me to sort out this issue Thanks, Vidya

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  • Mathemagics - 3 consecutive number

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved Three Consecutive numbers When I was young and handsome (OK, OK, just young), my father used to challenge us with riddles and tricks involving Logic, Math and general knowledge. Most of the time, at least after reaching the ripe age of 10, I would see thru his tricks in no time. This one is a bit more subtle. I had to think about it for close to an hour and then when I had the ‘AHA!’ effect, I could not understand why it had taken me so long. So here it is. You select a volunteer from the audience (or a shill, but that would be cheating!) and ask him to select three consecutive numbers, all of them 1 or 2 digits. So {1, 2, 3} would be good, albeit trivial set, as would {8, 9, 10} or {97, 98, 99} but not {99, 99, 100} (why?!). Now, using a calculator – and these days almost every phone has a built in calculator – he is to perform these steps: 1.      Select a single digit 2.      Multiply it by 3 and write it down 3.      Add the 3 consecutive numbers 4.      Add the number from step 2 5.      Multiply the sum by 67 6.      Now tell me the last 2 digits of the result and also the number you wrote down in step 2 I will tell you which numbers you selected. How do I do this? I’ll give you the mechanical answer, but because I like you to have the pleasure of an ‘AHA!’ effect, I will not really explain the ‘why’. So let’s you selected 30, 31, and 32 and also that your 3 multiple was 24, so here is what you get 30 + 31 + 32 = 93 93 + 24 = 117 117 x 67 = 7839, last 2 digits are 39, so you say “the last 2 digits are 39, and the other number is 24.” Now, I divide 24 by 3 getting 8. I subtract 8 from 39 and get 31. I then subtract 1 from this getting 30, and say: “You selected 30, 31, and 32.” This is the ‘how’. I leave the ‘why’ to you! That’s all folks! PS do you really want to know why? Post a feedback below. When 11 people or more will have asked for it, I’ll add a link to the full explanation.

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  • Asterisk dialplan context and label clarifications

    - by liv2hak
    I have been learning Asterisk dial plan for the past week.I have written down a simple IVR system with two levels of menu and an exit option.I have used concepts from different tutorials on the web.Can someone confirm if the IVR below is correct? Correct in the sense that if the below is used will it work.I know the IVR does not do much yet.But I am just trying to clarify my understanding. [incoming] exten => 123,1,Answer() same => n(menuprompt),Background(main-menu) exten => 1,1,Playback(digits/1) same => n,Goto(incoming,menuprompt,123) exten => 2,1,Playback(digits/2) same => n,Goto(incoming,menuprompt,123) exten => 9,1,Hangup() [main-menu] exten => n(menuprompt),Background(main-menu) exten => 3,1,Playback(digits/3) same => n,Goto(main-menu,menuprompt,n) exten => 4,1,Playback(digits/4) same => n,Goto(main-menu,menuprompt,n) exten => 9,1,Hangup()

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  • Paste a list of dates in format of "mm/dd/yy" to iWork-Numbers

    - by David.Chu.ca
    I have trouble to paste a list of strings in the format of 'mm/dd/yy' into iWork-Numbers. For example, I have a list of strings(text in VIM): 04/01/10 04/03/10 04/13/10 I copy those strings and then paste into my iWork-Numbers worksheet. The result will be: 2004-01-10 2004-03-10 04/13/10 It looks like that Numbers (mac workseet application in iWork) tries to convert the first two digits into year, then the next two into month if less than 12 and last two digits to a day, for the first two rows. For the third(04/13/10), since the middle two digits are 13 and cannot be a month, then this row is pasted as it is (actually it is what I need). Is there any way to paste whatever as they are, without any "smart date conversion"? Do I have to change settings in Numberers or Mac OS's System preference?

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  • Checking validation of entries in a Sudoku game written in Java

    - by Mico0
    I'm building a simple Sudoku game in Java which is based on a matrix (an array[9][9]) and I need to validate my board state according to these rules: all rows have 1-9 digits all columns have 1-9 digits. each 3x3 grid has 1-9 digits. This function should be efficient as possible for example if first case is not valid I believe there's no need to check other cases and so on (correct me if I'm wrong). When I tried doing this I had a conflict. Should I do one large for loop and inside check columns and row (in two other loops) or should I do each test separately and verify every case by it's own? (Please don't suggest too advanced solutions with other class/object helpers.) This is what I thought about: Main validating function (which I want pretty clean): public boolean testBoard() { boolean isBoardValid = false; if (validRows()) { if (validColumns()) { if (validCube()) { isBoardValid = true; } } } return isBoardValid; } Different methods to do the specific test such as: private boolean validRows() { int rowsDigitsCount = 0; for (int num = 1; num <= 9; num++) { boolean foundDigit = false; for (int row = 0; (row < board.length) && (!foundDigit); row++) { for (int col = 0; col < board[row].length; col++) { if (board[row][col] == num) { rowsDigitsCount++; foundDigit = true; break; } } } } return rowsDigitsCount == 9 ? true : false; } I don't know if I should keep doing tests separately because it looks like I'm duplicating my code.

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  • spoj: runlength

    - by user285825
    For RLM problem of SPOJ: This is the problem: "Run-length encoding of a number replaces a run of digits (that is, a sequence of consecutive equivalent digits) with the number of digits followed by the digit itself. For example, 44455 would become 3425 (three fours, two fives). Note that run-length encoding does not necessarily shorten the length of the data: 11 becomes 21, and 42 becomes 1412. If a number has more than nine consecutive digits of the same type, the encoding is done greedily: each run grabs as many digits as it can, so 111111111111111 is encoded as 9161. Implement an integer arithmetic calculator that takes operands and gives results in run-length format. You should support addition, subtraction, multiplication, and division. You won't have to divide by zero or deal with negative numbers. Input/Output The input will consist of several test cases, one per line. For each test case, compute the run-length mathematics expression and output the original expression and the result, as shown in the examples. The (decimal) representation of all operands and results will fit in signed 64-bit integers." These are my testcases: input: 11 + 11 988726 - 978625 12 * 41 1124 / 1112 13 * 33 15 / 16 19222317121013161815142715181017 + 10 10 + 19222317121013161815142715181017 19222317121013161815142715181017 / 19222317121013161815142715181017 19222317121013161815142715181017 / 11 11 / 19222317121013161815142715181017 19222317121013161815142715181017 / 12 12 / 19222317121013161815142715181017 19222317121013161815142715181017 / 141621161816101118141217131817191014 141621161816101118141217131817191014 / 19222317121013161815142715181017 19222317121013161815142715181017 / 141621161816101118141217131817191013 141621161816101118141217131817191013 / 19222317121013161815142715181017 19222317121013161815142715181017 * 11 11 * 19222317121013161815142715181017 19222317121013161815142715181017 * 10 10 * 19222317121013161815142715181017 19222317121013161815142715181017 - 10 19222317121013161815142715181017 - 19222317121013161815142715181017 19222317121013161815142715181017 - 141621161816101118141217131817191014 19222317121013161815142715181017 - 141621161816101118141217131817191013 141621161816101118141217131817191013 + 141621161816101118141217131817191013 141621161816101118141217131817191013 + 141621161816101118141217131817191014 141621161816101118141217131817191014 + 141621161816101118141217131817191013 141621161816101118141217131817191014 + 10 10 + 141621161816101118141217131817191013 141621161816101118141217131817191013 + 11 11 + 141621161816101118141217131817191013 141621161816101118141217131817191013 * 12 12 * 141621161816101118141217131817191013 141621161816101118141217131817191014 - 141621161816101118141217131817191014 141621161816101118141217131817191013 - 141621161816101118141217131817191013 141621161816101118141217131817191013 - 10 141621161816101118141217131817191014 - 11 141621161816101118141217131817191014 - 141621161816101118141217131817191013 141621161816101118141217131817191014 / 141621161816101118141217131817191014 141621161816101118141217131817191014 / 141621161816101118141217131817191013 141621161816101118141217131817191013 / 141621161816101118141217131817191014 141621161816101118141217131817191013 / 141621161816101118141217131817191013 141621161816101118141217131817191014 * 11 11 * 141621161816101118141217131817191014 141621161816101118141217131817191014 / 11 11 / 141621161816101118141217131817191014 10 + 10 10 + 11 10 + 15 15 + 10 11 + 10 11 + 10 10 - 10 15 - 10 10 * 10 10 * 15 15 * 10 10 / 111213 output: 11 + 11 = 12 988726 - 978625 = 919111 12 * 41 = 42 1124 / 1112 = 1112 13 * 33 = 39 15 / 16 = 10 19222317121013161815142715181017 + 10 = 19222317121013161815142715181017 10 + 19222317121013161815142715181017 = 19222317121013161815142715181017 19222317121013161815142715181017 / 19222317121013161815142715181017 = 11 19222317121013161815142715181017 / 11 = 19222317121013161815142715181017 11 / 19222317121013161815142715181017 = 10 19222317121013161815142715181017 / 12 = 141621161816101118141217131817191013 12 / 19222317121013161815142715181017 = 10 19222317121013161815142715181017 / 141621161816101118141217131817191014 = 11 141621161816101118141217131817191014 / 19222317121013161815142715181017 = 10 19222317121013161815142715181017 / 141621161816101118141217131817191013 = 12 141621161816101118141217131817191013 / 19222317121013161815142715181017 = 10 19222317121013161815142715181017 * 11 = 19222317121013161815142715181017 11 * 19222317121013161815142715181017 = 19222317121013161815142715181017 19222317121013161815142715181017 * 10 = 10 10 * 19222317121013161815142715181017 = 10 19222317121013161815142715181017 - 10 = 19222317121013161815142715181017 19222317121013161815142715181017 - 19222317121013161815142715181017 = 10 19222317121013161815142715181017 - 141621161816101118141217131817191014 = 141621161816101118141217131817191013 19222317121013161815142715181017 - 141621161816101118141217131817191013 = 141621161816101118141217131817191014 141621161816101118141217131817191013 + 141621161816101118141217131817191013 = 19222317121013161815142715181016 141621161816101118141217131817191013 + 141621161816101118141217131817191014 = 19222317121013161815142715181017 141621161816101118141217131817191014 + 141621161816101118141217131817191013 = 19222317121013161815142715181017 141621161816101118141217131817191014 + 10 = 141621161816101118141217131817191014 10 + 141621161816101118141217131817191013 = 141621161816101118141217131817191013 141621161816101118141217131817191013 + 11 = 141621161816101118141217131817191014 11 + 141621161816101118141217131817191013 = 141621161816101118141217131817191014 141621161816101118141217131817191013 * 12 = 19222317121013161815142715181016 12 * 141621161816101118141217131817191013 = 19222317121013161815142715181016 141621161816101118141217131817191014 - 141621161816101118141217131817191014 = 10 141621161816101118141217131817191013 - 141621161816101118141217131817191013 = 10 141621161816101118141217131817191013 - 10 = 141621161816101118141217131817191013 141621161816101118141217131817191014 - 11 = 141621161816101118141217131817191013 141621161816101118141217131817191014 - 141621161816101118141217131817191013 = 11 141621161816101118141217131817191014 / 141621161816101118141217131817191014 = 11 141621161816101118141217131817191014 / 141621161816101118141217131817191013 = 11 141621161816101118141217131817191013 / 141621161816101118141217131817191014 = 10 141621161816101118141217131817191013 / 141621161816101118141217131817191013 = 11 141621161816101118141217131817191014 * 11 = 141621161816101118141217131817191014 11 * 141621161816101118141217131817191014 = 141621161816101118141217131817191014 141621161816101118141217131817191014 / 11 = 141621161816101118141217131817191014 11 / 141621161816101118141217131817191014 = 10 10 + 10 = 10 10 + 11 = 11 10 + 15 = 15 15 + 10 = 15 11 + 10 = 11 11 + 10 = 11 10 - 10 = 10 15 - 10 = 15 10 * 10 = 10 10 * 15 = 10 15 * 10 = 10 10 / 111213 = 10 I am getting consistently wrong answer. I generated the above testcases trying to make them as representative as possible (boundary conditions, etc). I am not sure how to test it further. Some guidline would be really appreciated.

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  • TeX Font Mapping

    - by reprogrammer
    I am using a package written on top of XeLaTeX. This package uses fontspec to specify fonts for different parts of your text: latin, non-latin, math mode, ... The package comes with several sample files. I was able to xelatex most of them that depend on regular ttf or otf files. However, one of them tries to set the font of digits in math mode to some font, say "NonLatin Digits". But, the font doesn't seem to be a regular font. There are two files in the same directory called "nonlatindigits.map" and "nonlatindigits.tec". TECkit uses these mapping files to generate TeX fonts. However, for some reason it fails to create the files, and xelatex issues the following error message. kpathsea: Invalid fontname `NonLatin Digits', contains ' ' ! Font \zf@basefont="NonLatin Digits" at 10.0pt not loadable: Metric (TFM) file or installed font not found. The kpathsea program complains about the whitespace, but removing the whitespace does solve the problem with loading the TFM file. Any clues what I am doing wrong?

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  • Required Working Precision for the BBP Algorithm?

    - by brainfsck
    Hello, I'm looking to compute the nth digit of Pi in a low-memory environment. As I don't have decimals available to me, this integer-only BBP algorithm in Python has been a great starting point. I only need to calculate one digit of Pi at a time. How can I determine the lowest I can set D, the "number of digits of working precision"? D=4 gives me many correct digits, but a few digits will be off by one. For example, computing digit 393 with precision of 4 gives me 0xafda, from which I extract the digit 0xa. However, the correct digit is 0xb. No matter how high I set D, it seems that testing a sufficient number of digits finds an one where the formula returns an incorrect value. I've tried upping the precision when the digit is "close" to another, e.g. 0x3fff or 0x1000, but cannot find any good definition of "close"; for instance, calculating at digit 9798 gives me 0xcde6 , which is not very close to 0xd000, but the correct digit is 0xd. Can anyone help me figure out how much working precision is needed to calculate a given digit using this algorithm? Thank you,

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  • SQL Server: What locale should be used to format numeric values into SQL Server format?

    - by Ian Boyd
    It seems that SQL Server does not accept numbers formatted using any particular locale. It also doesn't support locales that have digits other than 0-9. For example, if the current locale is bengali, then the number 123456789 would come out as "?????????". And that's just the digits, nevermind what the digit grouping would be. But the same problem happens for numbers in the Invariant locale, which formats numbers as "123,456,789", which SQL Server won't accept. Is there a culture that matches what SQL Server accepts for numeric values? Or will i have to create some custom "sql server" culture, generating rules for that culture myself from lower level formatting routines? If i was in .NET (which i'm not), i could peruse the Standard Numeric Format strings. Of the format codes available in .NET: c (Currency): $123.46 d (Decimal): 1234 e (Exponentional): 1.052033E+003 f (Fixed Point): 1234.57 g (General): 123.456 n (Number): 1,234.57 p (Percent): 100.00 % r (Round Trip): 123456789.12345678 x (Hexadecimal): FF Only 6 accept all numeric types: c (Currency): $123.46 d (Decimal): 1234 e (Exponentional): 1.052033E+003 f (Fixed Point): 1234.57 g (General): 123.456 n (Number): 1,234.57 p (Percent): 100.00 % r (Round Trip): 123456789.12345678 x (Hexadecimal): FF And of those only 2 generate string representations, in the en-US locale anyway, that would be accepted by SQL Server: c (Currency): $123.46 d (Decimal): 1234 e (Exponentional): 1.052033E+003 f (Fixed Point): 1234.57 g (General): 123.456 n (Number): 1,234.57 p (Percent): 100.00 % r (Round Trip): 123456789.12345678 x (Hexadecimal): FF Of the remaining two, fixed is dependant on the locale's digits, rather than the number being used, leaving General g format: c (Currency): $123.46 d (Decimal): 1234 e (Exponentional): 1.052033E+003 f (Fixed Point): 1234.57 g (General): 123.456 n (Number): 1,234.57 p (Percent): 100.00 % r (Round Trip): 123456789.12345678 x (Hexadecimal): FF And i can't even say for certain that the g format won't add digit groupings (e.g. 1,234). Is there a locale that formats numbers in the way SQL Server expects? Is there a .NET format code? A java format code? A Delphi format code? A VB format code? A stdio format code? latin-numeral-digits

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  • Should not a tail-recursive function also be faster?

    - by Balint Erdi
    I have the following Clojure code to calculate a number with a certain "factorable" property. (what exactly the code does is secondary). (defn factor-9 ([] (let [digits (take 9 (iterate #(inc %) 1)) nums (map (fn [x] ,(Integer. (apply str x))) (permutations digits))] (some (fn [x] (and (factor-9 x) x)) nums))) ([n] (or (= 1 (count (str n))) (and (divisible-by-length n) (factor-9 (quot n 10)))))) Now, I'm into TCO and realize that Clojure can only provide tail-recursion if explicitly told so using the recur keyword. So I've rewritten the code to do that (replacing factor-9 with recur being the only difference): (defn factor-9 ([] (let [digits (take 9 (iterate #(inc %) 1)) nums (map (fn [x] ,(Integer. (apply str x))) (permutations digits))] (some (fn [x] (and (factor-9 x) x)) nums))) ([n] (or (= 1 (count (str n))) (and (divisible-by-length n) (recur (quot n 10)))))) To my knowledge, TCO has a double benefit. The first one is that it does not use the stack as heavily as a non tail-recursive call and thus does not blow it on larger recursions. The second, I think is that consequently it's faster since it can be converted to a loop. Now, I've made a very rough benchmark and have not seen any difference between the two implementations although. Am I wrong in my second assumption or does this have something to do with running on the JVM (which does not have automatic TCO) and recur using a trick to achieve it? Thank you.

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  • Scanning, Checking, Converting, Copying values ... How to ? -- C --

    - by ZaZu
    Hi there, Its been a while now and im still trying to get a certain code to work. I asked some question about different commands etc. before, but now I hope this is the final one (combining all questions in one code). I basically want to : *Scan an input (should be character ? ) *Check if its a number *If not, return error *Convert that character into a float number *Copy the value to another variable ( I called it imp here) Here is what I came up with : #include<stdio.h> #include<stdlib.h> #include<ctype.h> main(){ int digits; float imp=0; int alpha; do{ printf("Enter input\n\n"); scanf("\n%c",&alpha); digits=isdigit(alpha); if(digits==0){ printf("error\n\n"); } imp=atof(alpha); }while(digits==0); } The problem is this code does not work at all ... It gives me that atof must be of a const char and whenever I try changing it around, it just keeps failing. I am frustrated and forced to ask here, because I believe I have tried alot and I keep failing, but I wont be relieved until I get it to work xD So I really need your help guys. Please tell me why isnt this code working, what am I doing wrong ? I am still learning C and really appreciate your help :)

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  • Solving problems with near infinite potential solutions

    - by Zonda333
    Today I read the following problem: Use the digits 2, 0, 1, 1 and the operations +, -, x, ÷, sqrt, ^ , !, (), combinations, and permutations to write equations for the counting numbers 1 through 100. All four digits must be used in each expression. Only the digits 2, 0, 1, 1 may be used, and each must be used exactly once. Decimals may be used, as in .1, .02, etc. Digits may be combined; numbers such as 20 or 101 may be used. Example: 60 = 10*(2+1)!, 54 = ¹¹C2 - 0! Though I was able to quickly find around 50 solutions quite easily in my head, I thought programming it would be a far superior solution. However, I then realized I had no clue how to go about solving a problem like this. I am not asking for complete code for me to copy and paste, but for ideas about how I would solve this problems, and others like it that have nearly infinite potential solutions. As I will be writing it in python, where I have the most experience, I would prefer if the answers were more python based, but general ideas are great too.

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  • Passwords longer than 8 letter in Red Hat 4

    - by Oz123
    I have some machines with RHEL4 Nahant Update 6. Oddly, I found that passwords longer than 8 digits are not stored. So if I had a password 1ABCDEa!, and I changed it to 1ABCDEa!1ABCDEa! I could still log in to the machine with the old password. This machines use NIS authentication, but other machines with Red Hat 5 which use the same NIS server allow login ONLY with the NEW password (16 digits long...)!

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  • What is the significance of having the correct hostname for a cloud server in the control panel of the hosting company

    - by Logo
    What could be a problem that could arise if i do not have the correct hostname as my device name for the cloud server in a control panel of my hosting company basically the device name is supposedly the hostname when i created the cloud server they ensured this was my hostname for my new cloud server. but it looks like they will not allow me to use a domain name that is all digits. currently my host name in the cloud server itself is a domain name that is all digits.

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  • ansi-c fscanf problem

    - by mongoose
    hi i read the file as follows fscanf(fp,"%f %f %f",&*(p1+i), &*(p2+i), &*(p3+i)); my file's lines consists of three floating point numbers... the problem i have is that in the file let's say i have some floating points with let's say maximum of two digits after the dot. but when i ask c to print those values using different formatting, for example %lf,%.2lf,%.4lf... it starts to play with the digits... my only concern is this, if i have let's say 1343.23 in the file, then will c use this value exactly as it is in computations or it will play with the digits after the dot. if it will play, then how is it possible to make it so that it uses floating point numbers exactly as they are? for example in last case even if i ask it to print that value using %.10lf i would expect it to print only 1343.2300000000.? thanks a lot!

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  • Can any genius out there turn this code from generating permutation to generating combination?

    - by mark
    #include <string> int main(int,char**) { std::string default_str = "12345"; int perm=1, digits=default_str.size(); for (int i=1;i<=digits;perm*=i++); for (int a=0;a<perm;a++) { std::string avail=default_str; for (int b=digits,div=perm;b>0; b--) { div/=b; int index = (a/div)%b; printf("%c", avail[index] ); avail.erase(index,1) ; } printf("\n"); } printf("permutations:%d\n",perm); while(1); }

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  • How do I check the validity of the Canadian Social Insurance Number in C#?

    - by user518307
    I've been given the assignment to write an algorithm in C# that checks the validity of a Canadian Social Insurance Number (SIN). Here are the steps to validate a SIN. Given an example Number: 123 456 782 Remove the check digit (the last digit): 123456782 Extract the even digits (2,4,6,8th digith): 12345678 Double them: 2 4 6 8 | | | | v v v v 4 8 12 16 Add the digits together: 4+8+1+2+1+6 = 22 Add the Odd placed digits: 1+3+5+7 = 16 Total : 38 Validity Algorithm If the total is a multiple of 10, the check digit should be zero. Otherwise, Subtract the Total from the next highest multiple of 10 (40 in this case) The check digit for this SIN must be equal to the difference of the number and the totals from earlier (in this case, 40-38 = 2; check digit is 2, so the number is valid) I'm lost on how to actually implement this in C#, how do I do this?

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  • Handling "Big" Integers in C#

    - by priyanka.sarkar
    How do I handle big integers in C#? I have a function that will give me the product of divisors: private static int GetDivisorProduct(int N, int product) { for (int i = 1; i < N; i++) { if (N % i == 0) { Console.WriteLine(i.ToString()); product *= i; } } return product; } The calling function is GetDivisorProduct(N, 1) If the result is bigger than 4 digits , I should obtain only the last 4 digits. ( E.g. If I give an input of 957, the output is 7493 after trimming out only the last four values. The actual result is 876467493.). Other sample inputs: If I give 10000, the output is 0. The BigInteger class has been removed from the C# library! How can I get the last four digits?

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  • Need a regular expression for an Irish phone number

    - by Eoghan O'Brien
    I need to validate an Irish phone number but I don't want to make it too user unfriendly, many people are used to writing there phone number with brackets wrapping their area code followed by 5 to 7 digits for their number, some add spaces between the area code or mobile operator. The format of Irish landline numbers is an area code of between 1 and 4 digits and a number of between 5 to 8 digits. e.g. (021) 9876543 (01)9876543 01 9876543 (0402)39385 I'm looking for a regular expression for Javascript/PHP. Thanks.

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  • I need to generate credit card surrogates (tokens) that are format preserving.

    - by jammer59
    For an eCommerce application I need to take a credit card and use the real card for passing through to a payment gateway but I need to store, and return to the transaction initiator, a surrogate that is format preserving. Specifically, this means: 1) The number of digits in the surrogate is the same as the real card number (PAN). 2) The issuer type part of the card -- the initial 1,2 or 4 digits remains the same in the surrogate as in the original PAN. 3) The final 4 digits of the surrogate remain the same (for customer service purposes.) 4) The surrogate passes the Luhn mod10 check for a syntactially valid credit card. I can readily handle requirements 1-3 but #4 has me completely stumped! The final implementation will be either t-sql or c#. Any ideas?

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  • Need help with REGEXP_REPLACE

    - by Randy
    hey regex guru's I have a data column that contains a substring similar to this: 'This is a string with ID=123 contained inside' i need to replace the ID=123 with another fixed string say ID=1 i have a working REPLACE call that swaps out the values correctly, but this only works on a known original id number. I can extend to make it work when the number of digits are known by using some substr magic, however, the id number may have an arbitrary number of digits, so i'm thinking regex. any help with the regex magix to grab the entire ID=999 substring no matter how many digits would be very helpful. thanks

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  • How do I remove specific numbers from a string?

    - by user1666900
    I have this string in PHP Hopelessly Incredible |SPG:M| 766 STEAM_0:1:20130600 " banned "A Blatantly Obvious Hacker 740 STEAM_0:1:55386073 " (minutes "0") (reason "Multi-Hack") The Format of the string is: Name1 Number(0-3 digits) Steam_0:x:xxxx offense (banned/kicked/mute etc) Name2 Number(0-3 digits) Steam_0:x:xxxx time reason My goal is to remove the values 766 and 740 because it is just garbage. Those values can have single, double, and triple digits. The next step would be to strip STEAM_0:1:20130600 and STEAM_0:1:55386073 out of the string and capture it in a new variable. The only constant is STEAM_0: the rest can change. I am still learning regex but I fear this is a bit complicated for me to do. Some guidance would be most appreciative.

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  • C++ Program performs better when piped

    - by ET1 Nerd
    I haven't done any programming in a decade. I wanted to get back into it, so I made this little pointless program as practice. The easiest way to describe what it does is with output of my --help codeblock: ./prng_bench --help ./prng_bench: usage: ./prng_bench $N $B [$T] This program will generate an N digit base(B) random number until all N digits are the same. Once a repeating N digit base(B) number is found, the following statistics are displayed: -Decimal value of all N digits. -Time & number of tries taken to randomly find. Optionally, this process is repeated T times. When running multiple repititions, averages for all N digit base(B) numbers are displayed at the end, as well as total time and total tries. My "problem" is that when the problem is "easy", say a 3 digit base 10 number, and I have it do a large number of passes the "total time" is less when piped to grep. ie: command ; command |grep took : ./prng_bench 3 10 999999 ; ./prng_bench 3 10 999999|grep took .... Pass# 999999: All 3 base(10) digits = 3 base(10). Time: 0.00005 secs. Tries: 23 It took 191.86701 secs & 99947208 tries to find 999999 repeating 3 digit base(10) numbers. An average of 0.00019 secs & 99 tries was needed to find each one. It took 159.32355 secs & 99947208 tries to find 999999 repeating 3 digit base(10) numbers. If I run the same command many times w/o grep time is always VERY close. I'm using srand(1234) for now, to test. The code between my calls to clock_gettime() for start and stop do not involve any stream manipulation, which would obviously affect time. I realize this is an exercise in futility, but I'd like to know why it behaves this way. Below is heart of the program. Here's a link to the full source on DB if anybody wants to compile and test. https://www.dropbox.com/s/6olqnnjf3unkm2m/prng_bench.cpp clock_gettime() requires -lrt. for (int pass_num=1; pass_num<=passes; pass_num++) { //Executes $passes # of times. clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &temp_time); //get time start_time = timetodouble(temp_time); //convert time to double, store as start_time for(i=1, tries=0; i!=0; tries++) { //loops until 'comparison for' fully completes. counts reps as 'tries'. <------------ for (i=0; i<Ndigits; i++) //Move forward through array. | results[i]=(rand()%base); //assign random num of base to element (digit). | /*for (i=0; i<Ndigits; i++) //---Debug Lines--------------- | std::cout<<" "<<results[i]; //---a LOT of output.---------- | std::cout << "\n"; //---Comment/decoment to disable/enable.*/ // | for (i=Ndigits-1; i>0 && results[i]==results[0]; i--); //Move through array, != element breaks & i!=0, new digits drawn. -| } //If all are equal i will be 0, nested for condition satisfied. -| clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &temp_time); //get time draw_time = (timetodouble(temp_time) - start_time); //convert time to dbl, subtract start_time, set draw_time to diff. total_time += draw_time; //add time for this pass to total. total_tries += tries; //add tries for this pass to total. /*Formated output for each pass: Pass# ---: All -- base(--) digits = -- base(10) Time: ----.---- secs. Tries: ----- (LINE) */ std::cout<<"Pass# "<<std::setw(width_pass)<<pass_num<<": All "<<Ndigits<<" base("<<base<<") digits = " <<std::setw(width_base)<<results[0]<<" base(10). Time: "<<std::setw(width_time)<<draw_time <<" secs. Tries: "<<tries<<"\n"; } if(passes==1) return 0; //No need for totals and averages of 1 pass. /* It took ----.---- secs & ------ tries to find --- repeating -- digit base(--) numbers. (LINE) An average of ---.---- secs & ---- tries was needed to find each one. (LINE)(LINE) */ std::cout<<"It took "<<total_time<<" secs & "<<total_tries<<" tries to find " <<passes<<" repeating "<<Ndigits<<" digit base("<<base<<") numbers.\n" <<"An average of "<<total_time/passes<<" secs & "<<total_tries/passes <<" tries was needed to find each one. \n\n"; return 0;

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  • simple GET validation

    - by Andrew
    I have GET[] input and would like to carry out their validation. The input data is always a number by. Schema. I want to make sure that the pass number and the appropriate amount - not to throw the sql query. at this moment I am using the procedures $cc = $_GET['cc']; if ($cc=='') $cc='9012';$find=array("..", "/", "\\"); $replace=array("", "", ""); $cc=str_replace($find, $replace, $cc); $eic = $_GET['eic']; .... ect. // where f.ex. 9012 is an real existing data (in dbase) to generate sucure sql question GET[] variable data schema $_GET[$cc] - always 4 digits $_GET[$eic] - always 4 digits $_GET[$iy] - always 4 digits $_GET[$ir] - always 1 digit Can you show me a better way to secure my GET?

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