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  • Portable Device Path on Windows

    - by Ripei
    Hey guys I actually got an Windows/Java Question. I've got an plugged in Device which I want to access via Java. Normaly u can access an e.g. USB-Stick via the Drive letter... but this Tablet is displayed by Windows as an "Portable Device"... which means, that the Path is sth. like "Computer\Archos 5S" and there is no Drive letter. I want to access a File on this Device via Java, but I am not able to figure out the correct Path to it. There is a similar Question out there, but without a productive answear. Or is there an other way to access this Device via Java? thanks in advance ripei

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  • Flash AS 3 Loader OnComplete Inside a Loop

    - by meengla
    Hi, I think I posted my question as an answer elsewhere (http://stackoverflow.com/questions/2338317/how-to-get-associated-urlrequest-from-event-complete-fired-by-urlloader/2776515#2776515) . Sorry. Here is my question again: Hi, How can I make your function work for loader object in a loop? Thanks! Meengla Here is my existing (rough) code; I always get the mylabel from the last element of the array. var _loader = new Loader(); for (j = 0; j < 5; j++) { //mylabel variable is correct setup in the loop _loader.contentLoaderInfo.addEventListener(Event.COMPLETE, function(e:Event):void { doneLoad(e, mylabel); }); _loader.load(new URLRequest(encodeURI(recAC[j].url))); }//for loop

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  • Nested loop with dependent bounds trip count

    - by aaa
    hello. just out of curiosity I tried to do the following, which turned out to be not so obvious to me; Suppose I have nested loops with runtime bounds, for example: t = 0 // trip count for l in 0:N for k in 0:N for j in max(l,k):N for i in k:j+1 t += 1 t is loop trip count is there a general algorithm/way (better than N^4 obviously) to calculate loop trip count? I am working on the assumption that the iteration bounds depend only on constant or previous loop variables.

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  • Flash AS3 for loop query

    - by jimbo
    I was hoping for a way that I could save on code by creating a loop for a few lines of code. Let me explain a little, with-out loop: icon1.button.iconLoad.load(new URLRequest("icons/icon1.jpg")); icon2.button.iconLoad.load(new URLRequest("icons/icon2.jpg")); icon3.button.iconLoad.load(new URLRequest("icons/icon3.jpg")); icon4.button.iconLoad.load(new URLRequest("icons/icon4.jpg")); etc... But with a loop could I have something like: for (var i:uint = 0; i < 4; i++) { icon+i+.button.iconLoad.load(new URLRequest("icons/icon"+i+"jpg")); } Any ideas welcome...

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  • for loop vs while loop

    - by Atul
    We can use for loop and while loop for same purpose. in what means they effect our code if I use for instead of while? same question arises between if-else and switch-case? how to decide what to use? for example which one you would prefer? This code: int main() { int n; cin>>n; for(int i=0;i<n;i++) { do_something(); } return 0; } Or this code: int main() { int n,i=0; cin>>n; while(i<n) { do_something(); i++; } return 0; } if using for or while loop does not effect the code by any means then may I know What was the need to make 2 solution for same problem?

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  • Javascript Replace Child/Loop issue

    - by Charles John Thompson III
    I have this really bizarre issue where I have a forloop that is supposed to replace all divs with the class of "original" to text inputs with a class of "new". When I run the loop, it only replaces every-other div with an input, but if I run the loop to just replace the class of the div and not change the tag to input, it does every single div, and doesn't only do every-other. Here is my loop code, and a link to the live version: live version here function divChange() { var divs = document.getElementsByTagName("div"); for (var i=0; i<divs.length; i++) { if (divs[i].className == 'original') { var textInput = document.createElement('input'); textInput.className = 'new'; textInput.type = 'text'; textInput.value = divs[i].innerHTML; var parent = divs[i].parentNode; parent.replaceChild(textInput, divs[i]); } } }

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  • can i changed for loop index variable inside the loop in Matlab???

    - by shawana
    hi every one. i need to change my loop variable inside the iterationa as ihave to acces array elements in the loop which is changing w.r.t size inside the loop. ashort piece of code is that: que=[]; que=[2,3,4]; global len; len=size(que,2) x=4; for i=1:len if x<=10 que(x)= 5; len=size(que,2) x=x+1; end end que array should print like: 2 3 4 5 5 5 5 5 5 5 but it is printed in such a way: 2 3 4 5 5 5. how shuould it be accomplished in matlab? in visual c++ it happen correctly and print whole array of 10 elements which increases at run time plz reply me if have any ideaabout this as i m new into matlab

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  • jquery for loop on click image swap

    - by user2939914
    I've created a for loop of images. I would like each image to swap with another image on click individually. Here's the jQuery I've written so far: for ( var i = 1; i < 50; i++) { $('article').append('<div class="ps-block" id="' + i + '"><img src="img/bw/' + i + 'bw.png"></div>'); } $('img').click(function() { var imgid = $(this).attr('id'); $(this).attr("src", "img/color/" + imgid + ".png"); }); I also attempted to use this code inside the for loop after the append, but i ends up returning 50 every time you click since the loop has already ran: $('img[src="img/bw/' + i + 'bw.png"]').click(function() { $(this).attr("src", "img/color/" + this.id + ".png"); }); Thanks!

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  • BSOD Before Windows Will Loads - Graphics Related

    - by Brian
    Alright deep breath here: (Windows 7 Home Premium 64 bit btw) Today I installed Star Craft 2 Beta. After trying to log in, it had some issues where it said my device stopped working (referring to my video device I have to imagine). After I force quit the game there were some random "hot" (various colors if i remember correctly) pixels on the screen. I decided to reboot and try again with similar results. I figured that maybe my display drivers could stand to be updated (I don't frequently update them as I don't often run into problems). I went out to nVidia's website and grabbed the latest drivers for Windows 7 64 bit GeForce 9 series. (I have SLi-ed 9800 GTs). Everything seemed to install fine and I performed the restart. This is when things went from bad (can't play SC2 beta ;) ) to worse (can't boot into windows!). Initially the very first splash screen - I think it's the bios splash screen - had lines of colored pixels covering it. It then displayed a screen that had lots of "(" on it. After that it showed the normal windows 7 splash screen as if it were going to load into Windows. Before getting much further, it BSODed on me. It was a 0x0000003B stop error. At nvlddmkm.sys. A little digging let verified that this was a problem with an nVidia graphics device, not a real shocker. Windows decided it would try to help me diagnose the problem, which it's only answer to was a System Restore, which did nothing to alleviate the problem. I was able to boot up fine in safe mode and was not able to roll back the driver, however I did uninstall the driver and reboot. I still had the graphical anomalies during the first two screens (same colored "."'s and weird "("'s), but there was NOT a stop error. Windows loaded up, found a default driver for the device and installed it and I restarted to let it load - and had yet another BSOD Stop error. Repeat driver uninstall, this time I reloaded the same version (I think it's possible that I was running a 32 bit version or a vista versus windows 7 version, but I don't have that information handy) of the nVidia driver from their website. Restart, same anomalies, same Stop Error. I am at a loss - At this point all I can think is that the firmware for the Video cards got fried or there's actual damage to the cards which I sincerely hope is not the case but the sooner I know the better. Any insight into what I might be able to do to troubleshoot/fix this problem would be most helpful. Attached below is a dump from DxDiag. Please let me know if there is more info that I could provide. ------------------ System Information ------------------ Time of this report: 3/18/2010, 23:22:48 Machine name: BRIAN-PC Operating System: Windows 7 Home Premium 64-bit (6.1, Build 7600) (7600.win7_rtm.090713-1255) Language: English (Regional Setting: English) System Manufacturer: Dell Inc System Model: XPS 630i BIOS: Phoenix - AwardBIOS v6.00PG Processor: Intel(R) Core(TM)2 Quad CPU Q8200 @ 2.33GHz (4 CPUs), ~2.3GHz Memory: 8192MB RAM Available OS Memory: 8190MB RAM Page File: 1855MB used, 14521MB available Windows Dir: C:\Windows DirectX Version: DirectX 11 DX Setup Parameters: Not found User DPI Setting: Using System DPI System DPI Setting: 96 DPI (100 percent) DWM DPI Scaling: Disabled DxDiag Version: 6.01.7600.16385 32bit Unicode DxDiag Previously: Crashed in DirectShow (stage 1). Re-running DxDiag with "dontskip" command line parameter or choosing not to bypass information gathering when prompted might result in DxDiag successfully obtaining this information ------------ DxDiag Notes ------------ Display Tab 1: No problems found. Sound Tab 1: No problems found. Sound Tab 2: No problems found. Sound Tab 3: No problems found. Input Tab: No problems found. -------------------- DirectX Debug Levels -------------------- Direct3D: 0/4 (retail) DirectDraw: 0/4 (retail) DirectInput: 0/5 (retail) DirectMusic: 0/5 (retail) DirectPlay: 0/9 (retail) DirectSound: 0/5 (retail) DirectShow: 0/6 (retail) --------------- Display Devices --------------- Card name: Manufacturer: Chip type: DAC type: Device Key: Enum\ Display Memory: n/a Dedicated Memory: n/a Shared Memory: n/a Current Mode: 1600 x 1200 (32 bit) (1Hz) Driver Name: Driver File Version: () Driver Version: DDI Version: unknown Driver Model: unknown Driver Attributes: Final Retail Driver Date/Size: , 0 bytes WHQL Logo'd: n/a WHQL Date Stamp: n/a Device Identifier: {D7B70EE0-4340-11CF-B123-B03DAEC2CB35} Vendor ID: 0x0000 Device ID: 0x0000 SubSys ID: 0x00000000 Revision ID: 0x0000 Driver Strong Name: Unknown Rank Of Driver: Unknown Video Accel: Deinterlace Caps: n/a D3D9 Overlay: n/a DXVA-HD: n/a DDraw Status: Not Available D3D Status: Not Available AGP Status: Not Available ------------- Sound Devices ------------- Description: Speakers (Realtek High Definition Audio) Default Sound Playback: Yes Default Voice Playback: Yes Hardware ID: HDAUDIO\FUNC_01&VEN_10EC&DEV_0888&SUBSYS_10280249&REV_1001 Manufacturer ID: 1 Product ID: 100 Type: WDM Driver Name: RTKVHD64.sys Driver Version: 6.00.0001.5667 (English) Driver Attributes: Final Retail WHQL Logo'd: n/a Date and Size: 8/18/2008 04:05:28, 1485592 bytes Other Files: Driver Provider: Realtek Semiconductor Corp. HW Accel Level: Basic Cap Flags: 0x0 Min/Max Sample Rate: 0, 0 Static/Strm HW Mix Bufs: 0, 0 Static/Strm HW 3D Bufs: 0, 0 HW Memory: 0 Voice Management: No EAX(tm) 2.0 Listen/Src: No, No I3DL2(tm) Listen/Src: No, No Sensaura(tm) ZoomFX(tm): No Description: Realtek Digital Output (Realtek High Definition Audio) Default Sound Playback: No Default Voice Playback: No Hardware ID: HDAUDIO\FUNC_01&VEN_10EC&DEV_0888&SUBSYS_10280249&REV_1001 Manufacturer ID: 1 Product ID: 100 Type: WDM Driver Name: RTKVHD64.sys Driver Version: 6.00.0001.5667 (English) Driver Attributes: Final Retail WHQL Logo'd: n/a Date and Size: 8/18/2008 04:05:28, 1485592 bytes Other Files: Driver Provider: Realtek Semiconductor Corp. HW Accel Level: Basic Cap Flags: 0x0 Min/Max Sample Rate: 0, 0 Static/Strm HW Mix Bufs: 0, 0 Static/Strm HW 3D Bufs: 0, 0 HW Memory: 0 Voice Management: No EAX(tm) 2.0 Listen/Src: No, No I3DL2(tm) Listen/Src: No, No Sensaura(tm) ZoomFX(tm): No Description: Realtek HDMI Output (Realtek High Definition Audio) Default Sound Playback: No Default Voice Playback: No Hardware ID: HDAUDIO\FUNC_01&VEN_10EC&DEV_0888&SUBSYS_10280249&REV_1001 Manufacturer ID: 1 Product ID: 100 Type: WDM Driver Name: RTKVHD64.sys Driver Version: 6.00.0001.5667 (English) Driver Attributes: Final Retail WHQL Logo'd: n/a Date and Size: 8/18/2008 04:05:28, 1485592 bytes Other Files: Driver Provider: Realtek Semiconductor Corp. HW Accel Level: Basic Cap Flags: 0x0 Min/Max Sample Rate: 0, 0 Static/Strm HW Mix Bufs: 0, 0 Static/Strm HW 3D Bufs: 0, 0 HW Memory: 0 Voice Management: No EAX(tm) 2.0 Listen/Src: No, No I3DL2(tm) Listen/Src: No, No Sensaura(tm) ZoomFX(tm): No --------------------- Sound Capture Devices --------------------- Description: Microphone (Realtek High Definition Audio) Default Sound Capture: Yes Default Voice Capture: Yes Driver Name: RTKVHD64.sys Driver Version: 6.00.0001.5667 (English) Driver Attributes: Final Retail Date and Size: 8/18/2008 04:05:28, 1485592 bytes Cap Flags: 0x0 Format Flags: 0x0 Description: Realtek Digital Input (Realtek High Definition Audio) Default Sound Capture: No Default Voice Capture: No Driver Name: RTKVHD64.sys Driver Version: 6.00.0001.5667 (English) Driver Attributes: Final Retail Date and Size: 8/18/2008 04:05:28, 1485592 bytes Cap Flags: 0x0 Format Flags: 0x0 ------------------- DirectInput Devices ------------------- Device Name: Mouse Attached: 1 Controller ID: n/a Vendor/Product ID: n/a FF Driver: n/a Device Name: Keyboard Attached: 1 Controller ID: n/a Vendor/Product ID: n/a FF Driver: n/a Device Name: ESA FW Update Attached: 1 Controller ID: 0x0 Vendor/Product ID: 0x0955, 0x000A FF Driver: n/a Poll w/ Interrupt: No ----------- USB Devices ----------- + USB Root Hub | Vendor/Product ID: 0x10DE, 0x026D | Matching Device ID: usb\root_hub | Service: usbhub | +-+ USB Input Device | | Vendor/Product ID: 0x0955, 0x000A | | Location: Port_#0002.Hub_#0001 | | Matching Device ID: generic_hid_device | | Service: HidUsb | | | +-+ HID-compliant device | | | Vendor/Product ID: 0x0955, 0x000A | | | Matching Device ID: hid_device | | +-+ USB Input Device | | Vendor/Product ID: 0x046D, 0xC01E | | Location: Port_#0003.Hub_#0001 | | Matching Device ID: generic_hid_device | | Service: HidUsb | | | +-+ HID-compliant mouse | | | Vendor/Product ID: 0x046D, 0xC01E | | | Matching Device ID: hid_device_system_mouse | | | Service: mouhid ---------------- Gameport Devices ---------------- ------------ PS/2 Devices ------------ + Standard PS/2 Keyboard | Matching Device ID: *pnp0303 | Service: i8042prt | + Terminal Server Keyboard Driver | Matching Device ID: root\rdp_kbd | Upper Filters: kbdclass | Service: TermDD | + Terminal Server Mouse Driver | Matching Device ID: root\rdp_mou | Upper Filters: mouclass | Service: TermDD ------------------------ Disk & DVD/CD-ROM Drives ------------------------ Drive: C: Free Space: 324.3 GB Total Space: 608.4 GB File System: NTFS Model: WDC WD64 00AAKS-75A7B SCSI Disk Device Drive: D: Free Space: 1.0 GB Total Space: 2.0 GB File System: NTFS Model: WDC WD64 00AAKS-75A7B SCSI Disk Device Drive: E: Model: TSSTcorp DVD+-RW TS-H653F SCSI CdRom Device Driver: c:\windows\system32\drivers\cdrom.sys, 6.01.7600.16385 (English), , 0 bytes -------------- System Devices -------------- Name: PCI standard PCI-to-PCI bridge Device ID: PCI\VEN_10DE&DEV_03B7&SUBSYS_000010DE&REV_A1\3&2411E6FE&1&18 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03AF&SUBSYS_02491028&REV_A1\3&2411E6FE&1&0A Driver: n/a Name: PCI standard host CPU bridge Device ID: PCI\VEN_10DE&DEV_03A3&SUBSYS_02491028&REV_A2\3&2411E6FE&1&00 Driver: n/a Name: NVIDIA nForce Serial ATA Controller Device ID: PCI\VEN_10DE&DEV_0267&SUBSYS_02491028&REV_A1\3&2411E6FE&1&78 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03B6&SUBSYS_02491028&REV_A1\3&2411E6FE&1&10 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03AE&SUBSYS_02491028&REV_A1\3&2411E6FE&1&09 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_0272&SUBSYS_02491028&REV_A3\3&2411E6FE&1&52 Driver: n/a Name: NVIDIA nForce Serial ATA Controller Device ID: PCI\VEN_10DE&DEV_0266&SUBSYS_02491028&REV_A1\3&2411E6FE&1&70 Driver: n/a Name: LSI 1394 OHCI Compliant Host Controller Device ID: PCI\VEN_11C1&DEV_5811&SUBSYS_02491028&REV_70\4&14591D7E&0&2880 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03B5&SUBSYS_02491028&REV_A1\3&2411E6FE&1&06 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03AD&SUBSYS_02491028&REV_A1\3&2411E6FE&1&08 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_0270&SUBSYS_02491028&REV_A2\3&2411E6FE&1&48 Driver: n/a Name: Standard Dual Channel PCI IDE Controller Device ID: PCI\VEN_10DE&DEV_0265&SUBSYS_02491028&REV_A1\3&2411E6FE&1&68 Driver: n/a Name: NVIDIA GeForce 9800 GT Device ID: PCI\VEN_10DE&DEV_0605&SUBSYS_062D10DE&REV_A2\4&4BABE2A&0&0028 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03B4&SUBSYS_02491028&REV_A1\3&2411E6FE&1&07 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03AC&SUBSYS_02491028&REV_A1\3&2411E6FE&1&01 Driver: n/a Name: PCI standard PCI-to-PCI bridge Device ID: PCI\VEN_10DE&DEV_026F&SUBSYS_CB8410DE&REV_A2\3&2411E6FE&1&80 Driver: n/a Name: NVIDIA nForce PCI System Management Device ID: PCI\VEN_10DE&DEV_0264&SUBSYS_02491028&REV_A3\3&2411E6FE&1&51 Driver: n/a Name: NVIDIA GeForce 9800 GT Device ID: PCI\VEN_10DE&DEV_0605&SUBSYS_062D10DE&REV_A2\4&10BD3C89&0&0018 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03B3&SUBSYS_02491028&REV_A1\3&2411E6FE&1&0E Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03AB&SUBSYS_02491028&REV_A1\3&2411E6FE&1&04 Driver: n/a Name: Standard Enhanced PCI to USB Host Controller Device ID: PCI\VEN_10DE&DEV_026E&SUBSYS_02491028&REV_A3\3&2411E6FE&1&59 Driver: n/a Name: PCI standard ISA bridge Device ID: PCI\VEN_10DE&DEV_0260&SUBSYS_02491028&REV_A3\3&2411E6FE&1&50 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03BC&SUBSYS_02491028&REV_A1\3&2411E6FE&1&11 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03B2&SUBSYS_02491028&REV_A1\3&2411E6FE&1&0D Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03AA&SUBSYS_02491028&REV_A1\3&2411E6FE&1&02 Driver: n/a Name: Standard OpenHCD USB Host Controller Device ID: PCI\VEN_10DE&DEV_026D&SUBSYS_02491028&REV_A3\3&2411E6FE&1&58 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03BA&SUBSYS_02491028&REV_A1\3&2411E6FE&1&12 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03B1&SUBSYS_02491028&REV_A1\3&2411E6FE&1&0C Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03A9&SUBSYS_02491028&REV_A1\3&2411E6FE&1&03 Driver: n/a Name: High Definition Audio Controller Device ID: PCI\VEN_10DE&DEV_026C&SUBSYS_02491028&REV_A2\3&2411E6FE&1&81 Driver: n/a Name: PCI standard PCI-to-PCI bridge Device ID: PCI\VEN_10DE&DEV_03B8&SUBSYS_000010DE&REV_A1\3&2411E6FE&1&28 Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03B0&SUBSYS_02491028&REV_A1\3&2411E6FE&1&0B Driver: n/a Name: PCI standard RAM Controller Device ID: PCI\VEN_10DE&DEV_03A8&SUBSYS_02491028&REV_A2\3&2411E6FE&1&05 Driver: n/a Name: NVIDIA nForce Networking Controller Device ID: PCI\VEN_10DE&DEV_0269&SUBSYS_02491028&REV_A3\3&2411E6FE&1&A0 Driver: n/a --------------- EVR Power Information --------------- Current Setting: {5C67A112-A4C9-483F-B4A7-1D473BECAFDC} (Quality) Quality Flags: 2576 Enabled: Force throttling Allow half deinterlace Allow scaling Decode Power Usage: 100 Balanced Flags: 1424 Enabled: Force throttling Allow batching Force half deinterlace Force scaling Decode Power Usage: 50 PowerFlags: 1424 Enabled: Force throttling Allow batching Force half deinterlace Force scaling Decode Power Usage: 0

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  • How John Got 15x Improvement Without Really Trying

    - by rchrd
    The following article was published on a Sun Microsystems website a number of years ago by John Feo. It is still useful and worth preserving. So I'm republishing it here.  How I Got 15x Improvement Without Really Trying John Feo, Sun Microsystems Taking ten "personal" program codes used in scientific and engineering research, the author was able to get from 2 to 15 times performance improvement easily by applying some simple general optimization techniques. Introduction Scientific research based on computer simulation depends on the simulation for advancement. The research can advance only as fast as the computational codes can execute. The codes' efficiency determines both the rate and quality of results. In the same amount of time, a faster program can generate more results and can carry out a more detailed simulation of physical phenomena than a slower program. Highly optimized programs help science advance quickly and insure that monies supporting scientific research are used as effectively as possible. Scientific computer codes divide into three broad categories: ISV, community, and personal. ISV codes are large, mature production codes developed and sold commercially. The codes improve slowly over time both in methods and capabilities, and they are well tuned for most vendor platforms. Since the codes are mature and complex, there are few opportunities to improve their performance solely through code optimization. Improvements of 10% to 15% are typical. Examples of ISV codes are DYNA3D, Gaussian, and Nastran. Community codes are non-commercial production codes used by a particular research field. Generally, they are developed and distributed by a single academic or research institution with assistance from the community. Most users just run the codes, but some develop new methods and extensions that feed back into the general release. The codes are available on most vendor platforms. Since these codes are younger than ISV codes, there are more opportunities to optimize the source code. Improvements of 50% are not unusual. Examples of community codes are AMBER, CHARM, BLAST, and FASTA. Personal codes are those written by single users or small research groups for their own use. These codes are not distributed, but may be passed from professor-to-student or student-to-student over several years. They form the primordial ocean of applications from which community and ISV codes emerge. Government research grants pay for the development of most personal codes. This paper reports on the nature and performance of this class of codes. Over the last year, I have looked at over two dozen personal codes from more than a dozen research institutions. The codes cover a variety of scientific fields, including astronomy, atmospheric sciences, bioinformatics, biology, chemistry, geology, and physics. The sources range from a few hundred lines to more than ten thousand lines, and are written in Fortran, Fortran 90, C, and C++. For the most part, the codes are modular, documented, and written in a clear, straightforward manner. They do not use complex language features, advanced data structures, programming tricks, or libraries. I had little trouble understanding what the codes did or how data structures were used. Most came with a makefile. Surprisingly, only one of the applications is parallel. All developers have access to parallel machines, so availability is not an issue. Several tried to parallelize their applications, but stopped after encountering difficulties. Lack of education and a perception that parallelism is difficult prevented most from trying. I parallelized several of the codes using OpenMP, and did not judge any of the codes as difficult to parallelize. Even more surprising than the lack of parallelism is the inefficiency of the codes. I was able to get large improvements in performance in a matter of a few days applying simple optimization techniques. Table 1 lists ten representative codes [names and affiliation are omitted to preserve anonymity]. Improvements on one processor range from 2x to 15.5x with a simple average of 4.75x. I did not use sophisticated performance tools or drill deep into the program's execution character as one would do when tuning ISV or community codes. Using only a profiler and source line timers, I identified inefficient sections of code and improved their performance by inspection. The changes were at a high level. I am sure there is another factor of 2 or 3 in each code, and more if the codes are parallelized. The study’s results show that personal scientific codes are running many times slower than they should and that the problem is pervasive. Computational scientists are not sloppy programmers; however, few are trained in the art of computer programming or code optimization. I found that most have a working knowledge of some programming language and standard software engineering practices; but they do not know, or think about, how to make their programs run faster. They simply do not know the standard techniques used to make codes run faster. In fact, they do not even perceive that such techniques exist. The case studies described in this paper show that applying simple, well known techniques can significantly increase the performance of personal codes. It is important that the scientific community and the Government agencies that support scientific research find ways to better educate academic scientific programmers. The inefficiency of their codes is so bad that it is retarding both the quality and progress of scientific research. # cacheperformance redundantoperations loopstructures performanceimprovement 1 x x 15.5 2 x 2.8 3 x x 2.5 4 x 2.1 5 x x 2.0 6 x 5.0 7 x 5.8 8 x 6.3 9 2.2 10 x x 3.3 Table 1 — Area of improvement and performance gains of 10 codes The remainder of the paper is organized as follows: sections 2, 3, and 4 discuss the three most common sources of inefficiencies in the codes studied. These are cache performance, redundant operations, and loop structures. Each section includes several examples. The last section summaries the work and suggests a possible solution to the issues raised. Optimizing cache performance Commodity microprocessor systems use caches to increase memory bandwidth and reduce memory latencies. Typical latencies from processor to L1, L2, local, and remote memory are 3, 10, 50, and 200 cycles, respectively. Moreover, bandwidth falls off dramatically as memory distances increase. Programs that do not use cache effectively run many times slower than programs that do. When optimizing for cache, the biggest performance gains are achieved by accessing data in cache order and reusing data to amortize the overhead of cache misses. Secondary considerations are prefetching, associativity, and replacement; however, the understanding and analysis required to optimize for the latter are probably beyond the capabilities of the non-expert. Much can be gained simply by accessing data in the correct order and maximizing data reuse. 6 out of the 10 codes studied here benefited from such high level optimizations. Array Accesses The most important cache optimization is the most basic: accessing Fortran array elements in column order and C array elements in row order. Four of the ten codes—1, 2, 4, and 10—got it wrong. Compilers will restructure nested loops to optimize cache performance, but may not do so if the loop structure is too complex, or the loop body includes conditionals, complex addressing, or function calls. In code 1, the compiler failed to invert a key loop because of complex addressing do I = 0, 1010, delta_x IM = I - delta_x IP = I + delta_x do J = 5, 995, delta_x JM = J - delta_x JP = J + delta_x T1 = CA1(IP, J) + CA1(I, JP) T2 = CA1(IM, J) + CA1(I, JM) S1 = T1 + T2 - 4 * CA1(I, J) CA(I, J) = CA1(I, J) + D * S1 end do end do In code 2, the culprit is conditionals do I = 1, N do J = 1, N If (IFLAG(I,J) .EQ. 0) then T1 = Value(I, J-1) T2 = Value(I-1, J) T3 = Value(I, J) T4 = Value(I+1, J) T5 = Value(I, J+1) Value(I,J) = 0.25 * (T1 + T2 + T5 + T4) Delta = ABS(T3 - Value(I,J)) If (Delta .GT. MaxDelta) MaxDelta = Delta endif enddo enddo I fixed both programs by inverting the loops by hand. Code 10 has three-dimensional arrays and triply nested loops. The structure of the most computationally intensive loops is too complex to invert automatically or by hand. The only practical solution is to transpose the arrays so that the dimension accessed by the innermost loop is in cache order. The arrays can be transposed at construction or prior to entering a computationally intensive section of code. The former requires all array references to be modified, while the latter is cost effective only if the cost of the transpose is amortized over many accesses. I used the second approach to optimize code 10. Code 5 has four-dimensional arrays and loops are nested four deep. For all of the reasons cited above the compiler is not able to restructure three key loops. Assume C arrays and let the four dimensions of the arrays be i, j, k, and l. In the original code, the index structure of the three loops is L1: for i L2: for i L3: for i for l for l for j for k for j for k for j for k for l So only L3 accesses array elements in cache order. L1 is a very complex loop—much too complex to invert. I brought the loop into cache alignment by transposing the second and fourth dimensions of the arrays. Since the code uses a macro to compute all array indexes, I effected the transpose at construction and changed the macro appropriately. The dimensions of the new arrays are now: i, l, k, and j. L3 is a simple loop and easily inverted. L2 has a loop-carried scalar dependence in k. By promoting the scalar name that carries the dependence to an array, I was able to invert the third and fourth subloops aligning the loop with cache. Code 5 is by far the most difficult of the four codes to optimize for array accesses; but the knowledge required to fix the problems is no more than that required for the other codes. I would judge this code at the limits of, but not beyond, the capabilities of appropriately trained computational scientists. Array Strides When a cache miss occurs, a line (64 bytes) rather than just one word is loaded into the cache. If data is accessed stride 1, than the cost of the miss is amortized over 8 words. Any stride other than one reduces the cost savings. Two of the ten codes studied suffered from non-unit strides. The codes represent two important classes of "strided" codes. Code 1 employs a multi-grid algorithm to reduce time to convergence. The grids are every tenth, fifth, second, and unit element. Since time to convergence is inversely proportional to the distance between elements, coarse grids converge quickly providing good starting values for finer grids. The better starting values further reduce the time to convergence. The downside is that grids of every nth element, n > 1, introduce non-unit strides into the computation. In the original code, much of the savings of the multi-grid algorithm were lost due to this problem. I eliminated the problem by compressing (copying) coarse grids into continuous memory, and rewriting the computation as a function of the compressed grid. On convergence, I copied the final values of the compressed grid back to the original grid. The savings gained from unit stride access of the compressed grid more than paid for the cost of copying. Using compressed grids, the loop from code 1 included in the previous section becomes do j = 1, GZ do i = 1, GZ T1 = CA(i+0, j-1) + CA(i-1, j+0) T4 = CA1(i+1, j+0) + CA1(i+0, j+1) S1 = T1 + T4 - 4 * CA1(i+0, j+0) CA(i+0, j+0) = CA1(i+0, j+0) + DD * S1 enddo enddo where CA and CA1 are compressed arrays of size GZ. Code 7 traverses a list of objects selecting objects for later processing. The labels of the selected objects are stored in an array. The selection step has unit stride, but the processing steps have irregular stride. A fix is to save the parameters of the selected objects in temporary arrays as they are selected, and pass the temporary arrays to the processing functions. The fix is practical if the same parameters are used in selection as in processing, or if processing comprises a series of distinct steps which use overlapping subsets of the parameters. Both conditions are true for code 7, so I achieved significant improvement by copying parameters to temporary arrays during selection. Data reuse In the previous sections, we optimized for spatial locality. It is also important to optimize for temporal locality. Once read, a datum should be used as much as possible before it is forced from cache. Loop fusion and loop unrolling are two techniques that increase temporal locality. Unfortunately, both techniques increase register pressure—as loop bodies become larger, the number of registers required to hold temporary values grows. Once register spilling occurs, any gains evaporate quickly. For multiprocessors with small register sets or small caches, the sweet spot can be very small. In the ten codes presented here, I found no opportunities for loop fusion and only two opportunities for loop unrolling (codes 1 and 3). In code 1, unrolling the outer and inner loop one iteration increases the number of result values computed by the loop body from 1 to 4, do J = 1, GZ-2, 2 do I = 1, GZ-2, 2 T1 = CA1(i+0, j-1) + CA1(i-1, j+0) T2 = CA1(i+1, j-1) + CA1(i+0, j+0) T3 = CA1(i+0, j+0) + CA1(i-1, j+1) T4 = CA1(i+1, j+0) + CA1(i+0, j+1) T5 = CA1(i+2, j+0) + CA1(i+1, j+1) T6 = CA1(i+1, j+1) + CA1(i+0, j+2) T7 = CA1(i+2, j+1) + CA1(i+1, j+2) S1 = T1 + T4 - 4 * CA1(i+0, j+0) S2 = T2 + T5 - 4 * CA1(i+1, j+0) S3 = T3 + T6 - 4 * CA1(i+0, j+1) S4 = T4 + T7 - 4 * CA1(i+1, j+1) CA(i+0, j+0) = CA1(i+0, j+0) + DD * S1 CA(i+1, j+0) = CA1(i+1, j+0) + DD * S2 CA(i+0, j+1) = CA1(i+0, j+1) + DD * S3 CA(i+1, j+1) = CA1(i+1, j+1) + DD * S4 enddo enddo The loop body executes 12 reads, whereas as the rolled loop shown in the previous section executes 20 reads to compute the same four values. In code 3, two loops are unrolled 8 times and one loop is unrolled 4 times. Here is the before for (k = 0; k < NK[u]; k++) { sum = 0.0; for (y = 0; y < NY; y++) { sum += W[y][u][k] * delta[y]; } backprop[i++]=sum; } and after code for (k = 0; k < KK - 8; k+=8) { sum0 = 0.0; sum1 = 0.0; sum2 = 0.0; sum3 = 0.0; sum4 = 0.0; sum5 = 0.0; sum6 = 0.0; sum7 = 0.0; for (y = 0; y < NY; y++) { sum0 += W[y][0][k+0] * delta[y]; sum1 += W[y][0][k+1] * delta[y]; sum2 += W[y][0][k+2] * delta[y]; sum3 += W[y][0][k+3] * delta[y]; sum4 += W[y][0][k+4] * delta[y]; sum5 += W[y][0][k+5] * delta[y]; sum6 += W[y][0][k+6] * delta[y]; sum7 += W[y][0][k+7] * delta[y]; } backprop[k+0] = sum0; backprop[k+1] = sum1; backprop[k+2] = sum2; backprop[k+3] = sum3; backprop[k+4] = sum4; backprop[k+5] = sum5; backprop[k+6] = sum6; backprop[k+7] = sum7; } for one of the loops unrolled 8 times. Optimizing for temporal locality is the most difficult optimization considered in this paper. The concepts are not difficult, but the sweet spot is small. Identifying where the program can benefit from loop unrolling or loop fusion is not trivial. Moreover, it takes some effort to get it right. Still, educating scientific programmers about temporal locality and teaching them how to optimize for it will pay dividends. Reducing instruction count Execution time is a function of instruction count. Reduce the count and you usually reduce the time. The best solution is to use a more efficient algorithm; that is, an algorithm whose order of complexity is smaller, that converges quicker, or is more accurate. Optimizing source code without changing the algorithm yields smaller, but still significant, gains. This paper considers only the latter because the intent is to study how much better codes can run if written by programmers schooled in basic code optimization techniques. The ten codes studied benefited from three types of "instruction reducing" optimizations. The two most prevalent were hoisting invariant memory and data operations out of inner loops. The third was eliminating unnecessary data copying. The nature of these inefficiencies is language dependent. Memory operations The semantics of C make it difficult for the compiler to determine all the invariant memory operations in a loop. The problem is particularly acute for loops in functions since the compiler may not know the values of the function's parameters at every call site when compiling the function. Most compilers support pragmas to help resolve ambiguities; however, these pragmas are not comprehensive and there is no standard syntax. To guarantee that invariant memory operations are not executed repetitively, the user has little choice but to hoist the operations by hand. The problem is not as severe in Fortran programs because in the absence of equivalence statements, it is a violation of the language's semantics for two names to share memory. Codes 3 and 5 are C programs. In both cases, the compiler did not hoist all invariant memory operations from inner loops. Consider the following loop from code 3 for (y = 0; y < NY; y++) { i = 0; for (u = 0; u < NU; u++) { for (k = 0; k < NK[u]; k++) { dW[y][u][k] += delta[y] * I1[i++]; } } } Since dW[y][u] can point to the same memory space as delta for one or more values of y and u, assignment to dW[y][u][k] may change the value of delta[y]. In reality, dW and delta do not overlap in memory, so I rewrote the loop as for (y = 0; y < NY; y++) { i = 0; Dy = delta[y]; for (u = 0; u < NU; u++) { for (k = 0; k < NK[u]; k++) { dW[y][u][k] += Dy * I1[i++]; } } } Failure to hoist invariant memory operations may be due to complex address calculations. If the compiler can not determine that the address calculation is invariant, then it can hoist neither the calculation nor the associated memory operations. As noted above, code 5 uses a macro to address four-dimensional arrays #define MAT4D(a,q,i,j,k) (double *)((a)->data + (q)*(a)->strides[0] + (i)*(a)->strides[3] + (j)*(a)->strides[2] + (k)*(a)->strides[1]) The macro is too complex for the compiler to understand and so, it does not identify any subexpressions as loop invariant. The simplest way to eliminate the address calculation from the innermost loop (over i) is to define a0 = MAT4D(a,q,0,j,k) before the loop and then replace all instances of *MAT4D(a,q,i,j,k) in the loop with a0[i] A similar problem appears in code 6, a Fortran program. The key loop in this program is do n1 = 1, nh nx1 = (n1 - 1) / nz + 1 nz1 = n1 - nz * (nx1 - 1) do n2 = 1, nh nx2 = (n2 - 1) / nz + 1 nz2 = n2 - nz * (nx2 - 1) ndx = nx2 - nx1 ndy = nz2 - nz1 gxx = grn(1,ndx,ndy) gyy = grn(2,ndx,ndy) gxy = grn(3,ndx,ndy) balance(n1,1) = balance(n1,1) + (force(n2,1) * gxx + force(n2,2) * gxy) * h1 balance(n1,2) = balance(n1,2) + (force(n2,1) * gxy + force(n2,2) * gyy)*h1 end do end do The programmer has written this loop well—there are no loop invariant operations with respect to n1 and n2. However, the loop resides within an iterative loop over time and the index calculations are independent with respect to time. Trading space for time, I precomputed the index values prior to the entering the time loop and stored the values in two arrays. I then replaced the index calculations with reads of the arrays. Data operations Ways to reduce data operations can appear in many forms. Implementing a more efficient algorithm produces the biggest gains. The closest I came to an algorithm change was in code 4. This code computes the inner product of K-vectors A(i) and B(j), 0 = i < N, 0 = j < M, for most values of i and j. Since the program computes most of the NM possible inner products, it is more efficient to compute all the inner products in one triply-nested loop rather than one at a time when needed. The savings accrue from reading A(i) once for all B(j) vectors and from loop unrolling. for (i = 0; i < N; i+=8) { for (j = 0; j < M; j++) { sum0 = 0.0; sum1 = 0.0; sum2 = 0.0; sum3 = 0.0; sum4 = 0.0; sum5 = 0.0; sum6 = 0.0; sum7 = 0.0; for (k = 0; k < K; k++) { sum0 += A[i+0][k] * B[j][k]; sum1 += A[i+1][k] * B[j][k]; sum2 += A[i+2][k] * B[j][k]; sum3 += A[i+3][k] * B[j][k]; sum4 += A[i+4][k] * B[j][k]; sum5 += A[i+5][k] * B[j][k]; sum6 += A[i+6][k] * B[j][k]; sum7 += A[i+7][k] * B[j][k]; } C[i+0][j] = sum0; C[i+1][j] = sum1; C[i+2][j] = sum2; C[i+3][j] = sum3; C[i+4][j] = sum4; C[i+5][j] = sum5; C[i+6][j] = sum6; C[i+7][j] = sum7; }} This change requires knowledge of a typical run; i.e., that most inner products are computed. The reasons for the change, however, derive from basic optimization concepts. It is the type of change easily made at development time by a knowledgeable programmer. In code 5, we have the data version of the index optimization in code 6. Here a very expensive computation is a function of the loop indices and so cannot be hoisted out of the loop; however, the computation is invariant with respect to an outer iterative loop over time. We can compute its value for each iteration of the computation loop prior to entering the time loop and save the values in an array. The increase in memory required to store the values is small in comparison to the large savings in time. The main loop in Code 8 is doubly nested. The inner loop includes a series of guarded computations; some are a function of the inner loop index but not the outer loop index while others are a function of the outer loop index but not the inner loop index for (j = 0; j < N; j++) { for (i = 0; i < M; i++) { r = i * hrmax; R = A[j]; temp = (PRM[3] == 0.0) ? 1.0 : pow(r, PRM[3]); high = temp * kcoeff * B[j] * PRM[2] * PRM[4]; low = high * PRM[6] * PRM[6] / (1.0 + pow(PRM[4] * PRM[6], 2.0)); kap = (R > PRM[6]) ? high * R * R / (1.0 + pow(PRM[4]*r, 2.0) : low * pow(R/PRM[6], PRM[5]); < rest of loop omitted > }} Note that the value of temp is invariant to j. Thus, we can hoist the computation for temp out of the loop and save its values in an array. for (i = 0; i < M; i++) { r = i * hrmax; TEMP[i] = pow(r, PRM[3]); } [N.B. – the case for PRM[3] = 0 is omitted and will be reintroduced later.] We now hoist out of the inner loop the computations invariant to i. Since the conditional guarding the value of kap is invariant to i, it behooves us to hoist the computation out of the inner loop, thereby executing the guard once rather than M times. The final version of the code is for (j = 0; j < N; j++) { R = rig[j] / 1000.; tmp1 = kcoeff * par[2] * beta[j] * par[4]; tmp2 = 1.0 + (par[4] * par[4] * par[6] * par[6]); tmp3 = 1.0 + (par[4] * par[4] * R * R); tmp4 = par[6] * par[6] / tmp2; tmp5 = R * R / tmp3; tmp6 = pow(R / par[6], par[5]); if ((par[3] == 0.0) && (R > par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * tmp5; } else if ((par[3] == 0.0) && (R <= par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * tmp4 * tmp6; } else if ((par[3] != 0.0) && (R > par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * TEMP[i] * tmp5; } else if ((par[3] != 0.0) && (R <= par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * TEMP[i] * tmp4 * tmp6; } for (i = 0; i < M; i++) { kap = KAP[i]; r = i * hrmax; < rest of loop omitted > } } Maybe not the prettiest piece of code, but certainly much more efficient than the original loop, Copy operations Several programs unnecessarily copy data from one data structure to another. This problem occurs in both Fortran and C programs, although it manifests itself differently in the two languages. Code 1 declares two arrays—one for old values and one for new values. At the end of each iteration, the array of new values is copied to the array of old values to reset the data structures for the next iteration. This problem occurs in Fortran programs not included in this study and in both Fortran 77 and Fortran 90 code. Introducing pointers to the arrays and swapping pointer values is an obvious way to eliminate the copying; but pointers is not a feature that many Fortran programmers know well or are comfortable using. An easy solution not involving pointers is to extend the dimension of the value array by 1 and use the last dimension to differentiate between arrays at different times. For example, if the data space is N x N, declare the array (N, N, 2). Then store the problem’s initial values in (_, _, 2) and define the scalar names new = 2 and old = 1. At the start of each iteration, swap old and new to reset the arrays. The old–new copy problem did not appear in any C program. In programs that had new and old values, the code swapped pointers to reset data structures. Where unnecessary coping did occur is in structure assignment and parameter passing. Structures in C are handled much like scalars. Assignment causes the data space of the right-hand name to be copied to the data space of the left-hand name. Similarly, when a structure is passed to a function, the data space of the actual parameter is copied to the data space of the formal parameter. If the structure is large and the assignment or function call is in an inner loop, then copying costs can grow quite large. While none of the ten programs considered here manifested this problem, it did occur in programs not included in the study. A simple fix is always to refer to structures via pointers. Optimizing loop structures Since scientific programs spend almost all their time in loops, efficient loops are the key to good performance. Conditionals, function calls, little instruction level parallelism, and large numbers of temporary values make it difficult for the compiler to generate tightly packed, highly efficient code. Conditionals and function calls introduce jumps that disrupt code flow. Users should eliminate or isolate conditionls to their own loops as much as possible. Often logical expressions can be substituted for if-then-else statements. For example, code 2 includes the following snippet MaxDelta = 0.0 do J = 1, N do I = 1, M < code omitted > Delta = abs(OldValue ? NewValue) if (Delta > MaxDelta) MaxDelta = Delta enddo enddo if (MaxDelta .gt. 0.001) goto 200 Since the only use of MaxDelta is to control the jump to 200 and all that matters is whether or not it is greater than 0.001, I made MaxDelta a boolean and rewrote the snippet as MaxDelta = .false. do J = 1, N do I = 1, M < code omitted > Delta = abs(OldValue ? NewValue) MaxDelta = MaxDelta .or. (Delta .gt. 0.001) enddo enddo if (MaxDelta) goto 200 thereby, eliminating the conditional expression from the inner loop. A microprocessor can execute many instructions per instruction cycle. Typically, it can execute one or more memory, floating point, integer, and jump operations. To be executed simultaneously, the operations must be independent. Thick loops tend to have more instruction level parallelism than thin loops. Moreover, they reduce memory traffice by maximizing data reuse. Loop unrolling and loop fusion are two techniques to increase the size of loop bodies. Several of the codes studied benefitted from loop unrolling, but none benefitted from loop fusion. This observation is not too surpising since it is the general tendency of programmers to write thick loops. As loops become thicker, the number of temporary values grows, increasing register pressure. If registers spill, then memory traffic increases and code flow is disrupted. A thick loop with many temporary values may execute slower than an equivalent series of thin loops. The biggest gain will be achieved if the thick loop can be split into a series of independent loops eliminating the need to write and read temporary arrays. I found such an occasion in code 10 where I split the loop do i = 1, n do j = 1, m A24(j,i)= S24(j,i) * T24(j,i) + S25(j,i) * U25(j,i) B24(j,i)= S24(j,i) * T25(j,i) + S25(j,i) * U24(j,i) A25(j,i)= S24(j,i) * C24(j,i) + S25(j,i) * V24(j,i) B25(j,i)= S24(j,i) * U25(j,i) + S25(j,i) * V25(j,i) C24(j,i)= S26(j,i) * T26(j,i) + S27(j,i) * U26(j,i) D24(j,i)= S26(j,i) * T27(j,i) + S27(j,i) * V26(j,i) C25(j,i)= S27(j,i) * S28(j,i) + S26(j,i) * U28(j,i) D25(j,i)= S27(j,i) * T28(j,i) + S26(j,i) * V28(j,i) end do end do into two disjoint loops do i = 1, n do j = 1, m A24(j,i)= S24(j,i) * T24(j,i) + S25(j,i) * U25(j,i) B24(j,i)= S24(j,i) * T25(j,i) + S25(j,i) * U24(j,i) A25(j,i)= S24(j,i) * C24(j,i) + S25(j,i) * V24(j,i) B25(j,i)= S24(j,i) * U25(j,i) + S25(j,i) * V25(j,i) end do end do do i = 1, n do j = 1, m C24(j,i)= S26(j,i) * T26(j,i) + S27(j,i) * U26(j,i) D24(j,i)= S26(j,i) * T27(j,i) + S27(j,i) * V26(j,i) C25(j,i)= S27(j,i) * S28(j,i) + S26(j,i) * U28(j,i) D25(j,i)= S27(j,i) * T28(j,i) + S26(j,i) * V28(j,i) end do end do Conclusions Over the course of the last year, I have had the opportunity to work with over two dozen academic scientific programmers at leading research universities. Their research interests span a broad range of scientific fields. Except for two programs that relied almost exclusively on library routines (matrix multiply and fast Fourier transform), I was able to improve significantly the single processor performance of all codes. Improvements range from 2x to 15.5x with a simple average of 4.75x. Changes to the source code were at a very high level. I did not use sophisticated techniques or programming tools to discover inefficiencies or effect the changes. Only one code was parallel despite the availability of parallel systems to all developers. Clearly, we have a problem—personal scientific research codes are highly inefficient and not running parallel. The developers are unaware of simple optimization techniques to make programs run faster. They lack education in the art of code optimization and parallel programming. I do not believe we can fix the problem by publishing additional books or training manuals. To date, the developers in questions have not studied the books or manual available, and are unlikely to do so in the future. Short courses are a possible solution, but I believe they are too concentrated to be much use. The general concepts can be taught in a three or four day course, but that is not enough time for students to practice what they learn and acquire the experience to apply and extend the concepts to their codes. Practice is the key to becoming proficient at optimization. I recommend that graduate students be required to take a semester length course in optimization and parallel programming. We would never give someone access to state-of-the-art scientific equipment costing hundreds of thousands of dollars without first requiring them to demonstrate that they know how to use the equipment. Yet the criterion for time on state-of-the-art supercomputers is at most an interesting project. Requestors are never asked to demonstrate that they know how to use the system, or can use the system effectively. A semester course would teach them the required skills. Government agencies that fund academic scientific research pay for most of the computer systems supporting scientific research as well as the development of most personal scientific codes. These agencies should require graduate schools to offer a course in optimization and parallel programming as a requirement for funding. About the Author John Feo received his Ph.D. in Computer Science from The University of Texas at Austin in 1986. After graduate school, Dr. Feo worked at Lawrence Livermore National Laboratory where he was the Group Leader of the Computer Research Group and principal investigator of the Sisal Language Project. In 1997, Dr. Feo joined Tera Computer Company where he was project manager for the MTA, and oversaw the programming and evaluation of the MTA at the San Diego Supercomputer Center. In 2000, Dr. Feo joined Sun Microsystems as an HPC application specialist. He works with university research groups to optimize and parallelize scientific codes. Dr. Feo has published over two dozen research articles in the areas of parallel parallel programming, parallel programming languages, and application performance.

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  • Wireless Problem on HP Pavillion G6

    - by user47954
    I have a broadcom wireless card in my laptop and the wireless is not working correctly. right in front of the router the wireless signal is 70% and across the room it barely works and in another room it disconnects. i have the drivers and everything. i am running ubuntu 11.10 64bit.it works perfectly in windows 7. can anyone help! 00:00.0 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1705] 00:01.0 VGA compatible controller [0300]: ATI Technologies Inc Device [1002:9649] 00:01.1 Audio device [0403]: ATI Technologies Inc Device [1002:1714] Kernel driver in use: HDA Intel Kernel modules: snd-hda-intel 00:04.0 PCI bridge [0604]: Advanced Micro Devices [AMD] Device [1022:1709] Kernel driver in use: pcieport Kernel modules: shpchp 00:11.0 SATA controller [0106]: Advanced Micro Devices [AMD] Device [1022:7804] Kernel driver in use: ahci Kernel modules: ahci 00:12.0 USB Controller [0c03]: Advanced Micro Devices [AMD] Device [1022:7807] (rev 11) Kernel driver in use: ohci_hcd 00:12.2 USB Controller [0c03]: Advanced Micro Devices [AMD] Device [1022:7808] (rev 11) Kernel driver in use: ehci_hcd 00:13.0 USB Controller [0c03]: Advanced Micro Devices [AMD] Device [1022:7807] (rev 11) Kernel driver in use: ohci_hcd 00:13.2 USB Controller [0c03]: Advanced Micro Devices [AMD] Device [1022:7808] (rev 11) Kernel driver in use: ehci_hcd 00:14.0 SMBus [0c05]: Advanced Micro Devices [AMD] Device [1022:780b] (rev 13) Kernel modules: i2c-piix4 00:14.2 Audio device [0403]: Advanced Micro Devices [AMD] Device [1022:780d] (rev 01) Kernel driver in use: HDA Intel Kernel modules: snd-hda-intel 00:14.3 ISA bridge [0601]: Advanced Micro Devices [AMD] Device [1022:780e] (rev 11) 00:14.4 PCI bridge [0604]: Advanced Micro Devices [AMD] Device [1022:780f] (rev 40) 00:15.0 PCI bridge [0604]: Advanced Micro Devices [AMD] Device [1022:43a0] Kernel driver in use: pcieport Kernel modules: shpchp 00:15.1 PCI bridge [0604]: Advanced Micro Devices [AMD] Device [1022:43a1] Kernel driver in use: pcieport Kernel modules: shpchp 00:15.2 PCI bridge [0604]: Advanced Micro Devices [AMD] Device [1022:43a2] Kernel driver in use: pcieport Kernel modules: shpchp 00:18.0 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1700] (rev 43) 00:18.1 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1701] 00:18.2 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1702] 00:18.3 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1703] 00:18.4 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1704] 00:18.5 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1718] 00:18.6 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1716] 00:18.7 Host bridge [0600]: Advanced Micro Devices [AMD] Device [1022:1719] 01:00.0 Ethernet controller [0200]: Realtek Semiconductor Co., Ltd. RTL8101E/RTL8102E PCI Express Fast Ethernet controller [10ec:8136] (rev 05) Kernel driver in use: r8169 Kernel modules: r8169 07:00.0 Network controller [0280]: Broadcom Corporation Device [14e4:4727] (rev 01) Kernel driver in use: wl Kernel modules: wl 08:00.0 Class [ff00]: Realtek Semiconductor Co., Ltd. Device [10ec:5209] (rev 01)

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  • Ruby: Continue a loop after catching an exception

    - by Santa
    Basically, I want to do something like this (in Python, or similar imperative languages): for i in xrange(1, 5): try: do_something_that_might_raise_exceptions(i) except: continue # continue the loop at i = i + 1 How do I do this in Ruby? I know there are the redo and retry keywords, but they seem to re-execute the "try" block, instead of continuing the loop: for i in 1..5 begin do_something_that_might_raise_exceptions(i) rescue retry # do_something_* again, with same i end end

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  • use boolean value for loop

    - by Leslie
    So technically a boolean is True (1) or False(0)...how can I use a boolean in a loop? so if FYEProcessing is False, run this loop one time, if FYEProcessing is true, run it twice: for (Integer i=0; i<FYEProcessing; ++i){ CreatePaymentRecords(TermDates, FYEProcessing); }

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  • Custom language - FOR loop in a clojure interpeter?

    - by Mark
    I have a basic interpreter in clojure. Now i need to implement for (initialisation; finish-test; loop-update) { statements } Implement a similar for-loop for the interpreted language. The pattern will be: (for variable-declarations end-test loop-update do statement) The variable-declarations will set up initial values for variables.The end-test returns a boolean, and the loop will end if end-test returns false. The statement is interpreted followed by the loop-update for each pass of the loop. Examples of use are: (run ’(for ((i 0)) (< i 10) (set i (+ 1 i)) do (println i))) (run ’(for ((i 0) (j 0)) (< i 10) (seq (set i (+ 1 i)) (set j (+ j (* 2 i)))) do (println j))) inside my interpreter. I will attach my interpreter code I got so far. Any help is appreciated. Interpreter (declare interpret make-env) ;; needed as language terms call out to 'interpret' (def do-trace false) ;; change to 'true' to show calls to 'interpret' ;; simple utilities (def third ; return third item in a list (fn [a-list] (second (rest a-list)))) (def fourth ; return fourth item in a list (fn [a-list] (third (rest a-list)))) (def run ; make it easy to test the interpreter (fn [e] (println "Processing: " e) (println "=> " (interpret e (make-env))))) ;; for the environment (def make-env (fn [] '())) (def add-var (fn [env var val] (cons (list var val) env))) (def lookup-var (fn [env var] (cond (empty? env) 'error (= (first (first env)) var) (second (first env)) :else (lookup-var (rest env) var)))) ;; for terms in language ;; -- define numbers (def is-number? (fn [expn] (number? expn))) (def interpret-number (fn [expn env] expn)) ;; -- define symbols (def is-symbol? (fn [expn] (symbol? expn))) (def interpret-symbol (fn [expn env] (lookup-var env expn))) ;; -- define boolean (def is-boolean? (fn [expn] (or (= expn 'true) (= expn 'false)))) (def interpret-boolean (fn [expn env] expn)) ;; -- define functions (def is-function? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'lambda (first expn))))) (def interpret-function ; keep function definitions as they are written (fn [expn env] expn)) ;; -- define addition (def is-plus? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '+ (first expn))))) (def interpret-plus (fn [expn env] (+ (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define subtraction (def is-minus? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '- (first expn))))) (def interpret-minus (fn [expn env] (- (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define multiplication (def is-times? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '* (first expn))))) (def interpret-times (fn [expn env] (* (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define division (def is-divides? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '/ (first expn))))) (def interpret-divides (fn [expn env] (/ (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define equals test (def is-equals? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '= (first expn))))) (def interpret-equals (fn [expn env] (= (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define greater-than test (def is-greater-than? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '> (first expn))))) (def interpret-greater-than (fn [expn env] (> (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define not (def is-not? (fn [expn] (and (list? expn) (= 2 (count expn)) (= 'not (first expn))))) (def interpret-not (fn [expn env] (not (interpret (second expn) env)))) ;; -- define or (def is-or? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'or (first expn))))) (def interpret-or (fn [expn env] (or (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define and (def is-and? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'and (first expn))))) (def interpret-and (fn [expn env] (and (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define print (def is-print? (fn [expn] (and (list? expn) (= 2 (count expn)) (= 'println (first expn))))) (def interpret-print (fn [expn env] (println (interpret (second expn) env)))) ;; -- define with (def is-with? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'with (first expn))))) (def interpret-with (fn [expn env] (interpret (third expn) (add-var env (first (second expn)) (interpret (second (second expn)) env))))) ;; -- define if (def is-if? (fn [expn] (and (list? expn) (= 4 (count expn)) (= 'if (first expn))))) (def interpret-if (fn [expn env] (cond (interpret (second expn) env) (interpret (third expn) env) :else (interpret (fourth expn) env)))) ;; -- define function-application (def is-function-application? (fn [expn env] (and (list? expn) (= 2 (count expn)) (is-function? (interpret (first expn) env))))) (def interpret-function-application (fn [expn env] (let [function (interpret (first expn) env)] (interpret (third function) (add-var env (first (second function)) (interpret (second expn) env)))))) ;; the interpreter itself (def interpret (fn [expn env] (cond do-trace (println "Interpret is processing: " expn)) (cond ; basic values (is-number? expn) (interpret-number expn env) (is-symbol? expn) (interpret-symbol expn env) (is-boolean? expn) (interpret-boolean expn env) (is-function? expn) (interpret-function expn env) ; built-in functions (is-plus? expn) (interpret-plus expn env) (is-minus? expn) (interpret-minus expn env) (is-times? expn) (interpret-times expn env) (is-divides? expn) (interpret-divides expn env) (is-equals? expn) (interpret-equals expn env) (is-greater-than? expn) (interpret-greater-than expn env) (is-not? expn) (interpret-not expn env) (is-or? expn) (interpret-or expn env) (is-and? expn) (interpret-and expn env) (is-print? expn) (interpret-print expn env) ; special syntax (is-with? expn) (interpret-with expn env) (is-if? expn) (interpret-if expn env) ; functions (is-function-application? expn env) (interpret-function-application expn env) :else 'error))) ;; tests of using environment (println "Environment tests:") (println (add-var (make-env) 'x 1)) (println (add-var (add-var (add-var (make-env) 'x 1) 'y 2) 'x 3)) (println (lookup-var '() 'x)) (println (lookup-var '((x 1)) 'x)) (println (lookup-var '((x 1) (y 2)) 'x)) (println (lookup-var '((x 1) (y 2)) 'y)) (println (lookup-var '((x 3) (y 2) (x 1)) 'x)) ;; examples of using interpreter (println "Interpreter examples:") (run '1) (run '2) (run '(+ 1 2)) (run '(/ (* (+ 4 5) (- 2 4)) 2)) (run '(with (x 1) x)) (run '(with (x 1) (with (y 2) (+ x y)))) (run '(with (x (+ 2 4)) x)) (run 'false) (run '(not false)) (run '(with (x true) (with (y false) (or x y)))) (run '(or (= 3 4) (> 4 3))) (run '(with (x 1) (if (= x 1) 2 3))) (run '(with (x 2) (if (= x 1) 2 3))) (run '((lambda (n) (* 2 n)) 4)) (run '(with (double (lambda (n) (* 2 n))) (double 4))) (run '(with (sum-to (lambda (n) (if (= n 0) 0 (+ n (sum-to (- n 1)))))) (sum-to 100))) (run '(with (x 1) (with (f (lambda (n) (+ n x))) (with (x 2) (println (f 3))))))

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  • lsusb - where device description comes from

    - by tommyk
    For one of my attached USB devices (2773:0104) I see no description in lsusb command output: user@Thinkpad-Laptop:~/binaries$ lsusb Bus 008 Device 002: ID 0a5c:217f Broadcom Corp. Bus 008 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 007 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 002 Device 036: ID 2773:0104 Where USB description is comming from, is it from device driver or is it stored in the hardware itself ?

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  • Loop through a Map with JSTL

    - by Dean
    I'm looking to have JSTL loop through a Map and output the value of the key and it's value. For example I have a Map which can have any number of entries, i'd like to loop through this map using JSTL and output both the key and it's value. I know how to access the value using the key, ${myMap['keystring']}, but how do I access the key?

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  • jQuery loop through data() object

    - by bartclaeys
    Is it possible to loop through a data() object? Suppose this is my code: $('#mydiv').data('bar','lorem'); $('#mydiv').data('foo','ipsum'); $('#mydiv').data('cam','dolores'); How do I loop through this? Can each() be used for this?

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  • Loop over array and set all vars to false or true in javascript

    - by Sixfoot Studio
    Hi All, I need to loop over my array and set all the vars to false or true. I have tried numerous options, none of which are working and it's clearly my lack of javascript syntax knowledge..Please take a look at this: var closeAllCells = [IncomeOpen = "false", RehabOpen = "false", AttendantCareOpen = "false", HomeMaintenanceOpen = "false", DependantCareOpen = "false", IndexationOpen = "false", DeathFuneralOpen = "false", ComprehensiveOpen = "false", CollisionOpen = "false", LiabilityOpen = "false", DCPDOpen = "false"]; So my thinking is that I can just loop over this as follows for (var i=0;i<closeAllCells.length;i++) { closeAllCells[i] = true; // or false if I wished }

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  • Python how to convert this for loop into a while loop

    - by user1690198
    I have this for a for loop which I made I was wondering how I would write so it would work with a while loop. def scrollList(myList): negativeIndices=[] for i in range(0,len(myList)): if myList[i]<0: negativeIndices.append(i) return negativeIndices So far I have this def scrollList2(myList): negativeIndices=[] i= 0 length= len(myList) while i != length: if myList[i]<0: negativeIndices.append(i) i=i+1 return negativeIndices

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  • dynamic naming of UIButtons within a loop - objective-c, iphone sdk

    - by von steiner
    Dear Members, Scholars. As it may seem obvious I am not armed with Objective C knowledge. Levering on other more simple computer languages I am trying to set a dynamic name for a list of buttons generated by a simple loop (as the following code suggest). Simply putting it, I would like to have several UIButtons generated dynamically (within a loop) naming them dynamically, as well as other related functions. button1,button2,button3 etc.. After googling and searching Stackoverlow, I haven't arrived to a clear simple answer, thus my question. - (void)viewDidLoad { // This is not Dynamic, Obviously UIButton *button0 = [UIButton buttonWithType:UIButtonTypeRoundedRect]; [button0 setTitle:@"Button0" forState:UIControlStateNormal]; button0.tag = 0; button0.frame = CGRectMake(0.0, 0.0, 100.0, 100.0); button0.center = CGPointMake(160.0,50.0); [self.view addSubview:button0]; // I can duplication the lines manually in terms of copy them over and over, changing the name and other related functions, but it seems wrong. (I actually know its bad Karma) // The question at hand: // I would like to generate that within a loop // (The following code is wrong) float startPointY = 150.0; // for (int buttonsLoop = 1;buttonsLoop < 11;buttonsLoop++){ NSString *tempButtonName = [NSString stringWithFormat:@"button%i",buttonsLoop]; UIButton tempButtonName = [UIButton buttonWithType:UIButtonTypeRoundedRect]; [tempButtonName setTitle:tempButtonName forState:UIControlStateNormal]; tempButtonName.tag = tempButtonName; tempButtonName.frame = CGRectMake(0.0, 0.0, 100.0, 100.0); tempButtonName.center = CGPointMake(160.0,50.0+startPointY); [self.view addSubview:tempButtonName]; startPointY += 100; } }

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