Search Results

Search found 892 results on 36 pages for 'reg exp'.

Page 6/36 | < Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >

  • Add new types to Go

    - by nevalu
    I'm trying add new types for that been managed/used as in Go core types. To create new types is anything very interesting to validate data before of send it to a non-SQL DBMS or to check data from a form. Go uses univeral constants to define them at global level: var DateType = universe.DefineType("date", universePos, &dateType{}) In this case they're defined to be called from a package like types: var Date = &dateType{} I get these errors: test.go:58: o.lit undefined (cannot refer to unexported field lit) test.go:62: *dateType is not Type missing Pos() token.Position The code is based on: http://github.com/tav/go/blob/master/src/pkg/exp/eval/value.go http://github.com/tav/go/blob/master/src/pkg/exp/eval/type.go package main import ( "exp/eval" "fmt" // "go/token" ) // http://github.com/tav/go/blob/master/src/pkg/exp/eval/value.go type DateValue interface { eval.Value Get(*eval.Thread) string Set(*eval.Thread, string) } /* Date */ type dateV string func (v *dateV) String() string { return fmt.Sprint(*v) } func (v *dateV) Assign(t *eval.Thread, o eval.Value) { *v = dateV(o.(DateValue).Get(t)) } func (v *dateV) Get(*eval.Thread) string { return string(*v) } func (v *dateV) Set(t *eval.Thread, x string) { *v = dateV(x) } // http://github.com/tav/go/blob/master/src/pkg/exp/eval/type.go type Type interface { eval.Type // isDate returns true if this is a date type. isDate() bool } /* Common type */ type commonType struct{} // added func (commonType) isDate() bool { return false } /* Date */ type dateType struct { commonType } // * It should not be an universal constant //var universePos = token.Position{"<universe>", 0, 0, 0} // added //var DateType = universe.DefineType("date", universePos, &dateType{}) var Date = &dateType{} func (t *dateType) compat(o Type, conv bool) bool { t2, ok := o.lit().(*dateType) return ok && t == t2 } func (t *dateType) lit() Type { return t } func (t *dateType) isDate() bool { return true } func (t *dateType) String() string { return "<date>" } func (t *dateType) Zero() eval.Value { res := dateV("") return &res } /* Named types */ /* type NamedType struct { eval.NamedType Def Type }*/ type NamedType struct { // added // token.Position Name string // Underlying type. If incomplete is true, this will be nil. // If incomplete is false and this is still nil, then this is // a placeholder type representing an error. Def Type // True while this type is being defined. incomplete bool methods map[string]eval.Method } func (t *NamedType) isDate() bool { return t.Def.isDate() } /* *********************** */ func main() { print("foo") }

    Read the article

  • Converting F# Quotations into LINQ Expressions

    - by forki23
    Hi, I can convert a quotation of type Expr<'a -> 'b> to a Linq expression via the following snippet: /// Converts a F# Expression to a LINQ Lambda let toLambda (exp:Expr) = let linq = exp.ToLinqExpression() :?> MethodCallExpression linq.Arguments.[0] :?> LambdaExpression /// Converts a Lambda quotation into a Linq Lamba Expression with 1 parameter let ToLinq (exp : Expr<'a -> 'b>) = let lambda = toLambda exp Expression.Lambda<Func<'a, 'b>>(lambda.Body, lambda.Parameters) Now I want to convert a quotation of type Expr<'a * 'b -> 'c> or maybe even Expr<'a -> 'b -> 'c> to a Linq Lambda Expression of type Expression<Func<'a,'b'c>>. How can I do this? Regards, forki

    Read the article

  • Generating lognormally distributed random number from mean, coeff of variation

    - by Richie Cotton
    Most functions for generating lognormally distributed random numbers take the mean and standard deviation of the associated normal distribution as parameters. My problem is that I only know the mean and the coefficient of variation of the lognormal distribution. It is reasonably straight forward to derive the parameters I need for the standard functions from what I have: If mu and sigma are the mean and standard deviation of the associated normal distribution, we know that coeffOfVar^2 = variance / mean^2 = (exp(sigma^2) - 1) * exp(2*mu + sigma^2) / exp(mu + sigma^2/2)^2 = exp(sigma^2) - 1 We can rearrange this to sigma = sqrt(log(coeffOfVar^2 + 1)) We also know that mean = exp(mu + sigma^2/2) This rearranges to mu = log(mean) - sigma^2/2 Here's my R implementation rlnorm0 <- function(mean, coeffOfVar, n = 1e6) { sigma <- sqrt(log(coeffOfVar^2 + 1)) mu <- log(mean) - sigma^2 / 2 rlnorm(n, mu, sigma) } It works okay for small coefficients of variation r1 <- rlnorm0(2, 0.5) mean(r1) # 2.000095 sd(r1) / mean(r1) # 0.4998437 But not for larger values r2 <- rlnorm0(2, 50) mean(r2) # 2.048509 sd(r2) / mean(r2) # 68.55871 To check that it wasn't an R-specific issue, I reimplemented it in MATLAB. (Uses stats toolbox.) function y = lognrnd0(mean, coeffOfVar, sizeOut) if nargin < 3 || isempty(sizeOut) sizeOut = [1e6 1]; end sigma = sqrt(log(coeffOfVar.^2 + 1)); mu = log(mean) - sigma.^2 ./ 2; y = lognrnd(mu, sigma, sizeOut); end r1 = lognrnd0(2, 0.5); mean(r1) % 2.0013 std(r1) ./ mean(r1) % 0.5008 r2 = lognrnd0(2, 50); mean(r2) % 1.9611 std(r2) ./ mean(r2) % 22.61 Same problem. The question is, why is this happening? Is it just that the standard deviation is not robust when the variation is that wide? Or have a screwed up somewhere?

    Read the article

  • Model Fit of Binary GLM with more than 1 or 2 predictors

    - by Salmo salar
    I am trying to predict a binary GLM with multiple predictors. I can do it fine with one predictor variable however struggle when I use multiple Sample data: structure(list(attempt = structure(c(1L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 2L), .Label = c("1", "2"), class = "factor"), searchtime = c(137, 90, 164, 32, 39, 30, 197, 308, 172, 48, 867, 117, 63, 1345, 38, 122, 226, 397, 0, 106, 259, 220, 170, 102, 46, 327, 8, 10, 23, 108, 315, 318, 70, 646, 69, 97, 117, 45, 31, 64, 125, 17, 240, 63, 549, 1651, 233, 406, 334, 168, 127, 47, 881), mean.search.flow = c(15.97766667, 14.226, 17.15724762, 14.7465, 39.579, 23.355, 110.2926923, 71.95709524, 72.73666667, 32.37466667, 50.34905172, 27.98471429, 49.244, 109.1759778, 77.71733333, 37.446875, 101.23875, 67.78534615, 21.359, 36.54257143, 34.13961111, 64.35253333, 80.98554545, 61.50857143, 48.983, 63.81072727, 26.105, 46.783, 23.0605, 33.61557143, 46.31042857, 62.37061905, 12.565, 42.31983721, 15.3982, 14.49625, 23.77425, 25.626, 74.62485714, 170.1547778, 50.67125, 48.098, 66.83644444, 76.564875, 80.63189189, 136.0573243, 136.3484, 86.68688889, 34.82169565, 70.00415385, 64.67233333, 81.72766667, 57.74522034), Pass = structure(c(1L, 2L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 1L, 2L), .Label = c("0", "1"), class = "factor")), .Names = c("attempt", "searchtime", "mean.search.flow", "Pass"), class = "data.frame", row.names = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 28L, 29L, 30L, 31L, 32L, 33L, 34L, 35L, 36L, 37L, 38L, 39L, 40L, 50L, 51L, 53L, 54L, 60L, 61L, 62L, 63L, 64L, 65L, 66L, 67L, 68L, 69L, 70L, 71L, 72L)) First model with single predictor M2 <- glm(Pass ~ searchtime, data = DF3, family = binomial) summary(M2) drop1(M2, test = "Chi") Plot works fine P1 <- predict(M2, newdata = MyData, type = "link", se = TRUE) plot(x=MyData$searchtime, exp(P1$fit) / (1+exp(P1$fit)), type = "l", ylim = c(0,1), xlab = "search time", ylab = "pobability of passage") lines(MyData$searchtime, exp(P1$fit+1.96*P1$se.fit)/ (1 + exp(P1$fit + 1.96 * P1$se.fit)), lty = 2) lines(MyData$searchtime, exp(P1$fit-1.96*P1$se.fit)/ (1 + exp(P1$fit - 1.96 * P1$se.fit)), lty = 2) points(DF3$searchtime, DF3$Search.and.pass) Second model M2a <- glm(Pass ~ searchtime + mean.search.flow+ attempt, data = DF3, family = binomial) summary(M2a) drop1(M2a, test = "Chi") How do I plot this with "dummy" data? I have tried along the lines of Model.matrix and expand.grid, as you would do with glmer, but fail straight away due to the two categorical variables along with factor(attempt)

    Read the article

  • Peak decomposition

    - by midtiby
    Hi I want to examine a NMR spectre and make the best fit of a specific peak using a sum of gaussians. With the following code it is possible to fit two gaussians to the peak, but can it easily be generalized to n gaussians? freq <- seq(100, 200, 0.1) signal <- 3.5*exp(-(freq-130)^2/50) + 0.2 + 1.5*exp(-(freq-120)^2/10) simsignal <- rpois(length(signal), 100*signal) + rnorm(length(signal)) plot(freq, simsignal) res <- nls(simsignal ~ bg + h1 * exp(-((freq - m1)/s1)^2) + h2 * exp(-((freq - m2)/s2)^2), start=c(bg = 4, h1 = 300, m1 = 128, s1 = 6, h2 = 200, m2 = 122, s2 = 4), trace=T) lines(freq, predict(res, freq), col='red') Another wish is a visulization of the contribution from each of the gaussians to the original peak, eg. the gaussians should be plotted side by side (instead of plotting their sum as done above).

    Read the article

  • vba excel: do something every time a certain variable is changed

    - by every_answer_gets_a_point
    im doing a bunch of stuff to the variable St For i = 1 To 30000 Randomize e1 = Rnd e2 = Rnd z1 = Sqr(-2 * Log(e1)) * Cos(2 * 3.14 * e2) z2 = Sqr(-2 * Log(e1)) * Sin(2 * 3.14 * e2) St = So * Exp((r - (sigma ^ 2) / 2) * T + sigma * Sqr(T) * z1) C = C + Application.WorksheetFunction.Max(St - K, 0) St = So * Exp((r - (sigma ^ 2) / 2) * T - sigma * Sqr(T) * z1) C = C + Application.WorksheetFunction.Max(St - K, 0) St = So * Exp((r - (sigma ^ 2) / 2) * T + sigma * Sqr(T) * z2) C = C + Application.WorksheetFunction.Max(St - K, 0) St = So * Exp((r - (sigma ^ 2) / 2) * T - sigma * Sqr(T) * z2) C = C + Application.WorksheetFunction.Max(St - K, 0) Next i how do i get notified every time the variable changes?

    Read the article

  • Python unittest: Generate multiple tests programmatically?

    - by Rosarch
    I have a function to test, under_test, and a set of expected input/output pairs: [ (2, 332), (234, 99213), (9, 3), # ... ] I would like each one of these input/output pairs to be tested in its own test_* method. Is that possible? This is sort of what I want, but forcing every single input/output pair into a single test: class TestPreReqs(unittest.TestCase): def setUp(self): self.expected_pairs = [(23, 55), (4, 32)] def test_expected(self): for exp in self.expected_pairs: self.assertEqual(under_test(exp[0]), exp[1]) if __name__ == '__main__': unittest.main()

    Read the article

  • Using list() to extract a data.table inside of a function

    - by Nathan VanHoudnos
    I must admit that the data.table J syntax confuses me. I am attempting to use list() to extract a subset of a data.table as a data.table object as described in Section 1.4 of the data.table FAQ, but I can't get this behavior to work inside of a function. An example: require(data.table) ## Setup some test data set.seed(1) test.data <- data.table( X = rnorm(10), Y = rnorm(10), Z = rnorm(10) ) setkey(test.data, X) ## Notice that I can subset the data table easily with literal names test.data[, list(X,Y)] ## X Y ## 1: -0.8356286 -0.62124058 ## 2: -0.8204684 -0.04493361 ## 3: -0.6264538 1.51178117 ## 4: -0.3053884 0.59390132 ## 5: 0.1836433 0.38984324 ## 6: 0.3295078 1.12493092 ## 7: 0.4874291 -0.01619026 ## 8: 0.5757814 0.82122120 ## 9: 0.7383247 0.94383621 ## 10: 1.5952808 -2.21469989 I can even write a function that will return a column of the data.table as a vector when passed the name of a column as a character vector: get.a.vector <- function( my.dt, my.column ) { ## Step 1: Convert my.column to an expression column.exp <- parse(text=my.column) ## Step 2: Return the vector return( my.dt[, eval(column.exp)] ) } get.a.vector( test.data, 'X') ## [1] -0.8356286 -0.8204684 -0.6264538 -0.3053884 0.1836433 0.3295078 ## [7] 0.4874291 0.5757814 0.7383247 1.5952808 But I cannot pull a similar trick for list(). The inline comments are the output from the interactive browser() session. get.a.dt <- function( my.dt, my.column ) { ## Step 1: Convert my.column to an expression column.exp <- parse(text=my.column) ## Step 2: Enter the browser to play around browser() ## Step 3: Verity that a literal X works: my.dt[, list(X)] ## << not shown >> ## Step 4: Attempt to evaluate the parsed experssion my.dt[, list( eval(column.exp)] ## Error in `rownames<-`(`*tmp*`, value = paste(format(rn, right = TRUE), (from data.table.example.R@1032mCJ#7) : ## length of 'dimnames' [1] not equal to array extent return( my.dt[, list(eval(column.exp))] ) } get.a.dt( test.data, "X" ) What am I missing? Update: Due to some confusion as to why I would want to do this I wanted to clarify. My use case is when I need to access a data.table column when when I generate the name. Something like this: set.seed(2) test.data[, X.1 := rnorm(10)] which.column <- 'X' new.column <- paste(which.column, '.1', sep="") get.a.dt( test.data, new.column ) Hopefully that helps.

    Read the article

  • Oracle export problem

    - by Abhiram
    I use exp username/password@servername owner={ownername} file=backuppath; The parameters given are correct but still not able to connect Below is the error trace: EXP-00056: ORACLE error 12545 encountered ORA-12545: Connect failed because target host or object does not exist EXP-00000: Export terminated unsuccessfully What can be the possible reasons?

    Read the article

  • A Rose by Any Other Name..

    - by Geoff N. Hiten
    It is always a good start when you can steal a title line from one of the best writers in the English language.  Let’s hope I can make the rest of this post live up to the opening.  One recurring problem with SQL server is moving databases to new servers.  Client applications use a variety of ways to resolve SQL Server names, some of which are not changed easily <cough SharePoint /cough>.  If you happen to be using default instances on both the source and target SQL Server, then the solution is pretty simple.  You create (or bug the network admin until she creates) two DNS “A” records. One points the old name to the new IP address.  The other creates a new alias for the old server, since the original system name is now redirected.  Note this will redirect ALL traffic from the old server to the new server, including RDP and file share connection attempts.    Figure 1 – Microsoft DNS MMC Snap-In   Figure 2 – DNS New Host Dialog Box Both records are necessary so you can still access the old server via an alternate name. Server Role IP Address Name Alias Source 10.97.230.60 SQL01 SQL01_Old Target 10.97.230.80 SQL02 SQL01 Table 1 – Alias List If you or somebody set up connections via IP address, you deserve to have to go to each app and fix it by hand.  That is the only way to fix that particular foul-up. If have to deal with Named Instances either as a source or a target, then it gets more complicated.  The standard fix is to use the SQL Server Configuration Manager (or one of its earlier incarnations) to create a SQL client alias to redirect the connection.  This can be a pain installing and configuring the app on multiple client servers.  The good news is that SQL Server Configuration Manager AND all of its earlier versions simply write a few registry keys.  Extracting the keys into a .reg file makes centralized automated deployment a snap. If the client is a 32-bit system, you have to extract the native key.  If it is a 64-bit, you have to extract the native key and the WoW (32 bit on 64 bit host) key. First, pick a development system to create the actual registry key.  If you do this repeatedly, you can simply edit an existing registry file.  Create the entry using the SQL Configuration Manager.  You must use a 64-bit system to create the WoW key.  The following example redirects from a named instance “SQL01\SQLUtiluty” to a default instance on “SQL02”.   Figure 3 – SQL Server Configuration Manager - Native Figure 3 shows the native key listing. Figure 4 – SQL Server Configuration Manager – WoW If you think you don’t need the WoW key because your app is 64 it, think again.  SQL Server Management Server is a 32-bit app, as are most SQL test utilities.  Always create both keys for 64-bit target systems. Now that the keys exist, we can extract them into a .reg file. Fire up REGEDIT and browse to the following location:  HKLM\Software\Microsoft\MSSQLServer\Client\ConnectTo.  You can also search the registry for the string value of one of the server names (old or new). Right click on the “ConnectTo” label and choose “Export”.  Save with an appropriate name and location.  The resulting file should look something like this: Figure 5 – SQL01_Alias.reg Repeat the process with the location: HKLM\Software\Wow6432Node\Microsoft\MSSQLServer\Client\ConnectTo Note that if you have multiple alias entries, ALL of the entries will be exported.  In that case, you can edit the file and remove the extra aliases. You can edit the files together into a single file.  Just leave a blank line between new keys like this: Figure 6 – SQL01_Alias_All.reg Of course if you have an automatic way to deploy, it makes sense to have an automatic way to Un-deploy.  To delete a registry key, simply edit the .reg file and replace the target with a “-“ sign like so. Figure 7 – SQL01_Alias_UNDO.reg Now we have the ability to move any database to any server without having to install or change any applications on any client server.  The whole process should be transparent to the applications, which makes planning and coordinating database moves a far simpler task.

    Read the article

  • How to prevent a hacked-server from spoofing a master server?

    - by Cody Smith
    I wish to setup a room-based multilayer game model where players may host matches and serve as host (IE the server with authoritative power). I wish to host a master server which tracks player's items, rank, cash, exp, etc. In such a model, how can I prevent someone that is hosting a game (with a modified server) from spoofing the master server with invalid match results, thus gaining exp, money or rankings. Thanks. -Cody

    Read the article

  • How to Restore the Real Internet Explorer Desktop Icon in Windows 7

    - by The Geek
    Remember how previous versions of Windows had an Internet Explorer icon on the desktop, and you could right-click it to quickly access the Internet Options screen? It’s completely gone in Windows 7, but a geeky hack can bring it back. Microsoft removed this feature to comply with all those murky legal battles they’ve had, and their alternate suggestion is to create a standard shortcut to iexplore.exe on the Desktop, but it’s not the same thing. We’ve got a registry hack to bring it back. This guest article was written by Ramesh from the WinHelpOnline blog, where he’s got loads of really geeky registry hacks. Bring Back the Internet Explorer Namespace Icon in Windows 7 the Easy Way If you just want the IE icon back, all you need to do is download the RealInternetExplorerIcon.zip file, extract the contents, and then double-click on the w7_ie_icon_restore.reg file. That’s all you have to do. There’s also an undo registry file there if you want to get rid of it. Download the Real Internet Explorer Icon Registry Hack Manual Registry Hack If you prefer doing things the manual way, or just really want to understand how this hack works, you can follow through the manual steps below to learn how it was done, but we’ll have to warn you that it’s a lot of steps. Launch Regedit.exe using the Start Menu search box, and then navigate to the following location: HKEY_CLASSES_ROOT \ CLSID \ {871C5380-42A0-1069-A2EA-08002B30309D} Right-click on the key on the left-hand pane, choose Export, and save it to a .REG file (say, ie-guid.reg) Open up the REG file using Notepad… From the Edit menu, click Replace, and replace every occurrence of the following GUID string {871C5380-42A0-1069-A2EA-08002B30309D} … with a custom GUID string, such as: {871C5380-42A0-1069-A2EA-08002B30301D} Save the REG file and close Notepad, and then double-click on the file to merge the contents to the registry. Either re-open the registry editor, or use the F5 key to reload everything with the new changes (this step is important). Now you can navigate downto the following registry key: HKEY_CLASSES_ROOT \ CLSID \ {871C5380-42A0-1069-A2EA-08002B30301D} \ Shellex \ ContextMenuHandlers \ ieframe Double-click on the (default) key in the right-hand pane and set its data as: {871C5380-42A0-1069-A2EA-08002B30309D} With this done, press F5 on the desktop and you’ll see the Internet Explorer icon that looks like this: The icon appears incomplete without the Properties command in right click menu, so keep reading. Final Registry Hack Adjustments Click on the following key, which should still be viewable in your Registry editor window from the last step. HKEY_CLASSES_ROOT\CLSID\{871C5380-42A0-1069-A2EA-08002B30301D} Double-click LocalizedString in the right-hand pane and type the following data to rename the icon. Internet Explorer Select the following key: HKEY_CLASSES_ROOT\CLSID\{871C5380-42A0-1069-A2EA-08002B30301D}\shell Add a subkey and name it as Properties, then select the Properties key, double-click the (default) value and type the following: P&roperties Create a String value named Position, and type the following data bottom At this point the window should look something like this: Under Properties, create a subkey and name it as Command, and then set its (default) value as follows: control.exe inetcpl.cpl Navigate down to the following key, and then delete the value named LegacyDisable HKEY_CLASSES_ROOT \ CLSID \ {871C5380-42A0-1069-A2EA-08002B30301D} \ shell \ OpenHomePage Now head to the this key: HKEY_LOCAL_MACHINE \ SOFTWARE \ Microsoft \ Windows \ CurrentVersion \ Explorer \ Desktop \ NameSpace Create a subkey named {871C5380-42A0-1069-A2EA-08002B30301D} (which is the custom GUID that we used earlier in this article.) Press F5 to refresh the Desktop, and here is how the Internet Explorer icon would look like, finally. That’s it! It only took 24 steps, but you made it through to the end—of course, you could just download the registry hack and get the icon back with a double-click. Similar Articles Productive Geek Tips Quick Help: Restore Show Desktop Icon in Windows VistaQuick Help: Restore Flip3D Icon in Windows VistaAdd Internet Explorer Icon to Windows XP / Vista DesktopHide, Delete, or Destroy the Recycle Bin Icon in Windows 7 or VistaBuilt-in Quick Launch Hotkeys in Windows Vista TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Looking for Good Windows Media Player 12 Plug-ins? Find Out the Celebrity You Resemble With FaceDouble Whoa ! Use Printflush to Solve Printing Problems Icelandic Volcano Webcams Open Multiple Links At One Go

    Read the article

  • Error when trying to create a faceted plot in ggplot2

    - by John Horton
    I am trying to make a faceted plot in ggplot2 of the coefficients on the regressors from two linear models with the same predictors. The data frame I constructed is this: r.together> reg coef se y 1 (Intercept) 5.068608671 0.6990873 Labels 2 goodTRUE 0.310575129 0.5228815 Labels 3 indiaTRUE -1.196868662 0.5192330 Labels 4 moneyTRUE -0.586451273 0.6011257 Labels 5 maleTRUE -0.157618168 0.5332040 Labels 6 (Intercept) 4.225580743 0.6010509 Bonus 7 goodTRUE 1.272760149 0.4524954 Bonus 8 indiaTRUE -0.829588862 0.4492838 Bonus 9 moneyTRUE -0.003571476 0.5175601 Bonus 10 maleTRUE 0.977011737 0.4602726 Bonus The "y" column is a label for the model, reg are the regressors and coef and se are what you would think. I want to plot: g <- qplot(reg, coef, facets=.~y, data = r.together) + coord_flip() But when I try to display the plot, I get: > print(g) Error in names(df) <- output : 'names' attribute [2] must be the same length as the vector [1] What's strange is that qplot(reg, coef, colour=y, data = r.together) + coord_flip() plots as you would expect.

    Read the article

  • Is there a way to pass another parameter in the preg_replace_callback callback function?

    - by DaNieL
    mmmh guys, i really hope my english is good enaught to explain what i need. Lets take this example (that is just an example!) of code: class Something(){ public function Lower($string){ return strtolower($string); } } class Foo{ public $something; public $reg; public $string; public function __construct($reg, $string, $something){ $this->something = $something; $this->reg = $reg; $this->string = $string; } public function Replace(){ return preg_replace_callback($this->reg, 'Foo::Bar', $this->string); } public static function Bar($matches){ /* * [...] * do something with $matches and create the $output variable * [...] */ /* * I know is really useless in this example, but i need to have an istance to an object here * (in this example, the Something object, but can be something else!) */ return $this->something->Lower($output); } } $s = new Something(); $foo = new Foo($myregexp, $mystring, $s); $content = $foo->Replace(); So, the php manual say that to use a class method as callback in preg_replace_callback(), the method must be abstract. I need to pass an instance of a previuosly initialized object (in the example, an instance of the Something class) at the callback function. I tryed to use call_user_func(), but doesnt work (becose in this way i miss the matches parameter). Is there a way to do that, or have i to separate the process (doing before preg_match_all, for each match retrieve the replace value, and then a simple preg_replace)?

    Read the article

  • python to display the special characters

    - by Suhail
    Hi, I am facing issues with the special characters like ° and ® which represent the degreee Farenheit sign and the ® represent the registered sign, when i print the string the contains the special characters, it gives output like this: Preheat oven to 350&deg F Welcome to Lorem Ipsum Inc&reg is there a way i can output the exact characters and not their codes ? please let me know.

    Read the article

  • POST request from Python to PHP

    - by RainbowHat
    Python params = urllib.parse.urlencode({'spam': '1', 'eggs': '2', 'bacon': '3'}) binary_data = params.encode('utf-8') reg = urllib.request.Request("http://www.abc.com/abc/smart/ap/request/",binary_data) reg.add_header('Content-Type','application/x-www-form-urlencoded') f = urllib.request.urlopen(reg) print(f.read()) PHP if($_SERVER['REQUEST_METHOD'] == 'POST') { //parse_str($_SERVER['QUERY_STRING']); var_dump($_SERVER['QUERY_STRING']); } When i try print binary_data , it does show the parameter but by the time it reaches the PHP , i see nothing. Any idea?

    Read the article

  • question about prefix and suffix in java

    - by kate
    hi!!I have an issue and i want your help!I have a specific REGEX which i have named it "unique" and i want to store the data that it gives me!! The prefix and the suffix of this regex!!so!!someone has told me to use var prefix and var suffix but i don't know how to do it! for your convinience i give u my xml for this regex <reg name="unique"> <start><![CDATA[ <!-- 72 HOURS FORECASTS --> ]]></start> <end><![CDATA[<!-- 72 HOURS FORECASTS -->]]></end> </reg> the code where i call this regex is int k = 0; for(Xml reg_is:fetchsite.child("site").child("regexps").children("reg")) { if(reg_is.string("name").contains("unique")){ if(reg_is.child("start").content()=="") error += "\tNo prefix reg.exp. given.\n"; else prefix = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("start").content())); if(reg_is.child("end").content()=="") error += "\tNo suffix reg.exp. given.\n"; else suffix = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("end").content())); } else{ poleis[k][0]= HtmlMethods.removeBreaks(reg_is.string("name")); poleis[k][1] = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("start").content())); poleis[k][2] = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("end").content())); k++; }

    Read the article

  • Matlab: Optimization by perturbing variable

    - by S_H
    My main script contains following code: %# Grid and model parameters nModel=50; nModel_want=1; nI_grid1=5; Nth=1; nRow.Scale1=5; nCol.Scale1=5; nRow.Scale2=5^2; nCol.Scale2=5^2; theta = 90; % degrees a_minor = 2; % range along minor direction a_major = 5; % range along major direction sill = var(reshape(Deff_matrix_NthModel,nCell.Scale1,1)); % variance of the coarse data matrix of size nRow.Scale1 X nCol.Scale1 %# Covariance computation % Scale 1 for ihRow = 1:nRow.Scale1 for ihCol = 1:nCol.Scale1 [cov.Scale1(ihRow,ihCol),heff.Scale1(ihRow,ihCol)] = general_CovModel(theta, ihCol, ihRow, a_minor, a_major, sill, 'Exp'); end end % Scale 2 for ihRow = 1:nRow.Scale2 for ihCol = 1:nCol.Scale2 [cov.Scale2(ihRow,ihCol),heff.Scale2(ihRow,ihCol)] = general_CovModel(theta, ihCol/(nCol.Scale2/nCol.Scale1), ihRow/(nRow.Scale2/nRow.Scale1), a_minor, a_major, sill/(nRow.Scale2*nCol.Scale2), 'Exp'); end end %# Scale-up of fine scale values by averaging [covAvg.Scale2,var_covAvg.Scale2,varNorm_covAvg.Scale2] = general_AverageProperty(nRow.Scale2/nRow.Scale1,nCol.Scale2/nCol.Scale1,1,nRow.Scale1,nCol.Scale1,1,cov.Scale2,1); I am using two functions, general_CovModel() and general_AverageProperty(), in my main script which are given as following: function [cov,h_eff] = general_CovModel(theta, hx, hy, a_minor, a_major, sill, mod_type) % mod_type should be in strings angle_rad = theta*(pi/180); % theta in degrees, angle_rad in radians R_theta = [sin(angle_rad) cos(angle_rad); -cos(angle_rad) sin(angle_rad)]; h = [hx; hy]; lambda = a_minor/a_major; D_lambda = [lambda 0; 0 1]; h_2prime = D_lambda*R_theta*h; h_eff = sqrt((h_2prime(1)^2)+(h_2prime(2)^2)); if strcmp(mod_type,'Sph')==1 || strcmp(mod_type,'sph') ==1 if h_eff<=a cov = sill - sill.*(1.5*(h_eff/a_minor)-0.5*((h_eff/a_minor)^3)); else cov = sill; end elseif strcmp(mod_type,'Exp')==1 || strcmp(mod_type,'exp') ==1 cov = sill-(sill.*(1-exp(-(3*h_eff)/a_minor))); elseif strcmp(mod_type,'Gauss')==1 || strcmp(mod_type,'gauss') ==1 cov = sill-(sill.*(1-exp(-((3*h_eff)^2/(a_minor^2))))); end and function [PropertyAvg,variance_PropertyAvg,NormVariance_PropertyAvg]=... general_AverageProperty(blocksize_row,blocksize_col,blocksize_t,... nUpscaledRow,nUpscaledCol,nUpscaledT,PropertyArray,omega) % This function computes average of a property and variance of that averaged % property using power averaging PropertyAvg=zeros(nUpscaledRow,nUpscaledCol,nUpscaledT); %# Average of property for k=1:nUpscaledT, for j=1:nUpscaledCol, for i=1:nUpscaledRow, sum=0; for a=1:blocksize_row, for b=1:blocksize_col, for c=1:blocksize_t, sum=sum+(PropertyArray((i-1)*blocksize_row+a,(j-1)*blocksize_col+b,(k-1)*blocksize_t+c).^omega); % add all the property values in 'blocksize_x','blocksize_y','blocksize_t' to one variable end end end PropertyAvg(i,j,k)=(sum/(blocksize_row*blocksize_col*blocksize_t)).^(1/omega); % take average of the summed property end end end %# Variance of averageed property variance_PropertyAvg=var(reshape(PropertyAvg,... nUpscaledRow*nUpscaledCol*nUpscaledT,1),1,1); %# Normalized variance of averageed property NormVariance_PropertyAvg=variance_PropertyAvg./(var(reshape(... PropertyArray,numel(PropertyArray),1),1,1)); Question: Using Matlab, I would like to optimize covAvg.Scale2 such that it matches closely with cov.Scale1 by perturbing/varying any (or all) of the following variables 1) a_minor 2) a_major 3) theta Thanks.

    Read the article

  • Constructive criticsm on my linear sampling Gaussian blur

    - by Aequitas
    I've been attempting to implement a gaussian blur utilising linear sampling, I've come across a few articles presented on the web and a question posed here which dealt with the topic. I've now attempted to implement my own Gaussian function and pixel shader drawing reference from these articles. This is how I'm currently calculating my weights and offsets: int support = int(sigma * 3.0) weights.push_back(exp(-(0*0)/(2*sigma*sigma))/(sqrt(2*pi)*sigma)); total += weights.back(); offsets.push_back(0); for (int i = 1; i <= support; i++) { float w1 = exp(-(i*i)/(2*sigma*sigma))/(sqrt(2*pi)*sigma); float w2 = exp(-((i+1)*(i+1))/(2*sigma*sigma))/(sqrt(2*pi)*sigma); weights.push_back(w1 + w2); total += 2.0f * weights[i]; offsets.push_back(w1 / weights[i]); } for (int i = 0; i < support; i++) { weights[i] /= total; } Here is an example of my vertical pixel shader: vec3 acc = texture2D(tex_object, v_tex_coord.st).rgb*weights[0]; vec2 pixel_size = vec2(1.0 / tex_size.x, 1.0 / tex_size.y); for (int i = 1; i < NUM_SAMPLES; i++) { acc += texture2D(tex_object, (v_tex_coord.st+(vec2(0.0, offsets[i])*pixel_size))).rgb*weights[i]; acc += texture2D(tex_object, (v_tex_coord.st-(vec2(0.0, offsets[i])*pixel_size))).rgb*weights[i]; } gl_FragColor = vec4(acc, 1.0); Am I taking the correct route with this? Any criticism or potential tips to improving my method would be much appreciated.

    Read the article

  • Need Help Accessing the Vista Wampserver localhost from Virtual PC 2007 running an XP VM.

    - by Reg
    (I had posted this on stack overflow but it was suggested there that I post it here instead). I have a Vista laptop on which I'm running wampserver. I have Virtual PC 2007 setup with Windows XP running on the VM. My goal is to be able to use the XP VM to run IE6 to view the localhost in the Vista wampserver. I'm not interested in having the XP VM have any access to the internet -- only to my Vista wampserver's localhost. The vista wampserver works fine. As suggested on a blog I read, I installed the loopback adapter on Vista and I set the loopback to 192.168.21.1 and I set the xp vm ip to 192.168.21.2. I am able to successfully ping the vista-loopback adapter from the xp vm. I've turned the wampserver to "server online", and I've disabled the firewalls in both the vista host and the xp vm. But for some reason, I still can't seem to get the virtual XP to see the localhost on the vista wampserver. I've tried using the vista //name, and I've tried the ip 192.168.21.1 directly and with the port. For whatever its worth, I'm not able to see anything under the XM VM's network places (though I don't know if I'm supposed to be able to see anything). So at this point I'm stuck and I'm still not sure how to get this XP VM to "talk" to my vista wampserver localhost. Any advice on how to fix this problem is much appreciated. Thanks in advance for your help. -R

    Read the article

  • Beginners security question

    - by Reg H
    Hi everyone, I'm still pretty new to web development, and have a question about security. Every day I look at the "Latest Visitors" in my CPanel, and today there were some strange entries (one is pasted below). Not knowing any better, it looks to me like there is some site that's referring users to my site, for some reason. Can someone explain what these really are, and if it's something to be concerned about? Thanks! Host: 77.68.38.175 /?p=http://teen-37.net/myid.jpg? Http Code: 404 Date: Feb 17 08:13:58 Http Version: HTTP/1.1 Size in Bytes: - Referer: - Agent: libwww-perl/5.805 * /?p=../../../../../../../../../../../../../../../proc/self/environ%00 Http Code: 404 Date: Feb 17 08:13:59 Http Version: HTTP/1.1 Size in Bytes: - Referer: - Agent: libwww-perl/5.805

    Read the article

  • Is there a way to make IETab always open a site in Internet Explorer?

    - by reg
    Hello, IETab offers a setting that lets you define sites that should always be opened using IE's rendering engine. This is great and I use it all the time. There are a few sites, though, with which I encounter problems when I access them this way (needless to say that these have some IE-only features, otherwise I would simply use Firefox without IETab). So my question is: is there a way to make IETab (or any other extension that does the same thing) automatically open a specific list of sites in IE? To be clear: I want a way to specify a list of sites that will open an external IE process from Firefox, when clicking on those links or bookmarks from within Firefox.

    Read the article

  • Unable to browse one server unless using FQDN all others work.

    - by Reg
    Hello - I installed 4 new Windows 2008 R2 Servers. All are joined to the domain. One out of the four will not browse to our DC without using a FQDN. I can ping the DC server and see it in Network neighborhood but when I click on it I get Windows cannot access \SERVER. BUT accessing it by using \server.domain works fine. It is only having problems with the one DC server. Able to browse every other server with UNC without using FQDN.This is the only machine on our domain that is experiencing the problem and have tried different user accounts.

    Read the article

  • JQuery and PHP display problem

    - by TheCREATOR
    I'm new to JQuery but for some reason I cant get the php code to display correctly when I put it in my JQuery script. The php code will display correctly when its not in the JQuery code can someone help me fix my JQuery code so it will display my PHP code correctly? Here is the JQuery and PHP code. var count = 0; $(function(){ $('p#add_field').click(function(){ count += 1; $('#container').append( '<input type="text" name="sk" id="sk" />' + '<label for="exp">Exp: </label>' + '<?php' + 'echo \'<select id="exp" name="exp">\' . "\n";' + 'foreach($options as $option) {' + 'if ($option == $exp) {' + 'echo \'<option value="\' . stripslashes(htmlentities(strip_tags($option))) . \'" selected="selected">\' .' + ' stripslashes(htmlentities(strip_tags($option))) . \'</option>\' . "\n";' + '} else {' + 'echo \'<option value="\'. stripslashes(htmlentities(strip_tags($option))) . \'">\' .' + 'stripslashes(htmlentities(strip_tags($option))) . \'</option>\'."\n";' + '}' + '}' + 'echo \'</select>\';' + '?>' + '<label for="g">RGB: </label>' + '<?php' + 'echo \'<select id="g" name="g">\' . "\n";' + 'foreach($options as $option) {' + 'if ($option == $g) {' + 'echo \'<option value="\' . stripslashes(htmlentities(strip_tags($option))) . \'" selected="selected">\' .' + 'stripslashes(htmlentities(strip_tags($option))) . \'</option>\' . "\n";' + '} else {' + 'echo \'<option value="\'. stripslashes(htmlentities(strip_tags($option))) . \'">\' .' + 'stripslashes(htmlentities(strip_tags($option))) . \'</option>\'."\n";' + '}' + '}' + 'echo \'</select>\';' + '?></li>' ); }); });

    Read the article

  • Encountering NullPointerException when trying to add polynoms

    - by Ayler Cruz
    I need to add two polynomials, which is composed of two ints. For example, the coefficient and the exponent 3x^2 would be constructed using 3 and 2 as parameters. I am getting a NullPointerException but I can't figure out why. Any help would be appreciated! public class Polynomial { private Node poly; public Polynomial() { } private Polynomial(Node p) { poly = p; } private class Term { int coefficient; int exponent; private Term(int coefficient, int exponent) { this.coefficient = coefficient; this.exponent = exponent; } } private class Node { private Term data; private Node next; private Node(Term data, Node next) { this.data = data; this.next = next; } } public void addTerm(int coeff, int exp) { Node pointer = poly; if (pointer.next == null) { poly.next = new Node(new Term(coeff, exp), null); } else { while (pointer.next != null) { if (pointer.next.data.exponent < exp) { Node temp = new Node(new Term(coeff, exp), pointer.next.next); pointer.next = temp; return; } pointer = pointer.next; } pointer.next = new Node(new Term(coeff, exp), null); } } public Polynomial polyAdd(Polynomial p) { return new Polynomial(polyAdd(this.poly, p.poly)); } private Node polyAdd(Node p1, Node p2) { if (p1 == p2) { Term adding = new Term(p1.data.coefficient + p2.data.coefficient, p1.data.exponent); p1 = p1.next; p2 = p2.next; return new Node(adding, null); } if (p1.data.exponent > p2.data.exponent) { p2 = p2.next; } if (p1.data.exponent < p2.data.exponent) { p1 = p1.next; } if (p1.next != null && p2.next != null) { return polyAdd(p1, p2); } return new Node(null, null); } }

    Read the article

< Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >