Search Results

Search found 20386 results on 816 pages for 'split button'.

Page 6/816 | < Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >

  • Hide the built-in Send button in Outlook 2003

    - by Raheem
    I am using ms-outlook 2003, i want to hide the built-in send button and use the custom button to send the mail. As i have worked on C,C++ and on Java, dont know how to work on VB/VBScript/VBA, can any body tell me how to hide this button and also how to send mail from custom button, how to access the fields of mail (ie., the TO field, Subject field, Msg Body, attachment etc).

    Read the article

  • Disable button after submit

    - by Chris Philpotts
    I'm trying to disable a button when a user submits a payment form and the code to post the form is causing a double post in firefox. This problem does not occur when the code is removed, and does not occur in any browser other than firefox. Any idea how to prevent the double post here? System.Text.StringBuilder sb = new StringBuilder(); sb.Append("if (typeof(Page_ClientValidate) == 'function') { "); sb.Append("if (Page_ClientValidate() == false) { return false; }} "); sb.Append("this.value = 'Please wait...';"); sb.Append("this.disabled = true;"); sb.Append(Page.GetPostBackEventReference(btnSubmit )); sb.Append(";"); btnSubmit.Attributes.Add("onclick", sb.ToString()); it's the sb.Append(Page.GetPostBackEventReference(btnSubmit )) line that's causing the issue Thanks EDIT: Here's the c# of the button: <asp:Button ID="cmdSubmit" runat="server" Text="Submit" /> here's the html This code posts twice (and disables the submit button and verifies input): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="if (typeof(Page_ClientValidate) == 'function') { if (Page_ClientValidate() == false) { return false; }} this.value = 'Please wait...';this.disabled = true;document.getElementById('ctl00_MainContent_cmdBack').disabled = true;__doPostBack('ctl00$MainContent$cmdSubmit','');" id="ctl00_MainContent_cmdSubmit" /> This code posts twice (but doesn’t disable the submit button): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="__doPostBack('ctl00$MainContent$cmdSubmit','');" id="ctl00_MainContent_cmdSubmit" /> This code posts once (but doesn’t verify the user input and doesn’t disable the submit button): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" id="ctl00_MainContent_cmdSubmit" /> This code posts once (but doesn’t disable submit button): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="javascript:WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions(&quot;ctl00$MainContent$cmdSubmit&quot;, &quot;&quot;, true, &quot;&quot;, &quot;&quot;, false, false))" id="ctl00_MainContent_cmdSubmit" /> This code doesn’t post at all: <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="this.disabled = true;WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions(&quot;ctl00$MainContent$cmdSubmit&quot;, &quot;&quot;, true, &quot;&quot;, &quot;&quot;, false, false))" id="ctl00_MainContent_cmdSubmit" /> Obviously it’s the disabling of the submit button that’s posing the problem. Do you have any ideas how we can disable the submit to avoid multiple clicking?

    Read the article

  • jQuery Dynamic Button Click Handler

    - by Neb
    I have a code the change the html of a div to make a button. When I make a click handler for the dynamic button, nothing happens $('#signinup').html("<button id=\"login_submit\">Sign In</button>"); And the handler: $('#login_submit').click(function() { alert("Works!"); });

    Read the article

  • Swap button for image (Jquery)

    - by Skoder
    Hi I have a button and when it's clicked, I want to replace the button with an image. How can I do this in JQuery? Is it possible to replace the background of the image as well? The button itself is within a large div, and I don't want to add another div around the button because it messes up a previous layout. Thanks

    Read the article

  • styling a form button

    - by Ayrton
    Hi I would like to style a form button (input or button tag) with 2 background images to create a stretchable button (relative to the text-length). The form button should also have a hovered state and it should be cross browser (at least IE7 & +) would need to support it. I know how to obtain the effect with just css with an tag = test If anyone could help me a little bit, I would be pleased yours truthfully

    Read the article

  • ASP.NET button_click not firing, after browser back button

    - by the berserker
    I have a ASPX Page that contains several user controls, which are loaded dynamically after user interaction. On one of ascx I have a hidden button that is being clicked on some user actions (via button.click()), which works fine on 1st page load. But after the form is being submitted once, the other ascx is loaded. There if user clicks the back button and resubmits the 1st form (again via button.click()), button_clicked event on server does not fire again. Any thought?

    Read the article

  • Add button to a layout programmatically

    - by mmmbaileys
    I'm having trouble adding a button to a layout that I've created in XML. Here's what I want to achieve: //some class else { startActivity(new Intent(StatisticsScreen.this, ScreenTemperature.class)); } //// //ScreenTemperatureClass @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //this is where I call another class that //displays a nice graph setContentView(new GraphTemperature(getApplicationContext())); } I want to add a Button to this new screen so that it'll appear below the graph. I've tried creating a LinearLayout view, then create a Button and add it to this view but I just get NullPointerExceptions.. Any help would be appreciated. Thanks EDIT#1 Here's what I've tried using that created a NullPointerException and 'force close': Button buybutton; LinearLayout layout; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(new GraphTemperature(getApplicationContext())); layout = (LinearLayout) findViewById(R.id.statsviewlayout); Button buyButton = new Button(this); buyButton.setText(R.string.button_back); buyButton.setLayoutParams(new LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); layout.addView(buyButton); } And here's the logcat error: ERROR/AndroidRuntime(293): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.weatherapp/com.weatherapp.ScreenTemperature}: java.lang.NullPointerException ERROR/AndroidRuntime(293): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2663) ERROR/AndroidRuntime(293): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2679) ERROR/AndroidRuntime(293): at android.app.ActivityThread.access$2300(ActivityThread.java:125) ERROR/AndroidRuntime(293): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:2033) theres abviously more lines to do with this error in logcat, not sure if you want it? EDIT#2 So i tried bhups method: @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); GraphTemperature GT = new GraphTemperature(getApplicationContext()); layout = (LinearLayout) findViewById(R.id.statsviewlayout); Button buyButton = new Button(this); buyButton.setText(R.string.button_back); buyButton.setLayoutParams(new LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); layout.addView(GT); // line 27 layout.addView(buyButton); setContentView(layout); } This method produced the same logcat error as above, NullPointerException, indicating it was something to do with line no. 27 which is the layout.addView line of code. Any ideas? Thanks again

    Read the article

  • How can I split a string in Java?

    - by Sergio Tapia
    Imagine I have this string: string thing = "sergio|tapia|gutierrez|21|Boston"; In C# I could go: string[] Words = thing.Split('|'); Is there something similar in Java? I could use Substring and indexOf methods but it is horribly convoluted. I don't want that.

    Read the article

  • Regex split into overlapping strings

    - by polygenelubricants
    I'm exploring the power of regular expressions, so I'm just wondering if something like this is possible: public class StringSplit { public static void main(String args[]) { System.out.println( java.util.Arrays.deepToString( "12345".split(INSERT_REGEX_HERE) ) ); // prints "[12, 23, 34, 45]" } } If possible, then simply provide the regex (and preemptively some explanation on how it works). If it's only possible in some regex flavors other than Java, then feel free to provide those as well. If it's not possible, then please explain why.

    Read the article

  • PHP String Split

    - by deniz
    I need to split a string into chunks of 2,2,3,3 characters and was able to do so in Perl by using unpack: unpack("A2A2A3A3", 'thisisloremipsum'); However the same function does not work in PHP, it gives this output: Array ( [A2A3A3] => th ) How can I do this by using unpack? I don't want to write a function for it, it should be possible with unpack but how? Thanks in advance,

    Read the article

  • javascript number split

    - by Jaron787
    Can anyboyd help me split up this date number in javascript so that when it is outputted to the screen it has slashes between the 4th and 5th number and the 6th and 7th number, so that it can be understood by a vxml voice browser. The number can be any value so i need it to work for any eight digit number. Like so: 20100820 2010/08/20 Many thanks

    Read the article

  • Probelm with String.split() in java

    - by Matt
    What I am trying to do is read a .java file, and pick out all of the identifiers and store them in a list. My problem is with the .split() method. If you run this code the way it is, you will get ArrayOutOfBounds, but if you change the delimiter from "." to anything else, the code works. But I need to lines parsed by "." so is there another way I could accomplish this? import java.io.BufferedReader; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.*; public class MyHash { private static String[] reserved = new String[100]; private static List list = new LinkedList(); private static List list2 = new LinkedList(); public static void main (String args[]){ Hashtable hashtable = new Hashtable(997); makeReserved(); readFile(); String line; ListIterator itr = list.listIterator(); int listIndex = 0; while (listIndex < list.size()) { if (itr.hasNext()){ line = itr.next().toString(); //PROBLEM IS HERE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! String[] words = line.split("."); //CHANGE THIS AND IT WILL WORK System.out.println(words[0]); //TESTING TO SEE IF IT WORKED } listIndex++; } } public static void readFile() { String text; String[] words; BufferedReader in = null; try { in = new BufferedReader(new FileReader("MyHash.java")); //NAME OF INPUT FILE } catch (FileNotFoundException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } try { while ((text = in.readLine()) != null){ text = text.trim(); words = text.split("\\s+"); for (int i = 0; i < words.length; i++){ list.add(words[i]); } for (int j = 0; j < reserved.length; j++){ if (list.contains(reserved[j])){ list.remove(reserved[j]); } } } } catch (IOException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } try { in.close(); } catch (IOException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } } public static int keyIt (int x) { int key = x % 997; return key; } public static int horner (String word){ int length = word.length(); char[] letters = new char[length]; for (int i = 0; i < length; i++){ letters[i]=word.charAt(i); } char[] alphabet = new char[26]; String abc = "abcdefghijklmnopqrstuvwxyz"; for (int i = 0; i < 26; i++){ alphabet[i]=abc.charAt(i); } int[] numbers = new int[length]; int place = 0; for (int i = 0; i < length; i++){ for (int j = 0; j < 26; j++){ if (alphabet[j]==letters[i]){ numbers[place]=j+1; place++; } } } int hornered = numbers[0] * 32; for (int i = 1; i < numbers.length; i++){ hornered += numbers[i]; if (i == numbers.length -1){ return hornered; } hornered = hornered % 997; hornered *= 32; } return hornered; } public static String[] makeReserved (){ reserved[0] = "abstract"; reserved[1] = "assert"; reserved[2] = "boolean"; reserved[3] = "break"; reserved[4] = "byte"; reserved[5] = "case"; reserved[6] = "catch"; reserved[7] = "char"; reserved[8] = "class"; reserved[9] = "const"; reserved[10] = "continue"; reserved[11] = "default"; reserved[12] = "do"; reserved[13] = "double"; reserved[14] = "else"; reserved[15] = "enum"; reserved[16] = "extends"; reserved[17] = "false"; reserved[18] = "final"; reserved[19] = "finally"; reserved[20] = "float"; reserved[21] = "for"; reserved[22] = "goto"; reserved[23] = "if"; reserved[24] = "implements"; reserved[25] = "import"; reserved[26] = "instanceof"; reserved[27] = "int"; reserved[28] = "interface"; reserved[29] = "long"; reserved[30] = "native"; reserved[31] = "new"; reserved[32] = "null"; reserved[33] = "package"; reserved[34] = "private"; reserved[35] = "protected"; reserved[36] = "public"; reserved[37] = "return"; reserved[38] = "short"; reserved[39] = "static"; reserved[40] = "strictfp"; reserved[41] = "super"; reserved[42] = "switch"; reserved[43] = "synchronize"; reserved[44] = "this"; reserved[45] = "throw"; reserved[46] = "throws"; reserved[47] = "trasient"; reserved[48] = "true"; reserved[49] = "try"; reserved[50] = "void"; reserved[51] = "volatile"; reserved[52] = "while"; reserved[53] = "="; reserved[54] = "=="; reserved[55] = "!="; reserved[56] = "+"; reserved[57] = "-"; reserved[58] = "*"; reserved[59] = "/"; reserved[60] = "{"; reserved[61] = "}"; return reserved; } }

    Read the article

  • String split array

    - by mac
    Intention is to take a current line which contains commas, store trimmed values of all space and store the line into the array. Why does this not work? String[] currentLineArray = currentInputLine.replace("\\s", "").split(",");

    Read the article

  • Split string with zsh as in Python

    - by Olivier
    In python: s = '1::3' a = s.split(':') print a[0] # '1' good print a[1] # '' good print a[2] # '3' good How can I achieve the same effect with zsh? The following attempt fails: s="1::3" a=(${(s/:/)s}) echo $a[1] # 1 echo $a[2] # 3 ?? I want an empty string, as in Python

    Read the article

  • Java String.split

    - by user903772
    I have the following text: ARIYALUR:ARIYALUR|CHENNAI:CHENNAI|COIMBATORE:COIMBATORE|CUDDALORE:CUDDALORE|DINDIGUL:DINDIGUL|ERODE:ERODE|KANCHEEPURAM:KANCHEEPURAM|KANYAKUMARI:KANYAKUMARI|KRISHNAGIRI:KRISHNAGIRI|MADURAI:MADURAI|NAMAKKAL:NAMAKKAL|NILGIRIS:NILGIRIS|PERAMBALUR:PERAMBALUR|PONDICHERRY:PONDICHERRY|SALEM:SALEM|THANJAVUR:THANJAVUR|THENI:THENI|THIRUVALLUR:THIRUVALLUR|THOOTHUKUDI:THOOTHUKUDI|TIRUNELVELI:TIRUNELVELI|VELLORE:VELLORE|VILLUPURAM:VILLUPURAM|VIRUDHUNAGAR:VIRUDHUNAGAR| I tried to do a split("|") but my array is made up of alphabets and not each district. Please help.

    Read the article

  • How to use Split with jQuery?

    - by Matt
    I need to break apart a string that always looks like this: something -- something_else. I need to put "something_else" in another input field. Currently, this string example is being added to an HTML table row on the fly like this: tRow.append($('<td>').text($('[id$=txtEntry2]').val())); I figure "split" is the way to go but there is very little documentation that I can find yet.

    Read the article

  • mysql split value from one field to two

    - by tsiger
    Hello, I 've got a table field (membername) which contains both the last name and the first name of users. Is it possible to split those into 2 fields (memberfirst - memberlast)? All the records have this format "Firstname Lastname" (without quotes and a space in between).

    Read the article

< Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >