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  • jquery: popup menu upon clicking link ?

    - by wefwgeweg
    is there any way to "wait for user action on popupmenu" after an element is clicked ? for example: person A clicks on link. javascript menu popups asking what the user would like to do with this link. user should not be allowed to click anywhere else but the popup menu. after user clicks an action on the menu, the default browser action should happen (ie. link to the next page)

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  • Thread sleep and thread join.

    - by Dhruv Gairola
    hi guys, if i put a thread to sleep in a loop, netbeans gives me a caution saying Invoking Thread.sleep in loop can cause performance problems. However, if i were to replace the sleep with join, no such caution is given. Both versions compile and work fine tho. My code is below (check the last few lines for "Thread.sleep() vs t.join()"). public class Test{ //Display a message, preceded by the name of the current thread static void threadMessage(String message) { String threadName = Thread.currentThread().getName(); System.out.format("%s: %s%n", threadName, message); } private static class MessageLoop implements Runnable { public void run() { String importantInfo[] = { "Mares eat oats", "Does eat oats", "Little lambs eat ivy", "A kid will eat ivy too" }; try { for (int i = 0; i < importantInfo.length; i++) { //Pause for 4 seconds Thread.sleep(4000); //Print a message threadMessage(importantInfo[i]); } } catch (InterruptedException e) { threadMessage("I wasn't done!"); } } } public static void main(String args[]) throws InterruptedException { //Delay, in milliseconds before we interrupt MessageLoop //thread (default one hour). long patience = 1000 * 60 * 60; //If command line argument present, gives patience in seconds. if (args.length > 0) { try { patience = Long.parseLong(args[0]) * 1000; } catch (NumberFormatException e) { System.err.println("Argument must be an integer."); System.exit(1); } } threadMessage("Starting MessageLoop thread"); long startTime = System.currentTimeMillis(); Thread t = new Thread(new MessageLoop()); t.start(); threadMessage("Waiting for MessageLoop thread to finish"); //loop until MessageLoop thread exits while (t.isAlive()) { threadMessage("Still waiting..."); //Wait maximum of 1 second for MessageLoop thread to //finish. /*******LOOK HERE**********************/ Thread.sleep(1000);//issues caution unlike t.join(1000) /**************************************/ if (((System.currentTimeMillis() - startTime) > patience) && t.isAlive()) { threadMessage("Tired of waiting!"); t.interrupt(); //Shouldn't be long now -- wait indefinitely t.join(); } } threadMessage("Finally!"); } } As i understand it, join waits for the other thread to complete, but in this case, arent both sleep and join doing the same thing? Then why does netbeans throw the caution?

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  • Flex saving progress bar

    - by Deena
    Hi, I am developing a static flex application which does not have a database connection, all the values are hardcoded(its just a prototype for the original app). Now when i click the save button, i need to get a message like saving in progress... please wait, I need to display this message for 3 seconds. Please let me know how could this be done. Thanks! Cheers, Deena

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  • timeout stringwithcontentsofurl

    - by sergiobuj
    Hi, I have this call to stringwithcontentsofurl: [NSString stringWithContentsOfURL:url usedEncoding:NSASCIIStringEncoding error:nil]; How can I give that a simple timeout? I don't want to use threads or operation queues (the content of the url is about 100 characters), I just don't want to wait too long when the connection is slow.

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  • Redirecting one file to another using dub2 and strtok

    - by Sergiy Zakharov
    OK, here goes. I have to write a program, in which I need to use strtok and dup2 to redirect one file to another, but I need to also have the user to actually put the command cat < file1 file2, but not from the shell, but instead by using my program. That's why I need strtok. And the reason my program doesn't work is probably because of that, because I don't really understand how strtok works. I found a similar program on the internet, but they just take the ls command and redirect it to the file. That's it. My program is much more complicated. I mean, it would've been easier just to say in shell cat < file1 file2, but for some reason they want us to do it this way. So, anyways, here is what I have so far (here I just combined what I have found on the internet with what I already had from before. We had to do something similar but then the user would just go ls or ls -l. Very simple stuff. This is much harder, for me, at least.) #include <fcntl.h> #include <unistd.h> #include <stdio.h> #include <errno.h> #include <sys/wait.h> #include <string.h> int main() { pid_t pid; char line[256]; char *args[129]; int i; int fd; int status; char *temp; while (1) { printf(">"); if (fgets(line, 256, stdin) == 0) { exit(0); } else { pid = fork(); if (pid == 0) { i = 0; temp = strtok("<",line); while (temp != NULL) { args[i++] = temp; temp = strtok(">",line); args[i] = '\0'; } fd = open("hello", O_RDONLY); dup2(fd, STDIN_FILENO); fd = open("world", O_WRONLY|O_CREAT|O_TRUNC, S_IRWXU); dup2(fd, STDOUT_FILENO ); close(fd); execvp(args[0], args); } else { close(fd); wait(&status); } } } } Any help would be greatly appreciated.

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  • Why sockets does not die when server dies? Why socket dies when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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  • Simple Scala actor question

    - by 7zark7
    I'm sure this is a very simple question, but embarrassed to say I can't get my head around it: I have a list of values in Scala. I would like to use use actors to make some (external) calls with each value, in parallel. I would like to wait until all values have been processed, and then proceed. There's no shared values being modified. Could anyone advise? Thanks

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  • ThreadPoolExecutor fixed thread pool with custom behaviour

    - by Simone Margaritelli
    i'm new to this topic ... i'm using a ThreadPoolExecutor created with Executors.newFixedThreadPool( 10 ) and after the pool is full i'm starting to get a RejectedExecutionException . Is there a way to "force" the executor to put the new task in a "wait" status instead of rejecting it and starting it when the pool is freed ? Thanks Issue regarding this https://github.com/evilsocket/dsploit/issues/159 Line of code involved https://github.com/evilsocket/dsploit/blob/master/src/it/evilsocket/dsploit/net/NetworkDiscovery.java#L150

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  • lock-free memory reclamation with 64bit pointers

    - by JDonner
    Herlihy and Shavit's book (The Art of Multiprocessor Programming) solution to memory reclamation uses Java's AtomicStampedReference<T>;. To write one in C++ for the x86_64 I imagine requires at least a 12 byte swap operation - 8 for a 64bit pointer and 4 for the int. Is there x86 hardware support for this and if not, any pointers on how to do wait-free memory reclamation without it?

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  • How do I change the curosr during a jQuery synchronous browser blocking POST?

    - by Tommy
    $.ajax({ url: "/cgi-bin/stats.exe", method: "post", async: false, data: { refresh: "a41" } }); Using ajax post synchronously - "async: false". While it blocks the browser during the active request, what is the most efficient way to change the cursor to the hourglass or display a wait .gif? Perhaps set the cursor as it enters this function then change it back in the success or complete function? Any advice is appreciated. Thank You.

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  • Boost thread synchronization in release build

    - by Joseph16
    Hi, when I try to run the following code in debug and release mode in VS2005. Each time I see different output in console and It doesn't seem like the multithreading is achieved in release mode. 1. #include <boost/thread.hpp> 2. #include <iostream> 3. 4. void wait(int seconds) 5. { 6. boost::this_thread::sleep(boost::posix_time::seconds(seconds)); 7. } 8. 9. boost::mutex mutex; 10. 11. void thread() 12. { 13. for (int i = 0; i < 5; ++i) 14. { 15. //wait(1); 16. mutex.lock(); 17. std::cout << "Thread " << boost::this_thread::get_id() << ": " << i << std::endl; 18. mutex.unlock(); 19. } 20. } 21. 22. int main() 23. { 24. boost::thread t1(thread); 25. boost::thread t2(thread); 26. t1.join(); 27. t2.join(); 28. } Debug Mode Thread 00153E60: 0 Thread 00153E90: 0 Thread 00153E60: 1 Thread 00153E90: 1 Thread 00153E90: 2 Thread 00153E60: 2 Thread 00153E90: 3 Thread 00153E60: 3 Thread 00153E60: 4 Thread 00153E90: 4 Press any key to continue . . . Release Mode Thread 00153D28: 0 Thread 00153D28: 1 Thread 00153D28: 2 Thread 00153D28: 3 Thread 00153D28: 4 Thread 00153D58: 0 Thread 00153D58: 1 Thread 00153D58: 2 Thread 00153D58: 3 Thread 00153D58: 4 Press any key to continue . . .

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  • Provide local fallback for CSS from CDN

    - by BadHorsie
    I'm loading the Bootstrap CSS on my page from the CDN bootstrapcdn.com <link href="//netdna.bootstrapcdn.com/twitter-bootstrap/2.3.2/css/bootstrap-combined.min.css" rel="stylesheet"> How can I test if the stylesheet was loaded, and if not provide a local fallback? I do not want to wait for jQuery or other libraries to load before doing the test; I want all CSS to be loaded on the page first.

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  • Sending POST Requests without waiting for response?

    - by Gotys
    I am writing a simple REST service, which responds to requests from clients. All in PHP. My concern is, that when my server responds to a request, it could end up tying up resources if the client side is too slow in sending back "ok" response. How do I send a POST request via lib_curl setting it to not wait for any responses, but rather quit immidiately after the POST data have been sent? Is this even possible? Thank you !

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  • Opengl-es android best way to preload images

    - by lacas
    I have a game app, and i have many screens. The first screen will be the SCREEN.LOADING screen. When the app starting, I want to show a picture "loading please wait" while the images, menus, etc loaded succesfull. I tried asynctask to do this, but its not work in GLThread. What is the way to do this in opengl-es? 03-06 12:46:35.282: ERROR/AndroidRuntime(32736): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare() Thanks, Leslie

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