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  • Easy way to convert a string of 0's and 1's into a character? C language

    - by Nick
    I'm doing a steganography project where I read in bytes from a ppm file and add the least significant bit to an array. So once 8 bytes are read in, I would have 8 bits in my array, which should equal some character in a hidden message. Is there an easy way to convert an array of 0's and 1's into an ascii value? For example, the array: char bits[] = "0,1,1,1,0,1,0,0" would equal 't'.

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  • Does anyone know what is the 32 character string before the product image filename in Magento ?

    - by Daniel Higgins
    I ask this question, since I am trying to get the images I have just copied from Domain A to work in Domain B, (which is using the same database). http://DOMAIN_A/magento/media/catalog/product/cache/1/image/9df78eab33525d08d6e5fb8d27136e95/b/0/b0041-1.jpg I think knowing what the 32 character string is, which help me find a good explanation why the images are not being found in the front or backend of Magento after reinstall on DOMAIN B. RE: Magento version 1.4.0.1

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  • Help Prevent Carpal Tunnel Problems with Workrave

    - by Matthew Guay
    Whether for work or leisure, many of us spend entirely too much time on the computer everyday.  This puts us at risk of having or aggravating Carpal Tunnel problems, but thanks to Workrave you can help to divert these problems. Workrave helps Carpal Tunnel problems by reminding you to get away from your computer periodically.  Breaking up your computer time with movement can help alleviate many computer and office related health problems.  Workrave helps by reminding you to take short pauses after several minutes of computer use, and longer breaks after continued use.  You can also use it to keep from using the computer for too much You time in a day.  Since you can change the settings to suit you, this can be a great way to make sure you’re getting the breaks you need. Install Workrave on Windows If you’re using Workrave on Windows, download (link below) and install it with the default settings. One installation setting you may wish to change is the startup.  By default Workrave will run automatically when you start your computer; if you don’t want this, you can simply uncheck the box and proceed with the installation. Once setup is finished, you can run Workrave directly from the installer. Or you can open it from your start menu by entering “workrave” in the search box. Install Workrave in Ubuntu If you wish to use it in Ubuntu, you can install it directly from the Ubuntu Software Center.  Click the Applications menu, and select Ubuntu Software Center. Enter “workrave” into the search box in the top right corner of the Software Center, and it will automatically find it.  Click the arrow to proceed to Workrave’s page. This will give you information about Workrave; simply click Install to install Workrave on your system. Enter your password when prompted. Workrave will automatically download and install.   When finished, you can find Workrave in your Applications menu under Universal Access. Using Workrave Workrave by default shows a small counter on your desktop, showing the length of time until your next Micro break (30 second break), Rest break (10 minute break), and max amount of computer usage for the day. When it’s time for a micro break, Workrave will popup a reminder on your desktop. If you continue working, it will disappear at the end of the timer.  If you stop, it will start a micro-break which will freeze most on-screen activities until the timer is over.  You can click Skip or Postpone if you do not want to take a break right then. After an hour of work, Workrave will give you a 10 minute rest break.  During this it will show you some exercises that can help eliminate eyestrain, muscle tension, and other problems from prolonged computer usage.  You can click through the exercises, or can skip or postpone the break if you wish.   Preferences You can change your Workrave preferences by right-clicking on its icon in your system tray and selecting Preferences. Here you can customize the time between your breaks, and the length of your breaks.  You can also change your daily computer usage limit, and can even turn off the postpone and skip buttons on notifications if you want to make sure you follow Workrave and take your rests! From the context menu, you can also choose Statistics.  This gives you an overview of how many breaks, prompts, and more were shown on a given day.  It also shows a total Overdue time, which is the total length of the breaks you skipped or postponed.  You can view your Workrave history as well by simply selecting a date on the calendar.   Additionally, the Activity tab in the Statics pane shows more info about your computer usage, including total mouse movement, mouse button clicks, and keystrokes. Conclusion Whether you’re suffering with Carpal Tunnel or trying to prevent it, Workrave is a great solution to help remind you to get away from your computer periodically and rest.  Of course, since you can simply postpone or skip the prompts, you’ve still got to make an effort to help your own health.  But it does give you a great way to remind yourself to get away from the computer, and especially for geeks, this may be something that we really need! Download Workrave Similar Articles Productive Geek Tips Switch to the Dvorak Keyboard Layout in XPAccess Your MySQL Server Remotely Over SSHHow to Secure Gaim Instant Messenger traffic at Work with SecureCRT and SSHConnect to VMware Server Console Over SSHDisclaimers TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional StockFox puts a Lightweight Stock Ticker in your Statusbar Explore Google Public Data Visually The Ultimate Excel Cheatsheet Convert the Quick Launch Bar into a Super Application Launcher Automate Tasks in Linux with Crontab Discover New Bundled Feeds in Google Reader

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  • User Input That Involves A ' ' Causes A Substring Out Of Range Error

    - by Greenhouse Gases
    Hi Stackoverflow people. You have already helped me quite a bit but near the end of writing this program I have somewhat of a bug. You see in order to read in city names with a space in from a text file I use a '/' that is then replaced by the program for a ' ' (and when the serializer runs the opposite happens for next time the program is run). The problem is when a user inputs a name too add, search for, or delete that contains a space, for instance 'New York' I get a Debug Assertion Error with a substring out of range expression. I have a feeling it's to do with my correctCase function, or setElementsNull that looks at the string until it experiences a null element in the array, however ' ' is not null so I'm not sure how to fix this and I'm going a bit insane. Any help would be much appreciated. Here is my code: // U08221.cpp : main project file. #include "stdafx.h" #include <_iostream> #include <_string> #include <_fstream> #include <_cmath> using namespace std; class locationNode { public: string nodeCityName; double nodeLati; double nodeLongi; locationNode* Next; locationNode(string nameOf, double lat, double lon) { this->nodeCityName = nameOf; this->nodeLati = lat; this->nodeLongi = lon; this->Next = NULL; } locationNode() // NULL constructor { } void swapProps(locationNode *node2) { locationNode place; place.nodeCityName = this->nodeCityName; place.nodeLati = this->nodeLati; place.nodeLongi = this->nodeLongi; this->nodeCityName = node2->nodeCityName; this->nodeLati = node2->nodeLati; this->nodeLongi = node2->nodeLongi; node2->nodeCityName = place.nodeCityName; node2->nodeLati = place.nodeLati; node2->nodeLongi = place.nodeLongi; } void modify(string name) { this->nodeCityName = name; } void modify(double latlon, int mod) { switch(mod) { case 2: this->nodeLati = latlon; break; case 3: this->nodeLongi = latlon; break; } } void correctCase() // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = this->nodeCityName[0], letVal; int n = 1; // variable for name index from second letter onwards if((this->nodeCityName[0] >90) && (this->nodeCityName[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter this->nodeCityName[0] = firstLetVal; } while(this->nodeCityName[n] != NULL) { if((this->nodeCityName[n] >= 65) && (this->nodeCityName[n] <= 90)) { if(this->nodeCityName[n - 1] != 32) { letVal = this->nodeCityName[n] + 32; this->nodeCityName[n] = letVal; } } n++; } } }; Here is the main part of the program: // U08221.cpp : main project file. #include "stdafx.h" #include "Locations2.h" #include <_iostream> #include <_string> #include <_fstream> #include <_cmath> using namespace std; #define pi 3.14159265358979323846264338327950288 #define radius 6371 #define gig 1073741824 //size of a gigabyte in bytes int n = 0,x, locationCount = 0, MAX_SIZE = 35 , g = 0, i = 0, modKey = 0, xx; string cityNameInput, alter; char targetCity[35], skipKey = ' '; double lat1, lon1, lat2, lon2, dist, dummy, modVal, result; bool acceptedInput = false, match = false, nodeExists = false;// note: addLocation(), set to true to enable user input as opposed to txt file locationNode *temp, *temp2, *example, *seek, *bridge, *start_ptr = NULL; class Menu { int junction; public: /* Convert decimal degrees to radians */ public: void setElementsNull(char cityParam[]) { int y=0; while(cityParam[y] != NULL) { y++; } while(y < MAX_SIZE) { cityParam[y] = NULL; y++; } } void correctCase(string name) // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = name[0], letVal; int n = 1; // variable for name index from second letter onwards if((name[0] >90) && (name[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter name[0] = firstLetVal; } while(name[n] != NULL) { if((name[n] >= 65) && (name[n] <= 90)) { letVal = name[n] + 32; name[n] = letVal; } n++; } for(n = 0; targetCity[n] != NULL; n++) { targetCity[n] = name[n]; } } bool nodeExistTest(char targetCity[]) // see if entry is present in the database { match = false; seek = start_ptr; int letters = 0, letters2 = 0, x = 0, y = 0; while(targetCity[y] != NULL) { letters2++; y++; } while(x <= locationCount) // locationCount is number of entries currently in list { y=0, letters = 0; while(seek->nodeCityName[y] != NULL) // count letters in the current name { letters++; y++; } if(letters == letters2) // same amount of letters in the name { y = 0; while(y <= letters) // compare each letter against one another { if(targetCity[y] == seek->nodeCityName[y]) { match = true; y++; } else { match = false; y = letters + 1; // no match, terminate comparison } } } if(match) { x = locationCount + 1; //found match so terminate loop } else{ if(seek->Next != NULL) { bridge = seek; seek = seek->Next; x++; } else { x = locationCount + 1; // end of list so terminate loop } } } return match; } double deg2rad(double deg) { return (deg * pi / 180); } /* Convert radians to decimal degrees */ double rad2deg(double rad) { return (rad * 180 / pi); } /* Do the calculation */ double distance(double lat1, double lon1, double lat2, double lon2, double dist) { dist = sin(deg2rad(lat1)) * sin(deg2rad(lat2)) + cos(deg2rad(lat1)) * cos(deg2rad(lat2)) * cos(deg2rad(lon1 - lon2)); dist = acos(dist); dist = rad2deg(dist); dist = (radius * pi * dist) / 180; return dist; } void serialise() { // Serialize to format that can be written to text file fstream outfile; outfile.open("locations.txt",ios::out); temp = start_ptr; do { for(xx = 0; temp->nodeCityName[xx] != NULL; xx++) { if(temp->nodeCityName[xx] == 32) { temp->nodeCityName[xx] = 47; } } outfile << endl << temp->nodeCityName<< " "; outfile<<temp->nodeLati<< " "; outfile<<temp->nodeLongi; temp = temp->Next; }while(temp != NULL); outfile.close(); } void sortList() // do this { int changes = 1; locationNode *node1, *node2; while(changes > 0) // while changes are still being made to the list execute { node1 = start_ptr; node2 = node1->Next; changes = 0; do { xx = 1; if(node1->nodeCityName[0] > node2->nodeCityName[0]) //compare first letter of name with next in list { node1->swapProps(node2); // should come after the next in the list changes++; } else if(node1->nodeCityName[0] == node2->nodeCityName[0]) // if same first letter { while(node1->nodeCityName[xx] == node2->nodeCityName[xx]) // check next letter of name { if((node1->nodeCityName[xx + 1] != NULL) && (node2->nodeCityName[xx + 1] != NULL)) // check next letter until not the same { xx++; } else break; } if(node1->nodeCityName[xx] > node2->nodeCityName[xx]) { node1->swapProps(node2); // should come after the next in the list changes++; } } node1 = node2; node2 = node2->Next; // move to next pair in list } while(node2 != NULL); } } void initialise() { cout << "Populating List..."; ifstream inputFile; inputFile.open ("locations.txt", ios::in); char inputName[35] = " "; double inputLati = 0, inputLongi = 0; //temp = new locationNode(inputName, inputLati, inputLongi); do { inputFile.get(inputName, 35, ' '); inputFile >> inputLati; inputFile >> inputLongi; if(inputName[0] == 10 || 13) //remove linefeed from input { for(int i = 0; inputName[i] != NULL; i++) { inputName[i] = inputName[i + 1]; } } for(xx = 0; inputName[xx] != NULL; xx++) { if(inputName[xx] == 47) // if it is a '/' { inputName[xx] = 32; // replace it for a space } } temp = new locationNode(inputName, inputLati, inputLongi); if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list } while(!inputFile.eof()); cout << "Successful!" << endl << "List contains: " << locationCount << " entries" << endl; inputFile.close(); cout << endl << "*******************************************************************" << endl << "DISTANCE CALCULATOR v2.0\tAuthors: Darius Hodaei, Joe Clifton" << endl; } void menuInput() { char menuChoice = ' '; while(menuChoice != 'Q') { // Menu if(skipKey != 'X') // This is set by case 'S' below if a searched term does not exist but wants to be added { cout << endl << "*******************************************************************" << endl; cout << "Please enter a choice for the menu..." << endl << endl; cout << "(P) To print out the list" << endl << "(O) To order the list alphabetically" << endl << "(A) To add a location" << endl << "(D) To delete a record" << endl << "(C) To calculate distance between two points" << endl << "(S) To search for a location in the list" << endl << "(M) To check memory usage" << endl << "(U) To update a record" << endl << "(Q) To quit" << endl; cout << endl << "*******************************************************************" << endl; cin >> menuChoice; if(menuChoice >= 97) { menuChoice = menuChoice - 32; // Turn the lower case letter into an upper case letter } } skipKey = ' '; //Reset skipKey so that it does not skip the menu switch(menuChoice) { case 'P': temp = start_ptr; // set temp to the start of the list do { if (temp == NULL) { cout << "You have reached the end of the database" << endl; } else { // Display details for what temp points to at that stage cout << "Location : " << temp->nodeCityName << endl; cout << "Latitude : " << temp->nodeLati << endl; cout << "Longitude : " << temp->nodeLongi << endl; cout << endl; // Move on to next locationNode if one exists temp = temp->Next; } } while (temp != NULL); break; case 'O': { sortList(); // pass by reference??? cout << "List reordered alphabetically" << endl; } break; case 'A': char cityName[35]; double lati, longi; cout << endl << "Enter the name of the location: "; cin >> cityName; for(xx = 0; cityName[xx] != NULL; xx++) { if(cityName[xx] == 47) // if it is a '/' { cityName[xx] = 32; // replace it for a space } } if(!nodeExistTest(cityName)) { cout << endl << "Please enter the latitude value for this location: "; cin >> lati; cout << endl << "Please enter the longitude value for this location: "; cin >> longi; cout << endl; temp = new locationNode(cityName, lati, longi); temp->correctCase(); //start_ptr allignment if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list cout << "Location sucessfully added to the database! There are " << locationCount << " location(s) stored" << endl; } else { cout << "Node is already present in the list and so cannot be added again" << endl; } break; case 'D': { junction = 0; locationNode *place; cout << "Enter the name of the city you wish to remove" << endl; cin >> targetCity; setElementsNull(targetCity); correctCase(targetCity); for(xx = 0; targetCity[xx] != NULL; xx++) { if(targetCity[xx] == 47) { targetCity[xx] = 32; } } if(nodeExistTest(targetCity)) //if this node does exist { if(seek == start_ptr) // if it is the first in the list { junction = 1; } if(seek->Next == NULL) // if it is last in the list { junction = 2; } switch(junction) // will alter list accordingly dependant on where the searched for link is { case 1: start_ptr = start_ptr->Next; delete seek; --locationCount; break; case 2: place = seek; seek = bridge; seek->Next = NULL; delete place; --locationCount; break; default: bridge->Next = seek->Next; delete seek; --locationCount; break; } cout << endl << "Link deleted. There are now " << locationCount << " locations." << endl; } else { cout << "That entry does not currently exist" << endl << endl << endl; } } break; case 'C': { char city1[35], city2[35]; cout << "Enter the first city name" << endl; cin >> city1; setElementsNull(city1); correctCase(targetCity); if(nodeExistTest(city1)) { lat1 = seek->nodeLati; lon1 = seek->nodeLongi; cout << "Lati = " << seek->nodeLati << endl << "Longi = " << seek->nodeLongi << endl << endl; } cout << "Enter the second city name" << endl; cin >> city2; setElementsNull(city2); correctCase(targetCity); if(nodeExistTest(city2)) { lat2 = seek->nodeLati; lon2 = seek->nodeLongi; cout << "Lati = " << seek->nodeLati << endl << "Longi = " << seek->nodeLongi << endl << endl; } result = distance (lat1, lon1, lat2, lon2, dist); cout << "The distance between these two locations is " << result << " kilometres." << endl; } break; case 'S': { char choice; cout << "Enter search term..." << endl; cin >> targetCity; setElementsNull(targetCity); correctCase(targetCity); if(nodeExistTest(targetCity)) { cout << "Latitude: " << seek->nodeLati << endl << "Longitude: " << seek->nodeLongi << endl; } else { cout << "Sorry, that city is not currently present in the list." << endl << "Would you like to add this city now Y/N?" << endl; cin >> choice; /*while(choice != ('Y' || 'N')) { cout << "Please enter a valid choice..." << endl; cin >> choice; }*/ switch(choice) { case 'Y': skipKey = 'X'; menuChoice = 'A'; break; case 'N': break; default : cout << "Invalid choice" << endl; break; } } break; } case 'M': { cout << "Locations currently stored: " << locationCount << endl << "Memory used for this: " << (sizeof(start_ptr) * locationCount) << " bytes" << endl << endl << "You can store " << ((gig - (sizeof(start_ptr) * locationCount)) / sizeof(start_ptr)) << " more locations" << endl ; break; } case 'U': { cout << "Enter the name of the Location you would like to update: "; cin >> targetCity; setElementsNull(targetCity); correctCase(targetCity); if(nodeExistTest(targetCity)) { cout << "Select (1) to alter City Name, (2) to alter Longitude, (3) to alter Latitude" << endl; cin >> modKey; switch(modKey) { case 1: cout << "Enter the new name: "; cin >> alter; cout << endl; seek->modify(alter); break; case 2: cout << "Enter the new latitude: "; cin >> modVal; cout << endl; seek->modify(modVal, modKey); break; case 3: cout << "Enter the new longitude: "; cin >> modVal; cout << endl; seek->modify(modVal, modKey); break; default: break; } } else cout << "Location not found" << endl; break; } } } } }; int main(array<System::String ^> ^args) { Menu mm; //mm.initialise(); mm.menuInput(); mm.serialise(); }

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  • The Joy Of Hex

    - by Jim Giercyk
    While working on a mainframe integration project, it occurred to me that some basic computer concepts are slipping into obscurity. For example, just about anyone can tell you that a 64-bit processor is faster than a 32-bit processer. A grade school child could tell you that a computer “speaks” in ‘1’s and ‘0’s. Some people can even tell you that there are 8 bits in a byte. However, I have found that even the most seasoned developers often can’t explain the theory behind those statements. That is not a knock on programmers; in the age of IntelliSense, what reason do we have to work with data at the bit level? Many computer theory classes treat bit-level programming as a thing of the past, no longer necessary now that storage space is plentiful. The trouble with that mindset is that the world is full of legacy systems that run programs written in the 1970’s.  Today our jobs require us to extract data from those systems, regardless of the format, and that often involves low-level programming. Because it seems knowledge of the low-level concepts is waning in recent times, I thought a review would be in order.       CHARACTER: See Spot Run HEX: 53 65 65 20 53 70 6F 74 20 52 75 6E DECIMAL: 83 101 101 32 83 112 111 116 32 82 117 110 BINARY: 01010011 01100101 01100101 00100000 01010011 01110000 01101111 01110100 00100000 01010010 01110101 01101110 In this example, I have broken down the words “See Spot Run” to a level computers can understand – machine language.     CHARACTER:  The character level is what is rendered by the computer.  A “Character Set” or “Code Page” contains 256 characters, both printable and unprintable.  Each character represents 1 BYTE of data.  For example, the character string “See Spot Run” is 12 Bytes long, exclusive of the quotation marks.  Remember, a SPACE is an unprintable character, but it still requires a byte.  In the example I have used the default Windows character set, ASCII, which you can see here:  http://www.asciitable.com/ HEX:  Hex is short for hexadecimal, or Base 16.  Humans are comfortable thinking in base ten, perhaps because they have 10 fingers and 10 toes; fingers and toes are called digits, so it’s not much of a stretch.  Computers think in Base 16, with numeric values ranging from zero to fifteen, or 0 – F.  Each decimal place has a possible 16 values as opposed to a possible 10 values in base 10.  Therefore, the number 10 in Hex is equal to the number 16 in Decimal.  DECIMAL:  The Decimal conversion is strictly for us humans to use for calculations and conversions.  It is much easier for us humans to calculate that [30 – 10 = 20] in decimal than it is for us to calculate [1E – A = 14] in Hex.  In the old days, an error in a program could be found by determining the displacement from the entry point of a module.  Since those values were dumped from the computers head, they were in hex. A programmer needed to convert them to decimal, do the equation and convert back to hex.  This gets into relative and absolute addressing, a topic for another day.  BINARY:  Binary, or machine code, is where any value can be expressed in 1s and 0s.  It is really Base 2, because each decimal place can have a possibility of only 2 characters, a 1 or a 0.  In Binary, the number 10 is equal to the number 2 in decimal. Why only 1s and 0s?  Very simply, computers are made up of lots and lots of transistors which at any given moment can be ON ( 1 ) or OFF ( 0 ).  Each transistor is a bit, and the order that the transistors fire (or not fire) is what distinguishes one value from  another in the computers head (or CPU).  Consider 32 bit vs 64 bit processing…..a 64 bit processor has the capability to read 64 transistors at a time.  A 32 bit processor can only read half as many at a time, so in theory the 64 bit processor should be much faster.  There are many more factors involved in CPU performance, but that is the fundamental difference.    DECIMAL HEX BINARY 0 0 0000 1 1 0001 2 2 0010 3 3 0011 4 4 0100 5 5 0101 6 6 0110 7 7 0111 8 8 1000 9 9 1001 10 A 1010 11 B 1011 12 C 1100 13 D 1101 14 E 1110 15 F 1111   Remember that each character is a BYTE, there are 2 HEX characters in a byte (called nibbles) and 8 BITS in a byte.  I hope you enjoyed reading about the theory of data processing.  This is just a high-level explanation, and there is much more to be learned.  It is safe to say that, no matter how advanced our programming languages and visual studios become, they are nothing more than a way to interpret bits and bytes.  There is nothing like the joy of hex to get the mind racing.

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  • switch statement in for loop and if statement not completing

    - by user2373912
    I'm trying to find out how many of each character are in a string. I've searched around for a while and can't seem to figure out why my switch statement is stopping after the first case. function charFreq(string){ var splitUp = string.split(""); console.log(splitUp); var a; var b; var c; var v; for (var i = 0; i<splitUp.length; i++){ if (i<1){ switch (splitUp[i]){ case "a": a = 1; break; case "b": b = 1; break; case "c": c = 1; break; case "v": v = 1; break; } } else { switch (splitUp[i]){ case "a": a += 1; break; case "b": b += 1; break; case "c": c += 1; break; case "v": v += 1; break; } } } console.log("There are " + a + " A's, " + b + " B's, " + c + " C's, and " + v + " V's.") } charFreq("aaabccbbavabac"); What am I doing wrong that would make the console read: There are 6 A's, NaN B's, NaN C's, and NaN V's.

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  • Serving .docx files through Php

    - by user275074
    Hi, I'm having issues when attempting to serve a .docx file using Php. When uploading the file I detect the file mime type and upload the file using the file with the correct extension based on the mime type; e.g. below: application/msword - doc application/vnd.openxmlformats-officedocument.wordprocessingml.document - docx When attempting to serve the files for download, I do the reverse in detecting the extension and serving based on the mime type e.g. public static function fileMimeType($extention) { if(!is_null($extention)) { switch($extention) { case 'txt': return 'text/plain'; break; case 'odt': return 'application/vnd.oasis.opendocument.text'; break; case 'doc': return 'application/msword'; break; case 'docx': return 'application/vnd.openxmlformats-officedocument.wordprocessingml.document'; break; case ('jpg' || 'jpeg'): return 'image/jpeg'; break; case 'png': return 'image/png'; break; case 'pdf': return 'application/pdf'; break; default: break; } } } All files appear to download correctly and open fine but when attempting to open a docx file, Word (on multiple files) throws a error stating the file is corrupt. Any ideas would be great, thanks.

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  • file transfer through bluetooth

    - by venkat
    is it possible to transfer files from one android phone to any other device through bluetooth? if possible the send give me a link the sample code... switch (msg.what) { case MESSAGE_STATE_CHANGE: if(D) Log.i(TAG, "MESSAGE_STATE_CHANGE: " + msg.arg1); switch (msg.arg1) { case BluetoothChatService.STATE_CONNECTED: mTitle.setText(R.string.title_connected_to); mTitle.append(mConnectedDeviceName); mConversationArrayAdapter.clear(); break; case BluetoothChatService.STATE_CONNECTING: mTitle.setText(R.string.title_connecting); break; case BluetoothChatService.STATE_LISTEN: case BluetoothChatService.STATE_NONE: mTitle.setText(R.string.title_not_connected); break; } break; case MESSAGE_WRITE: byte[] writeBuf = (byte[]) msg.obj; // construct a string from the buffer String writeMessage = new String(writeBuf); mConversationArrayAdapter.add("Me: " + writeMessage); break; case MESSAGE_READ: byte[] readBuf = (byte[]) msg.obj; // construct a string from the valid bytes in the buffer String readMessage = new String(readBuf, 0, msg.arg1); mConversationArrayAdapter.add(mConnectedDeviceName+": " + readMessage); break; case MESSAGE_DEVICE_NAME: // save the connected device's name mConnectedDeviceName = msg.getData().getString(DEVICE_NAME); Toast.makeText(getApplicationContext(), "Connected to " + mConnectedDeviceName, Toast.LENGTH_SHORT).show(); break; case MESSAGE_TOAST: Toast.makeText(getApplicationContext(), msg.getData().getString(TOAST), Toast.LENGTH_SHORT).show(); break;

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  • Why does Internet Explorer break "pegman" display in Google Maps API v3?

    - by Chad
    On my site here, the SteetView control, aka "Pegman", works great under Firefox. Under IE (7 in this case, but tested on 8 as well - same result) it breaks the display of the pegman control. Here's my map code: var directionsDisplay; var directionsService = new google.maps.DirectionsService(); var map; directionsDisplay = new google.maps.DirectionsRenderer(); var milBase = new google.maps.LatLng(35.79648921414565, 139.40663874149323); var mapOpts = { streetViewControl: true, zoom: 12, center: milBase, mapTypeControlOptions: { style: google.maps.MapTypeControlStyle.DROPDOWN_MENU }, mapTypeId: google.maps.MapTypeId.ROADMAP }; map = new google.maps.Map($("#dirMap").get(0), mapOpts); directionsDisplay.setMap(map); var basePoly = new google.maps.Polygon({ paths: [new google.maps.LatLng(35.724496338474104, 139.3444061279297), new google.maps.LatLng(35.74748750802863, 139.3363380432129), new google.maps.LatLng(35.75765724051559, 139.34303283691406), new google.maps.LatLng(35.76545779822543, 139.3418312072754), new google.maps.LatLng(35.767547103447725, 139.3476676940918), new google.maps.LatLng(35.75835374997911, 139.34955596923828), new google.maps.LatLng(35.755149755962755, 139.3567657470703), new google.maps.LatLng(35.74679090345495, 139.35796737670898), new google.maps.LatLng(35.74762682821177, 139.36294555664062), new google.maps.LatLng(35.744422402303826, 139.36346054077148), new google.maps.LatLng(35.74860206266584, 139.36946868896484), new google.maps.LatLng(35.735644401200986, 139.36843872070312), new google.maps.LatLng(35.73843117306677, 139.36174392700195), new google.maps.LatLng(35.73592308277646, 139.3531608581543), new google.maps.LatLng(35.72686543236113, 139.35298919677734), new google.maps.LatLng(35.724496338474104, 139.3444061279297)], strokeColor: "#ff0000", strokeOpacity: 0.8, strokeWeight: 2, fillColor: "#FF0000", fillOpacity: 0.35 }); basePoly.setMap(map); var marker = new google.maps.Marker({ position: new google.maps.LatLng(35.79648921414565, 139.40663874149323), map: map, title: "Ruby International" }); function calcRoute() { var start = new google.maps.LatLng(35.74005964772476, 139.37083393335342); var end = new google.maps.LatLng(35.79648921414565, 139.40663874149323); var request = { origin: start, destination: end, travelMode: google.maps.DirectionsTravelMode.DRIVING }; directionsService.route(request, function(result, status) { if (status == google.maps.DirectionsStatus.OK) { directionsDisplay.setDirections(result); } }); } The only real difference from my code and Google's code is that I use jQuery's document ready function instead of the body onload event to initialize my map. Can't imagine that's the cause though (works in v2 of the maps). Have I found a bug or is there something wrong in my code? Thanks in advance!

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  • How do I break down an NSTimeInterval into year, months, days, hours, minutes and seconds on iPhone?

    - by willc2
    I have a time interval that spans years and I want all the time components from year down to seconds. My first thought is to integer divide the time interval by seconds in a year, subtract that from a running total of seconds, divide that by seconds in a month, subtract that from the running total and so on. That just seems convoluted and I've read that whenever you are doing something that looks convoluted, there is probably a built-in method. Is there? I integrated Alex's 2nd method into my code. It's in a method called by a UIDatePicker in my interface. NSDate *now = [NSDate date]; NSDate *then = self.datePicker.date; NSTimeInterval howLong = [now timeIntervalSinceDate:then]; NSDate *date = [NSDate dateWithTimeIntervalSince1970:howLong]; NSString *dateStr = [date description]; const char *dateStrPtr = [dateStr UTF8String]; int year, month, day, hour, minute, sec; sscanf(dateStrPtr, "%d-%d-%d %d:%d:%d", &year, &month, &day, &hour, &minute, &sec); year -= 1970; NSLog(@"%d years\n%d months\n%d days\n%d hours\n%d minutes\n%d seconds", year, month, day, hour, minute, sec); When I set the date picker to a date 1 year and 1 day in the past, I get: 1 years 1 months 1 days 16 hours 0 minutes 20 seconds which is 1 month and 16 hours off. If I set the date picker to 1 day in the past, I am off by the same amount. Update: I have an app that calculates your age in years, given your birthday (set from a UIDatePicker), yet it was often off. This proves there was an inaccuracy, but I can't figure out where it comes from, can you?

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  • How to remotely connect to jmx on tomcat using ssh tunnelling and not break ehcache...

    - by Unsavory
    I've followed the instructions in the following link to create my own RMI registry and jmx server on a single port inside tomcat. According to the comments, I need to set -Djava.rmi.server.hostname=localhost. Once I do that, I can indeed connect to my server via jconsole using ssh port forwarding. http://blogs.sun.com/jmxetc/entry/connecting_through_firewall_using_jmx However, I've found it has the very bad side affect of breaking our ehcache replication which uses RMI. It fails complaining that it cannot bootstrap from remote peer localhost. I'm guessing because the peers all have their rmi server hostname set to localhost from setting -Djava.rmi.server.hostname=localhost. Does anyone have a possible workaround to this problem?

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  • PHP: go back to the start of loop using a sort of 'break' ?

    - by matthy
    Hi i have a loop and i was wondering if there was a command that you can jump back to the start of the loop and ignore the rest of the code in the loop example: for ($index = 0; $index < 10; $index++) { if ($index == 6) that command to go the start of the loop echo "$index, "; } should output 1,2,3,4,5,7,8,9 and skip the six sort of same result as for ($index = 0; $index < 10; $index++) { if ($index != 6) echo "$index, "; } is there a command for that? thanks, matthy

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  • How do I break down MySQL query results into categories, each with a specific number of rows?

    - by Mel
    Hello, Problem: I want to list n number of games from each genre (order not important) The following MySQL query resides inside a ColdFusion function. It is meant to list all games under a platform (for example, list all PS3 games; list all Xbox 360 games; etc...). The variable for PlatformID is passed through the URL. I have 9 genres, and I would like to list 10 games from each genre. SELECT games.GameID AS GameID, games.GameReleaseDate AS rDate, titles.TitleName AS tName, titles.TitleShortDescription AS sDesc, genres.GenreName AS gName, platforms.PlatformID, platforms.PlatformName AS pName, platforms.PlatformAbbreviation AS pAbbr FROM (((games join titles on((games.TitleID = titles.TitleID))) join genres on((genres.GenreID = games.GenreID))) join platforms on((platforms.PlatformID = games.PlatformID))) WHERE (games.PlatformID = '#ARGUMENTS.PlatformID#') ORDER BY GenreName ASC, GameReleaseDate DESC Once the query results come back I group them in ColdFusion as follows: <cfoutput query="ListGames" group="gName"> (first loop which lists genres) #ListGames.gName# <cfoutput> (nested loop which lists games) #ListGames.tName# </cfoutput> </cfoutput> The problem is that I only want 10 games from each genre to be listed. If I place a "limit" of 50 in the SQL, I will get ~ 50 games of the same genre (depending on how much games of that genre there are). The second issue is I don't want the overload of querying the database for all games when each person will only look at a few. What is the correct way to do this? Many thanks!

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  • How do i break a number down into a percentage (0 - 100%)? Details inside...

    - by AJ
    I am using a JS progress bar that is set using a percentage: 0 to 100 (percent). I need the progress bar to reach 100% when 160,000 people have signed a certain form. I have the total number of signers set in a PHP variable but am lost on how to do the math to convert that into a percentage that fits within 1 - 100 (so that the progress bar actually reflects the goal of 160,000). I may be missing something obvious here (i suck at anything number-related) so does anyone here have a clue as to how to do this?

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  • Did iPhone Simulator 3.0 break two-finger div scrolling?

    - by Edward
    I recently upgraded to iPhone Simulator 3.0, and when I do a two-finger scroll on a div (in Safari or UIWebView), it no longer works. To do a two-finger scroll in iPhone simulator, hold option to get two fingers, hold shift to lock the fingers in place relative to eachother, and then click and drag the div. You can try scrolling the example div on this page: http://www.domedia.org/oveklykken/css-div-scroll.php Can anyone reproduce this?

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  • How do I break down MySQL query results into categories, each with a specific number of rows?

    - by Mel
    Hello, Problem: I want to list n number of games from each genre (order not important) The following MySQL query resides inside a ColdFusion function. It is meant to list all games under a platform (for example, list all PS3 games; list all Xbox 360 games; etc...). The variable for PlatformID is passed through the URL. I have 9 genres, and I would like to list 10 games from each genre. SELECT games.GameID AS GameID, games.GameReleaseDate AS rDate, titles.TitleName AS tName, titles.TitleShortDescription AS sDesc, genres.GenreName AS gName, platforms.PlatformID, platforms.PlatformName AS pName, platforms.PlatformAbbreviation AS pAbbr FROM (((games join titles on((games.TitleID = titles.TitleID))) join genres on((genres.GenreID = games.GenreID))) join platforms on((platforms.PlatformID = games.PlatformID))) WHERE (games.PlatformID = '#ARGUMENTS.PlatformID#') ORDER BY GenreName ASC, GameReleaseDate DESC Once the query results come back I group them in ColdFusion as follows: <cfoutput query="ListGames" group="gName"> (first loop which lists genres) #ListGames.gName# <cfoutput> (nested loop which lists games) #ListGames.tName# </cfoutput> </cfoutput> The problem is that I only want 10 games from each genre to be listed. If I place a "limit" of 50 in the SQL, I will get ~ 50 games of the same genre (depending on how much games of that genre there are). The second issue is I don't want the overload of querying the database for all games when each person will only look at a few. What is the correct way to do this? Many thanks!

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  • How does this code break the Law of Demeter?

    - by Dave Jarvis
    The following code breaks the Law of Demeter: public class Student extends Person { private Grades grades; public Student() { } /** Must never return null; throw an appropriately named exception, instead. */ private synchronized Grades getGrades() throws GradesException { if( this.grades == null ) { this.grades = createGrades(); } return this.grades; } /** Create a new instance of grades for this student. */ protected Grades createGrades() throws GradesException { // Reads the grades from the database, if needed. // return new Grades(); } /** Answers if this student was graded by a teacher with the given name. */ public boolean isTeacher( int year, String name ) throws GradesException, TeacherException { // The method only knows about Teacher instances. // return getTeacher( year ).nameEquals( name ); } private Grades getGradesForYear( int year ) throws GradesException { // The method only knows about Grades instances. // return getGrades().getForYear( year ); } private Teacher getTeacher( int year ) throws GradesException, TeacherException { // This method knows about Grades and Teacher instances. A mistake? // return getGradesForYear( year ).getTeacher(); } } public class Teacher extends Person { public Teacher() { } /** * This method will take into consideration first name, * last name, middle initial, case sensitivity, and * eventually it could answer true to wild cards and * regular expressions. */ public boolean nameEquals( String name ) { return getName().equalsIgnoreCase( name ); } /** Never returns null. */ private synchronized String getName() { if( this.name == null ) { this.name == ""; } return this.name; } } Questions How is the LoD broken? Where is the code breaking the LoD? How should the code be written to uphold the LoD?

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  • If I write an algorithm to encrypt a file, are their tools available to break the encryption?

    - by Andrew
    I have an idea for encryption that I could program fairly easily to encrypt some local text file. Given that my approach is novel, and does not use any of the industry standard encryption techniques, would I be able to test the strength of my encryption using 'cracker' apps or suchlike? Or do all those tools rely on advanced knowledge of the encryption process (or intercepted 'keys'), meaning I'd have to build my own cracker for testing?

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  • CakePHP: Why does adding 'Security' component break my app?

    - by Steve
    I have a strange problem -- of my own making -- that's cropped up, and is driving me crazy. At some point, I inadvertently destroyed a file in the app/tmp directory...I'm not sure which file. But now my app breaks when I include the "Security" component, and works just fine when it's not included. I'm thinking it might be related to the Security.salt value somehow, or possibly to the saved session info, but I don't really have a deep enough knowledge of CakePHP to figure it out. Can anyone offer any insight here?

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