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  • Annotating Graphs From Textual Data

    - by steven
    I've got a graph that was generated from a data set that contains: (date, value, annotation) The annotation is a constant value [its either there or is blank] and I would like to add in the third bit of data into the graph I have. An example of this is in the image. The blue line is a graph of the (date, value) graph, and I would like to add in the red dots as graphing (date, annotation@value). Is there an easy way to do this in excel, without having to modify the appearance of the data?

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  • How to change x-axis min/max of Column chart in Excel?

    - by Ian Boyd
    Here i have a column chart of binomial distribution, showing how many times you can expect to roll a six in 235 dice rolls: Note: You could also call it a binomial mass distribution for p=1/6, n=235 Now that graph is kinda squooshed. i'd like to change the Minimum and Maximum on the horizontal axis. i'd like to change them to: Minimum: 22 Maximum: 57 Meaning i want to zoom in on this section of the graph: Bonus points to the reader who can say how the numbers 22 and 57 were arrived at If this were a Scatter graph in Excel, i could adjust the horizintal axis minimum and maximum as i desired: Unfortunately, this is a Column chart, where there are no options to adjust the minimum and maximum limits of the ordinate axis: i can do a pretty horrible thing to the graph in Photoshop, but it's not very useful afterwards: Question: how to a change the x-axis minimum and maximum of a Column chart in Excel (2007)?

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  • Excel 2010: How to color the area between charts?

    - by Quasdunk
    Hello, I asked this question already on stackoverflow but it hasn't been answered yet. Instead I was advised to try it here, so here I go :) So there's that simple XY-Line-Chart in Excel (2010). It is surrounded by two other graphs which are parallel but offset by the same factor in both the positive and negative direction - something like this: ---------------- (positively offset parallel graph) ---------------- (main graph) ---------------- (negatively offset parallel graph) Now I want to color the space between the main graph and the offset ones, but I just can't seem to find a way! Is it maybe possible with VBA? Or is there maybe a solution for Excel 2007?

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  • Jung Meets the NetBeans Platform

    - by Geertjan
    Here's a small Jung diagram in a NetBeans Platform application: And the code, copied directly from the Jung 2.0 Tutorial:  public final class JungTopComponent extends TopComponent { public JungTopComponent() { initComponents(); setName(Bundle.CTL_JungTopComponent()); setToolTipText(Bundle.HINT_JungTopComponent()); setLayout(new BorderLayout()); Graph sgv = getGraph(); Layout<Integer, String> layout = new CircleLayout(sgv); layout.setSize(new Dimension(300, 300)); BasicVisualizationServer<Integer, String> vv = new BasicVisualizationServer<Integer, String>(layout); vv.setPreferredSize(new Dimension(350, 350)); add(vv, BorderLayout.CENTER); } public Graph getGraph() { Graph<Integer, String> g = new SparseMultigraph<Integer, String>(); g.addVertex((Integer) 1); g.addVertex((Integer) 2); g.addVertex((Integer) 3); g.addEdge("Edge-A", 1, 2); g.addEdge("Edge-B", 2, 3); Graph<Integer, String> g2 = new SparseMultigraph<Integer, String>(); g2.addVertex((Integer) 1); g2.addVertex((Integer) 2); g2.addVertex((Integer) 3); g2.addEdge("Edge-A", 1, 3); g2.addEdge("Edge-B", 2, 3, EdgeType.DIRECTED); g2.addEdge("Edge-C", 3, 2, EdgeType.DIRECTED); g2.addEdge("Edge-P", 2, 3); return g; } And here's what someone who attended a NetBeans Platform training course in Poland has done with Jung and the NetBeans Platform: The source code for the above is on Git: git://gitorious.org/j2t/j2t.git

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  • Finding all the shortest paths between two nodes in unweighted directed graphs using BFS algorithm

    - by andra-isan
    Hi All, I am working on a problem that I need to find all the shortest path between two nodes in a given directed unweighted graph. I have used BFS algorithm to do the job, but unfortunately I can only print one shortest path not all of them, for example if they are 4 paths having lenght 3, my algorithm only prints the first one but I would like it to print all the four shortest paths. I was wondering in the following code, how should I change it so that all the shortest paths between two nodes could be printed out? class graphNode{ public: int id; string name; bool status; double weight;}; map<int, map<int,graphNode>* > graph; int Graph::BFS(graphNode &v, graphNode &w){ queue <int> q; map <int, int> map1; // this is to check if the node has been visited or not. std::string str= ""; map<int,int> inQ; // just to check that we do not insert the same iterm twice in the queue map <int, map<int, graphNode>* >::iterator pos; pos = graph.find(v.id); if(pos == graph.end()) { cout << v.id << " does not exists in the graph " <<endl; return 1; } int parents[graph.size()+1]; // this vector keeps track of the parents for the node parents[v.id] = -1; // there is a direct path between these two words, simply print that path as the shortest path if (findDirectEdge(v.id,w.id) == 1 ){ cout << " Shortest Path: " << v.id << " -> " << w.id << endl; return 1; } //if else{ int gn; map <int, map<int, graphNode>* >::iterator pos; q.push(v.id); inQ.insert(make_pair(v.id, v.id)); while (!q.empty()){ gn = q.front(); q.pop(); map<int, int>::iterator it; cout << " Popping: " << gn <<endl; map1.insert(make_pair(gn,gn)); //backtracing to print all the nodes if gn is the same as our target node such as w.id if (gn == w.id){ int current = w.id; cout << current << " - > "; while (current!=v.id){ current = parents[current]; cout << current << " -> "; } cout <<endl; } if ((pos = graph.find(gn)) == graph.end()) { cout << " pos is empty " <<endl; continue; } map<int, graphNode>* pn = pos->second; map<int, graphNode>::iterator p = pn->begin(); while(p != pn->end()) { map<int, int>::iterator it; //map1 keeps track of the visited nodes it = map1.find(p->first); graphNode gn1= p->second; if (it== map1.end()) { map<int, int>::iterator it1; //if the node already exits in the inQ, we do not insert it twice it1 = inQ.find(p->first); if (it1== inQ.end()){ parents[p->first] = gn; cout << " inserting " << p->first << " into the queue " <<endl; q.push(p->first); // add it to the queue } //if } //if p++; } //while } //while } I do appreciate all your great help Thanks, Andra

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  • Oracle Unveils Industry’s Broadest Cloud Strategy

    - by kellsey.ruppel
    Oracle Unveils Industry’s Broadest Cloud Strategy Adds Social Cloud and Showcases early customers Redwood Shores, Calif. – June 6, 2012 “Almost seven years of relentless engineering and innovation plus key strategic acquisitions. An investment of billions. We are now announcing the most comprehensive Cloud on the planet Earth,” said Oracle CEO, Larry Ellison. “Most cloud vendors only have niche assets. They don’t have platforms to extend. Oracle is the only vendor that offers a complete suite of modern, socially-enabled applications, all based on a standards-based platform.” News Facts In a major strategy update today, Larry Ellison announced the industry’s broadest and most advanced Cloud strategy and introduced Oracle Cloud Social Services, a broad Enterprise Social Platform offering. Oracle Cloud delivers a broad set of industry-standards based, integrated services that provide customers with subscription-based access to Oracle Platform Services, Application Services, and Social Services, all completely managed, hosted and supported by Oracle. Offering a wide range of business applications and platform services, the Oracle Cloud is the only cloud to enable customers to avoid the data and business process fragmentation that occurs when using multiple, siloed public clouds. Oracle Cloud is powered by leading enterprise-grade infrastructure, including Oracle Exadata and Oracle Exalogic, providing customers and partners with a high-performance, reliable, and secure infrastructure for running critical business applications. Oracle Cloud enables easy self-service for both business users and developers. Business users can order, configure, extend, and monitor their applications. Developers and administrators can easily develop, deploy, monitor and manage their applications. As part of the event, Oracle also showcased several early Oracle Cloud customers and partners including system integrators and independent software vendors. Oracle Cloud Platform Services Built on a common, complete, standards-based and enterprise-grade set of infrastructure components, Oracle Cloud Platform Services enable customers to speed time to market and lower costs by quickly building, deploying and managing bespoke applications. Oracle Cloud Platform Services will include: Database Services to manage data and build database applications with the Oracle Database. Java Services to develop, deploy and manage Java applications with Oracle WebLogic. Developer Services to allow application developers to collaboratively build applications. Web Services to build Web applications rapidly using PHP, Ruby, and Python. Mobile Services to allow developers to build cross-platform native and HTML5 mobile applications for leading smartphones and tablets. Documents Services to allow project teams to collaborate and share documents through online workspaces and portals. Sites Services to allow business users to develop and maintain visually engaging .com sites Analytics Services to allow business users to quickly build and share analytic dashboards and reports through the Cloud. Oracle Cloud Application Services Oracle Cloud Application Services provides customers access to the industry’s broadest range of enterprise applications available in the cloud today, with built-in business intelligence, social and mobile capabilities. Easy to setup, configure, extend, use and administer, Oracle Cloud Application Services will include: ERP Services: A complete set of Financial Accounting, Project Management, Procurement, Sourcing, and Governance, Risk & Compliance solutions. HCM Services: A complete Human Capital Management solution including Global HR, Workforce Lifecycle Management, Compensation, Benefits, Payroll and other solutions. Talent Management Services: A complete Talent Management solution including Recruiting, Sourcing, Performance Management, and Learning. Sales and Marketing Services: A complete Sales and Marketing solution including Sales Planning, Territory Management, Leads & Opportunity Management, and Forecasting. Customer Experience Services: A complete Customer Service solution including Web Self-Service, Contact Centers, Knowledge Management, Chat, and e-mail Management. Oracle Cloud Social Services Oracle Cloud Social Services provides the most broad and complete enterprise social platform available in the cloud today.  With Oracle Cloud Social Services, enterprises can engage with their customers on a range of social media properties in a comprehensive and meaningful fashion including social marketing, commerce, service and listening. The platform also provides enterprises with a rich social networking solution for their employees to collaborate effectively inside the enterprise. Oracle’s integrated social platform will include: Oracle Social Network to enable secure enterprise collaboration and purposeful social networking for business. Oracle Social Data Services to aggregate data from social networks and enterprise data sources to enrich business applications. Oracle Social Marketing and Engagement Services to enable marketers to centrally create, publish, moderate, manage, measure and report on their social marketing campaigns. Oracle Social Intelligence Services to enable marketers to analyze social media interactions and to enable customer service and sales teams to engage with customers and prospects effectively. Supporting Resources Oracle Cloud – learn more cloud.oracle.com – sign up now Webcast – watch the replay About Oracle Oracle engineers hardware and software to work together in the cloud and in your data center. For more information about Oracle (NASDAQ:ORCL), visit www.oracle.com. TrademarksOracle and Java are registered trademarks of Oracle and/or its affiliates. Other names may be trademarks of their respective owners.

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  • Genetic algorithms with large chromosomes

    - by Howie
    I'm trying to solve the graph partitioning problem on large graphs (between a billion and trillion elements) using GA. The problem is that even one chromosome will take several gigs of memory. Are there any general compression techniques for chromosome encoding? Or should I look into distributed GA? NOTE: using some sort of evolutionary algorithm for this problem is a must! GA seems to be the best fit (although not for such large chromosomes). EDIT: I'm looking for state-of-the-art methods that other authors have used to solved the problem of large chromosomes. Note that I'm looking for either a more general solution or a solution particular to graph partitioning. Basically I'm looking for related works, as I, too, am attempting using GA for the problem of graph partitioning. So far I haven't found anyone that might have this problem of large chromosomes nor has tried to solve it.

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  • How/where to run the algorithm on large dataset?

    - by niko
    I would like to run the PageRank algorithm on graph with 4 000 000 nodes and around 45 000 000 edges. Currently I use neo4j graph databse and classic relational database (postgres) and for software projects I mostly use C# and Java. Does anyone know what would be the best way to perform a PageRank computation on such graph? Is there any way to modify the PageRank algorithm in order to run it at home computer or server (48GB RAM) or is there any useful cloud service to push the data along the algorithm and retrieve the results? At this stage the project is at the research stage so in case of using cloud service if possible, would like to use such provider that doesn't require much administration and service setup, but instead focus just on running the algorith once and get the results without much overhead administration work.

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  • How should I make searching a relational database more efficient?

    - by Travis J
    This is in the scope of a web application. I have a database which has a few nested relations. There is a feature which depicts the history of a large chain of relations. It is essentially a data analysis feature. The issue is that in order to search, a large object graph must be loaded - the loading time for this object graph is not quick enough to be viable. The problem is that without loading the whole graph it makes searching from a single string nearly impossible. In order to search, explicit fields must be specified and the search data supplied. Is there a design pattern for exposing the data in a way which facilitates a single string search instead of having to explicitly define parameters?

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  • SQL Server IO handling mechanism can be severely affected by high CPU usage

    - by sqlworkshops
    Are you using SSD or SAN / NAS based storage solution and sporadically observe SQL Server experiencing high IO wait times or from time to time your DAS / HDD becomes very slow according to SQL Server statistics? Read on… I need your help to up vote my connect item – https://connect.microsoft.com/SQLServer/feedback/details/744650/sql-server-io-handling-mechanism-can-be-severely-affected-by-high-cpu-usage. Instead of taking few seconds, queries could take minutes/hours to complete when CPU is busy.In SQL Server when a query / request needs to read data that is not in data cache or when the request has to write to disk, like transaction log records, the request / task will queue up the IO operation and wait for it to complete (task in suspended state, this wait time is the resource wait time). When the IO operation is complete, the task will be queued to run on the CPU. If the CPU is busy executing other tasks, this task will wait (task in runnable state) until other tasks in the queue either complete or get suspended due to waits or exhaust their quantum of 4ms (this is the signal wait time, which along with resource wait time will increase the overall wait time). When the CPU becomes free, the task will finally be run on the CPU (task in running state).The signal wait time can be up to 4ms per runnable task, this is by design. So if a CPU has 5 runnable tasks in the queue, then this query after the resource becomes available might wait up to a maximum of 5 X 4ms = 20ms in the runnable state (normally less as other tasks might not use the full quantum).In case the CPU usage is high, let’s say many CPU intensive queries are running on the instance, there is a possibility that the IO operations that are completed at the Hardware and Operating System level are not yet processed by SQL Server, keeping the task in the resource wait state for longer than necessary. In case of an SSD, the IO operation might even complete in less than a millisecond, but it might take SQL Server 100s of milliseconds, for instance, to process the completed IO operation. For example, let’s say you have a user inserting 500 rows in individual transactions. When the transaction log is on an SSD or battery backed up controller that has write cache enabled, all of these inserts will complete in 100 to 200ms. With a CPU intensive parallel query executing across all CPU cores, the same inserts might take minutes to complete. WRITELOG wait time will be very high in this case (both under sys.dm_io_virtual_file_stats and sys.dm_os_wait_stats). In addition you will notice a large number of WAITELOG waits since log records are written by LOG WRITER and hence very high signal_wait_time_ms leading to more query delays. However, Performance Monitor Counter, PhysicalDisk, Avg. Disk sec/Write will report very low latency times.Such delayed IO handling also occurs to read operations with artificially very high PAGEIOLATCH_SH wait time (with number of PAGEIOLATCH_SH waits remaining the same). This problem will manifest more and more as customers start using SSD based storage for SQL Server, since they drive the CPU usage to the limits with faster IOs. We have a few workarounds for specific scenarios, but we think Microsoft should resolve this issue at the product level. We have a connect item open – https://connect.microsoft.com/SQLServer/feedback/details/744650/sql-server-io-handling-mechanism-can-be-severely-affected-by-high-cpu-usage - (with example scripts) to reproduce this behavior, please up vote the item so the issue will be addressed by the SQL Server product team soon.Thanks for your help and best regards,Ramesh MeyyappanHome: www.sqlworkshops.comLinkedIn: http://at.linkedin.com/in/rmeyyappan

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  • Synchronous Actions

    - by Dan Krasinski-Oracle
    Since the introduction of SMF, svcadm(1M) has had the ability to enable or disable a service instance and wait for that service instance to reach a final state.  With Oracle Solaris 11.2, we’ve expanded the set of administrative actions which can be invoked synchronously. Now all subcommands of svcadm(1M) have synchronous behavior. Let’s take a look at the new usage: Usage: svcadm [-v] [cmd [args ... ]] svcadm enable [-rt] [-s [-T timeout]] <service> ... enable and online service(s) svcadm disable [-t] [-s [-T timeout]] <service> ... disable and offline service(s) svcadm restart [-s [-T timeout]] <service> ... restart specified service(s) svcadm refresh [-s [-T timeout]] <service> ... re-read service configuration svcadm mark [-It] [-s [-T timeout]] <state> <service> ... set maintenance state svcadm clear [-s [-T timeout]] <service> ... clear maintenance state svcadm milestone [-d] [-s [-T timeout]] <milestone> advance to a service milestone svcadm delegate [-s] <restarter> <svc> ... delegate service to a restarter As you can see, each subcommand now has a ‘-s’ flag. That flag tells svcadm(1M) to wait for the subcommand to complete before returning. For enables, that means waiting until the instance is either ‘online’ or in the ‘maintenance’ state. For disable, the instance must reach the ‘disabled’ state. Other subcommands complete when: restart A restart is considered complete once the instance has gone offline after running the ‘stop’ method, and then has either returned to the ‘online’ state or has entered the ‘maintenance’ state. refresh If an instance is in the ‘online’ state, a refresh is considered complete once the ‘refresh’ method for the instance has finished. mark maintenance Marking an instance for maintenance completes when the instance has reached the ‘maintenance’ state. mark degraded Marking an instance as degraded completes when the instance has reached the ‘degraded’ state from the ‘online’ state. milestone A milestone transition can occur in one of two directions. Either the transition moves from a lower milestone to a higher one, or from a higher one to a lower one. When moving to a higher milestone, the transition is considered complete when the instance representing that milestone reaches the ‘online’ state. The transition to a lower milestone, on the other hand, completes only when all instances which are part of higher milestones have reached the ‘disabled’ state. That’s not the whole story. svcadm(1M) will also try to determine if the actions initiated by a particular subcommand cannot complete. Trying to enable an instance which does not have its dependencies satisfied, for example, will cause svcadm(1M) to terminate before that instance reaches the ‘online’ state. You’ll also notice the optional ‘-T’ flag which can be used in conjunction with the ‘-s’ flag. This flag sets a timeout, in seconds, after which svcadm gives up on waiting for the subcommand to complete and terminates. This is useful in many cases, but in particular when the start method for an instance has an infinite timeout but might get stuck waiting for some resource that may never become available. For the C-oriented, each of these administrative actions has a corresponding function in libscf(3SCF), with names like smf_enable_instance_synchronous(3SCF) and smf_restart_instance_synchronous(3SCF).  Take a look at smf_enable_instance_synchronous(3SCF) for details.

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  • Can't update scala on Gentoo

    - by xhochy
    As I wanted to test Scala 2.9.2 on my gentoo system I tried updated the package but ended up with this error. I can't figure out where the problem may be: Calculating dependencies ...... done! >>> Verifying ebuild manifests >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> Emerging (1 of 1) dev-lang/scala-2.9.2 >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> Failed to emerge dev-lang/scala-2.9.2, Log file: >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> '/var/tmp/portage/dev-lang/scala-2.9.2/temp/build.log' >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> Jobs: 0 of 1 complete, 1 running, 1 failed Load avg: 0.23, 0.16, 0.20 >>> Jobs: 0 of 1 complete, 1 failed Load avg: 0.23, 0.16, 0.20 * Package: dev-lang/scala-2.9.2 * Repository: gentoo * Maintainer: [email protected] * USE: amd64 elibc_glibc kernel_linux multilib userland_GNU * FEATURES: sandbox [01m[31;06m!!! ERROR: Couldn't find suitable VM. Possible invalid dependency string. Due to jdk-with-com-sun requiring a target of 1.7 but the virtual machines constrained by virtual/jdk-1.6 and/or this package requiring virtual(s) jdk-with-com-sun[0m * Unable to determine VM for building from dependencies: NV_DEPEND: virtual/jdk:1.6 java-virtuals/jdk-with-com-sun !binary? ( dev-java/ant-contrib:0 ) app-arch/xz-utils >=dev-java/java-config-2.1.9-r1 source? ( app-arch/zip ) >=dev-java/ant-core-1.7.0 dev-java/ant-nodeps >=dev-java/javatoolkit-0.3.0-r2 >=dev-lang/python-2.4 * ERROR: dev-lang/scala-2.9.2 failed (setup phase): * Failed to determine VM for building. * * Call stack: * ebuild.sh, line 93: Called pkg_setup * scala-2.9.2.ebuild, line 43: Called java-pkg-2_pkg_setup * java-pkg-2.eclass, line 53: Called java-pkg_init * java-utils-2.eclass, line 2187: Called java-pkg_switch-vm * java-utils-2.eclass, line 2674: Called die * The specific snippet of code: * die "Failed to determine VM for building." * * If you need support, post the output of `emerge --info '=dev-lang/scala-2.9.2'`, * the complete build log and the output of `emerge -pqv '=dev-lang/scala-2.9.2'`. !!! When you file a bug report, please include the following information: GENTOO_VM= CLASSPATH="" JAVA_HOME="" JAVACFLAGS="" COMPILER="" and of course, the output of emerge --info * The complete build log is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/build.log'. * The ebuild environment file is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/die.env'. * Working directory: '/var/tmp/portage/dev-lang/scala-2.9.2' * S: '/var/tmp/portage/dev-lang/scala-2.9.2/work/scala-2.9.2-sources' * Messages for package dev-lang/scala-2.9.2: * Unable to determine VM for building from dependencies: * ERROR: dev-lang/scala-2.9.2 failed (setup phase): * Failed to determine VM for building. * * Call stack: * ebuild.sh, line 93: Called pkg_setup * scala-2.9.2.ebuild, line 43: Called java-pkg-2_pkg_setup * java-pkg-2.eclass, line 53: Called java-pkg_init * java-utils-2.eclass, line 2187: Called java-pkg_switch-vm * java-utils-2.eclass, line 2674: Called die * The specific snippet of code: * die "Failed to determine VM for building." * * If you need support, post the output of `emerge --info '=dev-lang/scala-2.9.2'`, * the complete build log and the output of `emerge -pqv '=dev-lang/scala-2.9.2'`. * The complete build log is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/build.log'. * The ebuild environment file is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/die.env'. * Working directory: '/var/tmp/portage/dev-lang/scala-2.9.2' * S: '/var/tmp/portage/dev-lang/scala-2.9.2/work/scala-2.9.2-sources' The following eix output may help: % eix java-virtuals/jdk-with-com-sun [I] java-virtuals/jdk-with-com-sun Available versions: 20111111 {{ELIBC="FreeBSD"}} Installed versions: 20111111(16:08:51 18/04/12)(ELIBC="-FreeBSD") Homepage: http://www.gentoo.org Description: Virtual ebuilds that require internal com.sun classes from a JDK Both virtual jdks 1.6 and 1.7 are installed: % eix virtual/jdk [I] virtual/jdk Available versions: (1.4) ~1.4.2-r1[1] (1.5) 1.5.0 ~1.5.0-r3[1] (1.6) 1.6.0 1.6.0-r1 (1.7) (~)1.7.0 Installed versions: 1.6.0-r1(1.6)(23:22:48 10/11/12) 1.7.0(1.7)(23:21:09 10/11/12) Description: Virtual for JDK [1] "java-overlay" /var/lib/layman/java-overlay

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  • Sabnzbd Installed on Linux NAS

    - by Mike Szp.
    I installed SABnzbd on a linux formatted NAS. Now the directory it downloads to is mapped differently on the NAS itself, because the path that SABnzbd knows about starts in it's own folder. If this sounds confusing let me give you an example: \\MYNAS\Volume_1\ That is the path of the drive on the NAS. I would like my SABnzbd downloads to go to: \\MYNAS\Volume_1\Downloads Right now SABnzbd is installed to: \\MYNAS\Volume_1\ffp\opt\optware\share\SABnzbd And the default download directory (as indicated in SABnzbd is): /ffp/opt/optware/share/SABnzbd/downloads/complete I know that the mapping is different somehow because It is installed on the NAS, but I just am lost as to what I should do. So far, I have tried for the complete folder: /192.168.restofip/Volume_1/downloads/complete /Volumes/Volume_1/downloads/complete /Volume_1/downloads/complete Does anyone know how to change the path so that I can have it download to one of the topmost folders on the NAS instead of having it download to a folder so deep in the drive?

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  • Servlet : Usage of Constants.java class vs context param

    - by Pongsakorn Semsuwan
    I'm just wondering whether to keep some of my variables in Constants class or keep it in web.xml Say, I want to keep a variable of Facebook graph API prefix or api_key, client_id From my understand, the difference between Constants.java and web.xml is web.xml is easier to rewrite on compile using ant. So, you can replace your variables in web.xml according to what environment you are building you app for. (client_id varies by development environment/production environment, for example) If I understand it right, then Facebook graph API prefix should be kept in Constants.java (because it always is "https://graph.facebook.com/") and api_key, client_id should be kept in web.xml? What's the proper way to use them?

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  • Facebook Insights numbers don't add up

    - by ChristopherJ
    I'm having trouble understanding the Facebook stats for a Fan page under reach as they don't seem to add up. Under the reach tab, if I expand the countries demographics at the top, then the countries listed add up to around 16k people. But scrolling down under reach, the graph reaches as high as 260k in a particular week. From what they say, it seems that both the graph and demographics are talking about unique users, so where are the other 244k unique users that are in the graph but seemingly not from any country on Earth?

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  • How to compare page views/visitors to site totals in Google Analytics?

    - by frntk
    I want to measure the effects in total traffic (views or visitors) of a single URL across a time frame. For example, let's say I published a blog post on July 2012. I want to measure what chunk of the site's total traffic is coming to this particular post on a month-by-month graph from July 2012 to date. Is there a way to do this? Edit: I should clarify that what I'd like to do is to generate a month-to-month graph, similar to the one you can see comparing a metric on a period of time against the previous equivalent period (year vs last year, for example) but comparing a particular URL traffic to the site's total traffic. In other words, I can get to the part where I can see the URL's traffic for the timeframe I selected and it shows how much of the total traffic corresponds to the current URL: But I'd like to add a second line to the graph, representing the site's total pageviews, similiar to this (but this one is showing just a different metric for the same URL): Thanks!

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  • creating objects from trivial graph format text file. java. dijkstra algorithm.

    - by user560084
    i want to create objects, vertex and edge, from trivial graph format txt file. one of programmers here suggested that i use trivial graph format to store data for dijkstra algorithm. the problem is that at the moment all the information, e.g., weight, links, is in the sourcecode. i want to have a separate text file for that and read it into the program. i thought about using a code for scanning through the text file by using scanner. but i am not quite sure how to create different objects from the same file. could i have some help please? the file is v0 Harrisburg v1 Baltimore v2 Washington v3 Philadelphia v4 Binghamton v5 Allentown v6 New York # v0 v1 79.83 v0 v5 81.15 v1 v0 79.75 v1 v2 39.42 v1 v3 103.00 v2 v1 38.65 v3 v1 102.53 v3 v5 61.44 v3 v6 96.79 v4 v5 133.04 v5 v0 81.77 v5 v3 62.05 v5 v4 134.47 v5 v6 91.63 v6 v3 97.24 v6 v5 87.94 and the dijkstra algorithm code is Downloaded from: http://en.literateprograms.org/Special:Downloadcode/Dijkstra%27s_algorithm_%28Java%29 */ import java.util.PriorityQueue; import java.util.List; import java.util.ArrayList; import java.util.Collections; class Vertex implements Comparable<Vertex> { public final String name; public Edge[] adjacencies; public double minDistance = Double.POSITIVE_INFINITY; public Vertex previous; public Vertex(String argName) { name = argName; } public String toString() { return name; } public int compareTo(Vertex other) { return Double.compare(minDistance, other.minDistance); } } class Edge { public final Vertex target; public final double weight; public Edge(Vertex argTarget, double argWeight) { target = argTarget; weight = argWeight; } } public class Dijkstra { public static void computePaths(Vertex source) { source.minDistance = 0.; PriorityQueue<Vertex> vertexQueue = new PriorityQueue<Vertex>(); vertexQueue.add(source); while (!vertexQueue.isEmpty()) { Vertex u = vertexQueue.poll(); // Visit each edge exiting u for (Edge e : u.adjacencies) { Vertex v = e.target; double weight = e.weight; double distanceThroughU = u.minDistance + weight; if (distanceThroughU < v.minDistance) { vertexQueue.remove(v); v.minDistance = distanceThroughU ; v.previous = u; vertexQueue.add(v); } } } } public static List<Vertex> getShortestPathTo(Vertex target) { List<Vertex> path = new ArrayList<Vertex>(); for (Vertex vertex = target; vertex != null; vertex = vertex.previous) path.add(vertex); Collections.reverse(path); return path; } public static void main(String[] args) { Vertex v0 = new Vertex("Nottinghill_Gate"); Vertex v1 = new Vertex("High_Street_kensignton"); Vertex v2 = new Vertex("Glouchester_Road"); Vertex v3 = new Vertex("South_Kensignton"); Vertex v4 = new Vertex("Sloane_Square"); Vertex v5 = new Vertex("Victoria"); Vertex v6 = new Vertex("Westminster"); v0.adjacencies = new Edge[]{new Edge(v1, 79.83), new Edge(v6, 97.24)}; v1.adjacencies = new Edge[]{new Edge(v2, 39.42), new Edge(v0, 79.83)}; v2.adjacencies = new Edge[]{new Edge(v3, 38.65), new Edge(v1, 39.42)}; v3.adjacencies = new Edge[]{new Edge(v4, 102.53), new Edge(v2, 38.65)}; v4.adjacencies = new Edge[]{new Edge(v5, 133.04), new Edge(v3, 102.53)}; v5.adjacencies = new Edge[]{new Edge(v6, 81.77), new Edge(v4, 133.04)}; v6.adjacencies = new Edge[]{new Edge(v0, 97.24), new Edge(v5, 81.77)}; Vertex[] vertices = { v0, v1, v2, v3, v4, v5, v6 }; computePaths(v0); for (Vertex v : vertices) { System.out.println("Distance to " + v + ": " + v.minDistance); List<Vertex> path = getShortestPathTo(v); System.out.println("Path: " + path); } } } and the code for scanning file is import java.util.Scanner; import java.io.File; import java.io.FileNotFoundException; public class DataScanner1 { //private int total = 0; //private int distance = 0; private String vector; private String stations; private double [] Edge = new double []; /*public int getTotal(){ return total; } */ /* public void getMenuInput(){ KeyboardInput in = new KeyboardInput; System.out.println("Enter the destination? "); String val = in.readString(); return val; } */ public void readFile(String fileName) { try { Scanner scanner = new Scanner(new File(fileName)); scanner.useDelimiter (System.getProperty("line.separator")); while (scanner.hasNext()) { parseLine(scanner.next()); } scanner.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } } public void parseLine(String line) { Scanner lineScanner = new Scanner(line); lineScanner.useDelimiter("\\s*,\\s*"); vector = lineScanner.next(); stations = lineScanner.next(); System.out.println("The current station is " + vector + " and the destination to the next station is " + stations + "."); //total += distance; //System.out.println("The total distance is " + total); } public static void main(String[] args) { /* if (args.length != 1) { System.err.println("usage: java TextScanner2" + "file location"); System.exit(0); } */ DataScanner1 scanner = new DataScanner1(); scanner.readFile(args[0]); //int total =+ distance; //System.out.println(""); //System.out.println("The total distance is " + scanner.getTotal()); } }

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  • C# TextBox Autocomplete (Winforms) key events and customization?

    - by m0s
    Hi, I was wondering if it is possible to catch key events for auto-complete list. For example instead of Enter key press for auto-complete use lets say Tab key. Also is it possible to change the colors and add background image for the auto-complete pop-up list? Currently I have my own implementation which is a separate window(form) with a list-box, which works OK, but Id really like to use .net's auto-complete if it can do what I need. Thanks for attention.

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  • Mike Cohn-style burndown charts in JIRA

    - by Fuzzy Purple Monkey
    We use Jira/Greenhopper for our project planning/tracking. The built-in graphs are great, but when a new issue/story is added during a project, the whole burn-down graph moves up rather than increasing the part of the graph when the issue was added. Ideally I'd like to generate a Mike Cohn-style burndown graph, which shows a hump when new issues are added. Does anyone know of any plugins that support this, or been able to extract this data directly from the database?

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  • fluent nhibernate select n+1 problem

    - by Andrew Bullock
    I have a fairly deep object graph (5-6 nodes), and as I traverse portions of it NHProf is telling me I've got a "Select N+1" problem (which I do). The two solutions I'm aware of are Eager load children Break apart my object graph (and eager load) I don't really want to do either of these (although I may break the graph apart later as I forsee it growing) For now.... Is it possible to tell NHibernate (with fluentnhib) that whenever i try to access children, to load them all in one go, instead of selectn+1ing as i iterate over them? I'm also getting "unbounded results set"s, which is presumably the same problem (or rather, will be solved by the above solution if possible). Each child collection (throughout the graph) will only ever have about 20 members, but 20^5 is a lot, so i dont want to eager load everything when i get the root, but simply get all of a child collection whenever i go near it Edit: an afterthought.... what if i want to introduce paging when i want to render children? do i HAVE to break my object graph here, or is there some sneakyness i can employ to solve all these issues?

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  • Plot Title/Annotation

    - by Kevin
    Hello, I want to add a title to my graph that gives a short description or name about the plot. For example, I have a table with a list of products and my graph shows how much those products cost. There should be a label/annotation superimposed on the graph that gives the name of the product.

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  • Parallel curve like algorithm for graphs

    - by skrat
    Is there a well know algorithm for calculating "parallel graph"? where by parallel graph I mean the same as parallel curve, vaguely called "offset curve", but with a graph instead of a curve. Given this picture how can I calculate points of black outlined polygons?

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