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  • Mysql Query is not working, why?

    - by Furkan Kadioglu
    Im using this example: www.jtable.org Now i download to jtable php version. And i edited script. Jtable simple version is working but my edition is doesnt working. I can do list, but i cant do add a row; this codes having problem. But php doesnt giving any error. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } if you doesnt understand, please ask me question. Where is the problem?

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  • can't upload greater 50MB

    - by Syom
    i want to upload two files. here is the script <? ini_set('memory_limit', "400M"); ini_set('file_uploads', "5"); ini_set('max_execution_time', "900"); ini_set('upload_max_filesize', "400M"); ini_set('post_max_size', "400M"); ?> <form action="form.php" method="post" enctype="multipart/form-data" /> <input type="file" name="video" /> <input type="file" name="picture" > <input type="submit" class="input" value="?????" /> </form> form.php: <? ini_set('memory_limit', "400M"); ini_set('file_uploads', "5"); ini_set('max_execution_time', "900"); ini_set('upload_max_filesize', "400M"); ini_set('post_max_size', "400M"); print_r($_FILES); //returns Array ( ) ?> i've asked about this question here , and i've set ini_set(...) as you see, but when i try to upload the file greater than 50MB, it doesn't happen. could you tell me why?

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  • Change HTML DropDown Default Value with a MySQL value

    - by fzr11017
    I'm working on a profile page, where a registered user can update their information. Because the user has already submitted their information, I would like their information from the database to populate my HTML form. Within PHP, I'm creating the HTML form with the values filled in. However, I've tried creating an IF statement to determine whether an option is selected as the default value. Right now, my website is giving me a default value of the last option, Undeclared. Therefore, I'm not sure if all IF statements are evaluation as true, or if it is simply skipping to selected=selected. Here is my HTML, which is currently embedded with PHP(): <select name="Major"> <option if($row[Major] == Accounting){ selected="selected"}>Accounting</option> <option if($row[Major] == Business Honors Program){ selected="selected"}>Business Honors Program</option> <option if($row[Major] == Engineering Route to Business){ selected="selected"}>Engineering Route to Business</option> <option if($row[Major] == Finance){ selected="selected"}>Finance</option> <option if($row[Major] == International Business){ selected="selected"}>International Business</option> <option if($row[Major] == Management){ selected="selected"}>Management</option> <option if($row[Major] == Management Information Systems){ selected="selected"}>Management Information Systems</option> <option if($row[Major] == Marketing){ selected="selected"}>Marketing</option> <option if($row[Major] == MPA){ selected="selected"}>MPA</option> <option if($row[Major] == Supply Chain Management){ selected="selected"}>Supply Chain Management</option> <option if($row[Major] == Undeclared){ selected="selected"}>Undeclared</option> </select>

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  • Email server; Is this method spam-safe?

    - by Camran
    I have a classifieds website, and on each classified there is a tip-form where users may tip a friend about the classified. The tip-forms' action is set to a php-page, which mails the email after sanitizing etc... I have to filter away spam etc so that my email-server don't get blacklisted or anything... I have my own server (VPS, Linux) and have thought about a solution... How does this sound to you: 1- Install a mail-server 2- Configure Firewall to ONLY allow connections to the mail-server from my website 3- Configure the mail-server so that a maximum of 'x' emails may be sent every 5 minutes or so 4- Create a php filter before sending the mail, which checks for 'bad' words. 5- If necessary, as last resort, ask the user a question (ex 5+5) before submitting form I would rather preferr if I didn't have to implement the 5th implementation above... What do you think? Also, another q I have that you may answer is: If an email-server gets blacklisted, is there any way to un-blacklist it? Or whats the solution if this happens? Thanks

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  • Random Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the old and updated version of the code: New php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Old PHP: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will this first code guarantee uniqueness?

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  • Add values to an array after isset()

    - by user1656692
    I'm trying to add elements to an array after subsequent trials, but so far only one value is being added to the array. I've Googled and searched stackoverflow, and I seem to be getting only half the picture unless if I'm implementing it wrong. There are about 40 files, which will be needed to be submited one after another, and then a value from each trial is stored in the database. So far, this is what I've done. $_SESSION['task2'] = array(); //Submit Task 1 if (isset($_POST['submit_task_01'])) { $trial1_ac_sec = cleanInput($_POST['clockInputTask_01ac']); $trial1_est_sec = cleanInput($_POST['clockInputTask_01']); $trial1_ac = round(($trial1_ac_sec * 42.67), 2); $trial1_est = round(($trial1_est_sec * 42.67), 2); $trial1_judgErr = $trial1_ac - $trial1_est; $trial_1error = round($trial1_judgErr, 2); array_push($_SESSION['task2'],$trial_1error); header("location: Trial_2.php"); } //Submit Task2 if (isset($_POST['submit_task_02'])) { $trial2_ac_sec = cleanInput($_POST['clockInputTask_02ac']); $trial2_est_sec = cleanInput($_POST['clockInputTask_02']); $trial2_ac = round(($trial2_ac_sec * 42.67), 2); $trial2_est = round(($trial2_est_sec * 42.67), 2); $trial2_judgErr = $trial2_ac - $trial2_est; $trial_2error = round($trial2_judgErr, 2); array_push($_SESSION['task2'],$trial_2error); header("location: newEmptyPHPWebPage.php"); } ... and so on.. up until 40 I'm just wondering what am I doing wrong, I know that each time isset() will reload the page, and the previous data won't be available, so in that sense I thought I'd create an array for sessions and then push data in the session, however that doesn't seem to work. If anyone has any ideas on what I can do, I'll greatly appreciate it. Thank You.

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  • After mysql_query, no result output

    - by Jerry
    I have a simple mysql_query() update command to update mysql. When a user submits my form, it will jump to an update page to update the data. The problem is that there's supposed to be some data shown after the update, but it comes out blank. My form <form id="form1" method="POST" action="scheduleUpdate.php" > <select name=std1> <option>AA</option> <option>BB</option> <option>CC</option> </select> <select name=std2> <option>DD</option> <option>EE</option> <option>FF</option> </select> .......//more drop down menu but the name is std3..std4..etc... ....... </form> scheduleUpdate.php //$i is the value posted from my main app to tell me how many std we have for($k=0;$k<$i;$k++){ $std=$_POST['std'.$k]; //if i remove the updateQuery, the html will output.I know the query is the problem but i //couldn't fix it.. $updateQuery=mysql_query("UPDATE board SET student='$std' WHERE badStudent='$std' or goodStudent='$std'",$connection); //no output below this line at all if($updateQuery){ DIE('mysql Error:'+mysql_error()); } } // I have bunch of HTML here....but no output at all!!!! MySQL will be updated after I hit submit, but it doesn't shown any HTML.

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  • Assistance with CC Processing script

    - by JM4
    I am currently implementing a credit card processing script, most as provided by the merchant gateway. The code calls functions within a class and returns a string based on the response. The end php code I am using (details removed of course) with example information is: <?php $gw = new gwapi; $gw->setLogin("username", "password"); $gw->setBilling("John","Smith","Acme, Inc.","888","Suite 200", "Beverly Hills", "CA","77777","US","555-555-5555","555-555-5556","[email protected]", "www.example.com"); // "CA","90210","US","[email protected]"); $gw->setOrder("1234","Big Order",1, 2, "PO1234","65.192.14.10"); $r = $gw->doSale("1.00","4111111111111111","1010"); print $gw->responses['responsetext']; ?> where setlogin allows me to login, setbilling takes the sample consumer information, set order takes the order id and description, dosale takes the amount charged, cc number and exp date. when all the variables are sent validated then sent off for processing, a string is returned in the following format: response=1&responsetext=SUCCESS&authcode=123456&transactionid=23456&avsresponse=M&orderid=&type=sale&response_code=100 where: response = transaction approved or declined response text = textual response authcode = transaction authorization code transactionid = payment gateway tran id avsresponse = avs response code orderid = original order id passed in tran request response_code = numeric mapping of processor response I am trying to solve for the following: How do I take the data which is passed back and display it appropriately on the page - If the transaction failed or AVS code doesnt match my liking or something is wrong, an error is displayed to the consumer; if the transaction processed, they are taken to a completion page and the transaction id is sent in SESSION as output to the consumer If the response_code value matches a table of values, certain actions are taken, i.e. if code =100, take to success page, if code = 300 print specific error on original page to customer, etc.

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  • Create 2nd tables and add data

    - by Tyler Matema
    I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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  • A problem of a repeated parameter in the pagination links?

    - by myaccount
    The problem is that when I load page 2 for example the URL becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2 And that's fine but when I get to page 3 it becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2&currentpage=3 And so on, it adds one more currentpage parameter everytime a new page is loaded from the pagination links! I wonder how this problem can be fixed? Here's some of the pagination function's code /****** build the pagination links ******/ // Getting current page URL with its parameters $current_page_url = ($_SERVER["PHP_SELF"].(isset($_SERVER["QUERY_STRING"])?"?".htmlentities($_SERVER["QUERY_STRING"]):"")); // Determine which sign to use (? or &) before the (currentpage=xx) parameter $sign = preg_match('/\?/', $current_page_url) ? '&' : '?'; $pagination_links = ''; // if not on page 1, don't show back links if ($currentpage > 1) { // show << link to go back to page 1 $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=1'>First page</a> "; // get previous page num $prevpage = $currentpage - 1; // show < link to go back 1 page $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=$prevpage'>previous</a> "; } else { $pagination_links .= "? ?"; }// end if

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  • Joomla get plugin id

    - by Christian Sciberras
    I wrote a Joomla plugin which will eventually load a library. The path to library is a plugin parameter, as such when the path is incorrect, a message pops up in the backend, together with a link to edit the plugin parameters: /administrator/index.php?option=com_plugins&view=plugin&client=site&task=edit&cid[]=36 See the 36 at the end? That's my plugin's id in the database (table jos_plugins). My issue is that this id changes on installation, ie, on different installs, it would be something else. So I need to find this id programmatically. The problem is that I couldn't find this id from the plugin object itself (as to why not, that would be joomla's arguably short-sighted design decision). So unless you know about some neat trick, (I've checked and double checked JPlugin and JPluginHelper classes), I'll be using the DB. Edit; Some useful links: http://docs.joomla.org/Plugin_Developer_Overview http://api.joomla.org/Joomla-Framework/Plugin/JPlugin.html http://api.joomla.org/Joomla-Framework/Plugin/JPluginHelper.html http://forum.joomla.org/viewtopic.php?p=2227737 Guess I'll be using the wisdom from that last link...

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  • Custom stream wrappers, what could they be useful for in web applications?

    - by michael
    I suppose the concept is language agnostic, but I don't know what it's called in other languages. In PHP they're Stream Wrappers. In short, a wrapper class that allows manipulation of a streamable resource (resource that can be read to/written to/seek into, such as a file, a db, an url). For example, in a template engine (a view), upon including a template file such as: include "view.wrapper://path/to/my/template/file.phtml"; my custom wrapper, declared elsewhere and associated with "view.wrapper", would first intercepts the file to replace such things as short tags (<?=) with a more verbose counterpart (<?php echo). This allows developers to use short tags in views, even if the server isn't set to allow it. It can also be applied to the preprocessing of views pseudo syntax such as {@myVar} (e.g. replacing it with $this->myVar). This is only one application of custom stream wrappers, but the feature seems powerful enough to make me think that there are others that could make life a lot simpler for developers. What have you built, or thought about building, custom stream wrappers for? where have you seen some interesting implementations? I'm particularly interested in their applications in web development.

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  • Silverstripe: outputting DataObjectManager in template include

    - by Fraser
    I have followed the tutorial here http://doc.silverstripe.org/old/modules:dataobjectmanager to create a dataobjectmanager in my CMS. It's all working perfectly there however I am having an issue getting it to output in the template. My code is as follows <?php class InfoArea extends DataObject{ static $db = array( 'Title' => 'Varchar(255)', 'Content' => 'HTMLText' ); static $has_one = array( 'ResortPage' => 'ResortPage' ); public function getCMSFields_forPopup(){ return new FieldSet( new TextField('Title'), new SimpleTinyMCEField('Content') ); } } ResortPage.php ....... static $has_many = array ( "InfoAreas" => "InfoArea" ); ....... $fields->addFieldToTab("Root.Content.AdditionalInformation", new DataObjectManager( $this, 'InfoAreas', 'InfoArea', array('Title' => 'Title','Content'=>'Content'), 'getCMSFields_forPopup' )); ........ I have a template "ResortPage.ss" which has an include "ResortInfo.ss". It is from within this include file that I need to output the DataObject. I have tried the below but it doesn't output anything <% control InfoArea %> $Title $Content <% end_control %> What am I doing wrong here? Thanks

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  • MySQL table doesn't update, can't find the error message

    - by mobius1ski
    My knowledge level here is like zilch, but please bear with me. I have a site built in PHP/MySQL that uses the Smarty template engine. There's a registration form that, for some reason, isn't posting the data to the DB. Here's the function: $u = new H_User; $u->setFrom($p); $smarty->assign('user', $u); $val = $u->validate(); if ($val === true) { $temp = new H_User; $temp->orderBy('user_id desc'); $temp->find(true); $next_id = $temp->user_id + 1; $u->user_id = $next_id; $u->user_password = md5($p['user_password']); $u->user_regdate = mktime(); $u->user_active = 0; $u->insert(); $hash = md5($u->user_email . $u->user_regdate); $smarty->assign('hash', $hash); $smarty->assign('user', $u); $smarty->assign('registration_complete', true); $d = new H_Demographic; $d->setFrom($p); $d->insert(); How can I figure out what's wrong here? I don't get any PHP errors and I don't know how to get MySQL to display the errors that might indicate what's wrong with that syntax.

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  • Test a database conection without codeigniter throwing a fit, can it be done?

    - by RobertWHurst
    I'm just about finished my first release of automailer, a program I've been working on for a while now. I've just got to finish writing the installer. Its job is to rewrite the codigniter configs from templates. I've got the read/write stuff working, but I'd like to be able to test the server credentials given by the user without codingiter throwing a system error if they're wrong. Is there a function other than mysql_connect that I can use to test a connection that will return true or false and won't make codeigniter have a fit? This is what I have function _test_connection(){ if(mysql_connect($_POST['host'], $_POST['username'], $_POST['password'], TRUE)) return TRUE; else return FALSE; } Codigniter doesn't like this and throws a system error. <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;"> <h4>A PHP Error was encountered</h4> <p>Severity: Warning</p> <p>Message: mysql_connect() [<a href='function.mysql-connect'>function.mysql-connect</a>]: Unknown MySQL server host 'x' (1)</p> <p>Filename: controllers/install.php</p> <p>Line Number: 57</p> </div> I'd rather not turn off error reporting.

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  • Variable wont echo

    - by jonnnnnnnnnie
    I have the following code, where the var $username doesn't echo, when you type in a value. //TODO: SET AUTH TOKEN as random hash, save in session $auth_token = rand(); if (isset($_POST['action']) && $_POST['action'] == 'Login') { $errors = array(); //USED TO BUILD UP ARRAY OF ERRORS WHICH ARE THEN ECHOED $username = $_POST['username']; if ($username = '') { $errors['username'] = 'Username is required'; } echo $username; // var_dump($username) returns string 0 } require_once 'login_form.html.php'; ?> login_form is this: <form method="POST" action=""> <input type="hidden" name="auth_token" value="<?php echo $auth_token ?>"> Username: <input type="text" name="username"> Password: <input type="password" name="password1"> <input type="submit" name="action" value="Login"> </form> The auth token part isn't important, it just when I type in a value in username textbox and press the login button, the username wont echo, var_dump returns string (0) and print_r is just blank.

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  • cannot get FilesMatch and mod_rewrite working together

    - by neil
    Hello, I'm having a little difficulty with my .htaccess when combining a password protection on a file and a mod_rewrite: If I only have this as my .htaccess <FilesMatch "manage.php"> AuthName "Member Only" AuthType Basic AuthUserFile /home/myuser/.htpasswd require valid-user </FilesMatch> It password protects manage.php fine. If I have this as my .htaccess RewriteEngine on RewriteCond $1 !^(index\.php|manage\.php|robots\.txt) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L,QSA] It works as expected: robots.txt, index.php and manage.php are left alone and are called as normal, everything else is redirected to index.php/$1 HOWEVER, If I combine them then when I visit manage.php it gets redirected as index.php/$1, i.e. the FilesMatch is causing the entry in rewritecond to be ignored. If I actually enter a password in the original test and get to the file, it works in this last test. So I guess something is up with the rewrite and the file match. i.e. entering this causes .\manage.php to be called as .\index.php\manage.php <FilesMatch "manage.php"> AuthName "Member Only" AuthType Basic AuthUserFile /home/myuser/.htpasswd require valid-user </FilesMatch> RewriteEngine on RewriteCond $1 !^(index\.php|manage\.php|robots\.txt) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L,QSA] Thanks for any help :)

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  • HTML + Button with text and image on it.

    - by lucky
    Hello, I have a problem in creating a Button with text and image on it. <td> <button type="submit" name="report" value="Report" <?php if($tab == 'Excel') echo "id=\"tab_inactive\""; else echo "id=\"tab_active\"" ; ?>> <img src="images/report.gif" alt="Report"/>Report </button> <button type="submit" name="excel" value="Excel" <?php if($tab == 'Excel' ) echo "id=\"tab_active\""; else echo "id=\"tab_inactive\"" ; ?>> <img src="images/Excel.gif" alt="Excel" width="16" height="16" /> Excel </button> </td> Here $tab is $tab = strlen(trim($_POST[excel]))>0 ? $_POST[excel] : $_POST[report]; I tried this way, but this is behaving so strangely. On click the button:- The submit function is working properly in firefox, but not in IE. Instead of submitting the value(in this example values are 'Report' and 'Excel'), indeed it is submitting the label of the button. That is if i am checking the value of array PRINT_R($_POST). The value of it is Array ( [report] =>(Icon that i used) Report [excel] => (Icon that i used) Excel [frm_analysis] => [to_analysis] => ) Here i have more than 1 button, then all the labels are submitted eventhough one of them is pressed. i dont how to capture which button is pressed. I even tried changing button type=button and onclick="document.formname.submit()" Even this is resulting in the same. Can you please help me to solve this.

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  • Making more recent items more likely to be drawn

    - by bobo
    There are a few hundred of book records in the database and each record has a publish time. In the homepage of the website, I am required to write some codes to randomly pick 10 books and put them there. The requirement is that newer books need to have higher chances of getting displayed. Since the time is an integer, I am thinking like this to calculate the probability for each book: Probability of a book to be drawn = (current time - publish time of the book) / ((current time - publish time of the book1) + (current time - publish time of the book1) + ... (current time - publish time of the bookn)) After a book is drawn, the next round of the loop will minus the (current time - publish time of the book) from the denominator and recalculate the probability for each of the remaining books, the loop continues until 10 books have been drawn. Is this algorithm a correct one? By the way, the website is written in PHP. Feel free to suggest some PHP codes if you have a better algorithm in your mind. Many thanks to you all.

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  • pass parameter from $.post() callback to outer variable

    - by Nazmin
    basically i want to hold a parameter that retrieve value from $.post() call like this: init = function(){ var lastpage = getLastPage(); } function getLastPage(){ $.post("getInfo.php",{ last: "yes" }, function(data){ setLast(data.last); },'json'); return function setLast(data){ return data; } } so when reach at last post (last page) i should check with lastpage variable that has a value returned from getLastPage() function. I'm pretty blur with javascript pointer and all. Please help guys. update (20/4/2010): I've done the other way around, like this: init = function(){ getLastPage(); if((page+1) == $("#lastpage").val()){ alert("this is last post"); }else{ page++; //get info and display to the page here } } function getLastPage(){ $.post("getInfo.php",{ last: "yes" }, function(data){ $("#lastpage").val(data.last); },'json'); } first run the function to temporarily store the value in hidden input tag (lastpage) and then grab the value again to check it whenever i click forward button. if you all have more appropriate way please tell me.

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  • MySQLi Wrapper -- will this slow down performance?

    - by Kerry
    I found the following code on php.net. I'm trying to write a wrapper for the MySQLi library to make things incredibly simple. If this is going to slow down performance, I'll skip it and find another way, if this works, then I'll do that. I have a single query function, if someone passes in more than one variable, I assume the function has to be prepared. The function that I would use to pass in an array to mysqli_stmt_bind_param is call_user_func_array, I have a feeling that is going to slow things down. Am I right? <?php /* just explaining how to call mysqli_stmt_bind_param with a parameter array */ $sql_link = mysqli_connect('localhost', 'my_user', 'my_password', 'world'); $type = "isssi"; $param = array("5", "File Description", "File Title", "Original Name", time()); $sql = "INSERT INTO file_detail (file_id, file_description, file_title, file_original_name, file_upload_date) VALUES (?, ?, ?, ?, ?)"; $sql_stmt = mysqli_prepare ($sql_link, $sql); call_user_func_array('mysqli_stmt_bind_param', array_merge (array($sql_stmt, $type), $param); mysqli_stmt_execute($sql_stmt); ?>

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  • Sessions not sticking linux server

    - by Jacob Windsor
    I have just moved the dev site over to my linux server for production but the sessions don't seem to be sticking for very long. I am guessing it is the server settings and not the php because it does the same thing with the plesk panel. Whenever a script is executed the sessions seems to get unset. I see nothing in the error log so not sure what it is. It all worked fine on wamp. Anyway I uploaded the php.ini file which was in the wamp server as it had all the settings i needed and all was working on localhost. Not sure what the problem is and this is the final thing that I have to sort out before going into production. And just too add the sessions are being started as they last for a little bit just don't stick around long. Here is the relevent part of my login script just in case there is something wrong with the code: // if login is ok then we add a cookie if($flag == 0) { $pass = htmlspecialchars(mysql_real_escape_string($_POST['pass'])); $username = htmlspecialchars(mysql_real_escape_string($_POST['username'])); $_SESSION['username']=$username; $_SESSION['password']=$pass;

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  • How to current snapshot of MySQL Table and store it into CSV file(after creating it) ?

    - by Rachel
    I have large database table, approximately 5GB, now I wan to getCurrentSnapshot of Database using "Select * from MyTableName", am using PDO in PHP to interact with Database. So preparing a query and then executing it // Execute the prepared query $result->execute(); $resultCollection = $result->fetchAll(PDO::FETCH_ASSOC); is not an efficient way as lots of memory is being user for storing into the associative array data which is approximately, 5GB. My final goal is to collect data returned by Select query into an CSV file and put CSV file at an FTP Location from where Client can get it. Other Option I thought was to do: SELECT * INTO OUTFILE "c:/mydata.csv" FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"' LINES TERMINATED BY "\n" FROM my_table; But I am not sure if this would work as I have cron that initiates the complete process and we do not have an csv file, so basically for this approach, PHP Scripts will have to create an CSV file. Do a Select query on the database. Store the select query result into the CSV file. What would be the best or efficient way to do this kind of task ? Any Suggestions !!!

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  • Update MySQl table onDrop?

    - by dougvt
    Hi all. I am writing a PHP/MySQL application (using CodeIgniter) that uses some jQuery functionality for dragging table rows. I have a table in which the user can drag rows to the desired order (kind of a queue for which I need to preserve the rank of each row). I've been trying to figure out how to (and whether I should) update the database each time the user drops a row, in order to simplify the UI and avoid a "Save" button. I have the jQuery working and can send a serialized list back to the server onDrop, but is it good design practice to run an update query this often? The table will usually have 30-40 rows max, but if the user drags row 1 far down the list, then potentially all the rows would need to be updated to update the rank field. I've been wondering whether to send a giant query to the server, to loop through the rows in PHP and update each row with its own Update query, to send a small serialized list to a stored procedure to let the server do all the work, or perhaps a better method I haven't considered. I've read that stored procedures in MySQL are not very efficient and use a separate process for each call. Any advice as to the right solution here? Thanks very much for your help!

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  • text in div not going to next line

    - by Kia Dull
    for some reason the text in my div doesn't go to the next line, i've tried several different css elements which don't seem to work.... word-wrap:break word, just jumbles the letters... what i want is for one there is an extra word it goes down to the next line like it's supposed to here is my code this is the div it's in #top7 { width: 150px; height:auto; margin: 5px; display: block; float: left; word-wrap:break-word; } text that it's in #p6 { font-family: Myriad Pro; margin: 1px; font-size: 22px; background-color:#540f45; padding: 5px 5px 3px 4px; margin:4px; } a { text-decoration: none; color: white; text-align: right; font-family: Myriad Pro; } here is the php function that retrieves the data from the database <p id='p6'><?php echo "<a href='' "</a>"; ?></p> this is all wrapped in these two id's body { background:#603e4f; display: block; } #foursquare { background-color:#603e4f; width: 290px; display: block; position: absolute; }

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