Search Results

Search found 33321 results on 1333 pages for 'php qt'.

Page 616/1333 | < Previous Page | 612 613 614 615 616 617 618 619 620 621 622 623  | Next Page >

  • Unable to center text in IE but works in firefox

    - by greenpool
    Can somebody point out where I'm going wrong with the following code. Text inside td elements need to be centered except for Summary and Experience. This only appears to work in Firefox/chrome. In IE8 all td text are displayed as left-justified. No matter what I try it doesn't center it. Any particular reason why this would happen? Thanks. css #viewAll { font-family:"Trebuchet MS", Arial, Helvetica, sans-serif; width:100%; border-collapse:collapse; margin-left:10px; table-layout: fixed; } #viewAll td, #viewAll th { font-size:1.1em; border:1px solid #98bf21; word-wrap:break-word; text-align:center; overflow:hidden; } #viewAll tbody td{ padding:2px; } #viewAll th { font-size:1.1em; padding-top:5px; padding-bottom:4px; background-color:#A7C942; color:#ffffff; } table <?php echo '<table id="viewAll" class="tablesorter">'; echo '<thead>'; echo '<tr align="center">'; echo '<th style="width:70px;">Product</th>'; echo '<th style="width:105px;">Prob</th>'; echo '<th style="width:105px;">I</th>'; echo '<th style="width:60px;">Status</th>'; echo '<th style="width:120px;">Experience</th>'; echo '<th style="width:200px;">Technical Summary</th>'; echo '<th style="width:80px;">Record Created</th>'; echo '<th style="width:80px;">Record Updated</th>'; echo '<th style="width:50px;">Open</th>'; echo '</tr>'; echo '</thead>'; echo '<tbody>'; while ($data=mysqli_fetch_array($result)){ #limiting the summary text displayed in the table $limited_summary = (strlen($data['summary']) > 300) ? substr(($data['summary']),0,300) . '...' : $data['summary']; $limited_exp = (strlen($data['exp']) > 300) ? substr(($data['exp']),0,300) . '...' : $data['exp']; echo '<tr align="center"> <td style="width:70px; text-align:center;">'.$data['product'].'</td>'; //if value is '-' do not display as link if ($data['prob'] != '-'){ echo '<td style="width:105px;">'.$data['prob'].'</a></td>'; } else{ echo '<td style="width:105px; ">'.$data['prob'].'</td>'; } if ($data['i'] != '-'){ echo '<td style="width:105px; ">'.$data['i'].'</a></td>'; } else{ echo '<td style="width:105px; ">'.$data['i'].'</td>'; } echo'<td style="width:40px; " >'.$data['status'].'</td> <td style="width:120px; text-align:left;">'.$limited_cust_exp.'</td> <td style="width:200px; text-align:left;">'.$limited_summary.'</td> <td style="width:80px; ">'.$data['created'].'</td> <td style="width:80px; ">'.$data['updated'].'</td>'; if (isset($_SESSION['username'])){ echo '<td style="width:50px; "> <form action="displayRecord.php" method="get">'.' <input type="hidden" name="id" value="'. $data['id'].'" style="text-decoration: none" /><input type="submit" value="Open" /></form></td>'; }else{ echo '<td style="width:50px; "> <form action="displayRecord.php" method="get">'.' <input type="hidden" name="id" value="'. $data['id'].'" style="text-decoration: none" /><input type="submit" value="View" /></form></td>'; } echo '</tr>'; }#end of while echo '</tbody>'; echo '</table>'; ?>

    Read the article

  • I can NOT submit the form

    - by buri kuri
    Hey guys Im trying to develop an advance consumer website using php and I stuck somewhere while trying to get the data with submitting to another page. All I want to do is to get the checkbox values which are stored in an array and checked by user. I urgently need your help please here is the code: $sql2="SELECT * FROM alinanfis WHERE alinanfis.fis_id='".$fis."'" ; $resultFis=mysql_query($sql2); if(mysql_num_rows($resultFis)>0) { print "<form method='POST' action='deletionResult.php'>"; print "<table>"; print "<tr>"; print "<th style='background: transparent;'></th>"; print "<th>Fis No</th>"; print "<th>isim</th>"; print "<th>soyisim</th>"; print "<th >Tarih</th>"; print "<th>Fis Tipi</th>"; print "<th>Nerede</th>"; print "<th>Litre</th>"; print "<th>Tutar</th>"; print "</tr>"; while($rowAlinan=mysql_fetch_array($resultFis)) { $sqlFisTipi="SELECT * FROM atype WHERE a_id='".$rowAlinan['a_id']."'" ; $resultFisTipi=mysql_query($sqlFisTipi); $rowFisTipi=mysql_fetch_array($resultFisTipi); $sqlNerede="SELECT * FROM isyeri WHERE i_id='".$rowAlinan['nerde']."'" ; $resultNerede=mysql_query($sqlNerede); $rowNerede=mysql_fetch_array($resultNerede); $sqlMID="SELECT * FROM musteri WHERE m_id='".$rowAlinan['m_id']."'" ; $resultMID1=mysql_query($sqlMID); $rowMID1=mysql_fetch_array($resultMID1); print "<tr>"; print "<td><input name='checkBox[]' type='checkbox' value='".$rowAlinan['fis_id']."' /> php</td>"; print "<td>".$rowAlinan['fis_id']."</td>"; print "<td>".$rowMID1['m_name']."</td>"; print "<td>".$rowMID1['m_lastName']."</td>"; print "<td>".$rowAlinan['alinan_tarih']."</td>"; print "<td>".$rowFisTipi['a_name']."</td>"; print "<td>".$rowNerede['i_name']."</td>"; print "<td>".$rowAlinan['litre']."</td>"; print "<td>".$rowAlinan['tutar']."</td>"; print "</tr>"; } print '<div class="form_settings">'; print "<input class='submit' type='submit' name= 'send' value='Send'>"; / print '</div>'; print "</table>"; print "</form>"; }//end of if(num_rows>0) else echo '*no such receipt found!!'; mysql_close($con);

    Read the article

  • Array from HTML forms - Internal Server Error

    - by user1392411
    I try to make a requestform for our school. But if I transmit this form I get a "Internal Server Error". I searched but I found nothing like that. Also I don't get a only this error message "Internal Server Error", nothing more. Any ideas why? <!DOCTYPE html> <html> <head> <title></title> <meta charset="utf-8"> <meta name="description" content=""> <link rel="stylesheet" href="../css/normalize.css" /> <link rel="stylesheet" href="../css/bestellformular.css" /> <!-- HTML 5 in Internet Explorer 9 und kleiner aktivieren --> <!--[if lt IE 9]> <script type="textt/javascript" src="js/html5shiv.js"></script> <![endif]--> </head> <body> <section id="head"> </section> <form action="../php/einlesen.php" method="post"> <section id="body"> <h1>Bestellung</h1> <table> <colgroup> <col width="10%"> <col width="80%"> <col width="10%"> </colgroup> <tr> <th> Artikel-Nr. </th> <th> Artikel </th> <th> Menge </th> </tr> <tr> <td> <input type="number" placeholder="Artikel-Nr." name="articelnr[]" required /> </td> <td> <input type="text" placeholder="Name des Artikels" name="articelname[]" required /> </td> <td> <input type="number" placeholder="Menge" name="quantity[]" required /> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> <tr> <td> <input type="number" name="articelnr[]" /> </td> <td> <input type="text" name="articelname[]" /> </td> <td> <input type="number" name="quantity[]"/> </td> </tr> </table> </section> <section id="info"> <div class="left"> <hr /> <p> Kundennummer <input type="text" /> </p> </div> <div class="right"> <table> <tr> <td>Firma</td> <td><input type="text" name="company"required /></td> </tr> <tr> <td>Ort, PLZ</td> <td><input type="text" name="place" required /></td> <td><input type="number" name="plz" class="number" required /></td> </tr> <tr> <td>Straße, Nr.</td> <td><input type="text" name="street"required /></td> <td><input type="number" name="streetnr" class="number" required /></td> </tr> <tr> <td>Telefon</td> <td><input type="tel" name="tel" required /></td> </tr> <tr> <td>Fax</td> <td><input type="text" name="fax" required /></td> </tr> <tr> <td>E-Mail</td> <td><input type="email" name="email" required /></td> </tr> <tr> <td>Datum</td> <td><input type="date" name="date" required placeholder="tt.mm.jj"/></td> </tr> </table> </div> </section> <section id="submit"> <input type="checkbox" name="agb" required /> Ich habe die <a href="../docs/agb.pdf">AGB</a> gelesen und akzeptiere diese. <input type="submit" value="Bestellung Abschicken"/> </section> </form> <section id="footer"> <hr /> </section> </body> </html> Any Ideas why? The data is sent to a yet empty PHP document. The bracelets in the name tag are used to get an array. My PHP version is 5.3.8

    Read the article

  • GTK app: How do I create a working indicator with Qt/C++?

    - by hakermania
    I've tried in 2 forums, but I had no luck so far. So, I am using Qt IDE in order to build my application so as to participate to the Ubuntu Showdown contest. In my application, I've done the following: void show_app(MainWindow *data) { //this works fine: app_indicator_set_status(appindicator, APP_INDICATOR_STATUS_PASSIVE); //this crashes the application: data->show(); } void MainWindow::make_indicator() { if(appindicator){ //appindicator has already been created return; } appindicator = app_indicator_new("Format Junkie Indicator", "formatjunkie", APP_INDICATOR_CATEGORY_APPLICATION_STATUS); GtkWidget* showapp_option; GtkWidget* indicatormenu = gtk_menu_new(); GtkWidget* item = gtk_menu_item_new_with_label("Format Junkie main menu"); gtk_menu_item_set_submenu(GTK_MENU_ITEM(item), indicatormenu); showapp_option = gtk_menu_item_new_with_label("Show App!"); g_signal_connect(showapp_option, "activate", G_CALLBACK(show_app), this); gtk_menu_shell_append(GTK_MENU_SHELL(indicatormenu), showapp_option); gtk_widget_show_all(indicatormenu); app_indicator_set_status(appindicator, APP_INDICATOR_STATUS_ACTIVE); app_indicator_set_attention_icon(appindicator, "dialog-warning"); app_indicator_set_menu(appindicator, GTK_MENU (indicatormenu)); } So, basically I am trying to make a simple indicator entry, which, on click, it will hide the indicator and display the application. The indicator can be successfully hidden using the PASSIVE thingy over there, but, during the call data-show();, the application crashes. Any help on what I am doing wrong would be appreciated! Also, please help me to correct this problem I'm facing (alternatively, I will migrate to the old and good tray icon (it works fine in 12.04, anyway) which I can handle very easily and efficiently)

    Read the article

  • In QT 4.6 w/ Webkit: How to handle popup window requests (WebView::createWindow)?

    - by CM
    Hi all, I'm new to QT and have been trying to create a test browser. What I'm trying to do now is to handle js-based popup requests. After reading the QT documentation, I learned that I need to re-implement the QWebView::createWindow method to do just that. Now I've re-implemented this method, but it seems to be not called when I try to click a link that triggers a popup window. Can any one help me? Do I need to subclass both the WebView and WebPage classes? If so, how do I do that? I'm quite new to QT and I've done tons of searches and found nothing. Thank you all in advance for any hint and advice!

    Read the article

  • GROUP_CONCAT in CodeIgniter

    - by mickaelb91
    I'm just blocking to how create my group_concat with my sql request in CodeIgniter. All my queries are listed in a table, using Jtable library. All work fine, except when I try to insert GROUP_CONCAT. Here's my model page : function list_all() { $login_id = $this->session->userdata('User_id'); $this->db->select('p.project_id, p.Project, p.Description, p.Status, p.Thumbnail, t.Template'); $this->db->from('assigned_projects_ppeople a'); $this->db->where('people_id', $login_id); $this->db->join('projects p', 'p.project_id = a.project_id'); $this->db->join('project_templates t', 't.template_id = p.template_id'); $this->db->select('GROUP_CONCAT(u.Asset SEPARATOR ",") as assetslist', FALSE); $this->db->from('assigned_assets_pproject b'); $this->db->join('assets u', 'u.asset_id = b.asset_id'); $query = $this->db->get(); $rows = $query->result_array(); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Records'] = $rows; return $jTableResult; } My controller page : function listRecord(){ $this->load->model('project_model'); $result = $this->project_model->list_all(); print json_encode($result); } And to finish my view page : <table id="listtable"></table> <script type="text/javascript"> $(document).ready(function () { $('#listtable').jtable({ title: 'Table test', actions: { listAction: '<?php echo base_url().'project/listRecord';?>', createAction: '/GettingStarted/CreatePerson', updateAction: '/GettingStarted/UpdatePerson', deleteAction: '/GettingStarted/DeletePerson' }, fields: { project_id: { key: true, list: false }, Project: { title: 'Project Name' }, Description: { title: 'Description' }, Status: { title: 'Status', width: '20px' }, Thumbnail: { title: 'Thumbnail', display: function (data) { return '<a href="<?php echo base_url('project');?>/' + data.record.project_id + '"><img class="thumbnail" width="50px" height="50px" src="' + data.record.Thumbnail + '" alt="' + data.record.Thumbnail + '" ></a>'; } }, Template: { title: 'Template' }, Asset: { title: 'Assets' }, RecordDate: { title: 'Record date', type: 'date', create: false, edit: false } } }); //Load person list from server $('#listtable').jtable('load'); }); </script> I read lot of posts talking about that, like replace ',' separator by ",", or use OUTER to the join, or group_by('p.project_id') before using get method, don't work. Here is a the output of the query in json : {"Result":"OK","Records":[{"project_id":"1","Project":"Adam & Eve : A Famous Story","Description":"The story about Adam & Eve reviewed in 3D Animation movie !","Status":"wip","Thumbnail":"http:\/\/localhost\/assets\/images\/thumb\/projectAdamAndEve.png","Template":"Animation Movie","assetslist":"Apple, Adam, Eve, Garden of Eden"}]} We can see the GROUP_CONCAT is here (after "assetslist"), but the column stills empty. If asked, I can post the database SQL file. Thank you.

    Read the article

  • Include WordPress Content Outside of WordPress

    - by S Pangborn
    I'm looking to build a mobile version of a WordPress site and have most of it built in static files, but am trying to get access to the WordPress content from inside an external PHP file that the mobile site will run from. How can I get access to the loop or database without manually writing SQL queries?

    Read the article

  • Magento - Fatal error: Class name must be a valid object or a string

    - by Jason Millward
    I'm having a problem with a Magento installation that I hope someone can help me with. I suddenly started getting the following error message when I accessed the site: Fatal error: Class name must be a valid object or a string in /app/code/core/Mage/Core/Model/Resource.php on line 215 I've searched for someone with a similar issue but not had any luck so i'm stuck and really need to get this resolved Can anyone help?

    Read the article

  • Warning: Illegal string offset 'new_file' - Magento Site

    - by Roy
    We just migrated our magento installation from one of the hosting company and this keeps popping up whenever I try to duplicate product. Something wrong with codebase...Can someone please help. The code at 130 is… $object->setData($mediaAttrCode, $newImages[$attrData]['new_file']); THanks Warning: Illegal string offset 'new_file' in /home/spotzee/webapps/yourchemistonline/app/code/core/Mage/Catalog/Model/Product/Attribute/Backend/Media.php on line 130

    Read the article

  • allow file download to all types of files

    - by Avinash
    hi i have given my user to upload nay types of files. But my problem is that how can i force user top just download any type of files? Since pdf, jpg and text files are directly viewable to browser. So i want that any type of file should be downloaded to view. Running on php Thanks Avinash

    Read the article

  • Authentication and Login on 2 website

    - by xRobot
    Hi at all, I have 2 site: example.com and exampletwo.com I want that when a user login on example.com then he is automatically authenticated also on exampletwo.com How can I do that ? I use Django + Nginx on first website and Tornado framework + Tornado server on second website. Thanks ;) . P.S. If you don't know this platforms ( Django or Tornado or Nginx ), I accept also a solution for a generic PHP+Apache platform and then I will do some research :)

    Read the article

  • Country/City/state validation

    - by M.M.H.Masud
    I want to do the following things using PHP and jQuery https://www.careerbuilder.com/share/register.aspx?sc_cmp1=JS_LoginASPX_RegNow Steps Select a country from a dropdown list. The city dropdown list will fillup automatically with the list of cities of the selected country. If state is available for that country then state list will be visible with all state list of that country. Then I need to validate the selected city, state and country. Do you have any ideas? Thanks in advance

    Read the article

  • apache2: bad user name www-data

    - by Robert Ross
    Starting web server apache2 apache2: bad user name www-data I just tried restarting my webserver because of an update I did to my php.ini and originally I was getting something about the PID file being overwritten. Now I just get this: * Starting web server apache2 apache2: bad user name www-data this has NEVER happened before, and I haven't changed and permissions or apache2 configuration files. What gives?

    Read the article

  • Facebook: Get User's Birthday

    - by Sarfraz
    Hello, As I asked previously but without any luck about how to get current user's birthday. I would like to simply get the birthday of current logged in user (I am using facebook connect & php client library) using any possible way you guys could suggest. I have also heared about OAuth and Graph API but facebook documentation is very bad, I can not get a working example. Please show me any method to get current user's birthday. Thanks

    Read the article

  • PROBLEM WITH FPDF

    - by user297801
    Hello i'm trying to create a report using FPDF from a website using php, see i need to put a signature line at the en of the report, but I don't know how, can you help me??

    Read the article

  • What couse this error?? Fatal error: Call to undefined function mcrypt_encrypt()

    - by Jin Yong
    Does Anyone know whcy this error message display (Call to undefined function mcrypt_encrypt() ) when I run the following code below? Am I missing some steps perhaps any setting in PHP I have to do before this code can work? $key = 'password to (en/de)crypt'; $string = 'string to be encrypted'; $test = mcrypt_encrypt(MCRYPT_RIJNDAEL_256, md5($key), $string, MCRYPT_MODE_CBC, md5(md5($key)));

    Read the article

  • Disable button until tabs have ben read...

    - by jimbo
    I have some tabs which have been created using Javascript and Mootools, my client wants the 'next button' at the bottom of the page to be disabled, until the tabs have been read(clicked). The page is dynamic (created with PHP and MySQL) and there could be two tabs or three, depending on the set-up. I am struggling today to think of the best solution. Any help more than welcome...

    Read the article

  • use stream_socket_client to retrieve 2 remote files at the same time

    - by Hintswen
    I have a script in PHP which retrieves two very similar files and performs some tasks on the data then outputs a result. I'm currently using curl and getting one, processing it, then getting the other and processing it. I want to switch to stream_socket_client as I've heard you can retrieve both files at the same time and do the processing once they have been retrieved but I am unsure how to do this.

    Read the article

  • Read a text file and transfer contents to mysql database

    - by Jack Brown
    I need a php script to read a .txt file. The content of the text file are like this: data.txt 145|Joe Blogs|17/03/1954 986|Jim Smith|12/01/1976 234|Paul Jones|19/07/1923 098|James Smith|12/09/1998 234|Carl Jones|01/01/1925 These would then get stored into a database like this DataID |Name |DOB 234 |Carl Jones|01/01/1925 I would be so grateful if someone could give me script to achieve this.

    Read the article

  • Google Charts Over HTTPS

    - by swt83
    I'm trying to load charts as images in a secured site. An example of a Google Chart image over https would be this: https://www.google.com/chart?cht=lc&chs=200x125&chd=s:helloWorld The problem is that while you can load an image like this by directly clicking the link, you can't include it as an image in your page. It just won't load. Any idea on how to bypass this? Or solution generally using PHP?

    Read the article

  • Eclipse PDT debugging web application: evaluating expressions in a console

    - by dreftymac
    When using Eclipse PDT with XDebug to debug a PHP web application, is there any way to open up a console window that will allow me to type in and see the value of arbitrary expressions in the current scope? This would seem like an obvious element of the debugging environment, and I may be missing something, but the only thing resembling a console says "no consoles to display at this time"

    Read the article

  • Do i need to apply htmlspecialchars / htmlentites on json array?

    - by Imran Omar Bukhsh
    I wanted to ask that in a php script of mine which I am accessing through an ajax request, I am returning json data ( converted from an array ) as such echo json_encode($row_array); I get this data in jquery and display it in a form. Do i need to apply htmlspecialchars / htmlentites before returning the data? Is do then whats the correct way to do it? The following code gives me an error: echo htmlentities(json_encode($row_array)); Thanking you Imran

    Read the article

< Previous Page | 612 613 614 615 616 617 618 619 620 621 622 623  | Next Page >