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  • How do you get the viewport scale after pinch/zoom on an iPhone web app?

    - by Loktar
    Does anyone know how to get the size in pixels or scale value of the viewport after a user has pinched or double tapped to zoom in/out on a page in JavaScript? I've tried using window.innerWidth but I've had mixed results. Sometimes it seems to accurately give the number of pixels the viewport is showing, however, if I zoom way in on a page and then do a large pinch to zoom back out, window.innerWidth will be around 600-700 even though it is only showing ~200px of the page. The page is only 400px wide and it didn't show the checkered "you've gone too far" background you see when you zoom out beyond the page size. If I do small pinches to zoom in and out, window.innerWidth appears to work just fine. Unfortunately I can't rely on a user only making small pinch gestures :) I've also tried to use the scale property on the gesture event object, but I've found that unreliable because you don't always know the initial scale when you reload the page or use back/forward buttons to navigate to it even when using the meta tag to specify it. Ultimately, I'm trying to make an app that is aware of when a user is trying to zoom out beyond the maximum zoom level so if there is another way to do this I'm interested in hearing about it :) Here's the code I'm using to get the innerWidth: document.body.addEventListener('gestureend', function (evt) { console.log(window.innerWidth); // inaccurate when doing large pinch gestures }, false); Thanks!

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  • How to select the first property with unknown name from JSON and how to select first item from array

    - by Oscar Godson
    I actually have two questions, both are probably simple, but for some odd reason I cant figure it out... I've worked with JSON 100s of times before too! but here is the JSON in question: {"69256":{"streaminfo":{"stream_ID":"1025","sourceowner_ID":"2","sourceowner_avatar":"http:\/\/content.nozzlmedia.com\/images\/sourceowner_avatar2.jpg","sourceownertype_ID":"1","stream_name":"Twitter","streamtype":"Social media","appsarray":[]},"item":{"headline":"Charboy","main_image":"http:\/\/content.nozzlmedia.com\/images\/author_avatar173212.jpg","summary":"ate a tomato and avocado for dinner...","nozzl_captured":"2010-05-12 23:02:12","geoarray":[{"state":"OR","county":"Multnomah","city":"Portland","neighborhood":"Downtown","zip":"97205","street":"462 SW 11th Ave","latitude":"45.5219","longitude":"-122.682"}],"full_content":"ate a tomato and avocado for dinner tonight. such tasty foods. just enjoyable.","body_text":"ate a tomato and avocado for dinner tonight. such tasty foods. just enjoyable.","author_name":"Charboy","author_avatar":"http:\/\/content.nozzlmedia.com\/images\/author_avatar173212.jpg","fulltext_url":"http:\/\/twitter.com\/charboy\/statuses\/13889868936","leftovers":{"twitter_id":"tag:search.twitter.com,2005:13889868936","date":"2010-05-13T02:59:59Z","location":"iPhone: 45.521866,-122.682262"},"wordarray":{"0":"ate","1":"tomato","2":"avocado","3":"dinner","4":"tonight","5":"tasty","6":"foods","7":"just","8":"enjoyable","9":"Charboy","11":"Twitter","13":"state:OR","14":"county:Multnomah, OR","15":"city:Portland, OR","16":"neighborhood:Downtown","17":"zip:97205"}}}} Question 1: How do I loop through each item (69256) when the number is random? e.g. item 1 is 123, item2 is 646? Like, for example, a normal JSON feed would have something like: {'item':{'blah':'lorem'},'item':{'blah':'ipsum'}} the JS would be like console.log(item.blah) to return lorem then ipsum in a loop How do I do it when i dont know the first item of the object? Question 2: How do I select items from the geoarray object? I tried: json.test.item.geoarray.latitude and json.test.item.geoarray['latitude']

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  • Google App Engine Java app couldn't find javac ?

    - by Frank
    I'm learning to use Google App Engine, I installed it in Netbeans, the project works, but when I clicked on "Deploy To Google App Engine", I got the following error : Beginning server interaction for ... 0% Creating staging directory 5% Scanning for jsp files. 8% Compiling jsp files. 11% Compiling java files. Error Details: Apr 20, 2010 3:51:23 PM org.apache.jasper.JspC processFile INFO: Built File: \PayPal_Monitor.jsp java.lang.IllegalStateException: cannot find javac executable based on java.home, tried "C:\Program Files (x86)\Java\jre6\bin\javac.exe" and "C:\Program Files (x86)\Java\bin\javac.exe" Unable to update app: cannot find javac executable based on java.home, tried "C:\Program Files (x86)\Java\jre6\bin\javac.exe" and "C:\Program Files (x86)\Java\bin\javac.exe" Please see the logs [C:\Users\NM\AppData\Local\Temp\appcfg3946701335172983337.log] for further information. The file "javac.exe" is in : C:\Program Files (x86)\Java\jdk1.6.0_18\bin How can I add it to "java.home" ? I'm using Win Vista, and I tried to add it from "System - Environment Variables", but there is no "java.home" in there. Where can I find it ? Frank

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  • Why can't I access the facebook friends list after reopening a session in ios

    - by user1532390
    I am upgrading to the facebook 3.0 sdk for ios. Things went well, until I tried to open an existing session after relaunching the application. I am trying to access the list of friends for the facebook user. if ([[FBSession activeSession] isOpen]) { [request startWithCompletionHandler:^(FBRequestConnection *connection, id result, NSError *error) { //do something here }]; }else{ [[self session] openWithCompletionHandler:^(FBSession *session, FBSessionState status, NSError *error) { if ([self isValid]) { [request startWithCompletionHandler:^(FBRequestConnection *connection, id result, NSError *error) { //log this error we always get NSLog(@"%@",error); //do something else }]; } }]; } However I get this error: Error Domain=com.facebook.sdk Code=5 "The operation couldn’t be completed. (com.facebook.sdk error 5.)" UserInfo=0x1d92ff40 {com.facebook.sdk:ParsedJSONResponseKey={ body = { error = { code = 2500; message = "An active access token must be used to query information about the current user."; type = OAuthException; }; }; code = 400; }, com.facebook.sdk:HTTPStatusCode=400} I've found that if I use the FBSession reauthorize method it allows me to complete the request without error, but it also means I must show UI or switch apps every time we relaunch the application which is unacceptable. Any suggestions on what I should be doing differently?

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  • Rails uploaded file blank

    - by Ceilingfish
    Hi chaps, I'm trying to upload a file to the server using a HTTP multipart form in rails, and for some reason it's turning up blank at the other end. I can see it being received in the rails log thusly: Processing Admin::HeadlinesController#update (for 127.0.0.1 at 2010-03-08 12:26:13) [PUT] Parameters: {"commit"=>"Save changes", "action"=>"update", "_method"=>"put", "authenticity_token"=>"mK70XRk5gOPUwXOcNboT/4K8PD9RBM7GqCOlEUKZwcA=", "headline"=>{"position"=>"1", "location"=>"primary", "attachment_id"=>"13", "headline_content"=>"questionnaires", "article_id"=>"3", "image"=>#<File:/tmp/RackMultipart20100308-63211-1vym9nj-0>}, "id"=>"140", "controller"=>"admin/headlines"} But if I have a look in /tmp/RackMultipart20100308-63211-1vym9nj-0 the file is blank. Am I right in thinking that this should be the file that I uploaded? I'm running Phusion Passenger 2.2.7 on Apache 2.2.13, with ruby 1.8.7 and rails 2.3.5, on OSX 10.6.2

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  • Getting wierd issue with TO_NUMBER function in Oracle

    - by Fazal
    I have been getting an intermittent issue when executing to_number function in the where clause on a varchar2 column if number of records exceed a certain number n. I used n as there is no exact number of records on which it happens. On one DB it happens after n was 1 million on another when it was 0.1. million. E.g. I have a table with 10 million records say Table Country which has field1 varchar2 containing numberic data and Id If I do a query as an example select * from country where to_number(field1) = 23 and id 1 and id < 100000 This works But if i do the query select * from country where to_number(field1) = 23 and id 1 and id < 100001 It fails saying invalid number Next I try the query select * from country where to_number(field1) = 23 and id 2 and id < 100001 It works again As I only got invalid number it was confusing, but in the log file it said Memory Notification: Library Cache Object loaded into SGA Heap size 3823K exceeds notification threshold (2048K) KGL object name :with sqlplan as ( select c006 object_owner, c007 object_type,c008 object_name from htmldb_collections where COLLECTION_NAME='HTMLDB_QUERY_PLAN' and c007 in ('TABLE','INDEX','MATERIALIZED VIEW','INDEX (UNIQUE)')), ws_schemas as( select schema from wwv_flow_company_schemas where security_group_id = :flow_security_group_id), t as( select s.object_owner table_owner,s.object_name table_name, d.OBJECT_ID from sqlplan s,sys.dba_objects d It seems its related to SGA size, but google did not give me much help on this. Does anyone have any idea about this issue with TO_NUMBER or oracle functions for large data?

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  • Use Javascript RegEx to extract column names from SQLite Create Table SQL

    - by NimbusSoftware
    I'm trying to extract column names from a SQLite result set from sqlite_master's sql column. I get hosed up in the regular expressions in the match() and split() functions. t1.executeSql('SELECT name, sql FROM sqlite_master WHERE type="table" and name!="__WebKitDatabaseInfoTable__";', [], function(t1, result) { for(i = 0;i < result.rows.length; i++){ var tbl = result.rows.item(i).name; var dbSchema = result.rows.item(i).sql; // errors out on next line var columns = dbSchema.match(/.*CREATE\s+TABLE\s+(\S+)\s+\((.*)\).*/)[2].split(/\s+[^,]+,?\s*/); } }, function(){console.log('err1');} ); I want to parse SQL statements like these... CREATE TABLE sqlite_sequence(name,seq); CREATE TABLE tblConfig (Key TEXT NOT NULL,Value TEXT NOT NULL); CREATE TABLE tblIcon (IconID INTEGER NOT NULL PRIMARY KEY,png TEXT NOT NULL,img32 TEXT NOT NULL,img64 TEXT NOT NULL,Version TEXT NOT NULL) into a strings like theses... name,seq Key,Value IconID,png,img32,img64,Version Any help with a RegEx would be greatly appreciated.

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  • OleDB connection only working when debugging

    - by Francesc
    I have a C# application that connects to a named SQL Express instance on the local machine using OleDBConnection: _connection = new OleDbConnection(_strConn); _connection.Open(); _strConn is something like this: "Provider=sqloledb;Data Source=.\NAMEDINSTANCE;Initial Catalog=dbname;User Id=sa;Password=password;" If I debug the application, the connection works fine. If I run the application from Windows Explorer (the same debug compilation), I get an "OleDBException: Login timeout expired" in the Open() line after 30 seconds. The strange thing is the exception happens even if I attach the debugger to the exe. I can see that the connection string is correct and everything seems fine. I can't fine any extra information in the SQL Express error log or SQL Activity Monitor either. If it helps, here is the exception: System.Data.OleDb.OleDbException: Login timeout expired at System.Data.OleDb.OleDbConnectionInternal..ctor(OleDbConnectionString constr, OleDbConnection connection) at System.Data.OleDb.OleDbConnectionFactory.CreateConnection(DbConnectionOptions options, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningObject) at System.Data.ProviderBase.DbConnectionFactory.CreateNonPooledConnection(DbConnection owningConnection, DbConnectionPoolGroup poolGroup) at System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection owningConnection) at System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory) at System.Data.OleDb.OleDbConnection.Open() I imagine that find the issue with the information I give here might be difficult, but I don't know where else to look or what other tests to do, so any ideas on what it could be or what test I could do to find out will be really appreciated.

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • Ruby on Rails Mongrel web server stuck when MySQL service is running

    - by Marcos Buarque
    Hi, I am a Ruby on Rails newbie and already have a problem. I have started the Mongrel web server and it works fine when MySQL service isn't running. But when MySQL is on, Mongrel stucks. It ceases from serving the pages. So far, I have tested the localhost:3000 URL. When MySQL is off, it serves the page. When I click "about application's environment", I get the messasge (of course) "Can't connect to MySQL server on 'localhost' (10061)". After starting the MySQL service and refreshing, I get no more answer and Mongrel does not serve the webpage. It gets stuck with no answer to the browser. Then I have to stop the webserver and restart it. I have installed mysql2 gem with the command gem install mysql2. I was able to create the _test and _development databases with the command line rake db:create. I have tested with MySQL root user and blank password and also tried with a superuser user I have created. No success. Here is the server log: ======================== Started GET "/rails/info/properties" for 127.0.0.1 at Fri Dec 24 17:41:25 -0200 2010 Mysql2::Error (Can't connect to MySQL server on 'localhost' (10061)): Rendered C:/Ruby187/lib/ruby/gems/1.8/gems/actionpack-3.0.3/lib/action_dispatch/middleware/templates/rescues/_trace.erb (1.0ms) Rendered C:/Ruby187/lib/ruby/gems/1.8/gems/actionpack-3.0.3/lib/action_dispatch/middleware/templates/rescues/_request_and_response.erb (5.0ms) Rendered C:/Ruby187/lib/ruby/gems/1.8/gems/actionpack-3.0.3/lib/action_dispatch/middleware/templates/rescues/diagnostics.erb within rescues/layout (35.0ms) ================= I am running on a Windows 7 environment with firewall down.

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  • Add an item to the Finder/Save dialog sidebar

    - by Clinton Blackmore
    I'm working on a script where a user logs into a guest account on OS and is prompted for their network credentials in order to mount their network home folder (while they benefit from working on a local user folder). As the guest folder is deleted when users log out, I want to discourage them from saving anything there. I would like to replace the items on the Finder and Open/Save sidebar lists (such as "Desktop", username, "Documents", etc) with ones that would save into their network home folder. It is possible to do this using AppleScript or Cocoa APIs, or do I need to modify a plist and restart the Finder? [Ack. Looking into ~/Library/Preferences/com.apple.sidebars.plist, it isn't at all clear how I'd populate it.] Similar Questions: AppleScript: adding mounted folder to Finder Sidebar? suggests using fstab; this code will most likely run as a user and really, automounting at that point would be too late. How do you programmatically put folder icons on the Finder sidebar, given that you have to use a custom icon for the folder? Says there is no Cocoa API, but that you can use a carbon-style LSSharedFileList API that is only documented in a single header file. Does anyone know of some example code to add an item to the Finder sidebar?

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  • ldap login form works, but need to add active-directory group access

    - by Brad
    I created a form that asks you to log in, then verifies the user/pass against the ldap server/active-directory, if successful, it creates a session, which will be checked on every page. Now I want to check the session, which is the username of the person who is logged in, and do a search for them using ldap_search, so I can check what group they belong to and pass that group thru a function to verify that they can view that page. Each page will accessible to a certain group or groups of users, which those groups are defined within Active Directory. I am unsure on how I can do that using ldap_search, or maybe that is just one piece of the puzzle I am trying to solve. Any help is appreciated - thank you! In the example code below, it is seeing if the user belongs to the student active-directory group (I do not know if this code works, but it should give you an idea of what I want to accomplish). $filter = "CN=StudentCN=Users,dc=domain,dc=control"; $result = ldap_search($ldapconn,$filter,$valid_session_username); if($result == TRUE) { print $valid_session_username.' does have access to this page'; } else { print $valid_session_username.' does NOT have access to this page'; }

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  • Rails 4, not saving @user.save when registering new user

    - by Yuichi
    When I try to register an user, it does not give me any error but just cannot save the user. I don't have attr_accessible. I'm not sure what I am missing. Please help me. user.rb class User < ActiveRecord::Base has_secure_password validates :email, presence: true, uniqueness: true, format: { with: /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i } validates :password, presence: true, length: {minimum: 6} validates :nickname, presence: true, uniqueness: true end users_controller.rb class UsersController < ApplicationController def new @user = User.new end def create @user = User.new(user_params) # Not saving @user ... if @user.save flash[:success] = "Successfully registered" redirect_to videos_path else flash[:error] = "Cannot create an user, check the input and try again" render :new end end private def user_params params.require(:user).permit(:email, :password, :nickname) end end Log: Processing by UsersController#create as HTML Parameters: {"utf8"=>"?", "authenticity_token"=>"x5OqMgarqMFj17dVSuA8tVueg1dncS3YtkCfMzMpOUE=", "user"=>{"email"=>"[email protected]", "password"=>"[FILTERED]", "nickname"=>"example"}, "commit"=>"Register"} (0.1ms) begin transaction User Exists (0.2ms) SELECT 1 AS one FROM "users" WHERE "users"."email" = '[email protected]' LIMIT 1 User Exists (0.1ms) SELECT 1 AS one FROM "users" WHERE "users"."nickname" = 'example' LIMIT 1 (0.1ms) rollback transaction

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  • Storing float numbers as strings in android database

    - by sandis
    So I have an app where I put arbitrary strings in a database and later extract them like this: Cursor DBresult = myDatabase.query(false, Constant.DATABASE_NOTES_TABLE_NAME, new String[] {"myStuff"}, where, null, null, null, null, null); DBresult.getString(0); This works fine in all cases except for when the string looks like a float number, for example "221.123123123". After saving it to the database I can extract the database to my computer and look inside it with a DB-viewer, and the saved number is correct. However, when using cursor.getString() the string "221.123" is returned. I cant for the life of me understand how I can prevent this. I guess I could do a cursor.getDouble() on every single string to see if this gives a better result, but that feels sooo ugly and inefficient. Any suggestions? Cheers, edit: I just made a small test program. This program prints "result: 123.123", when I would like it to print "result: 123.123123123" SQLiteDatabase database = openOrCreateDatabase("databas", Context.MODE_PRIVATE, null); database.execSQL("create table if not exists tabell (nyckel string primary key);"); ContentValues value = new ContentValues(); value.put("nyckel", "123.123123123"); database.insert("tabell", null, value); Cursor result = database.query("tabell", new String[]{"nyckel"}, null, null, null, null, null); result.moveToFirst(); Log.d("TAG","result: " + result.getString(0));

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  • Hibernate: Walk millions of rows and don't leak memory

    - by Autocracy
    The below code functions, but Hibernate never lets go of its grip of any object. Calling session.clear() causes exceptions regarding fetching a joined class, and calling session.evict(currentObject) before retrieving the next object also fails to free the memory. Eventually I exhaust my heap space. Checking my heap dumps, StatefulPersistenceContext is the garbage collector's root for all references pointing to my objects. public class CriteriaReportSource implements JRDataSource { private ScrollableResults sr; private Object currentObject; private Criteria c; private static final int scrollSize = 10; private int offset = 1; public CriteriaReportSource(Criteria c) { this.c = c; advanceScroll(); } private void advanceScroll() { // ((Session) Main.em.getDelegate()).clear(); this.sr = c.setFirstResult(offset) .setMaxResults(scrollSize) .scroll(ScrollMode.FORWARD_ONLY); offset += scrollSize; } public boolean next() { if (sr.next()) { currentObject = sr.get(0); if (sr.isLast()) { advanceScroll(); } return true; } return false; } public Object getFieldValue(JRField jrf) throws JRException { Object retVal = null; if(currentObject == null) { return null; } try { retVal = PropertyUtils.getProperty(currentObject, jrf.getName()); } catch (Exception ex) { Logger.getLogger(CriteriaReportSource.class.getName()).log(Level.SEVERE, null, ex); } return retVal; } }

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  • RoR - howto convert some HTML-elements with css to Rails

    - by NicoJuicy
    I have old HTML code with html and css.. <form action="login" method="post"> <div class="field"> <label for="username">Username</label> <input type="text" class="text" id="username" name="username" value="just click login !"/> </div> <span class="fright"> <button class="button" type="submit"><strong>Log In</strong></button> </span> </div> How can i convert this code to decent rails code? I came up with this, but it ain't right :-( : <% form_for :user, @user, :url => { :action => "login" } do |f| %> <% div_for f, :class => "field text" do %> <%= f.text_field :username %> <%= f.password_field :password, :class => "field text" %> <% end %> <span class="fright"> <%= submit_tag '<strong>Inloggen</strong>', :class => "button",:disable_with => 'verwerken...' %></span> <% end %> I'm having problems with the <strong>Inloggen</strong> And with the <% div_for f, :class => "field text" do %>

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  • Error installing FeedZirra

    - by Gautam
    Hi, I am new to Ruby on Rails. I am excited about Feed parsing but when I install FeedZirra I am getting this error. I use Windows 7 and Ruby 1.8.7. Please help. Thanks in advance. C:\Ruby187>gem sources -a http://gems.github.com http://gems.github.com added to sources C:\Ruby187>gem install pauldix-feedzirra Building native extensions. This could take a while... ERROR: Error installing pauldix-feedzirra: ERROR: Failed to build gem native extension. C:/Ruby187/bin/ruby.exe extconf.rb checking for curl-config... no checking for main() in -lcurl... no *** extconf.rb failed *** Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=C:/Ruby187/bin/ruby --with-curl-dir --without-curl-dir --with-curl-include --without-curl-include=${curl-dir}/include --with-curl-lib --without-curl-lib=${curl-dir}/lib --with-curllib --without-curllib extconf.rb:12: Can't find libcurl or curl/curl.h (RuntimeError) Try passing --with-curl-dir or --with-curl-lib and --with-curl-include options to extconf. Gem files will remain installed in C:/Ruby187/lib/ruby/gems/1.8/gems/taf2-curb-0 .5.4.0 for inspection. Results logged to C:/Ruby187/lib/ruby/gems/1.8/gems/taf2-curb-0.5.4.0/ext/gem_ma ke.out

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  • Graceful DOS Command Error-Handling

    - by Captain Obvious
    PHP 5.2.13 on Windows 2003 I am using the DOS Start /B command to launch a background application using the PHP popen() function: popen("start /B {$_SERVER['HOMEPATH']}/{$app}.exe > {$_SERVER['HOMEPATH']}/bg_output.log 2>&1 & echo $!", 'r'); The popen() function launches a cmd.exe process that runs the specified command; however, if the command fails (e.g. the {$app}.exe doesn't exist or is locked in the above example), the cmd.exe process never returns, and PHP hangs indefinitely as a result. Calling the failing DOS command directly using the Command Prompt results in an Error prompt that requires clicking the OK button. I assume this error confirmation requirement is what's preventing the cmd.exe process from returning to PHP both from the Command Prompt (using both CGI and CLI) and the web (using Apache 2.0 handler w/Apache 2.2). Is there a way to write the DOS command or configure the server or cmd.exe app itself to return the DOS error to the originating call rather than waiting for confirmation?

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  • At which line in the following code should I commit my unit of work?

    - by Pure.Krome
    I have the following code which is in a transaction. I'm not sure where/when I should be commiting my unit of work. On purpose, I've not mentioned what type of Respoistory i'm using - eg. Linq-To-Sql, Entity Framework 4, NHibernate, etc. If someone knows where, can they please explain WHY they have said, where? (i'm trying to understand the pattern through example(s), as opposed to just getting my code to work). Here's what i've got :- using ( TransactionScope transactionScope = new TransactionScope ( TransactionScopeOption.RequiresNew, new TransactionOptions { IsolationLevel = IsolationLevel.ReadUncommitted } ) ) { _logEntryRepository.InsertOrUpdate(logEntry); //_unitOfWork.Commit(); // Here, commit #1 ? // Now, if this log entry was a NewConnection or an LostConnection, // then we need to make sure we update the ConnectedClients. if (logEntry.EventType == EventType.NewConnection) { _connectedClientRepository.Insert( new ConnectedClient { LogEntryId = logEntry.LogEntryId }); //_unitOfWork.Commit(); // Here, commit #2 ? } // A (PB) BanKick does _NOT_ register a lost connection, // so we need to make sure we handle those scenario's as a LostConnection. if (logEntry.EventType == EventType.LostConnection || logEntry.EventType == EventType.BanKick) { _connectedClientRepository.Delete( logEntry.ClientName, logEntry.ClientIpAndPort); //_unitOfWork.Commit(); // Here, commit #3 ? } _unitOfWork.Commit(); // Here, commit #4 ? transactionScope.Complete(); }

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  • Hibernate 3.5.0 causes extreme performance problems

    - by user303396
    I've recently updated from hibernate 3.3.1.GA to hibernate 3.5.0 and I'm having a lot of performance issues. As a test, I added around 8000 entities to my DB (which in turn cause other entities to be saved). These entities are saved in batches of 20 so that the transactions aren't too large for performance reasons. When using hibernate 3.3.1.GA all 8000 entities get saved in about 3 minutes. When using hibernate 3.5.0 it starts out slower than with hibernate 3.3.1. But it gets slower and slower. At around 4,000 entities, it sometimes takes 5 minutes just to save a batch of 20. If I then go to a mysql console and manually type in an insert statement from the mysql general query log, half of them run perfect in 0.00 seconds. And half of them take a long time (maybe 40 seconds) or timeout with "ERROR 1205 (HY000): Lock wait timeout exceeded; try restarting transaction" from MySQL. Has something changed in hibernate's transaction management in version 3.5.0 that I should be aware of? The ONLY thing I changed to experience these unusable performance issues is replace the following hibernate 3.3.1.GA jar files: com.springsource.org.hibernate-3.3.1.GA.jar, com.springsource.org.hibernate.annotations-3.4.0.GA.jar, com.springsource.org.hibernate.annotations.common-3.3.0.ga.jar, com.springsource.javassist-3.3.0.ga.jar with the new hibernate 3.5.0 release hibernate3.jar and javassist-3.9.0.GA.jar. Thanks.

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  • Why is my searchable activity's Intent.getAction() null?

    - by originalbryan
    I've followed the SearchManager documentation yet am still having trouble making one of my app's activities searchable. From my activity, the SearchDialog appears, I enter a query, hit search, my activity reopens, then I see this in the log: D/SearchDialog( 584): launching Intent { act=android.intent.action.SEARCH flg=0x10000000 cmp=com.clinkybot.geodroid2/.views.Waypoints (has extras) } I/SearchDialog( 584): Starting (as ourselves) #Intent;action=android.intent.action.SEARCH;launchFlags=0x10000000;component=com.clinkybot.geodroid2/.views.Waypoints;S.user_query=sdaf;S.query=sdaf;end I/ActivityManager( 584): Starting activity: Intent { act=android.intent.action.SEARCH flg=0x10000000 cmp=com.clinkybot.geodroid2/.views.Waypoints (has extras) } D/WAYPOINTS( 1018): NI Intent { cmp=com.clinkybot.geodroid2/.views.Waypoints (has extras) } D/WAYPOINTS( 1018): NI null D/WAYPOINTS( 1018): NI false It appears to me that everything is fine up until the last three lines. The "NI" lines are getIntent().toString(), getIntent().getAction(), and getIntent().hasExtra(SearchManager.QUERY) respectively. ActivityManager appears to be starting my activity with the correct action. Then when my activity starts, it contains no action!? What am I doing wrong? The relevant portion of my manifest is: <activity android:name=".views.Waypoints" android:label="Waypoints" android:launchMode="singleTop"> <intent-filter> <action android:name="android.intent.action.SEARCH" /> <category android:name="android.intent.category.DEFAULT" /> </intent-filter> <meta-data android:name="android.app.searchable" android:resource="@xml/searchable" /> </activity>

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  • Dynamic Auto updating (to UI, Grid) binding list in C# Winform?

    - by Dhana
    I'm not even sure if i'm doing this correctly. But basically I have a list of objects that are built out of a class/interface. From there, I am binding the list to a datagrid view that is on a Windows Form (C#) Here the list is a Sync list which will auto update the UI, in this case datagridview. Every thing works fine now, but now i would like to have the List should have an dynamic object, that is the object will have by default two static property (ID, Name), and at run time user will select remaining properties. These should be bind to the data grid. Any update on the list should be auto reflected in the grid. I am aware that, we can use dynamic objects, but i would like to know , how to approach for solution, datagridview.DataSource = myData; // myData is AutoUpdateList<IPersonInfo> Now IPersonInfo is the type of object, need to add dynamic properties for this type at runtime. public class AutoUpdateList<T> : System.ComponentModel.BindingList<T> { private System.ComponentModel.ISynchronizeInvoke _SyncObject; private System.Action<System.ComponentModel.ListChangedEventArgs> _FireEventAction; public AutoUpdateList() : this(null) { } public AutoUpdateList(System.ComponentModel.ISynchronizeInvoke syncObject) { _SyncObject = syncObject; _FireEventAction = FireEvent; } protected override void OnListChanged(System.ComponentModel.ListChangedEventArgs args) { try { if (_SyncObject == null) { FireEvent(args); } else { _SyncObject.Invoke(_FireEventAction, new object[] { args }); } } catch (Exception) { // TODO: Log Here } } private void FireEvent(System.ComponentModel.ListChangedEventArgs args) { base.OnListChanged(args); } } Could you help out on this?

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  • getting error as Internal Server error

    - by Rishi2686
    Hi There, When I try to run my site it gives error as Internal Server error, when I refresh the page I get my result properly.The error page looks like this: Internal Server Error The server encountered an internal error or misconfiguration and was unable to complete your request. Please contact the server administrator, [email protected] and inform them of the time the error occurred, and anything you might have done that may have caused the error. More information about this error may be available in the server error log. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request. I also checked error_log file on my server, it gives error as: [Sat Jun 12 01:21:55 2010] [error] [client 117.195.6.76] File does not exist: /home/rohit25/public_html/test/500.shtml, referer: http://www.test.mysite.com/home.php sometimes error can be; [Sat May 29 19:35:12 2010] [error] [client 97.85.189.208] File does not exist: /home2/carlton/public_html/test/favicon.ico Are there any changes required in configuration file, I also tried to involve this error code in custom error page, it shows error page, which could not resolve this issue. Your urgent help will be greatly appreciated.

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  • Configurating JOOMLA's e-mail notification for new account

    - by Dion
    I'm using Joomla 1.5 to create a local site for my office. The site will be accessed locally via intranet, and my PC will be the localhost for the site. I'm using a Login pluggin, so that anyone who wanted to enter the site should create an account. In JOOMLA, all user who created their account for the first time will receive a notification e-mail like : "Hello pras, You have been added as a User to Information Center by an Administrator. This e-mail contains your username and password to log in to http://localhost/yaddayadda/ Username: hadisuryo.prasetio Password: xxxx Please do not respond to this message as it is automatically generated and is for information purposes only." but if the user click the URL in the mail, which is, "localhost/yaddayadda/" they will not be directed to my site, but to their own PC's localhost.... My question is : How can I Modified the e-mail or the site configuration so that the URL will not be "localhost/yaddayadda/" anymore, but will be "(My-IP adress)/yaddayadda" I'm not going to host my site to a web hosting service, just using my PC as a host. I've been trying to trace on each config and .ini files...it seems that i have to do something with the "JURI" function or the "$mosConfig_live_site" on the backlink.php file $mosConfig_absolute_path = JPATH_SITE; $mosConfig_live_site = JURI :: base(); $url_array = explode('/', $_SERVER['REQUEST_URI']); Can anyone give me assistance ? Thank You

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  • What would cause objectForKey: to return null with a valid string in place?

    - by theMikeSwan
    I am having an issue with NSDictionary returning null for an NSString even though the string in in the dictionary. Here is the code: - (void)sourceDidChange:(NSNotification *)aNote { NSDictionary *aDict = [aNote userInfo]; DLog(@"%@", aDict); NSString *newSourceString = [aDict objectForKey:@"newSource"]; DLog(@"%@", newSourceString); newSourceString = [newSourceString stringByReplacingOccurrencesOfString:@" " withString:@""]; DLog(@"%@", newSourceString); NSString *inspectorString = [newSourceString stringByAppendingString:@"InspectorController"]; DLog(@"%@", inspectorString); newSourceString = [newSourceString stringByAppendingString:@"ViewController"]; DLog(@"%@", newSourceString); } And I get the following log statements: 2010-04-17 23:50:13.913 CoreDataUISandbox[13417:a0f] -[RightViewController sourceDidChange:] newSource = "Second View"; 2010-04-17 23:50:13.914 CoreDataUISandbox[13417:a0f] -[RightViewController sourceDidChange:] (null) 2010-04-17 23:50:13.916 CoreDataUISandbox[13417:a0f] -[RightViewController sourceDidChange:] (null) 2010-04-17 23:50:13.917 CoreDataUISandbox[13417:a0f] -[RightViewController sourceDidChange:] (null) 2010-04-17 23:50:13.917 CoreDataUISandbox[13417:a0f] -[RightViewController sourceDidChange:] (null) As you can see the string is in the dictionary under the key newSource, yet when I call objectForKey: I get null. I have even tried the fallback option of cleaning the project. Has anyone ever run into this, or have I just forgotten something really basic?

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