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  • Can MySQL reasonably perform queries on billions of rows?

    - by haxney
    I am planning on storing scans from a mass spectrometer in a MySQL database and would like to know whether storing and analyzing this amount of data is remotely feasible. I know performance varies wildly depending on the environment, but I'm looking for the rough order of magnitude: will queries take 5 days or 5 milliseconds? Input format Each input file contains a single run of the spectrometer; each run is comprised of a set of scans, and each scan has an ordered array of datapoints. There is a bit of metadata, but the majority of the file is comprised of arrays 32- or 64-bit ints or floats. Host system |----------------+-------------------------------| | OS | Windows 2008 64-bit | | MySQL version | 5.5.24 (x86_64) | | CPU | 2x Xeon E5420 (8 cores total) | | RAM | 8GB | | SSD filesystem | 500 GiB | | HDD RAID | 12 TiB | |----------------+-------------------------------| There are some other services running on the server using negligible processor time. File statistics |------------------+--------------| | number of files | ~16,000 | | total size | 1.3 TiB | | min size | 0 bytes | | max size | 12 GiB | | mean | 800 MiB | | median | 500 MiB | | total datapoints | ~200 billion | |------------------+--------------| The total number of datapoints is a very rough estimate. Proposed schema I'm planning on doing things "right" (i.e. normalizing the data like crazy) and so would have a runs table, a spectra table with a foreign key to runs, and a datapoints table with a foreign key to spectra. The 200 Billion datapoint question I am going to be analyzing across multiple spectra and possibly even multiple runs, resulting in queries which could touch millions of rows. Assuming I index everything properly (which is a topic for another question) and am not trying to shuffle hundreds of MiB across the network, is it remotely plausible for MySQL to handle this? UPDATE: additional info The scan data will be coming from files in the XML-based mzML format. The meat of this format is in the <binaryDataArrayList> elements where the data is stored. Each scan produces = 2 <binaryDataArray> elements which, taken together, form a 2-dimensional (or more) array of the form [[123.456, 234.567, ...], ...]. These data are write-once, so update performance and transaction safety are not concerns. My naïve plan for a database schema is: runs table | column name | type | |-------------+-------------| | id | PRIMARY KEY | | start_time | TIMESTAMP | | name | VARCHAR | |-------------+-------------| spectra table | column name | type | |----------------+-------------| | id | PRIMARY KEY | | name | VARCHAR | | index | INT | | spectrum_type | INT | | representation | INT | | run_id | FOREIGN KEY | |----------------+-------------| datapoints table | column name | type | |-------------+-------------| | id | PRIMARY KEY | | spectrum_id | FOREIGN KEY | | mz | DOUBLE | | num_counts | DOUBLE | | index | INT | |-------------+-------------| Is this reasonable?

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  • How optimize queries with fully qualified names in t-sql?

    - by tomaszs
    Whe I call: select * from Database.dbo.Table where NAME = 'cat' It takes: 200 ms And when I change database to Database in Management Studio and call it without fully qualified name it's much faster: select * from Table where NAME = 'cat' It takes: 17 ms Is there any way to make fully qualified queries faster without changing database?

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  • How to combine these three sql queries into one?

    - by lam3r4370
    How to combine these two sql queries into one? SELECT DISTINCT * FROM rss WHERE MATCH(content,title) AGAINST ('$filter') SELECT COUNT(content) FROM rss WHERE MATCH(content,title) AGAINST ('$filters') And if the result is 0 from the above query - SELECT DISTINCT * FROM rss WHERE content LIKE '%$filters%' OR title LIKE '%$filters%'; $filter .= $row['filter']; $filters = $row['filter']; $filters may be more than one keyword

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  • Need help with 2 MySql Queries. Join vs Subqueries.

    - by BugBusterX
    I have 2 tables: user: id, name message: sender_id, receiver_id, message, read_at, created_at There are 2 results I need to retrieve and I'm trying to find the best solution. I have included queries that I'm using in the very end. I need to retrieve a list of users, and also with each user have information available whether there are any unread messages from each user (them as sender, me as receiver) and whether or not there are any read messages between us ( they send I'm receiver or I send they are receivers) I need Same as above, but only those members where there has been any messaging between us, sorted by unread first, then by last message received. Can you advise please? Should this be done with joins or subqueries? In first case I do not need the count, I just need to know whether or not there is at least one unread message. I'm posting code and my current queries, please have a look when you get a chance: BTW, everything is the way I want in fist query. My concern is: In second query I would like to order by messages.created_at, but I dont think I can do that with grouping? And also I dont know if this approach is the most optimized and fast. CREATE TABLE `user` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `user` VALUES (1,'User 1'),(2,'User 2'),(3,'User 3'),(4,'User 4'),(5,'User 5'); CREATE TABLE `message` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `sender_id` bigint(20) DEFAULT NULL, `receiver_id` bigint(20) DEFAULT NULL, `message` text, `read_at` datetime DEFAULT NULL, `created_at` datetime NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `message` VALUES (1,3,1,'Messge',NULL,'2010-10-10 10:10:10'),(2,1,4,'Hey','2010-10-10 10:10:12','2010-10-10 10:10:11'),(3,4,1,'Hello','2010-10-10 10:10:19','2010-10-10 10:10:15'),(4,1,4,'Again','2010-10-10 10:10:25','2010-10-10 10:10:21'),(5,3,1,'Hiii',NULL,'2010-10-10 10:10:21'); SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) GROUP BY u.id SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) where m.id IS NOT NULL GROUP BY u.id

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  • How to translate this 2 queries from Mysql to Postgresql? :

    - by xRobot
    How can I translate this 2 queries in postgresql ? : CREATE TABLE `example` ( `id` int(10) unsigned NOT NULL auto_increment, `from` varchar(255) NOT NULL default '0', `message` text NOT NULL, `lastactivity` timestamp NULL default '0000-00-00 00:00:00', `read` int(10) unsigned NOT NULL, PRIMARY KEY (`id`), KEY `from` (`from`) ) DEFAULT CHARSET=utf8; Query: SELECT * FROM table_1 LEFT OUTER JOIN table_2 ON ( table_1.id = table_2.id ) WHERE (table_1.lastactivity > NOW()-100);

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  • Which is more efficient in mysql, a big join or multiple queries of single table?

    - by Tom Greenpoint
    I have a mysql database like this Post – 500,000 rows (Postid,Userid) Photo – 200,000 rows (Photoid,Postid) About 50,000 posts have photos, average 4 each, most posts do not have photos. I need to get a feed of all posts with photos for a userid, average 50 posts each. Which approach would be more efficient? 1: Big Join select * from post left join photo on post.postid=photo.postid where post.userid=123 2: Multiple queries select * from post where userid=123 while (loop through rows) { select * from photo where postid=row[postid] }

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  • How to write native SQL queries in Hibernate without hardcoding table names and fields?

    - by serg555
    Sometimes you have to write some of your queries in native SQL rather than hibernate HQL. Is there a nice way to avoid hardcoding table names and fields and get this data from existing mapping? For example instead of: String sql = "select user_name from tbl_user where user_id = :id"; something like: String sql = "select " + Hibernate.getFieldName("user.name") + " from " + Hibernate.getTableName(User.class) + " where " + Hibernate.getFieldName("user.id") + " = :id";

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  • Nested dereferencing arrows in Perl: to omit or not to omit?

    - by DVK
    In Perl, when you have a nested data structure, it is permissible to omit de-referencing arrows to 2d and more level of nesting. In other words, the following two syntaxes are identical: my $hash_ref = { 1 => [ 11, 12, 13 ], 3 => [31, 32] }; my $elem1 = $hash_ref->{1}->[1]; my $elem2 = $hash_ref->{1}[1]; # exactly the same as above Now, my question is, is there a good reason to choose one style over the other? It seems to be a popular bone of stylistic contention (Just on SO, I accidentally bumped into this and this in the space of 5 minutes). So far, none of the usual suspects says anything definitive: perldoc merely says "you are free to omit the pointer dereferencing arrow". Conway's "Perl Best Practices" says "whenever possible, dereference with arrows", but it appears to only apply to the context of dereferencing the main reference, not optional arrows on 2d level of nested data structures. "MAstering Perl for Bioinfirmatics" author James Tisdall doesn't give very solid preference either: "The sharp-witted reader may have noticed that we seem to be omitting arrow operators between array subscripts. (After all, these are anonymous arrays of anonymous arrays of anonymous arrays, etc., so shouldn't they be written [$array-[$i]-[$j]-[$k]?) Perl allows this; only the arrow operator between the variable name and the first array subscript is required. It make things easier on the eyes and helps avoid carpal tunnel syndrome. On the other hand, you may prefer to keep the dereferencing arrows in place, to make it clear you are dealing with references. Your choice." Personally, i'm on the side of "always put arrows in, since itg's more readable and obvious tiy're dealing with a reference".

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  • [Java] Nested methods vs "piped" methods, which is better?

    - by Michael Mao
    Hi: Since uni, I've programming in Java for 3 years, although I am not fully dedicated to this language, I have spent quite some time in it, nevertheless. I understand both ways, just curious which style do you prefer. public class Test{ public static void main(String[] args) { System.out.println(getAgent().getAgentName()); } private static Agent getAgent() { return new Agent(); }} class Agent{ private String getAgentName() { return "John Smith"; }} I am pretty happy with nested method calls such like the following public class Test{ public static void main(String[] args) { getAgentName(getAgent()); } private static void getAgentName(Agent agent) { System.out.println(agent.getName()); } private static Agent getAgent() { return new Agent(); }} class Agent { public String getName(){ return "John Smith"; }} They have identical output I saw "John Smith" twice. I wonder, if one way of doing this has better performance or other advantages over the other. Personally I prefer the latter, since for nested methods I can certainly tell which starts first, and which is after. The above code is but a sample, The code that I am working with now is much more complicated, a bit like a maze... So switching between the two styles often blows my head in no time.

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  • What is better in WPF for UI layout, using one Grid, or nested Grids.

    - by Matthijs Wessels
    I am making a UI in WPF, I have a bunch of functional areas and I use a Grid to organize it. Now the Grid that I want is not uniform, as in, some functional area will span multiple cells in the Grid. I was wondering what the best practise is in solving this. Should I create one grid and then for each functional area set it to span multiple cells, or should I split it up into multiple nested Grids. In this image, the leftmost panel (panels separated by the gray bar) is what I want. The middle panel shows one grid where the blue lines are overlapped by a functional area. The rightmost panel shows how I could do it with nested grids. You can see the green grid has one horizontal split. In the bottom cell is the yellow Grid with a vertical split. In side the left cell is the red Grid with again a horizontal split. I was just wondering what is best practise, the middle or the right panel.

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  • How to create nested ViewComponents in Monorail and NVelocity?

    - by rob_g
    I have been asked to update the menu on a website we maintain. The website uses Castle Windors Monorail and NVelocity as the template. The menu is currently rendered using custom made subclasses of ViewComponent, which render li elements. At the moment there is only one (horizontal) level, so the current mechanism is fine. I have been asked to add drop down menus to some of the existing menus. As this is the first time I have seen Monorail and NVelocity, I'm a little lost. What currently exists: <ul> #component(MenuComponent with "title=Home" "hover=autoselect" "link=/") #component(MenuComponent with "title=Videos" "hover=autoselect") #component(MenuComponent with "title=VPS" "hover=autoselect" "link=/vps") #component(MenuComponent with "title=Add-Ons" "hover=autoselect" "link=/addons") #component(MenuComponent with "title=Hosting" "hover=autoselect" "link=/hosting") #component(MenuComponent with "title=Support" "hover=autoselect" "link=/support") #component(MenuComponent with "title=News" "hover=autoselect" "link=/news") #component(MenuComponent with "title=Contact Us" "hover=autoselect" "link=/contact-us") </ul> Is it possible to have nested MenuComponents (or a new SubMenuComponent) something like: <ul> #component(MenuComponent with "title=Home" "hover=autoselect" "link=/") #component(MenuComponent with "title=Videos" "hover=autoselect") #blockcomponent(MenuComponent with "title=VPS" "hover=autoselect" "link=/vps") #component(SubMenuComponent with "title="Plans" "hover=autoselect" "link=/vps/plans") #component(SubMenuComponent with "title="Operating Systems" "hover=autoselect" "link=/vps/os") #component(SubMenuComponent with "title="Supported Applications" "hover=autoselect" "link=/vps/apps") #end #component(MenuComponent with "title=Add-Ons" "hover=autoselect" "link=/addons") #component(MenuComponent with "title=Hosting" "hover=autoselect" "link=/hosting") #component(MenuComponent with "title=Support" "hover=autoselect" "link=/support") #component(MenuComponent with "title=News" "hover=autoselect" "link=/news") #component(MenuComponent with "title=Contact Us" "hover=autoselect" "link=/contact-us") </ul> I need to draw the sub menu (ul and li elements) inside the overridden Render method on MenuComponent, so using nested ViewComponent derivatives may not work. I would like a method keep the basically declarative method for creating menus, if at all possible.

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  • Can we run two simultaneous non-nested loops in Perl?

    - by Mike
    Part of my code goes like this: while(1){ my $winmm = new Win32::MediaPlayer; $winmm->load('1.mp3'); $winmm->play; $winmm->volume(100); Do Some Stuff; last if some condition is met; } Problem is: I want the music to be always on when I'm in the Do Some Stuff stage in the while loop. But the length of the music is so short that it will come to a full stop before I go to the next stage, so I want the music to repeat itself, but the Win32::Mediaplayer module does not seem to have a repeat mode, so I'm thinking of doing an infinite loop for the music playing part. Like this: while(1){ my $winmm = new Win32::MediaPlayer; $winmm->load('1.mp3'); $winmm->play; $winmm->volume(100); } while(2){ Do some stuff; last if some condition is met } But based on my current Perl knowledge if I'm in the while(1) part, I can never go to the while(2) part. Even if it comes to a nested loop, I have to do something to break out of the inside loop before going to the other part of the outside loop. The answer to my question "Can we run two simultaneous non-nested loops in Perl?" may be a NO, but I assume there is some way of handling such situation. Correct me if I'm wrong. Thanks as always for any comments/suggestions :) UPDATE I really appreciate the help from everyone. Thanks :) So the answer to my question is a YES, not a NO. I'm happy that I've learned how to use fork() and threads to solve a real problem :)

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  • What's the jquery CSS3 selector for excluding nested descendents?

    - by Danjah
    Per my SO question here, which has turned to jquery to solve this, but which may be worked back into YUI if I get my thinking straight, I need a selector to exclude descendents. The solution proposed says something like this: $( '.revealer:not(.revealer > .revealer)' ); To fit more accurately with my situation, because I have multiple HTML chunks to perform the same test on, I have updated it be: $( '#_revealerEl_0 .handle:not(#_revealerEl_0 .reveal .handle)' ); The HTML its selecting on (image there are numerous copies of this same chunk on a page, each needing to be treated alone - an id attribute is assigned to each 'revealer'): <div class="revealer"> <div class="hotspot"> <a class="handle" href="javascript:;">A</a> <div class="reveal"> <p>Content A.</p> </div> <div class="reveal"> <p>Content B.</p> <!-- nested revealer --> <div class="revealer"> <div class="hotspot"> <a class="handle" href="javascript:;">A</a> <div class="reveal"> <p>Sub-content A.</p> </div> <div class="reveal"> <p>Sub-content B.</p> </div> </div> </div> </div> </div> </div> In a nutshell: I need to target 'top level' handles within a 'hotspot', per revealer - and no nested descendents with the same class names. thanks, d

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  • Circular reference with entity manager factory

    - by CodesLikeA_Mokey
    Every time I try and start my app, I get this error on startup: SEVERE: Exception sending context initialized event to listener instance of class org.springframework.web.context.ContextLoaderListener org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor#0': Initialization of bean failed; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'identityAccessAppConfig': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: com.package.identityaccess.identity.UserRepository com.package.identityaccess.IdentityAccessAppConfig.userRepository; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userRepository': Cannot create inner bean '(inner bean)' of type [org.springframework.orm.jpa.SharedEntityManagerCreator] while setting bean property 'entityManager'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name '(inner bean)#1': Cannot resolve reference to bean 'identityAccessEntityManagerFactory' while setting constructor argument; nested exception is org.springframework.beans.factory.BeanCurrentlyInCreationException: Error creating bean with name 'identityAccessEntityManagerFactory': Requested bean is currently in creation: Is there an unresolvable circular reference? at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:529) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:458) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:295) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:223) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:292) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:198) at org.springframework.context.support.AbstractApplicationContext.registerBeanPostProcessors(AbstractApplicationContext.java:741) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:464) at org.springframework.web.context.ContextLoader.configureAndRefreshWebApplicationContext(ContextLoader.java:389) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:294) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:112) at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4797) at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5291) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150) at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1559) at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1549) at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:334) at java.util.concurrent.FutureTask.run(FutureTask.java:166) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615) at java.lang.Thread.run(Thread.java:722) Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'identityAccessAppConfig': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: com.package.identityaccess.identity.UserRepository com.package.identityaccess.IdentityAccessAppConfig.userRepository; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userRepository': Cannot create inner bean '(inner bean)' of type [org.springframework.orm.jpa.SharedEntityManagerCreator] while setting bean property 'entityManager'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name '(inner bean)#1': Cannot resolve reference to bean 'identityAccessEntityManagerFactory' while setting constructor argument; nested exception is org.springframework.beans.factory.BeanCurrentlyInCreationException: Error creating bean with name 'identityAccessEntityManagerFactory': Requested bean is currently in creation: Is there an unresolvable circular reference? at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:288) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1116) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:458) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:295) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:223) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:292) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:194) at org.springframework.beans.factory.support.ConstructorResolver.instantiateUsingFactoryMethod(ConstructorResolver.java:353) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.instantiateUsingFactoryMethod(AbstractAutowireCapableBeanFactory.java:1025) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBeanInstance(AbstractAutowireCapableBeanFactory.java:921) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:487) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:458) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:295) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:223) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:292) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:198) at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBeansOfType(DefaultListableBeanFactory.java:438) at org.springframework.beans.factory.BeanFactoryUtils.beansOfTypeIncludingAncestors(BeanFactoryUtils.java:277) at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.detectPersistenceExceptionTranslators(PersistenceExceptionTranslationInterceptor.java:139) at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.<init>(PersistenceExceptionTranslationInterceptor.java:79) at org.springframework.dao.annotation.PersistenceExceptionTranslationAdvisor.<init>(PersistenceExceptionTranslationAdvisor.java:71) at org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor.setBeanFactory(PersistenceExceptionTranslationPostProcessor.java:85) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeAwareMethods(AbstractAutowireCapableBeanFactory.java:1502) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1470) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:521) ... 20 more Caused by: org.springframework.beans.factory.BeanCreationException: Could not autowire field: com.package.identityaccess.identity.UserRepository com.package.identityaccess.IdentityAccessAppConfig.userRepository; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userRepository': Cannot create inner bean '(inner bean)' of type [org.springframework.orm.jpa.SharedEntityManagerCreator] while setting bean property 'entityManager'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name '(inner bean)#1': Cannot resolve reference to bean 'identityAccessEntityManagerFactory' while setting constructor argument; nested exception is org.springframework.beans.factory.BeanCurrentlyInCreationException: Error creating bean with name 'identityAccessEntityManagerFactory': Requested bean is currently in creation: Is there an unresolvable circular reference? at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:514) at org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:87) at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:285) ... 45 more Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userRepository': Cannot create inner bean '(inner bean)' of type [org.springframework.orm.jpa.SharedEntityManagerCreator] while setting bean property 'entityManager'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name '(inner bean)#1': Cannot resolve reference to bean 'identityAccessEntityManagerFactory' while setting constructor argument; nested exception is org.springframework.beans.factory.BeanCurrentlyInCreationException: Error creating bean with name 'identityAccessEntityManagerFactory': Requested bean is currently in creation: Is there an unresolvable circular reference? at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveInnerBean(BeanDefinitionValueResolver.java:282) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:126) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1387) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1128) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:458) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:295) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:223) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:292) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:194) at org.springframework.beans.factory.support.DefaultListableBeanFactory.findAutowireCandidates(DefaultListableBeanFactory.java:912) at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:855) at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:770) at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:486) ... 47 more Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name '(inner bean)#1': Cannot resolve reference to bean 'identityAccessEntityManagerFactory' while setting constructor argument; nested exception is org.springframework.beans.factory.BeanCurrentlyInCreationException: Error creating bean with name 'identityAccessEntityManagerFactory': Requested bean is currently in creation: Is there an unresolvable circular reference? at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:329) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:107) at org.springframework.beans.factory.support.ConstructorResolver.resolveConstructorArguments(ConstructorResolver.java:615) at org.springframework.beans.factory.support.ConstructorResolver.instantiateUsingFactoryMethod(ConstructorResolver.java:441) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.instantiateUsingFactoryMethod(AbstractAutowireCapableBeanFactory.java:1025) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBeanInstance(AbstractAutowireCapableBeanFactory.java:921) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:487) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:458) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveInnerBean(BeanDefinitionValueResolver.java:271) ... 60 more Caused by: org.springframework.beans.factory.BeanCurrentlyInCreationException: Error creating bean with name 'identityAccessEntityManagerFactory': Requested bean is currently in creation: Is there an unresolvable circular reference? at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.beforeSingletonCreation(DefaultSingletonBeanRegistry.java:327) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:217) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:292) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:194) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:323) I am new to configuring spring through java and have been spinning circles for days. I have my application which includes 2 separate modules. The identity-access module will handle user and access information and will have a datasource to an older database. The other module module2 will eventually have its own database. Here are the config files: application: @Configuration @EnableWebMvc @ComponentScan(basePackages = "com.package.myapp.web") @ImportResource({"classpath:com/package/appbase/appbase-context.xml"}) @Import(com.package.identityaccess.IdentityAccessAppConfig.class) public class IMSAppConfig extends WebMvcConfigurerAdapter { @Override public void addResourceHandlers(ResourceHandlerRegistry registry) { registry.addResourceHandler("/resources/**").addResourceLocations("ims/resources/"); } } identity-access: @Configuration @ComponentScan(basePackages = "com.package.identityaccess") @EnableJpaRepositories(entityManagerFactoryRef = "identityAccessEntityManagerFactory", value = "com.package.identityaccess") @EnableTransactionManagement public class IdentityAccessAppConfig { @Autowired UserRepository userRepository; @Bean public DataSource identityAccessDataSource() throws IOException, SQLException { return new SelfConfiguringBasicDataSource(System.getProperty("db_properties_path") + "/dev.oracle.properties", ""); } @Bean public Map<String, Object> identityAccessJpaProperties() { Map<String, Object> props = new HashMap<>(); props.put("eclipselink.weaving", "false"); props.put("eclipselink.target-database", OraclePlatform.class.getName()); return props; } @Bean public JpaVendorAdapter identityAccessJpaVendorAdapter() { EclipseLinkJpaVendorAdapter eclipseLinkJpaVendorAdapter = new EclipseLinkJpaVendorAdapter(); eclipseLinkJpaVendorAdapter.setDatabasePlatform(OraclePlatform.class.getName()); eclipseLinkJpaVendorAdapter.setGenerateDdl(false); eclipseLinkJpaVendorAdapter.setShowSql(true); return eclipseLinkJpaVendorAdapter; } @Bean public PlatformTransactionManager identityAccessTransactionManager() throws IOException, SQLException { JpaTransactionManager txManager = new JpaTransactionManager(); txManager.setEntityManagerFactory(identityAccessEntityManagerFactory().getObject()); return txManager; } @Bean public LocalContainerEntityManagerFactoryBean identityAccessEntityManagerFactory() throws IOException, SQLException { LocalContainerEntityManagerFactoryBean lef = new LocalContainerEntityManagerFactoryBean(); lef.setDataSource(identityAccessDataSource()); lef.setJpaPropertyMap(identityAccessJpaProperties()); lef.setJpaVendorAdapter(identityAccessJpaVendorAdapter()); lef.setPackagesToScan("com.package.identityaccess"); return lef; } @Bean public AuthenticationService authenticationService() { return new AuthenticationServiceImpl(userRepository); } } module2: @Configuration @ComponentScan(basePackages = "com.package.myapp.core") @EnableJpaRepositories("com.package.myapp.core.domain") @EnableTransactionManagement public class ModuleTwoAppConfig { @Bean public DataSource dataSource() { EmbeddedDatabaseBuilder embeddedDatabaseBuilder = new EmbeddedDatabaseBuilder(); embeddedDatabaseBuilder.setType(EmbeddedDatabaseType.HSQL); embeddedDatabaseBuilder.addScript("setup.sql"); return embeddedDatabaseBuilder.build(); } @Bean public Map<String, Object> jpaProperties() { Map<String, Object> props = new HashMap<>(); props.put("eclipselink.weaving", "false"); props.put("eclipselink.ddl-generation", "create-tables"); props.put("eclipselink.target-database", HSQLPlatform.class.getName()); return props; } @Bean public JpaVendorAdapter jpaVendorAdapter() { EclipseLinkJpaVendorAdapter eclipseLinkJpaVendorAdapter = new EclipseLinkJpaVendorAdapter(); eclipseLinkJpaVendorAdapter.setDatabasePlatform(HSQLPlatform.class.getName()); eclipseLinkJpaVendorAdapter.setGenerateDdl(true); eclipseLinkJpaVendorAdapter.setShowSql(true); return eclipseLinkJpaVendorAdapter; } @Bean public PlatformTransactionManager transactionManager() { JpaTransactionManager txManager = new JpaTransactionManager(); txManager.setEntityManagerFactory(entityManagerFactory().getObject()); return txManager; } @Bean public LocalContainerEntityManagerFactoryBean entityManagerFactory() { LocalContainerEntityManagerFactoryBean lef = new LocalContainerEntityManagerFactoryBean(); lef.setDataSource(dataSource()); lef.setJpaPropertyMap(jpaProperties()); lef.setJpaVendorAdapter(jpaVendorAdapter()); lef.setPackagesToScan("com.package.myapp.core.domain"); return lef; } } UserRepository (uses spring-data): public interface UserRepository extends JpaRepository<User, Long> { @Query("select u from User u where u.user_id = ?1") User findByUserId(String userId); } Can you see any problems with what I've done?

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  • ASP.NET MVC <OutputCache> SqlDependency (CommandNotification?) with LINQ queries

    - by sinni800
    Hello, I use LINQ queries in my ASP.NET MVC application and want to use OutputCache in some of my Actions. I hear this should be possible with CommandNotifications. But those seem to only go for self-created SQLCommands, or am I wrong? Can I manually tell SQL server to send SQLDependency notifications if certain tables change? And if yes, how can I attach them to the OutputCache? Another side question: Can you do this with strongly types views too? Thank you in advance...

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  • How can I generate an Expression tree that queries an object with List<T> as a property?

    - by David Robbins
    Forgive my clumsy explanation, but I have a class that contains a List: public class Document { public int OwnerId { get; set; } public List<User> Users { get; set; } public Document() { } } public class User { public string UserName { get; set; } public string Department { get; set; } } Currently I use PredicateBuilder to perform dynmica queries on my objects. How can I turn the following LINQ statement into an Expression Tree: var predicate= PredicateBuilder.True<User>(); predicate= predicate.And<User>(user => user.Deparment == "HR"); var deptDocs = documents.AsQueryable() .Where(doc => doc.Users .AsQueryable().Count(predicate) > 0) .ToList(); In other words var deptDocs = documents.HasUserAttributes("Department", "HR").ToList();

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  • Trying to use VB to automate some queries. Running into what looks like a string problem

    - by Jeff
    Hi there I'm using MS Access 2003 and I'm trying to execute a few queries at once using VB. When I write out the query in SQL it works fine, but when I try to do it in VB it asks me to "Enter Parameter Value" for DEPA, then DND (which are the first few letters of a two strings I have). Here's the code: Option Compare Database Public Sub RemoveDupelicateDepartments() Dim oldID As String Dim newID As String Dim sqlStatement As String oldID = "DND-01" newID = "DEPA-04" sqlStatement = "UPDATE [Clean student table] SET [HomeDepartment]=" & newID & " WHERE [HomeDepartment]=" & oldID & ";" DoCmd.RunSQL sqlStatement & "" End Sub It looks to me as though it's taking in the string up to the - then nothing else. I dunno, that's why I'm asking lol. What should my code look like?

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