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  • Remove/squash entries in a vertical hash

    - by Forkrul Assail
    I have a grid that represents an X, Y matrix, stored as a hash here. Some points on the X Y matrix may have values (as type string), and some may not. A typical grid could look like this: {[9, 5]=>"Alaina", [10, 3]=>"Courtney", [11, 1]=>"Gladys", [8, 7]=>"Alford", [14, 11]=>"Lesley", [17, 2]=>"Lawson", [0, 5]=>"Katrine", [2, 1]=>"Tyra", [3, 3]=>"Fredy", [1, 7]=>"Magnus", [6, 9]=>"Nels", [7, 11]=>"Kylie", [11, 0]=>"Kellen", [10, 2]=>"Johan", [14, 10]=>"Justice", [0, 4]=>"Barton", [2, 0]=>"Charley", [3, 2]=>"Magnolia", [1, 6]=>"Maximo", [7, 10]=>"Olga", [19, 5]=>"Isadore", [16, 3]=>"Delfina", [17, 1]=>"Noe", [20, 11]=>"Francis", [10, 5]=>"Creola", [9, 3]=>"Bulah", [8, 1]=>"Lempi", [11, 7]=>"Raquel", [13, 11]=>"Jace", [1, 5]=>"Garth", [3, 1]=>"Ernest", [2, 3]=>"Malcolm", [0, 7]=>"Alejandrin", [7, 9]=>"Marina", [6, 11]=>"Otilia", [16, 2]=>"Hailey", [20, 10]=>"Brandt", [8, 0]=>"Madeline", [9, 2]=>"Leanne", [13, 10]=>"Jenifer", [1, 4]=>"Humberto", [3, 0]=>"Nicholaus", [2, 2]=>"Nadia", [0, 6]=>"Abigail", [6, 10]=>"Zola", [20, 5]=>"Clementina", [23, 3]=>"Alvah", [19, 11]=>"Wallace", [11, 5]=>"Tracey", [8, 3]=>"Hulda", [9, 1]=>"Jedidiah", [10, 7]=>"Annetta", [12, 11]=>"Nicole", [2, 5]=>"Alison", [0, 1]=>"Wilma", [1, 3]=>"Shana", [3, 7]=>"Judd", [4, 9]=>"Lucio", [5, 11]=>"Hardy", [19, 10]=>"Immanuel", [9, 0]=>"Uriel", [8, 2]=>"Milton", [12, 10]=>"Elody", [5, 10]=>"Alexanne", [1, 2]=>"Lauretta", [0, 0]=>"Louvenia", [2, 4]=>"Adelia", [21, 5]=>"Erling", [18, 11]=>"Corene", [22, 3]=>"Haskell", [11, 11]=>"Leta", [10, 9]=>"Terrence", [14, 1]=>"Giuseppe", [15, 3]=>"Silas", [12, 5]=>"Johnnie", [4, 11]=>"Aurelie", [5, 9]=>"Meggie", [2, 7]=>"Phoebe", [0, 3]=>"Sister", [1, 1]=>"Violet", [3, 5]=>"Lilian", [18, 10]=>"Eusebio", [11, 10]=>"Emma", [15, 2]=>"Theodore", [14, 0]=>"Cassidy", [4, 10]=>"Edmund", [2, 6]=>"Claire", [0, 2]=>"Madisen", [1, 0]=>"Kasey", [3, 4]=>"Elijah", [17, 11]=>"Susana", [20, 1]=>"Nicklaus", [21, 3]=>"Kelsie", [10, 11]=>"Garnett", [11, 9]=>"Emanuel", [15, 1]=>"Louvenia", [14, 3]=>"Otho", [13, 5]=>"Vincenza", [3, 11]=>"Tate", [2, 9]=>"Beau", [5, 7]=>"Jason", [6, 1]=>"Jayde", [7, 3]=>"Lamont", [4, 5]=>"Curt", [17, 10]=>"Mack", [21, 2]=>"Lilyan", [10, 10]=>"Ruthe", [14, 2]=>"Georgianna", [4, 4]=>"Nyasia", [6, 0]=>"Sadie", [16, 11]=>"Emil", [21, 1]=>"Melba", [20, 3]=>"Delia", [3, 10]=>"Rosalee", [2, 8]=>"Myrtle", [7, 2]=>"Rigoberto", [14, 5]=>"Jedidiah", [13, 3]=>"Flavie", [12, 1]=>"Evie", [8, 9]=>"Olaf", [9, 11]=>"Stan", [20, 2]=>"Judge", [5, 5]=>"Cassie", [7, 1]=>"Gracie", [6, 3]=>"Armando", [4, 7]=>"Delia", [3, 9]=>"Marley", [16, 10]=>"Robyn", [2, 11]=>"Richie", [12, 0]=>"Gilberto", [13, 2]=>"Dedrick", [9, 10]=>"Liam", [5, 4]=>"Jabari", [7, 0]=>"Enola", [6, 2]=>"Lela", [3, 8]=>"Jade", [2, 10]=>"Johnson", [15, 5]=>"Willow", [12, 3]=>"Fredrick", [13, 1]=>"Beau", [9, 9]=>"Carlie", [8, 11]=>"Daisha", [6, 5]=>"Declan", [4, 1]=>"Carolina", [5, 3]=>"Cruz", [7, 7]=>"Jaime", [0, 9]=>"Anthony", [1, 11]=>"Esta", [13, 0]=>"Shaina", [12, 2]=>"Alec", [8, 10]=>"Lora", [6, 4]=>"Emely", [4, 0]=>"Rodger", [5, 2]=>"Cedrick", [0, 8]=>"Collin", [1, 10]=>"Armani", [16, 5]=>"Brooks", [19, 3]=>"Eleanora", [18, 1]=>"Alva", [7, 5]=>"Melissa", [5, 1]=>"Tabitha", [4, 3]=>"Aniya", [6, 7]=>"Marc", [1, 9]=>"Marjorie", [0, 11]=>"Arvilla", [19, 2]=>"Adela", [7, 4]=>"Zakary", [5, 0]=>"Emely", [4, 2]=>"Alison", [1, 8]=>"Lorenz", [0, 10]=>"Lisandro", [17, 5]=>"Aylin", [18, 3]=>"Giles", [19, 1]=>"Kyleigh", [8, 5]=>"Mary", [11, 3]=>"Claire", [10, 1]=>"Avis", [9, 7]=>"Manuela", [15, 11]=>"Chesley", [18, 2]=>"Kristopher", [24, 3]=>"Zola", [8, 4]=>"Pietro", [10, 0]=>"Delores", [11, 2]=>"Timmy", [15, 10]=>"Khalil", [18, 5]=>"Trudie", [17, 3]=>"Rafael", [16, 1]=>"Anthony"} What I need to do though, is basically remove all the empty entries. Let's say [17,3] = Raphael does not have an element in front of if (let's say - no [16,3] exists) then [17,3] should become [16,3] etc. So basically all empty items will be popped off the vertical (row) structure of the hash. Are there functions I should have a look at or is there an easy squash-like method that would just remove blanks and adjust and move other items? Thanks in advance for your help.

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  • C# Active Directory - Check username / password

    - by Michael G
    I'm using the following code on Windows Vista Ultimate SP1 to query our active directory server to check the user name and password of a user on a domain. public Object IsAuthenticated() { String domainAndUsername = strDomain + @"\" + strUser; DirectoryEntry entry = new DirectoryEntry(_path, domainAndUsername, strPass); SearchResult result; try { //Bind to the native AdsObject to force authentication. DirectorySearcher search = new DirectorySearcher(entry) { Filter = ("(SAMAccountName=" + strUser + ")") }; search.PropertiesToLoad.Add("givenName"); // First Name search.PropertiesToLoad.Add("sn"); // Last Name search.PropertiesToLoad.Add("cn"); // Last Name result = search.FindOne(); if (null == result) { return null; } //Update the new path to the user in the directory. _path = result.Path; _filterAttribute = (String)result.Properties["cn"][0]; } catch (Exception ex) { return new Exception("Error authenticating user. " + ex.Message); } return user; } the target is using .NET 3.5, and compiled with VS 2008 standard I'm logged in under a domain account that is a domain admin where the application is running. The code works perfectly on windows XP; but i get the following exception when running it on Vista: System.DirectoryServices.DirectoryServicesCOMException (0x8007052E): Logon failure: unknown user name or bad password. at System.DirectoryServices.DirectoryEntry.Bind(Boolean throwIfFail) at System.DirectoryServices.DirectoryEntry.Bind() at System.DirectoryServices.DirectoryEntry.get_AdsObject() at System.DirectoryServices.DirectorySearcher.FindAll(Boolean findMoreThanOne) at System.DirectoryServices.DirectorySearcher.FindOne() at Chain_Of_Custody.Classes.Authentication.LdapAuthentication.IsAuthenticated() at System.DirectoryServices.DirectoryEntry.Bind(Boolean throwIfFail) at System.DirectoryServices.DirectoryEntry.Bind() at System.DirectoryServices.DirectoryEntry.get_AdsObject() at System.DirectoryServices.DirectorySearcher.FindAll(Boolean findMoreThanOne) at System.DirectoryServices.DirectorySearcher.FindOne() at Chain_Of_Custody.Classes.Authentication.LdapAuthentication.IsAuthenticated() I've tried changing the authentication types, I'm not sure what's going on. See also: http://stackoverflow.com/questions/290548/c-validate-a-username-and-password-against-active-directory

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  • django: cannot import settings, cannot login to admin, cannot change admin password

    - by xpanta
    Hi, It seems that I am completely lost here. Yesterday I noticed that I cannot login to the admin panel (don't use it much, so it's been some weeks since last login). I thought that I might have changed the admin password and now I can't remember it (though I doubt it). I tried django-admin.py changepassword (using django 1.2.1) but it said that 'changepassword' is unknown command (I have all the necessary imports in my settings.py. Admin interface used to work ok). Then I gave a django-admin.py validate. Then the hell begun. django-admin.py validate gave me this error: Error: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined. I then gave a set DJANGO_SETTINGS_MODULE=myproject.settings and then again a django-admin.py validate This is what I get now: Error: Could not import settings 'myproject.settings' (Is it on sys.path? Does it have syntax errors?): No module named myproject.settings and now I am lost. I tried django console and sys.path.append('c:\workspace') or sys.append('c:\workspace\myproject') but still get the same errors. I use windows 7 and my project dir is c:\workspace. I don't use a PYTHONPATH variable (although I tried setting it temporarily to C:\workspace but I still get the same error). I don't use Apache, just the django development server. What am I doing wrong? My web page works fine. I think that the fact that I can't login as admin is related to the previous import error, no? PS: I also tried this: http://coderseye.com/2007/howto-reset-the-admin-password-in-django.html but still I couldn't change admin password for some reason. Although I could create another admin user (with which I couldn't login).

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  • Insert MANY key value pairs fast into berkeley db with hash access

    - by Kungi
    Hi, i'm trying to build a hash with berkeley db, which shall contain many tuples (approx 18GB of key value pairs), but in all my tests the performance of the insert operations degrades drastically over time. I've written this script to test the performance: #include<iostream> #include<db_cxx.h> #include<ctime> #define MILLION 1000000 int main () { long long a = 0; long long b = 0; int passes = 0; int i = 0; u_int32_t flags = DB_CREATE; Db* dbp = new Db(NULL,0); dbp->set_cachesize( 0, 1024 * 1024 * 1024, 1 ); int ret = dbp->open( NULL, "test.db", NULL, DB_HASH, flags, 0); time_t time1 = time(NULL); while ( passes < 100 ) { while( i < MILLION ) { Dbt key( &a, sizeof(long long) ); Dbt data( &b, sizeof(long long) ); dbp->put( NULL, &key, &data, 0); a++; b++; i++; } DbEnv* dbep = dbp->get_env(); int tmp; dbep->memp_trickle( 50, &tmp ); i=0; passes++; std::cout << "Inserted one million --> pass: " << passes << " took: " << time(NULL) - time1 << "sec" << std::endl; time1 = time(NULL); } } Perhaps you can tell me why after some time the "put" operation takes increasingly longer and maybe how to fix this. Thanks for your help, Andreas

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  • Parsing Chunk of Data into Hash of Array With Perl

    - by neversaint
    I have data that looks like this: #info #info2 1:SRX004541 Submitter: UT-MGS, UT-MGS Study: Glossina morsitans transcript sequencing project(SRP000741) Sample: Glossina morsitans(SRS002835) Instrument: Illumina Genome Analyzer Total: 1 run, 8.3M spots, 299.9M bases Run #1: SRR016086, 8330172 spots, 299886192 bases 2:SRX004540 Submitter: UT-MGS Study: Anopheles stephensi transcript sequencing project(SRP000747) Sample: Anopheles stephensi(SRS002864) Instrument: Solexa 1G Genome Analyzer Total: 1 run, 8.4M spots, 401M bases Run #1: SRR017875, 8354743 spots, 401027664 bases 3:SRX002521 Submitter: UT-MGS Study: Massive transcriptional start site mapping of human cells under hypoxic conditions.(SRP000403) Sample: Human DLD-1 tissue culture cell line(SRS001843) Instrument: Solexa 1G Genome Analyzer Total: 6 runs, 27.1M spots, 977M bases Run #1: SRR013356, 4801519 spots, 172854684 bases Run #2: SRR013357, 3603355 spots, 129720780 bases Run #3: SRR013358, 3459692 spots, 124548912 bases Run #4: SRR013360, 5219342 spots, 187896312 bases Run #5: SRR013361, 5140152 spots, 185045472 bases Run #6: SRR013370, 4916054 spots, 176977944 bases What I want to do is to create a hash of array with first line of each chunk as keys and SR## part of lines with "^Run" as its array member: $VAR = { 'SRX004541' => ['SRR016086'], # etc } But why my construct doesn't work. And it must be a better way to do it. use Data::Dumper; my %bighash; my $head = ""; my @temp = (); while ( <> ) { chomp; next if (/^\#/); if ( /^\d{1,2}:(\w+)/ ) { print "$1\n"; $head = $1; } elsif (/^Run \#\d+: (\w+),.*/){ print "\t$1\n"; push @temp, $1; } elsif (/^$/) { push @{$bighash{$head}}, [@temp]; @temp =(); } } print Dumper \%bighash ;

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  • Outlook Interop: Password protected PST file headache

    - by Ed Manet
    Okay, I have no problem identifying the .PST file using the Outlook Interop assemblies in a C# app. But as soon as I hit a password protected file, I am prompted for a password. We are in the process of disabling the use of PSTs in our organization and one of the steps is to unload the PST files from the users' Outlook profile. I need to have this app run silently and not prompt the user. Any ideas? Is there a way to create the Outlook.Application object with no UI and then just try to catch an Exception on password protected files? // create the app and namespace Application olApp = new Application(); NameSpace olMAPI = olApp.GetNamespace("MAPI"); // get the storeID of the default inbox string rootStoreID = olMAPI.GetDefaultFolder(OlDefaultFolders.olFolderInbox).StoreID; // loop thru each of the folders foreach (MAPIFolder fo in olMAPI.Folders) { // compare the first 75 chars of the storeid // to prevent removing the Inbox folder. string s1 = rootStoreID.Substring(1, 75); string s2 = fo.StoreID.Substring(1, 75); if (s1 != s2) { // unload the folder olMAPI.RemoveStore(fo); } } olApp.Quit();

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  • Python-based password tracker (or dictionary)

    - by Arrieta
    Hello: Where we work we need to remember about 10 long passwords which need to change every so often. I would like to create a utility which can potentially save these passwords in an encrypted file so that we can keep track of them. I can think of some sort of dictionary passwd = {'host1':'pass1', 'host2':'pass2'}, etc, but I don't know what to do about encryption (absolutely zero experience in the topic). So, my question is really two questions: Is there a Linux-based utility which lets you do that? If you were to program it in Python, how would you go about it? A perk of approach two, would be for the software to update the ssh public keys after the password has been changed (you know the pain of updating ~15 tokens once you change your password). As it can be expected, I have zero control over the actual network configuration and the management of scp keys. I can only hope to provide a simple utility to me an my very few coworkers so that, if we need to, we can retrieve a password on demand. Cheers.

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  • Saving Email/Password to Keychain in iOS

    - by Jason
    I'm very new to iOS development so forgive me if this is a newbie question. I have a simple authentication mechanism for my app that takes a user's email address and password. I also have a switch that says 'Remember me'. If the user toggles that switch on, I'd like to preserve their email/password so those fields can be auto-populated in the future. I've gotten this to work with saving to a plist file but I know that's not the best idea since the password is unencrypted. I found some sample code for saving to the keychain, but to be honest, I'm a little lost. For the function below, I'm not sure how to call it and how to modify it to save the email address as well. I'm guessing to call it would be: saveString(@"passwordgoeshere"); Thank you for any help!!! + (void)saveString:(NSString *)inputString forKey:(NSString *)account { NSAssert(account != nil, @"Invalid account"); NSAssert(inputString != nil, @"Invalid string"); NSMutableDictionary *query = [NSMutableDictionary dictionary]; [query setObject:(id)kSecClassGenericPassword forKey:(id)kSecClass]; [query setObject:account forKey:(id)kSecAttrAccount]; [query setObject:(id)kSecAttrAccessibleWhenUnlocked forKey:(id)kSecAttrAccessible]; OSStatus error = SecItemCopyMatching((CFDictionaryRef)query, NULL); if (error == errSecSuccess) { // do update NSDictionary *attributesToUpdate = [NSDictionary dictionaryWithObject:[inputString dataUsingEncoding:NSUTF8StringEncoding] forKey:(id)kSecValueData]; error = SecItemUpdate((CFDictionaryRef)query, (CFDictionaryRef)attributesToUpdate); NSAssert1(error == errSecSuccess, @"SecItemUpdate failed: %d", error); } else if (error == errSecItemNotFound) { // do add [query setObject:[inputString dataUsingEncoding:NSUTF8StringEncoding] forKey:(id)kSecValueData]; error = SecItemAdd((CFDictionaryRef)query, NULL); NSAssert1(error == errSecSuccess, @"SecItemAdd failed: %d", error); } else { NSAssert1(NO, @"SecItemCopyMatching failed: %d", error); } }

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  • XML serialization of hash table(C#3.0)

    - by Newbie
    Hi I am trying to serialize a hash table but not happening private void Form1_Load(object sender, EventArgs e) { Hashtable ht = new Hashtable(); DateTime dt = DateTime.Now; for (int i = 0; i < 10; i++) ht.Add(dt.AddDays(i), i); SerializeToXmlAsFile(typeof(Hashtable), ht); } private void SerializeToXmlAsFile(Type targetType, Object targetObject) { try { string fileName = @"C:\testtttttt.xml"; //Serialize to XML XmlSerializer s = new XmlSerializer(targetType); TextWriter w = new StreamWriter(fileName); s.Serialize(w, targetObject); w.Flush(); w.Close(); } catch (Exception ex) { throw ex; } } After a google search , I found that objects that impelment IDictonary cannot be serialized. However, I got success with binary serialization. But I want to have xml one. Is there any way of doing so? I am using C#3.0 Thanks

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  • get random password with puppet function

    - by ninja-2
    I have a function that allow me to generate random password. My function is working well without a puppetmaster. When i tried with a master an error appear when I called the function : Error 400 on SERVER: bad value for range Here is my function module Puppet::Parser::Functions newfunction(:get_random_password, :type => :rvalue, :doc => <<-EOS Returns a random password. EOS ) do |args| raise(Puppet::ParseError, "get_random_password(): Wrong number of arguments " + "given (#{args.size} for 1)") if args.size != 1 specials = ((33..33).to_a + (35..38).to_a + (40..47).to_a + (58..64).to_a + (91..93).to_a + (95..96).to_a + (123..125).to_a).pack('U*').chars.to_a numbers = (0..9).to_a alphal = ('a'..'z').to_a alphau = ('A'..'Z').to_a length = args[0] CHARS = (alphal + specials + numbers + alphau) pwd = CHARS.sort_by { rand }.join[0...length] return pwd end end The function is called in both case with $pwd = get_random_password(10). When I specified the length directly in the function to 10 for example. the password is well generated in master mode. Have you any idea why i can't specify the lentgth value ? Thanks for any help.

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  • sudo in Debian squeeze inside linux-vserver always wants password

    - by mark
    Every since I upgraded all my linux-vserver Debian guests from Lenny to Squeeze I've the apparent problem that whenever I want to use sudo it asks me for my password. Every time. I've configured sudo to have a timeout of 30 minutes: Defaults timestamp_timeout=30 . This has been configured when it was still Lenny (note: as suggested by EightBitTony I've also tried without this setting - no change). I've a hard time figuring out what the problem here is, since I think my configuration is right. I thought about it being a problem with the file used to record the timestamp, maybe a permission issue, but was unlucky to find any hard evidence. I've compared the contents of /var/lib/sudo/ between a working and a non-working system but couldn't spot any difference. The version of sudo used in both environments is 1.7.4p4-2.squeeze.3. My non-working system(s): find /var/lib/sudo/ -ls 17319289 4 drwx------ 4 root root 4096 Jan 1 1985 /var/lib/sudo/ 17319286 4 drwx------ 2 root mark 4096 Jan 1 1985 /var/lib/sudo/mark 17319312 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/6 17319361 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/9 17319490 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/10 17319326 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/4 17319491 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/2 A working system: find /var/lib/sudo -ls 2598921 4 drwx------ 5 root root 4096 Jan 1 1985 /var/lib/sudo 1999522 4 drwx------ 2 root mark 4096 Jan 1 1985 /var/lib/sudo/mark 2000781 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/8 1998998 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/17 1999459 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/26 1998930 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/24 2000771 4 -rw------- 1 root mark 40 Jun 25 11:39 /var/lib/sudo/mark/4 2000773 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/5 1999223 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/0 1998908 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/14 2000769 4 -rw------- 1 root mark 40 Jul 9 13:30 /var/lib/sudo/mark/2 2000770 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/3 2000782 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/9 2000778 4 -rw------- 1 root mark 40 Jul 8 00:11 /var/lib/sudo/mark/7 1998892 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/19 1999264 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/23 2000789 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/12 1999093 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/25 1998880 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/18 1998853 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/20 2000790 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/15 1998878 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/16 1998874 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/13 2000774 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/6 2000786 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/11 1998893 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/22 2000783 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/10 1998949 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/1 Despite the obvious (some up2date timestamps on the working system) I don't see anything wrong here, so it could be as well be a wrong track. Here's my current /etc/sudoers: # /etc/sudoers # # This file MUST be edited with the 'visudo' command as root. # # See the man page for details on how to write a sudoers file. # Defaults env_reset # Host alias specification # User alias specification User_Alias FULLADMIN = user1, user2, user3 # Cmnd alias specification # User privilege specification root ALL=(ALL) ALL FULLADMIN ALL = (ALL) ALL # Allow members of group sudo to execute any command # (Note that later entries override this, so you might need to move # it further down) %sudo ALL=(ALL) ALL # #includedir /etc/sudoers.d #Defaults always_set_home,timestamp_timeout=30

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  • How can I login to lightdm with password for fingerprint-enabled user after 12.10 upgrade?

    - by jxn
    Sorry for the long question. I have a laptop with ubuntu quantal 12.10, a fingerprint scanner, and a few active user accounts. When the machine boots up to lightdm, I get a prompt toenter my password or scan my finger print. Every now and then, fingerprint scanning just doesn't seem to work. Before the 12.10 upgrade, I was always able to enter my password for this user when fingerprint failed. Now, no matter what, I have to scan my prints to login as this user. If I try to login as a different user (fingerprint is not enabled for any others), I can see the password is typed out -- asterisks show in the password input box as I type them -- and get in. Not so for the fingerprint user. Any clues on how to figure out what's gone wrong?

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  • Disable Password Complexity/Expiration etc. Policy on Windows Server 2008

    - by Sahil Malik
    Ad:: SharePoint 2007 Training in .NET 3.5 technologies (more information). One of the things I like to do, for development environments only is to get rid of that excessively bothersome password policies. I like to have my password as something like p@ssword1, so they are easy to remember etc. etc. Obviously never do this in production. However, Windows Server 2008 comes with a password policy that expires my passwords every 90 days, and requires me to pick complex passwords, can’t reuse passwords etc. etc. Well here is how you disable password policy on a Windows Server 2008 machine - Run Group Policy Management (gpmc.msc) Expand to your domain, look for Forest\Domains\yourdomain\default domain policy. Go to the settings tab, right click on the tab, and choose “Edit”. This will open the Group Policy Management Editor, in which - Go to Computer Configuration\Policies\Windows Settings\Security Settings\Account Policies\Password Policy, and change the policy to whatever that suits you. Close everything, and run command prompt as administrator, and issue a “gpupdate /force” command to force the group policy update on the machine. Restart, and you’re done! :) Comment on the article ....

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  • PhP Login/Register system [migrated]

    - by Marian
    I found this good tutorial on creating a login/register system using PhP and MySQL. The forum is around 5 years old (edited last year) but it can still be usefull. Beginner Simple Register-Login system There seems to be an issue with both login and register pages. <?php function register_form(){ $date = date('D, M, Y'); echo "<form action='?act=register' method='post'>" ."Username: <input type='text' name='username' size='30'><br>" ."Password: <input type='password' name='password' size='30'><br>" ."Confirm your password: <input type='password' name='password_conf' size='30'><br>" ."Email: <input type='text' name='email' size='30'><br>" ."<input type='hidden' name='date' value='$date'>" ."<input type='submit' value='Register'>" ."</form>"; } function register(){ $connect = mysql_connect("host", "username", "password"); if(!$connect){ die(mysql_error()); } $select_db = mysql_select_db("database", $connect); if(!$select_db){ die(mysql_error()); } $username = $_REQUEST['username']; $password = $_REQUEST['password']; $pass_conf = $_REQUEST['password_conf']; $email = $_REQUEST['email']; $date = $_REQUEST['date']; if(empty($username)){ die("Please enter your username!<br>"); } if(empty($password)){ die("Please enter your password!<br>"); } if(empty($pass_conf)){ die("Please confirm your password!<br>"); } if(empty($email)){ die("Please enter your email!"); } $user_check = mysql_query("SELECT username FROM users WHERE username='$username'"); $do_user_check = mysql_num_rows($user_check); $email_check = mysql_query("SELECT email FROM users WHERE email='$email'"); $do_email_check = mysql_num_rows($email_check); if($do_user_check > 0){ die("Username is already in use!<br>"); } if($do_email_check > 0){ die("Email is already in use!"); } if($password != $pass_conf){ die("Passwords don't match!"); } $insert = mysql_query("INSERT INTO users (username, password, email) VALUES ('$username', '$password', '$email')"); if(!$insert){ die("There's little problem: ".mysql_error()); } echo $username.", you are now registered. Thank you!<br><a href=login.php>Login</a> | <a href=index.php>Index</a>"; } switch($act){ default; register_form(); break; case "register"; register(); break; } ?> Once pressed the register button the page does nothing, fields are erased and no data is added inside the database or error given. I tought that the problem might be the switch($act){ part so I removed it and changed the page using a require require('connect.php'); where connect.php is <?php mysql_connect("localhost","host","password"); mysql_select_db("database"); ?> Removed the function register_form(){ and echo part turning it into an HTML code: <form action='register' method='post'> Username: <input type='text' name='username' size='30'><br> Password: <input type='password' name='password' size='30'><br> Confirm your password: <input type='password' name='password_conf' size='30'><br> Email: <input type='text' name='email' size='30'><br> <input type='hidden' name='date' value='$date'> <input type='submit' name="register" value='Register'> </form> And instead of having a function register(){ I replaced it with a if($register){ So when the Register button is pressed it runs the php code, but this edit doesn't seem to work either. So what can the problem be? If needed I can re-add this code on my Domain The login page has the same issue, nothing happens when the button is pressed beside emptying the fields.

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  • How do I make the PolicyKit authentication agent window not dissapear when I enter faulty password in Ubuntu 12.04?

    - by Petar
    As far as I remember in previous versions of Ubuntu, whenever authentication was required and when the PolicyKit authentication agent window was presented, it stayed there even after I would enter a faulty password. But now, whenever I make a mistake, the window is closed immediately. I find this behaviour irritating. For instance I use Synaptic rather frequently, and I prefer to start it using Synapse. I press Ctrl+Space to invoke Synapse, then I enter "syn" (s-shows SMplayer, sy- shows System Monitor) and than I press Enter so that Synaptic is invoked. Then I'm presented with the PolicyKit authentication agent window. As my password is rather complicated - using special characters and big letters, it's easy to make a mistake. If I do make a mistake while typing my password, I'm forced to redo all the previous steps. It's annoying as hell, knowing that this is not the way the PolicyKit authentication agent window behaved before. It used to warn me that the password was not correct and than wait for the correct input. I'm not sure if it allowed trying for the correct password indefinitely, or it was limited to 3 retries which is a much saner behaviour than the current one. I'm using Gnome 3, but the same thing happens in Unity too, although the window looks different.

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  • After locking the screen in Ubuntu 14.04, password is not accepted, How can it be fixed?

    - by Itai Ganot
    I'm running Ubuntu 14.04 fully updated on my laptop. Since the last update every time I lock the screen (when leaving my room for example) - when I get back and input my password, it is not accepted even though it's the correct password, the error I get is: Password incorrect, please try again I found that clicking the "Switch Account" fixes the issue but it is very annoying, if you know any way to fix it, it would be nice. Thanks in advance

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  • How do I include a password with SSH command? (want to make shell script)

    - by Evan
    I'm trying to SSH to a server on startup with a .sh script, but that will require me to enter the password for the account on the server that I'm SSHing to. I did some RTFMing, and I see in "-o" that it has "PasswordAuthentication" but I'm not sure how or if I could use that option. As this will be in a shell script, obviously I'd like to have the password in that file, or in any case not have to enter in the password manually every time the script runs.

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  • How to enter the Default Keyring password via the command line?

    - by Jerkofalltrades
    Is there a way to enter the default keyring password using the command line? For instance: You have a remote setup of Ubuntu 10.10 thats set to auto login. You don't want to remove the keyring password. All right the system boots up and logs in automatically, then asks for the keyring password now at this point you can create ssh connections but you can't remote desktop. What can you do to enter the keyring password at this point? Also, to better clarify, this is from a remote connection using the command line.

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  • is it possible to ssh into ubuntu server with keys and from another computer using password?

    - by Sandro Dzneladze
    I have ubuntu server at home, and I use SSH keys to log in via terminal from my laptop. Rarely, but mostly from work, I need to access this server, but I dont want to copy keys on my work laptop - Id rather just use plain password for that. So if I enable password log in from ssh config file, it will ask me password on my laptop too even though it contains keys, right? Is there a way to stop this behavior? Thanks.

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  • ADODB Connection String: Workgroup Information file is Missing?

    - by Mohgeroth
    I have a few data sources in access that I need to connect to programatically to do things with behind the scenes and keep visibility away from users. Said datasource has a password 'pass' as I'm going to call it here. Using this connection method I get an error attempting to use the open method Dim conn as ADODB.Connection Set ROBBERS.conn = New ADODB.Connection conn.open "Provider=Microsoft.Jet.OLEDB.4.0;" _ & "Data Source=\\pep-home\projects\billing\autobilling\DPBilling2.mdb;" _ & "Jet OLEDB:Database Password=pass;", "admin", "pass" "Cannot start your application. The workgroup information file is missing or opened exclusively by another user." Due to planning to move into 2007, we are not using nor have ever used a workgroup identification file through access. The database password on the data source was set through the Set Databa Password which had to be done on an exclusive open. Ive spent a good while changing around my connection options, where to put the passwords etc and either cannot find the right format, or (why I'm asking here) I think there may be some other unknown that I must setup to do this. Anyone out there got some useful information?

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  • Is it possible to convert a 40-character SHA1 hash to a 20-character SHA1 hash?

    - by ewitch
    My problem is a bit hairy, and I may be asking the wrong questions, so please bear with me... I have a legacy MySQL database which stores the user passwords & salts for a membership system. Both of these values have been hashed using the Ruby framework - roughly like this: hashedsalt = Digest::SHA1.hexdigest("--#{Time.now.to_s}--#{login}--") hashedpassword = Digest::SHA1.hexdigest("#{hashedsalt}:#{password}") So both values are stored as 40-character strings (varchar(40)) in MySQL. Now I need to import all of these users into the ASP.NET membership framework for a new web site, which uses a SQL Server database. It is my understanding that the the way I have ASP.NET membership configured, the user passwords and salts are also stored in the membership database (in table aspnet_Membership) as SHA1 hashes, which are then Base64 encoded (see here for details) and stored as nvarchar(128) data. But from the length of the Base64 encoded strings that are stored (28 characters) it seems that the SHA1 hashes that ASP.NET membership generates are only 20 characters long, rather than 40. From some other reading I have been doing I am thinking this has to do with the number of bits per character/character set/encoding or something related. So is there some way to convert the 40-character SHA1 hashes to 20-character hashes which I can then transfer to the new ASP.NET membership data table? I'm pretty familiar with ASP.NET membership by now but I feel like I'm just missing this one piece. However, it may also be known that SHA1 in Ruby and SHA1 in .NET are incompatible, so I'm fighting a losing battle... Thanks in advance for any insight.

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  • C# how to calculate hashcode from an object reference.

    - by Wayne
    Folks, here's a thorny problem for you! A part of the TickZoom system must collect instances of every type of object into a Dictionary< type. It is imperative that their equality and hash code be based on the instance of the object which means reference equality instead of value equality. The challenge is that some of the objects in the system have overridden Equals() and GetHashCode() for use as value equality and their internal values will change over time. That means that their Equals and GetHashCode are useless. How to solve this generically rather than intrusively? So far, We created a struct to wrap each object called ObjectHandle for hashing into the Dictionary. As you see below we implemented Equals() but the problem of how to calculate a hash code remains. public struct ObjectHandle : IEquatable<ObjectHandle>{ public object Object; public bool Equals(ObjectHandle other) { return object.ReferenceEquals(this.Object,other.Object); } } See? There is the method object.ReferenceEquals() which will compare reference equality without regard for any overridden Equals() implementation in the object. Now, how to calculate a matching GetHashCode() by only considering the reference without concern for any overridden GetHashCode() method? Ahh, I hope this give you an interesting puzzle. We're stuck over here. Sincerely, Wayne

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  • Improve Log Exceptions

    - by Jaider
    I am planning to use log4net in a new web project. In my experience, I see how big the log table can get, also I notice that errors or exceptions are repeated. For instance, I just query a log table that have more than 132.000 records, and I using distinct and found that only 2.500 records are unique (~2%), the others (~98%) are just duplicates. so, I came up with this idea to improve logging. Having a couple of new columns: counter and updated_dt, that are updated every time try to insert same record. If want to track the user that cause the exception, need to create a user_log or log_user table, to map N-N relationship. Create this model may made the system slow and inefficient trying to compare all these long text... Here the trick, we should also has a hash column of binary of 16 or 32, that hash the message and the exception, and configure an index on it. We can use HASHBYTES to help us. I am not an expert in DB, but I think that will made the faster way to locate a similar record. And because hashing doesn't guarantee uniqueness, will help to locale those similar record much faster and later compare by message or exception directly to make sure that are unique. This is a theoretical/practical solution, but will it work or bring more complexity? what aspects I am leaving out or what other considerations need to have? the trigger will do the job of insert or update, but is the trigger the best way to do it?

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  • Hashing Function for Map C++

    - by Josh
    I am trying to determine a hash function which takes an input (i, k) and determines a unique solution. The possible inputs for (i, k) range from 0 to 100. Consider each (i, k) as a position of a node in a trinomial tree. Ex: (0, 0) can diverge to (1, 1) (1, 0) (1, -1). (1, 1) can diverge to (2, 2) (2, 1) (2, 0). Sample given here: http://www.google.com/imgres?imgurl=http://sfb649.wiwi.hu-berlin.de/fedc_homepage/xplore/tutorials/stfhtmlimg1156.gif&imgrefurl=http://sfb649.wiwi.hu-berlin.de/fedc_homepage/xplore/tutorials/stfhtmlnode41.html&h=413&w=416&sz=4&tbnid=OegDZu-yeVitZM:&tbnh=90&tbnw=91&zoom=1&usg=__9uQWDNYNLV14YioWWbrqPgfa3DQ=&docid=2hhitNyRWjI_DM&hl=en&sa=X&ei=xAfFUIbyG8nzyAHv2YDICg&ved=0CDsQ9QEwAQ I am using a map map <double, double> hash_table I need a key value to be determined from pairs (i, k) to hash to to value for that (i, k) So far I was only able to come up with linear functions such as: double Hash_function(int i, int k) { //double val = pow(i, k) + i; //return (val % 4294967296); return (i*3.1415 + k*i*9.12341); } However, I cannot determine a unique key with a certain (i, k). What kind of functions can I use to help me do so?

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  • The different of SHA512 between openssl and php

    - by solomon_wzs
    Here is C code: #include <openssl/sha.h> #include <stdio.h> char *hash_sha512(char *data){ SHA512_CTX ctx; char *md=malloc(sizeof(char)*(SHA512_DIGEST_LENGTH+1)); SHA512_Init(&ctx); SHA512_Update(&ctx, data, strlen(data)); SHA512_Final(md, &ctx); md[SHA512_DIGEST_LENGTH]='\0'; return md; } int main(int argc, char *argv[]){ str=hash_sha512("GFLOuJnR19881218"); printf("%s\n", str); free(str); return 1; } The output: ?<?4????IIA[r?? ?#? 6p?8jD????J?b9?????^X? Here is PHP code: $hash=hash('sha512', 'GFLOuJnR19881218', TRUE); The output: ?<??4??j??II?-A[r???? ??#??D6p?8jD???????J?b9?????^X? The results of C code and PHP code are different, what is wrong with my code?

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