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  • Torrents: Can I protect my software by sending wrong bytes?

    - by Martijn Courteaux
    Hi, It's a topic that everyone interests. How can I protect my software against stealing, hacking, reverse engineering? I was thinking: Do my best to protect the program for reverse engineering. Then people will crack it and seed it with torrents. Then I download my own cracked software with a torrent with my own torrent-software. My own torrent-software has then to seed incorrect data (bytes). Of course it has to seed critical bytes. So people who want to steal my software download my wrong bytes. Just that bytes that are important to startup, saving and loading data, etc... So if the stealer download from me (and seed it later) can't do anything with it, because it is broken. Is this idea relevant? Maybe, good torrent-clients check hashes from more peers to check if the packages (containing my broken bytes) I want to seed are correct or not? Thanks

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  • How can I reverse ruby's include function.

    - by Glen
    I'll explain what i'm looking for in code as thats probably the most succinct: module Mixin def method puts "Foo" end end class Whatever include Mixin end w = Whatever.new w.method => "Foo" # some magic here w2 = Whatever.new w.method => NoMethodError I had tried just undefining the Mixin module using remove_const, but this doesn't seem to make any difference to Whatever. I had assumed that #include just added a reference to the module into the class's method resolution chain - but this behaviour doesn't agree with that. Can anyone tell me what include actually does behind the scenes, and how to reverse this?

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  • Splitting an HTTP request into multiple byte-range requests

    - by redpola
    I have arrived at the unusual situation of having two completely independent Internet connections to my home. This has the advantage of redundancy etc but the drawback that both connections max out at about 6Mb/s. So one individual outbound http request is directed by my "intelligent gateway" (TP-LINK ER6120) out over one or the other connection for its lifetime. This works fine over complex web pages and utilises both external connects fine. However, single-http-request downloads are limited to the maximum rate of one of the two connections. So I'm thinking, surely I can setup some kind of proxy server to direct all my http requests to. For each incoming http request, the proxy server will issue multiple byte-range requests for the desired data and manage the reassembly and delivery of that data to the client's request. I can see this has some overhead, and also some edge cases where there will be blocking problems waiting for data. I also imagine webmasters of single-servers would rather I didn't hit them with 8 byte-range requests instead of one request. How can I achieve this http request deconstruct/reconstruction? Or am I just barking mad?

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  • recursively reverse linked list.

    - by Amanda
    I am implementing a function to recursively reverse a linked-list, but getting seg-fault. typedef struct _node { int data; struct _node *next; } Node, *NodeP; NodeP recursiveReverseList(NodeP first){ if(first == NULL) return NULL; if(first->next == NULL) return head; NodeP rest = recursiveReverseList(head->next); rest->next = first; first->next = NULL; return first; } Can you please help. P.S. The iterative version is working fine though. Its not homework. Just practicing C.

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  • How do you permanently disable the 'This Connection is Untrusted' page on Firefox

    - by TheIronChef9
    I'm going insane. Can someone please help me to COMPLETELY DISABLE the 'This Connection is Untrusted' page on Firefox. Facts: I am running Firefox 23.0 on an Ubuntu machine (downloaded and installed ubuntu today) It is a work computer and I have to use my employer's proxy While visiting Webpages/webapps like Gmail or Google brings up the 'This Connection is Untrusted' page and I have to go through the whole tedious task of selecting 'I understand the Risks' and add Exceptions, etc. etc. The fact is, I don't care about the risks. I would rather this computer melt into the ground than have to see that page ever again. I want to dance naked in untrusted pages and not give a damn about the consequences. I just never want to see that page again. Ever. For some sites (eg. wikipedia), the css doesn't load and I end up seeing them in plain text. As a result these sites are completely useless. Wasted hours trying to solve this for stackoverflow.com. These issues happen on the Firefox on my Windows XP machine as well (also using the same proxy). I don't want to export/import certificates or create exceptions for every site that shows this bloody page. I just want this page gone. I don't want Firefox to tell me what's safe and what's not. Also, my system time and date are correct. I've also tried the lies on this page too with no good results. Edit: I've also tried the whole going into the Advance-Certificates-validation setup page and unchecked 'Use the Online Certificate Status Protocol (OCSP) to confirm the current validity of certificates' checkbox. Nothing happened even after restarting firefox or rebooting. I need help. Thanks.

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  • Empty $upstream_http_location variable if response was cached

    - by Ivaldi
    I would like to cache the response of an redirect. (Cache the request to some site which returns a redirect and cache the second request which returns the actual content.) So far my config looks like this: location = /proxy { error_page 301 302 307 = @redir; resolver 8.8.8.8; proxy_pass $arg_url; proxy_intercept_errors on; proxy_cache pcache; proxy_cache_key $arg_url; proxy_cache_valid 200 301 302 307 1d; proxy_cache_min_uses 1; proxy_ignore_client_abort on; proxy_ignore_headers Set-Cookie Expires Cache-Control; } location @redir { resolver 8.8.8.8; # we need to assign $upstream_http_location to another var in order to use it with proxy_pass set $target $upstream_http_location; proxy_pass $target; proxy_cache predirects; proxy_cache_key $upstream_http_location; proxy_cache_valid 200 301 302 307 1d; proxy_cache_min_uses 1; proxy_ignore_headers Set-Cookie Expires Cache-Control; } It works for the first request or without the 30x codes for proxy_cache_valid in the /proxy part, but $target and $upstream_http_location are empty, if the response was cached. Is there a nice solution to cache both requests? Thanks!

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  • mod_rewrite with AJAX applictions: possible?

    - by MrJackV
    I am trying to run Shell In a Box (link) through another server (the computer running shellinabox is not accessible from the internet) . Ideally I could use ProxyPass in the Apache config to have a reverse proxy. Problem is I can't access the conf file. So I tried using .htaccess and I discover that I cannot use ProxyPass in there. So I tried and used mod_rewrite to do the job. Currently I have the following on the .htaccess file RewriteEngine On RewriteRule ^$ http://10.1.13.236:4200/ [P] However while it displays the title correctly and if I open up the source code I can see there is something in the page, nothing is diplayed on the screen (it remains blank). My suspicion is that there are problems with AJAX and this kind of proxy. What I am trying to accomplish with the mod_rewrite as close as possible behaviour to ProxyPass (Mirorr a website in a subdirectory). Is this possible? Is there some other solution (I tried phproxy and khproxy but neither of them is able to display anything)? Thanks in advance

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  • Creating a New Reverse Java Array

    - by mandir08
    Given an array of ints length 3, return a new array with the elements in reverse order, so {1, 2, 3} becomes {3, 2, 1}. public int[] reverse3(int[] nums) { int[] values = new int[3]; for(int i=0; i<=nums.length-1; i++) { for(int j=nums.length-1; j>=0; j--) { values[i]=nums[j]; } } return values; } I cant get this to work properly, usually the last int in the array, becomes every single int in the new array

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  • info about intel Cos embedded i86 os

    - by Tim Williscroft
    I've got some old Intel printer (Etherexpress XL ) print servers and they seem to be running an Intel OS called Cos aka Intel Client Os i86 I've found out that much just looking in the update files from Intel. It was at least partly written in C. How do I make a custom software image Intel Cos's boot loader will understand ? I know a host PC xmodem's the image to the client device, and I was wondering if anyone had already either reverse-engineered this or had original info ? or is my only recousre to reverse engineer the update file format ?

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  • Core Data not-reverse relationship subquery

    - by user561485
    Hi, I have the following entities in CoreData: Village - villageID Bookmark - (relation) village There are multiple villages with each an unique villageID. I have a entity Bookmark which only has a relation to a Village entity; it isn't possible to make a reverse relation. Now I would like to get the village entities where there exists a Bookmark relation. I've red something about subqueries, but I can't get it right for this situation. It must be something like: Village.villageID IN (Bookmark.village.villageID) It isn't possible to get first all the Bookmarks and then loop to get all the Villages, because of the design of the framework. Can this be done in CoreData (I presume the answer is "Yes, of course!") and how?

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  • undo or reverse argsort(), python

    - by Vincent
    Given an array 'a' I would like to sort the array by columns "a.sort(axis=0)" do some stuff to the array and then undo the sort. By that I don't mean re sort but basically reversing how each element was moved. I assume argsort() is what I need but it is not clear to me how to sort an array with the results of argsort() or more importantly apply the reverse/inverse of argsort() Here is a little more detail I have an array a, shape(a) = rXc I need to sort each column aargsort = a.argsort(axis=0) # May use this later aSort = a.sort(axis=0) now average each row aSortRM = asort.mean(axis=1) now replace each col in a row with the row mean. is there a better way than this aWithMeans = ones_like(a) for ind in range(r) # r = number of rows aWithMeans[ind]* aSortRM[ind] Now I need to undo the sort I did in the first step. ????

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  • How to reverse a dictionary that it has repeated values (python)

    - by Galois
    Hi guys! So, I have a dictionary with almost 100,000 (key, values) pairs and the majority of the keys map to the same values. For example imagine something like that: dict = {'a': 1, 'c': 2, 'b': 1, 'e': 2, 'd': 3, 'h': 1, 'j': 3} What I want to do, is to reverse the dictionary so that each value in dict is going to be a key at the reverse_dict and is going to map to a list of all the dict.keys that used to map to that value at the dict. So based on the example above I would get: reversed_dict = {1: ['a', 'b', 'h'], 2:['e', 'c'] , 3:['d', 'j']} I came up with a solution that is very expensive and I would really want to hear any ideas more efficient than mine. my expensive solution: reversed_dict = {} for value in dict.values(): reversed_dict[value] = [] for key in dict.keys(): if dict[key] == value: if key not in reversed_dict[value]: reversed_dict[value].append(key) Output >> reversed_dict = {1: ['a', 'b', 'h'], 2: ['c', 'e'], 3: ['d', 'j']} I would really appreciate to hear any ideas better and more efficient than than mine. Thanks!

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  • Error while trying to reverse a char array

    - by mpminnich
    Hi, I'm trying to get better at C++ (I know a little). I'm working on character arrays. I found an exercise where the objective is to reverse a character array (after I convert it from an integer). I'm getting the following error (using VS2005): Run-Time Check Failure #2 - Stack around the variable 'revBuffer' was corrupted. When I step through the code, I notice the following: revBuffer = 0x0012fe40 "100899ÌÌÌÌÌÌÌÌÌÌ998001" The relevant code is below. char buffer[5]; char revBuffer[5]; int i; int j=5; long number = 998001; itoa(number, buffer, 10); for(i=0; i<strlen(buffer);i++) { revBuffer[j] = buffer[i]; j--; } Any help would be great. TIA!

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  • question on reverse array

    - by davit-datuashvili
    we know algorithm how reverse array of n integers for (int i=0;i<n/2;i++){ swap(a[i],a[n-1-i]): } is this method better according the speed of algorithm or not because swap using xor is more fast then in other method here is code public class swap { public static void main(String[]args){ int a[]=new int[]{2,4,5,7,8,11,13,12,14,24}; System.out.println(" array at the begining:"); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } for (int j=0;j<a.length/2;j++){ a[j]^=a[a.length-1-j]; a[a.length-1-j]^=a[j]; a[j]^=a[a.length-1-j]; } System.out.println("reversed array:"); for (int j=0;j<a.length;j++){ System.out.println(a[j]); } } } Result: array at the begining: 2 4 5 7 8 11 13 12 14 24 reversed array: 24 14 12 13 11 8 7 5 4 2

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  • Error while trying to reverse a char array in C++

    - by mpminnich
    Hi, I'm trying to get better at C++ (I know a little). I'm working on character arrays. I found an exercise where the objective is to reverse a character array (after I convert it from an integer). I'm getting the following error (using VS2005): Run-Time Check Failure #2 - Stack around the variable 'revBuffer' was corrupted. When I step through the code, I notice the following: revBuffer = 0x0012fe40 "100899ÌÌÌÌÌÌÌÌÌÌ998001" The relevant code is below. char buffer[5]; char revBuffer[5]; int i; int j=5; long number = 998001; itoa(number, buffer, 10); for(i=0; i<strlen(buffer);i++) { revBuffer[j] = buffer[i]; j--; } Any help would be great. TIA!

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  • Following the Thread in OSB

    - by Antony Reynolds
    Threading in OSB The Scenario I recently led an OSB POC where we needed to get high throughput from an OSB pipeline that had the following logic: 1. Receive Request 2. Send Request to External System 3. If Response has a particular value   3.1 Modify Request   3.2 Resend Request to External System 4. Send Response back to Requestor All looks very straightforward and no nasty wrinkles along the way.  The flow was implemented in OSB as follows (see diagram for more details): Proxy Service to Receive Request and Send Response Request Pipeline   Copies Original Request for use in step 3 Route Node   Sends Request to External System exposed as a Business Service Response Pipeline   Checks Response to Check If Request Needs to Be Resubmitted Modify Request Callout to External System (same Business Service as Route Node) The Proxy and the Business Service were each assigned their own Work Manager, effectively giving each of them their own thread pool. The Surprise Imagine our surprise when, on stressing the system we saw it lock up, with large numbers of blocked threads.  The reason for the lock up is due to some subtleties in the OSB thread model which is the topic of this post.   Basic Thread Model OSB goes to great lengths to avoid holding on to threads.  Lets start by looking at how how OSB deals with a simple request/response routing to a business service in a route node. Most Business Services are implemented by OSB in two parts.  The first part uses the request thread to send the request to the target.  In the diagram this is represented by the thread T1.  After sending the request to the target (the Business Service in our diagram) the request thread is released back to whatever pool it came from.  A multiplexor (muxer) is used to wait for the response.  When the response is received the muxer hands off the response to a new thread that is used to execute the response pipeline, this is represented in the diagram by T2. OSB allows you to assign different Work Managers and hence different thread pools to each Proxy Service and Business Service.  In out example we have the “Proxy Service Work Manager” assigned to the Proxy Service and the “Business Service Work Manager” assigned to the Business Service.  Note that the Business Service Work Manager is only used to assign the thread to process the response, it is never used to process the request. This architecture means that while waiting for a response from a business service there are no threads in use, which makes for better scalability in terms of thread usage. First Wrinkle Note that if the Proxy and the Business Service both use the same Work Manager then there is potential for starvation.  For example: Request Pipeline makes a blocking callout, say to perform a database read. Business Service response tries to allocate a thread from thread pool but all threads are blocked in the database read. New requests arrive and contend with responses arriving for the available threads. Similar problems can occur if the response pipeline blocks for some reason, maybe a database update for example. Solution The solution to this is to make sure that the Proxy and Business Service use different Work Managers so that they do not contend with each other for threads. Do Nothing Route Thread Model So what happens if there is no route node?  In this case OSB just echoes the Request message as a Response message, but what happens to the threads?  OSB still uses a separate thread for the response, but in this case the Work Manager used is the Default Work Manager. So this is really a special case of the Basic Thread Model discussed above, except that the response pipeline will always execute on the Default Work Manager.   Proxy Chaining Thread Model So what happens when the route node is actually calling a Proxy Service rather than a Business Service, does the second Proxy Service use its own Thread or does it re-use the thread of the original Request Pipeline? Well as you can see from the diagram when a route node calls another proxy service then the original Work Manager is used for both request pipelines.  Similarly the response pipeline uses the Work Manager associated with the ultimate Business Service invoked via a Route Node.  This actually fits in with the earlier description I gave about Business Services and by extension Route Nodes they “… uses the request thread to send the request to the target”. Call Out Threading Model So what happens when you make a Service Callout to a Business Service from within a pipeline.  The documentation says that “The pipeline processor will block the thread until the response arrives asynchronously” when using a Service Callout.  What this means is that the target Business Service is called using the pipeline thread but the response is also handled by the pipeline thread.  This implies that the pipeline thread blocks waiting for a response.  It is the handling of this response that behaves in an unexpected way. When a Business Service is called via a Service Callout, the calling thread is suspended after sending the request, but unlike the Route Node case the thread is not released, it waits for the response.  The muxer uses the Business Service Work Manager to allocate a thread to process the response, but in this case processing the response means getting the response and notifying the blocked pipeline thread that the response is available.  The original pipeline thread can then continue to process the response. Second Wrinkle This leads to an unfortunate wrinkle.  If the Business Service is using the same Work Manager as the Pipeline then it is possible for starvation or a deadlock to occur.  The scenario is as follows: Pipeline makes a Callout and the thread is suspended but still allocated Multiple Pipeline instances using the same Work Manager are in this state (common for a system under load) Response comes back but all Work Manager threads are allocated to blocked pipelines. Response cannot be processed and so pipeline threads never unblock – deadlock! Solution The solution to this is to make sure that any Business Services used by a Callout in a pipeline use a different Work Manager to the pipeline itself. The Solution to My Problem Looking back at my original workflow we see that the same Business Service is called twice, once in a Routing Node and once in a Response Pipeline Callout.  This was what was causing my problem because the response pipeline was using the Business Service Work Manager, but the Service Callout wanted to use the same Work Manager to handle the responses and so eventually my Response Pipeline hogged all the available threads so no responses could be processed. The solution was to create a second Business Service pointing to the same location as the original Business Service, the only difference was to assign a different Work Manager to this Business Service.  This ensured that when the Service Callout completed there were always threads available to process the response because the response processing from the Service Callout had its own dedicated Work Manager. Summary Request Pipeline Executes on Proxy Work Manager (WM) Thread so limited by setting of that WM.  If no WM specified then uses WLS default WM. Route Node Request sent using Proxy WM Thread Proxy WM Thread is released before getting response Muxer is used to handle response Muxer hands off response to Business Service (BS) WM Response Pipeline Executes on Routed Business Service WM Thread so limited by setting of that WM.  If no WM specified then uses WLS default WM. No Route Node (Echo functionality) Proxy WM thread released New thread from the default WM used for response pipeline Service Callout Request sent using proxy pipeline thread Proxy thread is suspended (not released) until the response comes back Notification of response handled by BS WM thread so limited by setting of that WM.  If no WM specified then uses WLS default WM. Note this is a very short lived use of the thread After notification by callout BS WM thread that thread is released and execution continues on the original pipeline thread. Route/Callout to Proxy Service Request Pipeline of callee executes on requestor thread Response Pipeline of caller executes on response thread of requested proxy Throttling Request message may be queued if limit reached. Requesting thread is released (route node) or suspended (callout) So what this means is that you may get deadlocks caused by thread starvation if you use the same thread pool for the business service in a route node and the business service in a callout from the response pipeline because the callout will need a notification thread from the same thread pool as the response pipeline.  This was the problem we were having. You get a similar problem if you use the same work manager for the proxy request pipeline and a business service callout from that request pipeline. It also means you may want to have different work managers for the proxy and business service in the route node. Basically you need to think carefully about how threading impacts your proxy services. References Thanks to Jay Kasi, Gerald Nunn and Deb Ayers for helping to explain this to me.  Any errors are my own and not theirs.  Also thanks to my colleagues Milind Pandit and Prasad Bopardikar who travelled this road with me. OSB Thread Model Great Blog Post on Thread Usage in OSB

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  • Python Django sites on Apache+mod_wsgi with nginx proxy: highly fluctuating performance

    - by Halfgaar
    I have an Ubuntu 10.04 box running several dozen Python Django sites using mod_wsgi (embedded mode; the faster mode, if properly configured). Performance highly fluctuates. Sometimes fast, sometimes several seconds delay. The smokeping graphs are al over the place. Recently, I also added an nginx proxy for the static content, in the hopes it would cure the highly fluctuating performance. But, even though it reduced the number of requests Apache has to process significantly, it didn't help with the main problem. When clicking around on websites while running htop, it can be seen that sometimes requests are almost instant, whereas sometimes it causes Apache to consume 100% CPU for a few seconds. I really don't understand where this fluctuation comes from. I have configured the mpm_worker for Apache like this: StartServers 1 MinSpareThreads 50 MaxSpareThreads 50 ThreadLimit 64 ThreadsPerChild 50 MaxClients 50 ServerLimit 1 MaxRequestsPerChild 0 MaxMemFree 2048 1 server with 50 threads, max 50 clients. Munin and apache2ctl -t both show a consistent presence of workers; they are not destroyed and created all the time. Yet, it behaves as such. This tells me that once a sub interpreter is created, it should remain in memory, yet it seems sites have to reload all the time. I also have a nginx+gunicorn box, which performs quite well. I would really like to know why Apache is so random. This is a virtual host config: <VirtualHost *:81> ServerAdmin [email protected] ServerName example.com DocumentRoot /srv/http/site/bla Alias /static/ /srv/http/site/static Alias /media/ /srv/http/site/media WSGIScriptAlias / /srv/http/site/passenger_wsgi.py <Directory /> AllowOverride None </Directory> <Directory /srv/http/site> Options -Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> Ubuntu 10.04 Apache 2.2.14 mod_wsgi 2.8 nginx 0.7.65 Edit: I've put some code in the settings.py file of a site that writes the date to a tmp file whenever it's loaded. I can now see that the site is not randomly reloaded all the time, so Apache must be keeping it in memory. So, that's good, except it doesn't bring me closer to an answer... Edit: I just found an error that might also be related to this: File "/usr/lib/python2.6/subprocess.py", line 633, in __init__ errread, errwrite) File "/usr/lib/python2.6/subprocess.py", line 1049, in _execute_child self.pid = os.fork() OSError: [Errno 12] Cannot allocate memory The server has 600 of 2000 MB free, which should be plenty. Is there a limit that is set on Apache or WSGI somewhere?

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  • what's wrong with my Ubuntu 11.10 bind9 configuration?

    - by John Bowlinger
    I've followed several tutorials on installing your own nameservers and I'm pretty much at my wit's end, because I cannot get them to resolve. Note, the actual domain and ip address has been changed for privacy to example.com and 192.168.0.1. My named.conf.local file: zone "example.com" { type master; file "/var/cache/bind/example.com.db"; }; zone "0.168.192.in_addr.arpa" { type master; file "/var/cache/bind/192.168.0.db"; }; My named.conf.options file: options { forwarders { 192.168.0.1; }; auth-nxdomain no; # conform to RFC1035 listen-on-v6 { any; }; }; My resolv.conf file: search example.com. nameserver 192.168.0.1 My Forward DNS file: ORIGIN example.com. $TTL 86400 @ IN SOA ns1.example.com. root.example.com. ( 2012083101 ; Serial 604800 ; Refresh 86400 ; Retry 2419200 ; Expire 3600 ) ; Negative Cache TTL example.com. NS ns1.example.com. example.com. NS ns2.example.com. example.com. MX 10 mail.example.com. @ IN A 192.168.0.1 ns1.example.com IN A 192.168.0.1 ns2.example.com IN A 192.168.0.2 mail IN A 192.168.0.1 server1 IN A 192.168.0.1 gateway IN CNAME ns1.example.com. headoffice IN CNAME server1.example.com. smtp IN CNAME mail.example.com. pop IN CNAME mail.example.com. imap IN CNAME mail.example.com. www IN CNAME server1.example.com. sql IN CNAME server1.example.com. And my reverse DNS: $ORIGIN 0.168.192.in-addr.arpa. $TTL 86400 @ IN SOA ns1.example.com. root.example.com. ( 2009013101 ; Serial 604800 ; Refresh 86400 ; Retry 2419200 ; Expire 3600 ) ; Negative Cache TTL 1 PTR mail.example.com. 1 PTR server1.example.com. 2 PTR ns1.example.com. Yet, when I restart bind9 and do: host ns1.example.com localhost I get: Using domain server: Name: localhost Address: 127.0.0.1#53 Aliases: Host ns1.example.com.example.com not found: 2(SERVFAIL) Similarly, for: host 192.168.0.1 localhost I get: ;; connection timed out; no servers could be reached Anybody know what's going on? Btw, my domain name "www.example.com" that I've used in this question is being forwarded to my ISP's nameservers. Would that affect my bind9 configuration? I want to learn how to do set up nameservers on my own for learning, so that is why I'm going through all this trouble.

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  • Apache mod_proxy vs mod_rewrite

    - by Scott
    What is the difference between using mod_proxy and mod_rewrite? I have a requirement to send certain url patterns through the tomcat, which runs on the same host but under port 8080. I know this is something for mod_proxy, but I"m wondering why I can't just use mod_rewrite, or what the difference is? Probably has to do w/ reverse proxy, and also when in the pipeline it gets handled? Thanks.

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  • VirtualServer reverseproxy works locally, but not from client

    - by Yep
    Setup: 2 Webservers pointed to 127.0.0.1:8080 and :8081. Curl validates they work as expected. Apache with the following virt hosts: NameVirtualHost 192.168.1.1:80 <VirtualHost 192.168.1.1:80> ServerAdmin [email protected] ProxyPass / http://127.0.0.1:8080/ ProxyPassReverse / http://127.0.0.1:8080/ ServerName 192.168.1.1 ServerAlias http://192.168.1.1 </VirtualHost> NameVirtualHost 192.168.1.2:80 <VirtualHost 192.168.1.2:80> ServerAdmin [email protected] ProxyPass / http://127.0.0.1:8081/ ProxyPassReverse / http://127.0.0.1:8081/ ServerName 192.168.1.2 ServerAlias http://192.168.1.2 </VirtualHost> On the server I can curl to the virtualhosts and receive appropriate responses. (curl 192.168.1.1 gives me the webservers response from localhost:8080, etc) remote hosts cannot however connect to 192.168.1.1 or .2 at all. What am I missing? Re: comments Yes, the default directory Directive is still in place. # Deny access to root file system <Directory /> Options None AllowOverride None Order Deny,Allow deny from all </Directory> No apache logs are generated when trying to reach 192.168.1.1 remotely. They do get generated when curl from local. If I point the webservers to *:8080 and *:8081 instead of binding to localhost, I can access them from a remote host via 192.168.1.1 and 192.168.1.2 if i specify the 8080 and 8081 ports (both ports work on both IP's, which is what I'm trying to avoid with apache reverse proxy bind to 80 on each interface) Edit2: curl verbose output: (similar for second webserver, and for 127.0.0.1:portnum) [user@host mingle_12_2_1]$ curl -v 192.168.1.1 * About to connect() to 192.168.1.1 port 80 * Trying 192.168.1.1... connected * Connected to 192.168.1.1 (192.168.1.1) port 80 > GET / HTTP/1.1 > User-Agent: curl/7.15.5 (x86_64-redhat-linux-gnu) libcurl/7.15.5 OpenSSL/0.9.8b zlib/1.2.3 libidn/0.6.5 > Host: 192.168.1.1 > Accept: */* > < HTTP/1.1 302 Found < Date: Tue, 16 Oct 2012 16:22:08 GMT < Server: Jetty(6.1.19) < Cache-Control: no-cache < Location: http://192.168.1.1/install < X-Runtime: 130 < Content-Type: text/html; charset=utf-8 < Content-Length: 94 < Connection: close Closing connection #0 <html><body>You are being <a href="http://192.168.1.1/install">redirected</a>.</body></html> log from the request local 192.168.1.1 - - [16/Oct/2012:12:22:08 -0400] "GET / HTTP/1.1" 302 94 no apache access log or error log generated when requests from remote clients.

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  • Reliable access to Internet but not local network (not DNS or proxy issues)

    - by Ian Goldby
    I'm looking for help with a Vista Home Premium laptop that has trouble accessing any resource on our home network, but accesses the Internet just fine. The set-up is this: The Vista laptop and a MacBook Pro connect wirelessly to the router-modem. A Synology DS212j NAS drive has a wired connection to the router-modem. Devices on the local network are always referred to by IP address, so this cannot be a DNS issue. The MacBook Pro connects reliably to the NA via AFP (network shared folders), SMB (network shared folders) and HTTP. The Vista laptop connects to and browses sites on the Internet without any problems. It can log into the NAS via SMB and list the shared folders (so there is nothing wrong with the log-in credentials), but when it tries to open any of the folders Explorer just hangs with the spinning cursor for several minutes and then says "\192.168.1.64\shared\Photos is not accessible. You might not have permission to use this network resource. Contact the administrator of this server to find out if you have access permissions. The specified network name is no longer available." It can ping the NAS successfully. If I try to open the NAS drive's web interface, the browser just hangs. This is the same with IE, Firefox and Chrome. (There is no proxy.) I can log into the NAS drive with FTP and navigate directories, but when I try to list the contents of a directory with more than a handful of entries, the ftp client hangs. I set up a website on the MacBook. The Vista laptop was able to load some of the pages, but loading any of the images was very hit and miss. Images embedded in HTML pages never worked no matter how many times I reloaded the page, but when I linked directly to the image it did load (though several attempts were sometimes needed). I tried all of this with the Windows Firewall turned off, and with AVG turned off. That made no difference. I'd really appreciate any suggestions anyone can make. The fact that the Vista laptop has trouble with HTTP and FTP as well as SMB connections suggests to me that this is a problem at the TCP level or below. But don't forget it accesses sites outside the LAN with no problems.

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  • How to setup Proxy Cache with Nginx and Passenger

    - by tiny
    I use Nginx and Passenger for my rails application. I want to use proxy cache to cache my pages. However, every request go direct to my rails application. I don't know what wrong with my configuration. Below is my configuration: user www-data; worker_processes 1; events { worker_connections 1024; } http { passenger_root /usr/lib/ruby/gems/1.8/gems/passenger-2.2.15; passenger_ruby /usr/bin/ruby1.8; passenger_max_pool_size 6; passenger_max_instances_per_app 1; passenger_pool_idle_time 0; rails_spawn_method conservative; include mime.types; default_type application/octet-stream; server_names_hash_bucket_size 512; sendfile on; #tcp_nopush on; keepalive_timeout 65; tcp_nodelay on; gzip on; gzip_http_version 1.0; gzip_vary on; gzip_comp_level 6; gzip_proxied any; gzip_types text/plain text/css text/javascript application/javascript application/json application/x-javascript text/xml application/xml application/xml+rss; proxy_cache_path /var/www/cache/webapp levels=1:2 keys_zone=webapp:8m max_size=1000m inactive=600m; include vhosts/*.conf; include /opt/nginx/conf/sites-enabled/*; root /var/www; } server { listen 127.0.0.1:3008; server_name localhost; root /var/www/yoolk_web_app/public; # <--- be sure to point to 'public'! passenger_enabled on; rails_env development; passenger_use_global_queue on; } server { listen 80; server_name webpage.dev; proxy_set_header X-Real-IP $remote_addr; proxy_set_header Host $host; error_page 503 http://$host/maintenance.html; location ~* (css|js|png|jpe?g|gif|ico)$ { root /var/www/web_app/public; expires max; } location / { proxy_pass http://127.0.0.1:3008/; proxy_cache webapp; proxy_cache_valid 200 10m; } #More Location }

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  • How do i route TCP connections via TOR? [on hold]

    - by acidzombie24
    I was reading about torchat which is essentially an anonymous chat program. It sounded cool so i wanted to experiment with making my own. First i wrote a test to grab a webpage using Http. Sicne .NET doesnt support SOCKS4A/SOCKS5 i used privoxy and my app worked. Then i switch to a TCP echo test and privoxy doesnt support TCP so i searched and installed 6+ proxy apps (freecap, socat, freeproxy, delegate are the ones i can remember from the top of my head, i also played with putty bc i know it supports tunnels and SOCK5) but i couldnt successfully get any of them to work let alone get it running with my http test that privoxy easily and painlessly did. What may i use to get TCP connections going through TOR? I spent more then 2 hours without success. I don't know if i am looking for a relay, tunnel, forwarder, proxy or a proxychain which all came up in my search. I use the config below for .NET. I need TCP working but i am first testing with http since i know i had it working using privoxy. What apps and configs do i use to get TCP going through tor? <?xml version="1.0" encoding="utf-8" ?> <configuration> <system.net> <defaultProxy enabled="true"> <proxy bypassonlocal="True" proxyaddress="http://127.0.0.1:8118"/> </defaultProxy> <settings> <httpWebRequest useUnsafeHeaderParsing="true"/> </settings> </system.net> </configuration> -edit- Thanks to Bernd i have a solution. Here is the code i ended up writing. It isn't amazing but its fair. static NetworkStream ConnectSocksProxy(string proxyDomain, short proxyPort, string host, short hostPort, TcpClient tc) { tc.Connect(proxyDomain, proxyPort); if (System.Text.RegularExpressions.Regex.IsMatch(host, @"[\:/\\]")) throw new Exception("Invalid Host name. Use FQDN such as www.google.com. Do not have http, a port or / in it"); NetworkStream ns = tc.GetStream(); var HostNameBuf = new ASCIIEncoding().GetBytes(host); var HostPortBuf = BitConverter.GetBytes(IPAddress.HostToNetworkOrder(hostPort)); if (true) //5 { var bufout = new byte[128]; var buflen = 0; ns.Write(new byte[] { 5, 1, 0 }, 0, 3); buflen = ns.Read(bufout, 0, bufout.Length); if (buflen != 2 || bufout[0] != 5 || bufout[1] != 0) throw new Exception(); var buf = new byte[] { 5, 1, 0, 3, (byte)HostNameBuf.Length }; var mem = new MemoryStream(); mem.Write(buf, 0, buf.Length); mem.Write(HostNameBuf, 0, HostNameBuf.Length); mem.Write(new byte[] { HostPortBuf[0], HostPortBuf[1] }, 0, 2); var memarr = mem.ToArray(); ns.Write(memarr, 0, memarr.Length); buflen = ns.Read(bufout, 0, bufout.Length); if (bufout[0] != 5 || bufout[1] != 0) throw new Exception(); } else //4a { var bufout = new byte[128]; var buflen = 0; var mem = new MemoryStream(); mem.WriteByte(4); mem.WriteByte(1); mem.Write(HostPortBuf, 0, 2); mem.Write(BitConverter.GetBytes(IPAddress.HostToNetworkOrder(1)), 0, 4); mem.WriteByte(0); mem.Write(HostNameBuf, 0, HostNameBuf.Length); mem.WriteByte(0); var memarr = mem.ToArray(); ns.Write(memarr, 0, memarr.Length); buflen = ns.Read(bufout, 0, bufout.Length); if (buflen != 8 || bufout[0] != 0 || bufout[1] != 90) throw new Exception(); } return ns; } Usage using (TcpClient client = new TcpClient()) using (var ns = ConnectSocksProxy("127.0.0.1", 9050, "website.com", 80, client)) {...}

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  • .net question - where are the DefaultCredentials stored/accessed from for a WinForms v3.5 app?

    - by Greg
    Hi, Where are the DefaultCredentials stored/accessed from for a WinForms v3.5 app? That is if I am using the settings for defaultProxy for my Winforms v3.5 application, and set a proxy server address here, exactly where does/can the username/password come from? Or in other words where does the framework source the "default credentials" for a winforms application running on the client PC? <defaultProxy enabled="true|false" useDefaultCredentials="true|false" <bypasslist> … </bypasslist> <proxy> … </proxy> <module> … </module> /> Background - apparently ClickOnce can use this for a client side application, however I'm trying to work out where click once would get this defaultCredential from, for a user who is running the clickonce install for my winforms application.

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  • JDBC connections: How to specify the port for data-transfer?

    - by LeO
    I wanto to run my JDBC-connection (either Oracle or MSSQL) through a proxy-server. Reason for this is to have additional controls of the traffic, especially for developing. I know, I could specify the proxy, which runs on my machine, and the port in the connection-string. But the specified connection-settings are only taken as some kind of handshake to agree on which port the data is finally transferred. And this is defenitly not the port which I have under proxy-control. So, does anybody have an idea, how to specify the port for the data-transfer? I would prefer if this could be done in the connection-string. The same issue applies for Oracle and MSSQL. Thx LeO

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