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  • What is the difference between du -h and ls -lh?

    - by PeanutsMonkey
    I am having a difficult time grasping what is the correct way to read the size of the files since each command gives you varying results. I also came across a post at http://forums.devshed.com/linux-help-33/du-and-ls-generating-inconsistent-file-sizes-42169.html which states the following; du gives you the size of the file as it resides on the file system. ( IE will will always give you a result that is divisible by 1024 ). ls will give you the actual size of the file. What you are looking at is the difference between the actual size of the file and the amount of space on disk it takes. ( also called file system efficiency ). What is the difference between as it resides on the file system and actual size of the fil

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  • Could not load file or assembly or one of its dependencies. The located assembly's manifest definiti

    - by kp
    Hello, I changed some names of nameapces, assemblies in one of exsisting project(C# and ASP.NET). But when I try to debug it; I get this error. Could not load file or assembly 'HR' or one of its dependencies. The located assembly's manifest definition does not match the assembly reference. (Exception from HRESULT: 0x80131040). I have replced DFI with HR in the code. Please help, Thank you

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  • Path Problem in ASP.net

    - by Hany
    Hi I am trying to do the following I am building asp.net website with c# language I want to read a text file from my project(the file is inside the project) I tried to get the file Path by this way : string path=Request.PhysicalApplicationPath+"filename.txt"; but I can't use The "Request" object from separated C# file ?? note: separated C3 file,I mean it's not related with aspx file can you help me with my way or do you have another way ?? thx

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  • OpenGL Shader Compile Error

    - by Tomas Cokis
    I'm having a bit of a problem with my code for compiling shaders, namely they both register as failed compiles and no log is received. This is the shader compiling code: /* Make the shader */ Uint size; GLchar* file; loadFileRaw(filePath, file, &size); const char * pFile = file; const GLint pSize = size; newCashe.shader = glCreateShader(shaderType); glShaderSource(newCashe.shader, 1, &pFile, &pSize); glCompileShader(newCashe.shader); GLint shaderCompiled; glGetShaderiv(newCashe.shader, GL_COMPILE_STATUS, &shaderCompiled); if(shaderCompiled == GL_FALSE) { ReportFiler->makeReport("ShaderCasher.cpp", "loadShader()", "Shader did not compile", "The shader " + filePath + " failed to compile, reporting the error - " + OpenGLServices::getShaderLog(newCashe.shader)); } And these are the support functions: bool loadFileRaw(string fileName, char* data, Uint* size) { if (fileName != "") { FILE *file = fopen(fileName.c_str(), "rt"); if (file != NULL) { fseek(file, 0, SEEK_END); *size = ftell(file); rewind(file); if (*size > 0) { data = (char*)malloc(sizeof(char) * (*size + 1)); *size = fread(data, sizeof(char), *size, file); data[*size] = '\0'; } fclose(file); } } return data; } string OpenGLServices::getShaderLog(GLuint obj) { int infologLength = 0; int charsWritten = 0; char *infoLog; glGetShaderiv(obj, GL_INFO_LOG_LENGTH,&infologLength); if (infologLength > 0) { infoLog = (char *)malloc(infologLength); glGetShaderInfoLog(obj, infologLength, &charsWritten, infoLog); string log = infoLog; free(infoLog); return log; } return "<Blank Log>"; } and the shaders I'm loading: void main(void) { gl_FragColor = vec4(1.0, 0.0, 0.0, 1.0); } void main(void) { gl_Position = ftransform(); } In short I get From: ShaderCasher.cpp, In: loadShader(), Subject: Shader did not compile Message: The shader Data/Shaders/Standard/standard.vs failed to compile, reporting the error - <Blank Log> for every shader I compile I've tried replacing the file reading with just a hard coded string but I get the same error so there must be something wrong with how I'm compiling them. I have run and compiled example programs with shaders, so I doubt my drivers are the issue, but in any case I'm on a Nvidia 8600m GT. Can anyone help?

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  • To read the hyperlink path of a text from Excel file via JAVA?

    - by Guru
    I have done upto reading text (String) from Excel file i could leverage the same into my JAVA. But now i have an other querry. Supposing if the text in excel is a hyperlink i need the link path of that text. Say: "hyperlink text" path manually mapped to say ("C:\Folder\iamge.jpg") I want this path in java. Can any one help me with this!

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  • im writing a spellchecking program, how do i replace ch in a string..eg..

    - by Ajay Hopkins
    what am i doing wrong/what can i do?? import sys import string def remove(file): punctuation = string.punctuation for ch in file: if len(ch) > 1: print('error - ch is larger than 1 --| {0} |--'.format(ch)) if ch in punctuation: ch = ' ' return ch else: return ch ref = (open("ref.txt","r")) test_file = (open("test.txt", "r")) dictionary = ref.read().split() file = test_file.read().lower() file = remove(file) print(file) p.s, this is in Python 3.1.2

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  • How to concatenate all commit messages from subversion into one text file with no metadata?

    - by user144182
    I would like to take all the commit messages in my subversion log and just concatenate them into one text file. Each commit message has this format: - r1 message - r1 message - r1 message What I would like is something like: - r1 message - r1 message - r2 message - r2 message - r3 message [...] - r1000 message Update I thought the above was clear, but what I don't want in the log is this type of info: r2130 | user| 2010-03-19 10:36:13 -0400 (Fri, 19 Mar 2010) | 1 line No meta data, I simply want the commit messages.

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  • Reverse SCP over SSH connection

    - by pavpanchekha
    I pretty often need some file from some server when I'm on my laptop. But if I don't know where that file is, I have to ssh into the server, look around, exit, and then scp server:file .. If I'm working with my desktop and my server, both of which have static IPs, I can just SCP the file in reverse (scp desktop:~ file), but I can't do that for my laptop. Is there any nice way to SCP a file backwards over an SSH connection? So that the computer I connect to with SSH sends a file backwards to the client?

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  • Regular Expression to replace a pattern at runtime(C#3.0)

    - by deepak.kumar.goyal
    I have a requirement. I have some files in a folder among which some file names looks like say **EUDataFiles20100503.txt, MigrateFiles20101006.txt.** Basically these are the files that I need to work upon. Now I have a config file where it is mentioned as the file pattern type as EUDataFilesYYYYMMDD, MigrateFilesYYYYMMDD. Basically the idea is that, the user can configure the file pattern and based on the pattern mentioned, I need to search for those files that are present in the folder. i.e. at runtime the YYYYMMDD will get replaced by the Year Month and Date Values. It does not matter what dates will be there(but not with time stamp ; only dates)). And the EUDataFiles or MigrateFiles names will be there.(they are fixed) i.e. If the folder has a file name as EUDataFile20100504.txt(i.e. Year 2010, Month 05, Day 04) , I should ignore this file as it is not EUDataFiles20100504.txt (kindly note that the name is plural - File(s) and not file for which the system will ignore the file). Similarly, if the Pattern given as EUDataFilesYYYYMMDD and if the file present is of type EUDataFilesYYYYDDMM then also the system should ignore. How can I solve this problem? Is it doable using regular expression(Replacing the pattern at runtime)? If so can anyone be good enough in helping me out? I am using C#3.0 and dotnet framework 3.5. Thanks

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  • How do I force the download of a file which link is inside a GridView?

    - by murderdoll
    I have a Gridview that shows a list of files previously uploaded to the server with a HyperLink control to be able to download it, I need to force a download every time the user clicks on one of the provided links, so that the file does not open directly on the browser (they are usually images). Currently I have a side-server function that forces a download, but I do not know how to assign this function to each one of the links when the user clicks on it.

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  • Zend - Deny access to CSS, JS, Image files

    - by Vincent
    All, I have the following Zend application structure: helloworld - application - configs - controllers - models - layouts - include - library - public - design -- css -- site.css -- js -- global.js -- images -- siteheader.gif -- sitefooter.gif - .htaccess - index.php My .htaccess file in public folder looks like this: Options -MultiViews RewriteEngine On RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] My document root points to the "public" folder. Currently, if the user visits a directory level URL, (Ex: http://localhost/design or localhost/css) , my .htaccess file above make sure to show him the "Access Forbidden" page. But if he visits the file level URL, (Ex: http://localhost/design/css/site.css), it shows him the CSS file or the js file or PHP file.. How can I make sure to lock file level access for the above file types, if accessed directly from the URL? Since my application is JS intensive, I want to protect it from users looking at it. Thanks

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