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  • Referencing Entity from external data model - Core Data

    - by Ben Reeves
    I have a external library which includes a core data model, I would like to add a new entity to this model which has a relationship with one of the entities from the library. I know I could modify the original, but is there a way to without needing to pollute the library? I tried just creating a new model with an entity named the same, but that doesn't work: * Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Can't merge models with two different entities named 'Host''

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  • Alternate datasource for django model?

    - by slypete
    I'm trying to seamlessly integrate some legacy data into a django application. I would like to know if it's possible to use an alternate datasource for a django model. For example, can I contact a server to populate a list of a model? The server would not be SQL based at all. Instead it uses some proprietary tcp based protocol. Copying the data is not an option, as the legacy application will continue to be used for some time. Would a custom manager allow me to do this? This model should behave just like any other django model. It should even pluggable to the admin interface. What do you think? Thanks, Pete

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  • How to convert String to Java.sql.date and Java.sql.time

    - by Mr Morgan
    Hello If I have a method like this: public static String convertDateTimeToString(DateTime dt) { return dt.getDate() + " " + dt.getTime(); } Which takes a Datetime object of my own which contains a Java.sql.date and a Java.sql.time, what is the best way of reversing the process so that I can substring a Java.sql.date and a Java.sql.time from a string? Or if DateTime dt is a JodaTime DateTime object? If this can be done without reference to Java.util.date. Thanks Mr Morgan.

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  • Yet another date formatting problem :(

    - by Jonesy
    Hi folks, I seem to have a date formatting problem every day! I am querying a table and am getting a date back in the format dd/mm/yyyy (as a string btw). Brilliant! thats what I want. But, now I want to convert that string to a date so i can do dim dayNumber as integer = day.DayOfWeek But when I convert it to a date it changes it to #m/dd/yyyy#. AHHHH! how can I change this? Cheers

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  • Model associations

    - by Kalyan M
    I have two models Library and Book. In my Library model, I have an array - book_ids. The primary key of Book model is ID. How do I create a has_many :books relation in my library model? This is a legacy database we are using with rails. Thanks.

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  • MySQL ORDER BY date and team

    - by Michael
    I would like to order by date and then team in a MySQL query. It should be something similar to this: SELECT * FROM games ORDER BY gamedate ASC, team_id AND it should output something like this: 2010-04-12 10:20 Game 1 Team 1 2010-04-12 11:00 Game 3 Team 1 2010-04-12 10:30 Game 2 Team 2 2010-04-14 10:00 Game 4 Team 1 So that Team 1 is under each other on the same date, but separate on a new date

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  • Php date() giving the wrong time after parsing

    - by Kirill
    This is confusing as hell, here's the php I'm using: <?php echo date('H:i D j, F',$j->date); ?> This is what it gives me: 01:33 Thu 1, January Which seems fine, until you look at the actual time that is being given ($j-date provides): 2010-06-12 21:12:23 Why is it giving me a January and what am I doing wrong?

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  • Dynamic model choice field in django formset using multiple select elements

    - by Aryeh Leib Taurog
    I posted this question on the django-users list, but haven't had a reply there yet. I have models that look something like this: class ProductGroup(models.Model): name = models.CharField(max_length=10, primary_key=True) def __unicode__(self): return self.name class ProductRun(models.Model): date = models.DateField(primary_key=True) def __unicode__(self): return self.date.isoformat() class CatalogItem(models.Model): cid = models.CharField(max_length=25, primary_key=True) group = models.ForeignKey(ProductGroup) run = models.ForeignKey(ProductRun) pnumber = models.IntegerField() def __unicode__(self): return self.cid class Meta: unique_together = ('group', 'run', 'pnumber') class Transaction(models.Model): timestamp = models.DateTimeField() user = models.ForeignKey(User) item = models.ForeignKey(CatalogItem) quantity = models.IntegerField() price = models.FloatField() Let's say there are about 10 ProductGroups and 10-20 relevant ProductRuns at any given time. Each group has 20-200 distinct product numbers (pnumber), so there are at least a few thousand CatalogItems. I am working on formsets for the Transaction model. Instead of a single select menu with the several thousand CatalogItems for the ForeignKey field, I want to substitute three drop-down menus, for group, run, and pnumber, which uniquely identify the CatalogItem. I'd also like to limit the choices in the second two drop-downs to those runs and pnumbers which are available for the currently selected product group (I can update them via AJAX if the user changes the product group, but it's important that the initial page load as described without relying on AJAX). What's the best way to do this? As a point of departure, here's what I've tried/considered so far: My first approach was to exclude the item foreign key field from the form, add the substitute dropdowns by overriding the add_fields method of the formset, and then extract the data and populate the fields manually on the model instances before saving them. It's straightforward and pretty simple, but it's not very reusable and I don't think it is the right way to do this. My second approach was to create a new field which inherits both MultiValueField and ModelChoiceField, and a corresponding MultiWidget subclass. This seems like the right approach. As Malcolm Tredinnick put it in a django-users discussion, "the 'smarts' of a field lie in the Field class." The problem I'm having is when/where to fetch the lists of choices from the db. The code I have now does it in the Field's __init__, but that means I have to know which ProductGroup I'm dealing with before I can even define the Form class, since I have to instantiate the Field when I define the form. So I have a factory function which I call at the last minute from my view--after I know what CatalogItems I have and which product group they're in--to create form/formset classes and instantiate them. It works, but I wonder if there's a better way. After all, the field should be able to determine the correct choices much later on, once it knows its current value. Another problem is that my implementation limits the entire formset to transactions relating to (CatalogItems from) a single ProductGroup. A third possibility I'm entertaining is to put it all in the Widget class. Once I have the related model instance, or the cid, or whatever the widget is given, I can get the ProductGroup and construct the drop-downs. This would solve the issues with my second approach, but doesn't seem like the right approach.

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  • Django - Better evaluation of relationship at the model level

    - by Brant
    Here's a simple relational pair of models. class Shelf(models.Model): name = models.CharField(max_length=100) def has_books(self): if Book.objects.filter(shelf=self): return True else: return False class Book(models.Model): shelf = models.ForeignKey(Shelf) name = models.CharField(max_length=100) Is there a better (or alternative) way to write the "has_book" method? I'm not a fan of the double database hit but I want to do this at the model level.

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  • Logging from symfony's model layer

    - by naag
    I'm currently working on a project with symfony 1.4 and Doctrine 1.2. I'm looking for a proper way to do logging from the model layer. In some model classes I use the record hook postSave() to create a ZIP file using exec() (since PHP zip doesn't provide for storage method 'Stored'). To be sure that everythings works fine I check the return code and log an error if something goes wrong. My first naive approach was to do it like this: if ($returnCode != 0) { sfContext::getInstance()->getLogger()->debug(...); } As you know, this doesn't work so well because sfContext belongs to the controller layer and shouldn't be used from the model layer. My next try was to use the model's constructor to pass in an sfLogger instance, but this doesn't work due to Doctrine 1.2 reserving the constructor for internal use (Doctrine 1.2 Documentation). I'm looking forward for your suggestions!

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  • Learning MVC - Maintaining model state

    - by GenericTypeTea
    First of all, I'm very new to MVC. Bought the books, but not got the T-Shirt yet. I've put together my first little application, but I'm looking at the way I'm maintaining my model and I don't think it looks right. My form contains the following: <% using (Html.BeginForm("Reconfigured", null, FormMethod.Post, new { id = "configurationForm" })) { %> <%= Html.DropDownList("selectedCompany", new SelectList(Model.Companies, Model.SelectedCompany), new { onchange = "$('#configurationForm').submit()" })%> <%= Html.DropDownList("selectedDepartment", new SelectList(Model.Departments, Model.SelectedDepartment), new { onchange = "$('#configurationForm').submit()" })%> <%=Html.TextArea("comment", Model.Comment) %> <%} %> My controller has the following: public ActionResult Index(string company, string department, string comment) { TestModel form = new TestModel(); form.Departments = _someRepository.GetList(); form.Companies = _someRepository.GetList(); form.Comment = comment; form.SelectedCompany = company; form.SelectedDepartment = department; return View(form); } [HttpPost] public ActionResult Reconfigured(string selectedCompany, string selectedDepartment, string comment) { return RedirectToAction("Index", new { company = selectedCompany, department = selectedDepartment, comment = comment}); } And finally, this is my route: routes.MapRoute( "Default", "{controller}/{company}/{department}", new { controller = "CompanyController", action = "Index", company="", department="" } ); Now, every time I change DropDownList value, all my values are maintained. I end up with a URL like the following after the Reconfigure action is called: http://localhost/Main/Index/Company/Sales?comment=Foo%20Bar Ideally I'd like the URL to remain as: http://localhost/Main/Index My routing object is probably wrong. This can't be the right way? It seems totally wrong to me as for each extra field I add, I have to add the property into the Index() method? I had a look at this answer where the form is passed through TempData. This is obviously an improvement, but it's not strongly typed? Is there a way to do something similar but have it strongly typed? This may be a simple-enough question, but the curse of 10 years of WinForms/WebForms makes this MVC malarky hard to get your head 'round.

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  • What is the best way to format a date in JSON for Mongo DB storage

    - by Poul
    I have a date with a time. I'm using ruby, but the language shouldn't matter. d = "2010-04-01 13:00:00" What is the best way to format this date for Mongo DB? By 'best' I mean, is there a certain format I could use where Mongo would recognize it as a date and might give me more-advanced filtering optons? ie: If formatted correctly, could I ask Mongo to return all records whose month is '04'? Thanks!

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  • Extracting text from a file where date -time is the index

    - by Soham
    I have got around 800 files of maximum 55KB-100KB each where the data is in this format Date/Time/Float1/Float2/Float3/Float4/Integer Date is in DD/MM/YYYY format and Time is in the format of HH:MM Here the date ranges from say 1st May to 1June and each day, the Time varies from 09:00 to 15:30. I want to run a program so that, for each file, it extracts the data pertaining to a particular given date and writes to a file. I will not face any problem in writing into directory operations. I am trying to get around, to form a to do a search and extract operation. I dont know, how to do it, would like to have some idea. Thanks Soham

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  • Rails 3.1 text_field form helper and jQuery datepicker date format

    - by DanyW
    I have a form field in my Rails view like this: <%= f.text_field :date, :class => "datepicker" %> A javascript function converts all input fields of that class to a jQueryUI datepicker. $(".datepicker").datepicker({ dateFormat : "dd MM yy", buttonImageOnly : true, buttonImage : "<%= asset_path('iconDatePicker.gif') %>", showOn : "both", changeMonth : true, changeYear : true, yearRange : "c-20:c+5" }) So far so good. I can edit the record and it persists the date correctly all the way to the DB. My problem is when I want to edit the record again. When the form is pre-populated from the record it displays in 'yyyy-mm-dd' format. The javascript only formats dates which are selected in the datepicker control. Is there any way I can format the date retrieved from the database? At which stage can I do this? Thanks, Dany. Some more details following the discussion below, my form is spread across two files, a view and a partial. Here's the view: <%= form_tag("/shows/update_individual", :method => "put") do %> <% for show in @shows %> <%= fields_for "shows[]", show do |f| %> <%= render "fields", :f => f %> <% end %> <% end %> <%= submit_tag "Submit"%> <% end %> And here's the _fields partial view: <p> <%= f.label :name %> <%= f.text_field :name %> </p> <p> <%= f.date %> <%= f.label :date %> <%= f.text_field :date, :class => "datepicker" %> </p> Controller code: def edit_individual @shows = Show.find(params[:show_ids]) end

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  • JSTL - Format date

    - by John Manak
    Hi! I have a loop that goes through all the news items we have on our site. One of the fields is date ${newsitem.value['Date']}, given in millliseconds. I'd like to display this date in month/day/year format on the webpage. I thought JSTL format tag, <fmt:formatDate>, would help, but I haven't succeeded. Do you know how to do it? <cms:contentaccess var="newsitem" /> <h2><c:out value="${newsitem.value['Title']}" /></h2> // display date here <c:out value="${newsitem.value['Text']}" escapeXml="false" />

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  • date() is showing December 1969

    - by Doug
    $sql = "SELECT * FROM news ORDER BY `news_id` DESC LIMIT 1"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_assoc($result); $date = $row['time_posted']; echo "<i> " .date("Y/m/d", $date) . "</i>: "; I used timestamp in mysql. So, what's the problem?

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  • Mysql : Count Posts and Group by date

    - by Oguz
    Hello , I am not very good at sql , generally I use php to do my complicated tasks , But in this task , there are lots of data , so using php for counting posts is very slow. So I want a sql which counts post by date , but my date column in table is php's time stamp.I will crate post number x date chart

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  • Problem using date when querying the appengine datastore

    - by manu1001
    I'm running this query: SELECT FROM com.Data WHERE entryDate DATE('2010-3-16') I get this error: org.datanucleus.store.appengine.query.DatastoreQuery$UnsupportedDatastoreFeatureException: Problem with query DATE('2010-3-16'): Unsupported method while parsing expression: InvokeExpression{[null].DATE(Literal{2010-3-16})} The same query works when I use it on the admin console. But it does not work for code (java), either locally or when deployed. Any ideas?

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  • displaying data between date ranges mysql

    - by Kyle Hudson
    Hi Guys, I need to work out a period of 6 months (backwards) from a given date. Example date: 07/06/2010 00:00:00 needs to count back 6 months and display: 07/12/2009 00:00:00 I have been scanning through: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html and non of these functions make sense to me :( Hope this makes sense and any help would be appriciated. Kyle

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  • [CakePHP] Can not Bake table model, controller and view

    - by user198003
    I developed small CakePHP application, and now I want to add one more table (in fact, model/controller/view) into system, named notes. I had already created a table of course. But when I run command cake bake model, I do not get table Notes on the list. I can add it manually, but after that I get some errors when running cake bake controller and cake bake view. Can you give me some clue why I have those problems, and how to add that new model?

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