Search Results

Search found 4567 results on 183 pages for 'gae models'.

Page 66/183 | < Previous Page | 62 63 64 65 66 67 68 69 70 71 72 73  | Next Page >

  • Search over multiple fields

    - by schneck
    Hi there, I think I don't unterstand django-haystack properly: I have a data model containing several fields, and I would to have two of them searched: class UserProfile(models.Model): user = models.ForeignKey(User, unique=True, default=None) twitter_account = models.CharField(max_length=50, blank=False) My search index settings: class UserProfileIndex(SearchIndex): text = CharField(document=True, model_attr='user') twitter_account = CharField(model_attr='twitter_account') def get_queryset(self): """Used when the entire index for model is updated.""" return UserProfile.objects.all() But when I perform a search, only the field "username" is searched; "twitter_account" is ignored. When I select the Searchresults via dbshell, the objects contain the correct values for "user" and "twitter_account", but the result page shows a "no results": {% if query %} <h3>Results</h3> {% for result in page.object_list %} <p> <a href="{{ result.object.get_absolute_url }}">{{ result.object.id }}</a> </p> {% empty %} <p>No results</p> {% endfor %} {% endif %} Any ideas?

    Read the article

  • What is the autoload class names structure, for the root "library" dir in a Zend Framework 1.10.2 pr

    - by Doron
    I have a project I created with Zend Framework 1.10.2. I usually use the application/models directory for new model files I create, and the auto loading is fine, so for example - My_Model_SampleClass is located application/models/SampleClass.php. However, I have just created a custom Exception class, and it does not fit in the models directory inside the application dir (at least the way I see it, I could be logically wrong), so I've created it in the root "library" dir, but I can't seem to find the correct class name + file name to use, so auto loading will be done correctly. BTW, I use a namespace for all custom classes I use, let's assume it's "My".

    Read the article

  • bidirectional habtm linking

    - by Alexey Poimtsev
    Hi, all. I have application with 2 groups of models - content based (news, questions) and "something" based (devices, applications etc). I need to link all models between groups - for example question may belongs to 3 different things - one application and 2 devices. The same - for news. From other side - i need to see all news articles and questions related to some application or device. Any idea how to develop this in rails? I have only one idea - mixins that will add methods content_id and thing_id to models and join table.

    Read the article

  • Automatically generate buddy classes from model in C#

    - by JohnnyO
    I use Linq to Sql (although this is equally applicable in Entity Framework) for my models, and I'm finding myself creating buddy classes for my models all the time. I find this time consuming and repetitive. Is there an easy way to automatically generate these buddy classes based on the models? Perhaps a visual studio macro? An example of a buddy class that I'd like to create: [MetadataType(typeof(PersonMetadata))] public partial class Person { } public class PersonMetadata { public object Id { get; set; } public object FirstName { get; set; } } Thanks in advance.

    Read the article

  • HowTo init Django model, before using it?

    - by mosg
    Hi. I'm new to python and django. Apps | Versions: Python 2.6.2 Django (working with PostgreSQL) Question: I wrote a simple model: class OperationType(models.Model): eid = models.IntegerField(unique=True) name = models.CharField(max_length=64) def __unicode__(self): tpl = 'eid="', str(self.eid), '" name="', self.name, '"' return ''.join(tpl) Now I need to initialize it, for example with this data: 0, "None" 1, "Add" 2, "Edit" 3, "Delete" But I need to initialize this data not with admin web panel, but after class model created in the same code. How to do this? Thanks for help!

    Read the article

  • ActiveRecord Save Dependent Model

    - by Dmitriy Likhten
    I am trying to save a model with it's dependency models being saved. Model1 has_many :model2, :autosave => true Model2 belongs_to :model1 has_many :model3, :autosave => true Model3 belongs_to :model2 I want to save Model1, and have Model2 and 3 save as well. I tried this without and with the autosave feature. What winds up happening is Model1 is saved, Model2 is saved, Model3 is untouched. Is there a way to tell ActiveRecord that for this save I want to save the model and all child models all at once? As a side note, all 3 are just created and are not in the database. I cannot do .create on the models because I cannot save them until all validation passes and all business logic succeeds (has to be a transaction).

    Read the article

  • The Utilization of Software Engineering Development Principles

    - by Chance
    Being a CS student I've had to take a course in basic software engineering. I was a little curious to find such elaborate "software development processes", like the spiral model, the waterfall model, et cetera. Some of these methodologies seem a little antiquated to me and, after speaking with several employed developers, I can't seem to find anyone who actually adheres to these models. Does anyone here have experience working under the guidance of these models? Were they useful to you and your team during the development of your product? Or are these models just some way to communicate a sense of progression to interested parties outside of the development team?

    Read the article

  • yiic shell: failed to perform 'crud'

    - by ufw
    Debian Squeeze, PHP 5.3.2-1, Yii 1.1.2, PHP $path to php is /usr/bin/php, permissions are '777'. When I try to run 'crud Test' in yii shell, I get the following error message: PHP Warning: include(/var/www/test/protected/models/Test.php): failed to open stream: No such file or directory in /var/www/yii/framework/YiiBase.php on line 335 PHP Warning: include(): Failed opening '/var/www/test/protected/models/Test.php' for inclusion (include_path='.:/var/www/test/protected/components:/var/www/test/protected/models:/usr/share/php:/usr/share/pear') in /var/www/yii/framework/YiiBase.php on line 335 PHP Fatal error: Class 'Test' not found in /var/www/yii/framework/db/ar/CActiveRecord.php on line 341

    Read the article

  • What project management methodology to use to develop new software internally?

    - by Setareh
    As part of my assignment I have to answer this question: The Sales Department has decided to develop new software internally. They will thus need to manage the IT project formally. Briefly describe two suitable project management methodologies models that could be used. I'm quite confused by the amount of methodologies. I Thought maybe PMBOK and SCRUM might be the best but still not sure if they are the ones for developing software internally. or whether they work for small projects, for instance. The thing about PRINCE2 is that is very comprehensive and seems to suit the large projects, however I read that it also suits to small projects as well. Any suggestions, which project management methodologies models to use for developing new software internally? What would be two suitable project management methodologies models?

    Read the article

  • Can't enumerate LinQ results with left join

    - by nvtthang
    var itemSet = from item in da.GetList<Models.account>() join file in objFileStorageList on item.account_id equals file.parent_id into objFile from fileItem in objFile.DefaultIfEmpty() where item.company != null && item.company.company_id == 123 orderby item.updatedDate descending select new { Id = item.account_id, RefNo = item.refNo, StartDate = item.StartDate , EndDate = item.EndDate , Comment = item.comment, FileStorageID = fileItem != null ? fileItem.fileStorage_id : -1, Identification = fileItem != null ? fileItem.identifier : null, fileName = fileItem != null ? fileItem.file_nm : null }; It raises error message when I try to enumerate through collection result from Linq query above. LINQ to Entities does not recognize the method 'System.Collections.Generic.IEnumerable1[SCEFramework.Models.fileStorage] DefaultIfEmpty[fileStorage](System.Collections.Generic.IEnumerable1[SCEFramework.Models.fileStorage])' method, and this method cannot be translated into a store expression foreach (var item in itemSet) { string itemRef= item.RefNo; } Please suggest me any solutions. Thanks in advance.

    Read the article

  • Data Model Evolution

    - by redleafong
    Hey guys, When writing code I am seeing requirements to change data models (e.g. adding/changing/removing data members from a class). When these data models belong to an interface, it seems difficult to change without breaking the existing client codes. So I am wondering if there is any best practice of designing interfaces/data models in a way to minimize the impact during evolution. The closest thing I can find from google is data contract versioning. But that seems to be a .net specific topic. I am wondering if the same practice applies to the Java world, or there is a different or generic way to deal with data model evolution. Thanks

    Read the article

  • Solutions for redundant server and client code?

    - by Fragsworth
    In our system, the code which exists on the client side (in Flash and Javascript) mirrors the code that exists on the server side (e.g. in Python or PHP), normally with respect to the models, the methods available for those models, and the unit tests written for them. This becomes a problem in systems where you want to minimize data transfer (e.g. multiplayer games). I do not want to write the same code and unit tests redundantly for both the client and server, but I don't know of any standard solutions to deal with this. Basically, I want a language/compiler which can produce models and methods for three main languages: Actionscript, Javascript, and any server language. Does something like this exist?

    Read the article

  • More strict query yields more results?

    - by Mark
    I've got a query that looks like this affiliates = User.objects.annotate(referral_count=Count('referrals')).filter(referral_count__gt=0) But when I restrict it more by adding referrals__user__date_joined__gt=start_date to the filter, I get even higher referral counts. I'm trying to count the number of people a user has referred within a time period. The relevant model looks like this: class Profile(models.Model): user = models.ForeignKey(User, unique=True, related_name='profile') referred_by = models.ForeignKey(User, null=True, blank=True, related_name='referrals') In contrast, when I try it like this: affiliates = User.objects \ .exclude(referrals__user__date_joined__lte=sd, referrals__user__date_joined__gt=ed) \ .annotate(referral_count=Count('referrals')) \ .filter(referral_count__gt=0) The exclude statement seems to do nothing... the counts don't change (should be 0 if no referred users have joined within that time period, but it isn't).

    Read the article

  • Does MVC replace traditional manually created UI, BLL, DAL ?

    - by used2could
    I'm use to creating the UI, BLL, DAL by hand (some times i've used LINQ-SQL or SubSonic for the DAL). I've done several small projects using MVC since it's release. On these projects i've still continued to write a BLL and DAL by hand and then incorporate those into the MVC's models/controllers. Looking to optimize my time on projects this seems like over kill and a potential waste of time. My question is: Would it be acceptable to roll a DAL such as SubSonic and directly use it in the Models/Controllers of my MVC web app? Now the models & controllers would act as the BLL. I just see this as a major time savor to not have to worry about another tier. (Agree ? "Please state way" : "Make argument")

    Read the article

  • QuestionOrAnswer model?

    - by Mark
    My site has Listings. Users can ask Questions about listings, and the author of the listing can respond with an Answer. However, the Answer might need clarification, so I've made them recursive (you can "answer" an answer). So how do I set up the database? The way I have it now looks like this (in Django-style models): class QuestionOrAnswer(Model): user = ForeignKey(User, related_name='questions') listing = ForeignKey(Listing, related_name='questions') parent = models.ForeignKey('self', null=True, blank=True, related_name='children') message = TextField() But what bugs me is that listing is now an attribute of the answers as well (it doesn't need to be). What happens if the database gets mangled and an answer belongs to a different listing than its parent question? That just doesn't make any sense. We can separate it with polymorphism: QuestionOrAnswer user message created updated Question(QuestionOrAnswer) shipment Answer(QuestionOrAnswer) parent = ForeignKey(QuestionOrAnswer) And that ought to work, but now ever question and answer is split into 2 tables. Is it worth this overhead for clearly defined models?

    Read the article

  • what is wrong with this insert method in asp.net mvc?

    - by Pandiya Chendur
    My controller calls a repository class method on insert, [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create([Bind(Exclude = "Id")]FormCollection collection) { try { MaterialsObj materialsObj = new MaterialsObj(); materialsObj.Mat_Name = collection["Mat_Name"]; materialsObj.Mes_Id = Convert.ToInt64(collection["MeasurementType"]); materialsObj.Mes_Name = collection["Mat_Type"]; materialsObj.CreatedDate = System.DateTime.Now; materialsObj.CreatedBy = Convert.ToInt64(1); materialsObj.IsDeleted = Convert.ToInt64(1); consRepository.createMaterials(materialsObj); return RedirectToAction("Index"); } catch { return View(); } } and my repository class has this, public MaterialsObj createMaterials(MaterialsObj materialsObj) { db.Materials.InsertOnSubmit(materialsObj); return materialsObj; } But when i compile this i get The best overloaded method match for 'System.Data.Linq.Table<CrMVC.Models.Material>.InsertOnSubmit(CrMVC.Models.Material)' has some invalid arguments... cannot convert from 'CrMVC.BusinessObjects.MaterialsObj' to 'CrMVC.Models.Material'.. am i missing something?

    Read the article

  • spring-nullpointerexception- cant access autowired annotated service (or dao) in a no-annotations class

    - by user286806
    I have this problem that I cannot fix. From my @Controller, i can easily access my autowired @Service class and play with it no problem. But when I do that from a separate class without annotations, it gives me a NullPointerException. My Controller (works)- @Controller public class UserController { @Autowired UserService userService;... My separate Java class (not working)- public final class UsersManagementUtil { @Autowired UserService userService; or @Autowired UserDao userDao; userService or userDao are always null! Was just trying if any one of them works. My component scan setting has the root level package set for scanning so that should be OK. my servlet context - <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd"> <!-- the application context definition for the springapp DispatcherServlet --> <!-- Enable annotation driven controllers, validation etc... --> <context:property-placeholder location="classpath:jdbc.properties" /> <context:component-scan base-package="x" /> <tx:annotation-driven transaction-manager="hibernateTransactionManager" /> <!-- package shortended --> <bean id="messageSource" class="o.s.c.s.ReloadableResourceBundleMessageSource"> <property name="basename" value="/WEB-INF/messages" /> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${database.driver}" /> <property name="url" value="${database.url}" /> <property name="username" value="${database.user}" /> <property name="password" value="${database.password}" /> </bean> <!-- package shortened --> <bean id="viewResolver" class="o.s.w.s.v.InternalResourceViewResolver"> <property name="prefix"> <value>/</value> </property> <property name="suffix"> <value>.jsp</value> </property> <property name="order"> <value>0</value> </property> </bean> <!-- package shortened --> <bean id="sessionFactory" class="o.s.o.h3.a.AnnotationSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="annotatedClasses"> <list> <value>orion.core.models.Question</value> <value>orion.core.models.User</value> <value>orion.core.models.Space</value> <value>orion.core.models.UserSkill</value> <value>orion.core.models.Question</value> <value>orion.core.models.Rating</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${hibernate.dialect}</prop> <prop key="hibernate.show_sql">${hibernate.show_sql}</prop> <prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop> </props> </property> </bean> <bean id="hibernateTransactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> Any clue?

    Read the article

  • How RPG characters are made

    - by user365314
    If RPG with the ability to change armors and clothes are made, how is it done? I mean the 3d side mostly If i make normal character, that has flat clothes, it would be easy, just change textures, but question is about armors, which have totally different models. So are only armor models recreated or character model with armor? How is it imported into game engine, only armor or character model with new armor? If person changes armor in game, will game swap the hole model or only the armor part? if only the armor part, then how the movement animations are done, are armor models animated on characters in 3d programs or what... :D

    Read the article

  • Polymorphic associations in CakePHP2

    - by Joseph
    I have 3 models, Page , Course and Content Page and Course contain meta data and Content contains HTML content. Page and Course both hasMany Content Content belongsTo Page and Course To avoid having page_id and course_id fields in Content (because I want this to scale to more than just 2 models) I am looking at using Polymorphic Associations. I started by using the Polymorphic Behavior in the Bakery but it is generating waaay too many SQL queries for my liking and it's also throwing an "Illegal Offset" error which I don't know how to fix (it was written in 2008 and nobody seems to have referred to it recently so perhaps the error is due to it not having been designed for Cake 2?) Anyway, I've found that I can almost do everything I need by hardcoding the associations in the models as such: Page Model CREATE TABLE `pages` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `slug` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `created` datetime NOT NULL, `updated` datetime NOT NULL, PRIMARY KEY (`id`) ) <?php class Page extends AppModel { var $name = 'Page'; var $hasMany = array( 'Content' => array( 'className' => 'Content', 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Page'), ) ); } ?> Course Model CREATE TABLE `courses` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `slug` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `created` datetime NOT NULL, `updated` datetime NOT NULL, PRIMARY KEY (`id`) ) <?php class Course extends AppModel { var $name = 'Course'; var $hasMany = array( 'Content' => array( 'className' => 'Content', 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Course'), ) ); } ?> Content model CREATE TABLE IF NOT EXISTS `contents` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `class` varchar(30) COLLATE utf8_unicode_ci NOT NULL, `foreign_id` int(11) unsigned NOT NULL, `title` varchar(100) COLLATE utf8_unicode_ci NOT NULL, `content` text COLLATE utf8_unicode_ci NOT NULL, `created` datetime DEFAULT NULL, `modified` datetime DEFAULT NULL, PRIMARY KEY (`id`) ) <?php class Content extends AppModel { var $name = 'Content'; var $belongsTo = array( 'Page' => array( 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Page') ), 'Course' => array( 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Course') ) ); } ?> The good thing is that $this->Content->find('first') only generates a single SQL query instead of 3 (as was the case with the Polymorphic Behavior) but the problem is that the dataset returned includes both of the belongsTo models, whereas it should only really return the one that exists. Here's how the returned data looks: array( 'Content' => array( 'id' => '1', 'class' => 'Course', 'foreign_id' => '1', 'title' => 'something about this course', 'content' => 'The content here', 'created' => null, 'modified' => null ), 'Page' => array( 'id' => null, 'title' => null, 'slug' => null, 'created' => null, 'updated' => null ), 'Course' => array( 'id' => '1', 'title' => 'Course name', 'slug' => 'name-of-the-course', 'created' => '2012-10-11 00:00:00', 'updated' => '2012-10-11 00:00:00' ) ) I only want it to return one of either Page or Course depending on which one is specified in Content.class UPDATE: Combining the Page and Course models would seem like the obvious solution to this problem but the schemas I have shown above are just shown for the purpose of this question. The actual schemas are actually very different in terms of their fields and the each have a different number of associations with other models too. UPDATE 2 Here is the query that results from running $this->Content->find('first'); : SELECT `Content`.`id`, `Content`.`class`, `Content`.`foreign_id`, `Content`.`title`, `Content`.`slug`, `Content`.`content`, `Content`.`created`, `Content`.`modified`, `Page`.`id`, `Page`.`title`, `Page`.`slug`, `Page`.`created`, `Page`.`updated`, `Course`.`id`, `Course`.`title`, `Course`.`slug`, `Course`.`created`, `Course`.`updated` FROM `cakedb`.`contents` AS `Content` LEFT JOIN `cakedb`.`pages` AS `Page` ON (`Content`.`foreign_id` = `Page`.`id` AND `Content`.`class` = 'Page') LEFT JOIN `cakedb`.`courses` AS `Course` ON (`Content`.`foreign_id` = `Course`.`id` AND `Content`.`class` = 'Course') WHERE 1 = 1 LIMIT 1

    Read the article

  • Django: Extending User Model - Inline User fields in UserProfile

    - by Jack Sparrow
    Is there a way to display User fields under a form that adds/edits a UserProfile model? I am extending default Django User model like this: class UserProfile(models.Model): user = models.OneToOneField(User, unique=True) about = models.TextField(blank=True) I know that it is possible to make a: class UserProfileInlineAdmin(admin.TabularInline): and then inline this in User ModelAdmin but I want to achieve the opposite effect, something like inverse inlining, displaying the fields of the model pointed by the OneToOne Relationship (User) in the page of the model defining the relationship (UserProfile). I don't care if it would be in the admin or in a custom view/template. I just need to know how to achieve this. I've been struggling with ModelForms and Formsets, I know the answer is somewhere there, but my little experience in Django doesn't allow me to come up with the solution yet. A little example would be really helpful!

    Read the article

  • Overriding the default error message for a ModelForm

    - by Jude Osborn
    Is there any way to override a error_message text for all the fields of a ModelForm's, without having to include all the field info in the ModelForm? For example, let's say I have a (very simple) model like this: People(models.Model): name = models.CharField(max_length=128, null=True, blank=True, help_text="Please type your name.") age = models.IntegerField(help_text="Please type your age.") I don't like the cut and dry default messages, such as, "Enter a whole number.", so I'd like to change them to something a bit nicer like "Please type a number." Ideally I'd be able to add an "error_message" property in the model, but the model does not support that property. So does that mean I have to basically duplicate all the model info in my ModelForm, or is there a way around that?

    Read the article

  • Reading file data during form's clean method

    - by Dominic Rodger
    So, I'm working on implementing the answer to my previous question. Here's my model: class Talk(models.Model): title = models.CharField(max_length=200) mp3 = models.FileField(upload_to = u'talks/', max_length=200) Here's my form: class TalkForm(forms.ModelForm): def clean(self): super(TalkForm, self).clean() cleaned_data = self.cleaned_data if u'mp3' in self.files: from mutagen.mp3 import MP3 if hasattr(self.files['mp3'], 'temporary_file_path'): audio = MP3(self.files['mp3'].temporary_file_path()) else: # What goes here? audio = None # setting to None for now ... return cleaned_data class Meta: model = Talk Mutagen needs file-like objects - the first case (where the uploaded file is larger than the size of file handled in memory) works fine, but I don't know how to handle InMemoryUploadedFile that I get otherwise. I've tried: # TypeError (coercing to Unicode: need string or buffer, InMemoryUploadedFile found) audio = MP3(self.files['mp3']) # TypeError (coercing to Unicode: need string or buffer, cStringIO.StringO found) audio = MP3(self.files['mp3'].file) # Hangs seemingly indefinitely audio = MP3(self.files['mp3'].file.read()) Is there something wrong with mutagen, or am I doing it wrong?

    Read the article

  • How can I update only certain fields in a Django model form?

    - by J. Frankenstein
    I have a model form that I use to update a model. class Turtle(models.Model): name = models.CharField(max_length=50, blank=False) description = models.TextField(blank=True) class TurtleForm(forms.ModelForm): class Meta: model = Turtle Sometimes I don't need to update the entire model, but only want to update one of the fields. So when I POST the form only has information for the description. When I do that the model never saves because it thinks that the name is being blanked out while my intent is that the name not change and just be used from the model. turtle_form = TurtleForm(request.POST, instance=object) if turtle_form.is_valid(): turtle_form.save() Is there any way to make this happen? Thanks!

    Read the article

  • Does MVC replace traditional manually created BLL?

    - by used2could
    I'm used to creating the UI, BLL, DAL by hand (some times I've used LINQ-to-SQL or SubSonic for the DAL). I've done several small projects using MVC since its release. On these projects I've still continued to write a BLL and DAL by hand and then incorporate those into the MVC's models/controllers. I'm looking to optimize my time on projects this seems like overkill and a potential waste of time. Question Would it be acceptable to roll a DAL such as SubSonic and directly use it in the Models/Controllers of my MVC web app? Now the models & controllers would act as the BLL. I just see this as a major timesaver to not have to worry about another tier. UPDATE: I just wanted to add that my concern isn't really with the DAL (I frequently use SubSonic and NH) but rather focus on the BLL. Sorry for the confusion.

    Read the article

  • How to create a nested form in backbone relational?

    - by jebek
    I would like to be able to create nested models at the same time in backbone. I know how to use backbone relational to create the parent model. Then once it is saved, I can create child models through backbone relational. However, I want to be able to create both the parent and child models at the same time, which might not be possible because I can only create the child model once the parent model has already been created. For example, let's say I was creating a forum like the one from the awesome backbone relational tutorial - http://antoviaque.org/docs/tutorials/backbone-relational-tutorial/. I would want to create a thread and a message at the same time(through the click of a single button) rather than create a thread then a message. Is this possible? Is there a better way of doing this that I'm not thinking of?

    Read the article

< Previous Page | 62 63 64 65 66 67 68 69 70 71 72 73  | Next Page >