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  • Help optimizing a query with 16 subqueries

    - by Webnet
    I have indexes/primaries on all appropriate ID fields for each type. I'm wondering though how I could make this more efficient. It takes a while to load the page with only 15,000 rows and that'll quickly grow to 500k. The $whereSql variable simply has a few more parameters for the main ebay_archive_listing table. NOTE: This is all done in a single query because I have ASC/DESC sorting for each subquery value. NOTE: I've converted some of the sub queries to INNER JOIN's SELECT product_master.product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price, ( SELECT MIN(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_bid_price, ( SELECT MAX(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_bid_price, ( SELECT MIN(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_buyout_price, ( SELECT MAX(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_buyout_price, round((( SELECT COUNT(ebay_archive_listing.id) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.status_id = 2 ) / ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id ) * 100), 1) as sold_percent FROM product_master '.$joinSql.' WHERE product_master.product_id IN ( SELECT product_id FROM ebay_archive_product_listing_assoc INNER JOIN ebay_archive_listing ON ( ebay_archive_listing.id = ebay_archive_product_listing_assoc.listing_id AND '.$whereSql.' ) )

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  • Calculating estimated data loss with Always on

    - by blakmk
    Ever wondered how calculate estimated data loss (time) for always on. The metric in the always on dashboard shows the metric quite nicely but there does seem to be a lack of documentation about where the metrics ---come from. Heres a script that calculates the data loss ( lag ) so you can set up alerts based on your DR SLA's:       WITH DR_CTE ( replica_server_name, database_name, last_commit_time) AS                 (                                 select ar.replica_server_name, database_name, rs.last_commit_time                                 from master.sys.dm_hadr_database_replica_states  rs                                 inner join master.sys.availability_replicas ar on rs.replica_id = ar.replica_id                                 inner join sys.dm_hadr_database_replica_cluster_states dcs on dcs.group_database_id = rs.group_database_id and rs.replica_id = dcs.replica_id                                 where replica_server_name != @@servername                 ) select ar.replica_server_name, dcs.database_name, rs.last_commit_time, DR_CTE.last_commit_time 'DR_commit_time', datediff(ss,  DR_CTE.last_commit_time, rs.last_commit_time) 'lag_in_seconds' from master.sys.dm_hadr_database_replica_states  rs inner join master.sys.availability_replicas ar on rs.replica_id = ar.replica_id inner join sys.dm_hadr_database_replica_cluster_states dcs on dcs.group_database_id = rs.group_database_id and rs.replica_id = dcs.replica_id inner join DR_CTE on DR_CTE.database_name = dcs.database_name where ar.replica_server_name = @@servername order by lag_in_seconds desc

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  • How to set the title as left alignment in the UIButton.

    - by Madan Mohan
    Hi Guys, I need to dispaly the email address from left side of a UIButton, But it is getting in the center. Is there any way to set the alignment to the left side of a UIButton. UIButton* emailBtn = [[UIButton alloc] initWithFrame:CGRectMake(5,30,250,height+15)]; emailBtn.backgroundColor=[UIColor clearColor]; [emailBtn setTitle:obj2.customerEmail forState:UIControlStateNormal]; emailBtn.titleLabel.font = [UIFont systemFontOfSize:12.5]; [emailBtn setTitleColor:[[[UIColor alloc]initWithRed:0.121 green:0.472 blue:0.823 alpha:1]autorelease] forState:UIControlStateNormal]; [emailBtn addTarget:self action:@selector(emailAction:) forControlEvents:UIControlEventTouchUpInside]; [elementView addSubview:emailBtn]; [emailBtn release]; Please help me. Thank You, Madan Mohan.

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  • Oracle bleibt auch 2011 Spitzenreiter im Bereich Datenbanken

    - by Anne Manke
    Mit der Veröffentlichung der aktuellen Ausgabe "Market Share: All Software Markets, Worldwide 2011" bestätigt das weltweit führende Marktanalyseunternehmen Gartner Oracle's Marktführerschaft im Bereich der Relationellen Datenbank Management Systeme (RDBMS). Oracle konnte innerhalb des letzten Jahres seinen Abstand zu seinen Marktbegleitern im Bereich der RDBMS mit einem stabilen Wachstum von 18% sogar ausbauen: der Marktanteil stieg im Jahr 2010 von 48,2% auf 48,8% im Jahr 2011. Damit ist der Abstand zu Oracle's stärkstem Verfolger IBM auf 28,6%.   Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin-top:0cm; mso-para-margin-right:0cm; mso-para-margin-bottom:12.0pt; mso-para-margin-left:0cm; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} table.MsoTableLightListAccent2 {mso-style-name:"Light List - Accent 2"; mso-tstyle-rowband-size:1; mso-tstyle-colband-size:1; mso-style-priority:61; mso-style-unhide:no; border:solid #C0504D 1.0pt; mso-border-themecolor:accent2; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} table.MsoTableLightListAccent2FirstRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:first-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-shading:#C0504D; mso-tstyle-shading-themecolor:accent2; mso-para-margin-top:0cm; mso-para-margin-bottom:0cm; mso-para-margin-bottom:.0001pt; line-height:normal; color:white; mso-themecolor:background1; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2LastRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:last-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:2.25pt double #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2; mso-para-margin-top:0cm; mso-para-margin-bottom:0cm; mso-para-margin-bottom:.0001pt; line-height:normal; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2FirstCol {mso-style-name:"Light List - Accent 2"; mso-table-condition:first-column; mso-style-priority:61; mso-style-unhide:no; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2LastCol {mso-style-name:"Light List - Accent 2"; mso-table-condition:last-column; mso-style-priority:61; mso-style-unhide:no; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2OddColumn {mso-style-name:"Light List - Accent 2"; mso-table-condition:odd-column; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:1.0pt solid #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2;} table.MsoTableLightListAccent2OddRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:odd-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:1.0pt solid #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2;} Revenue 2010 ($USM) Revenue 2011 ($USM) Growth 2010 Growth 2011 Share 2010 Share 2011 Oracle 9,990.5 11,787.0 10.9% 18.0% 48.2% 48.8% IBM 4,300.4 4,870.4 5.4% 13.3% 20.7% 20.2% Microsoft 3,641.2 4,098.9 10.1% 12.6% 17.6% 17.0% SAP/Sybase 744.4 1,101.1 12.8% 47.9% 3.6% 4.6% Teradata 754.7 882.3 16.9% 16.9% 3.6% 3.7% Source: Gartner’s “Market Share: All Software Markets, Worldwide 2011,” March 29, 2012, By Colleen Graham, Joanne Correia, David Coyle, Fabrizio Biscotti, Matthew Cheung, Ruggero Contu, Yanna Dharmasthira, Tom Eid, Chad Eschinger, Bianca Granetto, Hai Hong Swinehart, Sharon Mertz, Chris Pang, Asheesh Raina, Dan Sommer, Bhavish Sood, Marianne D'Aquila, Laurie Wurster and Jie Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin-top:0cm; mso-para-margin-right:0cm; mso-para-margin-bottom:12.0pt; mso-para-margin-left:0cm; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} table.MsoTableLightListAccent2 {mso-style-name:"Light List - Accent 2"; mso-tstyle-rowband-size:1; mso-tstyle-colband-size:1; mso-style-priority:61; mso-style-unhide:no; border:solid #C0504D 1.0pt; mso-border-themecolor:accent2; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} table.MsoTableLightListAccent2FirstRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:first-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-shading:#C0504D; mso-tstyle-shading-themecolor:accent2; mso-para-margin-top:0cm; mso-para-margin-bottom:0cm; mso-para-margin-bottom:.0001pt; line-height:normal; color:white; mso-themecolor:background1; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2LastRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:last-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:2.25pt double #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2; mso-para-margin-top:0cm; mso-para-margin-bottom:0cm; mso-para-margin-bottom:.0001pt; line-height:normal; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2FirstCol {mso-style-name:"Light List - Accent 2"; mso-table-condition:first-column; mso-style-priority:61; mso-style-unhide:no; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2LastCol {mso-style-name:"Light List - Accent 2"; mso-table-condition:last-column; mso-style-priority:61; mso-style-unhide:no; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2OddColumn {mso-style-name:"Light List - Accent 2"; mso-table-condition:odd-column; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:1.0pt solid #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2;} table.MsoTableLightListAccent2OddRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:odd-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:1.0pt solid #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2;} Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin-top:0cm; mso-para-margin-right:0cm; mso-para-margin-bottom:12.0pt; mso-para-margin-left:0cm; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} table.MsoTableLightListAccent2 {mso-style-name:"Light List - Accent 2"; mso-tstyle-rowband-size:1; mso-tstyle-colband-size:1; mso-style-priority:61; mso-style-unhide:no; border:solid #C0504D 1.0pt; mso-border-themecolor:accent2; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} table.MsoTableLightListAccent2FirstRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:first-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-shading:#C0504D; mso-tstyle-shading-themecolor:accent2; mso-para-margin-top:0cm; mso-para-margin-bottom:0cm; mso-para-margin-bottom:.0001pt; line-height:normal; color:white; mso-themecolor:background1; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2LastRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:last-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:2.25pt double #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2; mso-para-margin-top:0cm; mso-para-margin-bottom:0cm; mso-para-margin-bottom:.0001pt; line-height:normal; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2FirstCol {mso-style-name:"Light List - Accent 2"; mso-table-condition:first-column; mso-style-priority:61; mso-style-unhide:no; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2LastCol {mso-style-name:"Light List - Accent 2"; mso-table-condition:last-column; mso-style-priority:61; mso-style-unhide:no; mso-ansi-font-weight:bold; mso-bidi-font-weight:bold;} table.MsoTableLightListAccent2OddColumn {mso-style-name:"Light List - Accent 2"; mso-table-condition:odd-column; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:1.0pt solid #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2;} table.MsoTableLightListAccent2OddRow {mso-style-name:"Light List - Accent 2"; mso-table-condition:odd-row; mso-style-priority:61; mso-style-unhide:no; mso-tstyle-border-top:1.0pt solid #C0504D; mso-tstyle-border-top-themecolor:accent2; mso-tstyle-border-left:1.0pt solid #C0504D; mso-tstyle-border-left-themecolor:accent2; mso-tstyle-border-bottom:1.0pt solid #C0504D; mso-tstyle-border-bottom-themecolor:accent2; mso-tstyle-border-right:1.0pt solid #C0504D; mso-tstyle-border-right-themecolor:accent2;}

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  • problems with zend_pdf and right to left language and unicode?

    - by user1400
    hi all, i am using zend_pdf to create pdf files for Ritgh to left language as arabic or east asia langauges i use of this code $pdfDoc = new Zend_Pdf(); $pdfPage = $pdfDoc->newPage(Zend_Pdf_Page::SIZE_A4); $font = Zend_Pdf_Font::fontWithPath(APPLICATION_PATH.'/Fonts/arial.ttf'); $pdfPage->setFont($font, 36); $pdfDoc->pages[] = $pdfPage; $unicodeString = '????'; $pdfPage->drawText($unicodeString, 72, 720, 'UTF-8'); $pdfDoc->save('utf8.pdf'); but there are two problem 1- how can i change document's direction to right to left ? 2- characters are separated one by one. but in some laguages characters of a word are joint together. any idea? or i may use tcpdf? thanks

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  • How to Convert multiple sets of Data going from left to right to top to bottom the Pythonic way?

    - by ThinkCode
    Following is a sample of sets of contacts for each company going from left to right. ID Company ContactFirst1 ContactLast1 Title1 Email1 ContactFirst2 ContactLast2 Title2 Email2 1 ABC John Doe CEO [email protected] Steve Bern CIO [email protected] How do I get them to go top to bottom as shown? ID Company Contactfirst ContactLast Title Email 1 ABC John Doe CEO [email protected] 1 ABC Steve Bern CIO [email protected] I am hoping there is a Pythonic way of solving this task. Any pointers or samples are really appreciated! p.s : In the actual file, there are 10 sets of contacts going from left to right and there are few thousand such records. It is a CSV file and I loaded into MySQL to manipulate the data.

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  • jqGrid editForm problem

    - by PaulStanek
    Hi, I have simply jqgrid definitions like this: jQuery("#C2").jqGrid({ url: '/Customers.mvc/GetGridData/', datatype: 'json', autowidth: 'true', mtype: 'GET', colNames: ['Nazwa', 'Symbol', 'Status', 'Miasto', 'Ulica', 'Budynek', 'Mieszkanie', 'Koda pocztowy', 'Domena', ' '], colModel: [ { name: 'Name', index: 'Name', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Symbol', index: 'Symbol', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Status', index: 'Status', align: 'left', editable: 'true', edittype: 'text' }, { name: 'City', index: 'City', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Street', index: 'Street', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Building', index: 'Building', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Flat', index: 'Flat', align: 'left', editable: 'true', edittype: 'text'}, { name: 'PostalCode', index: 'PostalCode', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Domain', index: 'Domain', align: 'left', editable: 'true', edittype: 'text'}, { name: 'ExtId', index: 'ExtId', align: 'left', editable: 'true', edittype: 'text'}, ], pager: jQuery('#C2_p'), rowNum: 30, rowList: [20, 30, 50], sortname: 'Name', sortorder: 'Asc', viewrecords: 'true', width: '80%', height: '100%', editurl: '/Customers.mvc/SaveCustomer/', postData: { gridId: 'Customers' }, caption: 'Klienci2' }).navGrid('#C2_p', { edit: true, add: true, del: true, search: false, refresh: false }, {},//Options for the Edit Dialog {},//Options for the Add Dialog {}//Options for D ); }); And when i call edit/add form it's appears without text edit inputs. I'm using jquery 1.3.2 and jqgrid 3.6.4 Any help will be appreciated.

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  • Using LINQ to XML, how can I join two sets of data based on ordinal position?

    - by Donald Hughes
    Using LINQ to XML, how can I join two sets of data based on ordinal position? <document> <set1> <value>A</value> <value>B</value> <value>C</value> </set1> <set2> <value>1</value> <value>2</value> <value>3</value> </set2> </document> Based on the above fragment, I would like to join the two sets together such that "A" and "1" are in the same record, "B" and "2" are in the same record, and "C" and "3" are in the same record.

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  • How to get query result even if JOIN hasn't found any results?

    - by user1734651
    I want select data for user, and join another info from other table that related to the user. The problem is that this extra data not always exist for any user, just for few. How can I write a query that will return NULL for not found data, instead just return null for the whole query? SELECT a.*, b.* FROM user AS a LEFT JOIN extra AS b ON (a.userid = b.userid) WHERE a.userid = {$userid} LIMIT 1 When extra data found for the user, I get the resource as expected. If not, I get NULL for the whole query. Bottom line, I don't care if "extra" exist for the user or not, if yes - select it as well, if not - ignore that.

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  • Implement Tree/Details With Taskflow Regions Using EJB

    - by Deepak Siddappa
    This article describes on Display Tree/Details using taskflow regions.Use Case DescriptionLet us take scenario where we need to display Tree/Details, left region contains category hierarchy with items listed in a tree structure (ex:- Region-Countries-Locations-Departments in tree format) and right region contains the Employees list.In detail, Here User may drills down through categories using a tree until Employees are listed. Clicking the tree node name displays Employee list in the adjacent pane related to particular tree node. Implementation StepsThe script for creating the tables and inserting the data required for this application CreateSchema.sql Lets create a Java EE Web Application with Entities based on Regions, Countries, Locations, Departments and Employees table. Create a Stateless Session Bean and data control for the Stateless Session Bean. Add the below code to the session bean and expose the method in local/remote interface and generate a data control for that.Note:- Here in the below code "em" is a EntityManager. public List<Employees> empFilteredByTreeNode(String treeNodeType, String paramValue) { String queryString = null; try { if (treeNodeType == "null") { queryString = "select * from Employees emp ORDER BY emp.employee_id ASC"; } else if (Pattern.matches("[a-zA-Z]+[_]+[a-zA-Z]+[_]+[[0-9]+]+", treeNodeType)) { queryString = "select * from employees emp INNER JOIN departments dept\n" + "ON emp.department_id = dept.department_id JOIN locations loc\n" + "ON dept.location_id = loc.location_id JOIN countries cont\n" + "ON loc.country_id = cont.country_id JOIN regions reg\n" + "ON cont.region_id = reg.region_id and reg.region_name = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.contains("regionsFindAll_bc_countriesList_1")) { queryString = "select * from employees emp INNER JOIN departments dept \n" + "ON emp.department_id = dept.department_id JOIN locations loc \n" + "ON dept.location_id = loc.location_id JOIN countries cont \n" + "ON loc.country_id = cont.country_id and cont.country_name = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.contains("regionsFindAll_bc_locationsList_1")) { queryString = "select * from employees emp INNER JOIN departments dept ON emp.department_id = dept.department_id JOIN locations loc ON dept.location_id = loc.location_id and loc.city = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.trim().contains("regionsFindAll_bc_departmentsList_1")) { queryString = "select * from Employees emp INNER JOIN Departments dept ON emp.DEPARTMENT_ID = dept.DEPARTMENT_ID and dept.DEPARTMENT_NAME = '" + paramValue + "'"; } } catch (NullPointerException e) { System.out.println(e.getMessage()); } return em.createNativeQuery(queryString, Employees.class).getResultList(); } In the ViewController project, create two ADF taskflow with page Fragments and name them as FirstTaskflow and SecondTaskflow respectively. Open FirstTaskflow,from component palette drop view(Page Fragment) name it as TreeList.jsff. Open SeconfTaskflow, from component palette drop view(Page Fragment) name it as EmpList.jsff and create two paramters in its overview parameters tab as shown in below image. Open TreeList.jsff , from data control palette drop regionsFindAll->Tree as ADF Tree. In Edit Tree Binding dialog, for Tree Level Rules select the display attributes as follows:-model.Regions - regionNamemodel.Countries - countryNamemodel.Locations - citymodel.Departments - departmentName In structure panel, click on af:Tree - t1 and select selectionListener with edit property. Create a "TreeBean" managed bean with scope as "session" as shown in below Image. Create new method as getTreeNodeSelectedValue and click ok. Open TreeBean managed bean and add the below code: private String treeNodeType; private String paramValue; public void getTreeNodeSelectedValue(SelectionEvent selectionEvent) { RichTree tree = (RichTree)selectionEvent.getSource(); RowKeySet addedSet = selectionEvent.getAddedSet(); Iterator i = addedSet.iterator(); TreeModel model = (TreeModel)tree.getValue(); model.setRowKey(i.next()); JUCtrlHierNodeBinding node = (JUCtrlHierNodeBinding)tree.getRowData(); //oracle.jbo.Row Row rw = node.getRow(); Object selectedTreeNode = node.getAttribute(0); Object treeListType = node.getBindings(); String treeNodeType = treeListType.toString(); this.setParamValue(selectedTreeNode.toString()); this.setTreeNodeType(treeNodeType); } public void setTreeNodeType(String treeNodeType) { this.treeNodeType = treeNodeType; } public String getTreeNodeType() { return treeNodeType; } public void setParamValue(String paramValue) { this.paramValue = paramValue; } public String getParamValue() { return paramValue; }<br /> Open EmpList.jsff , from data control palette drop empFilteredByTreeNode->Employees->Table as ADF Read-only Table. After selecting the  Employees result set, in Edit Action Binding dialog window pass the pageFlowScope parameters as shown in below Image. In empList.jsff page, click Binding tab and click on Create Executable binding and select Invoke action and follow as shown in below image. Edit executeEmpFiltered invoke action properties and set the Refresh to ifNeeded, So when ever the page needs the method will be executed. Create Main.jspx page with page template as Oracle Three Column Layout. Drop FirstTaskflow as Region in start facet and drop SecondTaskflow as Region in center facet, Edit task Flow Binding dialog window pass the Input Paramters as shown in below Image. Run the Main.jspx, tree will be displayed in left region and emp details will displyaed on the right region. Click on the Americas in tree node, all emp related to the Americas related will be displayed. Click on Americas->United States of America->South San Francisco->Accounting, only employee belongs to the Accounting department will be displayed.

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  • How can i have a div stuck on the left side of the page no matter how much i scroll horizontally?

    - by Noor
    This is kind of difficult to explain so ill link to a page that has the effect i need; http://wpaoli.building58.com/wp-content/uploads/2009/08/feedback-panel.html The feedback thing on the left side is what im trying to implement on my side, instead of feedback im going to use it as a navigation menu that shows up when clicked on. the things above is what i have right now. my problem is when i scroll to the right ( my page is around 6000px wide ) i want it to stay on the left side, is there a way to pull this off? (this is to much for my brain to handle)..thanks!

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  • simple collision detection

    - by Rob
    Imagine 2 squares sitting side by side, both level with the ground: http://img19.imageshack.us/img19/8085/sqaures2.jpg A simple way to detect if one is hitting the other is to compare the location of each side. They are touching if ALL of the following are NOT true: The right square's left side is to the right of the left square's right side. The right square's right side is to the left of the left square's left side. The right square's bottom side is above the left square's top side. The right square's top side is below the left square's bottom side. If any of those are true, the squares are not touching. If all of those are false, the squares are touching. But consider a case like this, where one square is at a 45 degree angle: http://img189.imageshack.us/img189/4236/squaresb.jpg Is there an equally simple way to determine if those squares are touching?

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  • How to change the HTML text to Right-to-Left order when rendering the text within a WebBrowser.

    - by Java Doe
    hi, I am using a WebBrowser to render some HTML text. The WebBrowser is located within a rich client. I can detect the window's orientation when the rich client is launched. How do I make the text rendered within the WebBrowser to be dispayed in RTL order. I have tried body.setDir("rtl"), but it only aligned all the text in the WebBrowser to the right. It does not really reverse the content. For example, I have a photo that is displayed on the left and then a segment of text displayed on the right. After calling body.setDir("rtl"), it only aligned everything to the right in the WebBrowser, but it did not move the photo to the right, and it did not move the text to the left. Thanks a lot!

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  • Finding N contiguous zero bits in an integer to the left of the MSB position of another integer

    - by James Morris
    The problem is: given an integer val1 find the position of the highest bit set (Most Significant Bit) then, given a second integer val2 find a contiguous region of unset bits, with the minimum number of zero bits given by width to the left of the position (ie, in the higher bits). Here is the C code for my solution: typedef unsigned int t; unsigned const t_bits = sizeof(t) * CHAR_BIT; _Bool test_fit_within_left_of_msb( unsigned width, t val1, t val2, unsigned* offset_result) { unsigned offbit = 0; unsigned msb = 0; t mask; t b; while(val1 >>= 1) ++msb; while(offbit + width < t_bits - msb) { mask = (((t)1 << width) - 1) << (t_bits - width - offbit); b = val2 & mask; if (!b) { *offset_result = offbit; return true; } if (offbit++) /* this conditional bothers me! */ b <<= offbit - 1; while(b <<= 1) offbit++; } return false; } Aside from faster ways of finding the MSB of the first integer, the commented test for a zero offbit seems a bit extraneous, but necessary to skip the highest bit of type t if it is set. I have also implemented similar algorithms but working to the right of the MSB of the first number, so they don't require this seemingly extra condition. How can I get rid of this extra condition, or even, are there far more optimal solutions? Edit: Some background not strictly required. The offset result is a count of bits from the high bit, not from the low bit as maybe expected. This will be part of a wider algorithm which scans a 2D array for a 2D area of zero bits. Here, for testing, the algorithm has been simplified. val1 represents the first integer which does not have all bits set found in a row of the 2D array. From this the 2D version would scan down which is what val2 represents. Here's some output showing success and failure: t_bits:32 t_high: 10000000000000000000000000000000 ( 2147483648 ) --------- ----------------------------------- *** fit within left of msb test *** ----------------------------------- val1: 00000000000000000000000010000000 ( 128 ) val2: 01000001000100000000100100001001 ( 1091569929 ) msb: 7 offbit:0 + width: 8 = 8 mask: 11111111000000000000000000000000 ( 4278190080 ) b: 01000001000000000000000000000000 ( 1090519040 ) offbit:8 + width: 8 = 16 mask: 00000000111111110000000000000000 ( 16711680 ) b: 00000000000100000000000000000000 ( 1048576 ) offbit:12 + width: 8 = 20 mask: 00000000000011111111000000000000 ( 1044480 ) b: 00000000000000000000000000000000 ( 0 ) offbit:12 iters:10 ***** found room for width:8 at offset: 12 ***** ----------------------------------- *** fit within left of msb test *** ----------------------------------- val1: 00000000000000000000000001000000 ( 64 ) val2: 00010000000000001000010001000001 ( 268469313 ) msb: 6 offbit:0 + width: 13 = 13 mask: 11111111111110000000000000000000 ( 4294443008 ) b: 00010000000000000000000000000000 ( 268435456 ) offbit:4 + width: 13 = 17 mask: 00001111111111111000000000000000 ( 268402688 ) b: 00000000000000001000000000000000 ( 32768 ) ***** mask: 00001111111111111000000000000000 ( 268402688 ) offbit:17 iters:15 ***** no room found for width:13 ***** (iters is the count of iterations of the inner while loop)

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  • How to perform simple collision detection?

    - by Rob
    Imagine two squares sitting side by side, both level with the ground like so: A simple way to detect if one is hitting the other is to compare the location of each side. They are touching if all of the following are false: The right square's left side is to the right of the left square's right side. The right square's right side is to the left of the left square's left side. The right square's bottom side is above the left square's top side. The right square's top side is below the left square's bottom side. If any of those are true, the squares are not touching. But consider a case like this, where one square is at a 45 degree angle: Is there an equally simple way to determine if those squares are touching?

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  • SQL query: how to translate IN() into a JOIN?

    - by tangens
    I have a lot of SQL queries like this: SELECT o.Id, o.attrib1, o.attrib2 FROM table1 o WHERE o.Id IN ( SELECT DISTINCT Id FROM table1, table2, table3 WHERE ... ) These queries have to run on different database engines (MySql, Oracle, DB2, MS-Sql, Hypersonic), so I can only use common SQL syntax. Here I read, that with MySql the IN statement isn't optimized and it's really slow, so I want to switch this into a JOIN. I tried: SELECT o.Id, o.attrib1, o.attrib2 FROM table1 o, table2, table3 WHERE ... But this does not take into account the DISTINCT keyword. Question: How do I get rid of the duplicate rows using the JOIN approach?

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  • Does CakePHP treat all INT fields as ID's for join tables?

    - by Jonnie
    I am trying to save a User, their Profile, and some tags and my join table that links the profile and the tags keeps getting messed up. The profile model is called Instructor, the tag model is called Subject. The Instructor has a phone number and a zip code and for some reason CakePHP thinks these are the fields it should use when creating entries in my join table. My Join table always comes out as: id | instructor_id | subject_id | 1 | 90210 | 1 | // thinks that the zip code is an instructor_id 2 | 1112223333 | 1 | // thinks that the phone number is an instructor_id 3 | 1 | 1 | // thinks that user_id is an instructor_id 4 | 1 | 1 | // the actual instructor_id, this one's correct 5 | 90210 | 2 | 6 | 1112223333 | 2 | 3 | 1 | 2 | 4 | 1 | 2 | My Models: class Instructor extends AppModel { var $name = 'Instructor'; var $belongsTo = array('User', 'State'); var $hasAndBelongsToMany = array( 'Subject' = array( 'className' = 'Subject', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'instructor_id', 'associationForeignKey' = 'subject_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } class Subject extends AppModel { var $name = 'Subject'; var $hasAndBelongsToMany = array( 'Instructor' = array( 'className' = 'Instructor', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'subject_id', 'associationForeignKey' = 'instructor_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } My Model Associations: User hasOne Instructor Instructor belongsTo User Instructor hasAndBelongsToMany Subject Subject hasAndBelongsToMany Instructor My form data looks like: Array ( [User] = Array ( [username] = MrInstructor [password] = cddb06c93c72f34eb9408610529a34645c29c55d [group_id] = 2 ) [Instructor] = Array ( [name] = Jimmy Bob [email] = [email protected] [phone] = 1112223333 [city] = Beverly Hills [zip_code] = 90210 [states] = 5 [website] = www.jimmybobbaseballschool.com [description] = Jimmy Bob is an instructor. [user_id] = 1 [id] = 1 ) [Subject] = Array ( [name] = hitting, pitching ) ) My function for processing the form looks like: function instructor_register() { $this-set('groups', $this-User-Group-find('list')); $this-set('states', $this-User-Instructor-State-find('list')); if (!empty($this-data)) { // Set the group to Instructor $this-data['User']['group_id'] = 2; // Save the user data $user = $this-User-save($this-data, true, array( 'username', 'password', 'group_id' )); // If the user was saved, save the instructor's info if (!empty($user)) { $this-data['Instructor']['user_id'] = $this-User-id; $instructor = $this-User-Instructor-save($this-data, true, array( 'user_id', 'name', 'email', 'phone', 'city', 'zip_code', 'state_id', 'website', 'description' )); // If the instructor was saved, save the rest if(!empty($instructor)) { $instructorId = $this-User-Instructor-id; $this-data['Instructor']['id'] = $instructorId; // Save each subject seperately $subjects = explode(",", $this-data['Subject']['name']); foreach ($subjects as $_subject) { // Get the correct subject format $_subject = strtolower(trim($_subject)); $this-User-Instructor-Subject-create($this-data); $this-User-Instructor-Subject-set(array( 'name' = $_subject )); $this-User-Instructor-Subject-save(); echo ''; print_r($this-data); echo ''; } } } } }

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  • [Seamless Handover of WiFi] Can we program to automatically join the WiFi with the most strongest si

    - by Dobby
    Hi all, I am making a iphone program, I wish that: it can sense and display the current signals of wifi, with strength, - as I checked, this cannot be done by official SDK, but there were some private library that can handle. 2. i wish it can always automatically join the best wifi with the most highest strength ( assume that all wifi APs have no password, and all are not remembered into the used-list inside iphone), which is something like "seamless handover"... I just guess that, there should be some APIs to let the system join one designated wifi signal from the list, and wish someone could help me. I would like to appreciate a lot : ) Thanks a lot!

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  • How to make margin be relative to the center of the UIElement and not its top-left corner in a Grid?

    - by Nockawa
    I'd like the Margin property to reference the center of the UIElement and not the top-left corner. That way when I change the width/height of the UIElement it stays in the same spot. Is there a way to configure this behavior or I'll have to rely on Binding to make the adjustment ? Thanks. For instance if I change the Width/Height of the following rectangle, its center will move. <Grid> <Rectangle Fill="#FF991C1C" Width="10" Height="40" HorizontalAlignment="Left" Margin="90,161,0,0" VerticalAlignment="Top"/> </Grid>

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  • how do I align contents of a centered div to the left?

    - by Paul
    I have centered a div inside another div but want to left justify the contents of the centered inner div. How can I do this? My current HTML looks like this: <div style="border: solid 1px #ff0000;text-align:center;"> <div style="border:solid 1px #00ff00;"> <img src="/some_url_1/" style="width: 80px; height 80px; border: 0"/> <img src="/some_url_2/" style="width: 80px; height 80px; border: 0"/> </div> </div> Currently the images are centered inside the inner div but I would like them aligned to the left inside of the centered inner div. Any idea what I'm missing?

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  • Does INNER JOIN performance depends on order of tables?

    - by Kartic
    A question suddenly came to my mind while I was tuning one stored procedure. Let me ask it - I have two tables, table1 and table2. table1 contains huge data and table2 contains less data. Is there performance-wise any difference between these two queries(I am changing order of the tables)? Query1: SELECT t1.col1, t2.col2 FROM table1 t1 INNER JOIN table2 t2 ON t1.col1=t2.col2 Query2: SELECT t1.col1, t2.col2 FROM table2 t2 INNER JOIN table1 t1 ON t1.col1=t2.col2 We are using Microsoft SQL server 2005.

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