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  • JVM throws OutOfMemory during gc though there are plenty memory left...

    - by Shu L.
    I have my java application configured to use 5G memory. I got an OutOfMemory out of blue. I inspected the gc log and found plenty of memory left: young generation occupies 4% allocated space, tenure generation occupancy is 5% and perm generation is 43%. I am puzzled why JVM throws an OutOfMemory at the gc time. Does anyone know why this is happening? Your help is greatly appreciated. JVM memory and gc settings: -server -Xms5g -Xmx5g -Xss256k -XX:NewSize=2g -XX:MaxNewSize=2g -XX:+UseParallelOldGC -XX:+UseTLAB -XX:SurvivorRatio=8 -XX:TargetSurvivorRatio=90 -XX:+DisableExplicitGC gc.log 2009-09-19T03:34:59.741+0000: 92836.778: [GC Desired survivor size 152567808 bytes, new threshold 1 (max 15) [PSYoungGen: 1941492K-144057K(1947072K)] 3138022K-1340830K(5092800K), 0.1947640 secs] [Times: user=0.61 sys=0.01, real=0.19 secs] 2009-09-19T03:35:29.918+0000: 92866.954: [GC Desired survivor size 152109056 bytes, new threshold 1 (max 15) [PSYoungGen: 1941625K-144049K(1948608K)] 3138398K-1341080K(5094336K), 0.1942000 secs] [Times: user=0.61 sys=0.01, real=0.20 secs] 2009-09-19T03:35:56.883+0000: 92893.920: [GC Desired survivor size 156565504 bytes, new threshold 1 (max 15) [PSYoungGen: 1567994K-115427K(1915072K)] 2765026K-1312820K(5060800K), 0.1586320 secs] [Times: user=0.50 sys=0.01, real=0.16 secs] 2009-09-19T03:35:57.042+0000: 92894.079: [GC Desired survivor size 179961856 bytes, new threshold 1 (max 15) [PSYoungGen: 115427K-0K(1898560K)] 1312820K-1313987K(5044288K), 0.0775650 secs] [Times: user=0.42 sys=0.19, real=0.08 secs] 2009-09-19T03:35:57.120+0000: 92894.157: [Full GC [PSYoungGen: 0K-0K(1898560K)] [ParOldGen: 1313987K-159522K(3145728K)] 1313987K-159522K(5044288K) [PSPermGen: 20025K-19942K(40256K)], 0.56923 00 secs] [Times: user=2.18 sys=0.05, real=0.57 secs] 2009-09-19T03:35:57.690+0000: 92894.726: [GC Desired survivor size 197066752 bytes, new threshold 1 (max 15) [PSYoungGen: 0K-0K(1745728K)] 159522K-159522K(4891456K), 0.0072590 secs] [Times: user=0.01 sys=0.00, real=0.00 secs] 2009-09-19T03:35:57.698+0000: 92894.734: [Full GC [PSYoungGen: 0K-0K(1745728K)] [ParOldGen: 159522K-158627K(3145728K)] 159522K-158627K(4891456K) [PSPermGen: 19942K-19934K(45504K)], 0.3280480 secs] [Times: user=1.46 sys=0.00, real=0.33 secs] Heap PSYoungGen total 1745728K, used 87233K [0x00002aab73650000, 0x00002aabf3650000, 0x00002aabf3650000) eden space 1745664K, 4% used [0x00002aab73650000,0x00002aab78b80778,0x00002aabddf10000) from space 64K, 0% used [0x00002aabddf10000,0x00002aabddf10000,0x00002aabddf20000) to space 192448K, 0% used [0x00002aabe7a60000,0x00002aabe7a60000,0x00002aabf3650000) ParOldGen total 3145728K, used 158627K [0x00002aaab3650000, 0x00002aab73650000, 0x00002aab73650000) object space 3145728K, 5% used [0x00002aaab3650000,0x00002aaabd138d28,0x00002aab73650000) PSPermGen total 45504K, used 19965K [0x00002aaaae250000, 0x00002aaab0ec0000, 0x00002aaab3650000) object space 45504K, 43% used [0x00002aaaae250000,0x00002aaaaf5cf668,0x00002aaab0ec0000) I am on 64-bit Linux and JRE 1.6.0_10: $uname -a Linux x 2.6.24-etchnhalf.1-amd64 #1 SMP Tue Oct 14 03:11:45 UTC 2008 x86_64 GNU/Linux $java -version java version "1.6.0_10" Java(TM) SE Runtime Environment (build 1.6.0_10-b33) Java HotSpot(TM) 64-Bit Server VM (build 11.0-b15, mixed mode)

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  • C problem, left of '->' must point to class/struct/union/generic type ??

    - by Patrick
    Hello! Trying to understand why this doesn't work. I keep getting the following errors: left of '-nextNode' must point to class/struct/union/generic type (Also all the lines with a - in the function new_math_struct) Header file #ifndef MSTRUCT_H #define MSTRUCT_H #define PLUS 0 #define MINUS 1 #define DIVIDE 2 #define MULTIPLY 3 #define NUMBER 4 typedef struct math_struct { int type_of_value; int value; int sum; int is_used; struct math_struct* nextNode; } ; typedef struct math_struct* math_struct_ptr; #endif C file int get_input(math_struct_ptr* startNode) { /* character, input by the user */ char input_ch; char* input_ptr; math_struct_ptr* ptr; math_struct_ptr* previousNode; input_ptr = &input_ch; previousNode = startNode; /* as long as input is not ok */ while (1) { input_ch = get_input_character(); if (input_ch == ',') // Carrage return return 1; else if (input_ch == '.') // Illegal character return 0; if (input_ch == '+') ptr = new_math_struct(PLUS, 0); else if (input_ch == '-') ptr = new_math_struct(MINUS, 0); else if (input_ch == '/') ptr = new_math_struct(DIVIDE, 0); else if (input_ch == '*') ptr = new_math_struct(MULTIPLY, 0); else ptr = new_math_struct(NUMBER, atoi(input_ptr)); if (startNode == NULL) { startNode = previousNode = ptr; } else { previousNode->nextNode = ptr; previousNode = ptr; } } return 0; } math_struct_ptr* new_math_struct(int symbol, int value) { math_struct_ptr* ptr; ptr = (math_struct_ptr*)malloc(sizeof(math_struct_ptr)); ptr->type_of_value = symbol; ptr->value = value; ptr->sum = 0; ptr->is_used = 0; return ptr; } char get_input_character() { /* character, input by the user */ char input_ch; /* get the character */ scanf("%c", &input_ch); if (input_ch == '+' || input_ch == '-' || input_ch == '*' || input_ch == '/' || input_ch == ')') return input_ch; // A special character else if (input_ch == '\n') return ','; // A carrage return else if (input_ch < '0' || input_ch > '9') return '.'; // Not a number else return input_ch; // Number } The header for the C file just contains a reference to the struct header and the definitions of the functions. Language C.

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  • Can PetaPoco populate an object using a stored procedure with a join clause?

    - by Mark Kadlec
    I have a stored procedure that does something similar to: SELECT a.TaskId, b.CompanyCode FROM task a JOIN company b ON b.CompanyId = a.CompanyId; I have an object called TaskItem that has the TaskId and CompanyCode properties, but when I execute the following (which I would have assumed worked): var masterDatabase = new Database("MasterConnectionString"); var s = PetaPoco.Sql.Builder.Append("EXEC spGetTasks @@numberOfTasks = @0", numberOfTasks); var tasks = masterDatabase.Query<Task>(s); The problem is that the CompanyCode column does not exist in the task table, I did a trace and it seems that PetaPoco is trying to select all the properties from the task table and populating using the stored procedure. How can I use PetaPoco to simply populate the list of task objects with the results of the stored procedure?

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  • how to join a set of XElements to the values of a struct?

    - by jcollum
    Let's say I have a struct that contains local environments: public struct Environments { public const string Dev = "DEV"; public const string Qa1 = "SQA"; public const string Prod1 = "PROD"; public const string Prod2 = "PROD_SA"; public const string Uat = "UAT"; } And I'd like to pull a set of XElements out of an xml doc, but only those elements that have a key that matches a value in a struct. this.environments =(from e in settings.Element("Settings").Element("Environments") .Elements("Environment") .Where( x => x.HasAttribute("name") ) join f in [struct?] on e.Attribute("name") equals [struct value?]).ToDictionary(...) How would I go about doing this? Do I need reflection to get the values of the constants in the struct?

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  • Rails - How do i update a records value in a join model ?

    - by ChrisWesAllen
    I have a join model in a HABTM relationship with a through association (details below). I 'm trying to find a record....find the value of that records attribute...change the value and update the record but am having a hard time doing it. The model setup is this User.rb has_many :choices has_many :interests, :through => :choices Interest.rb has_many :choices has_many :users, :through => :choices Choice.rb belongs_to :user belongs_to :interest and Choice has the user_id, interest_id, score as fields. And I find the ?object? like so @choice = Choice.where(:user_id => @user.id, :interest_id => interest.id) So the model Choice has an attribute called :score. How do I find the value of the score column....and +1/-1 it and then resave? I tried @choice.score = @choice.score + 1 @choice.update_attributes(params[:choice]) flash[:notice] = "Successfully updated choices value." but I get "undefined method score"......What did i miss?

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  • Join DELETE in MySql? How to?

    - by Camran
    I have this: $query="DELETE FROM classified, $sql_table WHERE classified.ad_id = '$id' AND classified.classified_id = $sql_table.classified_id AND classified.poster_password='$pass'"; I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE classified.ad_id = 'Bmw_M3_E46_Full_29920' AND classified.cla' at line 1 Any help? As you can see the $sql_table is linked to the classifieds table with the fields classified_id I need to JOIN DELETE somehow. Basically classified table is the main table, then every category has its own tables with vehicle data. classified table has a field called classified_id which is the same as the Here is the full query echoed: DELETE FROM classified, vehicles WHERE classified.ad_id = 'Bmw_M3_E46_410811305' AND classified.classified_id = vehicles.classified_id AND classified.poster_password='some_password' Why isn't this working, Should it be so hard to delete from multiple tables? Thanks

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  • How to perform a join with CodeIgniter's Active Record class on a multicolumn key?

    - by Scott Southworth
    I've been able to make this code work using CodeIgniter's db->query as follows: $sql = 'SELECT mapping_code,zone_name,installation_name FROM installations,appearances,zones WHERE installations.installation_id = zones.installation_fk_id AND appearances.installation_fk_id = installations.installation_id AND appearances.zone_fk_id = zones.zone_id AND appearances.barcode = ? '; return $this->db->query($sql,array($barcode)); The 'appearances' table throws a 'not unique table' error if I try this using the Active Record class. I need to join appearances on both the zone and installations tables. How can I do this?

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  • Can I join between two MySQL tables stores on separate machines?

    - by CuriousCoder
    I have a relatively light query that needs information from a local MySQL table along with another MySQL table which is stored on a physically separate machine (on the same network). I'm keen to avoid setting up replication just to facilitate this light query that only needs executed once a day. Is there any way that I can join with a table on a remote machine using one query? Or run a SELECT INTO into a local table. Notes I'm using C# & .NET 4.

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  • Can I join 2+ styles together into a superstyle?

    - by Kurru
    Hi I was looking to join 2 styles together to make a super style for easy use and customisation of my page. Is it possible to define something like this? (if so how) .bold { font-weight: bold;} .color1 {color: white;} .boldColor {.bold; .color1;} where .boldColor is effectively .boldColor {font-weight:bold; color:white;} I want this so that I can have styles thoughout the page and be able to easily change the colors in many places in 1 place. I'm currently using <p class="bold color"> but some of my class defs are becoming long so I'd like to be able to use <p class="boldColor"> Thanks

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  • In which layer should I join 2 entities together?

    - by William
    I use Spring MVC and a regular JDBC. I've just learned that I should separate business process into layers which are presentation layer, controller layer, service layer, and repository/DAO layer. Now suppose that I have an Entity called Person that can have multiple Jobs. Job itself is another entity which have its own properties. From what I gathered, the repository layer only manages one entity. Now I have one entity that contains another entity. Where do I "join" them? The service layer? Suppose I want to get a person whose job isn't known yet (lazy loading). But the system might ask what the job of that particular person is later on. What is the role of each layer in this case? Please let me know if I need to add any detail into this question.

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  • Can anyone help me with a complex sum, 3 table join mysql query?

    - by Scarface
    Hey guys I have a query and it works fine, but I want to add another table to the mix. The invite table I want to add has two fields: username and user_invite. Much like this site, I am using a point system to encourage diligent users. The current query which is displayed below adds the up votes and down votes based on the user in question: $creator. I want to count the number of entries for that same user from the invite table, and add 50 for each row it finds to the current output/sum of my query. Is this possible with one query, or do I need two? "SELECT *, SUM(IF(points_id = \"1\", 1,0))-SUM(IF(points_id = \"2\", 1,0)) AS 'total' FROM points LEFT JOIN post ON post.post_id=points.points_id WHERE post.creator='$creator'"

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  • How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way?

    - by EugeneP
    How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way? As I see it returns a list of Objects. yes, it is tricky and only you who write the query know what should the query return (what objects). But are there ways to simplify things, so that it returned specific objects with no need in casting Object to a specific class according to its position in the query ? Maybe Spring can simplify things here? It has the similar functionality for JDBC, but I don't see if it can help in a similar way with Hibernate.

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  • Any Way to Use a Join in a Lambda Where() on a Table<>?

    - by lush
    I'm in my first couple of days using Linq in C#, and I'm curious to know if there is a more concise way of writing the following. MyEntities db = new MyEntities(ConnString); var q = from a in db.TableA join b in db.TableB on a.SomeFieldID equals b.SomeFieldID where (a.UserID == CurrentUser && b.MyField == Convert.ToInt32(MyDropDownList.SelectedValue)) select new { a, b }; if(q.Any()) { //snip } I know that if I were to want to check the existence of a value in the field of a single table, I could just use the following: if(db.TableA.Where(u => u.UserID == CurrentUser).Any()) { //snip } But I'm curious to know if there is a way to do the lambda technique, but where it would satisfy the first technique's conditions across those two tables. Sorry for any mistakes or clarity, I'll edit as necessary. Thanks in advance.

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  • dropbox slow on ubuntu 14.04

    - by Donbeo
    My dropbox syncing is incredibly slow... I am using dropbox from the ubuntu repository on an almost fresh ubuntu installation. I would like to avoid to install the package from the dropbox website for the reasons explained here Dropbox Upgrade Is someone having the same problem? How can I solve? EDIT : This is an example of what I get. donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining, 22 secs left) Uploading 17 files (123.3 KB/sec, 22 secs left) donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining, 3 mins left) Uploading 17 files (13.2 KB/sec, 3 mins left) donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining, 5 mins left) Uploading 17 files (8.2 KB/sec, 5 mins left) donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining) Uploading 17 files... donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining) Uploading 17 files... donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ EDIT: I have run sudo dropbox update so I am probably using the last version of dropbox

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  • Parallelism in .NET – Part 11, Divide and Conquer via Parallel.Invoke

    - by Reed
    Many algorithms are easily written to work via recursion.  For example, most data-oriented tasks where a tree of data must be processed are much more easily handled by starting at the root, and recursively “walking” the tree.  Some algorithms work this way on flat data structures, such as arrays, as well.  This is a form of divide and conquer: an algorithm design which is based around breaking up a set of work recursively, “dividing” the total work in each recursive step, and “conquering” the work when the remaining work is small enough to be solved easily. Recursive algorithms, especially ones based on a form of divide and conquer, are often a very good candidate for parallelization. This is apparent from a common sense standpoint.  Since we’re dividing up the total work in the algorithm, we have an obvious, built-in partitioning scheme.  Once partitioned, the data can be worked upon independently, so there is good, clean isolation of data. Implementing this type of algorithm is fairly simple.  The Parallel class in .NET 4 includes a method suited for this type of operation: Parallel.Invoke.  This method works by taking any number of delegates defined as an Action, and operating them all in parallel.  The method returns when every delegate has completed: Parallel.Invoke( () => { Console.WriteLine("Action 1 executing in thread {0}", Thread.CurrentThread.ManagedThreadId); }, () => { Console.WriteLine("Action 2 executing in thread {0}", Thread.CurrentThread.ManagedThreadId); }, () => { Console.WriteLine("Action 3 executing in thread {0}", Thread.CurrentThread.ManagedThreadId); } ); .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Running this simple example demonstrates the ease of using this method.  For example, on my system, I get three separate thread IDs when running the above code.  By allowing any number of delegates to be executed directly, concurrently, the Parallel.Invoke method provides us an easy way to parallelize any algorithm based on divide and conquer.  We can divide our work in each step, and execute each task in parallel, recursively. For example, suppose we wanted to implement our own quicksort routine.  The quicksort algorithm can be designed based on divide and conquer.  In each iteration, we pick a pivot point, and use that to partition the total array.  We swap the elements around the pivot, then recursively sort the lists on each side of the pivot.  For example, let’s look at this simple, sequential implementation of quicksort: public static void QuickSort<T>(T[] array) where T : IComparable<T> { QuickSortInternal(array, 0, array.Length - 1); } private static void QuickSortInternal<T>(T[] array, int left, int right) where T : IComparable<T> { if (left >= right) { return; } SwapElements(array, left, (left + right) / 2); int last = left; for (int current = left + 1; current <= right; ++current) { if (array[current].CompareTo(array[left]) < 0) { ++last; SwapElements(array, last, current); } } SwapElements(array, left, last); QuickSortInternal(array, left, last - 1); QuickSortInternal(array, last + 1, right); } static void SwapElements<T>(T[] array, int i, int j) { T temp = array[i]; array[i] = array[j]; array[j] = temp; } Here, we implement the quicksort algorithm in a very common, divide and conquer approach.  Running this against the built-in Array.Sort routine shows that we get the exact same answers (although the framework’s sort routine is slightly faster).  On my system, for example, I can use framework’s sort to sort ten million random doubles in about 7.3s, and this implementation takes about 9.3s on average. Looking at this routine, though, there is a clear opportunity to parallelize.  At the end of QuickSortInternal, we recursively call into QuickSortInternal with each partition of the array after the pivot is chosen.  This can be rewritten to use Parallel.Invoke by simply changing it to: // Code above is unchanged... SwapElements(array, left, last); Parallel.Invoke( () => QuickSortInternal(array, left, last - 1), () => QuickSortInternal(array, last + 1, right) ); } This routine will now run in parallel.  When executing, we now see the CPU usage across all cores spike while it executes.  However, there is a significant problem here – by parallelizing this routine, we took it from an execution time of 9.3s to an execution time of approximately 14 seconds!  We’re using more resources as seen in the CPU usage, but the overall result is a dramatic slowdown in overall processing time. This occurs because parallelization adds overhead.  Each time we split this array, we spawn two new tasks to parallelize this algorithm!  This is far, far too many tasks for our cores to operate upon at a single time.  In effect, we’re “over-parallelizing” this routine.  This is a common problem when working with divide and conquer algorithms, and leads to an important observation: When parallelizing a recursive routine, take special care not to add more tasks than necessary to fully utilize your system. This can be done with a few different approaches, in this case.  Typically, the way to handle this is to stop parallelizing the routine at a certain point, and revert back to the serial approach.  Since the first few recursions will all still be parallelized, our “deeper” recursive tasks will be running in parallel, and can take full advantage of the machine.  This also dramatically reduces the overhead added by parallelizing, since we’re only adding overhead for the first few recursive calls.  There are two basic approaches we can take here.  The first approach would be to look at the total work size, and if it’s smaller than a specific threshold, revert to our serial implementation.  In this case, we could just check right-left, and if it’s under a threshold, call the methods directly instead of using Parallel.Invoke. The second approach is to track how “deep” in the “tree” we are currently at, and if we are below some number of levels, stop parallelizing.  This approach is a more general-purpose approach, since it works on routines which parse trees as well as routines working off of a single array, but may not work as well if a poor partitioning strategy is chosen or the tree is not balanced evenly. This can be written very easily.  If we pass a maxDepth parameter into our internal routine, we can restrict the amount of times we parallelize by changing the recursive call to: // Code above is unchanged... SwapElements(array, left, last); if (maxDepth < 1) { QuickSortInternal(array, left, last - 1, maxDepth); QuickSortInternal(array, last + 1, right, maxDepth); } else { --maxDepth; Parallel.Invoke( () => QuickSortInternal(array, left, last - 1, maxDepth), () => QuickSortInternal(array, last + 1, right, maxDepth)); } We no longer allow this to parallelize indefinitely – only to a specific depth, at which time we revert to a serial implementation.  By starting the routine with a maxDepth equal to Environment.ProcessorCount, we can restrict the total amount of parallel operations significantly, but still provide adequate work for each processing core. With this final change, my timings are much better.  On average, I get the following timings: Framework via Array.Sort: 7.3 seconds Serial Quicksort Implementation: 9.3 seconds Naive Parallel Implementation: 14 seconds Parallel Implementation Restricting Depth: 4.7 seconds Finally, we are now faster than the framework’s Array.Sort implementation.

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  • Menu widget - no jQuery nor Javascript required - pure CSS

    - by Renso
    Goal: Create a menu widget that does not require any javascript, extremely lightweight, very fast, soley based on CSS, compatible with FireFox and Chrome. Issues: May have some rendering issues in some versions of IE, sorry :-) Instruments: css file html with specific menu format jQuery-ui library - optional if you want to use your own images/colors Implementation Details: HTML: <div id="header">   <div id="header_Menubar">     <ul class="linkList0 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">         <li class="first more ui-state-default ui-corner-top ui-tabs-selected"><a title="Home" href="/Home">Home</a>             <ul class="linkList01 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">                 <li class="ifirst ui-state-default ui-corner-top"><abbr title="Go Home"></abbr><a title="Home" href="/Home">Home</a></li>             </ul>         </li>         <li class="more ui-state-default ui-corner-top ui-tabs-selected"><a title="Menu 2" href="/Menu2a">Menu 2</a>             <ul class="linkList01 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">                 <li class="ifirst ui-state-default ui-corner-top"><abbr title="Menu 2 a"></abbr><a title="Menu 2 a" href="/Menu2a">Menu 2 a</a></li>                 <li class="ilast ui-state-default ui-corner-top"><abbr title="Menu 2 b"></abbr><a title="Menu 2 b" href="/Menu2b">Menu 2 b</a></li>             </ul>         </li>         <li class="more red ui-state-default ui-corner-top ui-tabs-selected"><a title="Menu 3" href="/Menu3 d">Menu 3</a>             <ul class="linkList01 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">                 <li class="ifirst ui-state-default ui-corner-top"><abbr title="Menu 3 a"><a title="Menu 3 a" href="/Menu3a">Menu 3 a</a></abbr></li>                 <li class="ui-state-default ui-corner-top"><abbr title="Menu 3 b"><a title="Menu 3 b" href="/Menu3b">Menu 3 b</a></abbr></li>                 <li class="ui-state-default ui-corner-top"><abbr title="Menu 3 c"><a title="Menu 3 c" href="/Menu3c">Menu 3 c</a></abbr></li>                 <li class="ilast ui-state-default ui-corner-top"><abbr title="Menu 3 d"><a title="Menu 3 d" href="/Menu3d">Menu 3 d</a></abbr></li>             </ul>         </li>     </ul>     </div> </div> CSS: /*    =Menu     -----------------------------------------------------------------------------------------    */ #header #header_Menubar {     margin: 0;     padding: 0;     border: 0;     width: 100%;     height: 22px; } #header {     background-color: #99cccc;     background-color: #aaccee;     background-color: #5BA3E0;     background-color: #006cb1; } /* Set menu bar background color     */ #header #header_Menubar {     background-attachment: scroll;     background-position: left center;     background-repeat: repeat-x; } /*    Set main (horizontal) menu typology    */ #header .linkList0 {     padding: 0 0 1em 0;     margin-bottom: 1em;     font-family: 'Trebuchet MS', 'Lucida Grande',           Verdana, Lucida, Geneva, Helvetica,           Arial, sans-serif;     font-weight: bold;     font-size: 1.085em;     font-size: 1em; } /*    Set all ul properties    */ #header .linkList0, #header .linkList0 ul {     list-style: none;     margin: 0;     padding: 0;     list-style-position: outside; } /*    Set all li properties    */ #header .linkList0 > li {     float: left;     position: relative;     font-size: 90%;     margin: 0 0 -1px;     width: 9.7em;     padding-right: 2em;     z-index: 100;    /*IE7:    Fix for IE7 hiding drop down list behind some other page elements    */ } /*    Set all li properties    */ #header .linkList01 > li {     width: 190px; } #header .linkList0 .linkList01 li {     margin-left: 0px; } /*    Set all list background image properties    */ /*#header .linkList0 li a {     background-position: left center;     background-image: url(  '../Content/Images/VerticalButtonBarGradientFade.png' );     background-repeat: repeat-x;     background-attachment: scroll; }*/ /*    Set all A ancor properties    */ #header .linkList0 li a {     display: block;     text-decoration: none;     line-height: 22px; } /*    IE7: Fix for a bug in IE7 where the margins between list items is doubled - need to set height explicitly    */ *+html #header .linkList0 ul li {     height: auto;     margin-bottom: -.3em; } /*    Menu:    Set different borders for different nested level lists     --------------------------------------------------------------    */ #header .linkList0 > li a {     border-left: 10px solid Transparent;     border-right: none; } #header .linkList0 > li a {     border-left: 0px;     margin-left: 0px;     border-right: none; } #header .linkList0 .linkList01 > li a {     border-left: 8px solid #336699;     border-right: none;     border: 1px solid Transparent;     -moz-border-radius: 5px 5px 5px 5px;     -moz-box-shadow: 3px 3px 4px #696969; } #header .linkList0 .linkList01 .linkList001 > li a {     border-left: 6px solid #336699;     border-right: none;     border: 1px solid Transparent;     -moz-border-radius: 5px 5px 5px 5px;     -moz-box-shadow: 3px 3px 4px #696969; } #header .linkList0 .linkList01 .linkList001 .linkList0001 > li a {     border-left: 4px solid #336699;     border-right: none;     border: 1px solid Transparent;     -moz-border-radius: 5px 5px 5px 5px;     -moz-box-shadow: 3px 3px 4px #696969; }     /*    Link and Visited pseudo-class settings for all lists (ul)    */ #header .linkList0 a:link, #header .linkList0 a:visited {     display: block;     text-decoration: none;     padding-left: 1em; } /*    Hide all the nested/sub menu items    */ #header .linkList0 ul {     display: none;     padding: 0;     position: absolute;    /*Important: must not impede on other page elements when drop down opens up    */ } /*    Hide all detail popups    */ #header .detailPopup {     display: none; } /*    Set the typology of all sub-menu list items li    */ /*#header .linkList0 ul li {     background-color: #AACCEE;     background-position: left center;     background-image: url(  '../Content/Images/VerticalButtonBarGradientFade.png' );     background-repeat: repeat-x;     background-attachment: scroll; }*/ #header .linkList0 ul li.more {     background: Transparent url('../Content/Images/ArrowRight.gif') no-repeat right center; } /*    Header list's margin and padding for all list items    */ #header .linkList0 ul li {     margin: 0 0 0 1em;     padding: 0; } #header .linkList01 ul li {     margin: 0;     padding: 0;     width: 189px; } /*    Set margins for the third li sibling (Plan a Call) to display to the right of the parent menu     to avoid the sub-menu overlaying the menu items below    */ #header .linkList0 li.more .linkList01 li.more > ul.linkList001 {     margin: -1.7em 0 0 13.2em;    /*Important, must be careful, if tbe EM since gap increases too much bewteen nested lists the gap will make the nested-list collapse prematurely    */ } /*    Set right hand arrow for list items with sub-menus (class-more)    */ #header li.more {     background: Transparent url('../Content/Images/ArrowRight.gif') no-repeat right center;     padding-right: 48px; } /*    Menu:    Dynamic Behavior of menu items (hover, visted, etc)     -----------------------------------------------------------    */ #header .linkList0 li a:link, #header .linkList01 li a:link {     display: block; } #header .linkList0 li a:visited, #header .linkList01 li a:visited {     display: block; } #header .linkList0 > li:hover { } #header .linkList01 > li:hover a ,#header .linkList001 > li:hover a {     text-decoration: underline; } #header .linkList0 > li abbr:hover span.detailPopup {     display: block;     position: absolute;     top: 1em;     left: 17em;     border: double 1px #696969;     border-style: outset;     width: 120%;     height: auto;     padding: 5px;     font-weight: 100; } #header .linkList0 > li:hover ,#header .linkList0 .linkList01 > li:hover { } #header .linkList0 .linkList01 .linkList001 > li:hover { } #header .linkList0 .linkList01 .linkList001 .linkList0001 > li:hover { } /*    Display the hidden sub menu when hovering over the parent ul's li    */ #header .linkList0 li:hover > ul {     display: block; } /*    Display the hidden sub menu when hovering over the parent ul's li    */ #header .linkList0 .linkList01 li:hover > ul {     display: block;         background: -moz-linear-gradient(top, #1E83CC, #619FCD);     /* Chrome, Safari:*/     background: -webkit-gradient(linear,                 center top, center bottom, from(#1E83CC), to(#619FCD)); } /*    Display the hidden sub menu when hovering over the parent ul's li    */ #header .linkList0 .linkList01 .linkList001 li:hover > ul {     display: block; } /*    Set right hand arrow for list items with sub-menus (class-more) on hover    */ #header li.more:hover { } Also some CSS for global settings that will affect this menu, you of course will have some other styling, but included it here so you can see how/why some css properties were set here: /* Neutralize styling:    Elements we want to clean out entirely: */ html, body {     margin: 0;     padding: 0;     font: 62.5%/120% Verdana, Arial, Helvetica, sans-serif; } /* Neutralize styling:    Elements with a vertical margin: */ h1, h2, h3, h4, h5, h6, p, pre, blockquote, ul, ol, dl, address {     margin: 0;    /*    most browsers set some default value that is not shared by all browsers    */     padding: 0;        /*    some borowsers default padding, set to 0 for all    */ } /* Apply left margin:    Only to the few elements that need it: */ li, dd, blockquote {     margin-left: 1em; }

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  • Android Can't get two virtual joysticks to move independently and at the same time

    - by Cole
    @Override public boolean onTouch(View v, MotionEvent event) { // TODO Auto-generated method stub float r = 70; float centerLx = (float) (screenWidth*.3425); float centerLy = (float) (screenHeight*.4958); float centerRx = (float) (screenWidth*.6538); float centerRy = (float) (screenHeight*.4917); float dx = 0; float dy = 0; float theta; float c; int action = event.getAction(); int actionCode = action & MotionEvent.ACTION_MASK; int pid = (action & MotionEvent.ACTION_POINTER_INDEX_MASK) >> MotionEvent.ACTION_POINTER_INDEX_SHIFT; int fingerid = event.getPointerId(pid); int x = (int) event.getX(pid); int y = (int) event.getY(pid); c = FloatMath.sqrt(dx*dx + dy*dy); theta = (float) Math.atan(Math.abs(dy/dx)); switch (actionCode) { case MotionEvent.ACTION_DOWN: case MotionEvent.ACTION_POINTER_DOWN: //if touching down on left stick, set leftstick ID to this fingerid. if(x < screenWidth/2 && c<r*.8) { lsId = fingerid; dx = x-centerLx; dy = y-centerLy; touchingLs = true; } else if(x > screenWidth/2 && c<r*.8) { rsId = fingerid; dx = x-centerRx; dy = y-centerRy; touchingRs = true; } break; case MotionEvent.ACTION_MOVE: if (touchingLs && fingerid == lsId) { dx = x - centerLx; dy = y - centerLy; }else if (touchingRs && fingerid == rsId) { dx = x - centerRx; dy = y - centerRy; } c = FloatMath.sqrt(dx*dx + dy*dy); theta = (float) Math.atan(Math.abs(dy/dx)); //if touching outside left radius and moving left stick if(c >= r && touchingLs && fingerid == lsId) { if(dx>0 && dy<0) { //top right quadrant lsX = r * FloatMath.cos(theta); lsY = -(r * FloatMath.sin(theta)); Log.i("message", "top right"); } if(dx<0 && dy<0) { //top left quadrant lsX = -(r * FloatMath.cos(theta)); lsY = -(r * FloatMath.sin(theta)); Log.i("message", "top left"); } if(dx<0 && dy>0) { //bottom left quadrant lsX = -(r * FloatMath.cos(theta)); lsY = r * FloatMath.sin(theta); Log.i("message", "bottom left"); } else if(dx > 0 && dy > 0){ //bottom right quadrant lsX = r * FloatMath.cos(theta); lsY = r * FloatMath.sin(theta); Log.i("message", "bottom right"); } } if(c >= r && touchingRs && fingerid == rsId) { if(dx>0 && dy<0) { //top right quadrant rsX = r * FloatMath.cos(theta); rsY = -(r * FloatMath.sin(theta)); Log.i("message", "top right"); } if(dx<0 && dy<0) { //top left quadrant rsX = -(r * FloatMath.cos(theta)); rsY = -(r * FloatMath.sin(theta)); Log.i("message", "top left"); } if(dx<0 && dy>0) { //bottom left quadrant rsX = -(r * FloatMath.cos(theta)); rsY = r * FloatMath.sin(theta); Log.i("message", "bottom left"); } else if(dx > 0 && dy > 0) { rsX = r * FloatMath.cos(theta); rsY = r * FloatMath.sin(theta); Log.i("message", "bottom right"); } } else { if(c < r && touchingLs && fingerid == lsId) { lsX = dx; lsY = dy; } if(c < r && touchingRs && fingerid == rsId){ rsX = dx; rsY = dy; } } break; case MotionEvent.ACTION_UP: case MotionEvent.ACTION_POINTER_UP: if (fingerid == lsId) { lsId = -1; lsX = 0; lsY = 0; touchingLs = false; } else if (fingerid == rsId) { rsId = -1; rsX = 0; rsY = 0; touchingRs = false; } break; } return true; } There's a left joystick and a right joystick. Right now only one will move at a time. If someone could set me on the right track I would be incredibly grateful cause I've been having nightmares about this problem.

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  • ALSA samples capture: cannot open device

    - by Randagio
    I'm quite new to Linux (Lubuntu 12.04 for sake of precision) and ALSA programming at all. I'm trying to write a C program to capture audio from internal PC microphone for processing it. So as first step I google a bit and I found this article for capturing audio samples A tutorial on using the ALSA Audio API but when I compile it and execute it with: ./capture "default" or ./capture "hw:0,0" and all the possible variants on theme it always raises the error: cannot open device hw:0,0 (no such file or directory). So the issue is: what is the name of the mic audio device to pass as parameter to record the audio from mic ? The mic is working ok because the Sound Recorder program records sounds perfectly and I can playback them. The output of the aplay -l is the following : **** List of PLAYBACK Hardware Devices **** card 0: I82801DBICH4 [Intel 82801DB-ICH4], device 0: Intel ICH [Intel 82801DB-ICH4] Subdevices: 1/1 Subdevice #0: subdevice #0 card 0: I82801DBICH4 [Intel 82801DB-ICH4], device 4: Intel ICH - IEC958 [Intel 82801DB-ICH4 - IEC958] Subdevices: 1/1 Subdevice #0: subdevice #0 and this is the amixer output (cut) Simple mixer control 'Master',0 Capabilities: pvolume pswitch penum Playback channels: Front Left - Front Right Limits: Playback 0 - 31 Mono: Front Left: Playback 31 [100%] [0.00dB] [on] Front Right: Playback 31 [100%] [0.00dB] [on] Simple mixer control 'Master Mono',0 Capabilities: pvolume pvolume-joined pswitch pswitch-joined penum Playback channels: Mono Limits: Playback 0 - 31 Mono: Playback 4 [13%] [-40.50dB] [on] Simple mixer control 'PCM',0 Capabilities: pvolume pswitch penum Playback channels: Front Left - Front Right Limits: Playback 0 - 31 Mono: Front Left: Playback 31 [100%] [12.00dB] [on] Front Right: Playback 31 [100%] [12.00dB] [on] Simple mixer control 'CD',0 Capabilities: pvolume pswitch cswitch cswitch-exclusive penum Capture exclusive group: 0 Playback channels: Front Left - Front Right Capture channels: Front Left - Front Right Limits: Playback 0 - 31 Front Left: Playback 0 [0%] [-34.50dB] [off] Capture [off] Front Right: Playback 0 [0%] [-34.50dB] [off] Capture [off] Simple mixer control 'Mic',0 Capabilities: pvolume pvolume-joined pswitch pswitch-joined cswitch cswitch-exclusive penum Capture exclusive group: 0 Playback channels: Mono Capture channels: Front Left - Front Right Limits: Playback 0 - 31 Mono: Playback 22 [71%] [-1.50dB] [on] Front Left: Capture [on] Front Right: Capture [on] Simple mixer control 'Mic Boost (+20dB)',0 Capabilities: pswitch pswitch-joined penum Playback channels: Mono Mono: Playback [off] Simple mixer control 'Mic Select',0 Capabilities: enum Items: 'Mic1' 'Mic2' Item0: 'Mic1' Simple mixer control 'Stereo Mic',0 Capabilities: pswitch pswitch-joined penum Playback channels: Mono Mono: Playback [off] so for aplay it seems I have no recording device, but for amixer I've got the mic, a mic boost and mic stereo as well with all those gorgeous stuffs on their place !!. If so, how could my Sound Recorder record the audio without any problem at all ?!?! For sure I'm giving the wrong device name to the command line for capturing audio but I'm loosing the hope for finding the correct one ! Please help....before I tear my hair out !!!

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  • Collision Error

    - by Manji
    I am having trouble with collision detection part of the game. I am using touch events to fire the gun as you will see in the video. Note, the android icon is a temporary graphic for the bullets When ever the user touches (represented by clicks in the video)the bullet appears and kills random sprites. As you can see it never touches the sprites it kills or kill the sprites it does touch. My Question is How do I fix it, so that the sprite dies when the bullet hits it? Collision Code snippet: //Handles Collision private void CheckCollisions(){ synchronized(mSurfaceHolder){ for (int i = sprites.size() - 1; i >= 0; i--){ Sprite sprite = sprites.get(i); if(sprite.isCollision(bullet)){ sprites.remove(sprite); mScore++; if(sprites.size() == 0){ mLevel = mLevel +1; currentLevel++; initLevel(); } break; } } } } Sprite Class Code Snippet: //bounding box left<right and top>bottom int left ; int right ; int top ; int bottom ; public boolean isCollision(Beam other) { // TODO Auto-generated method stub if(this.left>other.right || other.left<other.right)return false; if(this.bottom>other.top || other.bottom<other.top)return false; return true; } EDIT 1: Sprite Class: public class Sprite { // direction = 0 up, 1 left, 2 down, 3 right, // animation = 3 back, 1 left, 0 front, 2 right int[] DIRECTION_TO_ANIMATION_MAP = { 3, 1, 0, 2 }; private static final int BMP_ROWS = 4; private static final int BMP_COLUMNS = 3; private static final int MAX_SPEED = 5; private HitmanView gameView; private Bitmap bmp; private int x; private int y; private int xSpeed; private int ySpeed; private int currentFrame = 0; private int width; private int height; //bounding box left<right and top>bottom int left ; int right ; int top ; int bottom ; public Sprite(HitmanView gameView, Bitmap bmp) { this.width = bmp.getWidth() / BMP_COLUMNS; this.height = bmp.getHeight() / BMP_ROWS; this.gameView = gameView; this.bmp = bmp; Random rnd = new Random(); x = rnd.nextInt(gameView.getWidth() - width); y = rnd.nextInt(gameView.getHeight() - height); xSpeed = rnd.nextInt(MAX_SPEED * 2) - MAX_SPEED; ySpeed = rnd.nextInt(MAX_SPEED * 2) - MAX_SPEED; } private void update() { if (x >= gameView.getWidth() - width - xSpeed || x + xSpeed <= 0) { xSpeed = -xSpeed; } x = x + xSpeed; if (y >= gameView.getHeight() - height - ySpeed || y + ySpeed <= 0) { ySpeed = -ySpeed; } y = y + ySpeed; currentFrame = ++currentFrame % BMP_COLUMNS; } public void onDraw(Canvas canvas) { update(); int srcX = currentFrame * width; int srcY = getAnimationRow() * height; Rect src = new Rect(srcX, srcY, srcX + width, srcY + height); Rect dst = new Rect(x, y, x + width, y + height); canvas.drawBitmap(bmp, src, dst, null); } private int getAnimationRow() { double dirDouble = (Math.atan2(xSpeed, ySpeed) / (Math.PI / 2) + 2); int direction = (int) Math.round(dirDouble) % BMP_ROWS; return DIRECTION_TO_ANIMATION_MAP[direction]; } public boolean isCollision(float x2, float y2){ return x2 > x && x2 < x + width && y2 > y && y2 < y + height; } public boolean isCollision(Beam other) { // TODO Auto-generated method stub if(this.left>other.right || other.left<other.right)return false; if(this.bottom>other.top || other.bottom<other.top)return false; return true; } } Bullet Class: public class Bullet { int mX; int mY; private Bitmap mBitmap; //bounding box left<right and top>bottom int left ; int right ; int top ; int bottom ; public Bullet (Bitmap mBitmap){ this.mBitmap = mBitmap; } public void draw(Canvas canvas, int mX, int mY) { this.mX = mX; this.mY = mY; canvas.drawBitmap(mBitmap, mX, mY, null); } }

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  • Non persistent keyboard shortcuts in Unity

    - by nblumoe
    I did change the keyboard shortcuts for window navigation in Unity to use hjkl (vim movement). I did reassign the shortcuts via GUI in System Settings Keyboard Shortcuts. Here are two examples of the assigned shortcuts: Move window one workspace to the left = Shift+Ctrl+Alt+H Switch to workspace left = Ctrl+Alt+H Occasionally, when restarting the maching, these shortcuts are being reset to theit default values: Move window one workspace to the left = Shift+Ctrl+Alt+Left Switch to workspace left = Ctrl+Alt+Left How can I make these changes permanent? Can someone help me, narrowing down the problem?

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  • How to set sprite source coordinates?

    - by ChaosDev
    I am creating own sprite drawer with DX11 on C++. Works fine but I dont know how to apply source rectangle to texture coordinates of rendering surface(for animation sprite sheets) //source = (0,0,32,64); //RECT D3DXVECTOR2 t0 = D3DXVECTOR2( 1.0f, 0.0f); D3DXVECTOR2 t1 = D3DXVECTOR2( 1.0f, 1.0f); D3DXVECTOR2 t2 = D3DXVECTOR2( 0.0f, 1.0f); D3DXVECTOR2 t3 = D3DXVECTOR2( 0.0f, 1.0f); D3DXVECTOR2 t4 = D3DXVECTOR2( 0.0f, 0.0f); D3DXVECTOR2 t5 = D3DXVECTOR2( 1.0f, 0.0f); VertexPositionColorTexture vertices[] = { { D3DXVECTOR3( dest.left+dest.right, dest.top, z),D3DXVECTOR4(1,1,1,1), t0}, { D3DXVECTOR3( dest.left+dest.right, dest.top+dest.bottom, z),D3DXVECTOR4(1,1,1,1), t1}, { D3DXVECTOR3( dest.left, dest.top+dest.bottom, z),D3DXVECTOR4(1,1,1,1), t2}, { D3DXVECTOR3( dest.left, dest.top+dest.bottom, z),D3DXVECTOR4(1,1,1,1), t3}, { D3DXVECTOR3( dest.left , dest.top, z),D3DXVECTOR4(1,1,1,1), t4}, { D3DXVECTOR3( dest.left+dest.right, dest.top, z),D3DXVECTOR4(1,1,1,1), t5}, };

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  • Sorting an XML file through XSL

    - by jbugeja
    I have an XML file that I want to sort by an attribute. The file is structured as shown below: <wb xmlns:cf="http://www.macromedia.com/2004/cfform"> <a:form name="chart"> <a:input FIELDNUMBER="09" INDEX="2" LEFT="200" /> <a:input FIELDNUMBER="08" INDEX="3" LEFT="200" /> <a:fieldset FIELD="a" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="02" INDEX="4" LEFT="200" /> <a:select1 FIELDNUMBER="01" /> </a:fieldset> <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="04" INDEX="7" LEFT="200" /> <a:select1 FIELDNUMBER="03" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="06" INDEX="8" LEFT="200" /> <a:input FIELDNUMBER="05" INDEX="6" LEFT="200" /> </a:fieldset> </a:fieldset> </a:form> </wb> I would like to sort the above XML all throughout by @fieldnumber, but at the same I want to keep the same structure of the XML. I have managed to sort other XML file but they did not have such nesting levels. Is this possible with XSL alone and if so how can this be done? The output should be as follows: <wb xmlns:cf="http://www.macromedia.com/2004/cfform"> <a:form name="chart"> <a:input FIELDNUMBER="08" INDEX="3" LEFT="200" /> <a:input FIELDNUMBER="09" INDEX="2" LEFT="200" /> <a:fieldset FIELD="a" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="01" /> <a:input FIELDNUMBER="02" INDEX="4" LEFT="200" /> </a:fieldset> <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="03" /> <a:input FIELDNUMBER="04" INDEX="7" LEFT="200" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="05" INDEX="6" LEFT="200" /> <a:input FIELDNUMBER="06" INDEX="8" LEFT="200" /> </a:fieldset> </a:fieldset> </a:form> </wb> As another example, should the FIELDNUMBER 04 be changed to a value greater than 7 such as 10 (let's assume 10 in this example) then the output of the fieldset with FIELD value b becomes: <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="03" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="05" INDEX="6" LEFT="200" /> <a:input FIELDNUMBER="06" INDEX="8" LEFT="200" /> </a:fieldset> <a:input FIELDNUMBER="10" INDEX="7" LEFT="200" /> </a:fieldset>

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  • multi divs centered

    - by user1319385
    I have 2 divs with 3 divs inside them, all 2 wrapped around one big div. I try and center it and its not working. Here is my code: <div stye="margin-left:auto; margin-right:auto; width: 1210px;"> <div id="left" style=" float:left; width: 606px; height: 506px;"> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; height:502px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A picture of a cool guy wearing our shirt will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; border-left:0px; height:200px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A product image will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0;border-top:0px; border-left:0px; height:300px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A tight product image will go in here.</h1></div> </div> <div id="left" style="float:left; width: 604px; height: 506px;"> <div style="top:0px; float:right; width:300px; border: 2px solid #FF0; border-left:0px; height:502px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A picture of a cool guy wearing our shirt will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; border-left:0px; height:200px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A product image will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0;border-top:0px; border-left:0px; height:300px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A tight product image will go in here.</h1></div> </div> </div>

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  • How do I remove the time from printpreview dialog?

    - by Albo Best
    Here is my code: Imports System.Data.OleDb Imports System.Drawing.Printing Namespace Print Public Class Form1 Inherits System.Windows.Forms.Form Dim PrintC As PrinterClass Dim conn As OleDb.OleDbConnection Dim connectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=..\\db1.mdb" Dim sql As String = String.Empty Dim ds As DataSet Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load FillDataGrid() '//create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) End Sub Private Sub FillDataGrid() Try Dim dt As New DataTable Dim ds As New DataSet ds.Tables.Add(dt) Dim da As New OleDbDataAdapter con.Open() da = New OleDbDataAdapter("SELECT * from klient ", con) da.Fill(dt) con.Close() dataGrid.DataSource = dt.DefaultView Dim dTable As DataTable For Each dTable In ds.Tables Dim dgStyle As DataGridTableStyle = New DataGridTableStyle dgStyle.MappingName = dTable.TableName dataGrid.TableStyles.Add(dgStyle) Next ' DataGrid settings dataGrid.CaptionText = "TE GJITHE KLIENTET" dataGrid.HeaderFont = New Font("Verdana", 12) dataGrid.TableStyles(0).GridColumnStyles(0).Width = 60 dataGrid.TableStyles(0).GridColumnStyles(1).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(2).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(3).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(4).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(5).HeaderText = "" dataGrid.TableStyles(0).GridColumnStyles(5).Width = -1 Catch ex As Exception MessageBox.Show(ex.Message) End Try End Sub Private Sub btnPrint_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPrint.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) PrintDocument1.Print() End Sub Private Sub btnPreview_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPreview.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) ''preview Dim ps As New PaperSize("A4", 840, 1150) ps.PaperName = PaperKind.A4 PrintDocument1.DefaultPageSettings.PaperSize = ps PrintPreviewDialog1.WindowState = FormWindowState.Normal PrintPreviewDialog1.StartPosition = FormStartPosition.CenterScreen PrintPreviewDialog1.ClientSize = New Size(600, 600) PrintPreviewDialog1.ShowDialog() End Sub Private Sub PrintDocument1_PrintPage(ByVal sender As System.Object, ByVal e As System.Drawing.Printing.PrintPageEventArgs) Handles PrintDocument1.PrintPage 'print grid Dim morepages As Boolean = PrintC.Print(e.Graphics) If (morepages) Then e.HasMorePages = True End If End Sub End Class End Namespace This is how data looks in DataGrid (that's perfect)... and here is how it looks when I click PrintPreview. (I don't want the time to appear there, the "12:00:00" part. in database the date is stored as Short Date (10-Dec-12) Can somebody suggest a way around that? Imports System Imports System.Windows.Forms Imports System.Drawing Imports System.Drawing.Printing Imports System.Collections Imports System.Data Namespace Print Public Class PrinterClass '//clone of Datagrid Dim PrintGrid As Grid '//printdocument for initial printer settings Private PrintDoc As PrintDocument '//defines whether the grid is ordered right to left Private bRightToLeft As Boolean '//Current Top Private CurrentY As Single = 0 '//Current Left Private CurrentX As Single = 0 '//CurrentRow to print Private CurrentRow As Integer = 0 '//Page Counter Public PageCounter As Integer = 0 '/// <summary> '/// Constructor Class '/// </summary> '/// <param name="pdocument"></param> '/// <param name="dgrid"></param> Public Sub New(ByVal pdocument As PrintDocument, ByVal dgrid As DataGrid) 'MyBase.new() PrintGrid = New Grid(dgrid) PrintDoc = pdocument '//The grid columns are right to left bRightToLeft = dgrid.RightToLeft = RightToLeft.Yes '//init CurrentX and CurrentY CurrentY = pdocument.DefaultPageSettings.Margins.Top CurrentX = pdocument.DefaultPageSettings.Margins.Left End Sub Public Function Print(ByVal g As Graphics, ByRef currentX As Single, ByRef currentY As Single) As Boolean '//use predefined area currentX = currentX currentY = currentY PrintHeaders(g) Dim Morepages As Boolean = PrintDataGrid(g) currentY = currentY currentX = currentX Return Morepages End Function Public Function Print(ByVal g As Graphics) As Boolean CurrentX = PrintDoc.DefaultPageSettings.Margins.Left CurrentY = PrintDoc.DefaultPageSettings.Margins.Top PrintHeaders(g) Return PrintDataGrid(g) End Function '/// <summary> '/// Print the Grid Headers '/// </summary> '/// <param name="g"></param> Private Sub PrintHeaders(ByVal g As Graphics) Dim sf As StringFormat = New StringFormat '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = 0 To PrintGrid.Columns - 1 '//set header alignment Select Case (CType(PrintGrid.Headers.GetValue(i), Header).Alignment) Case HorizontalAlignment.Left 'left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX -= PrintGrid.Headers(i).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX += PrintGrid.Headers(i).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY = CurrentY + CType(PrintGrid.Headers.GetValue(0), Header).Height End Sub Private Function PrintDataGrid(ByVal g As Graphics) As Boolean Dim sf As StringFormat = New StringFormat PageCounter = PageCounter + 1 '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = CurrentRow To PrintGrid.Rows - 1 Dim j As Integer For j = 0 To PrintGrid.Columns - 1 '//set cell alignment Select Case (PrintGrid.Cell(i, j).Alignment) '//left Case HorizontalAlignment.Left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center '//right Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX -= PrintGrid.Cell(i, j).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text '//Draw text by alignment g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX += PrintGrid.Cell(i, j).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY += PrintGrid.Cell(i, 0).Height CurrentRow += 1 '//if we are beyond the page margin (bottom) then we need another page, '//return true If (CurrentY > PrintDoc.DefaultPageSettings.PaperSize.Height - PrintDoc.DefaultPageSettings.Margins.Bottom) Then Return True End If Next Return False End Function End Class End Namespace

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  • Not your usual "The multi-part identifier could not be bound" error

    - by Eugene Niemand
    I have the following query, now the strange thing is if I run this query on my development and pre-prod server it runs fine. If I run it on production it fails. I have figured out that if I run just the Select statement its happy but as soon as I try insert into the table variable it complains. DECLARE @RESULTS TABLE ( [Parent] VARCHAR(255) ,[client] VARCHAR(255) ,[ComponentName] VARCHAR(255) ,[DealName] VARCHAR(255) ,[Purchase Date] DATETIME ,[Start Date] DATETIME ,[End Date] DATETIME ,[Value] INT ,[Currency] VARCHAR(255) ,[Brand] VARCHAR(255) ,[Business Unit] VARCHAR(255) ,[Region] VARCHAR(255) ,[DealID] INT ) INSERT INTO @RESULTS SELECT DISTINCT ClientName 'Parent' ,F.ClientID 'client' ,ComponentName ,A.DealName ,CONVERT(SMALLDATETIME , ISNULL(PurchaseDate , '1900-01-01')) 'Purchase Date' ,CONVERT(SMALLDATETIME , ISNULL(StartDate , '1900-01-01')) 'Start Date' ,CONVERT(SMALLDATETIME , ISNULL(EndDate , '1900-01-01')) 'End Date' ,DealValue 'Value' ,D.Currency 'Currency' ,ShortBrand 'Brand' ,G.BU 'Business Unit' ,C.DMRegion 'Region' ,DealID FROM LTCDB_admin_tbl_Deals A INNER JOIN dbo_DM_Brand B ON A.BrandID = B.ID INNER JOIN LTCDB_admin_tbl_DM_Region C ON A.Region = C.ID INNER JOIN LTCDB_admin_tbl_Currency D ON A.Currency = D.ID INNER JOIN LTCDB_admin_tbl_Deal_Clients E ON A.DealID = E.Deal_ID INNER JOIN LTCDB_admin_tbl_Clients F ON E.Client_ID = F.ClientID INNER JOIN LTCDB_admin_tbl_DM_BU G ON G.ID = A.BU INNER JOIN LTCDB_admin_tbl_Deal_Components H ON A.DealID = H.Deal_ID INNER JOIN LTCDB_admin_tbl_Components I ON I.ComponentID = H.Component_ID WHERE EndDate != '1899-12-30T00:00:00.000' AND StartDate < EndDate AND B.ID IN ( 1 , 2 , 5 , 6 , 7 , 8 , 10 , 12 ) AND C.SalesRegionID IN ( 1 , 3 , 4 , 11 , 16 ) AND A.BU IN ( 1 , 2 , 3 , 4 , 5 , 6 , 8 , 9 , 11 , 12 , 15 , 16 , 19 , 20 , 22 , 23 , 24 , 26 , 28 , 30 ) AND ClientID = 16128 SELECT ... FROM @Results I get the following error Msg 8180, Level 16, State 1, Line 1 Statement(s) could not be prepared. Msg 4104, Level 16, State 1, Line 1 The multi-part identifier "Tbl1021.ComponentName" could not be bound. Msg 4104, Level 16, State 1, Line 1 The multi-part identifier "Tbl1011.Currency" could not be bound. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2454'. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2461'. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2491'. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2490'. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2482'. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2478'. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2477'. Msg 207, Level 16, State 1, Line 1 Invalid column name 'Col2475'. EDIT - EDIT - EDIT - EDIT - EDIT - EDIT through a process of elimination I have found that following and wondered if anyone can shed some light on this. If I remove only the DISTINCT the query runs fine, add the DISTINCT and I get strange errors. Also I have found that if I comment the following lines then the query runs with the DISTINCT what is strange is that none of the columns in the table LTCDB_admin_tbl_Deal_Components is referenced so I don't see how the distinct will affect that. INNER JOIN LTCDB_admin_tbl_Deal_Components H ON A.DealID = H.Deal_ID

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