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  • Rename tons of files

    - by ninjascorner
    How can I rename all the files with a pattern like this: thumb_f318d8a580ca5717d686a323b6c2ca0d.jpg0000777 thumb_f18d8aup90ca5717d686a323b6c2c5uh.jpg0000777 thumb_jessr8d8a580ca5717d68623etrtckks.jpg0000777 thumb_4hghd8a580ca5717d686a323b6c2ghjj.jpg0000777 .... to thumb_f318d8a580ca5717d686a323b6c2ca0d.jpg thumb_f18d8aup90ca5717d686a323b6c2c5uh.jpg thumb_jer8d8a580ca5717d686a323etrtckks.jpg thumb_4hghd8a580ca5717d686a323b6c2ghjj.jpg .... Thanks

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  • puppet master --compile logs errors to stdout

    - by danny
    I see a bug about this that was accepted and then closed a year ago: http://projects.puppetlabs.com/issues/3670 but I'm using puppet 2.7.14 and am getting the same issue. I'm trying to use "puppet solo" (i.e. just running puppet apply on each server to be configured) as I only have 2 or 3 servers in this project and adding another server as a puppetmaster would be completely overkill. Unless I'm mistaken, the best way to apply a node manually to a server is to do: puppet master --compile=mynode > catalog.json puppet apply --catalog catalog.json But the puppet master command outputs a couple of warnings and notices to stdout, mixed in with the desired json content. And it uses colored output so I can't just pipe it through egrep -v '^warning:' EDIT: I guess it's not too big of a deal to use grep - since puppet 2.7 pretty-prints the actual content and the warnings don't ever start with spaces, piping the output through egrep '^( |{|})' works So my questions are basically: Is there a better way than this to apply a puppet node without using a puppetmaster? I can't really find any good references online to using puppet without a puppetmaster, even though that seems like a perfectly reasonable thing to do for a small project. Is there a setting or flag that I'm missing that will get puppet master to stop being an asshole and send its errors to stderr instead of stdout? Or do I really have to turn off color logging, then grep to exclude warning: and notice: lines?

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  • Nginx trailing slash not working

    - by user1573604
    I am using the below to match urls and add a trailing slash. Under location / rewrite ^([^.]*[^/])$ $1/ permanent; According to he logs below, it is working, however the get request is still he old url, prior to adding the slash, which results in a 404. 2013/11/08 12:33:19 [notice] 29919#0: 92 "^([^.][^/])$" matches "/foo", client: 100.100.100.100, server: _, request: "GET /foo HTTP/1.1", host: "100.100.100.100" 2013/11/08 12:33:19 [notice] 29919#0: *92 rewritten redirect: "/foo/", client: 100.100.100.100, server: _, request: "GET /foo HTTP/1.1", host: "100.100.100.100" Any suggestions as to why this might be happening?

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  • Rsync and wildcards

    - by Jay White
    I am trying to back up both the "Last Session" and "Current Session" files for Google Chrome in one command, but using a wildcard doesn't seem to work. I am trying with the following command rsync -e "ssh -i new.key" -r --verbose -tz --stats --progress --delete '/cygdrive/c/Users/jay/AppData/Local/Google/Chrome/User Data/Default/*Session' user@host:"/chrome\ sessions/" and get the following error rsync: link_stat "/cygdrive/c/Users/jay/AppData/Local/Google/Chrome/User Data/Default/*Session" failed: No such file or directory (2) What am I doing wrong?

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  • using sed to replace 1 line with a multi-line variable in ksh

    - by Manda
    I have the following text in a file: XXXX NNNN YYYY NNNN ZZZZ NNNN I want to replace the NNNN to make it look like this: XXXX NNNN DUTY FORECASTER: YYYY NNNN DUTY FORECASTER: ZZZZ NNNN DUTY FORECASTER: How do I use sed to replace a variable with more than one line? Is there a better way of doing this without using sed? I have tried the following to no avail: sed 's/NNNN/"$value1"/g' testfile sed 's/NNNN/'"$value1"'/g' testfile sed 's/NNNN/${value1}/g' testfile sed 's/NNNN/'"${value1}"'/g' testfile I have also tried all of the above using double quotes. Any help is greatly appreciated. Thanks so much!

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  • unix command to verify span of word in text

    - by Ocasta Eshu
    What unix command(s) can I use to determine the line span that a word appears in text? The "span" being equal to the line number of the last instance of a word minus the line number of the first instance of the word. 1| unix is on two lines 2| once above, and once below 3| unix In the example above the "span" of 'unix' would be 2 (3-1). So far I've been trying to make use of grep -n but I don't think that grep is powerful enough. Maybe some use of sed or awk? Thanks!

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  • nginx dynamic servername with regular expression doesn't work for co.uk

    - by redn0x
    I'm trying to setup a nginx server which dynamically loads content from a folder for a domain. To do this I'm using regular expressions in the server name like so: server_name ((?<subdomain>.+)\.)?(?<domain>.+)\.(?<tld>.*); This will create a 3 variables for nginx to use later on, for example when using the following url: test.foo.example.com this will evaluate to: $subdomain = test.foo $domain = example $tld = com The problem arises when the co.uk top-level domain is used. In this case when using the url test.foo.example.co.ukit will evaluate to: $subdomain = test.foo.cedira $domain = co $tld = uk How can I edit the regular expression so that it will also work for co.uk?

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  • How to match a string in URI with regular expression?

    - by forestclown
    In my Apache config httpd.conf, I wish to setup a rule like below SetEnvIfNoCase %{QUERY_STRING} ^.*(getBook+)$ no-gzip dont-vary I am hoping to do no-gzip when my URL looks like http://myurl.fake.com/book/getBook3?id=234 http://myurl.fake.com/book/getBook1?id=xxx I am not sure if I can do that by setting up something like the above in httpd.conf.. The reason I do query string is because the url myurl.fake.com/book/getBook3 was mod_rewrite from myurl.fake.com/index.php?controller=book&action=getBook3 Thanks!

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  • Parsing text files

    - by d03boy
    I encountered a situation tonight where I wanted to parse a text file. I had a very, very long word list that contained English words delimited by lines. I wanted to get rid of every word (or line) that was longer than 7 characters. This would be simple in Linux but I can't seem to find a simple solution in WindowsXP. I tried using Notepad++ regular expression search but that was a huge failure. I tried using the expression .{6,} without finding any matches. I'm really at a loss because I thought this sort of thing would be extremely easy and there would be tons of tools to accomplish a task like this. It seems like Notepad++ supports every other feature in the world except the very basic ones that seem the most obvious. Another one of my goals was to put some code before and after the word on each line. aardvark apple azolio would turn into INSERT INTO Words (word) VALUES ('aardvark'); INSERT INTO Words (word) VALUES ('apple'); INSERT INTO Words (word) VALUES ('azolio'); What suggestions/tools/tips do you have to accomplish tasks similar to this in WindowsXP?

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  • postfix header_checks using regexp proper setup

    - by Philip Rhee
    I just can't seem to figure out why header_checks are not being evaluated. I'm on Ubuntu 12.04, postfix 2.7, dovecote, spamassasin, clamav, amavis. I add following line to /etc/postfix/main.cf : header_checks = regexp:/etc/postfix/header_checks And here is header_checks : /From: .*/ REPLACE From: [email protected] To test out regexp : #postmap -q "From: <werwe>" regexp:/etc/postfix/header_checks which evaluates correctly and give me return output of : REPLACE From: [email protected] However, when I try to send email from commandline or from php webpage, postfix will not replace the From header. I'm stumped.

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  • remove words containing non-alpha characters

    - by dnkb
    Given a text file with space separated string and a tab separated integer, I'd ;like to get rid of all words that have non-alpha characters but keep words consisting of alpha only characters and the tab plus the integer afterwards. My attempts like the ones below didin't yield any good. What I was trying to express is something like: "replace anything within word boundaries that starts and ends with 0 or more whatever and there is at least one :digits: or :punct: in between". sed 's/\b.[:digits::punct:]+.\b//g' sed 's/\b.[^:alpha:]+.\b//g' What am I missing? See sample input data below. Thank you! asdf 754m 563 a2a 754mm 291 754n 463 754 ppp 1409 754pin 4652 pin pin 462 754pins 652 754 ppp 1409 754pin 4652 pi$n pin 462 754/p ins 652 754 pp+p 1409 754 p=in 4652

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  • Use of backreferences in fail2ban filters possible?

    - by Izzy
    From time to time, I see collections of suspect "File not found" errors in my Apache logs, basically using the pattern File does not exist: /var/www/file, referer: http://my.server.com/file In human terms: The file was not found, though it referenced here itself. A clear hacking attempt, as that's hardly possible (and the REQUEST_URIs often enough suggest the same). In my eyes a clear case for fail2ban – if I could get backreferences to work here: failregex = ^%(_apache_error_client)s File does not exist: /var/www(.+), referer: http://.+\1$ (Justin Case: above examples assume the DIRECTORY_ROOT of that webserver being /var/www) I googled for hours, searched the fail2ban wiki up and down – but nowhere I could find a statement concerning backreferences in its filters. Are they not supported, or did I do it the wrong way? Any hints how to make it work (except from "dirty hacks" like first sending the request to another fake url using mod-rewrite, and then catching on that (if anyone is interested, I can elaborate on that approach in an answer), or doing something similar using mod-security)? as an entire log line was requested: [Fri Nov 08 14:57:28 2013] [error] [client 50.67.234.213] File does not exist: /var/www/text/files.htm++++++++++++++++++++++++++Result:+using+proxy+27.34.142.47:9090;+no+post+sending+forms+are+found;, referer: http://www.myserver.com/text/files.htm++++++++++++++++++++++++++Result:+using+proxy+27.34.142.47:9090;+no+post+sending+forms+are+found; (sorry, logs were just switched, so this long candidate was the only one left currently; minor adjustments were made for privacy reasons)

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  • Replacing quotes in a file

    - by Matthijs
    I have a large number of large semicolon-separated data files. All string fields are surrounded by double quotes. In some of the files, there are extra quotes in the string fields, which messes up the subsequent importing of the data for analysis (I'm importing to Stata). This code allows me to see the problematic quotes using gnu-awk: echo '"This";"is";1;"line" of" data";""with";"extra quotes""' | awk 'BEGIN { FPAT = "([^;]+)|(\"[^\"]+\")"}; {for ( i=1 ; i<=NF ; i++ ) if ($i ~ /^"(.*".*)+"$/) {print NR, $i}}' 1 "line" of" data" 1 ""with" 1 "extra quotes"" but I do not know how to replace them. I was thinking of doing the replace manually, but it turns out that there are several hundred matches in some of the files. I know about awk's -sub-, -gsub-, and -match- functions, but I am not sure how to design a search and replace for this specific problem. In the example above, the respective fields should be "This", "is", 1, "line of data", "with", "extra quotes", that is: all semicolons are separators, and all quotes except for the outermost quotes should be removed. Should I may be use -sed-, or is -awk- the right tool? Hope you can help me out! Thanks, Matthijs

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  • rm command and regular expressions via Linux BASH shell

    - by PeanutsMonkey
    I am attempting to use regular expressions to remove set of files however the bash shell returns the message rm: cannot remove `[0-99]+ -': No such file or directory rm: cannot remove `[a-zA-Z': No such file or directory rm: cannot remove `]+.[a-z]+': No such file or directory The command is [0-99]+\ - [a-zA-Z ]+\.[a-z]+ Questions Can I use regular expressions? If yes, how do I use them with commands such as rm, mkdir, etc

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  • Fix YAML syntax highlighting in VIM

    - by Kevin Burke
    The YAML syntax highlighting in Vim 7.3 isn't great. Putting an apostrophe in a line of text triggers quote highlighting even when there's no quote. The same thing happens in other files sometimes too. I've posted a screenshot below. Is there any way to fix this behavior, or is there a different YAML syntax file I can use that won't trigger this behavior? This occurs in both MacVim and Vim in the Terminal. I'm running v7.3. Thanks for your help, Kevin

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  • What regular expression can I use to match an IP address?

    - by jennifer
    With the following grep syntax I want to match all IP address in a file (from a ksh script) grep '[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}' file The problem: It also matches words (IP) that have more then 4 octets: 1.1.1.1.1 or 192.1.1.1.160 How can I match a valid IP and only IP addresses with 4 octets? I can also use Perl – a one line syntax solution, if grep doesn't work.

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  • Indentation-based Folding for TextMate

    - by Craig Walker
    SASS and HAML have indentation-based syntax, much like Python. Blocks of related code have the same number of spaces at the start of a line. Here's some example code: #drawer height: 100% color: #c2c7c4 font: size: 10px .slider overflow: hidden height: 100% .edge background: url('/images/foo') repeat-y .tab margin-top = !drawer_top width: 56px height: 161px display: block I'm using phuibonhoa's SASS bundle, and I'd like to enhance it so that the various sections can fold. For instance, I'd like to fold everything under #drawer, everything under .slider, everything under .edge, etc. The bundle currently includes the following folding code: foldingStartMarker = '/\*|^#|^\*|^\b|^\.'; foldingStopMarker = '\*/|^\s*$'; How can I enhance this to fold similarly-indented blocks?

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  • Mechanism behind user forwarding in ScriptAliasMatch

    - by jolivier
    I am following this tutorial to setup gitolite and at some point the following ScriptAliasMatch is used: ScriptAliasMatch \ "(?x)^/(.*/(HEAD | \ info/refs | \ objects/(info/[^/]+ | \ [0-9a-f]{2}/[0-9a-f]{38} | \ pack/pack-[0-9a-f]{40}\.(pack|idx)) | \ git-(upload|receive)-pack))$" \ /var/www/bin/gitolite-suexec-wrapper.sh/$1 And the target script starts with USER=$1 So I am guessing this is used to forward the user name from apache to the suexec script (which indeed requires it). But I cannot see how this is done. The ScriptAliasMatch documentation makes me think that the /$1 will be replaced by the first matching group of the regexp before it. For me it captures from (?x)^/(.* to ))$ so there is nothing about a user here. My underlying problem is that USER is empty in my script so I get no authorizations in gitolite. I give my username to apache via a basic authentication: <Location /> # Crowd auth AuthType Basic AuthName "Git repositories" ... Require valid-user </Location> defined just under the previous ScriptAliasMatch. So I am really wondering how this is supposed to work and what part of the mechanism I missed so that I don't retrieve the user in my script.

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  • Check if folders exist in Git repository... testing if a sub-string exists in bash with NULL as a separator

    - by Craig Francis
    I have a common git "post-receive" script for several projects, and it needs to perform different actions if an /app/ or /public/ folder exists in the root. Using: FOLDERS=`git ls-tree -d --name-only -z master`; I can see the directory listing, and I would like to use the RegExp support in bash to run something like: if [[ "$FOLDERS" =~ app ]]; then ... fi But that won't work if there was something like an "app lication" folder... I specified the "-z" option in the git "ls-tree" command so I could use the \0 (null) character as a separator, but not sure how to test for that in the bash RegExp. Likewise I know there is support for specifying a particular path in the ls-tree command, and could then pipe that to "wc -l", but I'd have thought it was quicker to get a full directory listing of the root (not recursive) then test for the 2 (or more) folders with the returned output. Possibly related to: http://stackoverflow.com/questions/7938094/git-how-to-check-which-files-exist-and-their-content-in-a-shared-bare-repos

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  • Add constant value to numeric XML attribute

    - by Dave Jarvis
    Background Add a constant value to numbers matched with a regular expression, using vim (gvim). Problem The following regular expression will match width="32": /width="\([0-9]\{2\}\)" Question How do you replace the numeric value of the width attribute with the results from a mathematical expression that uses the attribute's value? For example, I would like to perform the following global replacement: :%s/width="\([0-9]\{2\}\)"/width="\1+10"/g That would produce width="42" for width="32" and width="105" for width="95". Thank you!

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  • Regular Expression to replace part of URL in XML file

    - by Richie086
    I need a regular expression in Notepad++ to search/replace a string. My document (xml) has serveral thousand lines that look similar to this: <Url Source="Output/username/project/Content/Volume1VolumeName/TopicFileName.htm" /> I need to replace everything starting from Volume1 to .htm" / to replaced with X's or some other character to mask the actual file names in this file. So the resulting string would look like this after the search/replace was performed: <Url Source="Output/username/project/Content/Volume1XxxxxxXxxx/XxxxxXxxxXxxx.htm" /> I am working with confidential information that I cannot release to people outside of my company, but i need to send an example log file to a 3rd party for troubleshooting purposes. FYI the X's do not need to follow the upper/lower case after the replacement, i was just using different case X's for the hell of it :)

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  • Word Find - find any highlighted text that starts with a squared bracket

    - by user2953311
    Is there a way to Find highlighted text that ONLY begins with a open square bracket? I've tried using the square bracket as a wildcard, but it won't find any adjoining words. For example, I have a document containing conditional paragraphs, in squared brackets, with the "name" of the paragraph highlighted at the beginning: "[Document to return Thank you for sending the documents requested earlier.]" (the section in bold is highlighted in blue in Word) Is there a way to find "[Document to return"? I hope this makes sense Thanks in advance

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