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  • Creating User Generated Subdomains

    - by nicks451
    Hi there, The company I work for is close to being finished with our first web app and we recently made the decision to offer hosting for our smaller customers. (We provide software to lending companies and our larger customers are required to buy redundant servers to host their application). What we are trying to work out right now is how to create user generated subdomains that will hold a new instance of the software. So a user will be able to sign up and say that the company name is XYZ Credit once they click on the create account button a url of xyzcredit.ourcompanyname.com is created and the user is redirected to it. The servers that we want to use are running CentOS 5.5 and Virtualmin 3.83. Thank you for your help, Nick

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  • Letting the user draw a Polygon Body and Image

    - by Siddharth
    In my game, I want to provide the user with a drawing feature. By free hand drawing, the user creates a polygon shape. Then, in my game implementation, I have to create a body for the found vertices and generate an image based on that polygon shape. My problem is how to create an image that matches the user-provided vertices. I've heard that cocos2d has something called Image Masking. I don't understand how I could implement it in AndEngine. Could someone help?

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  • Printing Tip Handling User Initiated Dialogs Exceptions

    I see this question every so often so it makes sense to share it through a quick post. When using the print API in Silverlight 4 you can run into the dreaded exception: System.Security.SecurityException: Dialogs must be user-initiated Then you examine your code and confirm that your code where you invoke the PrintDocuments Print method are indeed being handled by a user-initiated event. If you are not invoking Print in a user-initiated event then your know your solution :) Here is some sample...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Who created that user?

    - by AaronBertrand
    Twitter has provided some great fodder for blog content lately. And twice this week, I've found an excuse to take advantage of the default trace. Tonight @meltondba asked: I'm trying to find who created a user act in a DB It is true, SQL Server doesn't really keep track of who created objects, such as user accounts in a database. You can get some of this information from the default trace, though, since it tracks EventClass 109 (Audit Add DB User). If you run this code: USE [master] ; GO CREATE LOGIN...(read more)

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  • Reusing OAuth request token when user refresh page - Twitter4j on GAE

    - by Tahir Akram
    Hi I am using Twitter4J API on GAE/J. I want to use the request token when user came to my page. (called back URL). And press refresh button. I write following code for that. But When user press refresh button. I got Authentication credentials error. Please see the stacktrance. It works fine when user first time used that token. HomeServlet.java code: HttpSession session = request.getSession(); twitter.setOAuthConsumer(FFConstants.CONSUMER_KEY, FFConstants.CONSUMER_SECRET); String token = (String) session.getAttribute("token"); String authorizedToken = (String)session.getAttribute("authorizedToken"); User user = null; if (!token.equals(authorizedToken)){ AccessToken accessToken = twitter.getOAuthAccessToken( token, (String) session .getAttribute("tokenSecret")); twitter.setOAuthAccessToken(accessToken); user = twitter.verifyCredentials(); session.setAttribute("authorizedToken", token); session.setAttribute("user", user); }else{ user = (User)session.getAttribute("user"); } TwitterUser twitterUser = new TwitterUser(); twitterUser.setFollowersCount(user.getFollowersCount()); twitterUser.setFriendsCount(user.getFriendsCount()); twitterUser.setFullName(user.getName()); twitterUser.setScreenName(user.getScreenName()); twitterUser.setLocation(user.getLocation()); Please suggest how I can do that. I have seen on many website. They retain the user with the same token. Even if user press browser refresh buttion again and again. Please help. Exception stacktrace: Reason: twitter4j.TwitterException: 401:Authentication credentials were missing or incorrect. /friends/ids.xml This method requires authentication. at twitter4j.http.HttpClient.httpRequest(HttpClient.java:469) at twitter4j.http.HttpClient.get(HttpClient.java:412) at twitter4j.Twitter.get(Twitter.java:276) at twitter4j.Twitter.get(Twitter.java:228) at twitter4j.Twitter.getFriendsIDs(Twitter.java:1819) at com.tff.servlet.HomeServlet.doGet(HomeServlet.java:86) at javax.servlet.http.HttpServlet.service(HttpServlet.java:693) at javax.servlet.http.HttpServlet.service(HttpServlet.java:806) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1093) at com.google.apphosting.utils.servlet.ParseBlobUploadFilter.doFilter(ParseBlobUploadFilter.java:97) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1084) at com.google.apphosting.runtime.jetty.SaveSessionFilter.doFilter(SaveSessionFilter.java:35) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1084) at com.google.apphosting.utils.servlet.TransactionCleanupFilter.doFilter(TransactionCleanupFilter.java:43) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1084) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:360) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:712) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.handle(AppVersionHandlerMap.java:238) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:139) at org.mortbay.jetty.Server.handle(Server.java:313) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:506) at org.mortbay.jetty.HttpConnection$RequestHandler.headerComplete(HttpConnection.java:830) at com.google.apphosting.runtime.jetty.RpcRequestParser.parseAvailable(RpcRequestParser.java:76) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:381) at com.google.apphosting.runtime.jetty.JettyServletEngineAdapter.serviceRequest(JettyServletEngineAdapter.java:135) at com.google.apphosting.runtime.JavaRuntime.handleRequest(JavaRuntime.java:235) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5235) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5233) at com.google.net.rpc.impl.BlockingApplicationHandler.handleRequest(BlockingApplicationHandler.java:24) at com.google.net.rpc.impl.RpcUtil.runRpcInApplication(RpcUtil.java:363) at com.google.net.rpc.impl.Server$2.run(Server.java:838) at com.google.tracing.LocalTraceSpanRunnable.run(LocalTraceSpanRunnable.java:56) at com.google.tracing.LocalTraceSpanBuilder.internalContinueSpan(LocalTraceSpanBuilder.java:536) at com.google.net.rpc.impl.Server.startRpc(Server.java:793) at com.google.net.rpc.impl.Server.processRequest(Server.java:368) at com.google.net.rpc.impl.ServerConnection.messageReceived(ServerConnection.java:448) at com.google.net.rpc.impl.RpcConnection.parseMessages(RpcConnection.java:319) at com.google.net.rpc.impl.RpcConnection.dataReceived(RpcConnection.java:290) at com.google.net.async.Connection.handleReadEvent(Connection.java:466) at com.google.net.async.EventDispatcher.processNetworkEvents(EventDispatcher.java:759) at com.google.net.async.EventDispatcher.internalLoop(EventDispatcher.java:205) at com.google.net.async.EventDispatcher.loop(EventDispatcher.java:101) at com.google.net.rpc.RpcService.runUntilServerShutdown(RpcService.java:251) at com.google.apphosting.runtime.JavaRuntime$RpcRunnable.run(JavaRuntime.java:394) at java.lang.Thread.run(Unknown Source)

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  • FTP User cannot modify files but has correct permissions

    - by Lothar_Grimpsenbacher
    I have created a new user (foo) and when he logs in via ftp he cannot edit the files in the directory to which he has access. In the directory he can log into ls -l gives me: -rw-rw-r-- 1 root www-pub 6427 Nov 17 04:21 index.html The user belongs to the group www-pub. Here is the output of cat /etc/group to demonstrate that he is indeed in that group: ... www-pub:x:1001:ftpuser,www-data,foo foo:x:1002: *edit the permissions on the containing directory are: drwxrwsr-x 5 root www-pub 4096 Nov 17 02:53 thecontainingdir and the one above that: drwxrwsr-x 49 root www-pub 4096 Nov 16 02:40 thenextdirup So since he can log in via ftp and since the file he needs to edit has the correct permissions to let the group www-pub read and write the file and he is a member of that group, why can't he edit it (or upload anything)? Only when I change the file to 777 can he edit it. It's as if he's NOT in the group... but he is! What's going on?

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  • User http does not have write permissions directory?

    - by dwieeb
    I have a bit of an odd set up, I think. I have groups for each domain my server hosts, and I add the user http to each domain group along with the users that should have access to the groups' domains. In my php script running from a directory 'public_html', I try creating a file: <?php $output = ""; print exec('touch test 2>&1', $output); But I get touch: cannot touch `test': Permission denied and the file is not created. But here, clearly stated, the group has all permissions on the directory: drwxrwxr-x 5 dwieeb example.com 1024 Feb 4 05:19 public_html And here are the permissions on the php file in public_html that is trying to use the exec function: -rw-rw-r-- 1 dwieeb example.com 59 Feb 4 05:19 test.php How is this possible if http is part of the example.com group (as seen from a cat on /etc/group) and the directory has full permissions for the group? ... example.com:x:1000:dwieeb,http I'm stumped. EDIT (since apparently I'm not cool enough to answer my own questions yet): Ah, I found the problem. Yes, I restarted Nginx, but the php-fpm daemon must be restarted as well when http is added to the group for my domain. On Arch Linux: rc.d restart php-fpm

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  • Retrieve a user's Exchange database in powershell

    - by Paul
    Hey Everyone, I've scoured the interwebs for a few days now off and on to find this. I am creating a powershell script for email-enabling new user's(Exchange 2007). To give you a little background when we have a new hire, their AD account is created at our off-site helpdesk, but they don't create their email account. I'm trying to automate the process of mail-enabling the user which involves putting them in the same database as an existing user, disable imap pop activesync, and lastly email the requester of the ticket. I would like to just get prompted for the New User's name, User to Replicate(mailbox, storage group, database), and the person to email after it's been created. So if someone could just help with a command to Retrieve a user's Exchange database in powershell that would be great, but if people also want to help with my hacked up script please do so as well!!! Here is what I have so far: Write-output “ENTER THE FOLLOWING DETAILS” $DName = Read-Host “User Diplay Name" $RUser = Read-Host "Replicate User(Database Grab)" ***$RData = #get the Replicate user's mailbox database here*** $REmail = #either just use a Read-Host “Requester's Email address" or ask for Requester's name and pipe through their email address by digging for it w/ powershell Enable-Mailbox -Identity "$DName" -Database "$RData" Send-MailMessage -From "John Doe <[email protected]>" -To (put $REmail here which is the Requester's email) -Subject "Test Person's email account" -Body "Test Person's email account has been setup.`n`n`nJohn Doe`nGeneric Company`nSystems Administrator`nOffice: 123.456.7890`[email protected]" -SmtpServer genericexchange.exchange.com

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  • Does ICS modify windows firewall policies in the registry?

    - by insipid
    I had a host machine I wanted to enable ICS on. First I realized that doing so was not possible until I enabled the Windows Firewall. Once I enabled the firewall and set up ICS, I noticed due to group policy I could no longer disable the firewall. Also, any ports I tried to open seemed to be ignored. Although nothing seemed to be configured when I used the mmc snap-in to view local computer policy, when I checked the registry I noticed several policies set there in HKLM (such as disabling AllowLocalPolicyMerge). I was able to remove the policies from the registry and my open ports worked, but they were eventually re-added without my input. The network I am sharing the internet from is an "unsecured" wireless network with an authentication page, is it possible that this is causing those policies to be set? Did ICS set those policies? When you go to the properties of the ICS enabled adapter and go to the ICS settings it takes you to a tab called services where you can add and remove "services running on your network that internet users can access". Is this related to the windows firewall?

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  • Site Review: Facebook.com and Blockbuster.com - Navigation Schemes

    After cycling through a list of my favorite sites I decided to select Facebook.com and Blockbuster.com for this  post because I found their navigation schemes very intuitive. Facebook in my opinion took a very simplistic and minimalistic approach when they designed their site and its navigation. For example, when you login to your account you will find on the upper left hand side a generic section of the site common areas to all users like news, messages, events, photos and friends. Below this in a separate navigation menu is a list of applications that a user has elected to access through bookmarks. Finally in the upper right hand corner of the site contains links to administer the user’s account like account settings, public profile, and a link back to the users’ home page. Blockbuster on the other had tried to make site navigation a little more slick by using a menu-submenu approach to navigation where user can click on things like Rent, Buy, On Demand, Games, Stores, and Gifts and a submenu of corresponding items appears below the original menu item. In addition they also took this approach and added categorized lists of movies that they offer on the homepage so that users can click on an item like “DVD Spotlight” and a list of movies represented as actual DVD box cases appear on the user’s screen so they can scroll through the list by using left and right arrows on either side of the images displayed. Both Facebook and Blockbuster have more than one navigation groupings because their respected sites are so large and offer an absorbent amount of features. Because of this reason they have to group the main functionality of information in to logical groups based on their actions they perform and the access to specific information. For example it would not make sense for Facebook to include a particular game you like to play within your account with a section pertaining to account administration. The game link would be completely out of place and really confuse the users experience because the groupings where not logically grouped. In addition I think that Facebook users would benefit if Facebook allowed its users to specify what they want on the general navigation from within their site or at least create a section to show frequently accessed pages or favorite sections. Finally regarding additional navigation, I think blockbuster users really benefit from the submenu system of categorizing data, and if fact Blockbuster even allows them to refine the information they are looking for through the use of secondary submenu systems allowing users to really drill down in to what they are looking for to learn more on. I do not think that having more than one navigation bar on a web page is not confusing for the user. For example if you have a navigation bar at the top of your page and at the bottom will allow users to move around the website easier because they can utilize the navigation closest to where their cursor is on the page. In regards to designers forcing all the navigation in to one navigation bar, I think it would be hard for the user to fully understand what is going on based on the size and complexity of the site they are dealing with. For example Blockbuster has a ton of content that could not easily be put in to one navigation bar. From my experience with both Facebook and Blockbuster, they both do a good job with cross browser compatibility. I have had no issues with either site in IE, Firefox, Chrome, and Safari over the years. In addition, I do not believe that either Facebook or Blockbuster require any additional plug-in to utilize their navigation bars.

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  • how can I parse and group/do stats on user agent strings?

    - by user151841
    I have a database that has the various user-agent strings of visitors to our site. I'd like to do a 'survey' of them to see what browsers our users are using, so that I can know what features I can use in future development. Is there a tool to parse and run statistics on user-agent strings, or a bunch of strings like this? Ideally, I'd like to see a hierarchical grouping of the stats. For instance: Opera/9.80 (Windows Mobile; WCE; Opera Mobi/WMD-50301; U; en) Presto/2.4.13 Version/10.00 Opera/9.80 (J2ME/MIDP; Opera Mini/4.2.14912/1280; U; en) Presto/2.2.0 Opera/9.80 (J2ME/MIDP; Opera Mini/4.2.13918/812; U; en) Presto/2.2.0 Opera/9.64 (Macintosh; Intel Mac OS X; U; en) Presto/2.1.1 Opera/9.60 (J2ME/MIDP; Opera Mini/4.2.13918/786; U; en) Presto/2.2.0 Opera/9.60 (J2ME/MIDP; Opera Mini/4.0.10992/432; U; en) Presto/2.2.0 I'd like to see 6 entries for Opera, broken down into 3 for 9.80, 1 for 9.64 and 2 for 9.60, and so forth for all browsers. Other dimensions, such as OS, would cross the boundaries of the browser version hierarchy, but it might be nice to see also.

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  • Task Scheduler Cannot Apply My Changes - Adding a User with Permissions

    - by Aaron
    I can log in to the server using a domain account without administrator privileges and create a task in the Task Scheduler. I am allowed to do an initial save of the task but unable to modify it with the same user account. When changes are complete, a message box prompts for the user password (same domain user I logged in with), then fails with the following message. Task Scheduler cannot apply your changes. The user account is unknown, the password is incorrect, or the account does not have permission to modify the task. When I check Log on as Batch Job Properties (found this from the Help documentation): This policy is accessible by opening the Control Panel, Administrative Tools, and then Local Security Policy. In the Local Security Policy window, click Local Policy, User Rights Assignment, and then Logon as batch job. Everything is grayed out, so I can't add a user. How can I add a user?

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  • SSRS 2008 - How to hide the plus icon in a group visibility toggle cell

    - by Daniel Coffman
    I have a report that shows or hides columns in a group based on a header cell. SSRS makes this pretty easy and is kind enough to place a little plus/minus icon in the toggling cell. I want to HIDE this plus/minus icon when there is only one column of data in the subgroup, because it shows that one column by default so expanding the group doesn't do anything. This really only applies to one specific group, because all the others always have more than one column of data, so a way to hide only the icon for a specific group would be fine. JavaScript won't work (I don't think) because the client ID of the plus/minus image is generated by the report and changes with each generation. see this image for more clarity: http://imgur.com/vqaQA.png

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  • Freeze the indent of a row group in DevExpress GridControl

    - by brader
    I am required to display a DevExpress WinForms GridControl where the rows must be grouped by a date column. When horizontally scrolling the grid, I am required to keep the group row and group indents fixed to the left of the control (so they do not scroll with the columns). I have so far been unable to find any built-in capability for this. There is the ability to fix a column to the left or right side of the control, but the indent is not a true column. FYI, the group row portion is staying "fixed" by handling the drawing of it to always position it at the left. I do not see a way of controlling the drawing of the indent however. Attempts to custom draw an indent have been unsuccessful so far. We are using version 9.3.2.0 of the DevExpress XtraGrid controls for WinForms. Does anyone have any solutions or workarounds that might allow us to at least give the appearance that the group indents are fixed? Thank you!

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  • Any screen capture software that captures webcam, microphone inputs too ?

    - by mohanr
    I am going to conduct a user study. Apart from capturing the screen while the user is interacting with the system, I also want to capture the video/audio of the user. Is there any software that in addition to capturing the screen also overlays it with the webcam/microphone inputs. The goal is to capture the complete experience of the user: key/mouse interactions with the system along with their facial/vocal responses. I know that I can maybe run a screen-capture software and also run a software for capturing webcam audio/video alongside and try to sync/overlay both these streams with timestamps. But I am going to be dealing with probably several hundred hours of data. So I am looking for a tool that can streamline the process for me amap and help me keep my sanity at end of the process. Thanks,

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  • Cannot create file in directory even though it's writable by a group I belong to

    - by Alan Berndt
    I have a directory structure owned by a certain group, and I am a member of the group that owns these directories. I am able to create files in one directory, but not in another, even though the permissions are the same. alan@bricky:/mnt/storage/media$ stat Music Music\ \(Lossy\)/ File: `Music' Size: 34 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 4215424 Links: 3 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.182586898 -0700 Modify: 2011-08-19 11:44:01.412840027 -0700 Change: 2011-08-19 11:45:02.734603240 -0700 File: `Music (Lossy)/' Size: 6 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 1512056832 Links: 2 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.190586606 -0700 Modify: 2011-08-19 10:34:46.526530313 -0700 Change: 2011-08-19 11:45:02.738603094 -0700 alan@bricky:/mnt/storage/media$ touch Music/test alan@bricky:/mnt/storage/media$ touch Music\ \(Lossy\)/test touch: cannot touch `Music (Lossy)/test': Permission denied

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  • Centos Xen resizing DomU partition and volume group

    - by thepearson
    I have a setup like so: Dom0 LV | DomU Physical Disk | | XVDA1 XVDA2 (/boot) (DomU PV) | VolGroup00 (DomU VG) | | LogVol00 LogVol01 (swap) (/) I am trying to resize the DomU root Filesystem. (VolGroup00-LogVol01) I realize that I now need to resize the partition XVDA2, however when I try doing this with parted on Dom0 it just tells me "Error: Could not detect file system." So to resize the root part VolGroup-LogVol00 shouldn't the process be: # Shut down DomU xm shutdown domU #Resize Dom0 Logical volume lvextend -L+2G /dev/volumes/domU-vol # Parted parted /dev/volumes/domU-vol # Resize root partition resize 2 START END (This is where I get an error) "Error: Could not detect file system." # add the vm volume group to Dom0 lvm kpartx -a /dev/volumes/domU-vol # resize the domU PV pvresize /dev/mapper/domU-pl (as listed in pvdisplay) # The domU volume group should automatically adjust # resize the DomU lv lvextend -L+2G /dev/VolGroup/LogVol00 And then obviously increase the fs, remove the device from kpartx etc The problem is I dont know how to resize the partition? How do I resize this partition so I can run pvresize on the DomU? Thanks

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  • VSFTP Users and Directories

    - by Mathew
    I'm stuck. I've been working all day on trying to figure out what I'm doing wrong and I've hit wall after wall. What I'm trying to do: Setup FTP in such a way that certain users have access only to their directory, but higher level users have access to all directories. What I've Googled so far: I started with this, but that didn't do what I needed it to. I then used this, but once I created one user, it wouldn't let me create another one. Finally, I decided to follow this, but it wouldn't let me even create one user. I'm using Ubuntu 10. I can login to ftp as a root user and it takes me to the home directory. If I try to login using the user I created in the tutorial it says: Status: Connection established, waiting for welcome message... Response: 220 (vsFTPd 2.2.2) Command: USER mathew Response: 331 Please specify the password. Command: PASS **** Response: 530 Login incorrect. Error: Critical error Error: Could not connect to server

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  • Why is user asked to choose their workgroup?

    - by Clinton Blackmore
    We running Mac OS X Server 10.5.8 with Mac OS X 10.5.8 clients. Students use network logins to, well, log in. I've been asked to deny internet access to a specific user. I was told that a good way to do it is to create a user workgroup called "No Internet Access" and manage settings there. (Specifically, I told parental controls to allow access to no sites, and blacklisted all the installed web browsers). Now, when the user authenticates to log in, they are greeted with this dialog: Workgroups for <username> Grade 7 Students No Internet Access It is unlikely that the student would willing choose "No Internet Access" to be their base group. Looking in Workgroup Manager at the student's record, it shows their primary group ID is the grade 7 group, and "No Internet Access" is listed as another group they belong to. I looked at the managed preferences for all the computers pertaining to logins. They are set to their defaults. Specifically, the computer groups' preference for Logins - Access has the defaults: [unchecked] Ignore workgroup nesting [checked] Combine available workgroup settings Based on my reading of Tips and Tricks for Mac Administrators, this should be correct, the user should not be asked which group they belong to, and settings from all applicable groups should be applied. How can I achieve that result? Edit: I've decided to add some additional information from the Tips and Tricks for Mac Management White Paper (via Apple in Education, via the author's site). On page 21, it says: With Leopard MCX, workgroup preference settings are combined by default into a single set of values. This means that instead of having to choose between the Math, Science, or Language Arts workgroups when logging in, a user can just authenticate and be taken directly to the desktop. All the settings for each of those workgroups are composited together, providing you with all the Dock items and a composite of all the other settings. On page 40, an example is given in which settings are combined from different 'domains', one computer group, two (user) workgroups, and one individual user's settings. [When johnd logs into a leopard client,] the items staged in the Dock from left to right are: computer group, first workgroup alphabetically, second workgroup, user. Items within the workgroup are staged alphabetically. Nowhere is there an indication that groups are nested; indeed, I can see no sensible (non-flat) heirarchy for groups like Math, Science, and Language Arts. I strongly believe that there is a way to apply settings from two unrelated user workgroups such that a user of OS X 10.5.x or newer does not need to choose their workgroup. This is what I seek to achieve.

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  • sql group by with left join

    - by cometta
    fail statement:Error: ORA-00979: not a GROUP BY expression select org_division.name , org_department.name , org_surveylog.division_code as divisionCode,org_surveylog.department_code as departmentCode , max(org_surveylog.actiondate) from org_surveylog left join org_division on (org_surveylog.division_code= org_division.division_code and org_surveylog.SURVEY_NUM= org_division.survey_num) left join org_department on (org_surveylog.department_code = org_department.department_code and org_surveylog.SURVEY_NUM = org_department.survey_num) group by org_surveylog.division_code,org_surveylog.department_code but below is ok select org_surveylog.division_code as divisionCode,org_surveylog.department_code as departmentCode , max(org_surveylog.actiondate) from org_surveylog left join org_division on (org_surveylog.division_code= org_division.division_code and org_surveylog.SURVEY_NUM= org_division.survey_num) left join org_department on (org_surveylog.department_code = org_department.department_code and org_surveylog.SURVEY_NUM = org_department.survey_num) group by org_surveylog.division_code,org_surveylog.department_code how to use group by with left join when i need to show value of org_division.name , org_department.name ?

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  • Configure Nagios To Alert Depending On Host Group That Service Alert Originates From

    - by StrangeWill
    So my setup: Services are shared between all hosts (CPU/RAM/Disk/Services). Hosts are split into two main groups: "Production" and "Development". We have two contact groups: "Production" and "Development". Lets say my development SQL server runs low on RAM, I want it to only alert those in "Development" contact group (this service is of course assigned to a host in the "Development" host group, using the shared RAM monitoring service). I'm pretty much stumped on this... I can't configure it at the service level (they're shared there), and I can't seem to get escalations to do it for me either... Do I need to use service groups along with escalations and bite the bullet on building that list? Or am I missing something stupidly simple? I'm using Centreon for configuration if that helps.

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  • "Fast link detected" warning in GP management console

    - by ???????? ??????
    There is a message that is shown in every report i make in Group Policy Results section of Group Policy Management Console, saying that "A fast link is detected". I followed the link in the waring, but after I read the page several times, I concluded, that I can ignore the warning. However, I noticed that the group policies are not applied when security filtering is used untl "gpupdate /sync" is executed... Is this related to the fast sync? In general, can somebody explain me the consequences of fast links briefly?

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  • I can't make this query work with SUM function

    - by Mehper C. Palavuzlar
    This query gives an error: select ep, case when ob is null and b2b_ob is null then 'a' when ob is not null or b2b_ob is not null then 'b' else null end as type, sum(b2b_d + b2b_t - b2b_i) as sales from table where ... group by ep, type Error: ORA-00904: "TYPE": invalid identifier When I run it with group by ep, the error message becomes: ORA-00979: not a GROUP BY expression The whole query works OK if I remove the lines sum(b2b_d+b2b_t-b2b_i) as sales and group by ..., so the problem should be related to SUM and GROUP BY functions. How can I make this work? Thanks in advance for your help.

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  • How to make multiple segmented inputs in a single input group in Bootstrap

    - by metaculus
    This is how it is supposed to look like on Airbnb home page http://airbnb.com I have tried .input-group-addon and nest in it another <input> like so: <div class="col-lg-6"> <div class="input-group"> <input type="text" class="form-control"> <span class="input-group-addon"> <input type="text" id="nested-input" class="form-control"> </span> <span class="input-group-btn"> <button class="btn btn-default" type="button">Go!</button> </span> </div> </div> </div> And it didn't work. Does Bootstrap support this styling?

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  • best way to store 1:1 user relationships in relational database

    - by aharon
    What is the best way to store user relationships, e.g. friendships, that must be bidirectional (you're my friend, thus I'm your friend) in a rel. database, e.g. MYSql? I can think of two ways: Everytime a user friends another user, I'd add two rows to a database, row A consisting of the user id of the innitiating user followed by the UID of the accepting user in the next column. Row B would be the reverse. You'd only add one row, UID(initiating user) followed by UID(accepting user); and then just search through both columns when trying to figure out whether user 1 is a friend of user 2. Surely there is something better?

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