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  • fit a ellipse in Python given a set of points xi=(xi,yi)

    - by Gianni
    I am computing a series of index from a 2D points (x,y). One index is the ratio between minor and major axis. To fit the ellipse i am using the following post when i run these function the final results looks strange because the center and the axis length are not in scale with the 2D points center = [ 560415.53298363+0.j 6368878.84576771+0.j] angle of rotation = (-0.0528033467597-5.55111512313e-17j) axes = [0.00000000-557.21553487j 6817.76933256 +0.j] thanks in advance for help import numpy as np from numpy.linalg import eig, inv def fitEllipse(x,y): x = x[:,np.newaxis] y = y[:,np.newaxis] D = np.hstack((x*x, x*y, y*y, x, y, np.ones_like(x))) S = np.dot(D.T,D) C = np.zeros([6,6]) C[0,2] = C[2,0] = 2; C[1,1] = -1 E, V = eig(np.dot(inv(S), C)) n = np.argmax(np.abs(E)) a = V[:,n] return a def ellipse_center(a): b,c,d,f,g,a = a[1]/2, a[2], a[3]/2, a[4]/2, a[5], a[0] num = b*b-a*c x0=(c*d-b*f)/num y0=(a*f-b*d)/num return np.array([x0,y0]) def ellipse_angle_of_rotation( a ): b,c,d,f,g,a = a[1]/2, a[2], a[3]/2, a[4]/2, a[5], a[0] return 0.5*np.arctan(2*b/(a-c)) def ellipse_axis_length( a ): b,c,d,f,g,a = a[1]/2, a[2], a[3]/2, a[4]/2, a[5], a[0] up = 2*(a*f*f+c*d*d+g*b*b-2*b*d*f-a*c*g) down1=(b*b-a*c)*( (c-a)*np.sqrt(1+4*b*b/((a-c)*(a-c)))-(c+a)) down2=(b*b-a*c)*( (a-c)*np.sqrt(1+4*b*b/((a-c)*(a-c)))-(c+a)) res1=np.sqrt(up/down1) res2=np.sqrt(up/down2) return np.array([res1, res2]) if __name__ == '__main__': points = [(560036.4495758876, 6362071.890493258), (560036.4495758876, 6362070.890493258), (560036.9495758876, 6362070.890493258), (560036.9495758876, 6362070.390493258), (560037.4495758876, 6362070.390493258), (560037.4495758876, 6362064.890493258), (560036.4495758876, 6362064.890493258), (560036.4495758876, 6362063.390493258), (560035.4495758876, 6362063.390493258), (560035.4495758876, 6362062.390493258), (560034.9495758876, 6362062.390493258), (560034.9495758876, 6362061.390493258), (560032.9495758876, 6362061.390493258), (560032.9495758876, 6362061.890493258), (560030.4495758876, 6362061.890493258), (560030.4495758876, 6362061.390493258), (560029.9495758876, 6362061.390493258), (560029.9495758876, 6362060.390493258), (560029.4495758876, 6362060.390493258), (560029.4495758876, 6362059.890493258), (560028.9495758876, 6362059.890493258), (560028.9495758876, 6362059.390493258), (560028.4495758876, 6362059.390493258), (560028.4495758876, 6362058.890493258), (560027.4495758876, 6362058.890493258), (560027.4495758876, 6362058.390493258), (560026.9495758876, 6362058.390493258), (560026.9495758876, 6362057.890493258), (560025.4495758876, 6362057.890493258), (560025.4495758876, 6362057.390493258), (560023.4495758876, 6362057.390493258), (560023.4495758876, 6362060.390493258), (560023.9495758876, 6362060.390493258), (560023.9495758876, 6362061.890493258), (560024.4495758876, 6362061.890493258), (560024.4495758876, 6362063.390493258), (560024.9495758876, 6362063.390493258), (560024.9495758876, 6362064.390493258), (560025.4495758876, 6362064.390493258), (560025.4495758876, 6362065.390493258), (560025.9495758876, 6362065.390493258), (560025.9495758876, 6362065.890493258), (560026.4495758876, 6362065.890493258), (560026.4495758876, 6362066.890493258), (560026.9495758876, 6362066.890493258), (560026.9495758876, 6362068.390493258), (560027.4495758876, 6362068.390493258), (560027.4495758876, 6362068.890493258), (560027.9495758876, 6362068.890493258), (560027.9495758876, 6362069.390493258), (560028.4495758876, 6362069.390493258), (560028.4495758876, 6362069.890493258), (560033.4495758876, 6362069.890493258), (560033.4495758876, 6362070.390493258), (560033.9495758876, 6362070.390493258), (560033.9495758876, 6362070.890493258), (560034.4495758876, 6362070.890493258), (560034.4495758876, 6362071.390493258), (560034.9495758876, 6362071.390493258), (560034.9495758876, 6362071.890493258), (560036.4495758876, 6362071.890493258)] a_points = np.array(points) x = a_points[:, 0] y = a_points[:, 1] from pylab import * plot(x,y) show() a = fitEllipse(x,y) center = ellipse_center(a) phi = ellipse_angle_of_rotation(a) axes = ellipse_axis_length(a) print "center = ", center print "angle of rotation = ", phi print "axes = ", axes from pylab import * plot(x,y) plot(center[0:1],center[1:], color = 'red') show() each vertex is a xi,y,i point plot of 2D point and center of fit ellipse

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  • Checkstyle for Python

    - by oneself
    Is there an application similar to Java's Checkstyle for Python? By which I mean, I tool that analyzes Python code, and can be run as part of continuous integration (e.g. CruiseControl or Hudson). After analyzing it should produce an online accessible report which outlines any problems found in the code. Thank you,

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  • Python Macros: Use Cases?

    - by Rick Copeland
    If Python had a macro facility similar to Lisp/Scheme (something like MetaPython), how would you use it? If you are a Lisp/Scheme programmer, what sorts of things do you use macros for (other than things that have a clear syntactic parallel in Python such as a while loop)?

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  • Lua parser in python

    - by Joe Simpson
    Hi, I'm looking into using Lua in a web project. I can't seem to find any way of directly parsing in pure python and running Lua code in Python. Does anyone know how to do this? Joe

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  • Embed bash in python

    - by Werner
    Hi, I am writting a python script and I am running out of time. I need to so some things that I know pretty well in bash, so I just wonder how can I embed some bash lines into a python script. Thanks

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  • efficient list mapping in python

    - by Joey
    Hi everyone, I have the following input: input = [(dog, dog, cat, mouse), (cat, ruby, python, mouse)] and trying to have the following output: outputlist = [[0, 0, 1, 2], [1, 3, 4, 2]] outputmapping = {0:dog, 1:cat, 2:mouse, 3:ruby, 4:python, 5:mouse} Any tips on how to handle given with scalability in mind (var input can get really large).

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  • Getting monitor size in python

    - by None
    I am using python and want to create a fullscreen window. I know about the pygame.FULLSCREEN flag but when I use that there's areas of black around the screen. Is there any way to get the monitor size using python so I can make the window the correct size?

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  • Strange Syntax Parsing Error in Python?

    - by user213060
    Am I missing something here? Why shouldn't the code under the "Broken" section work? I'm using Python 2.6. #!/usr/bin/env python def func(a,b,c): print a,b,c #Working: p={'c':3} func(1, b=2, c=3, ) #Working: func(1, b=2, **p,) #Broken: func(1, b=2, **p, )

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  • Python IDE on Linux Console

    - by Henrik P. Hessel
    This may sound strange, but I need a better way to build python scripts than opening a file with nano/vi, change something, quit the editor, and type in python script.py, over and over again. I need to build the script on a webserver without any gui. Any ideas how can I improve my workflow?

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  • Python Script to backup a directory

    - by rgolwalkar
    Filename:backup_ver1 import os import time 1 Using list to specify the files and directory to be backed up source = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\Dr Py\Final_Py' 2 define backup directory destination = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\PyDevResourse' 3 Setting the backup name targetBackup = destination + time.strftime('%Y%m%d%H%M%S') + '.rar' rar_command = "rar.exe a -ag '%s' %s" % (targetBackup, ''.join(source)) i am sure i am doing something wrong here - rar command please let me know if os.system(rar_command) == 0: print 'Successful backup to', targetBackup else: print 'Backup FAILED' O/P:- Backup FAILED winrar is added to Path and CLASSPATH under Environment variables as well - anyone else with a suggestion for backing up the directory is most welcome

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  • Modify an XML file in Python

    - by michele
    Hi, I have two file. I have to modify the file one in a particular node and add in a list of child. The list is in the file2. Can I do it, and how? from xml.dom.minidom import Document from xml.dom import minidom file1=modificare.xml file2=sorgente.xml xmldoc=minidom.parse(file1) for Node in xmldoc.getElementsByTagName("Sampler"): # put in the file2 content Thanks a lot.

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  • Memory efficient int-int dict in Python

    - by Bolo
    Hi, I need a memory efficient int-int dict in Python that would support the following operations in O(log n) time: d[k] = v # replace if present v = d[k] # None or a negative number if not present I need to hold ~250M pairs, so it really has to be tight. Do you happen to know a suitable implementation (Python 2.7)? EDIT Removed impossible requirement and other nonsense. Thanks, Craig and Kylotan! To rephrase. Here's a trivial int-int dictionary with 1M pairs: >>> import random, sys >>> from guppy import hpy >>> h = hpy() >>> h.setrelheap() >>> d = {} >>> for _ in xrange(1000000): ... d[random.randint(0, sys.maxint)] = random.randint(0, sys.maxint) ... >>> h.heap() Partition of a set of 1999530 objects. Total size = 49161112 bytes. Index Count % Size % Cumulative % Kind (class / dict of class) 0 1 0 25165960 51 25165960 51 dict (no owner) 1 1999521 100 23994252 49 49160212 100 int On average, a pair of integers uses 49 bytes. Here's an array of 2M integers: >>> import array, random, sys >>> from guppy import hpy >>> h = hpy() >>> h.setrelheap() >>> a = array.array('i') >>> for _ in xrange(2000000): ... a.append(random.randint(0, sys.maxint)) ... >>> h.heap() Partition of a set of 14 objects. Total size = 8001108 bytes. Index Count % Size % Cumulative % Kind (class / dict of class) 0 1 7 8000028 100 8000028 100 array.array On average, a pair of integers uses 8 bytes. I accept that 8 bytes/pair in a dictionary is rather hard to achieve in general. Rephrased question: is there a memory-efficient implementation of int-int dictionary that uses considerably less than 49 bytes/pair?

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  • Schedule Python Script - Windows 7

    - by Btibert3
    Hi Everyone, I am really new to Python, and programming in general, but I have a python script I would like to run at regular intervals. I am running windows 7. What is the best way to accomplish this? Easiest way? Any help you can provide will be very much appreciated! Brock

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