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• How do I do a grouping by year?

  - by kibyegn

  I have a books model with a date type column named publish_date. On my views I'm iterating through the books and I want to group the books by year such that I have a heading for every year and books that were published on that year to be listed below the year heading. So by starting with "2010" all books published on 2010 would be listed, then another heading "2009" with all books published in 2009 listed below it and so forth. <% @all_books.each do |book| %> <%=link_to book.title + ", (PDF, " + get_file_size(book.size) + ")" %> <% end %> By doing a book.publish_date.strftime("%Y") I am able to get the year but I do not know how to group the entries by year. Any help on this would be appreciated.

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• I would like to filter XSL output based on a Radio button selection

  - by Phil Speth

  Here is my example I am trying to filter by year based on user selection: I assume some js or jQuery code would be needed: XML file: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque3</title> <artist>Bob Dylan</artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> </cd> <cd> <title>Hide your heart</title> <artist>Bonnie Tyler</artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> <cd> <title>Greatest Hits</title> <artist>Dolly Parton</artist> <country>USA</country> <company>RCA</company> <price>9.90</price> <year>1982</year> </cd> <cd> <title>Still got the blues</title> <artist>Gary Moore</artist> <country>UK</country> <company>Virgin records</company> <price>10.20</price> <year>1990</year> </cd> <cd> <title>Eros</title> <artist>Eros Ramazzotti</artist> <country>EU</country> <company>BMG</company> <price>9.90</price> <year>1997</year> </cd> <cd> <title>One night only</title> <artist>Bee Gees</artist> <country>UK</country> <company>Polydor</company> <price>10.90</price> <year>1998</year> </cd> <cd> <title>Sylvias Mother</title> <artist>Dr.Hook</artist> <country>UK</country> <company>CBS</company> <price>8.10</price> <year>1973</year> </cd> <cd> <title>Maggie May</title> <artist>Rod Stewart</artist> <country>UK</country> <company>Pickwick</company> <price>8.50</price> <year>1990</year> </cd> <cd> <title>Romanza</title> <artist>Andrea Bocelli</artist> <country>EU</country> <company>Polydor</company> <price>10.80</price> <year>1996</year> </cd> <cd> <title>When a man loves a woman</title> <artist>Percy Sledge</artist> <country>USA</country> <company>Atlantic</company> <price>8.70</price> <year>1987</year> </cd> <cd> <title>Black angel</title> <artist>Savage Rose</artist> <country>EU</country> <company>Mega</company> <price>10.90</price> <year>1995</year> </cd> <cd> <title>1999 Grammy Nominees</title> <artist>Many</artist> <country>USA</country> <company>Grammy</company> <price>10.20</price> <year>1999</year> </cd> <cd> <title>For the good times</title> <artist>Kenny Rogers</artist> <country>UK</country> <company>Mucik Master</company> <price>8.70</price> <year>1995</year> </cd> <cd> <title>Big Willie style</title> <artist>Will Smith</artist> <country>USA</country> <company>Columbia</company> <price>9.90</price> <year>1997</year> </cd> <cd> <title>Tupelo Honey</title> <artist>Van Morrison</artist> <country>UK</country> <company>Polydor</company> <price>8.20</price> <year>1971</year> </cd> <cd> <title>Soulsville</title> <artist>Jorn Hoel</artist> <country>Norway</country> <company>WEA</company> <price>7.90</price> <year>1996</year> </cd> <cd> <title>The very best of</title> <artist>Cat Stevens</artist> <country>UK</country> <company>Island</company> <price>8.90</price> <year>1990</year> </cd> <cd> <title>Stop</title> <artist>Sam Brown</artist> <country>UK</country> <company>A and M</company> <price>8.90</price> <year>1988</year> </cd> <cd> <title>Bridge of Spies</title> <artist>T`Pau</artist> <country>UK</country> <company>Siren</company> <price>7.90</price> <year>1987</year> </cd> <cd> <title>Private Dancer</title> <artist>Tina Turner</artist> <country>UK</country> <company>Capitol</company> <price>8.90</price> <year>1983</year> </cd> <cd> <title>Midt om natten</title> <artist>Kim Larsen</artist> <country>EU</country> <company>Medley</company> <price>7.80</price> <year>1983</year> </cd> <cd> <title>Pavarotti Gala Concert</title> <artist>Luciano Pavarotti</artist> <country>UK</country> <company>DECCA</company> <price>9.90</price> <year>1991</year> </cd> <cd> <title>The dock of the bay</title> <artist>Otis Redding</artist> <country>USA</country> <company>Atlantic</company> <price>7.90</price> <year>1987</year> </cd> <cd> <title>Picture book</title> <artist>Simply Red</artist> <country>EU</country> <company>Elektra</company> <price>7.20</price> <year>1985</year> </cd> <cd> <title>Red</title> <artist>The Communards</artist> <country>UK</country> <company>London</company> <price>7.80</price> <year>1987</year> </cd> <cd> <title>Unchain my heart</title> <artist>Joe Cocker</artist> <country>USA</country> <company>EMI</company> <price>8.20</price> <year>1987</year> </cd> </catalog> XSL File: <?xml version="1.0" encoding="ISO-8859-1"?> <!-- Edited by XMLSpy® --> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <input type="radio" name="Cost" value="1980" checked="checked" /> 1980 <input type="radio" name="Cost" value="1990" /> 1990 <h2>My CD Collection</h2> <table border="1"> <tr bgcolor="#9acd32"> <th>Title</th> <th>Artist</th> </tr> <xsl:for-each select="catalog/cd"> <xsl:if test="year>1990"> <tr> <td><xsl:value-of select="title"/></td> <td><xsl:value-of select="artist"/></td> <td><xsl:value-of select="year"/></td> </tr> </xsl:if> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet>

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• Ordering of month/year pairs in T-SQL query

  - by Surya sasidhar

  I am writing a stored procedure for displaying month and year. It is working, but it is not returning the rows in the desired order. ALTER procedure [dbo].[audioblog_getarchivedates] as begin select DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) as ArchiveDate from audio_blog a group by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) order by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) desc end Results will come like this: March 2010 January 2010 February 2010 But that is not in a order (desc).

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• hi how restrict the year in jquery datepicker?

  - by udaya

  Hi I am using jquery.datePicker.js js file to create a date picker This is whati have in my view page <input type="text" style="font-family: verdana; width: 80px;" id="txtArrivalDate" class="startDate" name="txtArrivalDate" value="<?php echo $_POST['txtArrivalDate'] ?>" /> when i click on the arrival date text box the year column starts on current year say 2010 but the years less than 2010 also available on the year select box how to get rid of the years below current year

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• Generate a list of file names based on month and year arithmetic

  - by MacUsers

  How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here? Update: I think, I better upload the entire script for better understanding. #!/usr/bin/env python import os, sys from time import strftime from calendar import month_abbr vGroup = {} vo = "group_lhcb" SI00_fig = float(2.478) months = tuple(month_abbr) print "\n%-12s\t%10s\t%8s\t%10s" % ('VOs','CPU-time','CPU-time','kSI2K-hrs') print "%-12s\t%10s\t%8s\t%10s" % ('','(in Sec)','(in Hrs)','(*2.478)') print "=" * 58 for inFile in os.listdir('.'): if inFile.isdigit(): readFile = open(inFile, 'r') lines = readFile.readlines() readFile.close() month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) for line in lines[2:]: if line.find(vo)==0: g, i = line.split() s = vGroup.get(g, 0) vGroup[g] = s + int(i) sumHrs = ((vGroup[g]/60)/60) sumSi2k = sumHrs*SI00_fig print "%-12s\t%10s\t%8s\t%10.2f" % (mnYear,vGroup[g],sumHrs,sumSi2k) del vGroup[g] When I run the script, I get this: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ================================================== Jan, 2011 211201372 58667 145376.83 Dec, 2010 5064337 1406 3484.07 Feb, 2011 17506049 4862 12048.04 Sep, 2010 210874275 58576 145151.33 As I said in the original post, I like the result to be in this order instead: Sep, 2010 210874275 58576 145151.33 Dec, 2010 5064337 1406 3484.07 Jan, 2011 211201372 58667 145376.83 Feb, 2011 17506049 4862 12048.04 The files in the source directory reads like this: [root@serv07 usage]# ls -l total 3632 -rw-r--r-- 1 root root 1144972 Feb 9 19:23 01 -rw-r--r-- 1 root root 556630 Feb 13 09:11 02 -rw-r--r-- 1 root root 443782 Feb 11 17:23 02.bak -rw-r--r-- 1 root root 1144556 Feb 14 09:30 09 -rw-r--r-- 1 root root 370822 Feb 9 19:24 12 Did I give a better picture now? Sorry for not being very clear in the first place. Cheers!! Update @Mark Ransom This is the result from Mark's suggestion: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ========================================================== Dec, 2010 5064337 1406 3484.07 Sep, 2010 210874275 58576 145151.33 Feb, 2011 17506049 4862 12048.04 Jan, 2011 211201372 58667 145376.83 As I said before, I'm looking for the result to b printed in this order: Sep, 2010 - Dec, 2010 - Jan, 2011 - Feb, 2011 Cheers!!

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• Calculate average gas prices by year in excel

  - by ghostryder111

  I have 3 columns, A=Date, B=Price, C=Grade in Excel. I want to calculate the average price of fuel for each year and an overall average of all years by grade. The data table looks like this Date | Price | Grade 2012-05-01 | $3.49 | Regular 2012-06-07 | $3.58 | Regular 2012-04-01 | $3.98 | Premium 2012-02-17 | $3.87 | Premium 2013-01-01 | $3.49 | Regular 2013-02-01 | $3.89 | Premium 2013-03-06 | $3.89 | Premium 2013-03-09 | $3.45 | Regular The output should look something like this: Year | Regular | Premium 2012 | 3.43 | 3.67 2013 | 3.45 | 3.73 All | 3.44 | 3.70

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• PHP regex to match sentences that contain a year

  - by zen

  I need a regular expression that will extract sentences from text that contain a year in them. Example text: Next, in 1988 the Bradys were back again for a holiday celebration, "A Very Brady Christmas". Susan Olsen (Cindy) would be missing from this reunion, Jennifer Runyon took her place. This was a two hour movie in which the Bradys got together to celebrate Christmas, introducing the world to the spouses and children of the Brady kids. This movie was the highest rated TV-movie of 1988. If the example text was variable $string, I need it to return: $sentenceWithYear[0] = Next, in 1988 the Bradys were back again for a holiday celebration, "A Very Brady Christmas". $sentenceWithYear[1] = This movie was the highest rated TV-movie of 1988. If it's possible to retain the year via regex, I'd use the year within the sentence and eventually insert the sentences into a database like: INSERT INTO table_name (year, sentence) VALUES ('$year', '$sentenceWithYear[x]')

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• Storing year/make/model in a database?

  - by Mark

  Here's what I'm thinking (excuse the Django format): class VehicleMake(Model): name = CharField(max_length=50) class VehicleModel(Model): make = ForeignKey(VehicleMake) name = CharField(max_length=50) class VehicleYear(Model): model = ForeignKey(VehicleModel) year = PositiveIntegerField() This is going to be used in those contingent drop-down select boxes, which would visually be laid out like [- Year -][- Make -][- Model -]. So, to query the data I need I would first have to select all distinct years from the years table, sorted descending. Then I'd find all the vehicle makes that have produced a model in that year. And then all the models by that make in that year. Is this a good way to do it, or should I re-arrange the foreign keys somehow? Or use a many-to-many table for the years/models so that no year is repeated?

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• 5 year old server upgrade

  - by rizzo0917

  I am looking to upgrade a server for a web app. Currently the application is running very sluggish. We've made some adjustments to mysql (that's another issue in itself) and made some adjustments so that heaviest quires get run on a copy of the database on another server was have as a backup, however this will not last that much longer and we are looking to upgrade. Currently the servers CPUs are (4) Intel(R) XEON(TM) CPU 2.00GHz, with 1 gig of ram. The database is 442.5 MiB, with about 1,743,808 records. There are two parts of the program, the one, side a, inserts and updates most of the data. Side b, reads the data and does some minor updates. Currently our biggest day for side a are 800 users (of 40,000 users all year) imputing the system. And our Side b is currently unknown, however we have a total of 1000 clients. The system is most likely going to cap out at 5000 side b clients, with about a year 300,000 side a users. The current database is 5 years old, so we can most likely expect the database to grow pretty rapidly, possibly double each year (which we can most likely archive older records if it comes to that). So with that being said, should we get a server for each side of the app, side a being the master, side b being the slave, any updates made on side b are router to side a. So the question is should i get 2 of these or 1. 2 x Intel Nehalem Xeon E5520 2.26Ghz (8 Cores) 12GB DDRIII Memory 500GB SATAII HDD 100Mbps Port Speed And Naturally I would need to have a redundant backup so it could potentially be 4 of them.

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• How to avoid code duplication for a system which has logic that may change year wise?

  - by aravind

  What would be the way to design a system which has logic that may change year wise? There is an application which conducts online exams. There are five questions for a particular subject. The questions may (or may not) change year wise. As per my current design, the questions in database are stored year wise. There are some year specific code logic as well. In order to enable the application for another year, the year specific database records and code will be copied or duplicated. How to avoid this code duplication?

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• 2nd Year College - Learning - Microsoft Server Products

  - by Ryan

  As the title says, I just finished my first year of college (majoring in Software Engineering). Fortunately my school likes Microsoft enough, and I can get pretty much anything I want that Microsoft sells. I also can get IBM Websphere and the like for free as well. Earlier this year, I set up an oldish computer (2.6 Pentium D, x64) to run ubuntu server headless. I'm predominately a Java developer, so Apache, Maven, Nexus, Sonar, SVN, etc made it onto the machine. It worked really well for personal and school projects, especially team projects (quick ramp up). Anyways, I started to pick up C# to complement my Java knowledge (don't judge me :P), and am interested in working with some of the associated Microsoft equivalents. The machine currently has the Ubuntu install, as well as Windows 7 Ultimate. I do all of my actual development work off my laptop, also running Windows 7 Ultimate. I was wondering what software you would recommend putting on the machine. I’m not actually serving anything off the machine itself, but in Ubuntu I had it doing integration tests with Hudson on every commit, and profiling my applications, etc, etc. The machine would be running headless, and I would remote into it. Here is what I am currently leaning towards / wondering about: Windows 7 Ultimate vs Windows Server 2008 (R2) (no one is really clear why I should go with one over the other) Windows Team Foundation Sharepoint (Never used it before, kind of meh about it) IBM Websphere or Glassfish (Some Java EE web server) SQL Server 2008 A DVCS In order to better control product conflicts / limit resource use, I’m wondering if I should install things into virtual machines (I can get VmWare or Microsoft Virtualization Products) I also plan on installing everything I had running under Linux (it’s almost entirely Java based development software, so it’ll run on both, only reason I went with ubuntu during the year was because the apache build seemed better). I’m primarily looking to become familiar with enterprise software development tools, as well as get something functional that will help my development process. (IE, I’ll still use project and assign tasks even though I might be the only one to assign tasks to, just to practice doing so). Is there any other software / configuration details I should explore? Opinions on my current list? I primarily use C#, Java, and PHP. I'm familiar with ruby, and python as well. Thanks!

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• editable year planner

  - by Mick

  Can anyone recommend any freeware/shareware for creating an editable year planner?

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• Python Question: Year and Day of Year to date?

  - by Rie Mino

  I have a year value and a day of year and would like to convert to a date (day/month/year). Thanks in advance. :)

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• jQuery UI - Datepicker - Hide year

  - by David

  Hi, I'm using jQuery UI 1.8 and I would like to hide the year from the user in both the popup and the textbox. Essentially instead of picking the day, month and year I want the user to just pick the day and month. Hiding the year in the textbox is easy enough, the code shown below will do that. I'm stumped on how to hide the year from the popup - so it would say "April" instead of "April 2010". $(function() { $("#beginDateRange").datepicker({ dateFormat: 'mm/dd' }); }); <input type="text" name="beginDateRange" id="beginDateRange" /> Any help would be greatly appreciated.

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• Remove year component from NSDateFormatter style

  - by JK

  I would like to present a date in the kCFDateFormatterFullStyle, but without the year. Is there any way to remove the year component from this style? My app requires localization so practically I cannot programmatically set the format string for all locales. I have come accross a solution which removes the "y" characters from the format string returned by the built in styles. Unfortunately, this is not acceptable as the year components are not represented by "y" in some other languages like Japanese. Any suggestions to get the kCFDateFormatterFullStyle without the year would be great! Thanks.

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• insert number of days of year, months, days of month

  - by ml

  How can I insert in a database the number of days of the year and at the same time insert in the same record the month, day of the month, and the day of the week? This is my table: tabela/coluna.Dias_ano(registo 1...365) Year:=StrToInt(ano.Text); diasano.Text:= IntToStr( DaysInAYear(Year) ); diasAno| Mes |diames |dia semana | 1 | janeiro | 1 |Segunda | 2 | janeiro | 2 | Terça | ... 365 | Dezembro | 31 | Segunda

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• XSLT - group response as per month and year combination

  - by alisha

  I want into write xslt to get response for the input xml. thanks in advance. I want to group output such that month year combination is not repeated for each of the employee details. Input XML: <resultset> <row> <column> <name>Month</name> <value>2</value> </column> <column> <name>Year</name> <value>2010</value> </column> <column> <name>EmpName</name> <value>Anu</value> </column> <column> <name>Age</name> <value>24</value> </column> </row> <row> <column> <name>Month</name> <value>2</value> </column> <column> <name>Year</name> <value>2010</value> </column> <column> <name>EmpName</name> <value>Nancy</value> </column> <column> <name>Age</name> <value>26</value> </column> </row> <row> <column> <name>Month</name> <value>3</value> </column> <column> <name>Year</name> <value>2010</value> </column> <column> <name>EmpName</name> <value>Ned</value> </column> <column> <name>Age</name> <value>25</value> </column> </row> </resultset> Output expected: <Response> <PeriodInfo> <Month>2</Month> <Year>2010</Year> <EmployeeDetails> <Name>Anu</Name> <Age>24</Age> </EmployeeDetails> <EmployeeDetails> <Name>Nancy</Name> <Age>26</Age> </EmployeeDetails> </PeriodInfo> <PeriodInfo> <Month>3</Month> <Year>2010</Year> <EmployeeDetails> <Name>Ned</Name> <Age>25</Age> </EmployeeDetails> </PeriodInfo> </Response>

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• Rails 3 date_select for year only

  - by tvalent2

  I have a form in my Rails 3 app where I want to create a select tag for just the year on a method :grad_year. I have everything working - and storing - properly using date_select and adding :discard_month and :discard_day. However when I render @profile.grad_year I get the month and day values. So I'm wondering how to store and render only the year for @profile.grad_year? Here is the form: <%= f.date_select :grad_year, {:start_year => Time.now.year, :end_year => Time.now.year - 95, :discard_day => true, :discard_month => true}, :selected => @profile.grad_year %> In my migration: t.date :grad_year

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• How to separate the year from a birthdate?

  - by Sandipan

  I want to separate the year from the Birthdate.I have a checkbox called Birthdate and when checked it will show the mm/dd/yy. But I want to separate this and show only the date along with the month. And there will be another checkbox called year which will only show if the Birthdate checkbox is checked and if checked it will show the year

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• Award-Winning Architects at Oracle OpenWorld

  - by Bob Rhubart

  "The Winner," a sculpture by John J. Seward Jr. The role of the IT architect may be the most hotly debated and unjustly maligned role in IT. But at this year's Oracle OpenWorld in San Francisco several architects will enjoy some much-deserved recognition through the Oracle Magazine Technologist of the Year Awards. Part of the Oracle Excellence Awards, the Technologist of the Year Awards "honor Oracle technologists for their cutting-edge solutions using Oracle products and services." Seven of the ten Technologist of the Year categories honor architects: Technologist of the Year: Big Data Architect Technologist of the Year: Cloud Architect Technologist of the Year: Enterprise Architect Technologist of the Year: Mobile Architect Technologist of the Year: Security Architect Technologist of the Year: Social Architect Technologist of the Year: Virtualization Architect If you or one of your colleagues is an architect deserving of this recognition, click the appropriate link above to find the nomination form. Deadline for nominations is Tuesday, July 17, 2012. For more information see: Technologist of the Year Awards. See last year's winners here.

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• PHP strtotime without leap-years

  - by Christian Sciberras

  With regards to this thread, I've developed a partial solution: function strtosecs($time,$now=null){ static $LEAPDIFF=86400; $time=strtotime($time,$now); return $time-((date('Y',$time)-1968)/4*$LEAPDIFF); } The function is supposed to get the number of seconds given a string without checking leap-years. It does this calculating the number of leap-years 1970 [(year-1986)/4], multiplying it by the difference in seconds between a leap-year and a normal year (which in the end, it's just the number of seconds in a day). Finally, I simply remove all those excess leap-year seconds from the calculated time. Here's some examples of the inputs/outputs: // test code echo strtosecs('+20 years',0).'=>'.(strtosecs('+20 years',0)/31536000); echo strtosecs('+1 years',0).'=>'.(strtosecs('+1 years',0)/31536000); // test output 630676800 => 19.998630136986 31471200 => 0.99794520547945 You will probably ask why am I doing a division on the output? It's to test it out; 31536000 is the number of seconds in a year, so that 19.99... should be 20 and 0.99... should be a 1. Sure, I could round it all and get "correct" answer, but I'm worried about the inaccuracies.

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• Export 1 year of CVS to another repo?

  - by John Dibling

  We have a CVS repo with many years of history. It has become huge and unwieldly, so we would like to split this singe repo in to two repos: The main repo would have 1 year's worth of history, up to and including present day. This is where all dev work would take place. An archive repo would have the complete history, up to the point where the main repo would take over. This would be read-only, and only used to look at historical changes. Given that we are starting with one huge, monolithic CVS repo, is it possible to split it up in this way? How can this be accomplished?

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• Advice for last year college graduates

  - by Tomh

  Hey guys, I know there are many "advice" questions around this site. But I wanted to to narrow mine down to last year college students, in my case my last year as Master student in computer science. So far is a list of things I've done during my time in college (which I can recommend others to do aswell): Code a lot I've written several hobby projects, had part time jobs, entered the Imagine cup from Microsoft, took programming extensive courses and did freelance gigs. Read a lot I've bought most top books from the recommended book topics here, to be honest I have not read them all. learn different languages I've tried several languages including Haskell, Java, Python, Ruby, Lisp, Prolog, C#, PHP, JS, AS3 and possibly some more I forgot. Tried to start a blog Joel recommends to learn how to write, I tried starting a couple of blogs to improve upon this, I gave up on all instances after writing about three posts. It was just not my thing... Have a portfolio of launched projects/programs I'm busy with this, have a couple of finished, working projects I worked on to show to people. So this is my last year. Is there anything else you can recommend a last year college student to do before hitting the job market? Personally I'm tempted to spend my time on the following: Practice algorithm design Learn and memorize the usage of the low level API's of your favorite language Polish your portfolio Why? Because those first two will make sure you pass the majority of the interviews, here in Holland (I could be wrong). I rather not spend my time on those first two points, but I have to be realistic and thats just my experience on what kind of questions you'll get when you apply. The third point is my hope that I won't have to answer questions about the amount of standard types in c# for example if they can see I get projects done and launched. But I'm still graduating, so I don't know anything :), and many of you might be hiring grads on a recent base and could tell me and other interested people what you wish that the recent grads you interviewed would have done before they applied.

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• help, php calendar links

  - by Ray

  Below is a partial table row that will create a line row of 3 columns. Two columns in each side is links, left is previous year and right is next year links. Center is links for january thru december. When you click a month links, the calendar will show that month you've clicked in the current year the calendar is on. For example, the calendar will open current month and year by default...March 2010. If you clicked previous year (2009), it will display current month (March) of last year (2009)...and then if you click Jun, the calendar will display June of whatever the year the calendar is currently on, which is June of 2009. my question is, what can i do to following code to do such thing. $Calendar.= "</tr><tr><td>"."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=" . $LastYear["year"] ."\"> $LastY </a></td>\n"; $Calendar.= "<td colspan=\"5\">"."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[0] ."\">Jan.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[1] ."\">Feb.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[2] ."\">Mar.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[3] ."\">Apr.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[4] ."\">May</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[5] ."\">Jun.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[6] ."\">Jul.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[7] ."\">Aug.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[8] ."\">Sep.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[9] ."\">Oct.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[10] ."\">Nov.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[11] ."\">Dec.</a> </td>"; $Calendar.= "<td>"."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=" . $NextYear["year"] ."\"> $NextY </a></td>\n"; Thanks in advance.

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• A query for date within a year

  - by Fabiano PS

  My table is like this on Postgres, note that all days start by 01, there is only 1 entry a month+year SELECT * FROM "fis_historico_receita" +----+------------+---------------+ | id | data | receita_bruta | +----+------------+---------------+ | 1 | 2010-02-01 | 100000.0 | | 2 | 2010-01-01 | 100000.0 | | 3 | 2009-12-01 | 100000.0 | | 4 | 2009-11-01 | 100000.0 | | 5 | 2009-10-01 | 100000.0 | | 6 | 2009-09-01 | 100000.0 | | 7 | 2009-08-01 | 100000.0 | | 8 | 2009-07-01 | 100000.0 | | 9 | 2009-06-01 | 100000.0 | | 10 | 2009-05-01 | 100000.0 | | 11 | 2009-04-01 | 100000.0 | | 12 | 2009-03-01 | 100000.0 | | 13 | 2009-02-01 | 100000.0 | | 14 | 2009-01-01 | 100000.0 | | 15 | 2008-12-01 | 100000.0 | +----+------------+---------------+ What I want is to find 12 months starting right from before the current. I tried this: select * from fis_historico_receita where data in interval '1 year' I really would like an answer using Interval, +1 goes for everyone that runs on Postgres

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