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  • How to Generate XSL code automatically ?

    - by B. Kumar
    Hello Everyone, I have UI which provide the facility to create own format by using drag and drop utility. I have also xml file which contains the data. Now task is how to automatically generate the .xsl file of the dynamically designed format for the data stored in xml form. If you have any idea about the solution of the above problem. I will thankful for any help regarding this… Thanks B. Kumar

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  • XSL Doctype Issue

    - by Batfan
    I'm having issues with an XSL template that is outputting to HTML. There is a javascript being rendered on the resulting HTML page that requires a strict doctype in order to work across all browsers. However, I cant get the doctype to show up. Any thoughts on this? Would it be possible to insert it dynamically, using javascript or php? Any help is appreciated.

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  • Converting part of a multi-purpose XML file to RSS using XSL

    - by Nate McCloud
    I have an XML file that I use for storing and displaying recipes that I collect, but that same XML file also has updates for the site at the top of it. How would I, say, use Recipes.xsl to transform Recipes.xml for display as an actual website, and use RecipesRSS.xsl to transform Recipes.xml into Recipes.rss? Currently, my XML file is formatted something like this: <book> <updates> <update when="2010-04-19"> <format> <update>Formatting updates here, if any. Otherwise, omit the Format section.</update> ... </format> <recipes> <update>Recipe updates here, if any. Otherwise, omit the Recipes section.</update> ... </recipes> </update> ... </updates> <recipe name="Recipe Name"> <from>Recipe source</from> <category>Recipe category</category> <ingredients> <ingredient>Recipe ingredient</ingredient> ... </ingredients> <instructions> <step>Recipe instructions go here.</step> ... </instructions> <notes> <note>Additional notes go here, if any. Otherwise, Notes section is omitted.</note> ... </notes> </recipe> ... </book> Any help would be greatly appreciated.

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  • How to improve variable overriding/overwriting in XSL?

    - by ChrisBenyamin
    I want to do the following: Declare a variable Go into a if-statement Overwrite the variable XSL says I can't declare a variable twice, so what can I do to improve this step? Another approach was to check if a variable is set at all. I did this, because i skipped the first step and declared the variable in the if-statement. In another if-statement I wanted to check if the variable exists at all.

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  • Rotate text in XSL-FO

    - by Shekar_XSL
    Hi, I am generating the xsl-fo document for my XML content and then passing this content to one of the third party DLL that will generate the PDF. I have a requirement to display a test in 45 degrees angle. How to achive this? Thanks

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  • using thread to load xsl transformation gives error.

    - by infant programmer
    I had to use threading to avoid "XSL Compilation time-out error" Now the problem I am facing is: It gives error, saying the output-string(generated as a result of transformation) is null!! Here is my C# code : [click_me] And the errors I am getting is copied in this text file : [click_me] And the original code without threading .. [click_me]

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  • Creating a menu using xslt for Umbraco

    - by rob_g
    I've created a menu in umbraco using XSLT. The menu is using the usual ul and li elements and I'm displaying only the first level of the menu. The aim is to create a menu that expands to show the sub menu when I click a parent node (in the top level). I am after the xslt I would need to expose the sub menu when clicked. I think I would need to make use of ancestor-or-self to detect the current menu and parent menu and display them and also the $currentPage variable. I have the following xslt: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxml="urn:schemas-microsoft-com:xslt" xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:urlLib="urn:urlLib" exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib urlLib "> <xsl:output method="xml" omit-xml-declaration="yes"/> <xsl:param name="currentPage"/> <xsl:template match="/"> <div id="kb-categories"> <h3>Categories</h3> <xsl:call-template name="drawNodes"> <xsl:with-param name="parent" select="$currentPage/ancestor-or-self::node [@level=1]"/> </xsl:call-template> </div> </xsl:template> <xsl:template name="drawNodes"> <xsl:param name="parent"/> <xsl:if test="(umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 1)) and $parent/@level = 1"> <ul class="kb-menuLevel1" > <xsl:for-each select="$parent/node [string(./data [@alias='showInMenu']) = 1]"> <li> <a href="/kb{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> <xsl:variable name="level" select="@level" /> <xsl:if test="(count(./node [string(./data [@alias='showInMenu']) = '1']) &gt; 0)"> <xsl:call-template name="drawNodes"> <xsl:with-param name="parent" select="."/> </xsl:call-template> </xsl:if> </li> </xsl:for-each> </ul> </xsl:if> <xsl:if test="(umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 1)) and $parent/@level &gt; 1"> <ul class="kb-menuLevel{@level}" style="display: none;"> <xsl:for-each select="$parent/node [string(./data [@alias='showInMenu']) = 1]"> <li> <a href="/kb{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> <xsl:variable name="level" select="@level" /> <xsl:if test="(count(./node [string(./data [@alias='showInMenu']) = '1']) &gt; 0)"> <xsl:call-template name="drawNodes"> <xsl:with-param name="parent" select="."/> </xsl:call-template> </xsl:if> </li> </xsl:for-each> </ul> </xsl:if> </xsl:template> </xsl:stylesheet> I suspect this could be improved using apply-templates, but I'm not yet up to speed with that (this being only the second day of my learning xslt). My menu: Item 1 Item 2 Item 3 Item 4 when I click on Item 2 I want to see it's child menu too: Item 1 Item 2 -- Item 2.1 -- Item 2.2 Item 3 Item 4 and so on down the nested menu.

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  • XSLT string replace

    - by aximili
    I don't really know XSL but I need to fix this code, I have reduced it to make it simpler. I am getting this error Invalid XSLT/XPath function on this line <xsl:variable name="text" select="replace($text,'a','b')"/> This is the XSL <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:inm="http://www.inmagic.com/webpublisher/query" version='1.0'> <xsl:output method="text" encoding="UTF-8"/> <xsl:preserve-space elements="*"/> <xsl:template match="text()"></xsl:template> <xsl:template match="mos"> <xsl:apply-templates/> <xsl:for-each select="mosObj"> 'Notes or subject' <xsl:call-template name="rem-html"><xsl:with-param name="text" select="SBS_ABSTRACT"/></xsl:call-template> </xsl:for-each> </xsl:template> <xsl:template name="rem-html"> <xsl:param name="text"/> <xsl:variable name="text" select="replace($text,'a','b')"/> </xsl:template> </xsl:stylesheet> Can anyone tell me what's wrong with it? Thanks in advance.

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  • XSLT multiple string replacement with recursion

    - by John Terry
    I have been attempting to perform multiple (different) string replacement with recursion and I have hit a roadblock. I have sucessfully gotten the first replacement to work, but the subsequent replacements never fire. I know this has to do with the recursion and how the with-param string is passed back into the call-template. I see my error and why the next xsl:when never fires, but I just cant seem to figure out exactly how to pass the complete modified string from the first xsl:when to the second xsl:when. Any help is greatly appreciated. <xsl:template name="replace"> <xsl:param name="string" select="." /> <xsl:choose> <xsl:when test="contains($string, '&#13;&#10;')"> <xsl:value-of select="substring-before($string, '&#13;&#10;')" /> <br/> <xsl:call-template name="replace"> <xsl:with-param name="string" select="substring-after($string, '&#13;&#10;')"/> </xsl:call-template> </xsl:when> <xsl:when test="contains($string, 'TXT')"> <xsl:value-of select="substring-before($string, '&#13;TXT')" /> <xsl:call-template name="replace"> <xsl:with-param name="string" select="substring-after($string, '&#13;')" /> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$string"/> </xsl:otherwise> </xsl:choose> </xsl:template>

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  • XSLT Sort Alphabetically & Numerically Problem

    - by Bryan
    I have a group of strings ie g:lines = '9,1,306,LUCY,G,89' I need the output to be: 1,9,89,306,G,LUCY This is my current code: <xsl:for-each select="$all_alerts[g:problem!='normal_service'][g:service='bus']"> <xsl:sort select="g:line"/> <xsl:sort select="number(g:line)" data-type="number"/> <xsl:value-of select="normalize-space(g:line)" /><xsl:text/> <xsl:if test="position()!=last()"><xsl:text>,&#160;</xsl:text></xsl:if> </xsl:for-each> I can get it to only display '1, 12, 306, 38, 9, G, LUCY' because the 2nd sort isn't being picked up. Anyone able help me out?

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  • Setting XSL-FO XML Schema in Visual Studio

    - by Lukasz Kurylo
    I'm playing lately with an XSL-FO for generating a pdf documents. XSL-FO has a long list of available tags and attributes, which for a new guy who want to create a simple document is a nightmare to find a proper one. Fortunatelly we can set an schema for XSL-FO, so will result in acquire a full intellisense in VS. For a simple *.fo file, we can set the path to the schema directly in file: <?xml version="1.0" encoding="utf-8"?> <fo:root       xmlns:fo="http://www.w3.org/1999/XSL/Format"       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       xsi:schemaLocation=" http://www.w3.org/1999/XSL/Format http://www.xmlblueprint.com/documents/fop.xsd"> ...   We can of course use the build in VS XML Schemas selector. To use it, we must copy the schema file to the Schemas catalog (defaut path for VS2012 is C:\Program Files (x86)\Microsoft Visual Studio 11.0\Xml\Schemas). Then we can go to Properties of the opened xml/xslt file and set the new added schema to file:                 From now, we should have an enable intellisense as shown below: .

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  • XSL 2.0 unparsed text and formatting

    - by Maha
    I want the unparsed text to be formatted for bold characters or increase font-size based on the tag the example here is for replace the searched word with bold characters Example: test <b> how to <b> when bold <b> when there is more <b> than one place to bold Can you please advice what is wrong here? <xsl:variable name="tcline" select="unparsed-text('generic_tc.txt','UTF-8')"/> <xsl:analyze-string select="$tcline" regex="\'<b>'(.*?)\'<b>'"> <xsl:matching-substring> <xsl:value-of select="replace($tcline,'\"<b>"(.*?)\"<b>"','<em>$1\/em/g;')"/> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:value-of select="."/> </xsl:non-matching-substring> </xsl:analyze-string>

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  • Square Bullet in XSL-FO

    - by Igman
    I am attempting to create a list in XSL-FO using a square bracket. I have been able to get it working using the standard unicode bullet character (&#8226;) but I just can't seem to get it working for square brackets. I have tried using &#9632;, but that does not seem to work. It is important that i can get the square bullets working because I am matching an existing file format.Any help in getting this working would be greatly appreciated. <fo:list-item-label end-indent="label-end()"> <fo:block>&#x2022;</fo:block> </fo:list-item-label>

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  • JavaScript For Loop in XSL document

    - by Nagendra
    Hello All, I have a peculiar problem with having a JavaScript for loop in XSL document. Here it goes:: I am calling a JavaScript function on the click of a CheckBox. Following is what I wanted to do in the javascript function :: function SeelctAll() { for(var cnt = 0; cnt < 100; cnt++) { //Business Logic here. } } For this I replaced < with < and tried. I got an error saying "Object Expected". I then enclosed the whole function inside Any help on this would be greatly appreciable.

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  • Count end points in XML using XSL

    - by Chris
    I want to be able to count "end points" in an XML file using XSL. By endpoint I mean tag's with no children that contain data. i.e. <xmlsnippet> <tag1>NOTENOUGHDAYS</tag1> <tag2>INVALIDINPUTS</tag2> <tag3> <tag4> <tag5>2</tag5> <tag6>1</tag6> </tag4> </tag3> </xmlsnippet> This XML should return 4 as there are 4 "end points"

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  • XSL template structure for choosing latest event.

    - by Deborah Klenke
    I have a list grouped by Region and it currently shows all the items for each city. I want to reduce to only the most recent advisory for each city. I have tried to use an xsl:for-each statement but I am messing up the names/parameters. List is called mlc The list contains the fields: Title City Region Advisory DateCreated TT (calculated number field to find the number of minutes from the DateCreated to end of today which I intended to use the smallest to find the most recent) I have the list grouped by Region and it currently shows all the items for each city. I want to reduce to only the most recent advisory for each city.

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  • How to limit results in a SharePoint XSL query

    - by David
    Hello all, I am creating a SharePoint site that we will use to report issues with trucks used in our business. Linked to the list I have created will be a page that will display an overview of the trucks and a little truck icon will show the trucks current status. Green and the truck is okay (no open issues), Red and the truck have an open issue with status "Undrivable", Orange and there is two issues open that requires the user to look further into the truck before using it and finally a Gray truck for when there is a new issue created that has not been looked into (not sure if it is drivable or not). I have managed to create the "Dashboard" and with my limit XSL/XPATH knowledge been able to add a truck and replicate the description above but... in my test I have created 4 issues, for example if three of them are changed to status Closed and one left to Undrivable I will get four icons on the page, three with Green trucks and the last one Red. So in theory it works but I obviously only want to see the last truck, one truck. I am not interested in seeing the others. <xsl:template name="dvt_1.rowview"> <xsl:variable name="CountReport" select="count(/dsQueryResponse/Rows/Row[@Highloader='GGEU12' and @Status!='Closed'])" /> <xsl:variable name="MoreThan" select="$CountReport &gt; 1" /> <xsl:variable name="NoReports" select="$CountReport = 0" /> <xsl:variable name="Closed" select=" @Highloader='GGEU12' and @Status='Closed'" /> <xsl:choose> <xsl:when test="$MoreThan"> <div class="ms-vb"><img title='More than one report exist!' border='0' alt='In Progress' src='highloader/Library/hl-orange.png' /></div> </xsl:when> <xsl:otherwise> <div class="ms-vb"><xsl:value-of disable-output-escaping="yes" select="@Icon" /></div> </xsl:otherwise> </xsl:choose> </xsl:template> My hope is that someone with slightly more knowledge can find the last piece of the puzzle for me! Thanks for reading and asking questions to fill any gap I left above. David

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  • xsl:variable does not return a node-set in XSLT 2.0?

    - by Henry
    Hi all, I'm trying to get a node-set from a xsl variable for calculating. But my code only work with Opera, with other browsers, I keep getting the error. Please help me fix to run with all browser. Thanks in advance. Here are the xslt code: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:output method="html"/> <xsl:variable name="multipleSet"> <xsl:for-each select="myNums/numSet"> <xsl:element name="multiple"><xsl:value-of select="num1 * num2"/></xsl:element> </xsl:for-each> </xsl:variable> <xsl:template match="/"> <table border="1"> <tr> <th>Num 1</th> <th>Num 2</th> <th>Multiple</th> </tr> <xsl:for-each select="myNums/numSet"> <tr> <td><xsl:value-of select="num1"/></td> <td><xsl:value-of select="num2"/></td> <td><xsl:value-of select="num1 * num2"/></td> </tr> </xsl:for-each> <tr> <th colspan="2" align="right">Total:</th> <td><xsl:value-of select="sum($multipleSet/multiple)"/> </td> </tr> </table> </xsl:template> </xsl:stylesheet> And the xml: <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="test.xsl"?> <myNums> <numSet> <num1>5</num1> <num2>5</num2> </numSet> <numSet> <num1>10</num1> <num2>5</num2> </numSet> <numSet> <num1>15</num1> <num2>20</num2> </numSet> </myNums>

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  • How to edit the XSL for RSS Viewer Webpart

    - by Nagendra
    I am using a blog site as a source for my RSS Feed. As I see the RSS feed, its showing up as the following :: Blog: Posts Test Thursday, March 04, 2010 - Body: With 25 four's and 3 sixers Sachin crosses 200 (147 balls) runs in an single ODI innings. Creates another world record. Watch the final over where he got it double hundred with MSD on the other end. This is what he had to say after getting the MOM (man of the match): I dedicate this knock to all the people of India, who have supported me throughout over the last 20 years. I was timing the ball well, and I felt that anywhere between 340 to 350 was a good target. I thought Karthik, Yusuf and Dhoni supported me well. I thought that a 200 would be possible once I crossed 175 in the 42nd over. I am enjoying my cricket at the moment. There have been a few bad decisions I have made as a batsman, but as long as the passion is there I will carry on. It feels good that I lasted the 50 overs, it was a good test of my fitness and I would like to do this once again. Well!!! Wait for more. Published: 3/4/2010 3:18 PM More... I actually wanted to remove the Body, Published parameters. I just want my XSLT to be able to show only the Description of the blog. No need to have this meta data. Can anyone help me in specifying tthe XSL changes?

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  • using XSL to replace XML nodes with new nodes

    - by iHeartGreek
    I need an XSL solution to replace XML nodes with new nodes. Say I have the following existing XML structure: <root> <criteria> <criterion>AAA</criterion> </criteria> </root> And I want to replace the one criterion node with: <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> So that the final XML result is: <root> <criteria> <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> </criteria> </root> I have tried using substring-before and substring-after to just copy the first half of the structure, then just copy the second half (in order to fill in my new nodes in between the two halves) but it appears that the substring functions only recognize text in between the nodes' tags, and not the tags themselves like I want them to. :( :( Any other solutions?

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  • CUSTOM SORT XSL ?

    - by Nanda
    Hi This is my XML Structure like this input :- <MYDATA> <DETAILS> <DESCRIPTION>EASE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>COMPLEX</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>SIMPLE</DESCRIPTION> </DETAILS> </MYDATA> I want to display like this using xsl sort it mean custom sort i want to display firts simple second ease and third complex Output :- <MYDATA> <DETAILS> <DESCRIPTION>SIMPLE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>EASE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>COMPLEX</DESCRIPTION> </DETAILS> </MYDATA>

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  • Good coding style to do case-select in XSLT

    - by Scud
    I want to have a page display A,B,C,D depending on the return value from XML value (1,2,3,4). My approaches are by javascript or XSLT:choose. I want to know which way is better, and why? Can I do this case-select in .cs code (good or bad)? Should I javascript code in XSLT? Can the community please advise? Thanks. Below are the code. Javascript way (this one works): <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:js="urn:custom-javascript"> <xsl:template match="page"> <msxsl:script language="JavaScript" implements-prefix="js"> <![CDATA[ function translateSkillLevel(level) { switch (level) { case 0: return "Level 1"; case 1: return "Level 2"; case 2: return "Level 3"; } return "unknown"; } ]]> </msxsl:script> <div id="skill"> <table border="0" cellpadding="1" cellspacing="1"> <tr> <th>Level</th> </tr> <xsl:for-each select="/page/Skill"> <tr> <td> <!-- difference here --> <script type="text/javascript"> document.write(translateSkillLevel(<xsl:value-of select="@level"/>)); </script> </td> </tr> </xsl:for-each> </table> </div> </xsl:template> </xsl:stylesheet> Javascript way (this one doesn't work, getting undefined js tag): <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:js="urn:custom-javascript"> <xsl:template match="page"> <msxsl:script language="JavaScript" implements-prefix="js"> <![CDATA[ function translateSkillLevel(level) { switch (level) { case 0: return "Level 1"; case 1: return "Level 2"; case 2: return "Level 3"; } return "unknown"; } ]]> </msxsl:script> <div id="skill"> <table border="0" cellpadding="1" cellspacing="1"> <tr> <th>Level</th> </tr> <xsl:for-each select="/page/Skill"> <tr> <td> <!-- difference here --> <xsl:value-of select="js:translateSkillLevel(string(@level))"/> </td> </tr> </xsl:for-each> </table> </div> </xsl:template> </xsl:stylesheet> XSLT way: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="page"> <div id="skill"> <table border="0" cellpadding="1" cellspacing="1"> <tr> <th>Level</th> </tr> <xsl:for-each select="/page/Skill"> <tr> <td> <xsl:choose> <xsl:when test="@level = 0"> Level 1 </xsl:when> <xsl:when test="@level = 1"> Level 2 </xsl:when> <xsl:when test="@level = 2"> Level 3 </xsl:when> <xsl:otherwise> unknown </xsl:otherwisexsl:otherwise> </xsl:choose> </td> </tr> </xsl:for-each> </table> </div> </xsl:template> </xsl:stylesheet> EDIT: Also, I have some inline javascript functions for form submit. <input type="submit" onclick="javascript:document.forms[0].submit();return false;"/>

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  • Combine XML elements with xsl

    - by mpenrow
    I have the following xml: <RowSet> <Row> <Number>12345</Number> <Quantity>42</Quantity> </Row> <Row> <Number>12345</Number> <Quantity>12</Quantity> </Row> <Row> <Number>54321</Number> <Quantity>37</Quantity> </Row> </RowSet> I want to use an xsl to combine the elements with the same Number and the resulting should sum the Quantity elements. So the output should look like this: <RowSet> <Row> <Number>12345</Number> <Quantity>64</Quantity> </Row> <Row> <Number>54321</Number> <Quantity>37</Quantity> </Row> </RowSet>

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