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  • EPPlus - .xlsx is locked for editing by 'another user'

    - by AdamTheITMan
    I have searched through every possible answer on SO for a solution, but nothing has worked. I am basically creating an excel file from a database and sending the results to the response stream using EPPlus(OpenXML). The following code gives me an error when trying to open my generated excel sheet "[report].xlsx is locked for editing by 'another user'." It will open fine the first time, but the second time it's locked. Dim columnData As New List(Of Integer) Dim rowHeaders As New List(Of String) Dim letter As String = "B" Dim x As Integer = 0 Dim trendBy = context.Session("TRENDBY").ToString() Dim dateHeaders As New List(Of String) dateHeaders = DirectCast(context.Session("DATEHEADERS"), List(Of String)) Dim DS As New DataSet DS = DirectCast(context.Session("DS"), DataSet) Using excelPackage As New OfficeOpenXml.ExcelPackage Dim excelWorksheet = excelPackage.Workbook.Worksheets.Add("Report") 'Add title to the top With excelWorksheet.Cells("B1") .Value = "Account Totals by " + If(trendBy = "Months", "Month", "Week") .Style.Font.Bold = True End With 'add date headers x = 2 'start with letter B (aka 2) For Each Header As String In dateHeaders With excelWorksheet.Cells(letter + "2") .Value = Header .Style.HorizontalAlignment = OfficeOpenXml.Style.ExcelHorizontalAlignment.Right .AutoFitColumns() End With x = x + 1 letter = Helper.GetColumnIndexToColumnLetter(x) Next 'Adds the descriptive row headings down the left side of excel sheet x = 0 For Each DC As DataColumn In DS.Tables(0).Columns If (x < DS.Tables(0).Columns.Count) Then rowHeaders.Add(DC.ColumnName) End If Next Dim range = excelWorksheet.Cells("A3:A30") range.LoadFromCollection(rowHeaders) 'Add the meat and potatoes of report x = 2 For Each dTable As DataTable In DS.Tables columnData.Clear() For Each DR As DataRow In dTable.Rows For Each item As Object In DR.ItemArray columnData.Add(item) Next Next letter = Helper.GetColumnIndexToColumnLetter(x) excelWorksheet.Cells(letter + "3").LoadFromCollection(columnData) With excelWorksheet.Cells(letter + "3") .Formula = "=SUM(" + letter + "4:" + letter + "6)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "7") .Formula = "=SUM(" + letter + "8:" + letter + "11)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "12") .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "13") .Formula = "=SUM(" + letter + "14:" + letter + "20)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "21") .Formula = "=SUM(" + letter + "22:" + letter + "23)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "24") .Formula = "=SUM(" + letter + "25:" + letter + "26)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "27") .Formula = "=SUM(" + letter + "28:" + letter + "29)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "30") .Formula = "=SUM(" + letter + "3," + letter + "7," + letter + "12," + letter + "13," + letter + "21," + letter + "24," + letter + "27)" .Style.Font.Bold = True .Style.Font.Size = 12 End With x = x + 1 Next range.AutoFitColumns() 'send it to response Using stream As New MemoryStream(excelPackage.GetAsByteArray()) context.Response.Clear() context.Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet" context.Response.AddHeader("content-disposition", "attachment; filename=filetest.xlsx") context.Response.OutputStream.Write(stream.ToArray(), 0, stream.ToArray().Length) context.Response.Flush() context.Response.Close() End Using End Using

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  • HTTP Live Streaming, FFMPEG & FFSERVER, and iPhone OS 3

    - by jcnnghm
    In iPhone OS 3, Apple has introduced HTTP Live Streaming which should allow live streaming of video from the internet. I am currently operating a webcam, which feeds into my server, and is then converted into a flv stream by ffmpeg, and streamed back out using ffserver. Does anyone know how to setup a video stream the iPhone can use using ffmpeg and ffserver? I should be able to re-encode into just about any format on the fly.

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  • jQuery plugin for html5 video instream ads?

    - by dar
    Are there any jQuery plugins for html5 video to insert instream ads into the video? Most of the flash ones work by pausing the video at a particular timestamp, and playing an ad stream, then resuming the original video stream. The jquery captions plugin for html5 seems very similar, but different.

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  • RTP H.264 save and replay

    - by user301810
    We are interested in saving a H.264 stream and replaying it. Is there any one who experience saving h.264 using winpcap and replaying it. We were able to save H.263 and replay, but same logic does not work for H.264. We also tried rtpdump tool to save H264 stream, but we were unable to replay it in that format? thanks in advance

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  • Streaming live video from WCF service to Silverlight

    - by Yuval Peled
    Hi, I need to stream live captured data (from a screen/web cam) from a WCF service to a Silverlight client. Since it's live data I don't mind losing packets... More important that it will be real-time data. Any suggestions how can I do it? How does the WCF service transfer it? How does the Silverlight client should consume the stream?

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  • any good jsch examples?

    - by jshen
    I'm trying to run a command over ssh with jsch, but jsch has virtually no documentation and the examples I've found via google are terrible. For example, this one doesn't show code for handling the output stream. And, this one using an ugly hack to know when to stop reading from the output stream.

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  • Xuggle codec identification fail

    - by Thiago
    Hi there, I'm trying to run the following Xuggle code: public static boolean convert(String stream) throws IOException, InterruptedException { IMediaReader reader = ToolFactory.makeReader(stream + ".flv"); IMediaWriter writer = ToolFactory.makeWriter(stream + ".mp3", reader); reader.addListener(writer); while (reader.readPacket() != null) ; return true; } Where stream is the file path. But I'm getting the following exception: java.lang.IllegalArgumentException: could not find input codec id at com.xuggle.xuggler.IContainerFormat.establishOutputCodecId(IContainerFormat.java:393) at com.xuggle.xuggler.IContainerFormat.establishOutputCodecId(IContainerFormat.java:327) at com.xuggle.xuggler.IContainerFormat.establishOutputCodecId(IContainerFormat.java:300) at com.xuggle.mediatool.MediaWriter.addStreamFromContainer(MediaWriter.java:1141) at com.xuggle.mediatool.MediaWriter.getStream(MediaWriter.java:1046) at com.xuggle.mediatool.MediaWriter.encodeAudio(MediaWriter.java:837) at com.xuggle.mediatool.MediaWriter.onAudioSamples(MediaWriter.java:1448) at com.xuggle.mediatool.AMediaToolMixin.onAudioSamples(AMediaToolMixin.java:89) at com.xuggle.mediatool.MediaReader.dispatchAudioSamples(MediaReader.java:628) at com.xuggle.mediatool.MediaReader.decodeAudio(MediaReader.java:555) at com.xuggle.mediatool.MediaReader.readPacket(MediaReader.java:469) at <package_name>MediaFile.convert(MediaFile.java:66) at <package_name>.MediaFileTest.shouldConvertExistingFLV(MediaFileTest.java:32) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28) at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:73) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:46) at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:180) at org.junit.runners.ParentRunner.access$000(ParentRunner.java:41) at org.junit.runners.ParentRunner$1.evaluate(ParentRunner.java:173) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28) at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31) at org.junit.runners.ParentRunner.run(ParentRunner.java:220) at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:46) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197) The unit test is the following: @Test public void shouldConvertExistingFLV() throws IOException, InterruptedException { String str = "C:\Program Files\Wowza Media Systems\Wowza Media Server 2\content\Extremists"; //"c:/temp/corneta.flv" boolean result = MediaFile.convert(str); assertTrue(result); } So, why can't he find the codec, since I'm testing for a simple flv to mp3 conversion?

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  • Python error with IndentationError: unindent does not match any outer indentation level

    - by Vikrant Cornelio
    from tweepy import Stream from tweepy import OAuthHandler from tweepy.streaming import StreamListener ckey='W1VPPrau42ENAWP1EnDGpQ' csecret='qxtY2rYNN0QT0Ndl1L4PJhHcHuWRJWlEuVnHFDRSE' atoken='1577208120-B8vGWIquxbmscb9xdu5AUzENv09kGAJUCddJXAO' asecret='tc9Or4XoOugeLPhwmCLwR4XK8oUXQHqnl10VnQpTBzdNR' class listener(StreamListener): def on_data(self,data): print data return True def on_error(self,status): print status auth=OAuthHandler(ckey,csecret) auth.set_access_token(atoken,asecret) twitterStream=Stream(auth,listener()) twitterStream.filter(track=["car"]) I typed this in my Python shell i got an error...the error was IndentationError: unindent does not match any outer indentation level..Please help me!!!!!!!!!!!

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  • streaming desktop to flash player

    - by Erwing
    hi I would like to stream my desktop screen (or one of the application which i select) to flash player i woul like to publish my desktop in web i have wowze media player to multicast it but i have to create stream and give it to the wowze do you have any idea how to start what would be the best for it can you recomend something?

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  • Git: corrupt loose object

    - by NeoRiddle
    I was trying to merge my master branch with another one called pull-stage, but Git throws me this error: error: inflate: data stream error (invalid distance too far back) error: corrupt loose object '5a63450f4a0b72abbc1221ccb7d9f9bfef333250' fatal: loose object 5a63450f4a0b72abbc1221ccb7d9f9bfef333250 (stored in .git/objects/5a/63450f4a0b72abbc1221ccb7d9f9bfef333250) is corrupt How can I solve this issue? I have reviewed other posts, but with no successful results: How to replace corrupt Git objects with new ones created from my files, which are fine Git: "Corrupt loose object" Corrupted Git Repository (data stream error)

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  • Whats wrong with my triple DES wrapper??

    - by Chen Kinnrot
    it seems that my code adds 6 bytes to the result file after encrypt decrypt is called.. i tries it on a mkv file.. please help here is my code class TripleDESCryptoService : IEncryptor, IDecryptor { public void Encrypt(string inputFileName, string outputFileName, string key) { EncryptFile(inputFileName, outputFileName, key); } public void Decrypt(string inputFileName, string outputFileName, string key) { DecryptFile(inputFileName, outputFileName, key); } static void EncryptFile(string inputFileName, string outputFileName, string sKey) { var outFile = new FileStream(outputFileName, FileMode.OpenOrCreate, FileAccess.ReadWrite); // The chryptographic service provider we're going to use var cryptoAlgorithm = new TripleDESCryptoServiceProvider(); SetKeys(cryptoAlgorithm, sKey); // This object links data streams to cryptographic values var cryptoStream = new CryptoStream(outFile, cryptoAlgorithm.CreateEncryptor(), CryptoStreamMode.Write); // This stream writer will write the new file var encryptionStream = new BinaryWriter(cryptoStream); // This stream reader will read the file to encrypt var inFile = new FileStream(inputFileName, FileMode.Open, FileAccess.Read); var readwe = new BinaryReader(inFile); // Loop through the file to encrypt, line by line var date = readwe.ReadBytes((int)readwe.BaseStream.Length); // Write to the encryption stream encryptionStream.Write(date); // Wrap things up inFile.Close(); encryptionStream.Flush(); encryptionStream.Close(); } private static void SetKeys(SymmetricAlgorithm algorithm, string key) { var keyAsBytes = Encoding.ASCII.GetBytes(key); algorithm.IV = keyAsBytes.Take(algorithm.IV.Length).ToArray(); algorithm.Key = keyAsBytes.Take(algorithm.Key.Length).ToArray(); } static void DecryptFile(string inputFilename, string outputFilename, string sKey) { // The encrypted file var inFile = File.OpenRead(inputFilename); // The decrypted file var outFile = new FileStream(outputFilename, FileMode.OpenOrCreate, FileAccess.ReadWrite); // Prepare the encryption algorithm and read the key from the key file var cryptAlgorithm = new TripleDESCryptoServiceProvider(); SetKeys(cryptAlgorithm, sKey); // The cryptographic stream takes in the encrypted file var encryptionStream = new CryptoStream(inFile, cryptAlgorithm.CreateDecryptor(), CryptoStreamMode.Read); // Write the new unecrypted file var cleanStreamReader = new BinaryReader(encryptionStream); var cleanStreamWriter = new BinaryWriter(outFile); cleanStreamWriter.Write(cleanStreamReader.ReadBytes((int)inFile.Length)); cleanStreamWriter.Close(); outFile.Close(); cleanStreamReader.Close(); } }

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  • Cant full read querystring data in mvc4 application using a class array as input to action

    - by Anders Lindén
    I have made a mvc4 application and I have a Controller that outputs a png file like this: using System.Drawing; using System.Drawing.Drawing2D; using System.Drawing.Imaging; using System.Drawing.Text; using System.IO; using System.Web.Mvc; using Foobar.Classes; namespace Foobar.Controllers { public class ImageController : Controller { public ActionResult Index(Label[] labels) { var bmp = new Bitmap(400, 300); var pen = new Pen(Color.Black); var font = new Font("arial", 20); var g = Graphics.FromImage(bmp); g.SmoothingMode = SmoothingMode.HighQuality; g.TextRenderingHint = TextRenderingHint.AntiAliasGridFit; if (labels != null) { g.DrawString("" + labels.Length, font, pen.Brush, 20, 20); if (labels.Length > 0) { g.DrawString("" + labels[0].label, font, pen.Brush, 20, 40); } } var stream = new MemoryStream(); bmp.Save(stream, ImageFormat.Png); stream.Position = 0; return File(stream, "image/png"); } } } The Label class looks like this: using System; using System.Collections.Generic; using System.Linq; using System.Web; namespace Foobar.Classes { public class Label { public string label { get; set; } public int fontsize { get; set; } } } When I run my controller having this in the url: http://localhost:57775/image?labels[0][label]=Text+rad+1&labels[0][fontsize]=5&labels[1][fontsize]=5&labels[2][fontsize]=5 I get the correct amount of labels, so the image will show 3. But the instances of Label will not get its data members fill in. I have also tried to do this using plain variables (not properties). If they were filled in, the image would actually show "3" and "Text rad 1". So what do I put in the class "Label" to have the properties right? Should there be some kind of annotation? Where do I read about this?

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  • casting udp streams in perl

    - by user314536
    hello. my Perl scripts gets a udp response that is built out of 2 integers + float numbers. the problem is that the udp streams is one long stream of bytes. how do i cast the stream into parameters using Perl ?

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  • Is TcpClient BeginRead/Send thread safe?

    - by wb
    Using a dotNET TcpClient if I have called an asynchronous BeginRead() on the associated network stream can I still call Write() on that stream on another thread? Or do I have to lock() the TcpClient in the code that is called back from the BeginRead and the code that does the send? Also if I close the TcpClient with: client.GetStream().Close(); client.Close(); Do I have to lock() on the TcpClient as well? Thanks in advance.

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  • Darwin Streaming Server doesn't gives content

    - by cajax.mp
    Hello! I have problems with Darwin Streaming server 5.5.5 on Debian. When i'm trying to open some stream, for ex. rtsp://sample.com/sample_100kbit.mp4 player reports it can't load stream and breaks connection. "Access History" section reports file was requested, so, at least initial connection is working, but nothing more. What can be wrong and what to check?

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  • .NET Impersonate and file upload issues

    - by Jagd
    I have a webpage that allows a user to upload a file to a network share. When I run the webpage locally (within VS 2008) and try to upload the file, it works! However, when I deploy the website to the webserver and try to upload the file through the webpage, it doesn't work! The error being returned to me on the webserver says "Access to the path '\05prd1\emp\test.txt' is denied. So, obviously, this is a permissions issue. The network share is configured to allow full access both to me (NT authentication) and to the NETWORK SERVICE (which is .NET's default account and what we have set in our IIS application pool as the default user for this website). I have tried this with and without impersonation upon the webserver and neither way works, yet both ways work on my local machine (in other words, with and without impersonation works on my local machine). The code that does the file upload is below. Please note that the code below includes impersonation, but like I said above, I've tried it with and without impersonation and it's made no difference. if (fuCourses.PostedFile != null && fuCourses.PostedFile.ContentLength > 0) { System.Security.Principal.WindowsImpersonationContext impCtx; impCtx = ((System.Security.Principal.WindowsIdentity)User.Identity).Impersonate(); try { lblMsg.Visible = true; // The courses file to be uploaded HttpPostedFile file = fuCourses.PostedFile; string fName = file.FileName; string uploadPath = "\\\\05prd1\\emp\\"; // Get the file name if (fName.Contains("\\")) { fName = fName.Substring( fName.LastIndexOf("\\") + 1); } // Delete the courses file if it is already on \\05prd1\emp FileInfo fi = new FileInfo(uploadPath + fName); if (fi != null && fi.Exists) { fi.Delete(); } // Open new file stream on \\05prd1\emp and read bytes into it from file upload FileStream fs = File.Create(uploadPath + fName, file.ContentLength); using (Stream stream = file.InputStream) { byte[] b = new byte[4096]; int read; while ((read = stream.Read(b, 0, b.Length)) > 0) { fs.Write(b, 0, read); } } fs.Close(); lblMsg.Text = "File Successfully Uploaded"; lblMsg.ForeColor = System.Drawing.Color.Green; } catch (Exception ex) { lblMsg.Text = ex.Message; lblMsg.ForeColor = System.Drawing.Color.Red; } finally { impCtx.Undo(); } } Any help on this would be very appreciated!

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  • .NET Impersonate not working!

    - by Jagd
    I have a webpage that allows a user to upload a file to a network share. When I run the webpage locally (within VS 2008) and try to upload the file, it works! However, when I deploy the website to the webserver and try to upload the file through the webpage, it doesn't work! The error being returned to me on the webserver says "Access to the path '\05prd1\emp\test.txt' is denied. So, obviously, this is a permissions issue. The network share is configured to allow full access both to me (NT authentication) and to the NETWORK SERVICE (which is .NET's default account and what we have set in our IIS application pool as the default user for this website). I have tried this with and without authentication, and neither one works on the webserver, yet both ways works on my local machine. The code that does the file upload is below. Please note that the code below includes impersonation, but like I said above, I've tried it with and without impersonation and it's made no difference. if (fuCourses.PostedFile != null && fuCourses.PostedFile.ContentLength > 0) { System.Security.Principal.WindowsImpersonationContext impCtx; impCtx = ((System.Security.Principal.WindowsIdentity)User.Identity).Impersonate(); try { lblMsg.Visible = true; // The courses file to be uploaded HttpPostedFile file = fuCourses.PostedFile; string fName = file.FileName; string uploadPath = "\\\\05prd1\\emp\\"; // Get the file name if (fName.Contains("\\")) { fName = fName.Substring( fName.LastIndexOf("\\") + 1); } // Delete the courses file if it is already on \\05prd1\emp FileInfo fi = new FileInfo(uploadPath + fName); if (fi != null && fi.Exists) { fi.Delete(); } // Open new file stream on \\05prd1\emp and read bytes into it from file upload FileStream fs = File.Create(uploadPath + fName, file.ContentLength); using (Stream stream = file.InputStream) { byte[] b = new byte[4096]; int read; while ((read = stream.Read(b, 0, b.Length)) > 0) { fs.Write(b, 0, read); } } fs.Close(); lblMsg.Text = "File Successfully Uploaded"; lblMsg.ForeColor = System.Drawing.Color.Green; } catch (Exception ex) { lblMsg.Text = ex.Message; lblMsg.ForeColor = System.Drawing.Color.Red; } finally { impCtx.Undo(); } } Any help on this would be very appreciated!

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  • Using PHP's IMAP library triggers Kaspersky's Antivirus

    - by TMG
    Hello, I just started today working with PHP's IMAP library, and while imap_fetchbody or imap_body are called, it is triggering my Kaspersky antivirus. The viruses are Trojan.Win32.Agent.dmyq and Trojan.Win32.FraudPack.aoda. I am running this off a local development machine with XAMPP and Kaspersky AV. Now, I am sure there are viruses there since there is spam in the box (who doesn't need a some viagra or vicodin these days?). And I know that since the raw body includes attachments and different mime-types, bad stuff can be in the body. So my question is: are there any risks using these libraries? I am assuming that the IMAP functions are retrieving the body, caching it to disk/memory and the AV scanning it sees the data. Is that correct? Are there any known security concerns using this library (I couldn't find any)? Does it clean up cached message parts perfectly or might viral files be sitting somewhere? Is there a better way to get plain text out of the body than this? Right now I am using the following code (credit to Kevin Steffer): function get_mime_type(&$structure) { $primary_mime_type = array("TEXT", "MULTIPART","MESSAGE", "APPLICATION", "AUDIO","IMAGE", "VIDEO", "OTHER"); if($structure->subtype) { return $primary_mime_type[(int) $structure->type] . '/' .$structure->subtype; } return "TEXT/PLAIN"; } function get_part($stream, $msg_number, $mime_type, $structure = false, $part_number = false) { if(!$structure) { $structure = imap_fetchstructure($stream, $msg_number); } if($structure) { if($mime_type == get_mime_type($structure)) { if(!$part_number) { $part_number = "1"; } $text = imap_fetchbody($stream, $msg_number, $part_number); if($structure->encoding == 3) { return imap_base64($text); } else if($structure->encoding == 4) { return imap_qprint($text); } else { return $text; } } if($structure->type == 1) /* multipart */ { while(list($index, $sub_structure) = each($structure->parts)) { if($part_number) { $prefix = $part_number . '.'; } $data = get_part($stream, $msg_number, $mime_type, $sub_structure,$prefix . ($index + 1)); if($data) { return $data; } } // END OF WHILE } // END OF MULTIPART } // END OF STRUTURE return false; } // END OF FUNCTION $connection = imap_open($server, $login, $password); $count = imap_num_msg($connection); for($i = 1; $i <= $count; $i++) { $header = imap_headerinfo($connection, $i); $from = $header->fromaddress; $to = $header->toaddress; $subject = $header->subject; $date = $header->date; $body = get_part($connection, $i, "TEXT/PLAIN"); }

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  • running shell commands with gnu clisp

    - by Paul Nathan
    I'm trying to create a "system" command for clisp that works like this (setq result (system "pwd")) ;;now result is equal to /my/path/here I have something like this: (defun system (cmd) (ext:run-program :output :stream)) But, I am not sure how to transform a stream into a string. I've reviewed the hyperspec and google more than a few times.

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