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  • What is Cyber Monday? [Infographic]

    - by Jason Fitzpatrick
    Nearly everyone is familiar with Black Friday, the massive shopping day right after Thanksgiving, but Cyber Monday is a recent invention. Check out this infographic for the low down. Cyber Monday is only a scant six years old, an invention of online retailers looking to create a shopping day to compete with the in-store frenzy of Black Friday. Although quite a few retailers offer online Black Friday deals, Cyber Monday is a the biggest day for online deals–many shoppers fail to find the things they were looking for on Black Friday and turn to online sources. You can read more about Cyber Monday here or visit the link below for a higher resolution copy of the infographic. What Is Cyber Monday? [YouNeverLose via Mashable] How to See What Web Sites Your Computer is Secretly Connecting To HTG Explains: When Do You Need to Update Your Drivers? How to Make the Kindle Fire Silk Browser *Actually* Fast!

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  • An alternative to a video codec for storing motion changes [on hold]

    - by Andrew Simpson
    I have a 3 dimensional byte array. The 3-d array represents a jpeg image. Each channel/array represents part of the RGB spectrum. I am not interested in retaining black pixels. A black pixel is represented by this atypical arrangement: myarray[0,0,0] =0; myarray[0,0,1] =0; myarray[0,0,2] =0; So, I have flattened this 3d array out to a 1d array by doing this byte[] AFlatArray = new byte[width x height x 3] and then assigning values respective to the coordinate. But like I said I do not want black pixels. So this array has to only contain color pixels with the x,y coordinate. The result I want is to re-represent the image from the i dimension byte array that only contains non-black pixels. How do I do that? It looks like I have to store black pixels as well because of the xy coordinate system. I have tried writing to a binary file but the size of that file is greater than the jpeg file as the jpeg file is compressed. I am using c#.

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  • Is a control tree cached after the first call to FindWindowEx/EnumChildWindows?

    - by Ion Todirel
    I noticed that if you call FindWindowEx or EnumChildWindows against a hWnd that belongs to a window that's not in the foreground, i.e. minimized, then they don't report any children. On the other hand if I first call SetForegroundWindow against the window I'm querying, and after that FindWindowEx or EnumChildWindows, they report all the children. Next calls report all the children even if the window I'm interested in is not in foreground. It's almost it does some sort of caching after the first call?

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  • Ubuntu 12.10 "Turn screen off when inactive for: Never" still turns off

    - by Will
    After a fresh install of Ubuntu 12.10, my screen still goes off after about ten minutes. I've been to the Brightness and Lock control panel. The Turn screen off when inactive for: setting is set for Never. I've been through the dconf Editor searching for power, screen, and idle changing parameters. This doesn't seem to have any effect on the display timeout. Here's one more interesting thing, the screen doesn't go off, per se. It just goes black. Meaning, the back lighting is still on, and all the pixels are black. When it goes black, it does a very pleasant quick dim to black. Similarly, it quickly un-dim's after a key press, mouse movement, or mouse click. So, I'm feeling this is more of a software setting the timeout, not a power saving function.

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  • How can you get a list or traversable tree of bookmarks from within a Firefox Extension?

    - by Nathan
    I am working on a simple Firefox Extension, and I need a list of the user's bookmarks. I have found the nsINavBookmarksService class which appears to be the recommended way of manipulating bookmarks since Firefox 3.0. Strangely I don't see a method that I could use to get a list of all the bookmarks in a folder. I need some way of creating a flat list of all the Bookmark URIs, but without any methods that return information about more than one bookmark I don't see a way to do it.

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  • unable to see gui

    - by Vikasa
    Hey I have Installed UBUNTU 12.04 on vmware work station on windows 7 but when i start up it in vmware i get a message on black screen of ubuntu i.e. " [ 7.3326] pixx4_smbus 0000:00:07.3: Host SMBus controller not enabled! ", and after that it asks for user id and password on black screen and after entering them i still resides in black screen, i am unable to see GUI. please suggest what to do. i am newer to UBUNTU.

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  • Floodfill algorithm for GO

    - by user1048606
    The floodfill algorithm is used in the bucket tool in MS paint and photoshop, but it can also be used for GO and minesweeper. http://en.wikipedia.org/wiki/Flood_fill In go you can capture groups of stones, this website portrays it with two stones. http://www.connectedglobe.com/mindy/cap6.html This is my floodfill method in Java, it is not capturing a group of stones and I have no idea why because to me it makes sense. public void floodfill(int turn, int col, int row){ for(int a = col; a<19; a++){ for(int b = row; b<19; b++){ if(turn == black){ if(stones[col][row] == white){ stones[col][row] = 0; floodfill(black, col-1, row); floodfill(black, col+1, row); floodfill(black, col, row-1); floodfill(black, col, row+1); } } } } } It searches up, down, left, right for all the stones on the board. If the stones are white it captures them by making them 0, which represents empty.

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  • Are any of these quad-tree libraries any good?

    - by Noctis Skytower
    It appears that a certain project of mine will require the use of quad-trees, something that I have never worked with before. From what I have read they should allow substantial performance enhancements than a brute-force attempt at the problem would yield. Are any of these python modules any good? Quadtree 0.1.2 <= No: unable to execute in Python 3.1 QuadTree <= Yes: simple while working with rectangles quadtree.py <= No: no support for needed operations EDIT: Does anyone know of a better implementation that the one presented on the pygame wiki article?

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  • Boundary fill problem

    - by Taaseen
    hi...Im stuck in this bunch of codes...i cant get the pixel to fill up the circle??...any help #include<iostream> #include<glut.h> struct Color{ float red, green, blue; }; Color getPixel(int x, int y){ // gets the color of the pixel at (x,y) Color c; float color[4]; glReadPixels(x,y,1,1,GL_RGBA, GL_FLOAT, color); c.red = color[0]; c.green = color[1]; c.blue = color[2]; return c; } void setPixel(int x, int y, Color c){ glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glPushAttrib(GL_ALL_ATTRIB_BITS); glColor3f(c.red, c.green, c.blue); glBegin(GL_POINTS); glVertex2i(x,y); glEnd(); glPopAttrib(); glFlush(); } void init() { glClearColor(1.0,1.0,1.0,0.0); gluOrtho2D(0.0,300.0,0.0,300.0); } void drawPixel(int x,int y) { glBegin(GL_POINTS); glVertex2i(x,y); glEnd(); glFlush(); } void Boundary_fill(int x,int y,Color thisColor){ Color boundary_color; boundary_color.red=0.0; boundary_color.green=1.0; boundary_color.blue=0.0; Color nextpixel=getPixel(x,y); if((nextpixel.red!=boundary_color.red)&&(nextpixel.blue!=boundary_color.blue)&&(nextpixel.green!=boundary_color.green) && (nextpixel.red!=thisColor.red)&& (nextpixel.blue!=thisColor.blue)&& (nextpixel.green!=thisColor.green)){ setPixel(x,y,thisColor); Boundary_fill((x+1),y,thisColor); Boundary_fill((x-1),y,thisColor); Boundary_fill(x,(y+1),thisColor); Boundary_fill(x,(y-1),thisColor); } } void draw(int x1,int y1, int x, int y){ drawPixel(x1+x,y1+y);//quadrant1 drawPixel(x1+x,y1-y);//quadrant2 drawPixel(x1-x,y1+y);//quadrant3 drawPixel(x1-x,y1-y);//quadrant4 drawPixel(x1+y,y1+x);//quadrant5 drawPixel(x1+y,y1-x);//quadrant6 drawPixel(x1-y,y1+x);//quadrant7 drawPixel(x1-y,y1-x);//quadrant8 } void circle(int px,int py,int r){ int a,b; float p; a=0; b=r; p=(5/4)-r; while(a<=b){ draw(px,py,a,b); if(p<0){ p=p+(2*a)+1; } else{ b=b-1; p=p+(2*a)+1-(2*b); } a=a+1; } } void Circle(void) { Color thisColor; thisColor.red=1.0; thisColor.blue=0.0; thisColor.green=0.0; glClear(GL_COLOR_BUFFER_BIT); glColor3f(0.0,1.0,0.0); glPointSize(2.0); int x0 = 100; int y0 = 150; circle(x0,y0,50); glColor3f(thisColor.red,thisColor.blue,thisColor.green); Boundary_fill(x0,y0,thisColor); } void main(int argc, char**argv) { glutInit(&argc,argv); glutInitDisplayMode(GLUT_SINGLE | GLUT_RGB); glutInitWindowSize(400,400); glutInitWindowPosition(1,1); glutCreateWindow("Boundary fill in a circle:Taaseen And Abhinav"); init(); glutDisplayFunc(Circle); glutMainLoop(); }

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  • What Linux platform is Ubuntu Server

    - by Graeme
    I'm just trying to get an old HP ML150 up and running to learn on. I've installed ubuntu server on it and have found the drivers are all not installed. HP has drivers but I have no clue what platform to download.This is what I have to choose from. » Novell NetWare 6.5 » Red Hat Enterprise Linux 4 (AMD64/EM64T) » Red Hat Enterprise Linux 4 (x86) » Red Hat Enterprise Linux 5 Server (x86) » Red Hat Enterprise Linux 5 Server (x86-64) » SCO OpenServer 5 » SCO OpenServer 6 » SCO UnixWare 7 » SUSE Linux Enterprise Server 10 (AMD64/EM64T) » SUSE Linux Enterprise Server 10 (x86) » SUSE Linux Enterprise Server 9 (AMD64/EM64T) » SUSE Linux Enterprise Server 9 (x86) Any suggestions? Thank you in advance guys for your help.

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  • Image 1 becomes image 2 with sliding effect from left to right?

    - by Paul
    I would like to show a second image appearing while a "door" is closing on my character. I've got my character in the middle of the screen and a door coming from the left. When the door passes my character, I would like to have this second image appearing little by little. So far, I've gotten by with fadingOut the character and then fadingIn my second image of the character at the same position when the door is completely closed, but I would like to have both of them at the same time. (the effect that image 1 becomes image 2 when the door is sliding from left to right). Would you know how to do this with Cocos2d? Here are the images : at first, the character is blue, and the door is coming from the left : Then, behind the black door, the character becomes red, but only behind this door, so it stays blue when the door is not on him, and will become completely red when the door passes the character : EDIT : with this code, the black door hides the red and blue rectangles : (And if i add each of my layers at a different depth, and only use GL_LESS, same thing) blue.position = ccp( size.width*0.5 , size.height/2 ); red.position = ccp( size.width*0.46 , size.height/2 ); black.position = ccp( size.width*0.1 , size.height/2 ); glEnable(GL_DEPTH_TEST); [batch addChild:red z:0]; [batch addChild:black z:2]; glDepthFunc(GL_GREATER); [batch addChild:blue z:1]; glDepthFunc(GL_LESS); id action1 = [CCMoveTo actionWithDuration:3 position:ccp(size.width,size.height/2)]; [black runAction: [CCSequence actions:action1, nil]];

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  • Is there a way to easily convert a series of tarballs of a source tree into a git repository?

    - by Hotei
    I'm new to git and I have a moderately large number of weekly tarballs from a long running project. Each tarball has on average a few hundred files in it. I'm looking for a git strategy that will allow me to add the expanded contents of each tarball to a new git repository, starting from version 1.001 and going through version 1.650. As of this stage of the project 99.5% of tarball(n) is just a copy of version(n-1) - in other words, a perfect candidate for git. The desired end result is to have only the master branch remaining at the end of the process. I think I know git well enough to do this "by hand". As I understand it there is no possibility of a merge conflict since there will be no opportunity to change the master before the next version is added and committed. A shell script is my first guess, but I'm not sure how well bash will like it when git checkout branch_n gets processed while bash is executing in branch_n-1. For the purposes of this project the host environment is Ubuntu 10.4, resources available are 8 Gig RAM, 500 Gig Disk space free and 4 CPU processor at 3.ghz . I don't need someone else to solve the problem but I could use a nudge in the right direction as to how a git expert would approach it. Any advice from someone who's "been there done that" would be appreciated. Hotei PS: I have looked at site's suggested "related questions" and found nothing relevant.

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  • Converting 3 dimension byte array to a single byte array [on hold]

    - by Andrew Simpson
    I have a 3 dimensional byte array. The 3-d array represents a jpeg image. Each channel/array represents part of the RGB spectrum. I am not interested in retaining black pixels. A black pixel is represented by this atypical arrangement: myarray[0,0,0] =0; myarray[0,0,1] =0; myarray[0,0,2] =0; So, I have flattened this 3d array out to a 1d array by doing this byte[] AFlatArray = new byte[width x height x 3] and then assigning values respective to the coordinate. But like I said I do not want black pixels. So this array has to only contain color pixels with the x,y coordinate. The result I want is to re-represent the image from the i dimension byte array that only contains non-black pixels. How do I do that? It looks like I have to store black pixels as well because of the xy coordinate system. I have tried writing to a binary file but the size of that file is greater than the jpeg file as the jpeg file is compressed. I am using c#.

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  • Dynamic Quad/Oct Trees

    - by KKlouzal
    I've recently discovered the power of Quadtrees and Octrees and their role in culling/LOD applications, however I've been pondering on the implementations for a Dynamic Quad/Oct Tree. Such tree would not require a complete rebuild when some of the underlying data changes (Vertex Data). Would it be possible to create such a tree? What would that look like? Could someone point me in the correct direction to get started? The application here would, in my scenario, be used for a dynamically changing spherical landscape with over 10,000,000 verticies. The use of Quad/Oct Trees is obvious for Culling & LOD as well as the benefits from not having to completely recompute the tree when the underlying data changes.

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  • Best solution for getting referral information in PHP

    - by absentx
    I am currently redoing some link structuring on a website. In the past we have used specific php files on the last step to direct the user to the proper place. Example: www.mysite.com/action/go-to-blue.php or www.mysite.com/action/short/go-to-red.php www.mysite.com/action/tall/go-to-red.php We are now restructuring to eliminate the /short/ or /tall/ directory. What this means is now "go-to-blue.php" will be doing some extra processing to make sure it sends the visitor to the proper place. The static method of the past was quite effective, because, well, if they left from that page we knew we had it right. Now since we are 301 redirecting action/short/go-to-red.php to just action/go-to-red.php it is quite important on "go-to-red.php" that we realize a user may have been redirected from /short/ or /tall/. So right now I am using HTTP_REFERRER and of course in my testing that works fine, but after a lot of reading it is clear that this is not a solid solution, so I was starting to brainstorm on other ways to check and make sure we get the proper referral information. If we could check HTTP_REFERRER plus some other test, I would feel confident we have a pretty good system in place to send the visitor to the right place. Some questions/comments: Could I use a session variable or a cookie to accomplish this goal? If so, would that be maintained through the 301 redirect? I don't see why it wouldn't be.. Passing the url in the url is not an option in this case.

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  • Bouncing off a circular Boundary with multiple balls?

    - by Anarkie
    I am making a game like this : Yellow Smiley has to escape from red smileys, when yellow smiley hits the boundary game is over, when red smileys hit the boundary they should bounce back with the same angle they came, like shown below: Every 10 seconds a new red smiley comes in the big circle, when red smiley hits yellow, game is over, speed and starting angle of red smileys should be random. I control the yellow smiley with arrow keys. The biggest problem I have reflecting the red smileys from the boundary with the angle they came. I don't know how I can give a starting angle to a red smiley and bouncing it with the angle it came. I would be glad for any tips! My js source code : var canvas = document.getElementById("mycanvas"); var ctx = canvas.getContext("2d"); // Object containing some global Smiley properties. var SmileyApp = { radius: 15, xspeed: 0, yspeed: 0, xpos:200, // x-position of smiley ypos: 200 // y-position of smiley }; var SmileyRed = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 65 // y-position of smiley }; var SmileyReds = new Array(); for (var i=0; i<5; i++){ SmileyReds[i] = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 67 // y-position of smiley }; SmileyReds[i].xspeed = Math.floor((Math.random()*50)+1); SmileyReds[i].yspeed = Math.floor((Math.random()*50)+1); } function drawBigCircle() { var centerX = canvas.width / 2; var centerY = canvas.height / 2; var radiusBig = 300; ctx.beginPath(); ctx.arc(centerX, centerY, radiusBig, 0, 2 * Math.PI, false); // context.fillStyle = 'green'; // context.fill(); ctx.lineWidth = 5; // context.strokeStyle = '#003300'; // green ctx.stroke(); } function lineDistance( positionx, positiony ) { var xs = 0; var ys = 0; xs = positionx - 350; xs = xs * xs; ys = positiony - 350; ys = ys * ys; return Math.sqrt( xs + ys ); } function drawSmiley(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.7*r, y); ctx.arc(x,y,0.7*r, 0, Math.PI, false); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } function drawSmileyRed(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; //yellow ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.4*r, y+10); ctx.arc(x,y+10,0.4*r, 0, Math.PI, true); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } // --- Animation of smiley moving with constant speed and bounce back at edges of canvas --- var tprev = 0; // this is used to calculate the time step between two successive calls of run function run(t) { requestAnimationFrame(run); if (t === undefined) { t=0; } var h = t - tprev; // time step tprev = t; SmileyApp.xpos += SmileyApp.xspeed * h/1000; // update position according to constant speed SmileyApp.ypos += SmileyApp.yspeed * h/1000; // update position according to constant speed for (var i=0; i<SmileyReds.length; i++){ SmileyReds[i].xpos += SmileyReds[i].xspeed * h/1000; // update position according to constant speed SmileyReds[i].ypos += SmileyReds[i].yspeed * h/1000; // update position according to constant speed } // change speed direction if smiley hits canvas edges if (lineDistance(SmileyApp.xpos, SmileyApp.ypos) + SmileyApp.radius > 300) { alert("Game Over"); } // redraw smiley at new position ctx.clearRect(0,0,canvas.height, canvas.width); drawBigCircle(); drawSmiley(SmileyApp.xpos, SmileyApp.ypos, SmileyApp.radius); for (var i=0; i<SmileyReds.length; i++){ drawSmileyRed(SmileyReds[i].xpos, SmileyReds[i].ypos, SmileyReds[i].radius); } } // uncomment these two lines to get every going // SmileyApp.speed = 100; run(); // --- Control smiley motion with left/right arrow keys function arrowkeyCB(event) { event.preventDefault(); if (event.keyCode === 37) { // left arrow SmileyApp.xspeed = -100; SmileyApp.yspeed = 0; } else if (event.keyCode === 39) { // right arrow SmileyApp.xspeed = 100; SmileyApp.yspeed = 0; } else if (event.keyCode === 38) { // up arrow SmileyApp.yspeed = -100; SmileyApp.xspeed = 0; } else if (event.keyCode === 40) { // right arrow SmileyApp.yspeed = 100; SmileyApp.xspeed = 0; } } document.addEventListener('keydown', arrowkeyCB, true); JSFiddle : http://jsfiddle.net/gj4Q7/

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  • Is this more suited for key value storage or a tree?

    - by JC
    I'm trying to figure out the best way to represent some data. It basically follows the form Manufacturer.Product.Attribute = Value. Something like: Acme.*.MinimumPrice = 100 Acme.ProductA.MinimumPrice = 50 Acme.ProductB.MinimumPrice = 60 Acme.ProductC.DefaultColor = Blue So the minimum price across all Acme products is 100 except in the case of product A and B. I want to store this data in C# and have some function where GetValue("Acme.ProductC.MinimumPrice") returns 100 but GetValue("Acme.ProductA.MinimumPrice") return 50. I'm not sure how to best represent the data. Is there a clean way to code this in C#?

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  • jquery selecting all last elements of an nested tree menu unordered list...not just the :last-child.

    - by Ronedog
    I'm having some trouble figuring this out. I have an unordered list menu that I want to style all the last elements with a folder icon and style all the expandable (parent) elements with a plus.gif image. I wanted to simply change the class by using .addclass() using jquery, which will contain the css to add the background-image. My jquery code below is only selecting the ":last-child", which is placing a folder icon on the last element in the list. i need to place a folder icon in front of all the "li's" that don't hav any children, and place a plus icon in front of all those that do have children. Is there a way to accomplish this? Here's my HTML: <ul id="nav"> <li>Heading 1 <ul> <li>Sub page A <ul> <li>Sub page A - 1 <ul> <li>A - 1: 0</li> <li>A - 1: 1</li> <li>A - 1: 2</li> </ul> </li> <li>Sub page A - 3</li> <li>Sub page A - 2</li> </ul> </li> <li>Sub page B</li> <li>Sub page C <ul> <li>Sub page C - 1 <ul> <li>C - 1: 0</li> <li>C - 1: 1</li> <li>C - 1: 2</li> </ul> </li> <li>Sub page C - 3</li> <li>Sub page C - 2</li> </ul> </li> </ul> </li> <li>Heading 2 <ul> <li>Sub page D</li> <li>Sub page E</li> <li>Sub page F</li> </ul> </li> <li>Heading 3 <ul> <li>Sub page G</li> <li>Sub page H</li> <li>Sub page I</li> </ul> </li> </ul> Here's the jquery code: $(function(){ //add class to last item in each list $('#nav li').find('li:last').addClass('menu_last_child'); });

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  • Can i Automap a tree heirarchy with fluent nhibernate?

    - by NakChak
    Is it possible to auto map a simple nested object structure? Something like this public class Employee : Entity { public Employee() { this.Manages = new List<Employee>(); } public virtual string FirstName { get; set; } public virtual string LastName { get; set; } public virtual bool IsLineManager { get; set; } public virtual Employee Manager { get; set; } public virtual IList<Employee> Manages { get; set; } } Causes the following error at run time: Repeated column in mapping for collection: SharpKtulu.Core.Employee.Manages column: EmployeeFk Is it possible to automap this sort of structure, or do i have over ride the auto mapper for this sort of structure?

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  • Debugging Minimum Translation Vector

    - by SyntheCypher
    I implemented the minimum translation vector from codezealot's tutorial on SAT (Separating Axis Theorem) but I'm having an issue I can't quite figure out. Here's the example I have: As you can see in top and bottom left images regardless of the side the of the green car which red car is penetrating the MTV for the red car still remains as a negative number also here is the same example when the front of the red car is facing the opposite direction the number will always be positive. When the red car is past the half way through the green car it should switch polarity. I thought I'd compensated for this in my code, but apparently not either that or it's a bug I can find. Here is my function for finding and returning the MTV, any help would be much appreciated: Code

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  • Can I Automap a tree hierarchy with Fluent NHibernate?

    - by NakChak
    Is it possible to auto map a simple nested object structure? Something like this: public class Employee : Entity { public Employee() { this.Manages = new List<Employee>(); } public virtual string FirstName { get; set; } public virtual string LastName { get; set; } public virtual bool IsLineManager { get; set; } public virtual Employee Manager { get; set; } public virtual IList<Employee> Manages { get; set; } } It causes the following error at run time: Repeated column in mapping for collection: SharpKtulu.Core.Employee.Manages column: EmployeeFk Is it possible to automap this sort of structure, or do I have override the auto mapper for this sort of structure?

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  • What's the best way to compare blocks in a matching game that can be multiple colors?

    - by Ryan Detzel
    I have a match 3-4 game and the blocks can be one of 7 colors. There are an addition 7 blocks that are a mix of the original 7 colors so for example there is a red and blue block and there is also a red/blue block which can be matched with either the red or the blue. My original thought is just to use binary operations so. int red = 0x000000001; int blue = 0x000000010; int redblue = 0x000000011; Then just do an & operation so see if they match. Does this sound like a decent plan or am I over complicating it? edit: Better yet so it's more readable. int red = 1; int blue = 2; int red_blue = 3; int yellow = 4; int red_yellow = 5; maybe as defines or static vars?

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