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  • How to make an id auto_increment from where it last left off after a record delete?

    - by Sammy
    This isn't that big of a deal but I was wondering if it can be done. Right now when I insert a new record, the id field which is auto_increment and set as primary key increases it's value by one: id | first_name | last_name ------------------------------ 1 | John | Smith 2 | Jane | Doe But if I delete record 2, the next one I insert is going to have an id of 3. Is there any way to make it have an id of 2 automatically (without having to manually insert it)?

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  • How to insert multiple check-box values inside database when one or more will be left unchecked?

    - by Sally
    I have a form that contains 5 check boxes. The user may select one or more of these check boxes. The user may select 2 and leave 3 unchecked or select 4 and leave one unchecked and so on, in that case how can I write the php/mysql code that will insert the form data into the database. With just one selection it's easy, I would do: $checkbox_value = $_POST['i_agree']; mysql_query("INSERT INTO terms (user, pass, conditions) VALUES ('$user','$pass','$checkbox_value')"); But how can I write this when there are multiple check box options and only one or more of them will be checked? I want to insert them all in one column called "tags" separated by commas.

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  • radeon display driver clones monitors while using Xinerama

    - by gregmuellegger
    I'm trying to get my two Radeon HD 4770 cards working with three monitors. Xinerama works so far in the way that I have two fully working monitors were I can move windows from one to the other. My problem now is that my third monitor is a clone of my second monitor (displaying the exact same thing). These monitors are connected to the same graphic card ("Screen Middle" and "Screen Right" in the xorg.conf below). Here is my xorg.conf: Section "ServerLayout" Identifier "ThreeMonitors" Screen "Screen Left" 0 0 Screen "Screen Middle" RightOf "Screen Left" Screen "Screen Right" RightOf "Screen Middle" Option "Xinerama" EndSection Section "Monitor" Identifier "Monitor Left" Option "DPMS" EndSection Section "Monitor" Identifier "Monitor Middle" Option "DPMS" EndSection Section "Monitor" Identifier "Monitor Right" Option "DPMS" EndSection Section "Device" Identifier "Device Left" Driver "radeon" VendorName "ATI Technologies Inc" BoardName "ATI Radeon HD 4770 [RV740]" BusID "PCI:3:0:0" Screen 0 EndSection Section "Screen" Identifier "Screen Left" Device "Device Left" Monitor "Monitor Left" SubSection "Display" Depth 24 EndSubSection EndSection Section "Device" Identifier "Device Middle" Driver "radeon" VendorName "ATI Technologies Inc" BoardName "ATI Radeon HD 4770 [RV740]" BusID "PCI:2:0:0" Screen 0 EndSection Section "Screen" Identifier "Screen Middle" Device "Device Middle" Monitor "Monitor Middle" SubSection "Display" Depth 24 EndSubSection EndSection Section "Device" Identifier "Device Right" Driver "radeon" VendorName "ATI Technologies Inc" BoardName "ATI Radeon HD 4770 [RV740]" BusID "PCI:2:0:1" Screen 1 EndSection Section "Screen" Identifier "Screen Right" Device "Device Right" Monitor "Monitor Right" SubSection "Display" Depth 24 EndSubSection EndSection I'm using a fresh Kubuntu 10.10 installation with propsed-updates enabled since this repo contains a xorg fix for using multiple graphic cards. I hope someone can help me out. Very many thanks!!

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  • How can I align the left edge of HTML form elements using CSS?

    - by Naor
    I want to do the following: aa: ________ bbbb: ________ ccc: ________ So I wrote: <span>aa:</span><input type="text" /><br/> <span>bbbb:</span><input type="text" /><br/> <span>cc:</span><input type="text" /> And I get: aa:________ bbbb:________ ccc:________ I know I can arrange it easy with table. How do I do it without tables with as few css as I can. Thanks.

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  • Please quickly help with this problem I got 52 minutes left.

    - by Hamish Grubijan
    Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz". Woman said use any common language. Please make it short and test it. My screen is small. Thanks. P.S. I have test anxiety particularly after talking to people in suits. I also stayed up all night studying Java codes.

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  • Sorting arrays in java

    - by user360706
    Write a static method in Java : public static void sortByFour (int[] arr) That receives as a paramater an array full of non-negative numbers (zero or positive) and sorts the array in the following way : In the beginning of the array all the numbers that devide by four without a remainder will appear. After them all the numbers in the array that devide by 4 with a remainder of 1 will appear. After them all the numbers in the array that devide by 4 with a remainder of 2 will appear. In the end of the array all the rest numbers (those who divide by 4 with the remainder 3) will appear. (The order of the numbers in each group doesn't matter) The method must be the most efficient it can. This is what I wrote but unfortunately it doesn't work well... :( public static void swap( int[] arr, int left, int right ) { int temp = arr[left]; arr[left] = arr[right]; arr[right] = temp; } public static void sortByFour( int[] arr ) { int left = 0; int right = ( arr.length - 1 ); int mid = ( arr.length / 2 ); while ( left < right ) { if ( ( arr[left] % 4 ) > ( arr[right] % 4 ) ) { swap( arr, left, right ); right--; } if ( ( arr[left] % 4 ) == ( arr[right] % 4 ) ) left++; else left++; } } Can someone please help me by fixing my code so that it will work well or rewriting it?

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  • Need help with height 100% layout

    - by serg
    I am trying to build the following layout (file browser type of thing, left block would contain a list of files, right panel would contain selected file content): <------------- MENU -------------------> <--- LEFT ----><------- RIGHT ---------> <--- LEFT ----><------- RIGHT ---------> <--- LEFT ----><------- RIGHT ---------> <--- LEFT ----><------- RIGHT ---------> <--- LEFT ----><------- RIGHT ---------> <--- LEFT ----><------- RIGHT ---------> The page itself shouldn't have any scrollbars. Menu has 100% width and fixed height Left block has fixed width and 100% height. If content is taller - scroll bar appears inside the left block only. Right block contains <pre> element and takes the remaining width and 100% height. If content is wider or taller - scrollbar appears inside the right block only. This is what I have so far: http://jsbin.com/uqegi4/3/edit The problem is fixed menu height messes up 100% height calculation and all scrollbars inside left and right blocks appear at wrong time. I don't care about cross browser compatibility, only Chrome matters. Thanks.

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  • How long can a hash left out in the open be considered safe?

    - by Xeoncross
    If I were to leave a SHA2 family hash out on my website - how long would it be considered safe? How long would I have before I could be sure that someone would find a collision for it and know what was hashed? I know that the amount of time would be based on the computational power of the one seeking to break it. It would also depend on the string length, but I'm curious just how secure hashes are. Since many of us run web-servers we constantly have to be prepared for the day when someone might make it all the way to the database which stores the user hashes. So, move the server security out of the way and then what do you have? This is a slightly theoretical area for many of the people I have talked with, so I would love to actually have some more information about average expectations for cracking.

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  • SQL - date variable isn't being parsed correctly?

    - by Bill Sambrone
    I am pulling a list of invoices filtered by a starting and ending date, and further filtered by type of invoice from a SQL table. When I specify a range of 2013-07-01 through 2013-09-30 I am receiving 2 invoices per company when I expect 3. When I use the built in select top 1000 query in SSMS and add my date filters, all the expected invoices appear. Here is my fancy query that I'm using that utilizing variables that are fed in: DECLARE @ReportStart datetime DECLARE @ReportStop datetime SET @ReportStart = '2013-07-01' SET @ReportStop = '2013-09-30' SELECT Entity_Company.CompanyName, Reporting_AgreementTypes.Description, Reporting_Invoices.InvoiceAmount, ISNULL(Reporting_ProductCost.ProductCost,0), (Reporting_Invoices.InvoiceAmount - ISNULL(Reporting_ProductCost.ProductCost,0)), (Reporting_AgreementTypes.Description + Entity_Company.CompanyName), Reporting_Invoices.InvoiceDate FROM Reporting_Invoices JOIN Entity_Company ON Entity_Company.ClientID = Reporting_Invoices.ClientID LEFT JOIN Reporting_ProductCost ON Reporting_ProductCost.InvoiceNumber =Reporting_Invoices.InvoiceNumber JOIN Reporting_AgreementTypes ON Reporting_AgreementTypes.AgreementTypeID = Reporting_Invoices.AgreementTypeID WHERE Reporting_Invoices.AgreementTypeID = (SELECT AgreementTypeID FROM Reporting_AgreementTypes WHERE Description = 'Resold Services') AND Reporting_Invoices.InvoiceDate >= @ReportStart AND Reporting_Invoices.InvoiceDate <= @ReportStop ORDER BY CompanyName,InvoiceDate The above only returns 2 invoices per company. When I run a much more basic query through SSMS I get 3 as expected, which looks like: SELECT TOP 1000 [InvoiceID] ,[AgreementID] ,[AgreementTypeID] ,[InvoiceDate] ,[Comment] ,[InvoiceAmount] ,[InvoiceNumber] ,[TicketID] ,Entity_Company.CompanyName FROM Reporting_Invoices JOIN Entity_Company ON Entity_Company.ClientID = Reporting_Invoices.ClientID WHERE Entity_Company.ClientID = '9' AND AgreementTypeID = (SELECT AgreementTypeID FROM Reporting_AgreementTypes WHERE Description = 'Resold Services') AND Reporting_Invoices.InvoiceDate >= '2013-07-01' AND Reporting_Invoices.InvoiceDate <= '2013-09-30' ORDER BY InvoiceDate DESC I've tried stripping down the 1st query to include only a client ID on the original invoice table, the invoice date, and nothing else. Still only get 2 invoices instead of the expected 3. I've also tried manually entering the dates instead of the @ variables, same result. I confirmed that InvoiceDate is defined as a datetime in the table. I've tried making all JOIN's a FULL JOIN to see if anything is hiding, but no change. Here is how I stripped down the original query to keep all other tables out of the mix and yet I'm still getting only 2 invoices per client ID instead of 3 (I manually entered the ID for the type filter): --DECLARE @ReportStart datetime --DECLARE @ReportStop datetime --SET @ReportStart = '2013-07-01' --SET @ReportStop = '2013-09-30' SELECT --Entity_Company.CompanyName, --Reporting_AgreementTypes.Description, Reporting_Invoices.ClientID, Reporting_Invoices.InvoiceAmount, --ISNULL(Reporting_ProductCost.ProductCost,0), --(Reporting_Invoices.InvoiceAmount - ISNULL(Reporting_ProductCost.ProductCost,0)), --(Reporting_AgreementTypes.Description + Entity_Company.CompanyName), Reporting_Invoices.InvoiceDate FROM Reporting_Invoices --JOIN Entity_Company ON Entity_Company.ClientID = Reporting_Invoices.ClientID --LEFT JOIN Reporting_ProductCost ON Reporting_ProductCost.InvoiceNumber = Reporting_Invoices.InvoiceNumber --JOIN Reporting_AgreementTypes ON Reporting_AgreementTypes.AgreementTypeID = Reporting_Invoices.AgreementTypeID WHERE Reporting_Invoices.AgreementTypeID = '22'-- (SELECT AgreementTypeID FROM Reporting_AgreementTypes WHERE Description = 'Resold Services') AND Reporting_Invoices.InvoiceDate >= '2013-07-01' AND Reporting_Invoices.InvoiceDate <= '2013-09-30' ORDER BY ClientID,InvoiceDate This strikes me as really weird as it is pretty much the same query as the SSMS generated one that returns correct results. What am I overlooking? UPDATE I've further refined my "test query" that is returning only 2 invoices per company to help troubleshoot this. Below is the query and a relevant subset of data for 1 company from the appropriate tables: SELECT Reporting_Invoices.ClientID, Reporting_AgreementTypes.Description, Reporting_Invoices.InvoiceAmount, Reporting_Invoices.InvoiceDate FROM Reporting_Invoices JOIN Reporting_AgreementTypes ON Reporting_AgreementTypes.AgreementTypeID = Reporting_Invoices.AgreementTypeID WHERE Reporting_Invoices.AgreementTypeID = (SELECT AgreementTypeID FROM Reporting_AgreementTypes WHERE Description = 'Resold Services') AND Reporting_Invoices.InvoiceDate >= '2013-07-01T00:00:00' AND Reporting_Invoices.InvoiceDate <= '2013-09-30T00:00:00' ORDER BY Reporting_Invoices.ClientID,InvoiceDate The above only returns 2 invoices. Here is the relevant table data: Relevant data from Reporting_AgreementTypes AgreementTypeID Description 22 Resold Services Relevant data from Reporting_Invoices InvoiceID ClientID AgreementID AgreementTypeID InvoiceDate 16111 9 757 22 2013-09-30 00:00:00.000 15790 9 757 22 2013-08-30 00:00:00.000 15517 9 757 22 2013-07-31 00:00:00.000 Actual results from my new modified query ClientID Description InvoiceAmount InvoiceDate 9 Resold Services 3513.79 7/31/13 00:00:00 9 Resold Services 3570.49 8/30/13 00:00:00

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  • How to stop rendering invisible faces

    - by TheMorfeus
    I am making a voxel-based game, and for needs of it, i am creating a block rendering engine. Point is, that i need to generate lots of cubes. Every time i render more than 16x16x16 chunk of theese blocks, my FPS is dropped down hardly, because it renders all 6 faces of all of theese cubes. THat's 24 576 quads, and i dont want that. So, my question is, How to stop rendering vertices(or quads) that are not visible, and therefore increase performance of my game? Here is class for rendering of a block: public void renderBlock(int posx, int posy, int posz) { try{ //t.bind(); glEnable(GL_CULL_FACE); glCullFace(GL_BACK);// or even GL_FRONT_AND_BACK */); glPushMatrix(); GL11.glTranslatef((2*posx+0.5f),(2*posy+0.5f),(2*posz+0.5f)); // Move Right 1.5 Units And Into The Screen 6.0 GL11.glRotatef(rquad,1.0f,1.0f,1.0f); glBegin(GL_QUADS); // Draw A Quad GL11.glColor3f(0.5f, 0.4f, 0.4f); // Set The Color To Green GL11.glTexCoord2f(0,0); GL11.glVertex3f( 1f, 1f,-1f); // Top Right Of The Quad (Top) GL11.glTexCoord2f(1,0); GL11.glVertex3f(-1f, 1f,-1f); // Top Left Of The Quad (Top) GL11.glTexCoord2f(1,1); GL11.glVertex3f(-1f, 1f, 1f); // Bottom Left Of The Quad (Top) GL11.glTexCoord2f(0,1); GL11.glVertex3f( 1f, 1f, 1f); // Bottom Right Of The Quad (Top) //GL11.glColor3f(1.2f,0.5f,0.9f); // Set The Color To Orange GL11.glTexCoord2f(0,0); GL11.glVertex3f( 1f,-1f, 1f); // Top Right Of The Quad (Bottom) GL11.glTexCoord2f(0,1); GL11.glVertex3f(-1f,-1f, 1f); // Top Left Of The Quad (Bottom) GL11.glTexCoord2f(1,1); GL11.glVertex3f(-1f,-1f,-1f); // Bottom Left Of The Quad (Bottom) GL11.glTexCoord2f(1,0); GL11.glVertex3f( 1f,-1f,-1f); // Bottom Right Of The Quad (Bottom) //GL11.glColor3f(1.0f,0.0f,0.0f); // Set The Color To Red GL11.glTexCoord2f(0,0); GL11.glVertex3f( 1f, 1f, 1f); // Top Right Of The Quad (Front) GL11.glTexCoord2f(1,0); GL11.glVertex3f(-1f, 1f, 1f); // Top Left Of The Quad (Front) GL11.glTexCoord2f(1,1); GL11.glVertex3f(-1f,-1f, 1f); // Bottom Left Of The Quad (Front) GL11.glTexCoord2f(0,1); GL11.glVertex3f( 1f,-1f, 1f); // Bottom Right Of The Quad (Front) //GL11.glColor3f(1f,0.5f,0.0f); // Set The Color To Yellow GL11.glTexCoord2f(0,0); GL11.glVertex3f( 1f,-1f,-1f); // Bottom Left Of The Quad (Back) GL11.glTexCoord2f(1,0); GL11.glVertex3f(-1f,-1f,-1f); // Bottom Right Of The Quad (Back) GL11.glTexCoord2f(1,1); GL11.glVertex3f(-1f, 1f,-1f); // Top Right Of The Quad (Back) GL11.glTexCoord2f(0,1); GL11.glVertex3f( 1f, 1f,-1f); // Top Left Of The Quad (Back) //GL11.glColor3f(0.0f,0.0f,0.3f); // Set The Color To Blue GL11.glTexCoord2f(0,1); GL11.glVertex3f(-1f, 1f, 1f); // Top Right Of The Quad (Left) GL11.glTexCoord2f(1,1); GL11.glVertex3f(-1f, 1f,-1f); // Top Left Of The Quad (Left) GL11.glTexCoord2f(1,0); GL11.glVertex3f(-1f,-1f,-1f); // Bottom Left Of The Quad (Left) GL11.glTexCoord2f(0,0); GL11.glVertex3f(-1f,-1f, 1f); // Bottom Right Of The Quad (Left) //GL11.glColor3f(0.5f,0.0f,0.5f); // Set The Color To Violet GL11.glTexCoord2f(0,0); GL11.glVertex3f( 1f, 1f,-1f); // Top Right Of The Quad (Right) GL11.glTexCoord2f(1,0); GL11.glVertex3f( 1f, 1f, 1f); // Top Left Of The Quad (Right) GL11.glTexCoord2f(1,1); GL11.glVertex3f( 1f,-1f, 1f); // Bottom Left Of The Quad (Right) GL11.glTexCoord2f(0,1); GL11.glVertex3f( 1f,-1f,-1f); // Bottom Right Of The Quad (Right) //rquad+=0.0001f; glEnd(); glPopMatrix(); }catch(NullPointerException t){t.printStackTrace(); System.out.println("rendering block failed");} } Here is code that renders them: private void render() { GL11.glClear(GL11.GL_COLOR_BUFFER_BIT|GL11.GL_DEPTH_BUFFER_BIT); for(int y=0; y<32; y++){ for(int x=0; x<16; x++){ for(int z=0; z<16; z++) { b.renderBlock(x, y, z); } } } }

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  • How to get left-top and right-buttom latitude and longitude of map in MapKit For iPad ?

    - by damniatx
    Hi, i'm looking for answer about getting latitude and longitude from uimapkit. there is same problem that has been answered, but it didn't give right coordinate. http://yit.me/3ddp73 it's code from thread i'm linking above. CLLocationCoordinate2D topLeft, bottomRight; topLeft = [mapView convertPoint:CGPointMake(0,0) toCoordinateFromView:mapView]; CGPoint pointBottomRight = CGPointMake(mapView.frame.size.width, mapView.frame.size.height); bottomRight = [mapView convertPoint:pointBottomRight toCoordinateFromView:mapView]; NSLog(@"topleft = %f", topLeft); NSLog(@"bottom right = %f", bottomRight); any idea to fix this issue ? thanks

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  • Calling recursive function twice consecutively

    - by Zack
    #include <stdio.h> #define LENGTH 16 void makeBranches(int, int); void display(int, int); int main(){ makeBranches(0, LENGTH-1); } void makeBranches(int left, int right){ if(left >= right){ return; } else{ display(left, right); makeBranches(left, (right+left)/2); makeBranches((right+left/2)+1, right); } } void display(int left, int right){ printf("%d, %d", left, right); int mid = (left+right)/2; int i; for(i = left; i <= right; i++){ if(i == mid) printf("X"); else printf("-"); } if(right == LENGTH-1) printf("\n"); } The problem that I am having is the second call of makeBranches only executes with the values that caused the first call of makeBranches to return and not the original values that the first call used.

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  • JMS Step 1 - How to Create a Simple JMS Queue in Weblogic Server 11g

    - by John-Brown.Evans
    JMS Step 1 - How to Create a Simple JMS Queue in Weblogic Server 11g ol{margin:0;padding:0} .c5{vertical-align:top;width:156pt;border-style:solid;border-color:#000000;border-width:1pt;padding:0pt 2pt 0pt 2pt} .c7{list-style-type:disc;margin:0;padding:0} .c4{background-color:#ffffff} .c14{color:#1155cc;text-decoration:underline} .c6{height:11pt;text-align:center} .c13{color:inherit;text-decoration:inherit} .c3{padding-left:0pt;margin-left:36pt} .c0{border-collapse:collapse} .c12{text-align:center} .c1{direction:ltr} .c8{background-color:#f3f3f3} .c2{line-height:1.0} .c11{font-style:italic} .c10{height:11pt} .c9{font-weight:bold} .title{padding-top:24pt;line-height:1.15;text-align:left;color:#000000;font-size:36pt;font-family:"Arial";font-weight:bold;padding-bottom:6pt}.subtitle{padding-top:18pt;line-height:1.15;text-align:left;color:#666666;font-style:italic;font-size:24pt;font-family:"Georgia";padding-bottom:4pt} li{color:#000000;font-size:10pt;font-family:"Arial"} p{color:#000000;font-size:10pt;margin:0;font-family:"Arial"} h1{padding-top:0pt;line-height:1.15;text-align:left;color:#666;font-size:18pt;font-family:"Arial";font-weight:normal;padding-bottom:0pt} h2{padding-top:0pt;line-height:1.15;text-align:left;color:#666;font-size:14pt;font-family:"Arial";font-weight:normal;padding-bottom:0pt} h3{padding-top:0pt;line-height:1.15;text-align:left;color:#666;font-size:12pt;font-family:"Arial";font-weight:normal;padding-bottom:0pt} h4{padding-top:0pt;line-height:1.15;text-align:left;color:#666;font-style:italic;font-size:11pt;font-family:"Arial";padding-bottom:0pt} h5{padding-top:0pt;line-height:1.15;text-align:left;color:#666;font-size:10pt;font-family:"Arial";font-weight:normal;padding-bottom:0pt} h6{padding-top:0pt;line-height:1.15;text-align:left;color:#666;font-style:italic;font-size:10pt;font-family:"Arial";padding-bottom:0pt} This example shows the steps to create a simple JMS queue in WebLogic Server 11g for testing purposes. For example, to use with the two sample programs QueueSend.java and QueueReceive.java which will be shown in later examples. Additional, detailed information on JMS can be found in the following Oracle documentation: Oracle® Fusion Middleware Configuring and Managing JMS for Oracle WebLogic Server 11g Release 1 (10.3.6) Part Number E13738-06 http://docs.oracle.com/cd/E23943_01/web.1111/e13738/toc.htm 1. Introduction and Definitions A JMS queue in Weblogic Server is associated with a number of additional resources: JMS Server A JMS server acts as a management container for resources within JMS modules. Some of its responsibilities include the maintenance of persistence and state of messages and subscribers. A JMS server is required in order to create a JMS module. JMS Module A JMS module is a definition which contains JMS resources such as queues and topics. A JMS module is required in order to create a JMS queue. Subdeployment JMS modules are targeted to one or more WLS instances or a cluster. Resources within a JMS module, such as queues and topics are also targeted to a JMS server or WLS server instances. A subdeployment is a grouping of targets. It is also known as advanced targeting. Connection Factory A connection factory is a resource that enables JMS clients to create connections to JMS destinations. JMS Queue A JMS queue (as opposed to a JMS topic) is a point-to-point destination type. A message is written to a specific queue or received from a specific queue. The objects used in this example are: Object Name Type JNDI Name TestJMSServer JMS Server TestJMSModule JMS Module TestSubDeployment Subdeployment TestConnectionFactory Connection Factory jms/TestConnectionFactory TestJMSQueue JMS Queue jms/TestJMSQueue 2. Configuration Steps The following steps are done in the WebLogic Server Console, beginning with the left-hand navigation menu. 2.1 Create a JMS Server Services > Messaging > JMS Servers Select New Name: TestJMSServer Persistent Store: (none) Target: soa_server1  (or choose an available server) Finish The JMS server should now be visible in the list with Health OK. 2.2 Create a JMS Module Services > Messaging > JMS Modules Select New Name: TestJMSModule Leave the other options empty Targets: soa_server1  (or choose the same one as the JMS server)Press Next Leave “Would you like to add resources to this JMS system module” unchecked and  press Finish . 2.3 Create a SubDeployment A subdeployment is not necessary for the JMS queue to work, but it allows you to easily target subcomponents of the JMS module to a single target or group of targets. We will use the subdeployment in this example to target the following connection factory and JMS queue to the JMS server we created earlier. Services > Messaging > JMS Modules Select TestJMSModule Select the Subdeployments  tab and New Subdeployment Name: TestSubdeployment Press Next Here you can select the target(s) for the subdeployment. You can choose either Servers (i.e. WebLogic managed servers, such as the soa_server1) or JMS Servers such as the JMS Server created earlier. As the purpose of our subdeployment in this example is to target a specific JMS server, we will choose the JMS Server option. Select the TestJMSServer created earlier Press Finish 2.4  Create a Connection Factory Services > Messaging > JMS Modules Select TestJMSModule  and press New Select Connection Factory  and Next Name: TestConnectionFactory JNDI Name: jms/TestConnectionFactory Leave the other values at default On the Targets page, select the Advanced Targeting  button and select TestSubdeployment Press Finish The connection factory should be listed on the following page with TestSubdeployment and TestJMSServer as the target. 2.5 Create a JMS Queue Services > Messaging > JMS Modules Select TestJMSModule  and press New Select Queue and Next Name: TestJMSQueueJNDI Name: jms/TestJMSQueueTemplate: NonePress Next Subdeployments: TestSubdeployment Finish The TestJMSQueue should be listed on the following page with TestSubdeployment and TestJMSServer. Confirm the resources for the TestJMSModule. Using the Domain Structure tree, navigate to soa_domain > Services > Messaging > JMS Modules then select TestJMSModule You should see the following resources The JMS queue is now complete and can be accessed using the JNDI names jms/TestConnectionFactory andjms/TestJMSQueue. In the following blog post in this series, I will show you how to write a message to this queue, using the WebLogic sample Java program QueueSend.java.

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  • How do we greatly optimize our MySQL database (or replace it) when using joins?

    - by jkaz
    Hi there, This is the first time I'm approaching an extremely high-volume situation. This is an ad server based on MySQL. However, the query that is used incorporates a lot of JOINs and is generally just slow. (This is Rails ActiveRecord, btw) sel = Ads.find(:all, :select = '*', :joins = "JOIN campaigns ON ads.campaign_id = campaigns.id JOIN users ON campaigns.user_id = users.id LEFT JOIN countries ON countries.campaign_id = campaigns.id LEFT JOIN keywords ON keywords.campaign_id = campaigns.id", :conditions = [flashstr + "keywords.word = ? AND ads.format = ? AND campaigns.cenabled = 1 AND (countries.country IS NULL OR countries.country = ?) AND ads.enabled = 1 AND campaigns.dailyenabled = 1 AND users.uenabled = 1", kw, format, viewer['country'][0]], :order = order, :limit = limit) My questions: Is there an alternative database like MySQL that has JOIN support, but is much faster? (I know there's Postgre, still evaluating it.) Otherwise, would firing up a MySQL instance, loading a local database into memory and re-loading that every 5 minutes help? Otherwise, is there any way I could switch this entire operation to Redis or Cassandra, and somehow change the JOIN behavior to match the (non-JOIN-able) nature of NoSQL? Thank you!

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  • Need to add WHERE condition to query

    - by Angel Carlson
    I am trying to modify edit_orders.php in Zen Cart. Hoping someone might be able to help me add a condition to a query. I need the queries below to specify that the items selected from TABLE_PRODUCTS_DESCRIPTION and TABLE_CATEGORIES_DESCRIPTION must have a language_id = 1. Would be so grateful for any help you could provide. // ############################################################################ // Get List of All Products // ############################################################################ //$result = zen_db_query("SELECT products_name, p.products_id, x.categories_name, ptc.categories_id FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON pd.products_id=p.products_id LEFT JOIN " . TABLE_PRODUCTS_TO_CATEGORIES . " ptc ON ptc.products_id=p.products_id LEFT JOIN " . TABLE_CATEGORIES_DESCRIPTION . " cd ON cd.categories_id=ptc.categories_id LEFT JOIN " . TABLE_CATEGORIES_DESCRIPTION . " x ON x.categories_id=ptc.categories_id ORDER BY categories_id"); $result = $db -> Execute("SELECT products_name, p.products_id, categories_name, ptc.categories_id FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON pd.products_id=p.products_id LEFT JOIN " . TABLE_PRODUCTS_TO_CATEGORIES . " ptc ON ptc.products_id=p.products_id LEFT JOIN " . TABLE_CATEGORIES_DESCRIPTION . " cd ON cd.categories_id=ptc.categories_id ORDER BY categories_name");

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  • Performance of inter-database query (between linked servers)

    - by Swoosh
    I have an import between 2 linked servers. I basically got to get the data from a multiple join into a table on my side. The current query is something like this: select a.* from db1.dbo.tbl1 a inner join db1.dbo.tbl2 on ... inner join db1.dbo.tbl3 on ... inner join db1.dbo.tbl4 on ... inner join db2.dbo.myside on ... db1 = linked server db2 = my own database After this one, I am using an insert into + select to add this data in my table which is located in db2. (usually few hundred records - this import running once a minute) My question is related to performance. The tables on the linked server (tbl1, tbl2, tbl3, tbl4) are huge tables, with millions of records, and it is slowing down the import process. I was told that, if I do the join on the "other" side (db1 - linked server) for example in a stored procedure, than, even if the query looks the same, it would run faster. Is that right? This is kinda hard to test. Note that the join contains a table from my database too. Also. are there other "tricks" I could use in order to make this run faster? Thanks

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  • Does this query fetch unnecessary information? Should I change the query?

    - by Camran
    I have this classifieds website, and I have about 7 tables in MySql where all data is stored. I have one main table, called "classifieds". In the classifieds table, there is a column called classified_id. This is not the PK, or a key whatsoever. It is just a number which is used for me to JOIN table records together. Ex: classifieds table: fordon table: id => 33 id => 12 classified_id => 10 classified_id => 10 ad_id => 'bmw_m3_92923' This above is linked together by the classified_id column. Now to the Q, I use this method to fetch all records WHERE the column ad_id matches any of the values inside an array, called in this case $ad_arr: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id WHERE mt.ad_id IN ('$ad_arr')"; Is this good or would this actually fetch unnecessary information? Check out this Q I posted couple of days ago. In the comments HLGEM is commenting that it is wrong etc etc. What do you think? http://stackoverflow.com/questions/2782275/another-rookie-question-how-to-implement-count-here Thanks

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  • slow mysql count because of subselect

    - by frgt10
    how to make this select statement more faster? the first left join with the subselect is making it slower... mysql> SELECT COUNT(DISTINCT w1.id) AS AMOUNT FROM tblWerbemittel w1 JOIN tblVorgang v1 ON w1.object_group = v1.werbemittel_id INNER JOIN ( SELECT wmax.object_group, MAX( wmax.object_revision ) wmaxobjrev FROM tblWerbemittel wmax GROUP BY wmax.object_group ) AS wmaxselect ON w1.object_group = wmaxselect.object_group AND w1.object_revision = wmaxselect.wmaxobjrev LEFT JOIN ( SELECT vmax.object_group, MAX( vmax.object_revision ) vmaxobjrev FROM tblVorgang vmax GROUP BY vmax.object_group ) AS vmaxselect ON v1.object_group = vmaxselect.object_group AND v1.object_revision = vmaxselect.vmaxobjrev LEFT JOIN tblWerbemittel_has_tblAngebot wha ON wha.werbemittel_id = w1.object_group LEFT JOIN tblAngebot ta ON ta.id = wha.angebot_id LEFT JOIN tblLieferanten tl ON tl.id = ta.lieferant_id AND wha.zuschlag = (SELECT MAX(zuschlag) FROM tblWerbemittel_has_tblAngebot WHERE werbemittel_id = w1.object_group) WHERE w1.flags =0 AND v1.flags=0; +--------+ | AMOUNT | +--------+ | 1982 | +--------+ 1 row in set (1.30 sec) Some indexes has been already set and as EXPLAIN shows they were used. +----+--------------------+-------------------------------+--------+----------------------------------------+----------------------+---------+-----------------------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+--------------------+-------------------------------+--------+----------------------------------------+----------------------+---------+-----------------------------------------------+------+----------------------------------------------+ | 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 2072 | | | 1 | PRIMARY | v1 | ref | werbemittel_group,werbemittel_id_index | werbemittel_group | 4 | wmaxselect.object_group | 2 | Using where | | 1 | PRIMARY | <derived3> | ALL | NULL | NULL | NULL | NULL | 3376 | | | 1 | PRIMARY | w1 | eq_ref | object_revision,or_og_index | object_revision | 8 | wmaxselect.wmaxobjrev,wmaxselect.object_group | 1 | Using where | | 1 | PRIMARY | wha | ref | PRIMARY,werbemittel_id_index | werbemittel_id_index | 4 | dpd.w1.object_group | 1 | | | 1 | PRIMARY | ta | eq_ref | PRIMARY | PRIMARY | 4 | dpd.wha.angebot_id | 1 | | | 1 | PRIMARY | tl | eq_ref | PRIMARY | PRIMARY | 4 | dpd.ta.lieferant_id | 1 | Using index | | 4 | DEPENDENT SUBQUERY | tblWerbemittel_has_tblAngebot | ref | PRIMARY,werbemittel_id_index | werbemittel_id_index | 4 | dpd.w1.object_group | 1 | | | 3 | DERIVED | vmax | index | NULL | object_revision_uq | 8 | NULL | 4668 | Using index; Using temporary; Using filesort | | 2 | DERIVED | wmax | range | NULL | or_og_index | 4 | NULL | 2168 | Using index for group-by | +----+--------------------+-------------------------------+--------+----------------------------------------+----------------------+---------+-----------------------------------------------+------+----------------------------------------------+ 10 rows in set (0.01 sec) The main problem while the statement above takes about 2 seconds seems to be the subselect where no index can be used. How to write the statement even more faster? Thanks for help. MT

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