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  • Another Spring + Hibernate + JPA question

    - by Albinoswordfish
    I'm still struggling with changing my Spring Application to use Hibernate with JPA to do database activities. Well apparently from a previous post I need an persistence.xml file. However do I need to make changes to my current DAO class? public class JdbcProductDao extends Dao implements ProductDao { /** Logger for this class and subclasses */ protected final Log logger = LogFactory.getLog(getClass()); public List<Product> getProductList() { logger.info("Getting products!"); List<Product> products = getSimpleJdbcTemplate().query( "select id, description, price from products", new ProductMapper()); return products; } public void saveProduct(Product prod) { logger.info("Saving product: " + prod.getDescription()); int count = getSimpleJdbcTemplate().update( "update products set description = :description, price = :price where id = :id", new MapSqlParameterSource().addValue("description", prod.getDescription()) .addValue("price", prod.getPrice()) .addValue("id", prod.getId())); logger.info("Rows affected: " + count); } private static class ProductMapper implements ParameterizedRowMapper<Product> { public Product mapRow(ResultSet rs, int rowNum) throws SQLException { Product prod = new Product(); prod.setId(rs.getInt("id")); prod.setDescription(rs.getString("description")); prod.setPrice(new Double(rs.getDouble("price"))); return prod; } } } Also my Product.Java is below public class Product implements Serializable { private int id; private String description; private Double price; public void setId(int i) { id = i; } public int getId() { return id; } public String getDescription() { return description; } public void setDescription(String description) { this.description = description; } public Double getPrice() { return price; } public void setPrice(Double price) { this.price = price; } public String toString() { StringBuffer buffer = new StringBuffer(); buffer.append("Description: " + description + ";"); buffer.append("Price: " + price); return buffer.toString(); } } I guess my question would be, How would my current classes change after using Hibernate + JPA with an Entity Manager

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  • Crashing app when i want to go rootview from other view controller

    - by Priyanka
    Hello All, I want to go Root view Controller from another view controller but i got the terminating error. following is the error message in console, Terminating app due to uncaught exception 'NSRangeException', reason: '* -[NSCFArray removeObjectsInRange:]: index (4) beyond bounds (1)' This is my code for that NSArray *arr=self.navigationController.viewControllers; //ListOfInjuriesViewController *list=[[ListOfInjuriesViewController alloc]init]; [self.navigationController popToViewController:[arr objectAtIndex:2] animated:YES]; So any one can give me the suggestion on it so can remove the crash

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  • FF extension. how to show data extracted in a javascript function to the dropdown menu in the browse

    - by encryptor
    I am developing a ff extension. On one menupopup, the onpopupshowing calls a javascript function. Tha JS function extracts a list of names. Now these names have to be displayed in the same popup. How can i get this? Basically i will need to pass the data (just as we use beans in java) to the browser from the JS function. The data can change everytime the popup is called.

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  • RenderPattern headache with WSS 3.0 Document Library

    - by Ben
    Hi All, I'm trying to define the DisplayPattern of a custom field to do as follow. It's a simple text field used in document libraries, but i want the text entered to be displayed as a link to the document in the list view. <URL Cmd="Display"> gives me the display form, but I want the link to actually download/open the document... I can't for the life of me figure this one out... Thanks for your help!

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  • What is the best WebControl to create this

    - by balexandre
    current output wanted output current code public partial class test : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) populateData(); } private void populateData() { List<temp> ls = new List<temp>(); ls.Add(new temp { a = "AAA", b = "aa", c = "a", dt = DateTime.Now }); ls.Add(new temp { a = "BBB", b = "bb", c = "b", dt = DateTime.Now }); ls.Add(new temp { a = "CCC", b = "cc", c = "c", dt = DateTime.Now.AddDays(1) }); ls.Add(new temp { a = "DDD", b = "dd", c = "d", dt = DateTime.Now.AddDays(1) }); ls.Add(new temp { a = "EEE", b = "ee", c = "e", dt = DateTime.Now.AddDays(2) }); ls.Add(new temp { a = "FFF", b = "ff", c = "f", dt = DateTime.Now.AddDays(2) }); TemplateField tc = (TemplateField)gv.Columns[0]; // <-- want to assign here just day gv.Columns.Add(tc); // <-- want to assign here just day + 1 gv.Columns.Add(tc); // <-- want to assign here just day + 2 gv.DataSource = ls; gv.DataBind(); } } public class temp { public temp() { } public string a { get; set; } public string b { get; set; } public string c { get; set; } public DateTime dt { get; set; } } and in HTML <asp:GridView ID="gv" runat="server" AutoGenerateColumns="false"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:Label ID="Label1" runat="server" Text='<%# Eval("a") %>' Font-Bold="true" /><br /> <asp:Label ID="Label2" runat="server" Text='<%# Eval("b") %>' Font-Italic="true" /><br /> <asp:Label ID="Label3" runat="server" Text='<%# Eval("dt") %>' /> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> What I'm trying to avoid is repeat code so I can only use one unique TemplateField I can accomplish this with 3 x GridView, one per each day, but I'm really trying to simplify code as the Grid will be exactly the same (as the HTML code goes), just the DataSource changes. Any help is greatly appreciated, Thank you.

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  • Python sort strings started with digits

    - by vlad
    I have the next list: a = ['1th Word', 'Another Word', '10th Word'] print a.sort() >>> ['10th Word', '1th Word', 'Another Word'] But I need: ['1th Word', '10th Word','Another Word'] Is there an easy way to do this? I tried: r = re.compile(r'(\d+)') def sort_by_number(s): m = r.match(s) return m.group(0) x.sort(key=sort_by_number) But some strings do not have numbers and this leads to an errors. Thanks.

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  • filter divs by class - jquery

    - by Jason
    Hi, there are several list filters in jquery (quicksand, filterprojects, etc.), but I am looking to filter divs by class. I want the same functionality of the above - you select a menu item attached to a class and the other items fade out. Anyone seen anything like this anywhere?

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  • JSF action, value and binding catalog generator

    - by BBSnowman
    I am looking for a simple tool that generates a catalog of all used action methods, values and bindings. I'm working on a big JSF/RichFaces project and I have lost the overview of the used links to the beans. Therefore I need a tool (would be nice if it is a Eclipse plugin) that generates a simple list of all used EL expressions. Is there something out there?

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  • Number of elements in Python Set

    - by Tim
    I have a list of phone numbers that have been dialed (nums_dialed). I also have a set of phone numbers which are the number in a client's office (client_nums) How do I efficiently figure out how many times I've called a particular client (total) For example: >>>nums_dialed=[1,2,2,3,3] >>>client_nums=set([2,3]) >>>??? total=4 Problem is that I have a large-ish dataset: len(client_nums) ~ 10^5; and len(nums_dialed) ~10^3.

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  • PHP's form bracket trick is to Django's ___?

    - by Matt
    In PHP you can create form elements with names like: category[1] category[2] or even category[junk] category[test] When the form is posted, category is automatically turned into a nice dictionary like: category[1] => "the input value", category[2] => "the other input value" Is there a way to do that in Django? request.POST.getlist isn't quite right, because it simply returns a list, not a dictionary. I need the keys too.

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  • MySQL friends table

    - by asmo
    I have a MySQL DB in which I store data about each user. I would like to add a list of friends for each user. Should I create a table of friends for each user in the DB or is there a better way?

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  • not in gzip format error

    - by Ravindra
    while installing any Gem or doing any listing of gem gzip related error comes as shown below:- C:\Documents and Settings\gangunragem install rhosync -v 2.0.0.beta7 --pre ERROR: While executing gem ... (Zlib::GzipFile::Error) not in gzip format C:\Documents and Settings\gangunragem list rails -r * REMOTE GEMS * ERROR: While executing gem ... (Zlib::GzipFile::Error) not in gzip format Please help me out how to reslove this

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  • SQLAlchemy: an efficient/better select by primary keys?

    - by hadrien
    Yet another newbie question.. Let's say I have an user table in declarative mode: class User(Base): __tablename__ = 'user' id = Column(u'id', Integer(), primary_key=True) name = Column(u'name', String(50)) When I have a list of users identifiers, I fetch them from db with: user_ids = [1, 2, 3, 4, 5] users = Session.query(User).filter(User.id.in_(user_ids)).all() I dislike using in_ because I think I learned it has bad performance on indexed fields (is that true/false?). Anyway, is there a better way doing that query? Thanks!

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  • Is there any way to group edit buttons in MediaWiki?

    - by Mark Robinson
    Is there any way to group the edit buttons displayed above the edit dialog in MediaWiki? By grouping, I mean like Word does (and even this editor) - you can add dividing lines to group them so that e.g. Bold and Italic are in one group, numbered list and bullet points in another. We've added lots of new buttons (in EditPage.php) and they are in a logical order, but at 30 buttons it is a bit overwhelming for some users.

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  • How to use C# to parse a glossary into database?

    - by Yaaqov
    This should be a simple one, but I'm a beginner with C#. Given a glossary list in the following format: aptitude ability, skill, gift, talent aqueous watery arguably maybe, perhaps, possibly, could be How can I parse this, and insert into a database table in the format: TABLE: Term_Glossary ================================================ Term_Name | Term_Definition | ================================================ aptitude | ability, skill, gift, talent | ------------------------------------------------ aqueous | watery | ------------------------------------------------ arguably | maybe, perhaps, possibly, could be| ================================================ Any help would be appreciated - thanks.

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  • scp all files starting with 'file' from a server

    - by user209691
    Hi, I use this command to copy all files whose names start with 'file' from a server. scp -vp me@server:/location/files* ./ But i got a 'No Match' error. probably Concerning the '' in the command. How can i protect the '' for ssh to understand that this refers to a list of files and not taking it as a filename. Thx August

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  • how to get selected item in pyqt Qmenu

    - by Moayyad Yaghi
    hello is there any way to get the selected item in a qmenu ? i want to bind all items in that list to one function and get the item once user click it . i've been looking for a way to get the item's label or index for 3 days , but couldn't find it . any ideas ? thanks in advance

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  • Calling applescript from shell script using admin previleges

    - by Nir
    I'm running a shell script that runs an installation program (by ViseX) and selects different items in the installer through a list. The installer needs administrator privileges to run properly, but I don't want to use sudo. Here's the applescript I'm using: osascript <<-END tell application "$1" with timeout of 8 * 3600 seconds activate Select "$2" DoInstall end timeout end tell END

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