Search Results

Search found 5228 results on 210 pages for 'bash alias'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 73/210 | < Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >

  • Is there a unix command to output time elapsed during a command?

    - by Olivier Lacan
    I love using time to find out how long a command took to execute but when dealing with commands that execute sub-commands internally (and provide output that allows you to tell when each of those sub-commands start running) it would be really great to be able to tell after what number of seconds (or milliseconds) a specific sub-command started running. When I say sub-command, really the only way to distinguish these from the outside is anything printed to standard out. Really this seems like it should be an option to time.

    Read the article

  • Using watch with pipes

    - by Tom
    Hi! I'd like to run this command: watch -n 1 tail -n 200 log/site_dev.log | grep Doctrine But it does not run, because "I think" that the grep tries to run on the watch instead of the tail... Is there a way to do something like watch -n 1 (tail -n 200 log/site_dev.log | grep Doctrine) Thanks a lot!

    Read the article

  • Can't access Terminal anymore, only shows a cursor

    - by user138304
    I run OS X. Following these directions (Installing MySQL on Mac OS X) I added a file to /usr and the contents were PATH=/usr/local/mysql/bin:$PATH Actually I was trying to get the mysql command to work now I cannot access terminal. All I get is a cursor but no command line. I also cannot find the file I created in the Finder. I used command shift G to find the folder /usr and the file is not there. Edit: I Solved the problem by restarting my computer. I am really not sure what the problem was. I got the idea because Could not open a new pseudo-tty. appeared in my terminal after following slhck directions to remove my .profile file. I then searched google and found this; http://blogs.oreilly.com/digitalmedia/2008/03/fixing-terminal-tty-errors.html. Thanks

    Read the article

  • How do I change the .bash_history file location?

    - by Brian Graham
    I'm running CentOS 6.x and want to move the .bash_history to a different location. The home directories of my users are (because I run a VPS) in /var/www/vhost/<domain>.<tld> which is FTP accessible (and it should be). Because of this, I have changed the AuthorizedKeysFile for SSH connections out of the normal ~/.ssh/authorized_keys since FTP connections would easily be able to locate them. At the same time I want to move the .bash_history file to /home/%u/.bash_history where %u is the current user.

    Read the article

  • How to cd into smb://[email protected] from terminal?

    - by John
    I am using ubuntu and gnome on my computer. When I open up File Browser, on the left hand rail, I see conveniently a folder called "Work Server". When I mouse over it, the following caption appears "smb://[email protected]". If I click on that folder, then I can see the contents of that folder. Everything is great. So now when I open up a terminal/shell, I type in cd smb://[email protected] I get an error saying the directory doesn't exist. How do I enter this directory via shell/terminal?

    Read the article

  • Automake thumbnail

    - by Webmaster
    What I need to do is a program that given (as a command line argument) a directory with more directoreies inside, and 4 Pics inside of each dir, the program makes a thumbnail of the 4 files and glues them together (2 rows, 2 columns) and renames that image to the name of the directory. I think it could be done with a combination of a program and shell scripting (I'm experienced in M$, but new to linux). Some real examples would be great. Thanx in advance

    Read the article

  • UDISKS instead of HAL

    - by MeJ
    Does anybody have some expirence with udisks, because HAL won't be longer supported on the most linux distribution, so I am thinking of to use udisks for UDI in $(hal-find-by-property --key storage.bus --string usb) do HAL_TMP=`hal-get-property --udi $UDI --key storage.removable.media_available` if [ "$HAL_TMP" = "true" ]; then HAL_DEV=$(hal-get-property --udi $UDI --key block.device) HAL_SIZE=$(hal-get-property --udi $UDI --key storage.removable.media_size) HAL_TYPE=$(hal-get-property --udi $UDI --key storage.drive_type) How do I have to adapt the above mentioned commands but use udisks instead of hal Thanks!

    Read the article

  • Avoiding users to corrupt and use a script

    - by EverythingRightPlace
    Is it possible to deny the right to copy files? I have a script which should be executable by others. They are also allowed to read the file (though it would not be a problem to forbid reading). But I don't want the script to be changed and executed. It's not a problem to set those permissions, but one could easily copy, change and run the script. Can this even be avoided? /edit The OS is Red Hat Enterprise Linux Workstation release 6.2 (Santiago).

    Read the article

  • Linux script that indicates time the server was offline?

    - by RD
    Below is data taken from my dedicated server: root@namhost [~]# last root pts/0 XXX Tue May 18 09:46 still logged in root pts/0 XXX Mon May 17 08:51 - 12:18 (03:26) reboot system boot XXX Mon May 17 08:49 (1+00:59) root pts/0 XXX Sun May 16 11:50 - 13:15 (01:25) root@namhost [~]# last | grep "system boot" reboot system boot 2.6.18-164.15.1. Mon May 17 08:49 (1+01:02) reboot system boot 2.6.18-164.el5 Tue May 11 04:20 (7+05:31) reboot system boot 2.6.18-164.el5 Tue May 11 03:53 (7+05:58) reboot system boot 2.6.18-128.el5 Mon Oct 5 22:40 (-3:-50) .... I need a script that I can run on an hourly basis that will: 1. Calculate the total downtime since the first date 2. The overall downtime percentage 3. Store this data in a file at /home/bla/file.txt, in the following format: TotalDowntime=03:02:02 Average=0.01% How do I go about doing this?

    Read the article

  • Running a command line app with sudo and password automatically on OS X startup

    - by Designer023
    I need to run an app at startup/login on my mac. I want it to launch in the background and start doing it's work without interrupting me or me having to start it up because I invariably forget and then when I need it, it wasn't running! I have tried using AppleScript to tell Terminal to run it and type my password in, but it ends up opening multiple Terminal windows and not working. Ideally I need a script that I can just add to the user login items and it will run for me. The app has no way of taking a password argument either and it has a password as well as the sudo! I need a solution that can either be done as an applescript (which can be made into an executable) or i need a commandline script but I have no idea about them. This is the manual code I type $ sudo serverStatus password:123456 password:serverpass My AppleScript: tell application Terminal activate do shell script "sudo serverStatus" delay 5 do shell script "123456" delay 2 do shell script "serverpass" end tell

    Read the article

  • Passing the output of the last command to sed as an argument

    - by neurolysis
    Hi, Basically, I'm wanting to automate adding something to xorg.conf in the right place, I've used some commands to get the line number of the line I want to manipulate, but I'm not really sure how to go about passing this line number (as an argument and NOT something to be manipulated) to sed. I have been told about xargs and looked at the docs on it, but after some reading and experimentation I can't seem to get it to work. In case anyone can think of a better method entirely, the process I want to automate is just finding the line containing both "Identifier" and "Monitor0" (there will only be one) and adding a line below it. The problem with just finding Monitor0 and manipulating that line is that there are multiple lines with Monitor0 in. I've got this far: fgrep -n "Monitor0" </etc/X11/xorg.conf | fgrep "Identifier" | cut -f1 -d: This gives out the line number which I'm wanting to pass to sed, but I'm not really sure how to do it. ...or is there a simpler way which I'm not seeing? Thanks. :)

    Read the article

  • Diff and ignore lines missing in one file

    - by Millianz
    I want to diff two files and ignore lines that are present in one file but missing in the other. For example File1: foo bar baz bat File2: foo ball bat I'm currently running the following diff command diff File1 File2 --changed-group-format='%>' --unchanged-group-format='' Which in this case would produce bar baz as the output, i.e. only missing or conflicting lines. I would like to only print conflicting lines, i.e. ignore cases where one line is missing from File2 and is present in File1 (not the other way around). Is there any way to do something like this using diff or do I have to resort to other tools? If so, what would you recommend?

    Read the article

  • unexpected behaviour of Ctrl-a x and Ctrl-a X in screen?! regions, locking

    - by gojira
    According to the screen manual (version 4.0.2.) C-a x C-a C-x (lockscreen) Lock this terminal. C-a X (remove) Kill the current region. But what actually happens when I use it (Screen version 4.00.03 (FAU) 23-Oct-06): C-a X locks the terminal and asks me for the password. When I enter the correct passwword, I am back in screen but the region is killed (wtf) C-a x does nothing apparently Please note the differences between x (lowercase) and X (uppercase). Why is there a mixup between the functionalities of C-a X and C-a x? How can I fix this? I am on CentOS release 5 (Final).

    Read the article

  • merge two parts of pdf in one

    - by Yurij73
    I have two searchable pdf documents say even.pdf and odd.pdf which contains respectively even and odd pages of a book. I can decompile each pdf to separate files 001.pdf 002.pdf oo3.pdf ....The question is how to merge them? They are both even and odd sequences numbered 1,2,3. If it where other numbering on decompile stage with pdftk for even 1,3,5 and for odd 2,4,6 instead of existing order 1,2,3, 4.. i coulde simple merge them, but i ignore this method of numbering with pdftk. May be i need to do the task in other way?

    Read the article

  • log execution of certain commands on linux

    - by jlsksr
    I have to maintain a system (debian) on which several users are allowed to install programs - so I would like to log, for example, if anyone executes "apt-get install" or "apt-get purge", so I can keep track of manually installed packages.. I'm looking for a general way to achieve this; it's not just APT, but several programs/scripts etc. Any ideas? /edit a google-search with few different keywords brought up this: http://serverfault.com/questions/201221/how-to-log-every-linux-command-to-a-logserver http://stackoverflow.com/questions/15698590/how-to-capture-all-the-commands-typed-in-unix-linux-by-any-user http://sourceforge.net/projects/rootsh/

    Read the article

  • Recursive Unrar with Deletion as it progresses

    - by Jharwood
    Basically, i have a set of directories that are constantly being filled with .rar's, and i need to be able to extract them in place with automatic deletion of the left over .(rar|rXX) files. How would i go about this? Note: I can't delete all of them once done, they have to be deleted as the script completes one rar set. Example Directory Structure: / /folder1/ /file1.rar /file1.r00 /file1.r01 /folder2/ /sub.folder1/ /file2.part001.rar (contains a directory "file2") /file2.part002.rar /file2.part003.rar /sub.folder2/ /file3.rar /file3.r00 /file3.r01 Expected Result: / /folder1/ /file1.ext /folder2/ /sub.folder1/ /file2/ /file2.ext /sub.folder2/ /file3.ext

    Read the article

  • Moving directories full of files over the top

    - by JavaRocky
    I took a backup of a directory which has a number directories and files inside them. Recently some files have gone missing. I would like to just move over the missing files. I prefer moving files instead of just copying as space is a premium on this particular box and the files are quite large. How can i achieve this?

    Read the article

  • Setting up ssh config file with id_rsa through tunnel

    - by Rubens
    I've been struggling to set up a valid configuration to open a connection with a second machine, passing through another one, and using an id_rsa (which requests me a password) to connect to the third machine. I've asked this question in another forum, but I've received no answer that could be considered very helpful. The problem, better described, goes as follows: Local machine: user1@localhost Intermediary machine: user1@inter Remote target: user2@final I'm able to do the entire connection using pseudo-tty: ssh -t inter ssh user2@final (this will ask me the password for the id_rsa file I have in machine "inter") However, for speeding things up, I'd like to set my .ssh/config file, so that I can simply connect to machine "final" using: ssh final What I've got so far -- which does not work -- is, in my .ssh/config file: Host inter User user1 HostName inter.com IdentityFile ~/.ssh/id_rsa Host final User user2 HostName final.com IdentityFile ~/.ssh/id_rsa_2 ProxyCommand ssh inter nc %h %p The id_rsa file is used to connect to the middle machine (this requires me no password typing), and id_rsa_2 file is used to connect to machine "final" (this one requests a password). I've tried mixing up some LocalForward and/or RemoteForward fields, and putting the id_rsa files in both first and second machines, but I could not seem to succeed with no configuration whatsoever. Hope somebody can help me here! Regards! P.S.: the thread I've tried to get some help from: http://www.linuxquestions.org/questions/linux-general-1/proxycommand-on-ssh-config-file-4175433750/

    Read the article

  • Problems when loop over a series of ssh-ed commands

    - by Jack Medley
    I have a series of server machines which I want to run the same command on. Each command takes hours and (even though I am running the commands using nohup and setting them to run in the background) I have to wait for each to finish before the next starts. Here is roughly how I have set it up: On the host machines: for i in {1..9}; do ssh RemoteMachine${i} ./RunJobs.sh; done Where RunJobs.sh on each remote machine is: source ~/.bash_profile cd AriadneMatching for file in FileDirectory/Input_*; do nohup ./Executable ${file} & done exit Does anyone know of a way such that I dont have to wait for each job to finish before the next starts? Or alternatively a better way of doing this, I have a feeling what I am do is fairly sub-optimal. Cheers, Jack

    Read the article

  • Why would a process monitoring script use exit 1; on finding no problems?

    - by user568458
    General question: On a Linux (Centos) server, if a process monitoring script run by cron is set to close with exit 1; rather than exit 0; on finding that everything is okay and that no action is needed, is that a mistake? Or are there legitimate reasons for calling exit 1; instead of exit 0; on the "Everything's fine, no action needed" condition? exit 0; on finding no problems seems to me to be more appropriate. But maybe there's something I'm not aware of. For example, maybe there's something specific to Cron? Or maybe there's a convention in process monitoring scripts that 'failure' means 'this script failed to need to fix a problem' (rather than what I would expect which is that exit 1; would mean 'the process being monitored has failed'?) My specific case: I'm looking at a process monitoring script written by my web hosting company. By process monitoring script, I mean a script executed by Cron on a regular basis that checks if an important system process is running, and if it isn't running, takes actions such as mailing an administrator or restarting the process. Here's the (generalised) structure of their script, for a service running on port 8080 (in this case, Apache Tomcat): SERVICE=$(/usr/sbin/lsof -i tcp:8080 | wc -l); if [ $SERVICE != 0 ]; then exit 1; else #take action fi Seems simple enough even for someone with limited knowledge like me, except the exit 1; part seems odd. As I understand it, exit 0; closes a program and signifies to the parent that executed the program that everything is fine, exit n; where n0 and n<127 signifies that there has been some kind of error or problem. Here, their script seems to go against that rule - it calls exit 1; in the condition where everything is fine, and doesn't exit after taking remedial action in the problem condition. To me, this looks like a mistake - but my experience in this area is limited. Are there cases where calling exit 1; in the "Everything's fine, no action needed" condition is more appropriate than calling exit 0;? Or is it a mistake? Wider context is pretty simple. It's a Centos VPS, running Plesk. The script is being called by Cron via Plesk's "Scheduled tasks" Cron manager. There's no custom layer between Cron and this script that would respond in an unusual way to the exit call. It's a fairly average, almost out-of-the box Plesk-managed Centos VPS (in so far as there is such a thing). The process being monitored by this script is Apache Tomcat.

    Read the article

  • Change to different user, or let different user execute a command

    - by WG-
    I have a problem. There is a server which I can access with an account by ssh, lets say WG. Now there is a folder with the following permissions. drwxr-s---+ 855 vvz www-data 20K Aug 21 17:56 pictures I want to copy this folder using rsync, however since I am not the user www-data but WG I cannot execute rsync. So I want www-data to execute a rsync command. However, I do not posses sudo powers. My friend however tells me that I am actually able to execute the rsync command as www-data, but he will not tell me how. I asked him for some clues and he told me that it had something to do with reverse shell (which I figured out to be that you connect by ssh to your server and then you connect back to your own server, or something). I also asked if it was by-design or actually a flaw in the system. He tells me it is both. Furthermore I think it has something to do with the group permissions. If I just make sure that I am with the group permissions then I can also read the files. Anybody has a clue?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >