Search Results

Search found 35302 results on 1413 pages for 'string literals'.

Page 73/1413 | < Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >

  • SSI: Failed String Comparison with CGI Environment Variable [migrated]

    - by Calyo Delphi
    I am currently working on developing a personal website. It's not my first time doing this, but this is my first major foray into implementing SSI. I've run myself into a wall, however, with an if-else directive that uses one of the CGI environment variables as part of its comparison. Even after some limited attempts at debugging, all of the output and documentation that I have means that the comparisons being made should fail outright. This is not the case, and the wrong evaluation is being made by the if-else directive. Here's the code in the file index.shtml: <head> <!--#set var="page" value="Home" --> <!--#include file="headlinks.shtml" --> <style> img#ref { float: right; margin-left: 8px; border-width: 0px; } </style> </head> Here's the code in the file headlinks.shtml: <title><!--#echo var="page" --> &ndash; <!--#echo var="HTTP_HOST" --></title> <!--#set var="docroot" value="${DOCUMENT_ROOT}" --> <!--#echo var="docroot" --> <!--#if expr="( $docroot != '/Applications/MAMP/htdocs' ) || ( $docroot != '/home/dragarch/public_html' )" --> <link rel="stylesheet" type="text/css" href="../style.css"> <link rel="shortcut icon" type="image/svg+xml" href="../favicon.svg" /> <!--#else --> <link rel="stylesheet" type="text/css" href="style.css"> <link rel="shortcut icon" type="image/svg+xml" href="favicon.svg" /> <!--#endif --> And here's the output for the file index.shtml: <title>Home &ndash; dragarch</title> /Applications/MAMP/htdocs <link rel="stylesheet" type="text/css" href="../style.css"> <link rel="shortcut icon" type="image/svg+xml" href="../favicon.svg" /> Both style.css and favicon.svg are in the document root with index.shtml, so the if directive should fail and default to the output of the else directive. As you can see, while the document root (which is currently the MAMP htdocs folder on my own notebook) is correct according to the output of the echo directive, the comparison in the if-else directive fails to compare the strings properly. I'm using this page for my documentation: http://httpd.apache.org/docs/2.2/mod/mod_include.html I'm at a complete loss as to why this is the case, and need a bit of help here. EDIT: I should note that dragarch is a hostname that I configured in /etc/hosts to point to 127.0.0.1 so I could test the site without having to use localhost. It has no real effect on the functionality of anything, other than to just act as a prettier hostname to use.

    Read the article

  • return char1 + char2? Isn't it possible?

    - by pocoa
    I'm trying to return a string from a function. Which basically adds some chars together and return the string representation. string toString() { char c1, c2, c3; // some code here return c1 + c2; // Error: invalid conversion from `char' to `const char*' } it is possible to return boolean values like return c1 == 'x'. Isn't it possible to return string values? I know that it is possible to it like this: string result; result.append(c1, c2); return result; I'm new to C++ so I thought that there must be more elegant solution around.

    Read the article

  • Search Engine Optimization on a Shoe String Budget (aka DIY SEO) - Part I

    SEO is critical to having your small/local business being found online. There are services out there that charge hundreds or even thousands of dollars a month for this service and frankly many of them are worth that and more for the qualified leads they help send your way. However for the small business person there often is no budget for this so they have to have a more DIY (do it yourself) approach at the start. This article is the first in a series that outlines some basics before you start spending money.

    Read the article

  • Cannot pass a input from text box to a query string and then keep the string in this box.

    - by Nikita Barsukov
    I have a simple ASP.net page: <form id="form1" runat="server"> <p><asp:TextBox id="input_box" runat="server"></asp:TextBox> <asp:Button Text="OK" runat="server" OnClick="run" /></p> </form> I want to send input from input_box to a query string, and then keep this input in the input_box when the page reloads. That's the code behind page: protected void Page_Load(object sender, EventArgs e) { input_box.Text = Request.QueryString["input"]; } protected void run(object sender, EventArgs e) { string url = string.Format("?input={0}", input_box.Text); Response.Redirect(Request.Url.AbsolutePath + url); } Problem is that when query string is not empty, string from input_box cannot be passed to query string. How to correct it?

    Read the article

  • Stored Connection Strings per user

    - by pehaada
    In the past I've used a Singleton Pattern to load the connection string when the application starts via the global.asa file. I have a project now where each user has a unique connection string to the database. I would like to load this connection string once. The issue is that the singleton pattern will not work for me since each user has there own connection string. Basically the connection string is created dynamically. I do not want to store it is session. If anyway has a clever way of doing this in .NET let me know ?

    Read the article

  • How to insert complex strings into Actionscript?

    - by Ole Jak
    How to insert complex strings into Actionscript? So I have a string -vvv -I rc w:// v dv s="60x40" --ut="#scode{vcode=FV1,acode=p3,ab=128,ch=2,rate=4400}:dup{dt=st{ac=http{mime=v/x-flv},mux=mpeg{v},dt=:80/sm.fv}}" How to insert it into code like public var SuperPuperComplexString:String = new String(); SuperPuperComplexString = TO_THAT_COMPLEX_STRING; That string has so many problems like some cart of it can happen to be like regexp BUTI DO NOT want it to be parsed as any kind of reg exp - I need It AS IT IS!) How to put that strange string into variable (put it not inputing it thru UI - hardcode it into AS code)?

    Read the article

  • StringIndexOutOfBoundsException: String index out of range 0

    - by Evan F
    I'm trying to write a program to take the first letter of the user input to generate a username. I'm trying to write it so that if the user leaves the input blank, then the letter that would otherwise be taken to generate the username defaults to the letter 'z'. Here is my full code: import java.util.Scanner; /** UsernameGenerator.java Generates a username based on the users inputs. @author: Evan Fravert */ public class UsernameGenerator { /** * Generates a username based on the users inputs. *@param args command line argument */ public static void main(String[] args) { // abcde String first; String middle; String last; String password1; String password2; int randomNum; randomNum = (int) (Math.random() * 1000) + 100; Scanner userInput = new Scanner(System.in); System.out.println("Please enter your first name:"); first = userInput.nextLine(); String firstLower = first.toLowerCase(); System.out.println("Please enter your middle name:"); middle = userInput.nextLine(); String middleLower = middle.toLowerCase(); System.out.println("Please enter your last name:"); last = userInput.nextLine(); int lastEnd = last.length()-1; String lastLower = last.toLowerCase(); System.out.println("Please enter your password:"); password1 = userInput.nextLine(); System.out.println("Please enter your password again:"); password2 = userInput.nextLine(); char firstLetter = firstLower.charAt(0); char middleLetter = middleLower.charAt(0); char lastLetter = lastLower.charAt(0); char lastLast = lastLower.charAt(lastEnd); if first.length() == 0) { firstLetter = 'z'; } else { firstLetter = firstLower.charAt(0); } System.out.println("Your username is " + firstLetter + "" + middleLetter + "" + lastLetter + "" + "" + lastLast + "" + randomNum); System.out.println("Your password is " + password1); System.out.println("Welcome " + first + " " + middle + " " + last + "!"); } }

    Read the article

  • How to have NHibernate persist a String.Empty property value as NULL

    - by Todd
    I have a fairly simple class that I want to save to SQL Server via NHibernate (w/ Fluent mappings). The class is made up mostly of optional string fields. My problem is I default the class fields to string.empty to avoid NullRefExceptions and when NHibernate saves the row to the database each column contains an empty string instead of null. Question: Is there a way for me to get NHibernate to automatically save null when the string property is an empty string? Or do I need to litter my code with if (string.empty) checks?

    Read the article

  • The Connection String Reference Site

    - by Yousef_Jadallah
    In this great site http://www.connectionstrings.com/ you can find about 517 connection strings and 120 providers, drivers and class libraries listed in the database. These for Database Servers as well Data Files. Just you need to choose the needed element then you will get all the information that you calling for.   Hope this helps,

    Read the article

  • Java splitting string by custom regex match

    - by slikz
    I am completely new to regular expressions so I'm looking for a bit of help here. I am compiling under JDK 1.5 Take this line as an example that I read from standard input: ab:Some string po:bubblegum What I would like to do is split by the two characters and colon. That is, once the line is split and put into a string array, these should be the terms: ab:Some string po:bubblegum I have this regex right now: String[] split = input.split("[..:]"); This splits at the semicolon; what I would like is for it to match two characters and a semicolon, but split at the space before that starts. Is this even possible? Here is the output from the string array: ab Some String po bubblegum I've read about Pattern.compile() as well. Is this something I should be considering?

    Read the article

  • Wordpress - how to replace <!--more--> with string on the_content() in single.php [migrated]

    - by Bob Cavezza
    I want to add text on a single wordpress blog post page where the "read more" text would usually be inserted. However, I can't configure a plugin to replace that text. I tried a few different sources, but I'm having trouble finding the solution. After looking through WordPress plugin: finding the <!--more--> in the_content and the page it links to, I still haven't been able to find a solution to this.

    Read the article

  • Method to concatenate 2 Strings in Java

    - by GooF
    I have a method in Java that concatenates 2 Strings. It currently works correctly, but I think it can be written better. public static String concat(String str1, String str2) { String rVal = null; if (str1 != null || str2 != null) { rVal = ""; if (str1 != null) { rVal += str1; } if (str2 != null) { rVal += str2; } } return rVal; } Here are some of the requirements: If both str1 and str2 are null, the method returns null If either str1 or str2 is null, it will just return the not null String If str1 and str2 are not null, it will concatenate them It never adds "null" to the result Can anyone do this with less code?

    Read the article

  • Creating ASP.NET 3.5 Admin Pages using a Query String in a Master Page

    This is the continuation of part one which ran on Tuesday of last week. After deleting the styles lt style type= text css gt in the head section of MasterPage.master you will need to create an external CSS to solve the relative URL problems in the website. This will ensure that the background images and links work according to the master page design. This article will explain how to do this and more.... Comcast? Business Class - Official Site Learn About Comcast Small Business Services. Best in Phone, TV & Internet.

    Read the article

  • Parsing through Arabic / RTL text from left to right

    - by Dan W
    Let's say I have a string in an RTL language such as Arabic with some English chucked in: string s = "Test:?????;?????;?????;a;b" Notice there are semicolons in the string. When I use the Split command like string[] spl = s.Split(';');, then some of the strings are saved in reverse order. This is what happens: ??Test:????? ????? ????? a b The above is out of order compared to the original. Instead, I expect to get this: ?Test: ????? ????? ????? a b I'm prepared to write my own split function. However, the chars in the string also parse in reverse order, so I'm back to square one. I just want to go through each character as it's shown on the screen.

    Read the article

  • Falsey values vs null, undefned, or empty string

    - by user687554
    I've worked with jQuery over the years. However, recently, I've found myself getting deeper into the JavaScript language. Recently, I've heard about "truthy" and falsey values. However, I don't fully understand them. Currently, I have some code that looks like this: var fields = options.fields || ['id', 'query']; I need to identify if fields is null, undefined, or has a length of 0. I know the long way is to do: if ((fields === null) || (fields === undefined) || (fields.length === 0)) { ... } My question is, is the following the same: if (!fields) { ... } Thank you!

    Read the article

  • hibernate criteria list problem [migrated]

    - by user1022676
    I have a user dao @Entity @Table(name="EBIGUSERTIM") public class EbigUser { private String id; private Integer source; private String entryscheme; private String fullName; private String email; private Long flags; private String status; private String createdBy; private Date createdStamp; private String modifiedBy; private Date modifiedStamp; @Id @Column(name="ID") public String getId() { return id; } public void setId(String id) { this.id = id; } @Id @Column(name="SOURCE") public Integer getSource() { return source; } public void setSource(Integer source) { this.source = source; } @Column(name="ENTRYSCHEME") public String getEntryscheme() { return entryscheme; } public void setEntryscheme(String entryscheme) { this.entryscheme = entryscheme; } @Column(name="FULLNAME") public String getFullName() { return fullName; } public void setFullName(String fullName) { this.fullName = fullName; } @Column(name="EMAIL") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @Column(name="FLAGS") public Long getFlags() { return flags; } public void setFlags(Long flags) { this.flags = flags; } @Column(name="STATUS") public String getStatus() { return status; } public void setStatus(String status) { this.status = status; } @Column(name="CREATEDBY") public String getCreatedBy() { return createdBy; } public void setCreatedBy(String createdBy) { this.createdBy = createdBy; } @Column(name="CREATEDSTAMP") public Date getCreatedStamp() { return createdStamp; } public void setCreatedStamp(Date createdStamp) { this.createdStamp = createdStamp; } @Column(name="MODIFIEDBY") public String getModifiedBy() { return modifiedBy; } public void setModifiedBy(String modifiedBy) { this.modifiedBy = modifiedBy; } @Column(name="MODIFIEDSTAMP") public Date getModifiedStamp() { return modifiedStamp; } public void setModifiedStamp(Date modifiedStamp) { this.modifiedStamp = modifiedStamp; } i am selecting 2 rows out of the db. The sql works select * from ebigusertim where id='blah'. It returns 2 distinct rows. When i query the data using hibernate, it appears that the object memory is not being allocated for each entry in the list. Thus, i get 2 entries in the list with the same object. Criteria userCriteria = session.createCriteria(EbigUser.class); userCriteria.add(Restrictions.eq("id", id)); userlist = userCriteria.list();

    Read the article

  • String[] initialized by null???

    - by Esmond
    Hi i encountered this problem whereby when i initialized my String[], there seems to be a null in the String[] before i do anything. How do i initialized the String[] to be completely empty,i.e. without the null at the start? The output for the following code is: nullABC nullABC nullABC nullABC nullABC public static void main(String[] args){ String[] inputArr = new String[5]; for (int i = 0; i< inputArr.length; i++){ inputArr[i] += "ABC"; } for (int i = 0; i< inputArr.length; i++){ System.out.println(inputArr[i]); } } }

    Read the article

  • error: switch quantity not an integer

    - by nikeunltd
    I have researched my issue all over StackOverflow and multi-google links, and I am still confused. I figured the best thing for me is ask... Im creating a simple command line calculator. Here is my code so far: const std::string Calculator::SIN("sin"); const std::string Calculator::COS("cos"); const std::string Calculator::TAN("tan"); const std::string Calculator::LOG( "log" ); const std::string Calculator::LOG10( "log10" ); void Calculator::set_command( std::string cmd ) { for(unsigned i = 0; i < cmd.length(); i++) { cmd[i] = tolower(cmd[i]); } command = cmd; } bool Calculator::is_legal_command() const { switch(command) { case TAN: case SIN: case COS: case LOG: case LOG10: return true; break; default: return false; break; } } the error i get is: Calculator.cpp: In member function 'bool Calculator::is_trig_command() const': Calculator.cpp: error: switch quantity not an integer Calculator.cpp: error: 'Calculator::TAN' cannot appear in a constant-expression Calculator.cpp: error: 'Calculator::SIN' cannot appear in a constant-expression Calculator.cpp: error: 'Calculator::COS' cannot appear in a constant-expression The mighty internet, it says strings are allowed to be used in switch statements. Thanks everyone, I appreciate your help.

    Read the article

  • Problem with File IO and splitting strings with Environment.NewLine in VB.Net

    - by Senthil
    Hi, I was experimenting with basic VB.Net file read/write and encountered this problem. I don't know whether it has something to do with the File IO or the String splitting. I am writing text to a file like so Dim sWriter As New StreamWriter("Data.txt") sWriter.WriteLine("FirstItem") sWriter.WriteLine("SecondItem") sWriter.WriteLine("ThirdItem") sWriter.Close() Then, I am reading the text from the file Dim sReader As New StreamReader("Data.txt") Dim fileContents As String = sReader.ReadToEnd() sReader.Close() Now, I am splitting the fileContents variable using Environment.NewLine and saving the returned String array. Dim tempStr() As String = fileContents.Split(Environment.NewLine) When I print the array, I get some weird results For Each str As String In tempStr Console.WriteLine("*" + str + "*") Next I added the *'s to the beginning and end to find out what is going on. Since NewLine is used as the delimiter, I expect the strings in the array to NOT have any NewLine's. But the output was this - *FirstItem* * SecondItem* * ThirdItem* * * Shouldn't it be this - *FirstItem* *SecondItem* *ThirdItem* ?? Since I am using WriteLine, my guess is a new line is added after the last string and hence the last empty item in the array after splitting. But why is there a new line in the beginning of the second and third strings?

    Read the article

  • Fun things you can do by mutating Java strings

    - by polygenelubricants
    So I've come around since I asked how to limit setAccessible to only “legitimate” uses and have come to embrace its power for fun. Enabled by its power, of course, is string mutation. import java.lang.reflect.Field; public class Mutator { static void mutate(Object obj, String field, Object newValue) { try { Field f = obj.getClass().getDeclaredField(field); f.setAccessible(true); f.set(obj, newValue); } catch (Exception e) { } } public static void mutate(String from, String to) { mutate(from, "value", to.toCharArray()); mutate(from, "count", to.length()); } public static void main(String args[]) { Mutator.mutate(System.getProperty("line.separator"), "<br/>\n"); System.out.println("Hello world!"); Mutator.mutate(Integer.toString(Integer.MIN_VALUE), "OMG!"); System.out.println(-2147483648); Mutator.mutate(String.valueOf((Object) null), "LOL!"); System.out.println(Arrays.toString(new int[3][])); Mutator.mutate(Arrays.toString(new int[0]), ":("); System.out.println(Arrays.toString(new byte[0])); } } Output (if no exception is thrown): Hello world!<br/> OMG!<br/> [LOL!, LOL!, LOL!]<br/> :(<br/> Let's see what other fun things we can come up with.

    Read the article

  • How to put Listview items into String Array?

    - by user2851687
    Im developing an app and as the title says how to put items of listview into String array, not string array to listview but listview to string array. I've been searching for this but what I only found is putting String array items into listview. Please help me thank you in advance. To clarify this thread, the question is how to put listview items into String array. Thanks. :D Codes public class DailyPlanTab extends Activity implements OnItemClickListener { ListView dailyPlanList; ArrayList<DailyManager> taskList = new ArrayList<DailyManager>(); DatabaseDailyPlan db; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.dailyplan_layout); dailyPlanList = (ListView) findViewById(R.id.lvDailyPlanList); dailyPlanList.setOnItemClickListener(this); ImageView add = (ImageView) findViewById(R.id.ivDailyPlanAdd); add.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub Intent newDailyIntent = new Intent(getApplicationContext(), NewDailyPlan.class); startActivity(newDailyIntent); } }); } @Override protected void onResume() { // TODO Auto-generated method stub super.onResume(); taskList.clear(); db = new DatabaseDailyPlan(getApplicationContext()); db.getWritableDatabase(); ArrayList<DailyManager> tempList = db.getTask(); for (int i = 0; i < tempList.size(); i++) { String getTask = tempList.get(i).getDaily_name(); String getDate = tempList.get(i).getDaily_date(); int getId = tempList.get(i).getDaily_id(); DailyManager dm = new DailyManager(); dm.setDaily_name(getTask); dm.setDaily_date(getDate); dm.setDaily_id(getId); taskList.add(dm); } dailyPlanList.setAdapter(new ListAdapter(this)); // db.close(); } public class ListAdapter extends BaseAdapter { LayoutInflater inflater; ViewHolder viewHolder; public ListAdapter(Context c) { // TODO Auto-generated constructor stub inflater = LayoutInflater.from(c); } @Override public int getCount() { // TODO Auto-generated method stub return taskList.size(); } @Override public Object getItem(int position) { // TODO Auto-generated method stub return position; } @Override public long getItemId(int position) { // TODO Auto-generated method stub return position; } @Override public View getView(int position, View convertView, ViewGroup parent) { // TODO Auto-generated method stub if (convertView == null) { convertView = inflater.inflate(R.layout.row_checklist_item, null); viewHolder = new ViewHolder(); viewHolder.taskTitle = (TextView) convertView .findViewById(R.id.tvCheckListItem); convertView.setTag(viewHolder); } else { viewHolder = (ViewHolder) convertView.getTag(); } viewHolder.taskTitle.setText("" + taskList.get(position).getDaily_name()); return convertView; } } public class ViewHolder { TextView taskTitle, taskDate; } @Override public void onItemClick(AdapterView<?> arg0, View arg1, int position, long arg3) { // TODO Auto-generated method stub int taskId = taskList.get(position).getDaily_id(); String taskName = taskList.get(position).getDaily_name(); String taskDate = taskList.get(position).getDaily_date(); Intent newPlan = new Intent(getApplicationContext(), DailyPlan.class); newPlan.putExtra("task_id", taskId); newPlan.putExtra("task_name", taskName); startActivity(newPlan); } next is the information of the item inside the listview public class DailyPlan extends Activity implements OnItemClickListener { final ArrayList<DailyManager> savedItems = new ArrayList<DailyManager>(); ListView checkList; Boolean nextItem = false; TempManager tm; DatabaseTemp dbTemp; Intent i; int taskId = -1; String taskName = " ", taskDate = null; DatabaseDailyPlan db; DailyManager dm; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.saved_dailyplan); checkList = (ListView) findViewById(R.id.lvCheckList); // checkList.setOnItemClickListener(this); try { i = getIntent(); taskId = i.getExtras().getInt("task_id"); taskName = i.getExtras().getString("task_name"); Toast.makeText(getApplicationContext(), "From new id is" + taskId, 5000).show(); } catch (Exception e) { } Button addList = (Button) findViewById(R.id.bAddList); addList.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub // openDialog("", false, -1); } }); if (nextItem) { // openDialog("", false, -1); } } public void refresh() { DailyPlan.this.onResume(); } @Override protected void onResume() { // TODO Auto-generated method stub super.onResume(); savedItems.clear(); dbTemp = new DatabaseTemp(getApplicationContext()); dbTemp.getWritableDatabase(); db = new DatabaseDailyPlan(getApplicationContext()); db.getWritableDatabase(); if (taskId != -1) { // / For Load ArrayList<DailyManager> savedList = db.getList(taskId); for (int i = 0; i < savedList.size(); i++) { String savedListItems = savedList.get(i).getDaily_list(); String savedListTitle = savedList.get(i).getDaily_name(); String savedListDate = savedList.get(i).getDaily_date(); int savedListId = savedList.get(i).getDaily_id(); DailyManager dm = new DailyManager(); dm.setDaily_list(savedListItems); dm.setDaily_name(savedListTitle); dm.setDaily_date(savedListDate); dm.setDaily_id(savedListId); savedItems.add(dm); } } else { // / For New } checkList.setAdapter(new ListAdapter(this)); } public class ListAdapter extends BaseAdapter { LayoutInflater inflater; ViewHolder viewHolder; public ListAdapter(Context c) { // TODO Auto-generated constructor stub inflater = LayoutInflater.from(c); } @Override public int getCount() { // TODO Auto-generated method stub return savedItems.size(); } @Override public Object getItem(int position) { // TODO Auto-generated method stub return position; } @Override public long getItemId(int position) { // TODO Auto-generated method stub return position; } @Override public View getView(int position, View convertView, ViewGroup parent) { // TODO Auto-generated method stub if (convertView == null) { convertView = inflater.inflate(R.layout.row_checklist_item, null); viewHolder = new ViewHolder(); viewHolder.checkListItem = (TextView) convertView .findViewById(R.id.tvCheckListItem); convertView.setTag(viewHolder); } else { viewHolder = (ViewHolder) convertView.getTag(); } viewHolder.checkListItem.setText(savedItems.get(position) .getDaily_list() + position); final int temp = position; return convertView; } } private class ViewHolder { TextView checkListItem; } @Override public void onItemClick(AdapterView<?> arg0, View arg1, int item, long arg3) { // TODO Auto-generated method stub // openDialog(savedItems.get(item).getDaily_name(), true, // savedItems.get(item).getDaily_id()); } }

    Read the article

  • Need help in Hashtable implementation

    - by rafael
    Hi all, i'm quite a beginner in C# , i tried to write a program that extract words from an entered string, the user has to enter a minimum length for the word to filter the words output ... my code doesn't look good or intuitive, i used two arrays countStr to store words , countArr to store word length corresponding to each word .. but the problem is i need to use hashtables instead of those two arrays , because both of their sizes are depending on the string length that the user enter , i think that's not too safe for the memory or something ? here's my humble code , again i'm trying to replace those two arrays with one hashtable , how can this be done ? using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Collections; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { int i = 0 ; int j = 0; string myString = ""; int counter = 0; int detCounter = 0; myString = Console.ReadLine(); string[] countStr = new string[myString.Length]; int[] countArr = new int[myString.Length]; Console.Write("Enter minimum word length:"); detCounter = int.Parse(Console.ReadLine()); for (i = 0; i < myString.Length; i++) { if (myString[i] != ' ') { counter++; countStr[j] += myString[i]; } else { countArr[j] = counter; counter = 0; j++; } } if (i == myString.Length) { countArr[j] = counter; } for (i = 0; i < myString.Length ; i++) { if (detCounter <= countArr[i]) { Console.WriteLine(countStr[i]); } } Console.ReadLine(); } } }

    Read the article

< Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >