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  • How can I password protect & let cgi-bin to work?

    - by jaaaaaaax
    This is taken from sites-available directory. It's a virtual host setting for apache. Accessing myiphere/cgi-bin/ throws 403. The directory setting for /var/www2/ drwxrwxrwx 8 www-data www-data NameVirtualHost myiphere <VirtualHost myiphere> ServerAdmin webmaster@localhost DocumentRoot /var/www2/ <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www2/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined ServerSignature On Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory>

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  • Chrome Saved Passwords security issue

    - by Nalaka526
    If I save a password in Google chrome someone else can easily see the password from Setting -> Advance Settings -> Manage saved passwords -> Show (in required password field) and use it from another computer. Isn't it causing a security issue? I guess it is much secure if it display only the entry and all dots or something for the password (not the actual password). Is there any acceptable idea of showing the password to anyone this easily? Note: Firefox is also showing the actual passwords, I Didn't check in IE.

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  • I am unable to find login page for phpmyadmin

    - by Awan
    I was using phpmyadmin(in Wamp) without a password for root. I thought to set a password for root and goto Privileges page and set a password for root. Now whenever I go to localhost/phpmyadmin page it gives me the following error. MySQL said: Documentation #1045 - Access denied for user 'root'@'localhost' (using password: NO) phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server. I don't know that what is the problem. It is not showing me a login type page to enter a username and password. Any idea that what is the problem ? Thanks

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  • How can I download a phpbb forum with wget including password protected sections?

    - by Rocky84
    I want to make a download of a forum I moderate, before it closes for good. There's some useful info on it I want to save for myself and I don't want to export the data to another webserver, I just want the pages. Mind you, I'm a user at the forum, not the admin. Now, I googled this and found it can be easily done with wget: How can I download an entire (active) phpbb forum? I used: wget -k -m -E -p -np -R viewtopic.php*p=*,memberlist.php*,faq.php*,posting.php*,search.php*,ucp.php*,viewonline.php*,*sid*,*view=print*,*start=0* -o log.txt http://www.example.com/forum/ I experimented with this, but I can only achieve downloading the publicly visible sections, not the sections you have to log in for. I tried to achieve this by using a Firefox plugin to make a cookies.txt (while my session is logged into the forum) and add --load-cookies file cookies.txt to the command, but still I only get the publicly visible sections. Any suggestions to make this work?

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  • Authenticate by libpam-mysql and libnss-mysql (CentOS)

    - by Chris
    I'm trying to get MySQL to function as a backend for authenticating users on CentOS 6.3. So far I have successfully installed and configured libnss-mysql. I can test this by doing: # groups testuser testuser : sftp Testuser is a member of the sftp group in fact, all MySQL based useraccounts will be hardcoded to it. The sftp group is chrooted and forced to use internal-sftp so they cannot do anything but access their home directory. Then I configured pam-mysql and PAM to allow mysql logins. This also works.. When SELinux is not enforcing. When I do setenforce 1 users can no longer login. Error: Permission denied, please try again. This is my pam_mysql.conf file: users.host=localhost users.db_user=nss-pam-user users.db_passwd=*********** users.database=sftpusers users.table=users users.user_column=username users.password_column=password users.password_crypt=6 verbose=1 My /etc/pam.d/sshd: #%PAM-1.0 auth sufficient pam_sepermit.so auth include password-auth auth required pam_mysql.so config_file=/etc/pam_mysql.conf account sufficient pam_nologin.so account include password-auth account required pam_mysql.so config_file=/etc/pam_mysql.conf password include password-auth # pam_selinux.so close should be the first session rule session required pam_selinux.so close session required pam_loginuid.so # pam_selinux.so open should only be followed by sessions to be executed in the user context session required pam_selinux.so open env_params session optional pam_keyinit.so force revoke session include password-auth And to be complete the contents of some log files.. /var/logs/secure Nov 20 14:52:20 hostname unix_chkpwd[4891]: check pass; user unknown Nov 20 14:52:20 hostname unix_chkpwd[4891]: password check failed for user (testuser) Nov 20 14:52:20 hostname sshd[4880]: pam_unix(sshd:auth): authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=192.168.10.107 user=testuser Nov 20 14:52:22 sftpusers sshd[4880]: Failed password for testuser from 192.168.10.107 port 51849 ssh2 /var/logs/audit/audit.log type=USER_AUTH msg=audit(1353420107.070:812): user pid=5285 uid=0 auid=500 ses=24 subj=unconfined_u:system_r:sshd_t:s0-s0:c0.c1023 msg='op=pubkey acct="testuser" exe="/usr/sbin/sshd" hostname=? addr=192.168.10.107 terminal=ssh res=failed' type=USER_AUTH msg=audit(1353420112.312:813): user pid=5285 uid=0 auid=500 ses=24 subj=unconfined_u:system_r:sshd_t:s0-s0:c0.c1023 msg='op=PAM:authentication acct="testuser" exe="/usr/sbin/sshd" hostname=192.168.10.107 addr=192.168.10.107 terminal=ssh res=failed' type=USER_AUTH msg=audit(1353420112.456:814): user pid=5285 uid=0 auid=500 ses=24 subj=unconfined_u:system_r:sshd_t:s0-s0:c0.c1023 msg='op=password acct="testuser" exe="/usr/sbin/sshd" hostname=? addr=192.168.10.107 terminal=ssh res=failed' I tried to let audit2why explain the problem but it remains silent even though there are some errors. Does anyone see the problem? Thanks! EDIT: Turns out it's almost working with setenforce 0 I can mkdir foobar but if I do a single ls I get an error: Received message too long 16777216

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  • Is it possible to check if a BIOS supports password entry for a self-encrypting SSD/harddrive?

    - by therobyouknow
    I'm considering purchasing a SSD that has built-in hardware encryption / self-encrypting drive that provides its own full drive encryption. What can I do to check that the BIOS on my machine will support it? Background research so far Research on self-encrypting drives - good article below, but I would need to know if the BIOS can support it: http://www.computerweekly.com/feature/Self-encrypting-drives-SED-the-best-kept-secret-in-hard-drive-encryption-security

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  • How can I password prompt certain IPs and allow all others free access using Apache?

    - by Moak
    SOLVED: The idea is that if the visitor comes from China they have to pass a basic authentication. If you have any other IP address you can visit the site without being hassled (including proxies) //1400 rules.... SetEnvIf Remote_Addr 222.249.128.0/19 china SetEnvIf Remote_Addr 222.249.160.0/20 china SetEnvIf Remote_Addr 222.249.176.0/20 china AuthType Basic AuthName "Restricted" AuthUserFile /www/passwd/users Require valid-user Order allow,deny Allow from All Deny from env=china Satisfy any

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  • Not able to access the server after changing the password?

    - by cyrilsebastian
    While accessing the server, the error comes: Multiple connections to a server or shared resource by the same user, using more than one user name, are not allowed. Disconnect all previous connections to the server or shared resource and try again. I am logging in from Administrator in XP machine, able to access server from other machines. Is there any problem with administrator profile??

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  • Not able to access the server after changing the password?

    - by cyrilsebastian
    While accessing the server, the error comes: Multiple connections to a server or shared resource by the same user, using more than one user name, are not allowed. Disconnect all previous connections to the server or shared resource and try again. I am logging in from Administrator in XP machine, able to access server from other machines. Is there any problem with administrator profile??

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  • Import Firefox passwords into KeePassX or KeePass2

    - by rubo77
    I have an XML export of my Firefox Passwords in the form (I replaced real passwords with *): <xml> <entries ext="Password Exporter" extxmlversion="1.1" type="saved" encrypt="false"> <entry host="chrome://weave" user="****" password="****" formSubmitURL="" httpRealm="Mozilla Services Password" userFieldName="" passFieldName=""/> <entry host="chrome://weave" user="****" password="****" formSubmitURL="" httpRealm="Mozilla Services Encryption Passphrase" userFieldName="" passFieldName=""/> <entry host="http://www.example.de" user="rubo77" password="****" formSubmitURL="http://www.example.de" httpRealm="" userFieldName="benutzername" passFieldName="passwort"/> <entry host="http://example2.de" user="qqq" password="pppp" formSubmitURL="http://example2.de" httpRealm="" userFieldName="username" passFieldName="pass"/> ... Can I somehow convert this into a form KeePassX understands?

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  • weird SSH connection timed out

    - by bran
    This problem started when I tried to login to my brand spaning new VPS server. I remember that in my first SSH try on the server I actually got prompt for password several times which would mean that there is no port blocking problem from my isp. Since the password did'nt work for me (for some reason). I had a lot of authentication failure. After that attempting to log in to the server just timed out. I did the same at mediatemple (which used to work before with sftp) and put in wrong password and now trying to ssh (or even SFTP) gives me timeout error. So some kind of security feature is preventing me from trying too many times to log in, either from my side or from the server side. Any idea what it could be? TRaceroute and ping works on the ips. I am using a zyxel wimax modem (max-206m1r - if that's relevent) c:\Program Files (x86)\OpenSSH\bin>ssh.exe [email protected] ssh: connect to host 109.169.7.136 port 22: Connection timed out c:\Program Files (x86)\OpenSSH\bin>ssh.exe [email protected] ssh: connect to host 109.169.7.131 port 22: Connection timed out c:\Program Files (x86)\OpenSSH\bin>ssh.exe [email protected] ssh: connect to host 87.117.249.227 port 22: Connection timed out c:\Program Files (x86)\OpenSSH\bin>ssh.exe [email protected] -vv OpenSSH_5.6p1, OpenSSL 0.9.8r 8 Feb 2011 debug1: Reading configuration data /etc/ssh_config debug2: ssh_connect: needpriv 0 debug1: Connecting to 87.117.249.227 [87.117.249.227] port 22. debug1: connect to address 87.117.249.227 port 22: Connection timed out ssh: connect to host 87.117.249.227 port 22: Connection timed out c:\Program Files (x86)\OpenSSH\bin>ssh.exe s122797.gridserver.com Could not create directory '/home/pavs/.ssh'. The authenticity of host 's122797.gridserver.com (205.186.175.110)' can't be est ablished. RSA key fingerprint is 33:24:1e:38:bc:fd:75:02:81:d8:39:42:16:f6:f6:ff. Are you sure you want to continue connecting (yes/no)? yes Failed to add the host to the list of known hosts (/home/pavs/.ssh/known_hosts). Password: Password: Password: [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 205.186.175.110: 2: Too many authentication failures fo r pavs c:\Program Files (x86)\OpenSSH\bin>ssh.exe s122797.gridserver.com ssh: connect to host s122797.gridserver.com port 22: Connection timed out c:\Program Files (x86)\OpenSSH\bin>ssh.exe s122797.gridserver.com ssh: connect to host s122797.gridserver.com port 22: Connection timed out

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  • How do I stop ssh-agent from forgetting my password after I login to the screen session from SSH?

    - by Shwouchk
    I have a screen session open in an lxterminal window. If I SSH somewhere, the first time it happens, an ssh-agent window opens and asks me for my private key passphrase, and after that ssh goes right on. If I log in from outside to this machine and attach to the screen session however, ssh-agent now asks me every time I connect for my passphrase, in the terminal. Is there a way to avoid this and to let it continue using the X agent, or at least to have the non-X agent remember the passphrase?

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  • Adding local users / passwords on Kerberized Linux box

    - by Brian
    Right now if I try to add a non-system user not in the university's Kerberos realm I am prompted for a Kerberos password anyway. Obviously there is no password to be entered, so I just press enter and see: passwd: Authentication token manipulation error passwd: password unchanged Typing passwd newuser has the same issue with the same message. I tried using pwconv in the hopes that only a shadow entry was needed, but it changed nothing. I want to be able to add a local user not in the realm and give them a local password without being bothered about Kerberos. I am on Ubuntu 10.04. Here are my /etc/pam.d/common-* files (the defaults that Ubuntu's pam-auth-update package generates): account # here are the per-package modules (the "Primary" block) account [success=1 new_authtok_reqd=done default=ignore] pam_unix.so # here's the fallback if no module succeeds account requisite pam_deny.so # prime the stack with a positive return value if there isn't one already; # this avoids us returning an error just because nothing sets a success code # since the modules above will each just jump around account required pam_permit.so # and here are more per-package modules (the "Additional" block) account required pam_krb5.so minimum_uid=1000 # end of pam-auth-update config auth # here are the per-package modules (the "Primary" block) auth [success=2 default=ignore] pam_krb5.so minimum_uid=1000 auth [success=1 default=ignore] pam_unix.so nullok_secure try_first_pass # here's the fallback if no module succeeds auth requisite pam_deny.so # prime the stack with a positive return value if there isn't one already; # this avoids us returning an error just because nothing sets a success code # since the modules above will each just jump around auth required pam_permit.so # and here are more per-package modules (the "Additional" block) # end of pam-auth-update config password # here are the per-package modules (the "Primary" block) password requisite pam_krb5.so minimum_uid=1000 password [success=1 default=ignore] pam_unix.so obscure use_authtok try_first_pass sha512 # here's the fallback if no module succeeds password requisite pam_deny.so # prime the stack with a positive return value if there isn't one already; # this avoids us returning an error just because nothing sets a success code # since the modules above will each just jump around password required pam_permit.so # and here are more per-package modules (the "Additional" block) # end of pam-auth-update config session # here are the per-package modules (the "Primary" block) session [default=1] pam_permit.so # here's the fallback if no module succeeds session requisite pam_deny.so # prime the stack with a positive return value if there isn't one already; # this avoids us returning an error just because nothing sets a success code # since the modules above will each just jump around session required pam_permit.so # and here are more per-package modules (the "Additional" block) session optional pam_krb5.so minimum_uid=1000 session required pam_unix.so # end of pam-auth-update config

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  • How can I password protect & let cgi-bin to work?

    - by jaaaaaaax
    This is taken from sites-available directory. It's a virtual host setting for apache. Accessing myiphere/cgi-bin/ throws 403. The directory setting for /var/www2/ drwxrwxrwx 8 www-data www-data NameVirtualHost myiphere <VirtualHost myiphere> ServerAdmin webmaster@localhost DocumentRoot /var/www2/ <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www2/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined ServerSignature On Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory>

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  • Getting a Non-Genuine windows message on a Genuin Windows 7

    - by user36257
    I have a Genuin Win7 enterprise on my Laptop. A few hours ago when I wanted to log into windows it did not accept my Password. I used the safe mode and it accepted the password I was using before this new password. It is the laptop for work and we have a changing password policy for every three months, so the pasword that I could use in SAFE MODE was the password I had for the last previous threee months. ... after that I used SYSTEM RESTORE and it reveretd it back to Yesterday ... so this time I could loging successfully with my current password. BUT It shows me a message that I am a victim of software counterfeiting and when I restarted the windows again and logged into windows, this time it is just a black desktop. weird...any ideas?

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  • Windows 7 -Can't get access to shared folder from one computer to another.

    - by Carbonara
    I have 2 windows 7 computers and i'm trying to share a folder (that I want password protection on) outside of the homegroup. Both computers are part of the same workgroup and I have the same user account/password combination on both computers plus I have password protected sharing turned on in the network and sharing centre along with file and printer sharing turned on. On computer 1 I have right clicked and selected that I want the folder shared. When I navigate via the network on computer 2 to computer 1 the shared folder shows up on computer 2 but double clicking on it to open it gives me an alert saying I don't have permission to access it, no option to type in the user name and password (according to the help files I shouldn't even need to type the password in if both computers have the same username/password anyway but would need it if I'm logged in as a different user). It's just a blanket denial of access.

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  • Not able to access the server after changing the password? [closed]

    - by cyrilsebastian
    While accessing the server, the error comes: Multiple connections to a server or shared resource by the same user, using more than one user name, are not allowed. Disconnect all previous connections to the server or shared resource and try again. I am logging in from Administrator in XP machine, able to access server from other machines. Is there any problem with administrator profile??

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  • MVC Scaffold Template Not Generating?

    - by monkey9987
    Been working on an MVC project and my templates were not generating. I first created my Model inside my "Models" folder, then did a quick compile. Next I went to the Views folder to get it created, right click and say "Add View" then I clicked the checkbox to create an edit page. What happened was the template would never seem to pull in my Model, it would just have the default header items, but the entire model was missing.  My model was defined as follows: public class LogOnModel { [Required][Display(Name = "User name")]public string UserName;[Required][DataType(DataType.Password)][Display(Name = "Password")]public string Password;[Display(Name = "Remember me?")]public bool RememberMe; } See anything wrong with that? I couldn't figure out why each time I created my View and selected the option to create the "Edit" scaffold automatically, it would come up blank. Turns out I'm missing my get / set methods on the Model class items. Here's my code with the correct setup: public class LogOnModel { [Required][Display(Name = "User name")]public string UserName { get; set; } [Required][DataType(DataType.Password)][Display(Name = "Password")]public string Password { get; set; }[Display(Name = "Remember me?")]public bool RememberMe { get; set; } }  I hope that helps someone out, it's pretty simple when I look at it now, but that's always the case!  ~ Steve

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  • Ubuntu 13.04 client cannot connect to Raspbian samba share

    - by envoyweb
    I have a client Ubuntu 13.04 machine trying to connect to a server running Raspbian with samba and samba-common-bin installed on the server I can see my share and when I try to login I get this error: Unable to access location: Failed to write windows share Cannot allocate memory. I have installed ntfs-3g for the usb hard drive that already auto mounts on the server so I never had to create a directory or edit fstab. Testparm on the server states the following: [global] workgroup = ENVOYWEB server string = %h server map to guest = Bad User obey pam restrictions = Yes pam password change = Yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . unix password sync = Yes syslog = 0 log file = /var/log/samba/log.%m max log size = 1000 dns proxy = No usershare allow guests = Yes panic action = /usr/share/samba/panic-action %d idmap config * : backend = tdb [homes] comment = Home Directories valid users = %S create mask = 0700 directory mask = 0700 browseable = No [printers] comment = All Printers path = /var/spool/samba create mask = 0700 printable = Yes print ok = Yes browseable = No [print$] comment = Printer Drivers path = /var/lib/samba/printers [BigDude] comment = Sharing BigDude's Files path = /media/BigDude/ valid users = @users read only = No create mask = 0755 testparm on the client which is running ubuntu is as follows [global] workgroup = ENVOYWEB server string = %h server (Samba, Ubuntu) map to guest = Bad User obey pam restrictions = Yes pam password change = Yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . unix password sync = Yes syslog = 0 log file = /var/log/samba/log.%m max log size = 1000 dns proxy = No usershare allow guests = Yes panic action = /usr/share/samba/panic-action %d idmap config * : backend = tdb [printers] comment = All Printers path = /var/spool/samba create mask = 0700 printable = Yes print ok = Yes browseable = No [print$] comment = Printer Drivers path = /var/lib/samba/printers

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  • Nested entities in Google App Engine. Do I do it right?

    - by Aleksandr Makov
    Trying to make most of the GAE Datastore entities concept, but some doubts drill my head. Say I have the model: class User(ndb.Model): email = ndb.StringProperty(indexed=True) password = ndb.StringProperty(indexed=False) first_name = ndb.StringProperty(indexed=False) last_name = ndb.StringProperty(indexed=False) created_at = ndb.DateTimeProperty(auto_now_add=True) @classmethod def key(cls, email): return ndb.Key(User, email) @classmethod def Add(cls, email, password, first_name, last_name): user = User(parent=cls.key(email), email=email, password=password, first_name=first_name, last_name=last_name) user.put() UserLogin.Record(email) class UserLogin(ndb.Model): time = ndb.DateTimeProperty(auto_now_add=True) @classmethod def Record(cls, user_email): login = UserLogin(parent=User.key(user_email)) login.put() And I need to keep track of times of successful login operations. Each time user logs in, an UserLogin.Record() method will be executed. Now the question — do I make it right? Thanks. EDIT 2 Ok, used the typed arguments, but then it raised this: Expected Key instance, got User(key=Key('User', 5418393301680128), created_at=datetime.datetime(2013, 6, 27, 10, 12, 25, 479928), email=u'[email protected]', first_name=u'First', last_name=u'Last', password=u'password'). It's clear to understand, but I don't get why the docs are misleading? They implicitly propose to use: # Set Employee as Address entity's parent directly... address = Address(parent=employee) But Model expects key. And what's worse the parent=user.key() swears that key() isn't callable. And I found out the user.key works. EDIT 1 After reading the example form the docs and trying to replicate it — I got type error: TypeError('Model constructor takes no positional arguments.'). This is the exacto code used: user = User('[email protected]', 'password', 'First', 'Last') user.put() stamp = UserLogin(parent=user) stamp.put() I understand that Model was given the wrong argument, BUT why it's in the docs?

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  • What .NET objects should I use to create a cookie based session in MVC?

    - by makerofthings7
    I'm writing a custom password reset application that uses a validation technique that doesn't fit cleanly with ASP.NET Membership Provider's challenge questions. Namely I need to invoke a workflow and collect information from the end user (backup phone number, email address) after the user logs in using a custom form. The only way I know to create a cookie-based session (without too much "innovation" on my part) is to use WIF. What other standard objects can I use with ASP.NET MVC to create an authenticated session that works with non-windows user stores? Ideally I can store "role" or claim information in the session object such as "admin", "departmentXadmin", "normalUser", or "restrictedUser" The workflow would look like this: User logs in with username and password If the username and pw are correct a (stateless) cookie based session is created The user gets redirected to a HTML form that allows them to enter their backup phone number (for SMS dual factor), or validate it if already set. The user can then change their password using the form provided The "forgot password" would look like this User requests OTP code to be sent to the phone User logs in using username and OTP If the OTP is valid and not expired then create a cookie based session and redirect to a form that allows password reset Show password reset form, and process results.

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  • How to do MVC the right way

    - by Ieyasu Sawada
    I've been doing MVC for a few months now using the CodeIgniter framework in PHP but I still don't know if I'm really doing things right. What I currently do is: Model - this is where I put database queries (select, insert, update, delete). Here's a sample from one of the models that I have: function register_user($user_login, $user_profile, $department, $role) { $department_id = $this->get_department_id($department); $role_id = $this->get_role_id($role); array_push($user_login, $department_id, $role_id); $this->db->query("INSERT INTO tbl_users SET username=?, hashed_password=?, salt=?, department_id=?, role_id=?", $user_login); $user_id = $this->db->insert_id(); array_push($user_profile, $user_id); $this->db->query(" INSERT INTO tbl_userprofile SET firstname=?, midname=?, lastname=?, user_id=? ", $user_profile); } Controller - talks to the model, calls up the methods in the model which queries the database, supplies the data which the views will display(success alerts, error alerts, data from database), inherits a parent controller which checks if user is logged in. Here's a sample: function create_user(){ $this->load->helper('encryption/Bcrypt'); $bcrypt = new Bcrypt(15); $user_data = array( 'username' => 'Username', 'firstname' => 'Firstname', 'middlename' => 'Middlename', 'lastname' => 'Lastname', 'password' => 'Password', 'department' => 'Department', 'role' => 'Role' ); foreach ($user_data as $key => $value) { $this->form_validation->set_rules($key, $value, 'required|trim'); } if ($this->form_validation->run() == FALSE) { $departments = $this->user_model->list_departments(); $it_roles = $this->user_model->list_roles(1); $tc_roles = $this->user_model->list_roles(2); $assessor_roles = $this->user_model->list_roles(3); $data['data'] = array('departments' => $departments, 'it_roles' => $it_roles, 'tc_roles' => $tc_roles, 'assessor_roles' => $assessor_roles); $data['content'] = 'admin/create_user'; parent::error_alert(); $this->load->view($this->_at, $data); } else { $username = $this->input->post('username'); $salt = $bcrypt->getSalt(); $hashed_password = $bcrypt->hash($this->input->post('password'), $salt); $fname = $this->input->post('firstname'); $mname = $this->input->post('middlename'); $lname = $this->input->post('lastname'); $department = $this->input->post('department'); $role = $this->input->post('role'); $user_login = array($username, $hashed_password, $salt); $user_profile = array($fname, $mname, $lname); $this->user_model->register_user($user_login, $user_profile, $department, $role); $data['content'] = 'admin/view_user'; parent::success_alert(4, 'User Sucessfully Registered!', 'You may now login using your account'); $data['data'] = array('username' => $username, 'fname' => $fname, 'mname' => $mname, 'lname' => $lname, 'department' => $department, 'role' => $role); $this->load->view($this->_at, $data); } } Views - this is where I put html, css, and JavaScript code (form validation code for the current form, looping through the data supplied by controller, a few if statements to hide and show things depending on the data supplied by the controller). <!--User registration form--> <form class="well min-form" method="post"> <div class="form-heading"> <h3>User Registration</h3> </div> <label for="username">Username</label> <input type="text" id="username" name="username" class="span3" autofocus> <label for="password">Password</label> <input type="password" id="password" name="password" class="span3"> <label for="firstname">First name</label> <input type="text" id="firstname" name="firstname" class="span3"> <label for="middlename">Middle name</label> <input type="text" id="middlename" name="middlename" class="span3"> <label for="lastname">Last name</label> <input type="text" id="lastname" name="lastname" class="span3"> <label for="department">Department</label> <input type="text" id="department" name="department" class="span3" list="list_departments"> <datalist id="list_departments"> <?php foreach ($data['departments'] as $row) { ?> <option data-id="<?php echo $row['department_id']; ?>" value="<?php echo $row['department']; ?>"><?php echo $row['department']; ?></option> <?php } ?> </datalist> <label for="role">Role</label> <input type="text" id="role" name="role" class="span3" list=""> <datalist id="list_it"> <?php foreach ($data['it_roles'] as $row) { ?> <option data-id="<?php echo $row['role_id']; ?>" value="<?php echo $row['role']; ?>"><?php echo $row['role']; ?></option> <?php } ?> </datalist> <datalist id="list_collection"> <?php foreach ($data['tc_roles'] as $row) { ?> <option data-id="<?php echo $row['role_id']; ?>" value="<?php echo $row['role']; ?>"><?php echo $row['role']; ?></option> <?php } ?> </datalist> <datalist id="list_assessor"> <?php foreach ($data['assessor_roles'] as $row) { ?> <option data-id="<?php echo $row['role_id']; ?>" value="<?php echo $row['role']; ?>"><?php echo $row['role']; ?></option> <?php } ?> </datalist> <p> <button type="submit" class="btn btn-success">Create User</button> </p> </form> <script> var departments = []; var roles = []; $('#list_departments option').each(function(i){ departments[i] = $(this).val(); }); $('#list_it option').each(function(i){ roles[roles.length + 1] = $(this).val(); }); $('#list_collection option').each(function(i){ roles[roles.length + 1] = $(this).val(); }); $('#list_assessor option').each(function(i){ roles[roles.length + 1] = $(this).val(); }); $('#department').blur(function(){ var department = $.trim($(this).val()); $('#role').attr('list', 'list_' + department); }); var password = new LiveValidation('password'); password.add(Validate.Presence); password.add(Validate.Length, {minimum: 10}); $('input[type=text]').each(function(i){ var field_id = $(this).attr('id'); var field = new LiveValidation(field_id); field.add(Validate.Presence); if(field_id == 'department'){ field.add(Validate.Inclusion, {within : departments}); } else if(field_id == 'role'){ field.add(Validate.Inclusion, {within : roles}) } }); </script> The codes above are actually code from the application that I'm currently working on. I'm working on it alone so I don't really have someone to review my code for me and point out the wrong things in it so I'm posting it here in hopes that someone could point out the wrong things that I've done in here. I'm also looking for some guidelines in writing MVC code like what are the things that should be and shouldn't be included in views, models and controllers. How else can I improve the current code that I have right now. I've written some really terrible code before(duplication of logic, etc.) that's why I want to improve my code so that I can easily maintain it in the future. Thanks!

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  • What are some internet trends that you've noticed over the past ~10 years? [closed]

    - by Michael
    I'll give an example of one that I've noticed: the number of web sites that ask for your email address (GOOG ID, YAHOO! ID, etc.) has skyrocketed. I can come up with no legitimate reason for this other than (1) password reset [other ways to do this], or (2) to remind you that you have an account there, based upon the time of your last visit. Why does a web site need to know your email address (Google ID, etc.) if all you want to do is... download a file (no legit reason whatsoever) play a game (no legit reason whatsoever) take an IQ test or search a database (no legit reason whatsoever) watch a video or view a picture (no legit reason whatsoever) read a forum (no legit reason whatsoever) post on a forum (mildly legit reason: password reset) newsletter (only difference between a newsletter and a blog is that you're more likely to forget about the web site than you are to forget about your email address -- the majority of web sites do not send out newsletters, however, so this can't be the justification) post twitter messages or other instant messaging (mildly legit reason: password reset) buy something (mildly legit reasons: password reset + giving you a copy of a receipt that they can't delete, as receipts stored on their server can be deleted) On the other hand, I can think of plenty of very shady reasons for asking for this information: so the NSA, CIA, FBI, etc. can very easily track what you do by reading your email or asking GOOG, etc. what sites you used your GOOG ID at to use the password that you provide for your account in order to get into your email account (most people use the same password for all of their accounts), find all of your other accounts in your inbox, and then get into all of those accounts sell your email address to spammers These reasons, I believe, are why you are constantly asked to provide your email address. I can come up with no other explanations whatsoever. Question 1: Can anyone think of any legitimate or illegitimate reasons for asking for someone's email address? Question 2: What are some other interesting internet trends of the past ~10 years?

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