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How to search within an xml data set?

- by user187580

Hi, I have some xml data and I am trying to keyword search data. For example, if I search "some" for the following data it returns me the <id> and <title>. <resource> <id>101</id> <title>Test Environment</title> <description><b>Some</b> description. </description> <type>classroom</type> </resource> <resource> <id>102</id> <title>ABC Test Environment</title> <description><b>Some</b> another description. </description> <type>classroom</type> </resource> ... I had a look on on xpath e.g. $xml->xpath('//title') but looks for elements only. Basically what I need to do is to create a functionality where users can keyword search within the above data set which I receive from third party api in the above format. Any ideas how I can achieve this? using PHP/ Javascript etc. Thanks.

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parse a special xml in python

- by zhaojing

I have s special xml file like below: <alarm-dictionary source="DDD" type="ProxyComponent"> <alarm code="402" severity="Alarm" name="DDM_Alarm_402"> <message>Database memory usage low threshold crossed</message> <description>dnKinds = database type = quality_of_service perceived_severity = minor probable_cause = thresholdCrossed additional_text = Database memory usage low threshold crossed </description> </alarm> ... </alarm-dictionary> I know in python, I can get the "alarm code", "severity" in tag alarm by: for alarm_tag in dom.getElementsByTagName('alarm'): if alarm_tag.hasAttribute('code'): alarmcode = str(alarm_tag.getAttribute('code')) And I can get the text in tag message like below: for messages_tag in dom.getElementsByTagName('message'): messages = "" for message_tag in messages_tag.childNodes: if message_tag.nodeType in (message_tag.TEXT_NODE, message_tag.CDATA_SECTION_NODE): messages += message_tag.data But I also want to get the value like dnkind(database), type(quality_of_service), perceived_severity(thresholdCrossed) and probable_cause(Database memory usage low threshold crossed ) in tag description. That is, I also want to parse the content in the tag in xml. Could anyone help me with this? Thanks a lot!

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XML with iPhone app !

- by totato

hi .. I just work on web-based application for iPhone, And I try to retrieve data from my website to my app. can I edit XML code for my website as I want to be in my iPhone app? for example, XML for my website is: <item> <title>Announcement title</title> <link>iphone feed</link> <description>Announcement type</description> <category>Students</category> <pubDate>April 5, 2010, 12:50 pm</pubDate> <guid>iphone feed</guid> </item> but I can't retrieve all of this to the tableview in my app. So, I will edit the code to be like this: <item> <category name="staff"> <Announcement title="welcome back"> <description> hope all of you enjoy in the vacation, and welcome back to university </description> </Announcement> </category> </item> Is this the right way?

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Populate on demand a TreeView with datas in an XML

- by m6a-uds

Hi I have a large XML file (3000+ nodes) that I want to represent in a TreeView on ASP.NET. I cannot databind it to a XMLDataSource because loading the TreeView will then be way too slow (I never even waited long enough to see it finish...) So the solution for this would be to use the PopulateOnDemand property of the TreeNodes to load data only when needed. Problem is, I can't think of a way to acheive this... How can-I, based on the ID of a node, search a XMLDocument to get all the childnodes of the node having this ID? XML would look like that: <document ID=1> <document ID=2> <document ID=3> </document> </document> <document ID=4> </document> </document> There are nor rules on how much levels it can go down or anything...

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SQL Server Querying An XML Field

- by Gavin Draper

I have a table that contains some meta data in an XML field. For example <Meta> <From>[email protected]</From> <To> <Address>[email protected]</Address> <Address>[email protected]</Address> </To> <Subject>ESubject Goes Here</Subject> </Meta> I want to then be able to query this field to return the following results From To Subject [email protected] [email protected] Subject Goes Here [email protected] [email protected] Subject Goes Here I've written the following query SELECT MetaData.query('data(/Meta/From)') AS [From], MetaData.query('data(/Meta/To/Address)') AS [To], MetaData.query('data(/Meta/Subject)') AS [Subject] FROM Documents However this only returns one record for that XML field. It combines both the 2 addresses into one result. Is it possible for split these on to separate records? The result I'm getting is From To Subject [email protected] [email protected] [email protected] Subject Goes Here Thanks Gav

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How to send XML data through socket InputStream

- by THeK3nger

Hi, I'm trying to write a client-server application in Java with an XML-based protocol. But I have a great problem! See this part of client code: InputStream incoming = skt.getInputStream(); //I get Stream from Socket. OutputStream out = skt.getOutputStream(); [...] XMLSerializer serializer = new XMLSerializer(); //This create an XML document. tosend = WUTPClientWriter.createMessage100(projectid, cpuclock, cpunumber); serializer.setOutputByteStream(out); serializer.serialize(tosend); At this point server fall in deadlock. It wait for EOF but I can't send it because if I use out.close(); or skt.shutdownOutput(); I close Socket and I must keep alive this connection. I can't send '\0' becouse I get Parse Error in the server. How can I do? Can I "close" output stream without close socket? RESOLVED I've created new class XMLStreamOutput and XMLStreamInput with advanced Stream gesture.

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C# XML Documentation Compiler Warning

- by ImperialLion

I am curious as to why I get a compiler warning in the following situation. /// <summary>This is class A /// </summary> public class A { /// <summary>This is the documentation for Method A /// </summary> public void MethodA() { //Do something } } /// <summary>This is class B /// </summary> public class B : A { /// <summary>This does something that I want to /// reference <see cref="MethodA"/> /// </summary> public void MethodB() { //Do something } } The warning states that "XML comment on 'B.MethodB()' has cref attribute 'MethodA' that could not be resolved." If B inherits from A shouldn't the compiler be able to see that method when generating the documentation without me specifying the parent class in the cref? If I change the cref to be cref="A.MethodA()" it works fine, but it seems like that's unnecessary and is a pain to do, especially if I have to go up more than one level. As a note to anyone testing this you have to be sure to "XML documentation file" checked in the Properties - Build in order to see the warning.

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Switch XML value for another in google maps

- by JeffP

all thanks for taking a look. Problem: Using Google maps I need to switch catid value to another value. How would I approach this and display it in a the window. E.G var catid = { 2: { newcatid: 'london' }, 4: { newcatid: 'newyork' } }; function load() { var map = new google.maps.Map(document.getElementById("map"), { center: new google.maps.LatLng(47.6145, -122.3418), zoom: 5, mapTypeId: 'roadmap' }); var infoWindow = new google.maps.InfoWindow; // Change this depending on the name of your PHP file downloadUrl("index_xml.php", function(data) { var xml = data.responseXML; var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("title"); var address = markers[i].getAttribute("address"); var catid = markers[i].getAttribute("catid"); var point = new google.maps.LatLng( parseFloat(markers[i].getAttribute("latitude")), parseFloat(markers[i].getAttribute("langtitude"))); var html = "<b>" + name + "</b> <br/>" + address + "<br/>" + **catid** + "<br/> <a href='@'>Info</a>" ;

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Query decendants in XML to Linq

- by Gordon

I have the following xml data: <portfolio> <item> <title>Site</title> <description>Site.com is a </description> <url>http://www.site.com</url> <photos> <photo url="http://www.site.com/site/thumbnail.png" thumbnail="true" description="Main" /> <photo url="http://www.site.com/site/1.png" thumbnail="false" description="Main" /> </photos> </item> </portfolio> In c# I am using the following link query: List list = new List(); XDocument xmlDoc = XDocument.Load(HttpContext.Current.Server.MapPath("~/app_data/portfolio.xml")); list = (from portfolio in xmlDoc.Descendants("item") select new PortfolioItem() { Title = portfolio.Element("title").Value, Description = portfolio.Element("description").Value, Url = portfolio.Element("url").Value }).ToList(); How do I go about querying the photos node? In the PortfolioItem class I have a property: List Photos {get;set;} Any ideas would be greatly appreciated!

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Linq Return node level of hierarchical xml

- by Ryan

In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

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Deleting items from datagrid (xml)

- by Tonz

Hello, I have a datagrid buttoncolumn which acts as delete buttons for my xml nodes. The elements are simply displayed in a boundcolumn, so there names get displayed. Each item generated gets a unique id (each time one is made id+++). My question his how can i remove a item (the entire element node with that certain id) when i click on one of the buttons in the bound column? <root> <element id="0"> <name>One</name> </element> <element id="1"> <name>Two</name> </element> </root> protected void dg_DeleteCommand(object sender, DataGridCommandEventArgs e) { XmlFunctions.Remove(index); }/*dg_DeleteCommand*/ (function on other class, where all my xml methods are written) public static void Remove(string index) { XmlDocument XMLDoc = new XmlDocument(); XMLDoc.Load(XMLFile); XPathNavigator nav = XMLDoc.CreateNavigator(); var node = nav.SelectSingleNode("/test/one[@id='" +???+ "']"); node.DeleteSelf(); XMLDoc.Save(XMLFile); } Edit: added datagrid <asp:View ID="viewDelete" runat="server"> <asp:DataGrid ID="dgDelete runat="server" AutoGenerateColumns="False" OnDeleteCommand="dg_DeleteCommand"> <Columns> <asp:BoundColumn DataField="name" HeaderText="names" /> <asp:ButtonColumn ButtonType="PushButton" Text="Delete" CommandName="Delete" ></asp:ButtonColumn> </Columns> </asp:DataGrid> </asp:View>

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Is it possible to create the following XML using Xdocument(C#3.0)

- by Newbie

<?xml version='1.0' encoding='UTF-8'?> <StockMarket> <StockDate Day = "02" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.45</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>366.25</Amount> </Stock> </StockDate> <StockDate Day = "03" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.35</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>369.70</Amount> </Stock> </StockDate> </StockMarket> My approach so far is XDocument doc = new XDocument( new XElement("StockMarket", new XElement("StockDate", new XAttribute("Day", "02"),new XAttribute("Month","06"),new XAttribute("Year","2010")), new XElement("Stock") ) ); Since I am new to Linq to XML, I am presently struggling a lot and henceforth seeking for help. Using C#3.0 . Thanks

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Properly obsoleting old members in an XML Serializable class in C# VB .NET

- by George

Hi! Some time ago I defined a class that was serialized using XML. That class contained a serializable propertyA of integer type. Now I have extended and updated this class, whereby a new propertyB was added, whose type is another class that also has several serializable properties. The new propertyB is now supposed to play the role of propertyA, that is since type of propertyB is another class, one of its members would contain the value that previously propertyA contained, thus making peroptyA obsolete. What I am trying to figure out is how do I make sure that when I desireliaze the OLD version of this class (without propertyB in it), I make sure that the desreializer would take the value of propertyA from the old calss and set it as a value of one of the members of propertyB in a new class? Private WithEvents _Position As Position = New Position(Alignment.MiddleMiddle, 0, True, 0, True) Public Property Position() As Position 'NEW composite property that holds the value of the obsolted property, i.e. Alignment Get Return _Position End Get Set(ByVal value As Position) _Position = value End Set End Property Private _Alignment As Alignment = Alignment.MiddleMiddle <Xml.Serialization.XmlIgnore(), Obsolete("Use Position property instead.")> _ Public Property Alignment() As Alignment'The old, obsoleted property that I guess must be left for compliance with deserializing the old version of this class Get Return _Alignment End Get Set(ByVal value As Alignment) _Alignment = value End Set End Property Can you help me, please?

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Copy existing XML, duplicate element and modify

- by Robert

Hi, I have a tricky XSL problem at the moment. I need to copy the existing XML, copy a certain element (plus its child elements) and modify the value of two child-elements. The modifications are: divide value of the 'value' element by 110 and edit the value of the 'type' element from 'normal' to 'discount'. This is currently what I have: Current XML: <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> </prices> </data> </dataset> Expected result <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> <price> <value>45.00</value> <type>discount</type> </price> </prices> </data> </dataset> Any takers? I've gotten as far as copying the desired 'price' element using copy-of, but I'm stuck as to how to modify it next.

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creating xml from database

- by Prady

hi, I am creating an xml from salesforce database, Everything works fine except when there is a & in the data which is been fetched. <apex:page contenttype="text/xml" > controller="Test2ab" > <data > wiki-section="Timeline"> <apex:repeat > value="{!lsttask}" var="e" > <event > start="{!e.ActivityDate}" title= > "{!e.Subject}"> <apex:outputText > value="{!e.Subject}" /> </event> > </apex:repeat> </data></apex:page> and in the controller i am just querying > lsttask =[Select OwnerId,WhoId,Status,Subject,ActivityDate from Task where Status = 'Completed' Order By ActivityDate Desc]; How can i use an escape for the value retrieved from the database Thanks Prady

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Admob in xml not showing in Linear

- by NoobMe

i am implementing admob on my app it appears when the parent is in relative layout but i must not use the alignparentbottom so i am changing it to linear but it doesnt show when i change it to linear.. any tips? help? thanks in advance here it is in xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" > <RelativeLayout android:id="@+id/banner_holder" android:layout_width="match_parent" android:layout_height="wrap_content" > <ImageView android:id="@+id/offline_banner" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_centerInParent="true" android:background="@color/black" android:src="@drawable/offline_banner" /> <com.google.ads.AdView xmlns:ads="http://schemas.android.com/apk/lib/com.google.ads" android:id="@+id/adView" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerInParent="true" ads:adSize="SMART_BANNER" ads:adUnitId="@string/unit_id" ads:loadAdOnCreate="true" /> </RelativeLayout> <FrameLayout android:id="@+id/fragmentContainer" android:layout_width="match_parent" android:layout_height="wrap_content" /> </LinearLayout> i want the admob to be at the bottom part of the screen without using the alignparentbottom of relative layout thanks~

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Cannot get list of elements using Linq to XML

- by Blackator

Sample XML: <CONFIGURATION> <Files> <File>D:\Test\TestFolder\TestFolder1\TestFile.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile01.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile02.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile03.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile04.txt</File> </Files> <SizeMB>3</SizeMB> <BackupLocation>D:\Log backups\File backups</BackupLocation> </CONFIGURATION> I've been doing some tutorials but I am unable to get all the list of file inside the files element. It only shows the first element and doesn't display the rest. This is my code: var fileFolders = from file in XDocument.Load(@"D:\Hello\backupconfig1.xml").Descendants("Files") select new { File = file.Element("File").Value }; foreach (var fileFolder in fileFolders) { Console.WriteLine("File = " + fileFolder.File); } How do I display all the File in the Files element, the SizeMB and BackupLocation? Thanks

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Collaborate 2010: Spotlight on Oracle Content Management

- by [email protected]

Excitement is building for the Collaborate conference April 18th through the 22nd. Outside of the event being in Las Vegas, which for me often seems to add to the excitement, there will be a great lineup of Oracle Content Management focused sessions. In fact, there are currently over 30 content management sessions scheduled, and attendees will get to hear from customers, partners, as well as Oracle experts. Attendees should expect to hear a lot about Oracle Content Management 11g at Collaborate 2010. Roel Stalman and Andy MacMillan will kick off these discussions on Monday, April 19th as they present Oracle Content Management's product strategy and roadmap (10:45 - 11:45). Monday's lineup also includes sessions on Oracle Imaging and Process Management (I/PM) 11g and Oracle Forms Recognition (2:30 - 3:30), which were both released in January. For those customers using older versions of I/PM or Stellent IBPM, be sure not to miss the "migrating to I/PM 11g" session on Monday as well (1:15 - 2:15) as this should give you some insight into the migration process. Check out the entire list of Oracle Content Management sessions here. Another focus at Collaborate this year is to discuss the benefits of using Oracle Content Management with Oracle Applications - Oracle E-Business Suite, PeopleSoft, and Siebel - so be sure to check out these sessions too: Accelerating Accounts Payable Processes with Integrated Document Imaging(Monday, April 19th, 3:45 - 4:45)Supercharge Your Siebel Sales and Marketing with Integrated Document Management(Tuesday, April 20th, 2:00 - 3:00)Oracle Enterprise 2.0 for Oracle Applications: The Value of an Integrated E2.0 Platform(Tuesday, April 20th, 3:15 - 4:15)Comprehensive Human Resources Automation with Oracle Content Management(Wednesday, April 21st, 1:00 - 2:00) Collaborate is also the perfect opportunity to meet Oracle executives and product experts. Attendees can sign up for 1 on 1 meetings at the event, and there will be someone representing each Oracle Content Management product. These meetings are probably the best way to get your product questions answered in a face-to-face manner. It seems more and more to me that Oracle Content Management customers are viewing Collaborate as "the" conference to attend each year. I hope you have plans to attend and I will see you there.

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Retrieving XML node from a path specified in an attribute value of another node

- by Olivier PAYEN

From this XML source : <?xml version="1.0" encoding="utf-8" ?> <ROOT> <STRUCT> <COL order="1" nodeName="FOO/BAR" colName="Foo Bar" /> <COL order="2" nodeName="FIZZ" colName="Fizz" /> </STRUCT> <DATASET> <DATA> <FIZZ>testFizz</FIZZ> <FOO> <BAR>testBar</BAR> <LIB>testLib</LIB> </FOO> </DATA> <DATA> <FIZZ>testFizz2</FIZZ> <FOO> <BAR>testBar2</BAR> <LIB>testLib2</LIB> </FOO> </DATA> </DATASET> </ROOT> I want to generate this HTML : <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <td>Foo Bar</td> <td>Fizz</td> </tr> <tr> <td>testBar</td> <td>testFizz</td> </tr> <tr> <td>testBar2</td> <td>testFizz2</td> </tr> </table> </body> </html> Here is the XSLT I currently have : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="html" indent="yes"/> <xsl:template match="/ROOT"> <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr>  <xsl:apply-templates select="STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> </xsl:apply-templates> </tr> <xsl:apply-templates select="DATASET/DATA" /> </table> </body> </html> </xsl:template> <xsl:template match="COL">  <td> <xsl:value-of select="@colName"/> </td> </xsl:template> <xsl:template match="DATA"> <xsl:variable name="pos" select="position()" /> <tr> <xsl:for-each select="/ROOT/STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> <xsl:variable name="elementName" select="@nodeName" /> <td> <xsl:value-of select="/ROOT/DATASET/DATA[$pos]/*[name() = $elementName]" /> </td> </xsl:for-each> </tr> </xsl:template> </xsl:stylesheet> It almost works, the problem I have is to retrieve the correct DATA node from the path specified in the "nodeName" attribute value of the STRUCT block.

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placing the matched 2 different child elements xml values in a single line from xslt2.0

- by Girikumar Mathivanan

I have the below input xml, <GSKProductHierarchy> <GlobalBusinessIdentifier>ZGB001</GlobalBusinessIdentifier> <Hierarchy> <Material>335165140779</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006309</Level8> </Hierarchy> <Hierarchy> <Material>335165140780</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006310</Level8> </Hierarchy> <Texts> <ProductHierarchy>02AQ006310</ProductHierarchy> <Language>A</Language> <Description>CREAM</Description> </Texts> <Texts> <ProductHierarchy>02AQ006309</ProductHierarchy> <Language>B</Language> <Description>CREAM</Description> </Texts> as per the requirement, xsl should check the matched value of GSKProductHierarchy/Hierarchy/Level8 in the GSKProductHierarchy/Texts/ProductHierarchy elements...and its should result as below flat file. 335165140779|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|A|CREAM| 335165140780|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006310|02AQ006310|B|CREAM| Right now I have the below xslt, <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common" xmlns:set="http://exslt.org/sets" xmlns:str="http://exslt.org/strings" xmlns:java="http://xml.apache.org/xslt/java" xmlns:saxon="http://saxon.sf.net/" exclude-result-prefixes="exsl set str java saxon"> <xsl:output method="text" indent="yes"/> <xsl:variable name="VarPipe" select="'|'"/> <xsl:variable name="VarBreak" select="'
'"/> <xsl:template match="/"> <xsl:for-each select="GSKProductHierarchy/Hierarchy"> <xsl:variable name="currentIndex" select="position()"/> <xsl:variable name="Level8" select="Level8"/> <xsl:variable name="ProductHierarchy" select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:if test="$Level8=$ProductHierarchy"> <xsl:value-of select="Material"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level1"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level2"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level3"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level4"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level5"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level6"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level7"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level8"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Language"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Description"/> <xsl:value-of select="$VarPipe"/> <xsl:if test="not(position() = last())"> <xsl:value-of select="$VarBreak"/> </xsl:if> </xsl:if> </xsl:for-each> </xsl:template> can anyone please suggest what function should i need to use to get the desired result. Regards, Giri

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Can I make Windows to open Excel XML files with Excel without opening Explorer?

- by Sorin Sbarnea

I want to be able to open Excel XML files in Excel but without assigning XML directly to Excel. There are lots of XML files that are not Excel files and I don't want to open all of them in Excel. The file has proper header for opening in Excel but currently it does open Internet Explorer that asks me if I want to open the file with Excel, save or cancel. I just want to open it without two another annoying windows.

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What is a good XML Editor for Mac OS X?

- by g.

I am looking for a good lightweight XML viewer/editor for Mac OS X. It would only be for occasional use, so free options are preferable though paid options aren't out of the question. It would be used primarily for reviewing and making small changes to XML files and would require the following basic features. easily create a new file from clipboard (copy/paste) re-format (pretty print) xml syntax highlighting validation find

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XML-RPC with PHP and GoDaddy? Confusion sets in.

- by Chris Cooper

Hey folks, I am attempting to work with XML-RPC via PHP on a GoDaddy server. This same server is hosting a Wordpress Blog that makes use of XML-RPC and is functioning, though that may be unrelated... Whenever I attempt to use any functions that are integrated into PHP for use with XML-RPC, I get an error (function list here: http://us3.php.net/manual/en/ref.xmlrpc.php) e.g.: Fatal error: Class 'xmlrpc_client' not found Is this because XML-RPC's PHP functions are not enabled on my server? If so, how do I go about enabling those - it would seem I would have to install the XML-RPC library to do so and of course I cannot do that on a shared server. Doesn't Wordpress use the same batch of XML-RPC functions though (it works fine)? I think I have managed to thoroughly confuse myself. I have zero experience with XML-RPC.

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I am using jquery ajax using text() but any html written in the XML doesn't render?

- by Xtian

So I have Jquery Ajax working real nice, but an issue I am having is in my XML if I want to bold a work or Italicize a sentence, if I do it in the XML using HTML tags it will not show up. I am pretty sure it is due to using the .text(). Any suggestions on a work around for this? $(document).ready(function(){ $.ajax({ type: "GET", url: "xml/sites.xml", dataType: "xml", success: function(xml) { $(xml).find('site').each(function(){ $(this).find('desc').each(function(){ var brief = $(this).find('brief').text(); var long = $(this).find('long').text(); var url = $(this).find('url').text(); $('<div class="brief"></div>').html(brief).appendTo('#link_'+id);

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What is your prefered way to return XML from an ActionMethod in Asp.net MVC?

- by serbrech

I am displaying charts that load the data asynchronously because the searches are the work to fetch the data is quite heavy. The data has to be return as XML to make the chart library happy. My ActionMethods return a ContentResult with the type set as text/xml. I build my Xml using Linq to XML and call ToString. This works fine but it's not ideal to test. I have another idea to achieve this which would be to return a view that builds my XML using the XSLT View engine. I am curious and I always try to do the things "the right way". So how are you guys handling such scenarios? Do you implement a different ViewEngine (like xslt) to build your XML or do you Build your XML inside your controller (Or the service that serves your controller)?

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