Search Results

Search found 90812 results on 3633 pages for 'user story'.

Page 76/3633 | < Previous Page | 72 73 74 75 76 77 78 79 80 81 82 83  | Next Page >

  • Sudo won't execute command as another user

    - by TOdorus
    I'm trying to get a unicorn server to start when the server boots. I've created a shell script which works if I log as the ubuntu user and run /etc/init.d/unicorn start Shell script #!/bin/sh case "$1" in start) cd /home/ubuntu/projects/asbest/current/ unicorn_rails -c /home/ubuntu/projects/asbest/current/config/unicorn.rb -D -E production ;; stop) if ps aux | awk '{print $2 }' | grep `cat ~/projects/asbest/current/tmp/pids/unicorn.pid`> /dev/null; then kill `cat ~/projects/asbest/current/tmp/pids/uni$ ;; restart) $0 stop $0 start ;; esac When I rebooted the server I noticed that the unicorn server wasn't listening to a socket. Since I ran the code succesfully as the ubuntu user I modified the script to let it always use the ubuntu user via sudo. #!/bin/sh case "$1" in start) cd /home/ubuntu/projects/asbest/current/ sudo -u ubuntu unicorn_rails -c /home/ubuntu/projects/asbest/current/config/unicorn.rb -D -E production ;; stop) if ps aux | awk '{print $2 }' | grep `cat ~/projects/asbest/current/tmp/pids/unicorn.pid`> /dev/null; then sudo -u ubuntu kill `cat ~/projects/asbest/current/tmp/pids/uni$ ;; restart) $0 stop $0 start ;; esac After rebooting unicorn still wouldn't start, so I tried running the script from the command line. Now I get the following error sudo: unicorn_rails: command not found I've searched high and low to what could cause this, but I'm afraid I've tapped my limited understanding of Linux. From what I can understand is that although sudo should use the ubuntu user to execute the commands, it still uses the environment of the root user, which isn't configured to run ruby or unicorn. Does anybody have any experience with this?

    Read the article

  • Revoke directory access for a particular user in Solaris

    - by permissiontomars
    I have a need to allow directory access to a particular user on my file system. I want this user to be unable to access any other directory in my file system (initially anyway. It may need access to some directories later). For example: I have a directory called /opt/mydir. - I want my dedicated user to only be able to access this directory, and nothing else. - I want all other users to be able to access this directory as normal. I'm new to Linux and its permissions. I've read a fair bit of background material but I'm a little confused. Is there anyway to revoke permissions to /opt/mydir for a single dedicated user? A possible flawed method would be to only allow access to /opt/mydir and exclude every other user. This won't work because I want all other users to work as normal; accessing the directory. I'm working on Solaris 10. Any suggestions are appreciated.

    Read the article

  • How can I limit other (administrator) users access to my profile?

    - by kojo
    Hi, We in our club have a computer with Windows 7 Professional that every club member may use. And everyone has their own separate account. Those accounts have to have administrator priveleges since I want everyone to be able to install any software and use any feature they want. However, there is a single thing that they shouldn't be allowed to do - that is, look into another users' profiles. Now when anyone goes to 'c:\Users(Any User Name)' a little prompt appears that this folder is secured and whether you really want to look inside. Simply clickinh 'ok' give you access to any profile. I tried disabling taking ownership for Administrators group in Group Policies but that had no effect. How can I effectively prohibit administrators looking into each others' profiles and documents?

    Read the article

  • Setup SSH key per user for Git access

    - by ThatGuyJJ
    I'm setting up a site that will have multiple development instances running on the same server. Essentially, we'd have dev-a.whatever.com, dev-b.whatever.com, etc.. all running off a single server. I want to give each user some bit of SSH access in order to update and check in code from our Git repository and to manage files via SFTP. However, I want to restrict each user to their own site as well. So if you have access to dev-a.whatever.com, you don't also have access to dev-b.whatever.com and so on. The restriction is already in place if I login via FTP as a certain user, I can't navigate outside my own site -- but if I grant SSH access to that account I can immediately navigate to any file on the server in SFTP. Is RSSH part of the solution? And how can I assign the correct SSH pub key to the corresponding user? We're using BeanStalk for our Git repository management if that makes any impact.

    Read the article

  • Provide a user with service start/stop permissions

    - by slakr007
    I have a very basic domain that I use for development. I want to create a GPO that provides users in the Backup Operators group with start/stop permissions for two specific services on a specific server. I have read several articles about this, and they all indicate that this is very easy. Create a GPO, give the user start/stop permissions to the services under Computer Configuration Policies Windows Settings Security Settings System Services, and voila. Done. Not so much, but I have to be doing something wrong. My install is pretty much the default. The domain controller is in the Domain Controllers OU, the Backup Operators group is under Builtin, and I created a user called Backup under Users. I created a GPO and linked it to the Domain Controllers OU. In the GPO I give the Backup user permission to start/stop two specific services on the server. I forced an update with gpupdate. I used Group Policy Results to verify that my GPO is the winning GPO giving the user the permission to start/stop the two services. However, the user is still unable to start/stop the services. I attempted different loopback settings on the GPO to no avail. I'm sort of at a loss here.

    Read the article

  • I can not sign in as a user to the Domain [closed]

    - by Dior
    i have installed 2 windows 7 3 windows server 2008 I am trying to sign in with the second windows 7 machine as a user but i can not. What is the solution ? Thank you ! I use Vmplayer. With the second macine (windows 7) i try to log in with one of the user name example:JOwens after hit enter i get user name or password not correct. I try with other user name i have 25 and the same . I could sing in only with one of them. I joied to the Domain. I can not sign in with the users.

    Read the article

  • How does one track down an error using the YII Framework?

    - by ian
    I am learning the Yii Framework and I got this error wich does not really point to the specific pages I am working on or as far as i can tell show me where I should start looking for my problem. How do I make sense of this? As far as I can see all my 'type_id' references are typed in correctly. CException Description Property "Project.type_id" is not defined. Source File /Users/user/Dropbox/localhost/yii/framework/db/ar/CActiveRecord.php(107) 00095: */ 00096: public function __get($name) 00097: { 00098: if(isset($this->_attributes[$name])) 00099: return $this->_attributes[$name]; 00100: else if(isset($this->getMetaData()->columns[$name])) 00101: return null; 00102: else if(isset($this->_related[$name])) 00103: return $this->_related[$name]; 00104: else if(isset($this->getMetaData()->relations[$name])) 00105: return $this->getRelated($name); 00106: else 00107: return parent::__get($name); 00108: } 00109: 00110: /** 00111: * PHP setter magic method. 00112: * This method is overridden so that AR attributes can be accessed like properties. 00113: * @param string property name 00114: * @param mixed property value 00115: */ 00116: public function __set($name,$value) 00117: { 00118: if($this->setAttribute($name,$value)===false) 00119: { Stack Trace #0 /Users/user/Dropbox/localhost/yii/framework/db/ar/CActiveRecord.php(107): CComponent->__get('type_id') #1 /Users/user/Dropbox/localhost/trackstar/protected/views/project/_view.php(15): CActiveRecord->__get('type_id') #2 /Users/user/Dropbox/localhost/yii/framework/web/CBaseController.php(119): require('/Users/user/Dro...') #3 /Users/user/Dropbox/localhost/yii/framework/web/CBaseController.php(88): CBaseController->renderInternal('/Users/user/Dro...', Array, true) #4 /Users/user/Dropbox/localhost/yii/framework/web/CController.php(748): CBaseController->renderFile('/Users/user/Dro...', Array, true) #5 /Users/user/Dropbox/localhost/yii/framework/zii/widgets/CListView.php(215): CController->renderPartial('_view', Array) #6 /Users/user/Dropbox/localhost/yii/framework/zii/widgets/CBaseListView.php(152): CListView->renderItems() #7 [internal function]: CBaseListView->renderSection(Array) #8 /Users/user/Dropbox/localhost/yii/framework/zii/widgets/CBaseListView.php(135): preg_replace_callback('/{(\w+)}/', Array, '{summary}?{sort...') #9 /Users/user/Dropbox/localhost/yii/framework/zii/widgets/CBaseListView.php(121): CBaseListView->renderContent() #10 /Users/user/Dropbox/localhost/yii/framework/web/CBaseController.php(174): CBaseListView->run() #11 /Users/user/Dropbox/localhost/trackstar/protected/views/project/index.php(17): CBaseController->widget('zii.widgets.CLi...', Array) #12 /Users/user/Dropbox/localhost/yii/framework/web/CBaseController.php(119): require('/Users/user/Dro...') #13 /Users/user/Dropbox/localhost/yii/framework/web/CBaseController.php(88): CBaseController->renderInternal('/Users/user/Dro...', Array, true) #14 /Users/user/Dropbox/localhost/yii/framework/web/CController.php(748): CBaseController->renderFile('/Users/user/Dro...', Array, true) #15 /Users/user/Dropbox/localhost/yii/framework/web/CController.php(687): CController->renderPartial('index', Array, true) #16 /Users/user/Dropbox/localhost/trackstar/protected/controllers/ProjectController.php(148): CController->render('index', Array) #17 /Users/user/Dropbox/localhost/yii/framework/web/actions/CInlineAction.php(32): ProjectController->actionIndex() #18 /Users/user/Dropbox/localhost/yii/framework/web/CController.php(300): CInlineAction->run() #19 /Users/user/Dropbox/localhost/yii/framework/web/filters/CFilterChain.php(129): CController->runAction(Object(CInlineAction)) #20 /Users/user/Dropbox/localhost/yii/framework/web/filters/CFilter.php(41): CFilterChain->run() #21 /Users/user/Dropbox/localhost/yii/framework/web/CController.php(999): CFilter->filter(Object(CFilterChain)) #22 /Users/user/Dropbox/localhost/yii/framework/web/filters/CInlineFilter.php(59): CController->filterAccessControl(Object(CFilterChain)) #23 /Users/user/Dropbox/localhost/yii/framework/web/filters/CFilterChain.php(126): CInlineFilter->filter(Object(CFilterChain)) #24 /Users/user/Dropbox/localhost/yii/framework/web/CController.php(283): CFilterChain->run() #25 /Users/user/Dropbox/localhost/yii/framework/web/CController.php(257): CController->runActionWithFilters(Object(CInlineAction), Array) #26 /Users/user/Dropbox/localhost/yii/framework/web/CWebApplication.php(320): CController->run('') #27 /Users/user/Dropbox/localhost/yii/framework/web/CWebApplication.php(120): CWebApplication->runController('project') #28 /Users/user/Dropbox/localhost/yii/framework/base/CApplication.php(135): CWebApplication->processRequest() #29 /Users/user/Dropbox/localhost/trackstar/index.php(12): CApplication->run() #30 {main} 2011-10-17 18:17:18 Apache/2.2.17 (Unix) mod_ssl/2.2.17 OpenSSL/0.9.8r DAV/2 PHP/5.3.6 Yii Framework/1.1.2

    Read the article

  • Update Boolean attributes from another controller

    - by sidonstackoverflow
    I have Users controller and session controller . I want to update one user attribute from session controller . How can i do that ?? I am currently using rails 4.0 . Users controller: class UsersController < ApplicationController def show if Spec.find_by_user_id params[:id] @user = User.find(params[:id]) @spec = Spec.find_by_user_id params[:id] else if params[:id] == session[:id] redirect_to spec_edit_path(params[:id]) else redirect_to(community_index_path, {:notice => "Sorry there was an error"}) end end end def index end def new @user = User.new end def create @user = User.new(user_params) if @user.save flash[:success] = "Welcome buddy !" redirect_to @user else render 'new' end end private def user_params params.require(:user).permit(:name, :email, :password, :password_confirmation) end end Sessions Controller : class SessionsController < ApplicationController def new end def create user = User.find_by(email: params[:session][:email]) if user && user.authenticate(params[:session][:password]) session[:user_id] = user.id User.update(user.status, 'true') redirect_to root_url, :notice => 'You successfully logged in ' else flash.now[:error] = 'Invalid email/password combination' # Not quite right! render 'new' end end def destroy session[:user_id] = nil redirect_to root_url, :notice => 'You successfully logged out ' end end In above code when User logged in i just want to update my boolean column status at users table from sessions controller , but i failed . I am thankful to whom would like to answer my question !

    Read the article

  • is it possible to request UIWebView using user agent as Safari on iPhone?

    - by RAGOpoR
    i try to request on my application via this url http://reader.mac.com/mobile/v1/http%3A%2F%2Ffeeds.feedburner.com%2F9To5Mac-MacAllDay and it also return that it available on iPhone only how can i fix it? mycode NSMutableURLRequest *urlRequest = [[NSMutableURLRequest alloc] initWithURL: [NSURL URLWithString: myurl]]; [urlRequest setValue: @"iPhone" forHTTPHeaderField: @"Mozilla/5.0 (iPhone; U; CPU iPhone OS 3_0 like Mac OS X; en-us) AppleWebKit/528.18 (KHTML, like Gecko) Version/4.0 Mobile/7A341 Safari/528.16"]; [self.myWebView loadRequest:urlRequest];

    Read the article

  • Adding a custom control to a page, then adding multiple custom children into that one, null user con

    - by Rickjaah
    Hello all, While nerding my way through the day again. I came across a problem concerning adding children to an already add child control. I can add the controls, but when trying to use the controls in the added control, they all return null. This is the method: protected override CreateChildControls(EventArgs e) { UserControl uControl = LoadControl("~/controls/TwoColumn.ascx"); PlaceHolder holder = uControl.Controls.FindControl(phrContentMiddle) as PlaceHolder; holder.Controls.Add(LoadControl("~/controls/ImageShowControl"); } When i try to call any type of button/UserControl inside the ImageShowControl.... All return null. Is this something in the Page LifeCycle? If so, what is the way to go to realize this?

    Read the article

  • What is the recommended way to handle different user roles in a C# application?

    - by Sergio Tapia
    I'm going to make a small application for a business that will be used locally for scanning, and storing documents in a database located on the local machine or on a machine located in the same LAN. I could create a table called Users with username and password and according to the usertype ID show a form, or another form. But I'm more interested in the recommended approach by seasoned programmers. Any advice?

    Read the article

  • Where does the delete control go in my Cocoa user interface?

    - by Graham Lee
    Hi, I have a Cocoa application managing a collection of objects. The collection is presented in an NSCollectionView, with a "new object" button nearby so users can add to the collection. Of course, I know that having a "delete object" button next to that button would be dangerous, because people might accidentally knock it when they mean to create something. I don't like having "are you sure you want to..." dialogues, so I dispensed with the "delete object". There's a menu item under Edit for removing an object, and you can hit Cmd-backspace to do the same. The app supports undoing delete actions. Now I'm getting support emails ranging from "does it have to be so hard to delete things" to "why can't I delete objects?". That suggests I've made it a bit too hard, so what's the happy middle ground? I see applications from Apple that do it my way, or with the add/remove buttons next to each other, but I hate that latter option. Is there another good (and preferably common) convention for delete controls? I thought about an action menu but I don't think I have any other actions that would go in it, rendering the menu a bit thin.

    Read the article

  • How can variadic char template arguments from user defined literals be converted back into numeric types?

    - by Pubby
    This question is being asked because of this one. C++11 allows you to define literals like this for numeric literals: template<char...> OutputType operator "" _suffix(); Which means that 503_suffix would become <'5','0','3'> This is nice, although it isn't very useful in the form it's in. How can I transform this back into a numeric type? This would turn <'5','0','3'> into a constexpr 503. Additionally, it must also work on floating point literals. <'5','.','3> would turn into int 5 or float 5.3 A partial solution was found in the previous question, but it doesn't work on non-integers: template <typename t> constexpr t pow(t base, int exp) { return (exp > 0) ? base * pow(base, exp-1) : 1; }; template <char...> struct literal; template <> struct literal<> { static const unsigned int to_int = 0; }; template <char c, char ...cv> struct literal<c, cv...> { static const unsigned int to_int = (c - '0') * pow(10, sizeof...(cv)) + literal<cv...>::to_int; }; // use: literal<...>::to_int // literal<'1','.','5'>::to_int doesn't work // literal<'1','.','5'>::to_float not implemented

    Read the article

  • Splitting string to integer from single-line user input?

    - by pootzko
    I just started learning some ruby, and I want to do something like this: print "Insert two numbers: " a, b = gets.split(" ") but I want to make a and b to be integers at the same time (in the same line).. If I add .to_i to the second line (before or after split(" ")), it doesn't work... so, how should I approach this? mapping, splitting, slicing? ok, I know I could use scanf, but other than scanf, how would I do this? sorry for such a noobish question, but I just couldn't find a good enough answer only googling...

    Read the article

  • What is the best way for the application to refer to the user?

    - by user292450
    Forgive my noobishness, first time poster on stackoverflow! I can have the application read: "view your messages" "view my messages" "edit your profile" "edit my profile" etc. and others like that. Is one of these more correct then the other? I suppose that I could use neither and just leave it without any pronoun, but I would rather not. The person grading is a real stickler for "grammar" in code. Any input would be appreciated!

    Read the article

  • Auto Login facebook user into application

    - by user537562
    So, Here is the scenario I am trying to fix. A returning user is logged into facebook but not logged into the application. In this case when the user tries to load the application, since the user cookie is not attained yet, it redirects the user to the login page. I googled around and found this solution, FB.Event.subscribe('auth.sessionChange', function(response) { if (response.session) { window.location.reload(); } } basically whats happening here is, we are registering to facebook for a login/logout event and when it receives a response, we reload the page. Now its loads the right page since we have the user cookie on our site domain after the first load. this works, but the problem is the double load. It takes a lot of time. How can I attain the user cookie on server side for returning user? so that I don't have to do the initial page reload. Also, I have looked at yelp, and somehow they are able to load the user information without doing double load, does any body know they are able to do it? Any help is greatly appreciated, Thanks!

    Read the article

  • user inheritance in django

    - by amateur
    Hi guys, I saw a couple of ways extending user information of users and decided to adopt the model inheritance method. for instance, I have : class Parent(User): contact_means = models.IntegerField() is_staff = False objects = userManager() Now it is done, I've downloaded django_registration to help me out with sending emails to new users. The thing is, instead of using registration forms to register new user, I want to to invoke the email sending/acitvation capability of django_registration. So my workflow is: 1. add new Parent object in admin page. 2. send email My problem is, the django-registration creates a new registration profile together with a new user in the user table. how do I tweak this such that I am able to add the user entry into the custom user table. I have tried to create a modelAdmin and alter the save_model method to launch the create_inactive_user from django_registration, however I do not how to save the user object generated from django_registration into my Parent table when I have using model inheritance and I do not have a Foreign key attribute in my parent model.

    Read the article

  • Facebook App : Problem with storing user info

    - by Jack
    I want to store basic user info like name and proxied email into my MySQL database. Here's my code $user = $facebook->require_login($required_permissions = 'publish_stream','status_update','email'); $con = mysql_connect("xxxx","xxxxx","xxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("xxx_userdb", $con); //Uptil Here it is working fine...No problem with db connection $fql_firstname = "select first_name from user where uid = '$user'"; $fql_lastname = "select last_name from user where uid = '$user'"; $fql_email = "select proxied_email from user where uid = '$user'"; $fql_fname_result = $facebook->api_client->fql_query($fql_firstname); $fql_lname_result = $facebook->api_client->fql_query($fql_lastname); $fql_email_result = $facebook->api_client->fql_query($fql_email); echo "<pre>FQL Result:" . print_r($fql_fname_result,true) . "</pre>"; echo "<pre>FQL Result:" . print_r($fql_lname_result,true) . "</pre>"; echo "<pre>FQL Result:" . print_r($fql_email_result,true) . "</pre>"; Here's the output I get FQL Result: FQL Result: FQL Result: What am I doing wrong?

    Read the article

  • managing classes when everything is relative to a user in nhibernate (orm)

    - by Schotime
    Firstly I have three entities. Users, Roles, Items A user can have multiple Roles. An item gets assigned to one or more roles. Therefore a user will have access to a distinct set of items. Now there is a few ways I can see this working. There is a Collection on Users which has Roles via a many-to-many assoc. Then each Role in this collection will have its own collection of Items. So for each user I would have to get the User (using nhib and fetch the roles and items with it) then either do a selectMany on the Items in each Role to get all the Items for the user or do a couple of foreach's to port the data to a view or dto model. Create a db trigger to automatically insert into another table that just has the relationship between user and items so that on my User entity I only have a Items collections which has all the items assigned to me. Some other way that i can't think of yet, because I'm new to nHibernate. Now i know that the trigger doesn't feel right but I'm not sure how to do this. We also have some hierarchy later where a user may be in charge of a group of users. If anyone could shed some light on how they go about these scenarios in nhibernate or another orm that would be great, or point be in a direction. I know that in the past you would have to enter all combinations into a table so that the query worked, but when you know sql its not too bad. If you need any other info then let me know. Cheers

    Read the article

  • Cross-Application User Authentication

    - by Chris Lieb
    We have a webapp written in .NET that uses NTLM for SSO. We are writing a new webapp in Java that will tightly integrate with the original application. Unfortunately, Java has no support for performing the server portion of NTLM authentication and the only library that I can find requires too much setup to be allowed by IT. To work around this, I came up with a remote authentication scheme to work across applications and would like your opinions on it. It does not need to be extremely secure, but at the same time not easily be broken. User is authenticated into .NET application using NTLM User clicks link that leaves .NET application .NET application generates random number and stores it in the user table along with the user's full username (domain\username) Insecure token is formed as random number:username Insecure token is run through secure cipher (likely AES-256) using pre-shared key stored within the application to produce a secure token The secure token is passed as part of the query string to the Java application The Java application decrypts the secure key using the same pre-shared key stored within its own code to get the insecure token The random number and username are split apart The username is used to retrieve the user's information from the user table and the stored random number is checked against the one pulled from the insecure token If the numbers match, the username is put into the session for the user and they are now authenticated If the numbers do not match, the user is redirected to the .NET application's home page The random number is removed from the database

    Read the article

< Previous Page | 72 73 74 75 76 77 78 79 80 81 82 83  | Next Page >