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  • Syntax Error? When parsing XML value

    - by Ace Munim
    I don't know if I'm having a syntax error but the compiler is giving me TypeError: 'undefined' is not an object (evaluating 'xmlDoc.getElementsByTagName("icon")[i].childNodes') Its me giving me this problem when im parsing the XML from my server, my actual javascript code is like this var xmlDoc = Obj.responseXML; var count = 0; if(xmlDoc){ while(count <= xmlDoc.getElementsByTagName("item").length){ document.getElementById("flow").innerHTML += "<div class='item'><img class='content' src='" + xmlDoc.getElementsByTagName("icon")[i].childNodes[0].nodeValue.replace(/\s+$/g,' ') +"' /></div>"; count++; } }else{ alert("Unable to parse!"); } and my XML goes like this. <feed> <item> <title>Given Title</title> <icon> http://i178.photobucket.com/albums/w255/ace003_album/Logo-ETC-RGB-e1353503652739.jpg </icon> </item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> </feed> i just want to parse the image link and to show it.

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  • XML Serialization and Deserialization in C#

    - by SOF User
    <job id="ID00004" name="PeakValCalcO"> <uses file="Seismogram_FFI_0_1_ID00003.grm" link="input" /> <uses file="PeakVals_FFI_0_1_ID00003.bsa" link="output" /> </job> <job id="ID00005" name="SeismogramSynthesis" > <uses file="FFI_0_1_txt.variation-s07930-h00000" link="input" /> <uses file="Seismogram_FFI_0_1_ID00005.grm" link="output" /> </job> Let say I have this XML I want to convert into .net Object how can do this i tried it but it doesn't work correct... public class jobs : List<job> { } public class job { public string id { get; set; } public string name { get; set; } public List<uses> Files { get; set; } } public class uses { public string file { get; set; } public string link { get; set; } } private void Form1_Load(object sender, EventArgs e) { XmlSerializer serializer = new XmlSerializer(typeof(jobs)); TextReader tr = new StreamReader("CyberShake_100.xml"); job b = (job)serializer.Deserialize(tr); tr.Close(); }

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  • xml schema ........

    - by matt
    ive made an xml schema all the code basically and was wonder is there a way that the code genarates something like this http://www.novell.com/documentation/extend52/Docs/help/Director/books/PGImages/novell_portlet_xml_schema.gif and if i can then how do you do it?

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  • Is this XML file correct for RSS feeding?

    - by Hermet
    Hi guys I am generating a XML-RSS type file from PHP. The output for example is like this <?xml version="1.0" encoding="iso-8859-1"?> <rss version="2.0"> <channel> <title>Mi web mola</title> <link>http://www.dominio.com/blog.php</link> <language>es-ES</language> <description>Mallas y eso</description> <generator>Autor</generator> <item> <title>Articulo de prueba</title> <link>http://www.midominio.com/2342</link> <pubDate>14/06/2010</pubDate> <description><![CDATA[Descripcion de prueba bla bla bla]]></description> <content:encoded><![CDATA[Contenido prueba]]></content:encoded> </item> </channel> </rss> ... and all I can see in the Firefox preview is the title and the description of the blog, not the items, but in the source it appears correctly, so I've thought it must be a parse error or something like that.. What could be wrong? Again, excuse me for my bad english, and thank you very much.

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  • remove a duplicate element(with specific value) from xml using linq

    - by Q8Y
    If I have this xml <?xml version="1.0" encoding="utf-8"?> <super> <A value="1234"> <a1 xx="000" yy="dddddd" /> <a1 xx="111" yy="eeeeee" /> <a1 xx="222" yy="ffffff"/> </A> </super> and I need to remove a1 element (that have xx=222) completely. why this won't happen using my code?? i realized that it will delete it only if it was placed the first element(i.e, if i want to delete a1 that have x=000 , it will delete it since its the first one), why is that?? what wrong with the code ?? var employee = from emp in element.Elements("A") where (string)emp.Element("a1").Attribute("xx") == "222" select emp.Element("a1"); foreach (var empployee_1 in employee) { empployee_1.Remove(); } element.Save(@"TheLocation"); thanks alot

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  • linq to xml enumerating over descendants

    - by gh9
    Hi trying to write a simple linq query from a tutorial I read. But i cannot seem to get it to work. I am trying to display both the address in the attached xml document, but can only display the first one. Can someone help me figure out why both aren't being printed. Thank you very much <?xml version="1.0" encoding="utf-8" ?> <Emails> <Email group="FooBar"> <Subject>Test subject</Subject> <Content>Test Content</Content> <EmailTo> <Address>[email protected]</Address> <Address>[email protected]</Address> </EmailTo> </Email> </Emails> Dim steve = (From email In emailList.Descendants("Email") _ Where (email.Attribute("group").Value.Equals("FooBar")) _ Select content = email.Element("EmailTo").Descendants("Address")).ToList() If Not steve Is Nothing Then For Each addr In steve Console.WriteLine(addr.Value) Next Console.ReadLine() End If

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  • C# xml read, show error

    - by gloris
    Whats wrong with my code? XmlTextReader textReader = new XmlTextReader(@"D:\xml_file.xml"); textReader.Read(); // If the node has value while (textReader.Read()) { // Move to fist element textReader.MoveToElement(); Console.WriteLine("XmlTextReader Properties Test"); Console.WriteLine("==================="); // Read this element's properties and display them on console Console.WriteLine("id:" + textReader.id.ToString()); Console.WriteLine("name:" + textReader.name.ToString()); Console.WriteLine("time:" + textReader.time.ToString()); } Console.ReadLine() show erron on: id, name, time My XML file: <students> <student> <id>1</id> <name>Rikko Nora</name> <time>2010-03-12</time> </student> <student> <id>2</id> <name>Rikko Nora2</name> <time>2010-05-15</time> </student> </students>

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  • Uploading an xml direct to ftp

    - by Joshua Maerten
    i put this direct below a button: XmlDocument doc = new XmlDocument(); XmlElement root = doc.CreateElement("Login"); XmlElement id = doc.CreateElement("id"); id.SetAttribute("userName", usernameTxb.Text); id.SetAttribute("passWord", passwordTxb.Text); XmlElement name = doc.CreateElement("Name"); name.InnerText = nameTxb.Text; XmlElement age = doc.CreateElement("Age"); age.InnerText = ageTxb.Text; XmlElement Country = doc.CreateElement("Country"); Country.InnerText = countryTxb.Text; id.AppendChild(name); id.AppendChild(age); id.AppendChild(Country); root.AppendChild(id); doc.AppendChild(root); // Get the object used to communicate with the server. FtpWebRequest request = (FtpWebRequest)WebRequest.Create("ftp://users.skynet.be"); request.Method = WebRequestMethods.Ftp.UploadFile; request.UsePassive = false; // This example assumes the FTP site uses anonymous logon. request.Credentials = new NetworkCredential("fa490002", "password"); // Copy the contents of the file to the request stream. StreamReader sourceStream = new StreamReader(); byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); request.ContentLength = fileContents.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close(); FtpWebResponse response = (FtpWebResponse)request.GetResponse(); response.Close(); MessageBox.Show("Created SuccesFully!"); this.Close(); but i always get an error of the streamreader path, what do i need to place there ? the meening is, creating an account and when i press the button, an xml file is saved to, ftp://users.skynet.be/testxml/ the filename is from usernameTxb.Text + ".xml".

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  • How to search within an xml data set?

    - by user187580
    Hi, I have some xml data and I am trying to keyword search data. For example, if I search "some" for the following data it returns me the <id> and <title>. <resource> <id>101</id> <title>Test Environment</title> <description><b>Some</b> description. </description> <type>classroom</type> </resource> <resource> <id>102</id> <title>ABC Test Environment</title> <description><b>Some</b> another description. </description> <type>classroom</type> </resource> ... I had a look on on xpath e.g. $xml->xpath('//title') but looks for elements only. Basically what I need to do is to create a functionality where users can keyword search within the above data set which I receive from third party api in the above format. Any ideas how I can achieve this? using PHP/ Javascript etc. Thanks.

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  • parse a special xml in python

    - by zhaojing
    I have s special xml file like below: <alarm-dictionary source="DDD" type="ProxyComponent"> <alarm code="402" severity="Alarm" name="DDM_Alarm_402"> <message>Database memory usage low threshold crossed</message> <description>dnKinds = database type = quality_of_service perceived_severity = minor probable_cause = thresholdCrossed additional_text = Database memory usage low threshold crossed </description> </alarm> ... </alarm-dictionary> I know in python, I can get the "alarm code", "severity" in tag alarm by: for alarm_tag in dom.getElementsByTagName('alarm'): if alarm_tag.hasAttribute('code'): alarmcode = str(alarm_tag.getAttribute('code')) And I can get the text in tag message like below: for messages_tag in dom.getElementsByTagName('message'): messages = "" for message_tag in messages_tag.childNodes: if message_tag.nodeType in (message_tag.TEXT_NODE, message_tag.CDATA_SECTION_NODE): messages += message_tag.data But I also want to get the value like dnkind(database), type(quality_of_service), perceived_severity(thresholdCrossed) and probable_cause(Database memory usage low threshold crossed ) in tag description. That is, I also want to parse the content in the tag in xml. Could anyone help me with this? Thanks a lot!

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  • XML with iPhone app !

    - by totato
    hi .. I just work on web-based application for iPhone, And I try to retrieve data from my website to my app. can I edit XML code for my website as I want to be in my iPhone app? for example, XML for my website is: <item> <title>Announcement title</title> <link>iphone feed</link> <description>Announcement type</description> <category>Students</category> <pubDate>April 5, 2010, 12:50 pm</pubDate> <guid>iphone feed</guid> </item> but I can't retrieve all of this to the tableview in my app. So, I will edit the code to be like this: <item> <category name="staff"> <Announcement title="welcome back"> <description> hope all of you enjoy in the vacation, and welcome back to university </description> </Announcement> </category> </item> Is this the right way?

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  • Populate on demand a TreeView with datas in an XML

    - by m6a-uds
    Hi I have a large XML file (3000+ nodes) that I want to represent in a TreeView on ASP.NET. I cannot databind it to a XMLDataSource because loading the TreeView will then be way too slow (I never even waited long enough to see it finish...) So the solution for this would be to use the PopulateOnDemand property of the TreeNodes to load data only when needed. Problem is, I can't think of a way to acheive this... How can-I, based on the ID of a node, search a XMLDocument to get all the childnodes of the node having this ID? XML would look like that: <document ID=1> <document ID=2> <document ID=3> </document> </document> <document ID=4> </document> </document> There are nor rules on how much levels it can go down or anything...

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  • SQL Server Querying An XML Field

    - by Gavin Draper
    I have a table that contains some meta data in an XML field. For example <Meta> <From>[email protected]</From> <To> <Address>[email protected]</Address> <Address>[email protected]</Address> </To> <Subject>ESubject Goes Here</Subject> </Meta> I want to then be able to query this field to return the following results From To Subject [email protected] [email protected] Subject Goes Here [email protected] [email protected] Subject Goes Here I've written the following query SELECT MetaData.query('data(/Meta/From)') AS [From], MetaData.query('data(/Meta/To/Address)') AS [To], MetaData.query('data(/Meta/Subject)') AS [Subject] FROM Documents However this only returns one record for that XML field. It combines both the 2 addresses into one result. Is it possible for split these on to separate records? The result I'm getting is From To Subject [email protected] [email protected] [email protected] Subject Goes Here Thanks Gav

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  • How to send XML data through socket InputStream

    - by THeK3nger
    Hi, I'm trying to write a client-server application in Java with an XML-based protocol. But I have a great problem! See this part of client code: InputStream incoming = skt.getInputStream(); //I get Stream from Socket. OutputStream out = skt.getOutputStream(); [...] XMLSerializer serializer = new XMLSerializer(); //This create an XML document. tosend = WUTPClientWriter.createMessage100(projectid, cpuclock, cpunumber); serializer.setOutputByteStream(out); serializer.serialize(tosend); At this point server fall in deadlock. It wait for EOF but I can't send it because if I use out.close(); or skt.shutdownOutput(); I close Socket and I must keep alive this connection. I can't send '\0' becouse I get Parse Error in the server. How can I do? Can I "close" output stream without close socket? RESOLVED I've created new class XMLStreamOutput and XMLStreamInput with advanced Stream gesture.

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  • Switch XML value for another in google maps

    - by JeffP
    all thanks for taking a look. Problem: Using Google maps I need to switch catid value to another value. How would I approach this and display it in a the window. E.G var catid = { 2: { newcatid: 'london' }, 4: { newcatid: 'newyork' } }; function load() { var map = new google.maps.Map(document.getElementById("map"), { center: new google.maps.LatLng(47.6145, -122.3418), zoom: 5, mapTypeId: 'roadmap' }); var infoWindow = new google.maps.InfoWindow; // Change this depending on the name of your PHP file downloadUrl("index_xml.php", function(data) { var xml = data.responseXML; var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("title"); var address = markers[i].getAttribute("address"); var catid = markers[i].getAttribute("catid"); var point = new google.maps.LatLng( parseFloat(markers[i].getAttribute("latitude")), parseFloat(markers[i].getAttribute("langtitude"))); var html = "<b>" + name + "</b> <br/>" + address + "<br/>" + **catid** + "<br/> <a href='@'>Info</a>" ;

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  • Query decendants in XML to Linq

    - by Gordon
    I have the following xml data: <portfolio> <item> <title>Site</title> <description>Site.com is a </description> <url>http://www.site.com</url> <photos> <photo url="http://www.site.com/site/thumbnail.png" thumbnail="true" description="Main" /> <photo url="http://www.site.com/site/1.png" thumbnail="false" description="Main" /> </photos> </item> </portfolio> In c# I am using the following link query: List list = new List(); XDocument xmlDoc = XDocument.Load(HttpContext.Current.Server.MapPath("~/app_data/portfolio.xml")); list = (from portfolio in xmlDoc.Descendants("item") select new PortfolioItem() { Title = portfolio.Element("title").Value, Description = portfolio.Element("description").Value, Url = portfolio.Element("url").Value }).ToList(); How do I go about querying the photos node? In the PortfolioItem class I have a property: List Photos {get;set;} Any ideas would be greatly appreciated!

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  • Linq Return node level of hierarchical xml

    - by Ryan
    In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

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  • Is it possible to create the following XML using Xdocument(C#3.0)

    - by Newbie
    <?xml version='1.0' encoding='UTF-8'?> <StockMarket> <StockDate Day = "02" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.45</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>366.25</Amount> </Stock> </StockDate> <StockDate Day = "03" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.35</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>369.70</Amount> </Stock> </StockDate> </StockMarket> My approach so far is XDocument doc = new XDocument( new XElement("StockMarket", new XElement("StockDate", new XAttribute("Day", "02"),new XAttribute("Month","06"),new XAttribute("Year","2010")), new XElement("Stock") ) ); Since I am new to Linq to XML, I am presently struggling a lot and henceforth seeking for help. Using C#3.0 . Thanks

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  • Deleting items from datagrid (xml)

    - by Tonz
    Hello, I have a datagrid buttoncolumn which acts as delete buttons for my xml nodes. The elements are simply displayed in a boundcolumn, so there names get displayed. Each item generated gets a unique id (each time one is made id+++). My question his how can i remove a item (the entire element node with that certain id) when i click on one of the buttons in the bound column? <root> <element id="0"> <name>One</name> </element> <element id="1"> <name>Two</name> </element> </root> protected void dg_DeleteCommand(object sender, DataGridCommandEventArgs e) { XmlFunctions.Remove(index); }/*dg_DeleteCommand*/ (function on other class, where all my xml methods are written) public static void Remove(string index) { XmlDocument XMLDoc = new XmlDocument(); XMLDoc.Load(XMLFile); XPathNavigator nav = XMLDoc.CreateNavigator(); var node = nav.SelectSingleNode("/test/one[@id='" +???+ "']"); node.DeleteSelf(); XMLDoc.Save(XMLFile); } Edit: added datagrid <asp:View ID="viewDelete" runat="server"> <asp:DataGrid ID="dgDelete runat="server" AutoGenerateColumns="False" OnDeleteCommand="dg_DeleteCommand"> <Columns> <asp:BoundColumn DataField="name" HeaderText="names" /> <asp:ButtonColumn ButtonType="PushButton" Text="Delete" CommandName="Delete" ></asp:ButtonColumn> </Columns> </asp:DataGrid> </asp:View>

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  • Properly obsoleting old members in an XML Serializable class in C# VB .NET

    - by George
    Hi! Some time ago I defined a class that was serialized using XML. That class contained a serializable propertyA of integer type. Now I have extended and updated this class, whereby a new propertyB was added, whose type is another class that also has several serializable properties. The new propertyB is now supposed to play the role of propertyA, that is since type of propertyB is another class, one of its members would contain the value that previously propertyA contained, thus making peroptyA obsolete. What I am trying to figure out is how do I make sure that when I desireliaze the OLD version of this class (without propertyB in it), I make sure that the desreializer would take the value of propertyA from the old calss and set it as a value of one of the members of propertyB in a new class? Private WithEvents _Position As Position = New Position(Alignment.MiddleMiddle, 0, True, 0, True) Public Property Position() As Position 'NEW composite property that holds the value of the obsolted property, i.e. Alignment Get Return _Position End Get Set(ByVal value As Position) _Position = value End Set End Property Private _Alignment As Alignment = Alignment.MiddleMiddle <Xml.Serialization.XmlIgnore(), Obsolete("Use Position property instead.")> _ Public Property Alignment() As Alignment'The old, obsoleted property that I guess must be left for compliance with deserializing the old version of this class Get Return _Alignment End Get Set(ByVal value As Alignment) _Alignment = value End Set End Property Can you help me, please?

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  • Copy existing XML, duplicate element and modify

    - by Robert
    Hi, I have a tricky XSL problem at the moment. I need to copy the existing XML, copy a certain element (plus its child elements) and modify the value of two child-elements. The modifications are: divide value of the 'value' element by 110 and edit the value of the 'type' element from 'normal' to 'discount'. This is currently what I have: Current XML: <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> </prices> </data> </dataset> Expected result <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> <price> <value>45.00</value> <type>discount</type> </price> </prices> </data> </dataset> Any takers? I've gotten as far as copying the desired 'price' element using copy-of, but I'm stuck as to how to modify it next.

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  • creating xml from database

    - by Prady
    hi, I am creating an xml from salesforce database, Everything works fine except when there is a & in the data which is been fetched. <apex:page contenttype="text/xml" > controller="Test2ab" > <data > wiki-section="Timeline"> <apex:repeat > value="{!lsttask}" var="e" > <event > start="{!e.ActivityDate}" title= > "{!e.Subject}"> <apex:outputText > value="{!e.Subject}" /> </event> > </apex:repeat> </data></apex:page> and in the controller i am just querying > lsttask =[Select OwnerId,WhoId,Status,Subject,ActivityDate from Task where Status = 'Completed' Order By ActivityDate Desc]; How can i use an escape for the value retrieved from the database Thanks Prady

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  • Admob in xml not showing in Linear

    - by NoobMe
    i am implementing admob on my app it appears when the parent is in relative layout but i must not use the alignparentbottom so i am changing it to linear but it doesnt show when i change it to linear.. any tips? help? thanks in advance here it is in xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" > <RelativeLayout android:id="@+id/banner_holder" android:layout_width="match_parent" android:layout_height="wrap_content" > <ImageView android:id="@+id/offline_banner" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_centerInParent="true" android:background="@color/black" android:src="@drawable/offline_banner" /> <com.google.ads.AdView xmlns:ads="http://schemas.android.com/apk/lib/com.google.ads" android:id="@+id/adView" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerInParent="true" ads:adSize="SMART_BANNER" ads:adUnitId="@string/unit_id" ads:loadAdOnCreate="true" /> </RelativeLayout> <FrameLayout android:id="@+id/fragmentContainer" android:layout_width="match_parent" android:layout_height="wrap_content" /> </LinearLayout> i want the admob to be at the bottom part of the screen without using the alignparentbottom of relative layout thanks~

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  • Cannot get list of elements using Linq to XML

    - by Blackator
    Sample XML: <CONFIGURATION> <Files> <File>D:\Test\TestFolder\TestFolder1\TestFile.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile01.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile02.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile03.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile04.txt</File> </Files> <SizeMB>3</SizeMB> <BackupLocation>D:\Log backups\File backups</BackupLocation> </CONFIGURATION> I've been doing some tutorials but I am unable to get all the list of file inside the files element. It only shows the first element and doesn't display the rest. This is my code: var fileFolders = from file in XDocument.Load(@"D:\Hello\backupconfig1.xml").Descendants("Files") select new { File = file.Element("File").Value }; foreach (var fileFolder in fileFolders) { Console.WriteLine("File = " + fileFolder.File); } How do I display all the File in the Files element, the SizeMB and BackupLocation? Thanks

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