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• N Tiers with SubSonic 3, Dirty Columns collection is alwayes empty on update

  - by Adel

  Hello guys here is what i am doing, and not working for me. I have a DAL generated with SubSonic 3 ActiveRecord template, i have a service layer (business layer if you well) that have mixture of facade and some validation. say i have a method on the Service layer like public void UpdateClient(Client client); in my GUI i create a Client object fill it with some data with ID and pass it to the service method and this never worked, the dirty columns collection (that track which columns are altered in order to use more efficant update statment) is alwayes empty. if i tried to get the object from database inside my GUI then pass it to the service method it's not working either. the only scenario i find working is if i query the object from the database and call Update() on the same context all inside my GUI and this defeats the whole service layer i've created. however for insert and delete everything working fine, i wonder if this have to do something with object tracking but what i know is SubSonic don't do that. please advice. thanks. Adel.

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• In SQL can I return a tables with a varying number of columns

  - by Matt

  I have a somewhat more complicated scenario, but I think it should be possible. I have a large SPROC whose result is a set of characteristics for a set of persons. So the Table would look something like this: Property | Client1 Client 2 Client3 ----------------------------------------------------------- Sex | M F M Age | 67 56 67 Income | Low Mid Low It's built using cursors, iterating over different datasets. The problem I am facing is that there is a varying number of Clients and Properties, so an equally valid result over different input sets might be: Property | Client1 Client 2 ------------------------------------------- Sex | M F Age | 67 56 Weight | 122 122 The different number of properties is easy, those are just extra rows. My problem is that I need to declare a temporary table with a varying number of columns. There could be 2 clients or 100. Every client in guaranteed to have every property ultimately listed. What SQL structure would statisfy this and how can I declare it and insert things into it? I can't just flip the columns and rows either because there is a variable number of each.

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• Are there good reasons not to use an ORM?

  - by hangy

  During my apprenticeship, I have used NHibernate for some smaller projects which I mostly coded and designed on my own. Now, before starting some bigger project, the discussion arose how to design data access and whether or not to use an ORM layer. As I am still in my apprenticeship and still consider myself a beginner in enterprise programming, I did not really try to push in my opinion, which is that using an object relational mapper to the database can ease development quite a lot. The other coders in the development team are much more experienced than me, so I think I will just do what they say. :-) However, I do not completely understand two of the main reasons for not using NHibernate or a similar project: One can just build one’s own data access objects with SQL queries and copy those queries out of Microsoft SQL Server Management Studio. Debugging an ORM can be hard. So, of course I could just build my data access layer with a lot of SELECTs etc, but here I miss the advantage of automatic joins, lazy-loading proxy classes and a lower maintenance effort if a table gets a new column or a column gets renamed. (Updating numerous SELECT, INSERT and UPDATE queries vs. updating the mapping config and possibly refactoring the business classes and DTOs.) Also, using NHibernate you can run into unforeseen problems if you do not know the framework very well. That could be, for example, trusting the Table.hbm.xml where you set a string’s length to be automatically validated. However, I can also imagine similar bugs in a “simple” SqlConnection query based data access layer. Finally, are those arguments mentioned above really a good reason not to utilise an ORM for a non-trivial database based enterprise application? Are there probably other arguments they/I might have missed? (I should probably add that I think this is like the first “big” .NET/C# based application which will require teamwork. Good practices, which are seen as pretty normal on Stack Overflow, such as unit testing or continuous integration, are non-existing here up to now.)

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• Howw to add new value with generic Repository if there are foreign keys (EF-4)?

  - by Phsika

  i try to write a kind of generic repository to add method. Everything is ok to add but I have table which is related with two tables with FOREIGN KEY.But Not working because of foreign key public class DomainRepository<TModel> : IDomainRepository<TModel> where TModel : class { #region IDomainRepository<T> Members private ObjectContext _context; private IObjectSet<TModel> _objectSet; public DomainRepository() { } public DomainRepository(ObjectContext context) { _context = context; _objectSet = _context.CreateObjectSet<TModel>(); } //do something..... public TModel Add<TModel>(TModel entity) where TModel : IEntityWithKey { EntityKey key; object originalItem; key = _context.CreateEntityKey(entity.GetType().Name, entity); _context.AddObject(key.EntitySetName, entity); _context.SaveChanges(); return entity; } //do something..... } Calling REPOSITORY: //insert-update-delete public partial class AddtoTables { public table3 Add(int TaskId, int RefAircraftsId) { using (DomainRepository<table3> repTask = new DomainRepository<table3>(new TaskEntities())) { return repTask.Add<table3>(new table3() { TaskId = TaskId, TaskRefAircraftsID = RefAircraftsId }); } } } How to add a new value if this table includes foreign key relation

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• How to Inserting message into View that depends on session value. ASP.NET MVC. Best practice

  - by Andrew Florko

  User have to populate multistep questionnaire web-forms and step messages depend on the option chosen by user at the very beginning. Messages are stored in web.config file. I use asp.net mvc project, strong typed views and keep business logic separated from controller in static class. I don't want to make business logic dependency on web.config. Well, I have to insert message into view that depends on session value. There are at least 2 options how to implement this: View model has property that is populated in controller/businessLogic and rendered in view like <%: Model.HelpMessage1 %>. I have to pass web.config values from controller to businessLogic that makes business logic methods signature too complex. I don't want to make configuration source abstract (in order to let business logic read configuration values from its methods directly) also. Create static helper class that is called from view like <%: ViewHelper.HelpMessage1(Model.Option1) %>. But in this case logic what to show seems to be separated into two classes: business logic & viewHelper. What will you suggest? Thank you in advance!

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• Symfony 1.4 - Don't save a blank password on a executeUpdate action.

  - by Twelve47

  I have a form to edit a UserProfile which is stored in mysql db. Which includes the following custom configuration: public function configure() { $this->widgetSchema['password']=new sfWidgetFormInputPassword(); $this->validatorSchema['password']->setOption('required', false); // you don't need to specify a new password if you are editing a user. } When the user tries to save the executeUpdate method is called to commit the changes. If the password is left blank, the password field is set to '', but I want it to retain the old password instead of overwriting it. What is the best (/most in the symfony ethos) way of doing this? My solution was to override the setter method on the model (which i had done anyway for password encryption), and ignore blank values. public function setPassword( $password ) { if ($password=='') return false; // if password is blank don't save it. return $this->_set('password', UserProfile ::encryptPassword( $password )); } It seems to work fine like this, but is there a better way? If you're wondering I cannot use sfDoctrineGuard for this project as I am dealing with a legacy database, and cannot change the schema.

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• convert date error when retrieving data in twig page through doctrine

  - by user201892

  I just find this error when I retrieve all my records on twig page from the database through doctrine here is my twig code : {% extends "gestionConferenceApplicationBundle::layout.html.twig" %} {% block title "Hello " ~ name %} {% block content %} je suis un debutant <table border=2 > <th>Numéro</th> <th>Titre</th> <th>Ville</th> <th>Lieu</th> <th>Date de début</th> <th>Date de fin</th> {% for item in conferences %} <tr> <td>{{ item.id }}</td> <td>{{ item.titre }}</td> <td>{{ item.ville }}</td> <td>{{ item.lieu }}</td>* <td>{{ item.dateDebut }}</td> <td>{{ item.dateFin }}</td> </tr> {% endfor %} </table> {% endblock %} the error in the date : here it is : An exception has been thrown during the rendering of a template ("Catchable Fatal Error: Object of class DateTime could not be converted to string in C:\wamp\www\Symfony\app\cache\dev\twig\3c\dd\40a703549de9b8769fa40b82230e.php line 72") in gestionConferenceApplicationBundle:acceuil:acceuil.html.twig at line 19. do you have any idea how to convert this date or any other things in the MySql I have dateTime field and in doctrine I have : /** * @var \DateTime $dateDebut * * @ORM\Column(name="date_debut", type="datetime", nullable=false) */ private $dateDebut;

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• Saving temporary file name after uploading file with uplodify

  - by mIRU

  I have this script if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = dirname(__FILE__).$_POST['folder'] . '/'; $pathinfoFile = pathinfo($_FILES['Filedata']['name']); $targetFile = str_replace('//','/',$targetPath) .uniqid().'.'.$pathinfoFile['extension']; move_uploaded_file($tempFile,$targetFile); } this script is from uplodify , modified for saving the file with unique name , i need after user will upload the file , this unique name and original name , to save temporary , when user will submit the form , this temporary variables i will insert in database , the problem is that in firebug console , i can not see all the actions of this script , and i can not understand the way how to fix it, I tried to save in $_SESSION but i have problems , is not saving , i found why is not working with $_SESSION , http://uploadify.com/forum/viewtopic.php?f=5&t=43 , i tried the solution from forum but without result , exist a more easy way to solve this problem ? , or what is better way to do it ? . Sorry for so silly question , i ran out of ideas . Thanks a lot for helping me , and sorry again for my English

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• Ajax Request using jQuery in Rails

  - by Steve

  Hi... I am sending an Ajax Request using jQuery. What happens is that I am getting an "405 Method Not Allowed" Error. I am just posting a form, which would get the detail from the form and insert it into the DB. Just the usual stuff.I am using WEBrick that comes as default with the rails package. Can somebody please tell me how to fix this. This is the code that triggers the Ajax Request $.post($(this).attr("action") + ".js",$(this).serialize(),null,"script"); Response Headers Cache-Control no-cache Allow GET, PUT, DELETE Content-Type text/html; charset=utf-8 Content-Length 9502 Server WEBrick/1.3.1 (Ruby/1.9.1/2009-12-07) Date Wed, 02 Jun 2010 20:41:33 GMT Connection Keep-Alive Request Headers Host localhost:3000 User-Agent Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept application/json, text/javascript, */* Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 115 Connection keep-alive Content-Type application/x-www-form-urlencoded; charset=UTF-8 X-Requested-With XMLHttpRequest Referer http://localhost:3000/viewspot/3 Content-Length 141 Pragma no-cache Cache-Control no-cache

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• How to optimize a postgreSQL server for a "write once, read many"-type infrastructure ?

  - by mhu

  Greetings, I am working on a piece of software that logs entries (and related tagging) in a PostgreSQL database for storage and retrieval. We never update any data once it has been inserted; we might remove it when the entry gets too old, but this is done at most once a day. Stored entries can be retrieved by users. The insertion of new entries can happen rather fast and regularly, thus the database will commonly hold several millions elements. The tables used are pretty simple : one table for ids, raw content and insertion date; and one table storing tags and their values associated to an id. User search mostly concern tags values, so SELECTs usually consist of JOIN queries on ids on the two tables. To sum it up : 2 tables Lots of INSERT no UPDATE some DELETE, once a day at most some user-generated SELECT with JOIN huge data set What would an optimal server configuration (software and hardware, I assume for example that RAID10 could help) be for my PostgreSQL server, given these requirements ? By optimal, I mean one that allows SELECT queries taking a reasonably little amount of time. I can provide more information about the current setup (like tables, indexes ...) if needed.

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• SQLAlchemy, one to many vs many to one

  - by sadvaw

  Dear Everyone, I have the following data: CREATE TABLE `groups` ( `bookID` INT NOT NULL, `groupID` INT NOT NULL, PRIMARY KEY(`bookID`), KEY( `groupID`) ); and a book table which basically has books( bookID, name, ... ), but WITHOUT groupID. There is no way for me to determine what the groupID is at the time of the insert for books. I want to do this in sqlalchemy. Hence I tried mapping Book to the books joined with groups on book.bookID=groups.bookID. I made the following: tb_groups = Table( 'groups', metadata, Column('bookID', Integer, ForeignKey('books.bookID'), primary_key=True ), Column('groupID', Integer), ) tb_books = Table( 'books', metadata, Column('bookID', Integer, primary_key=True), tb_joinedBookGroup = sql.join( tb_books, tb_groups, \ tb_books.c.bookID == tb_groups.c.bookID) and defined the following mapper: mapper( Group, tb_groups, properties={ 'books': relation(Book, backref='group') }) mapper( Book, tb_joinedBookGroup ) ... However, when I execute this piece of code, I realized that each book object has a field groups, which is a list, and each group object has books field which is a singular assigment. I think my definition here must have been causing sqlalchemy to be confused about the many-to-one vs one-to-many relationship. Can someone help me sort this out? My desired goal is g.books = [b, b, b, .. ] book.group = g, where g is an instance of group, and b is an instance of book

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• Listen to Response on HTML Form embedded in GWT View?

  - by confile

  I have a HTML like the following: <div> <form> <input type="text" /> <button class="sendForm" value="Send form" /> </form> </div> <script> // post the form with Jquery post // register a callback that handles the response </script> I use this type of form a lot with a JavaScript/JQuery overlay that displays the form. That could be handled for example with plugins like FancyBox. I also want to use this form embedded into a GWT view. Lets assume that the for cannot be created on client side because it has some server based markup language inside to set up some model data. If I want to use this form in GWT I have to do the following. Tell GWT the form request url and use a RequestBuilder to query the html content of this form. Then I can insert it into a div generated by GWT. So far so good. Problem: When the user hits the send button the response is handled my the JQuery callback that is inside the script under the form. Is there a way to access this callback from within GWT? Is there a way to overwrite the JQuery send action? Since, the code is HTML and comes from the server I cannot place ui-binder UiFields inside to get access to these DOM elements. I need to get the response if the submitted form accessible to GWT. Is there a way how I can achieve this with JSNI?

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• Ruby on Rails: How to create associated models on the fly ?

  - by Misha Moroshko

  I have the following models: class Product < ActiveRecord::Base belongs_to :brand belongs_to :model accepts_nested_attributes_for :brand, :model ... end class Brand < ActiveRecord::Base has_many :products has_many :models ... end class Model < ActiveRecord::Base has_many :products belongs_to :brand accepts_nested_attributes_for :brand ... end I have a problem to create a new product. Here is the relevant code in the controller: class ProductsController < ApplicationController ... def create @product = Product.new(params[:product]) if @product.save ... # Here is the error end ... end When user adds a new brand and a new model, params[:product] contains the following: "brand_attributes"=>{"name"=>"my_new_brand"} "model_attributes"=>{"model_no"=>"my_new_model"} and I got the following error: Mysql2::Error: Column 'brand_id' cannot be null: INSERT INTO `models` ... because model has a foreign key brand_id which is not set. I can't set it because the brand (like the model) is created on the fly when the product is created. I don't want to create the brand before the product, because then I the product has errors, I will need to delete the created brand. Then I tried to change params[:product] like this: "brand_attributes"=>{"name"=>"my_new_brand", "model_attributes"=>{"model_no"=>"my_new_model"}} but I end up with this: unknown attribute: model_attributes What would be the proper way to handle this ?

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• joomla! migration

  - by tim

  I have a Joomla! installation on a remote site and I want to run it locally. I'm running Joomla! locally on a Mac through a standard MAMP installation: Joomla 1.5.12 PHP 5.2.6 MySQL 5.0.41 Apache 2.0.59 OS X 10.5.8 I've added a configuration file to the local Joomla! directory with all the correct local settings, database name, database user-name, database password etc. etc. I've tried a lot of different settings. I've also recreated the remote database locally, ensuring everything copied correctly. I followed a few different sets of instructions with roughly the same steps on how to do the migration. All of the above has not worked for me; at best I get bits of text from the site rendered in the browser. Other times I get SQL errors. What I want is for an already set up remote Joomla! installation to run on my own local machine. Does anyone have any advice as to how to get this working, it'd be very much appreciated? Thanks.

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• Posting a form using Ajax

  - by hopes

  Hi everyone, do u have an idea of how to send my radio button name for myAjaxPostrequest.send(parameters); can parameters be like this: var answername=document.getElementById('option1').name; var parameters=answername; ? this code is for using ajax to post a form and my php page needs the name of the radiobutton clicked I tried this code and it works as I want except for inserting in the database. It means parameters is the problem what I want to insert is the number located between brakects of the radiobutton name. I could do it when I post form without Ajax but now I can't send the name of the radiobutton any clue about what I can send as parameter for function myAjaxPostrequest.send(parameters);? <form id="Question1" method="post"> <br /> <P> The sky color is.. </P><img border="0" src="images/wonder.png" width="94" height="134"/><br /><br /><br /> <input type="radio" id="option1" name="answer[1]" value="correct!" onclick="submitFormWithAjax();"/> blue <br /> <input type="radio" id="option1" name="answer[1]" value="false!" onclick="submitFormWithAjax();"/> red <br /> <input type="radio" id="option1" name="answer[1]" value="false!" onclick="submitFormWithAjax();"/> green <br /> <input type="radio" id="option1" name="answer[1]" value="false!" onclick="submitFormWithAjax();"/> white <br /> <br /> </Form>

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• CakePHP Observe field for validation check(already exists)

  - by deck john

  i have already user observe field in cakephp 1.3 Now i want to do the same thing in cakephp 2.0 I have one form.there is a one field named email. When user insert email. onblur there is a popup one message that displays "email already exists" or "right" for that i have write below code in my projects. the below code is my add file code <?php $options = array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exist'); echo $this->ajax->observeField('UserEmailId',array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exists')); ?> In my controller i have created one function like public function is_exist($id = null) { $result = "yes"; $this->set('existdata',$result); } i have also created is_exists.ctp fiel in view/uers. i dont know why its not working. i did the same thing in Cakephp 1.3 and its working file but not in cakephp 2.0 can anyone tell me how i implement this ? thanks in advance

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• Do I need to write a trigger for such a simple constraint?

  - by Paul Hanbury

  I really had a hard time knowing what words to put into the title of my question, as I am not especially sure if there is a database pattern related to my problem. I will try to simplify matters as much as possible to get directly to the heart of the issue. Suppose I have some tables. The first one is a list of widget types: create table widget_types ( widget_type_id number(7,0) primary key, description varchar2(50) ); The next one contains icons: create table icons ( icon_id number(7,0) primary key, picture blob ); Even though the users get to select their preferred widget, there is a predefined subset of widgets that they can choose from for each widget type. create table icon_associations ( widget_type_id number(7,0) references widget_types, icon_id number(7,0) references icons, primary key (widget_type_id, icon_id) ); create table icon_prefs ( user_id number(7,0) references users, widget_type_id number(7,0), icon_id number(7,0), primary key (user_id, widget_type_id), foreign key (widget_type_id, icon_id) references icon_associations ); Pretty simple so far. Let us now assume that if we are displaying an icon to a user who has not set up his preferences, we choose one of the appropriate images associated with the current widget. I'd like to specify the preferred icon to display in such a case, and here's where I run into my problem: alter table icon_associations add ( is_preferred char(1) check( is_preferred in ('y','n') ) ) ; I do not see how I can enforce that for each widget_type there is one, and only one, row having is_preferred set to 'y'. I know that in MySQL, I am able to write a subquery in my check constraint to quickly resolve this issue. This is not possible with Oracle. Is my mistake that this column has no business being in the icon_associations table? If not where should it go? Is this a case where, in Oracle, the constraint can only be handled with a trigger? I ask only because I'd like to go the constraint route if at all possible. Thanks so much for your help, Paul

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• In ArrayBlockingQueue, why copy into ReentrantLock field into local final variable?

  - by mjlee

  In ArrayBlockingQueue, any method that requires lock will get set 'final' local variable before calling 'lock()'. public boolean offer(E e) { if (e == null) throw new NullPointerException(); final ReentrantLock lock = this.lock; lock.lock(); try { if (count == items.length) return false; else { insert(e); return true; } } finally { lock.unlock(); } } Is there any reason to set a local variable 'lock' from 'this.lock' when field 'this.lock' is final also. Additionally, it also set local variable of E[] before acting on. private E extract() { final E[] items = this.items; E x = items[takeIndex]; items[takeIndex] = null; takeIndex = inc(takeIndex); --count; notFull.signal(); return x; } Is there any reason for copying to local final variable?

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• Table index design

  - by Swoosh

  I would like to add index(s) to my table. I am looking for general ideas how to add more indexes to a table. Other than the PK clustered. I would like to know what to look for when I am doing this. So, my example: This table (let's call it TASK table) is going to be the biggest table of the whole application. Expecting millions records. IMPORTANT: massive bulk-insert is adding data in this table table has 27 columns: (so far, and counting :D ) int x 9 columns = id-s varchar x 10 columns bit x 2 columns datetime x 5 columns INT COLUMNS all of these are INT ID-s but from tables that are usually smaller than Task table (10-50 records max), example: Status table (with values like "open", "closed") or Priority table (with values like "important", "not so important", "normal") there is also a column like "parent-ID" (self - ID) join: all the "small" tables have PK, the usual way ... clustered STRING COLUMNS there is a (Company) column (string!) that is something like "5 characters long all the time" and every user will be restricted using this one. If in Task there are 15 different "Companies" the logged in user would only see one. So there's always a filter on this one. Might be a good idea to add an index to this column? DATE COLUMNS I think they don't index these ... right? Or can / should be?

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• Should I learn to code?

  - by saltcod

  Hi All, This is more of a philosophical question than a technical one, but I’d like some opinions on it, and I think that there are many others in my position that would benefit. My issue is that I don’t really have time to learn how to code. I know, I know… no one has time anymore, but please hear me out. Since learning to use Drupal about 2 years ago I’ve been involved with several projects wherein I’ve become the default quasi-developer, front-end designer, site manager, and system administrator. What I’ve found is that I can produce fairly nice, feature rich Drupal sites with the wealth of contrib. modules out there (Views, CCK, image handling, etc….). BUT! I can’t code. I know enough PHP to insert something into a block, or re-word a string, but that’s about it. I still don’t really even know how arrays work. My question Succinctly, my question is: Given the time that I have available for all of this stuff – in addition to a full-time job and regular life – am I better off trying to become more expert at the front-end stuff, or should I just learn PHP already? Pros 1. If a project doesn’t use Drupal, I’ll know enough PHP to be able to participate. 2. Learning PHP would help my Drupal development too 3. Learning PHP would make front-end theming easier 4. Learning PHP should give me that missing background in programming – and should allow me to learn other languages in the future Cons 1. At 28, I know I’m not too old to learn anything. But am I too old to become ‘good’? 2. Am I better off getting better and better at front-end UX work? 3. Am I better off farming out the PHP work? Suggestions from coders welcome! Thanks Terry

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• Why doesn't this PHP execute?

  - by cam

  I copied the code from this site exactly: http://davidwalsh.name/web-service-php-mysql-xml-json as follows, /* require the user as the parameter */ if(isset($_GET['user']) && intval($_GET['user'])) { /* soak in the passed variable or set our own */ $number_of_posts = isset($_GET['num']) ? intval($_GET['num']) : 10; //10 is the default $format = strtolower($_GET['format']) == 'json' ? 'json' : 'xml'; //xml is the default $user_id = intval($_GET['user']); //no default /* connect to the db */ $link = mysql_connect('localhost','username','password') or die('Cannot connect to the DB'); mysql_select_db('db_name',$link) or die('Cannot select the DB'); /* grab the posts from the db */ $query = "SELECT post_title, guid FROM wp_posts WHERE post_author = $user_id AND post_status = 'publish' ORDER BY ID DESC LIMIT $number_of_posts"; $result = mysql_query($query,$link) or die('Errant query: '.$query); /* create one master array of the records */ $posts = array(); if(mysql_num_rows($result)) { while($post = mysql_fetch_assoc($result)) { $posts[] = array('post'=>$post); } } /* output in necessary format */ if($format == 'json') { header('Content-type: application/json'); echo json_encode(array('posts'=>$posts)); } else { header('Content-type: text/xml'); echo '<posts>'; foreach($posts as $index => $post) { if(is_array($post)) { foreach($post as $key => $value) { echo '<',$key,'>'; if(is_array($value)) { foreach($value as $tag => $val) { echo '<',$tag,'>',htmlentities($val),'</',$tag,'>'; } } echo '</',$key,'>'; } } } echo '</posts>'; } /* disconnect from the db */ @mysql_close($link); } And the php doesn't execute, it just displays as plain text. What's the dealio? The host supports PHP, I use it to run a Wordpress blog and other things.

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• Need help with jQuery/AJAX call in Safari/Mac

  - by protohominid

  I've got something that works perfectly in FF and MSIE but it's not working properly in Safari. It's a form with selects that get updated via AJAX/jQuery from a MySQL DB. In Safari, when you select the first item, it correctly loads the options for the next select menu; however, when you choose one of those (which loads new options in a subsequent select menu), the whole form resets and is broken from that point on. Does anyone know of a Safari bug that would cause this? Here's the JS: $(document).ready(function(){ $("#searchForm select").change(updateSearchForm); }); function updateSearchForm() { $.ajax({ url: '/elements/search_form.php?ajax=true', data: $('#searchForm').serialize(), error:function(xhr,err){ alert("readyState: "+xhr.readyState+"\nstatus: "+xhr.status); alert("responseText: "+xhr.responseText); }, success: function(data) { $("#searchForm").html(data); $("#searchForm select").change(updateSearchForm); } }); } I can post the relevant PHP/HTML for the form, but it's lengthy. I'm relatively new to JS so I'm not sure where to start debugging this... TIA

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• What's a good way to parameterize "static" content (e.g. CSS) in a Tomcat webapp?

  - by Steven Huwig

  Some of our CSS files contain parameters that can vary based on the deployment location (dev, QA, prod). For example: background: url(#DOJO_PATH#/dijit/themes...) to avoid hardcoding a path to a particular CDN or locally-hosted Dojo installation. These values are textually substituted with the real values by a deployment script, when it copies the contents of the webapp into the Tomcat webapps directory. That way the same deployment archive file (WAR + TAR file containing other configuration) can be deployed to dev, QA, and prod, with the varying parameters provided by environment-specific configuration files. However, I'd like to make the contents of the WAR (including the templatized CSS files) independent of this in-house deployment script. Since we don't really have control over the deployment script, all I can think to do is configure Tomcat with #DOJO_PATH# etc. as environment variables in the application's context.xml, and use Tomcat to insert those parameters into the CSS at runtime. I could make the CSS files into generated JSPs, but it seems a little ugly to me. Moreover, the substitution only needs to be done once per application deployment, so repeatedly dynamically generating the stylesheets using JSP will be rather wasteful. Does anyone have any alternative ideas or tools to use for this? We're committed to Tomcat and to substituting these parameters at deployment or at runtime (that is, not at build time).

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• How to fix this simple SQL query?

  - by morpheous

  I have a database with three tables: user_table country_table city_table I want to write ANSI SQL which will allow me to fetch all the user data (i.e. user details including the name of the country of the last school and the name of the city they live in now). The problem I am having is that I have to use a self join, and I am getting slightly confused. The schema is shown below: CREATE TABLE user_table (id int, first_name varchar(16), last_school_country_id int, city_id int); CREATE TABLE country_table (id int, name varchar(32)); CREATE TABLE city_table (id int, country_id int, name varchar(32)); This is the query I have come up with so far, but the results are wrong, and sometimes, the db engine (mySQL), asks me if I want to show all [HUGE NUMBER HERE] results - which makes me suspect that I am unintentionally creating a cartesian product somewhere. Can someone explain what is wrong with this SQL statement, and what I need to do to fix it? SELECT usr.id AS id, usr.first_name, ctry1.name as loc_country_name, ctry2.name as school_country_name, city.name as loc_city_name FROM user_table usr, country_table ctry1, country_table ctry2, city_table city WHERE usr.last_school_country_id=ctry2.id AND usr.city_id=city.id AND city.country_id=ctry1.id AND ctry1.id=ctry2.id;

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• Php JSON Response Array

  - by Nick Kl

  I have this php code. As you can see i query a mysql database through a function showallevents. I return a the $result to the $event variable. I try to return all rows of the data that i take with the msql_fetch_assoc. I don't get response even when i encode the $response variable. It returns null to all fields. Can anyone help me on what i am doing wrong. I had a valid code but it was returning only 1 row of data so i tried to make an associative array but seems i am failing. if ($tag == 'showallevents') { // Request type is show all events // show all events $event = $db->showallevents(); if ($event != false) { $data = array(); while($row = mysql_fetch_assoc($event)) { $data[] = array( $response["success"] = 1, $response["uid"] = $event["uid"], $response["event"]["date"] = $event["date"], $response["event"]["hours"] = $event["hours"], $response["event"]["store_name"] = $event["store_name"], $response["event"]["event_information"] = $event["event_information"], $response["event"]["event_type"] = $event["event_type"], $response["event"]["Phone"] = $event["Phone"], $response["event"]["address"] = $event["address"], $response["event"]["created_at"] = $event["created_at"], $response["event"]["updated_at"] = $event["updated_at"]); } echo json_encode($data); } else { // event not found // echo json with error = 1 $response["error"] = 1; $response["error_msg"] = "Events not found"; echo json_encode($response); } } else { echo "Access Denied"; } } ?>

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