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  • How to create a timer the right way?

    - by mystify
    I always have an class which needs to set up a timer for as long as the object is alive. Typically an UIView which does some animation. Now the problem: If I strongly reference the NSTimer I create and invalidate and release the timer in -dealloc, the timer is never invalidated or released because -dealloc is never called, since the run loop maintains a strong reference to the target. So what can I do? If I cant hold a strong ref to the timer object, this is also bad because maybe I need a ref to it to be able to stop it. And a weak ref on a object is not good, because maybe i'm gonna access it when it's gone. So better have a retain on what I want to keep around. How are you guys solving this? must the superview create the timer? is that better? or should i really just make a weak ref on it and keep in mind that the run loop holds a strong ref on my timer for me, as long as it's not invalidated?

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  • Please help me out in fetching the desired result from below given DB table structure of MySQL..

    - by OM The Eternity
    Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

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  • Activerecord join search

    - by VP
    Hi, i have two models: class Category has many :jobs end class Job belongs_to :category end So for sure i'm able to do c = Category.first c.jobs My question is: how can i find just categories that has at least one job?

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  • need the right way to setcookie in wordpress

    - by jq beginner
    i've been looking the whole day how to setcookies in wordpress. in my way i found out (using the developer toolbar) that the cookie is set but still not working. i have 2 files the first contains the login form redirecting to another page to set the cookie and return to another page to check if it's working. domain which is tested on is like this : blog.mydomain.com. here's the setcookie file : <?php setcookie("user_name","test",time()+3600); ?> and chcking the cookie like this : if(isset($_COOKIE["user_name"])){ echo "cookie exists"; } else{ echo "cookie doesn't exist"; } i've read many topics about this issue but there was no clear answer. Thanks in advance

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  • Grabbing the right record in a drop down from mysql

    - by 86Stang
    I'm using a form where the user can edit an entry. Everything is populating and all is well with the exception that I can't get the drop down to show the project that they've already assigned the image to. $project_qry = "SELECT * from projects ORDER BY title ASC"; $project_res = mysql_query($project_qry); $project_drop = "<select name=\"project_id\">\n"; while ($row = mysql_fetch_array($project_res)) { if ($project_id == $row[title]) { $project_drop .= "<option value=\"$row[id]\" selected>$row[title]</option>\n"; } else { $project_drop .= "<option value=\"$row[id]\">$row[title]</option>\n"; } } $project_drop .= "</select>\n"; I'm sure it's something devilishly simple but I'm stumped.

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  • SQL JOIN with two or more tables as output - most efficient way?

    - by littlegreen
    I have an SQL query that executes a LEFT JOIN on another table, then outputs all results that could be coupled into a designated table. I then have a second SQL query that executes the LEFT JOIN again, then outputs the results that could not be coupled to a designated table. In code, this is something like: INSERT INTO coupledrecords SELECT b.col1, b.col2... s.col1, s.col2... FROM bigtable AS b LEFT JOIN smallertable AS s ON criterium WHERE s.col1 IS NOT NULL INSERT INTO notcoupledrecords SELECT b.col1, b.col2... bigtable AS b LEFT JOIN smallertable AS s ON criterium WHERE s.col1 IS NULL My question: I now have to execute the JOIN two times, in order to achieve what I want. I have a feeling that this is twice as slow as it could be. Is this true, and if yes, is there a way to do it more efficiently?

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  • JavaScript: String Concatenation slow performance? Array.join('')?

    - by NickNick
    I've read that if I have a for loop, I should not use string concation because it's slow. Such as: for (i=0;i<10000000;i++) { str += 'a'; } And instead, I should use Array.join(), since it's much faster: var tmp = []; for (i=0;i<10000000;i++) { tmp.push('a'); } var str = tmp.join(''); However, I have also read that string concatention is ONLY a problem for Internet Explorer and that browsers such as Safari/Chrome, which use Webkit, actually perform FASTER is using string concatention than Array.join(). I've attempting to find a performance comparison between all major browser of string concatenation vs Array.join() and haven't been able to find one. As such, what is faster and more efficient JavaScript code? Using string concatenation or Array.join()?

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  • MySQL create stored procedure fails but all internal queries succeed alone?

    - by Mark
    Hi all, I just created a simple database in MySQL, and I am learning how to write stored proc's. I'm familiar with M$SQL and as far as I can see the following should work: use mydb; -- -------------------------------------------------------------------------------- -- Routine DDL -- -------------------------------------------------------------------------------- DELIMITER // CREATE PROCEDURE mydb.doStats () BEGIN CREATE TABLE IF NOT EXISTS resultprobability ( ballNumber INT NOT NULL , probability FLOAT NULL, PRIMARY KEY (ballNumber) ); CREATE TABLE IF NOT EXISTS drawProbability ( drawDate DATE NOT NULL , ball1 INT NULL , ball2 INT NULL , ball3 INT NULL , ball4 INT NULL , ball5 INT NULL , ball6 INT NULL , ball7 INT NULL , score FLOAT NULL , PRIMARY KEY (drawDate) ); TRUNCATE TABLE resultprobability; TRUNCATE TABLE drawprobability; INSERT INTO resultprobability (ballNumber, probability) (select resultset.ballNumber ballNumber,(count(0)/(select count(0) from resultset)) probability from resultset group by resultset.ballNumber); INSERT INTO drawProbability (drawDate, ball1, ball2, ball3, ball4, ball5, ball6, ball7, score) (select distinct r.drawDate, a.ballnumber ball1, b.ballnumber ball2, c.ballnumber ball3, d.ballnumber ball4, e.ballnumber ball5, f.ballnumber ball6,g.ballnumber ball7, ((a.probability + b.probability + c.probability + d.probability + e.probability + f.probability + g.probability)/7) score from resultset r inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 1) a on a.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 2) b on b.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 3) c on c.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 4) d on d.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 5) e on e.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 6) f on f.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 7) g on g.drawdate = r.drawDate order by score desc); END // DELIMITER ; instead i get the following Executed successfully in 0.002 s, 0 rows affected. Line 1, column 1 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 26 Line 6, column 1 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')) probability from resultset group by resultset.ballNumber); INSERT INTO d' at line 1 Line 31, column 51 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') score from resultset r inner join (select r.drawDate, r.ballNumber, p.probabi' at line 1 Line 39, column 114 Execution finished after 0.002 s, 3 error(s) occurred. What am I doing wrong? I seem to have exhausted my limited mental abilities!

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  • Why does Python's math.factorial not play nice with threads?

    - by W1N9Zr0
    Why does math.factorial act so weird in a thread? Here is an example, it creates three threads: thread that just sleeps for a while thread that increments an int for a while thread that does math.factorial on a large number. It calls start on the threads, then join with a timeout The sleep and spin threads work as expected and return from start right away, and then sit in the join for the timeout. The factorial thread on the other hand does not return from start until it runs to the end! import sys from threading import Thread from time import sleep, time from math import factorial # Helper class that stores a start time to compare to class timed_thread(Thread): def __init__(self, time_start): Thread.__init__(self) self.time_start = time_start # Thread that just executes sleep() class sleep_thread(timed_thread): def run(self): sleep(15) print "st DONE:\t%f" % (time() - time_start) # Thread that increments a number for a while class spin_thread(timed_thread): def run(self): x = 1 while x < 120000000: x += 1 print "sp DONE:\t%f" % (time() - time_start) # Thread that calls math.factorial with a large number class factorial_thread(timed_thread): def run(self): factorial(50000) print "ft DONE:\t%f" % (time() - time_start) # the tests print print "sleep_thread test" time_start = time() st = sleep_thread(time_start) st.start() print "st.start:\t%f" % (time() - time_start) st.join(2) print "st.join:\t%f" % (time() - time_start) print "sleep alive:\t%r" % st.isAlive() print print "spin_thread test" time_start = time() sp = spin_thread(time_start) sp.start() print "sp.start:\t%f" % (time() - time_start) sp.join(2) print "sp.join:\t%f" % (time() - time_start) print "sp alive:\t%r" % sp.isAlive() print print "factorial_thread test" time_start = time() ft = factorial_thread(time_start) ft.start() print "ft.start:\t%f" % (time() - time_start) ft.join(2) print "ft.join:\t%f" % (time() - time_start) print "ft alive:\t%r" % ft.isAlive() And here is the output on Python 2.6.5 on CentOS x64: sleep_thread test st.start: 0.000675 st.join: 2.006963 sleep alive: True spin_thread test sp.start: 0.000595 sp.join: 2.010066 sp alive: True factorial_thread test ft DONE: 4.475453 ft.start: 4.475589 ft.join: 4.475615 ft alive: False st DONE: 10.994519 sp DONE: 12.054668 I've tried this on python 2.6.5 on CentOS x64, 2.7.2 on Windows x86 and the factorial thread does not return from start on either of them until the thread is done executing. I've also tried this with PyPy 1.8.0 on Windows x86, and there result is slightly different. The start does return immediately, but then the join doesn't time out! sleep_thread test st.start: 0.001000 st.join: 2.001000 sleep alive: True spin_thread test sp.start: 0.000000 sp DONE: 0.197000 sp.join: 0.236000 sp alive: False factorial_thread test ft.start: 0.032000 ft DONE: 9.011000 ft.join: 9.012000 ft alive: False st DONE: 12.763000

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  • What's the right/standard way of achieving separation of concerns?

    - by Ghanima
    Some background: I want to start developing games, and taking some of the advice given in this site, I've started with something simple and familiar, such as pong, tetris, etc. I want to take as much time as needed to make sure that I have the basics right before moving on to something bigger. I have medium programming experience but I realize making games is a different thing. I find myself wondering many things like should this be in a separate class? Should this module handle this stuff or is it better to let other modules have that kind of functionality? For example, the bouncing of a ball in pong, right now is handled in the ball module, but maybe it's better that some other module did it. Right now I have different modules: one for the graphics, one for the game logic, and others for the objects (depending on the kind of movement required, not all the objects are alike). I know I am asking a lot, any tips you have will be very much appreciated. Short question: What's the right or standard way of separating the modules? What have you found most effective? Is it enough to just keep the drawing (graphics) and the logic separate? Is it necessary to have a lot of classes? (for example for the objects in the game, to handle the movement, etc)

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  • Using CSS max-height on an outer div to force scroll on an inner-div.

    - by Jay Neely
    I have an outer div with a variable height (and max-height) that's set with a specific pixel amount by JavaScript, containing two divs within. The 1st div is intended to hold a variable amount of content, e.g. a list of links. It has no height set. The 2nd div is intended to hold a fixed amount of content, and has a specific height set. Right now, the max-height isn't working. The 1st div keeps growing, even with overflow: auto; set, and pushes the 2nd div below it outside the bounds of the outer div. How can I make it so that when the 1st div gets too large for the outer div to contain both it and the fixed-height 2nd div, the 1st div will start to scroll? Example page: http://thevastdesign.com/scrollTest.html Thanks for any help. I'd appreciate a CSS solution the most, even if it requires some hacks. It only has to work in Firefox 3+, IE8, and IE7. Ideas?

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  • problem with "select new Object ... join ... where"

    - by jacob
    Hi, I'm having a problem with an HQL query Three classes ClassOne is my BusinessObject public class ClassOne { private int id; private int status; private Set<ClassTwo> classTwos; + other fields/getters/setters/constructor etc } ClassTwo is referenced in a set of ClassOne and is kind of the history of an object of ClassOne public class ClassTwo { private int id; private int oldStatus; private int newStatus; private String message; //+ getters/setters/constructor etc } ClassThree is my DTO/VO with just one classTwo (not the whole history) public class ClassThree { private int id; private int status; private ClassTwo classTwo; public ClassThree(int pId, int pStatus, ClassTwo pClassTwo) { id=pId; status=pStatus; classTwo=pClassTwo; } //+ getters/setters etc } Now I'd like to create an HQL query like this: I'd like to get all objects of ClassThree with a certain status and if it exists the newest ClassTwo with a certain newStatus. For example: I'd like to get all the DTOs (ClassThree) of ClassOne whose status is now 1, but earlier in their history it has been 2 and I'd like to have the latest ClassTwo object which has 2 as newStatus. SELECT new ClassThree(c1.id, c1.status, c2) FROM ClassOne c1 LEFT JOIN c1.classtwos c2 (...) and (...) is where I don't know what to do, I'm not even sure if it's a join / join fetch Looked around and tried quite a lot already, but no clue. Especially with the join fetch I get some Hibernate errors like org.hibernate.QueryException: query specified join fetching, but the owner of the fetched association was not present in the select list. Fetching the BusinessObject like that is no problem SELECT distinct(c1) FROM ClassOne c1 LEFT OUTER JOIN FETCH c1.classtwos c2 and I get the ClassTwos as my field. Thanks in advance, Jacob P.S.: One thing might be important, ClassTwo has no reference to ClassOne!!

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  • How to implement a left outer join in the Entity Framework.

    - by user206736
    I have the following SQL query:- select distinct * from dbo.Profiles profiles left join ProfileSettings pSet on pSet.ProfileKey = profiles.ProfileKey left join PlatformIdentities pId on pId.ProfileKey = profiles.Profilekey I need to convert it to a LinqToEntities expression. I have tried the following:- from profiles in _dbContext.ProfileSet let leftOuter = (from pSet in _dbContext.ProfileSettingSet select new { pSet.isInternal }).FirstOrDefault() select new { profiles.ProfileKey, Internal = leftOuter.isInternal, profiles.FirstName, profiles.LastName, profiles.EmailAddress, profiles.DateCreated, profiles.LastLoggedIn, }; The above query works fine because I haven't considered the third table "PlatformIdentities". Single left outer join works with what I have done above. How do I include PlatformIdentities (the 3rd table) ? I basically want to translate the SQL query I specified at the beginning of this post (which gives me exactly what I need) in to LinqToEntities. Thanks

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  • Function Folding in #PowerQuery

    - by Darren Gosbell
    Originally posted on: http://geekswithblogs.net/darrengosbell/archive/2014/05/16/function-folding-in-powerquery.aspxLooking at a typical Power Query query you will noticed that it's made up of a number of small steps. As an example take a look at the query I did in my previous post about joining a fact table to a slowly changing dimension. It was roughly built up of the following steps: Get all records from the fact table Get all records from the dimension table do an outer join between these two tables on the business key (resulting in an increase in the row count as there are multiple records in the dimension table for each business key) Filter out the excess rows introduced in step 3 remove extra columns that are not required in the final result set. If Power Query was to execute a query like this literally, following the same steps in the same order it would not be overly efficient. Particularly if your two source tables were quite large. However Power Query has a feature called function folding where it can take a number of these small steps and push them down to the data source. The degree of function folding that can be performed depends on the data source, As you might expect, relational data sources like SQL Server, Oracle and Teradata support folding, but so do some of the other sources like OData, Exchange and Active Directory. To explore how this works I took the data from my previous post and loaded it into a SQL database. Then I converted my Power Query expression to source it's data from that database. Below is the resulting Power Query which I edited by hand so that the whole thing can be shown in a single expression: let     SqlSource = Sql.Database("localhost", "PowerQueryTest"),     BU = SqlSource{[Schema="dbo",Item="BU"]}[Data],     Fact = SqlSource{[Schema="dbo",Item="fact"]}[Data],     Source = Table.NestedJoin(Fact,{"BU_Code"},BU,{"BU_Code"},"NewColumn"),     LeftJoin = Table.ExpandTableColumn(Source, "NewColumn"                                   , {"BU_Key", "StartDate", "EndDate"}                                   , {"BU_Key", "StartDate", "EndDate"}),     BetweenFilter = Table.SelectRows(LeftJoin, each (([Date] >= [StartDate]) and ([Date] <= [EndDate])) ),     RemovedColumns = Table.RemoveColumns(BetweenFilter,{"StartDate", "EndDate"}) in     RemovedColumns If the above query was run step by step in a literal fashion you would expect it to run two queries against the SQL database doing "SELECT * …" from both tables. However a profiler trace shows just the following single SQL query: select [_].[BU_Code],     [_].[Date],     [_].[Amount],     [_].[BU_Key] from (     select [$Outer].[BU_Code],         [$Outer].[Date],         [$Outer].[Amount],         [$Inner].[BU_Key],         [$Inner].[StartDate],         [$Inner].[EndDate]     from [dbo].[fact] as [$Outer]     left outer join     (         select [_].[BU_Key] as [BU_Key],             [_].[BU_Code] as [BU_Code2],             [_].[BU_Name] as [BU_Name],             [_].[StartDate] as [StartDate],             [_].[EndDate] as [EndDate]         from [dbo].[BU] as [_]     ) as [$Inner] on ([$Outer].[BU_Code] = [$Inner].[BU_Code2] or [$Outer].[BU_Code] is null and [$Inner].[BU_Code2] is null) ) as [_] where [_].[Date] >= [_].[StartDate] and [_].[Date] <= [_].[EndDate] The resulting query is a little strange, you can probably tell that it was generated programmatically. But if you look closely you'll notice that every single part of the Power Query formula has been pushed down to SQL Server. Power Query itself ends up just constructing the query and passing the results back to Excel, it does not do any of the data transformation steps itself. So now you can feel a bit more comfortable showing Power Query to your less technical Colleagues knowing that the tool will do it's best fold all the  small steps in Power Query down the most efficient query that it can against the source systems.

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  • How do I get a get the left pane of my GUI app to talk to the right pane?

    - by bas-brain
    I need help on developing a UI for a app. Basically this app will have do panels, left and right, lets say. On the left panel will be displayed customers and when I click on the customer name on the right will appear tabs with information, some kind of form with name, email, picture, etc. I already developed the left panel with DictionaryGrid which I could found on tutorials and so on, but no idea on the right panel which is the form side. Any help??? Just the idea and the development is with me, thanks very much

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  • Left and right keys acting crazy on Ubuntu 10.10 Netbook Remix?

    - by Stephanie
    Hi guys, I just installed Ubuntu 10.10 Netbook Remix on my HP Mini 1000. Everything worked fine right up until I tried typing - apparently the left and right arrow keys on my keyboard are uncontrollable. Everything I type ends up looking messed up because the left and right keys keep automatically inserting themselves into everything I type. This also happens when I click on, say, "File" on Firefox. It starts rotating between all the different menu options even though I'm not pressing anything on the keyboard. Does anyone have any idea what's going on? Is this a problem with the keyboard itself?

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  • Should if statments be in inner or outer method?

    - by mjcopple
    Which of these designs is better? What are the pros and cons of each? Which one would you use? Any other suggestions of how to deal with methods like is are appreciated. It is reasonable to assume that Draw() is the only place that the other draw methods are called from. This needs to expand to many more Draw* methods and Show* properties, not just the three shown here. public void Draw() { if (ShowAxis) { DrawAxis(); } if (ShowLegend) { DrawLegend(); } if (ShowPoints && Points.Count > 0) { DrawPoints(); } } private void DrawAxis() { // Draw things. } private void DrawLegend() { // Draw things. } private void DrawPoints() { // Draw things. } Or public void Draw() { DrawAxis(); DrawLegend(); DrawPoints(); } private void DrawAxis() { if (!ShowAxis) { return; } // Draw things. } private void DrawLegend() { if (!ShowLegend) { return; } // Draw things. } private void DrawPoints() { if (!ShowPoints || Points.Count <= 0)) { return; } // Draw things. }

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  • Mysql - help me optimize this query

    - by sandeepan-nath
    About the system: -The system has a total of 8 tables - Users - Tutor_Details (Tutors are a type of User,Tutor_Details table is linked to Users) - learning_packs, (stores packs created by tutors) - learning_packs_tag_relations, (holds tag relations meant for search) - tutors_tag_relations and tags and orders (containing purchase details of tutor's packs), order_details linked to orders and tutor_details. For a more clear idea about the tables involved please check the The tables section in the end. -A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is a simpler representation (not the actual) of the more complex query which I am trying to optimize:- I have used statements like explanation of parts in the query select SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) as key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) as key_2_total_matches, td., u., count(distinct(od.id_od)), if (lp.id_lp > 0) then some conditional logic on lp fields else 0 as tutor_popularity from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN `some other tables on lp.id_lp - let's call learning pack tables set (including Learning_Packs table)` LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) where some condition on Users table's fields AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN `some conditions on learning pack tables set` ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN `some conditions on webclasses tables set` ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and some conditions on Orders table's fields ELSE 1 END AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%") group by td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 ===================================================================== What does the above query do? Does AND logic search on the search keywords (2 in this example - "Democracy" and "Dictatorship"). Returns only those tutors for which both the keywords are present in the union of the two sets - tutors details and details of all the packs created by a tutor. To make things clear - Suppose a Tutor name "Sandeepan Nath" has created a pack "My first pack", then:- Searching "Sandeepan Nath" returns Sandeepan Nath. Searching "Sandeepan first" returns Sandeepan Nath. Searching "Sandeepan second" does not return Sandeepan Nath. ====================================================================================== The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query on heavily loaded databases is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed, but I would appreciate a better query as a solution, optimized as much as possible, displaying the same results ========================================================================================== How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. ==================================================================== The tables Most of the following tables contain many other fields which I have omitted here. CREATE TABLE IF NOT EXISTS users ( id_user int(10) unsigned NOT NULL AUTO_INCREMENT, name varchar(100) NOT NULL DEFAULT '', surname varchar(155) NOT NULL DEFAULT '', PRIMARY KEY (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=636 ; CREATE TABLE IF NOT EXISTS tutor_details ( id_tutor int(10) NOT NULL AUTO_INCREMENT, id_user int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_tutor), KEY Users_FKIndex1 (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=51 ; CREATE TABLE IF NOT EXISTS orders ( id_order int(10) unsigned NOT NULL AUTO_INCREMENT, PRIMARY KEY (id_order), KEY Orders_FKIndex1 (id_user), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=275 ; ALTER TABLE orders ADD CONSTRAINT Orders_ibfk_1 FOREIGN KEY (id_user) REFERENCES users (id_user) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS order_details ( id_od int(10) unsigned NOT NULL AUTO_INCREMENT, id_order int(10) unsigned NOT NULL DEFAULT '0', id_author int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_od), KEY Order_Details_FKIndex1 (id_order) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=284 ; ALTER TABLE order_details ADD CONSTRAINT Order_Details_ibfk_1 FOREIGN KEY (id_order) REFERENCES orders (id_order) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs ( id_lp int(10) unsigned NOT NULL AUTO_INCREMENT, id_author int(10) unsigned NOT NULL DEFAULT '0', PRIMARY KEY (id_lp), KEY Learning_Packs_FKIndex2 (id_author), KEY id_lp (id_lp) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=23 ; CREATE TABLE IF NOT EXISTS tags ( id_tag int(10) unsigned NOT NULL AUTO_INCREMENT, tag varchar(255) DEFAULT NULL, PRIMARY KEY (id_tag), UNIQUE KEY tag (tag), KEY id_tag (id_tag), KEY tag_2 (tag), KEY tag_3 (tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3419 ; CREATE TABLE IF NOT EXISTS tutors_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, KEY Tutors_Tag_Relations (id_tag), KEY id_tutor (id_tutor), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE tutors_tag_relations ADD CONSTRAINT Tutors_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, id_lp int(10) unsigned DEFAULT NULL, KEY Learning_Packs_Tag_Relations_FKIndex1 (id_tag), KEY id_lp (id_lp), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE learning_packs_tag_relations ADD CONSTRAINT Learning_Packs_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; =================================================================================== Following is the exact query (this includes classes also - tutors can create classes and search terms are matched with classes created by tutors):- select count(distinct(od.id_od)) as tutor_popularity, CASE WHEN (IF((wc.id_wc 0), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT'))), 0)) THEN 1 ELSE 0 END as 'classes_published', CASE WHEN (IF((lp.id_lp 0), (lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT'))),0)) THEN 1 ELSE 0 END as 'packs_published', td . * , u . * from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN Learning_Packs_Categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN Learning_Packs_Categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN Learning_Pack_Content as lpct on (lp.id_lp = lpct.id_lp) LEFT JOIN Webclasses_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN WebClasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN Learning_Packs_Categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN Learning_Packs_Categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) OR (t.id_tag = wtagrels.id_tag) where (u.country='IE' or u.country IN ('INT')) AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and o.order_status = 'paid' and CASE WHEN (od.id_wc 0) THEN od.can_attend_class=1 ELSE 1 END ELSE 1 END AND 1 group by td.id_tutor order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 Please note - The provided database structure does not show all the fields and tables as in this query

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  • Why does RIGHT(@foostr, 0) return NULL when @foostr is varchar(max)?

    - by bob-montgomery
    In SQL Server 2005 If I want to find the right-most one character of a varchar(max) variable, no problem: declare @foostr varchar(max) set @foostr = 'abcd' select right (@foostr, 1) ---- d If I want to find the right-most zero characters of a string literal, no problem: select right ('abcd', 0) ------------------ It returns an empty string. If I want to find the right-most zero characters of a varchar(10), no problem: declare @foostr varchar(10) set @foostr = 'abcd' select right (@foostr, 0) ---- It returns an empty string. If I want to find the right-most zero characters of a varchar(max), well: declare @foostr varchar(max) set @foostr = 'abcd' select right (@foostr, 0) ---- NULL It returns NULL. Why?

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  • SQL SERVER – Puzzle to Win Print Book – Write T-SQL Self Join Without Using FIRST _VALUE and LAST_VALUE

    - by pinaldave
    Last week we asked a puzzle SQL SERVER – Puzzle to Win Print Book – Functions FIRST_VALUE and LAST_VALUE with OVER clause and ORDER BY . This puzzle got very interesting participation. The details of the winner is listed here. In this puzzle we received two very important feedback. This puzzle cleared the concepts of First_Value and Last_Value to the participants. As this was based on SQL Server 2012 many could not participate it as they have yet not installed SQL Server 2012. I really appreciate the feedback of user and decided to come up something as fun and helps learn new feature of SQL Server 2012. Please read yesterday’s blog post SQL SERVER – Introduction to LEAD and LAG – Analytic Functions Introduced in SQL Server 2012 before continuing this puzzle as it is based on yesterday’s post. Yesterday I ran following query which uses functions LEAD and LAG. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO The above query will give us the following result: Puzzle: Now use T-SQL Self Join where same table is joined to itself and get the same result without using LEAD or LAG functions. Hint: Introduction to JOINs – Basic of JOINs Self Join A new analytic functions in SQL Server Denali CTP3 – LEAD() and LAG() Rules Leave a comment with your detailed answer by Nov 21's blog post. Open world-wide (where Amazon ships books) If you blog about puzzle’s solution and if you win, you win additional surprise gift as well. Prizes Print copy of my new book SQL Server Interview Questions Amazon|Flipkart If you already have this book, you can opt for any of my other books SQL Wait Stats [Amazon|Flipkart|Kindle] and SQL Programming [Amazon|Flipkart|Kindle]. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Join us for our WebLogic Communtiy webcast on November 2nd 2012! OOW update WebLogic & ExaLogic

    - by JuergenKress
    NOVEMBER 2nd, 2012 AT 11:00 -11:45 AM CET (BERLIN TIME) Do you want to learn the latest about WebLogic and ExaLogic? Would you like to know what did Oracle announce at Oracle OpenWorld 2012? Join us for our WebLogic Communtiy webcast on November 2nd 2012! Don't miss this unique opportunity and learn the latest announcement and product updates on WebLogic and ExaLogic portfolio. Agenda Update announced about Cloud Application Foundation ExaLogic Update Key examples from successful customer Updated Roadmap Q&A Register to Attend! To Join the Webcast (Employees and Partners) AND / OR DIAL IN If you would like to dial in to the audio portion of the Webconference. Call ID: 8000524 & Call Passcode: 333111 Austria : +43(0)19286512 Belgium: +32(0)24010528 Denmark: +4532729222 Finland: +358(0)923193923 France: +33(0)176728936 Germany: +49(0)69222216106 Ireland: +353(0)12475650 Italy: +39(0)236008198 Netherlands: +31(0)207143543 Norway: +4721033443 Spain: +34914143755 Sweden: +46(0)856619465 Switzerland: +41(0)445804003 United Kingdom: +44(0)2081181001 Please click here to find more Local Numbers. Presenters: Maciej Gruszka Senior Principal Product Manager Tel: +4 (0) 8601 156 464 E-Mail: [email protected] LinkedIn: http://pl.linkedin.com/pub/maciej-gruszka/2/169/89 Jürgen Kress WebLogic Partner Adoption EMEA Tel. +49 89 1430 1479 E-Mail: [email protected] LinkedIn: http://de.linkedin.com/in/kress Twitter: http://twitter.com/wlscommunity Delivery Format This FREE online LIVE eSeminar will be delivered over the Web. Registrations received less than 24hours prior to start time may not receive confirmation to attend. Duration: 1 hour Looking forward to your participation! WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. BlogTwitterLinkedInMixForumWiki Technorati Tags: WebLogic Community Webcast,webcst,OOW updates WebLogic ExaLogic,WebLogic ppt,presenation,sales,WebLogic Community,Oracle,OPN,Jürgen Kress

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  • SQL query. An unusual join. DB implemented in sqlite-3

    - by user02814
    This is essentially a question about constructing an SQL query. The db is implemented with sqlite3. I am a relatively new user of SQL. I have two tables and want to join them in an unusual way. The following is an example to explain the problem. Table 1 (t1): id year name ------------------------- 297 2010 Charles 298 2011 David 300 2010 Peter 301 2011 Richard Table 2 (t2) id year food --------------------------- 296 2009 Bananas 296 2011 Bananas 297 2009 Melon 297 2010 Coffee 297 2012 Cheese 298 2007 Sugar 298 2008 Cereal 298 2012 Chocolate 299 2000 Peas 300 2007 Barley 300 2011 Beans 300 2012 Chickpeas 301 2010 Watermelon I want to join the tables on id and year. The catch is that (1) id must match exactly, but if there is no exact match in Table 2 for the year in Table 1, then I want to choose the year that is the next (lower) available. A selection of the kind that I want to produce would give the following result id year matchyr name food ------------------------------------------------- 297 2010 2010 Charles Coffee 298 2011 2008 David Cereal 300 2010 2007 Peter Barley 301 2011 2010 Richard Watermelon To summarise, id=297 had an exact match for year=2010 given in Table 1, so the corresponding line for id=297, year=2010 is chosen from Table 2. id=298, year=2011 did not have a matching year in Table 2, so the next available year (less than 2011) is chosen. As you can see, I would also like to know what that matched year (whether exactly , or inexactly) actually was. I would very much appreciate (1) an indication (yes/no answer) of whether this is possible to do in SQL alone, or whether I need to look outside SQL, and (2) a solution, if that is not too onerous.

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  • When is the right time to join open source project for programmer?

    - by Mahesh
    Most of the newcomers in programming start with basic projects to start with programming. Most of the C++ progammers spend some time with puzzles and contests but this is not always helpful. Sometimes you've to spend some time on real projects. Starting your own open source project could be a problem in self-learning for newbie cause of lack of mentors and peers who can't look at your code and give suggestions. Open source projects can solve this problem, some projects could be best suited for new programmers. Besides everybody is newbie at some point. So i'll try and make this question a bit from beginners perspective. I tried few questions on stack overflow before asking this like How do i join & Bare minimum you need and how to get involved with open source and what level of programming etc. But this is not helping me when it comes to self-evaluating with skills. How to find that out ? How can i check what it takes to join open source project and am i really that comfortable with huge source code etc. My question is when to consider yourself comfortable joining open source programming ? I mean how will you test yourself that you're ready to take burden of big/small projects of open source ? how will you test yourself to see if you could work with version control/other programmers/tight schedule etc ?

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  • How to re-join an AD2003 domain with Samba after deleting the machine account?

    - by Guss
    During some troubleshooting I deleted the machine account for a Linux server running samba from our AD 2003 domain. We are using Kerberos for authentication, and after I deleted the machine account I tried to join the domain again using net ads join -U Administrator But I keep getting Kerberos errors like these: [2009/08/18 16:14:36, 0] libads/kerberos.c:ads_kinit_password(228) kerberos_kinit_password [email protected] failed: Client not found in Kerberos database Failed to join domain: Improperly formed account name It appears as if samba remembers that it once had an account with the AD and keeps trying to reconnect to it, but I want to create a new account from scratch. I tried to delete all the .tdb files I could find as well as everything under /var/cache/samba but to no avail - it still behaves the same. I also tried to create the machine account on the AD side, but then I get a similar error when I try to join, about failure to authenticate with the machine account - it looks like samba tries the previous machine account password and I don't know how to reset it, or even if I could figure out what samba uses - how to set it in the AD. Any help would be greatly appreciated, as at this point the only thing I can think about is to reformat and reinstall the machine, and I would really REALLY love to not do that. Thanks in advance.

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  • STORED PROCEDURE working in my local test machine cannot be created in production environment.

    - by Marcos Buarque
    Hi, I have an SQL CREATE PROCEDURE statement that runs perfectly in my local SQL Server, but cannot be recreated in production environment. The error message I get in production is Msg 102, Level 15, State 1, Incorrect syntax near '='. It is a pretty big query and I don't want to annoy StackOverflow users, but I simply can't find a solution. If only you could point me out what settings I could check in the production server in order to enable running the code... I must be using some kind of syntax or something that is conflicting with some setting in production. This PROCEDURE was already registered in production before, but when I ran a DROP - CREATE PROCEDURE today, the server was able to drop the procedure, but not to recreate it. I will paste the code below. Thank you! =============== USE [Enorway] GO /****** Object: StoredProcedure [dbo].[Spel_CM_ChartsUsersTotals] Script Date: 03/17/2010 11:59:57 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE PROC [dbo].[Spel_CM_ChartsUsersTotals] @IdGroup int, @IdAssessment int, @UserId int AS SET NOCOUNT ON DECLARE @RequiredColor varchar(6) SET @RequiredColor = '3333cc' DECLARE @ManagersColor varchar(6) SET @ManagersColor = '993300' DECLARE @GroupColor varchar(6) SET @GroupColor = 'ff0000' DECLARE @SelfColor varchar(6) SET @SelfColor = '336600' DECLARE @TeamColor varchar(6) SET @TeamColor = '993399' DECLARE @intMyCounter tinyint DECLARE @intManagersPosition tinyint DECLARE @intGroupPosition tinyint DECLARE @intSelfPosition tinyint DECLARE @intTeamPosition tinyint SET @intMyCounter = 1 -- Table that will hold the subtotals... DECLARE @tblTotalsSource table ( IdCompetency int, CompetencyName nvarchar(200), FunctionRequiredLevel float, ManagersAverageAssessment float, SelfAssessment float, GroupAverageAssessment float, TeamAverageAssessment float ) INSERT INTO @tblTotalsSource ( IdCompetency, CompetencyName, FunctionRequiredLevel, ManagersAverageAssessment, SelfAssessment, GroupAverageAssessment, TeamAverageAssessment ) SELECT e.[IdCompetency], dbo.replaceAccentChar(e.[Name]) AS CompetencyName, (i.[LevelNumber]) AS FunctionRequiredLevel, ( SELECT ROUND(avg(CAST(ac.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData aa INNER JOIN Spel_CM_CompetenciesLevels ab ON aa.[IdCompetencyLevel] = ab.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels ac ON ab.[IdLevel] = ac.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents ad ON aa.[IdAssessmentEvent] = ad.[IdAssessmentEvent] WHERE aa.[EvaluatedUserId] = @UserId AND aa.[AssessmentType] = 't' AND aa.[IdGroup] = @IdGroup AND ab.[IdCompetency] = e.[IdCompetency] AND ad.[IdAssessment] = @IdAssessment ) AS ManagersAverageAssessment, ( SELECT bc.[LevelNumber] FROM Spel_CM_AssessmentsData ba INNER JOIN Spel_CM_CompetenciesLevels bb ON ba.[IdCompetencyLevel] = bb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels bc ON bb.[IdLevel] = bc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents bd ON ba.[IdAssessmentEvent] = bd.[IdAssessmentEvent] WHERE ba.[EvaluatedUserId] = @UserId AND ba.[AssessmentType] = 's' AND ba.[IdGroup] = @IdGroup AND bb.[IdCompetency] = e.[IdCompetency] AND bd.[IdAssessment] = @IdAssessment ) AS SelfAssessment, ( SELECT ROUND(avg(CAST(cc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData ca INNER JOIN Spel_CM_CompetenciesLevels cb ON ca.[IdCompetencyLevel] = cb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels cc ON cb.[IdLevel] = cc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents cd ON ca.[IdAssessmentEvent] = cd.[IdAssessmentEvent] WHERE ca.[EvaluatedUserId] = @UserId AND ca.[AssessmentType] = 'g' AND ca.[IdGroup] = @IdGroup AND cb.[IdCompetency] = e.[IdCompetency] AND cd.[IdAssessment] = @IdAssessment ) AS GroupAverageAssessment, ( SELECT ROUND(avg(CAST(dc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData da INNER JOIN Spel_CM_CompetenciesLevels db ON da.[IdCompetencyLevel] = db.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels dc ON db.[IdLevel] = dc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents dd ON da.[IdAssessmentEvent] = dd.[IdAssessmentEvent] WHERE da.[EvaluatedUserId] = @UserId AND da.[AssessmentType] = 'm' AND da.[IdGroup] = @IdGroup AND db.[IdCompetency] = e.[IdCompetency] AND dd.[IdAssessment] = @IdAssessment ) AS TeamAverageAssessment FROM Spel_CM_AssessmentsData a INNER JOIN Spel_CM_AssessmentsEvents c ON a.[IdAssessmentEvent] = c.[IdAssessmentEvent] INNER JOIN Spel_CM_CompetenciesLevels d ON a.[IdCompetencyLevel] = d.[IdCompetencyLevel] INNER JOIN Spel_CM_Competencies e ON d.[IdCompetency] = e.[IdCompetency] INNER JOIN Spel_CM_Levels f ON d.[IdLevel] = f.[IdLevel] -- This will link with user's assigned functions INNER JOIN Spel_CM_FunctionsCompetenciesLevels g ON a.[IdFunction] = g.[IdFunction] INNER JOIN Spel_CM_CompetenciesLevels h ON g.[IdCompetencyLevel] = h.[IdCompetencyLevel] AND e.[IdCompetency] = h.[IdCompetency] INNER JOIN Spel_CM_Levels i ON h.[IdLevel] = i.[IdLevel] WHERE (NOT c.[EndDate] IS NULL) AND a.[EvaluatedUserId] = @UserId AND c.[IdAssessment] = @IdAssessment AND a.[IdGroup] = @IdGroup GROUP BY e.[IdCompetency], e.[Name], i.[LevelNumber] ORDER BY e.[Name] ASC -- This will define the position of each element (managers, group, self and team) SELECT @intManagersPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT ManagersAverageAssessment IS NULL IF IsNumeric(@intManagersPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intGroupPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT GroupAverageAssessment IS NULL IF IsNumeric(@intGroupPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intSelfPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT SelfAssessment IS NULL IF IsNumeric(@intSelfPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intTeamPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT TeamAverageAssessment IS NULL -- This will render the final table for the end user. The tabe will flatten some of the numbers to allow them to be prepared for Google Graphics. SELECT SUBSTRING( ( SELECT ( '|' + REPLACE(ma.[CompetencyName],' ','+')) FROM @tblTotalsSource ma ORDER BY ma.[CompetencyName] DESC FOR XML PATH('') ), 2, 1000) AS 'CompetenciesNames', SUBSTRING( ( SELECT ( ',' + REPLACE(ra.[FunctionRequiredLevel]*10,' ','+')) FROM @tblTotalsSource ra FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredLevel', SUBSTRING( ( SELECT ( ',' + CAST(na.[ManagersAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource na FOR XML PATH('') ), 2, 1000) AS 'ManagersAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(oa.[GroupAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource oa FOR XML PATH('') ), 2, 1000) AS 'GroupAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(pa.[SelfAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource pa FOR XML PATH('') ), 2, 1000) AS 'SelfAssessment', SUBSTRING( ( SELECT ( ',' + CAST(qa.[TeamAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource qa FOR XML PATH('') ), 2, 1000) AS 'TeamAverageAssessment', SUBSTRING( ( SELECT ( '|t++' + CAST([FunctionRequiredLevel] AS varchar(10)) + ',' + @RequiredColor + ',0,' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredAverageLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([ManagersAverageAssessment] AS varchar(10)) + ',' + @ManagersColor + ',' + CAST(@intManagersPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'ManagersLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([GroupAverageAssessment] AS varchar(10)) + ',' + @GroupColor + ',' + CAST(@intGroupPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'GroupLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([SelfAssessment] AS varchar(10)) + ',' + @SelfColor + ',' + CAST(@intSelfPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'SelfLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([TeamAverageAssessment] AS varchar(10)) + ',' + @TeamColor + ',' + CAST(@intTeamPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',10') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'TeamLabel', (Count(src.[IdCompetency]) * 30) + 100 AS 'ControlHeight' FROM @tblTotalsSource src SET NOCOUNT OFF GO

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