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  • How to setup IIS subdomain pointing to folder on remote machine?

    - by zsharp
    Im trying to serve static content through a subdomain. The physical folder is shared on a second machine in the same local domain. How do I safely setup permissions on the shared folder so that when i do something like: src="subdomain.domain.com/Image1.png" I wont get access denied? IN IIS I have subdomain.domain.com as a separate website.

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  • What is the best Apache, PHP setup for a Mac developer? [on hold]

    - by hevets
    I'm a Web Developer who has just made the switch over to Mac. Despite all that I know and love about the Windows environment I find myself in a new mysterious place. My question: what is the best Apache, PHP setup for a Mac developer? On Windows I've been using WAMP which was quite nice, I know Mac comes shipped with Apache 2 and PHP pre-installed. I'm just wondering if there is a better solution out there.

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  • Minimal setup for sendmail to send outgoing email only?

    - by Michael
    I run a simple server that I administrate remotely, and I need it to be able to send an email to my personal email address every time an error occurs. With the default setup on Ubuntu, sendmail just accumulates emails in /var/spool/mail that are to be sent locally, but I need it to go to an external email. The tutorials I've found all talk about setting up postfix/sendmail as a full-fledged email server, but I just need outgoing only, no external logins. Is there an easy way to do this?

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  • Deploying Django on EC2 using Bitnami Djangostack: WSGI script cannot be loadded

    - by Arman
    I've been struggling to deploy Django application on Amazon EC2 using Bitnami Djangostack for the last couple of days. When I go to http://dewey.io I see the default bitnami page (/opt/bitnami/apache2/htdocs/index.html), however, when I open http://dewey.io/portnoy, I get 'Internal Server Error'. But it's known that if mod_wsgi is setup correctly, the DocumentRoot value from httpd.conf is ignored, thus, I should see my Django application when accessing http://dewey.io. Essentially, the main error is this - 'Target WSGI script cannot be loaded as Python module'. Two questions: 1) any ideas how to fix these mod_wsgi errors (the Apache logs are below)? 2) how to disable the default /opt/bitnami/apache2/htdocs/index.html page and show my homepage from django application when accessing http://dewey.io? Thank you in advance! The details On my EC2 instance I"m running 64-bit Ubuntu 12.04 with DjangoStack 1.4-1. My Django project is located here - /opt/bitnami/apps/django/django_projects/portnoy. root@dewey:/opt/bitnami/apps/django/django_projects/portnoy# ls manage.py README.md settings.py site_media users Procfile sandbox static test.py topics urls.py views.py __init__.pyc templates testviews.py Apache error logs (/opt/bitnami/apache2/logs/error_log): [Wed Jul 04 02:29:00 2012] [error] [client 140.180.6.212] File does not exist: /opt/bitnami/apache2/htdocs/favicon.ico [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] mod_wsgi (pid=3990): Target WSGI script '/opt/bitnami/apps/django/scripts/django.wsgi' cannot be loaded as Python module. [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] mod_wsgi (pid=3990): Exception occurred processing WSGI script '/opt/bitnami/apps/django/scripts/django.wsgi'. [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] Traceback (most recent call last): [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File "/opt/bitnami/apps/django/scripts/django.wsgi", line 8, in <module> [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] import django.core.handlers.wsgi [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File "/opt/bitnami/apps/django/lib/python2.7/site-packages/django/core/handlers/wsgi.py", line 8, in <module> [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] from django import http [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File "/opt/bitnami/apps/django/lib/python2.7/site-packages/django/http/__init__.py", line 119, in <module> [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] from django.http.multipartparser import MultiPartParser [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File "/opt/bitnami/apps/django/lib/python2.7/site-packages/django/http/multipartparser.py", line 13, in <module> [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] from django.utils.text import unescape_entities [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File "/opt/bitnami/apps/django/lib/python2.7/site-packages/django/utils/text.py", line 4, in <module> [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] from gzip import GzipFile [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File "/opt/bitnami/python/lib/python2.7/gzip.py", line 10, in <module> [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] import io [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File "/opt/bitnami/python/lib/python2.7/io.py", line 60, in <module> [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] import _io [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] ImportError: /opt/bitnami/python/lib/python2.7/lib-dynload/_io.so: undefined symbol: PyUnicodeUCS2_AsEncodedString [Wed Jul 04 02:29:15 2012] [error] [client 140.180.6.212] File does not exist: /opt/bitnami/apache2/htdocs/favicon.ico [Wed Jul 04 02:44:00 2012] [error] [client 140.180.6.212] File does not exist: /opt/bitnami/apache2/htdocs/favicon.ico Let me quickly introduce the contents of the files to make the case more concrete. This is my /etc/apache2/sites-available/default file <VirtualHost *:80> ServerAdmin [email protected] ServerName dewey.io Alias /site_media/ /opt/bitnami/apps/django/django_projects/portnoy/site_media/ Alias /static/ /opt/bitnami/apps/django/lib/python2.7/site-packages/django/contrib/admin/static/ Alias /robots.txt /opt/bitnami/apps/django/django_projects/portnoy/site_media/robots.txt Alias /favicon.ico /opt/bitnami/apps/django/django_projects/portnoy/site_media/favicon.ico CustomLog "|/usr/sbin/rotatelogs /opt/bitnami/apps/django/django_projects/logs/access.log.%Y%m%d-%H%M%S 5M" combined ErrorLog "|/usr/sbin/rotatelogs /opt/bitnami/apps/django/django_projects/logs/error.log.%Y%m%d-%H%M%S 5M" LogLevel warn WSGIProcessGroup dewey.io WSGIScriptAlias / /opt/bitnami/apps/django/scripts/django.wsgi <Directory /opt/bitnami/apps/django/django_projects/portnoy/site_media> Order deny,allow Allow from all Options -Indexes FollowSymLinks </Directory> <Directory /opt/bitnami/apps/django/django_projects/portnoy/conf/apache> Order deny,allow Allow from all </Directory> </VirtualHost> This is my /opt/bitnami/apps/django/scripts/django.wsgi file import os, sys sys.path.append('/opt/bitnami/apps/django/lib/python2.7/site-packages/') sys.path.append('/opt/bitnami/apps/django/django_projects') sys.path.append('/opt/bitnami/apps/django/django_projects/portnoy') os.environ['DJANGO_SETTINGS_MODULE'] = 'portnoy.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Here is the relevant portion of /opt/bitnami/apache2/conf/httpd.conf file: ServerRoot "/opt/bitnami/apache2" Listen 80 ServerName dewey.io DocumentRoot "/opt/bitnami/apache2/htdocs" LoadModule wsgi_module modules/mod_wsgi.so WSGIPythonHome /opt/bitnami/python Include "/opt/bitnami/apache2/conf/ssi.conf" Include "/opt/bitnami/apps/django/conf/django.conf" Include "/opt/bitnami/apache2/conf/bitnami/httpd.conf"

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  • python metaprogramming

    - by valya
    I'm trying to archive a task which turns out to be a bit complicated since I'm not very good at Python metaprogramming. I want to have a module locations with function get_location(name), which returns a class defined in a folder locations/ in the file with the name passed to function. Name of a class is something like NameLocation. So, my folder structure: program.py locations/ __init__.py first.py second.py program.py will be smth with with: from locations import get_location location = get_location('first') and the location is a class defined in first.py smth like this: from locations import Location # base class for all locations, defined in __init__ (?) class FirstLocation(Location): pass etc. Okay, I've tried a lot of import and getattribute statements but now I'm bored and surrender. How to archive such behaviour?

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  • Programmatically specifying Django model attributes

    - by mojbro
    Hi! I would like to add attributes to a Django models programmatically, at run time. For instance, lets say I have a Car model class and want to add one price attribute (database column) per currency, given a list of currencies. What is the best way to do this? I had an approach that I thought would work, but it didn't exactly. This is how I tried doing it, using the car example above: from django.db import models class Car(models.Model): name = models.CharField(max_length=50) currencies = ['EUR', 'USD'] for currency in currencies: Car.add_to_class('price_%s' % currency.lower(), models.IntegerField()) This does seem to work pretty well at first sight: $ ./manage.py syncdb Creating table shop_car $ ./manage.py dbshell shop=# \d shop_car Table "public.shop_car" Column | Type | Modifiers -----------+-----------------------+------------------------------------------------------- id | integer | not null default nextval('shop_car_id_seq'::regclass) name | character varying(50) | not null price_eur | integer | not null price_usd | integer | not null Indexes: "shop_car_pkey" PRIMARY KEY, btree (id) But when I try to create a new Car, it doesn't really work anymore: >>> from shop.models import Car >>> mycar = Car(name='VW Jetta', price_eur=100, price_usd=130) >>> mycar <Car: Car object> >>> mycar.save() Traceback (most recent call last): File "<console>", line 1, in <module> File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 410, in save self.save_base(force_insert=force_insert, force_update=force_update) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 495, in save_base result = manager._insert(values, return_id=update_pk) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/manager.py", line 177, in _insert return insert_query(self.model, values, **kwargs) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/query.py", line 1087, in insert_query return query.execute_sql(return_id) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/subqueries.py", line 320, in execute_sql cursor = super(InsertQuery, self).execute_sql(None) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/backends/util.py", line 19, in execute return self.cursor.execute(sql, params) ProgrammingError: column "price_eur" specified more than once LINE 1: ...NTO "shop_car" ("name", "price_eur", "price_usd", "price_eur... ^

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  • Django: CharField with fixed length, how?

    - by Giovanni Di Milia
    Hi everybody, I wold like to have in my model a CharField with fixed length. In other words I want that only a specified length is valid. I tried to do something like volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) but it gives me an error (it seems that I can use both max_length and min_length at the same time). Is there another quick way? Thanks EDIT: Following the suggestions of some people I will be a bit more specific: My model is this: class Volume(models.Model): vid = models.AutoField(primary_key=True) jid = models.ForeignKey(Journals, db_column='jid', null=True, verbose_name = "Journal") volumenumber = models.CharField('Volume Number') date_publication = models.CharField('Date of Publication', max_length=6, blank=True) class Meta: db_table = u'volume' verbose_name = "Volume" ordering = ['jid', 'volumenumber'] unique_together = ('jid', 'volumenumber') def __unicode__(self): return (str(self.jid) + ' - ' + str(self.volumenumber)) What I want is that the volumenumber must be exactly 4 characters. I.E. if someone insert '4b' django gives an error because it expects a string of 4 characters. So I tried with volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) but it gives me this error: Validating models... Unhandled exception in thread started by <function inner_run at 0x70feb0> Traceback (most recent call last): File "/Library/Python/2.5/site-packages/django/core/management/commands/runserver.py", line 48, in inner_run self.validate(display_num_errors=True) File "/Library/Python/2.5/site-packages/django/core/management/base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "/Library/Python/2.5/site-packages/django/core/management/validation.py", line 28, in get_validation_errors for (app_name, error) in get_app_errors().items(): File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 131, in get_app_errors self._populate() File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 58, in _populate self.load_app(app_name, True) File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 74, in load_app models = import_module('.models', app_name) File "/Library/Python/2.5/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Users/Giovanni/src/djangoTestSite/../djangoTestSite/journaldb/models.py", line 120, in <module> class Volume(models.Model): File "/Users/Giovanni/src/djangoTestSite/../djangoTestSite/journaldb/models.py", line 123, in Volume volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) TypeError: __init__() got an unexpected keyword argument 'min_length' That obviously doesn't appear if I use only "max_length" OR "min_length". I read the documentation on the django web site and it seems that I'm right (I cannot use both together) so I'm asking if there is another way to solve the problem. Thanks again

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  • python networkx

    - by krisdigitx
    hi, i am trying to use networkx with python, when i run this program, it get this error, is there anything missing? #!/usr/bin/env python import networkx as nx import matplotlib import matplotlib.pyplot import matplotlib.pyplot as plt G=nx.Graph() G.add_node(1) G.add_nodes_from([2,3,4,5,6,7,8,9,10]) #nx.draw_graphviz(G) #nx_write_dot(G, 'node.png') nx.draw(G) plt.savefig("/var/www/node.png") Traceback (most recent call last): File "graph.py", line 13, in <module> nx.draw(G) File "/usr/lib/pymodules/python2.5/networkx/drawing/nx_pylab.py", line 124, in draw cf=pylab.gcf() File "/usr/lib/pymodules/python2.5/matplotlib/pyplot.py", line 276, in gcf return figure() File "/usr/lib/pymodules/python2.5/matplotlib/pyplot.py", line 254, in figure **kwargs) File "/usr/lib/pymodules/python2.5/matplotlib/backends/backend_tkagg.py", line 90, in new_figure_manager window = Tk.Tk() File "/usr/lib/python2.5/lib-tk/Tkinter.py", line 1650, in __init__ self.tk = _tkinter.create(screenName, baseName, className, interactive, wantobjects, useTk, sync, use) _tkinter.TclError: no display name and no $DISPLAY environment variable

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  • Python: Define Classes in Packages

    - by rfkrocktk
    I'm learning Python and I have been playing around with packages. I wanted to know the best way to define classes in packages. It seems that the only way to define classes in a package is to define them in init.py of that package. Coming from Java, I'd kind of like to define individual files for my classes. Is this a recommended practice? I'd like to have my directory look somewhat like this: recursor/ __init__.py RecursionException.py RecursionResult.py Recursor.py So I could refer to my classes as "recursor.Recursor," "recursor.RecursionException," and "recursor.RecursionResult.py". Is this "do-able" or recommended in Python?

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  • Facebook publish HTTP Error 400 : bad request

    - by Abhishek
    Hey I am trying to publish a score to Facebook through python's urllib2 library. import urllib2,urllib url = "https://graph.facebook.com/USER_ID/scores" data = {} data['score']=SCORE data['access_token']='APP_ACCESS_TOKEN' data_encode = urllib.urlencode(data) request = urllib2.Request(url, data_encode) response = urllib2.urlopen(request) responseAsString = response.read() I am getting this error: response = urllib2.urlopen(request) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 124, in urlopen return _opener.open(url, data, timeout) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 389, in open response = meth(req, response) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 502, in http_response 'http', request, response, code, msg, hdrs) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 427, in error return self._call_chain(*args) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 361, in _call_chain result = func(*args) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 510, in http_error_default raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) urllib2.HTTPError: HTTP Error 400: Bad Request Not sure if this is relating to Facebook's Open Graph or improper urllib2 API use.

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  • How to get HTTP status message in (py)curl?

    - by mykhal
    spending some time studying pycurl and libcurl documentation, i still can't find a (simple) way, how to get HTTP status message (reason-phrase) in pycurl. status code is easy: import pycurl import cStringIO curl = pycurl.Curl() buff = cStringIO.StringIO() curl.setopt(pycurl.URL, 'http://example.org') curl.setopt(pycurl.WRITEFUNCTION, buff.write) curl.perform() print "status code: %s" % curl.getinfo(pycurl.HTTP_CODE) # -> 200 # print "status message: %s" % ??? # -> "OK"

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  • Which revision of html5lib is stable?

    - by Mat
    html5lib notes that it's latest release (0.11) is somewhat old. Using the Python portion, I have recursion problems as noted in Issue 70 and Issue 59 but can't find a recent Mercurial revision that is stable. The latest tip is no good, I got the following error from python setup.py install: byte-compiling build/bdist.linux-x86_64/egg/html5lib/treewalkers/_base.py to _base.pyc File "build/bdist.linux-x86_64/egg/html5lib/treewalkers/_base.py", line 40 "data": []} ^ SyntaxError: invalid syntax And I get the following errors at runtime: soup = parser.parse(page.read()) File "build/bdist.linux-x86_64/egg/html5lib/html5parser.py", line 165, in parse File "build/bdist.linux-x86_64/egg/html5lib/html5parser.py", line 144, in _parse File "build/bdist.linux-x86_64/egg/html5lib/html5parser.py", line 454, in processDoctype TypeError: insertDoctype() takes exactly 4 arguments (2 given) I'm using it on Python 2.5.2 with lxml and BeautifulSoup.

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  • Install TurboGears on windows xp

    - by coder
    I've been trying to get TurboGears installed on Windows by following this site. I've installed virtualenv but when I execute the command "virtualenv --no-site-packages testproj", I get the following message: New python executable in testproj\Scripts\python.exe Traceback (most recent call last): File "C:\Python26\Scripts\virtualenv-script.py", line 8, in load_entry_point('virtualenv==1.4.5', 'console_scripts', 'virtualenv')() File "C:\Python26\lib\site-packages\virtualenv-1.4.5-py2.6.egg\virtualenv.py", line 529, in main use_distribute=options.use_distribute) File "C:\Python26\lib\site-packages\virtualenv-1.4.5-py2.6.egg\virtualenv.py", line 612, in create_environment site_packages=site_packages, clear=clear)) File "C:\Python26\lib\site-packages\virtualenv-1.4.5-py2.6.egg\virtualenv.py", line 837, in install_python stdout=subprocess.PIPE) File "C:\Python26\lib\subprocess.py", line 621, in __init__ errread, errwrite) File "C:\Python26\lib\subprocess.py", line 830, in _execute_child startupinfo) WindowsError: [Error 14001] This application has failed to start because the application configuration is incorrect. Reinstalling the application may fix this problem Can someone help me debug this ? If any one knows a better tutorial to install turbogears, please let me know.

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  • I keep Getting KeyError: 'tried' Whenever I Tried to Run Django Dev Server from Remote Machine

    - by Spikie
    I am running django on python2.6.1, and did start the django web server like this manage.py runserver 192.0.0.1:8000 then tried to connect to the django dev web server on http://192.0.0.1:8000/ keep getting this message on the remote computer Traceback (most recent call last): File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 651, in call return self.application(environ, start_response) File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py", line 241, in call response = self.get_response(request) File "C:\Python26\lib\site-packages\django\core\handlers\base.py", line 115, in get_response return debug.technical_404_response(request, e) File "C:\Python26\Lib\site-packages\django\views\debug.py", line 247, in technical_404_response tried = exception.args[0]['tried'] KeyError: 'tried' what i am doing wrong ? it seen to work ok if i run http://192.0.0.1:8000/ on the computer that runs the Django web server and have that ip 192.0.0.1:8000

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  • How to setup Lucene search for a B2B web app?

    - by Bill Paetzke
    Given: 5000 databases (spread out over 5 servers) 1 database per client (so you can infer there are 1000 clients) 2 to 2000 users per client (let's say avg is 100 users per client) Clients (databases) come and go every day (let's assume most remain for at least one year) Let's stay agnostic of language or sql brand, since Lucene (and Solr) have a breadth of support The Question: How would you setup Lucene search so that each client can only search within its database? How would you setup the index(es)? Would you need to add a filter to all search queries? If a client cancelled, how would you delete their (part of the) index? (this may be trivial--not sure yet) Possible Solutions: Make an index for each client (database) Pro: Search is faster (than one-index-for-all method). Indices are relative to the size of the client's data. Con: I'm not sure what this entails, nor do I know if this is beyond Lucene's scope. Have a single, gigantic index with a database_name field. Always include database_name as a filter. Pro: Not sure. Maybe good for tech support or billing dept to search all databases for info. Con: Search is slower (than index-per-client method). Flawed security if query filter removed. For Example: Joel Spolsky said in Podcast #11 that his hosted web app product, FogBugz On-Demand, uses Lucene. He has thousands of on-demand clients. And each client gets their own database. His situation is quite similar to mine. Although, he didn't elaborate on the setup (particularly indices); hence, the need for this question. One last thing: I would also accept an answer that uses Solr (the extension of Lucene). Perhaps it's better suited for this problem. Not sure.

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  • Difference between URLLIB2 call in IDLE and from Django?

    - by danspants
    The following piece of code works as expected when running in a local install of django apache 2.2 fx = urllib2.Request(f); fx.add_header('User-Agent','Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US) AppleWebKit/525.19 (KHTML, like Gecko) Chrome/1.0.154.36 Safari/525.19'); url_opened = urllib2.urlopen(fx); However when I enter that code into IDLE on the same machine I get the following error: url_opened = urllib2.urlopen(fx); File "C:\Python25\lib\urllib2.py", line 124, in urlopen return _opener.open(url, data) File "C:\Python25\lib\urllib2.py", line 387, in open response = meth(req, response) File "C:\Python25\lib\urllib2.py", line 498, in http_response 'http', request, response, code, msg, hdrs) File "C:\Python25\lib\urllib2.py", line 425, in error return self._call_chain(*args) File "C:\Python25\lib\urllib2.py", line 360, in _call_chain result = func(*args) File "C:\Python25\lib\urllib2.py", line 506, in http_error_default raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) HTTPError: HTTP Error 407: Proxy Authentication Required Any ideas?

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  • In Python, urllib2 giving error

    - by pythBegin
    I tried running this, >>> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') But it is giving error like this, can anyone tell me a solution ? Traceback (most recent call last): File "<pyshell#11>", line 1, in <module> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') File "C:\Python26\lib\urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "C:\Python26\lib\urllib2.py", line 391, in open response = self._open(req, data) File "C:\Python26\lib\urllib2.py", line 409, in _open '_open', req) File "C:\Python26\lib\urllib2.py", line 369, in _call_chain result = func(*args) File "C:\Python26\lib\urllib2.py", line 1161, in http_open return self.do_open(httplib.HTTPConnection, req) File "C:\Python26\lib\urllib2.py", line 1136, in do_open raise URLError(err) URLError: <urlopen error [Errno 11001] getaddrinfo failed>

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  • How to do relative imports in Python?

    - by Joril
    Imagine this directory structure: app/ __init__.py sub1/ __init__.py mod1.py sub2/ __init__.py mod2.py I'm coding mod1, and I need to import something from mod2. How should I do it? I tried from ..sub2 import mod2 but I'm getting an "Attempted relative import in non-package". I googled around but found only "sys.path manipulation" hacks. Isn't there a clean way? Edit: all my __init__.py's are currently empty Edit2: I'm trying to do this because sub2 contains classes that are shared across sub packages (sub1, subX, etc.). Edit3: The behaviour I'm looking for is the same as described in PEP 366 (thanks John B)

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  • how to read a static file in .py file using django ..

    - by zjm1126
    this is my error code: text = open('/media/a.txt', 'rb').read() and my perplexed is: when i use this : text = open('a.txt', 'rb').read() it can be running but when i put the 'a.txt' to the 'media' folder, i can't running , why ? thanks IOError at / [Errno 13] file not accessible: '/media/a.txt'

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